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  • A Website With Smartly Placed Content In It

    Quality website as well as blog content has the ability to attract many unexpected visitors to your sites and if you spice your fresh content with the right keywords then you can be almost confident ... [Author: Alan Smith - Web Design and Development - May 13, 2010]

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  • Live from the #summit13 keynote : 2013-10-16

    - by AaronBertrand
    Early morning start here in Charlotte. I'm going to try and keep this post updated as I have new information from the keynote to share, so refresh often! 8:24 AM Bill Graziano takes the stage and welcomes us to the 15th PASS Summit. He mentions that PASS delivered over 700,000 hours of technical training in the previous fiscal year, and shows a Power BI Power Map video talking about all of the SQL Saturday accomplishments in the last few years. She introduces Amy Lewis, who wins this year's PASSion...(read more)

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  • Graphic Design for Impressive Website Look

    Graphic design can be a boon for your website or curse if done wrongly. Visual pleasure is the strongest asset and quality of any website which makes them a visitor attracting medium. No matter how g... [Author: Alan Smith - Web Design and Development - May 13, 2010]

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  • Flash Website Design in Online Business

    As Adobe has owned Macromedia, use of flash in websites has increased significantly. Flash represents the information in more interesting manner enhancing the visual value of a website. Non-stop mo... [Author: Alan Smith - Web Design and Development - May 27, 2010]

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  • Read Erotica on the iPad

    Requirements: -- An iPad -- Free Stanza reader for iPad. -- Free Stanza Desktop software (Runs on Window PC and Mac). -- Internet connection and a small amount of intelligence. Steps: For a detail... [Author: Chris Smith - Computers and Internet - May 04, 2010]

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  • Apps Script Office Hours - October 25, 2012

    Apps Script Office Hours - October 25, 2012 - Arun announces an election sample app - soon! Look for the blog post on googleappsdeveloper.blogspot.com - LAX hackathon googleappsdeveloper.blogspot.com - Bill (Google Hangout) asks about ScriptDb. Ikai makes a long analogy about libraries and datastores and offers possible explanations for why certain issues occur, as well as some of the difficulties in working with distributed datastores. From: GoogleDevelopers Views: 48 6 ratings Time: 29:34 More in Science & Technology

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  • Importance of Having a FAQ Web Page

    Companies those are serious about their online business, lay emphasis on developing a website that is perfect in every sense. Your site is the virtual shop that can be accessed 24/7/365 days a year. ... [Author: Alan Smith - Web Design and Development - June 17, 2010]

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  • Create Websites Using Website Templates

    Websites have become necessary tool for any business including small, medium as well as big business firms. If you want to capture and spread your business all over the world, you need to have a webs... [Author: Alan Smith - Web Design and Development - May 28, 2010]

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  • Importance of Corporate Logo Design

    You need to bind to certain basic principles that ensure that corporate logo design is professional and easy to remember and creates a great impact on viewers while successfully expressing the nature... [Author: Alan Smith - Web Design and Development - May 13, 2010]

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  • Overview of Dynamic and Static Sites

    Most of the websites that you can find online today are either dynamic or static websites. Both these techniques of have certain advantages and disadvantages based on which they are chosen. The righ... [Author: Alan Smith - Web Design and Development - June 06, 2010]

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  • Should I charge for travel expenses as a contractor?

    - by Keith
    Here's a question for all my fellow contractors - I'm paid quite handsomely for my normal contracted hours (any overtime is billed at the same rate) but do you think it fair to bill for travel time to the other end of the country (regional office) when this takes place outside of the normal working day (or overlapping into the evening) as well as actual time holed up in a hotel room when you get there, ready for a normal working day the next day, along with the return journey? Petrol is claimed normally (nominal rate) and hotel is covered by the company I contract for.

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  • Basics For Having Meaningful Websites For Companies

    A good website reflects organization and its services to the audiences online. For an effective website well thought out web design is must. Even the minute details should be well cared for to optimi... [Author: Alan Smith - Web Design and Development - June 08, 2010]

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  • Build Website with Flash Templates

    Flash website design is one step further in website designing. The way websites looked have undergone drastic change, apart from information source they have become more interactive in nature. Insert... [Author: Alan Smith - Web Design and Development - June 03, 2010]

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  • How Content Management System is Useful

    Internet has open doors for small, medium as well as big business ventures to promote them online. The work of website development does not stop at mere web designing, but it has to be used best to i... [Author: Alan Smith - Computers and Internet - May 14, 2010]

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  • Stairway to MDX - Level 10: “Relative” Member Functions: .CurrentMember, .PrevMember, and .NextMember

    SSAS Maestro, SQL Server MVP and Business Intelligence Architect Bill Pearson introduces three “major players” within the MDX “relative” functions. These basic, but highly employed, functions include the .CurrentMember, .PrevMember and .NextMember functions. Check SQL Server performance at a glanceWe consulted 1000 SQL Server professionals to make SQL Monitor’s UI as clear as possible. Start monitoring with a free trial.

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  • Stairway to MDX - Level 2: The Ordinal Function

    Business Intelligence Architect Bill Pearson introduces the MDX Ordinal Function, as a means for generating lists and for conditionally presenting calculations. He also demonstrates the use of the function in creating datasets to support report parameter picklists. Develop seamlessly between Management Studio and Visual StudioSQL Connect is a Visual Studio add-in that makes it easy to keep your database and Visual Studio project in sync.

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  • CNC Information - Data Storage and Transfer

    A CNC machine must be tried when there is need to improve speed and accuracy. The machine performs better in doing repetitive tasks and getting large jobs done quicker. Woodworking shops or industria... [Author: Scheygen Smith - Computers and Internet - March 21, 2010]

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  • Is there any way to retire a AT&T Yahoo Email Account

    - by KindaSortaAsking
    Here are the facts as I (pretty sure) know them. Yahoo handles AT&T's DSL email accounts. I've called AT&T tech support and customer service and they say they can't help, but there has GOT to be a way to do this. It's too simple of a thing not to be able to do. I got behind on my dsl bill and my account got suspended. When I paid my bill, they said my account had been deactivated and I had to get a new account. When I tried to register my account with my old email address it would not let me, saying it was in use. I used a new email. The old email address is tied to a dsl account that can NEVER be reactivated. There has got to be a way to retire the old email address so that I can re-create it as a subaccount on my new dsl account. I'm not interested in anything that was in the old account (emails, addresses, etc) - I just want the address back.

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  • Linq-to-XML query to select specific sub-element based on additional criteria

    - by BrianLy
    My current LINQ query and example XML are below. What I'd like to do is select the primary email address from the email-addresses element into the User.Email property. The type element under the email-address element is set to primary when this is true. There may be more than one element under the email-addresses but only one will be marked primary. What is the simplest approach to take here? Current Linq Query (User.Email is currently empty): var users = from response in xdoc.Descendants("response") where response.Element("id") != null select new User { Id = (string)response.Element("id"), Name = (string)response.Element("full-name"), Email = (string)response.Element("email-addresses"), JobTitle = (string)response.Element("job-title"), NetworkId = (string)response.Element("network-id"), Type = (string)response.Element("type") }; Example XML: <?xml version="1.0" encoding="UTF-8"?> <response> <response> <contact> <phone-numbers/> <im> <provider></provider> <username></username> </im> <email-addresses> <email-address> <type>primary</type> <address>[email protected]</address> </email-address> </email-addresses> </contact> <job-title>Account Manager</job-title> <type>user</type> <expertise nil="true"></expertise> <summary nil="true"></summary> <kids-names nil="true"></kids-names> <location nil="true"></location> <guid nil="true"></guid> <timezone>Eastern Time (US &amp; Canada)</timezone> <network-name>Domain</network-name> <full-name>Alice</full-name> <network-id>79629</network-id> <stats> <followers>2</followers> <updates>4</updates> <following>3</following> </stats> <mugshot-url> https://assets3.yammer.com/images/no_photo_small.gif</mugshot-url> <previous-companies/> <birth-date></birth-date> <name>alice</name> <web-url>https://www.yammer.com/domain.com/users/alice</web-url> <interests nil="true"></interests> <state>active</state> <external-urls/> <url>https://www.yammer.com/api/v1/users/1089943</url> <network-domains> <network-domain>domain.com</network-domain> </network-domains> <id>1089943</id> <schools/> <hire-date nil="true"></hire-date> <significant-other nil="true"></significant-other> </response> <response> <contact> <phone-numbers/> <im> <provider></provider> <username></username> </im> <email-addresses> <email-address> <type>primary</type> <address>[email protected]</address> </email-address> </email-addresses> </contact> <job-title>Office Manager</job-title> <type>user</type> <expertise nil="true"></expertise> <summary nil="true"></summary> <kids-names nil="true"></kids-names> <location nil="true"></location> <guid nil="true"></guid> <timezone>Eastern Time (US &amp; Canada)</timezone> <network-name>Domain</network-name> <full-name>Bill</full-name> <network-id>79629</network-id> <stats> <followers>3</followers> <updates>1</updates> <following>1</following> </stats> <mugshot-url> https://assets3.yammer.com/images/no_photo_small.gif</mugshot-url> <previous-companies/> <birth-date></birth-date> <name>bill</name> <web-url>https://www.yammer.com/domain.com/users/bill</web-url> <interests nil="true"></interests> <state>active</state> <external-urls/> <url>https://www.yammer.com/api/v1/users/1089920</url> <network-domains> <network-domain>domain.com</network-domain> </network-domains> <id>1089920</id> <schools/> <hire-date nil="true"></hire-date> <significant-other nil="true"></significant-other> </response> </response>

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  • Crypted_password is null when using Authlogic to save a user

    - by kareem
    i'm getting a strange error on my production install when i try and create a new user using AL: ActiveRecord::StatementInvalid: Mysql::Error: Column 'crypted_password' cannot be null: INSERT INTO users especially strange b/c it works as expected on my local box. RUnning Rails 2.3.2 and ruby 1.8.7 on both boxes. user.rb: class User < ActiveRecord::Base before_create :set_username acts_as_authentic do |c| c.require_password_confirmation = false c.login_field = "email" c.validates_length_of_password_field_options = {:minimum => 4} c.validate_login_field = false #don't validate email field with additional validations end end Here's output from my production console: >> u = User.new => #<User id: nil, username: nil, email: nil, crypted_password: nil, password_salt: nil, persistence_token: nil, single_access_token: nil, perishable_token: nil, login_count: 0, failed_login_count: 0, last_request_at: nil, current_login_at: nil, last_login_at: nil, current_login_ip: nil, last_login_ip: nil, created_at: nil, updated_at: nil, is_admin: 0, first_name: nil, last_name: nil> >> u.full_name = 'john smith' => "john smith" >> u.password = 'test' => "test" >> u.email = '[email protected]' => "[email protected]" >> u.valid? => true >> u.save ActiveRecord::StatementInvalid: Mysql::Error: Column 'crypted_password' cannot be null: INSERT INTO `users` (`single_access_token`, `last_request_at`, `created_at`, `crypted_password`, `perishable_token`, `updated_at`, `username`, `failed_login_count`, `current_login_ip`, `password_salt`, `current_login_at`, `is_admin`, `persistence_token`, `login_count`, `last_name`, `last_login_ip`, `last_login_at`, `email`, `first_name`) VALUES('B-XSXwhO7hkbtISIOyEq', NULL, '2009-07-31 01:10:44', NULL, 'FK3mYS2Tp5Tzeq5IXE1z', '2009-07-31 01:10:44', 'john', 0, NULL, NULL, NULL, 0, '2c76b645f761eb3509353290e93874cecdb68a63caa165812ab1b126d63660757090ecf69995caef9e78f93d070b524e2542b3fec4ee050726088c2a9fdb0c9f', 0, 'smith', NULL, NULL, '[email protected]', 'john') from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/connection_adapters/abstract_adapter.rb:212:in `log' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/connection_adapters/mysql_adapter.rb:320:in `execute' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/connection_adapters/abstract/database_statements.rb: 259:in `insert_sql' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/connection_adapters/mysql_adapter.rb:330:in `insert_sql' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/connection_adapters/abstract/database_statements.rb: 44:in `insert_without_query_dirty' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/connection_adapters/abstract/query_cache.rb:18:in `insert' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/base.rb:2902:in `create_without_timestamps' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/timestamp.rb:29:in `create_without_callbacks' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/callbacks.rb:266:in `create' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/base.rb:2868:in `create_or_update_without_callbacks' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/callbacks.rb:250:in `create_or_update' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/base.rb:2539:in `save_without_validation' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/validations.rb:1009:in `save_without_dirty' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/dirty.rb:79:in `save_without_transactions' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/transactions.rb:229:in `send' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/transactions.rb:229:in `with_transaction_returning_status' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/connection_adapters/abstract/database_statements.rb: 136:in `transaction' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/transactions.rb:182:in `transaction' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/transactions.rb:228:in `with_transaction_returning_status' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/transactions.rb:196:in `save' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/transactions.rb:208:in `rollback_active_record_state!' from /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.2/lib/ active_record/transactions.rb:196:in `save' No idea why this is happening, and especially why this saves a new user on dev but not on production. Any help is much appreciated, thanks! edit: using Apache & Passenger 2.2.4

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  • MySQL Query GROUP_CONCAT Over Multiple Rows

    - by PeteGO
    I'm getting name and address data out of generic question / answer data to create some kind of normalised reporting database. The query I've got uses group_concat and works for individual sets of questions but not for multiple sets. I've tried to simplify what I'm doing by using just forename and surname and just 3 records, 2 for 1 person and 1 for another. In reality though there are more than 300,000 records. Example of results with qs.Id = 1. QuestionSetId Forename Surname ------------------------------------------------------- 1 Bob Jones Example of results with qs.Id IN (1, 2, 3). QuestionSetId Forename Surname ------------------------------------------------------- 3 Bob,Bob,Frank Jones,Jones,Smith What I would like to see for qs.Id IN (1, 2, 3). QuestionSetId Forename Surname ------------------------------------------------------- 1 Bob Jones 2 Bob Jones 3 Frank Smith So how can I make the 2nd example return a separate row for each set of name and address information? I realise the current way the data is stored is "questionable" but I cannot change the way the data is stored. I can get sets of individual answers but not sure how to combine the others. My simplified Schema that I cannot change: CREATE TABLE StaticQuestion ( Id INT NOT NULL, StaticText VARCHAR(500) NOT NULL); CREATE TABLE Question ( Id INT NOT NULL, Text VARCHAR(500) NOT NULL); CREATE TABLE StaticQuestionQuestionLink ( Id INT NOT NULL, StaticQuestionId INT NOT NULL, QuestionId INT NOT NULL, DateEffective DATETIME NOT NULL); CREATE TABLE Answer ( Id INT NOT NULL, Text VARCHAR(500) NOT NULL); CREATE TABLE QuestionSet ( Id INT NOT NULL, DateEffective DATETIME NOT NULL); CREATE TABLE QuestionAnswerLink ( Id INT NOT NULL, QuestionSetId INT NOT NULL, QuestionId INT NOT NULL, AnswerId INT NOT NULL, StaticQuestionId INT NOT NULL); Some example data for only forename and surname. INSERT INTO StaticQuestion (Id, StaticText) VALUES (1, 'FirstName'), (2, 'LastName'); INSERT INTO Question (Id, Text) VALUES (1, 'What is your first name?'), (2, 'What is your forename?'), (3, 'What is your Surname?'); INSERT INTO StaticQuestionQuestionLink (Id, StaticQuestionId, QuestionId, DateEffective) VALUES (1, 1, 1, '2001-01-01'), (2, 1, 2, '2008-08-08'), (3, 2, 3, '2001-01-01'); INSERT INTO Answer (Id, Text) VALUES (1, 'Bob'), (2, 'Jones'), (3, 'Bob'), (4, 'Jones'), (5, 'Frank'), (6, 'Smith'); INSERT INTO QuestionSet (Id, DateEffective) VALUES (1, '2002-03-25'), (2, '2009-05-05'), (3, '2009-08-06'); INSERT INTO QuestionAnswerLink (Id, QuestionSetId, QuestionId, AnswerId, StaticQuestionId) VALUES (1, 1, 1, 1, 1), (2, 1, 3, 2, 2), (3, 2, 2, 3, 1), (4, 2, 3, 4, 2), (5, 3, 2, 5, 1), (6, 3, 3, 6, 2); Just in case SQLFiddle is down here are the 3 queries from the examples I've linked to: 1: - working query but only on 1 set of data. SELECT MAX(QuestionSetId) AS QuestionSetId, GROUP_CONCAT(Forename) AS Forename, GROUP_CONCAT(Surname) AS Surname FROM (SELECT x.QuestionSetId, CASE x.StaticQuestionId WHEN 1 THEN Text END AS Forename, CASE x.StaticQuestionId WHEN 2 THEN Text END AS Surname FROM (SELECT (SELECT link.StaticQuestionId FROM StaticQuestionQuestionLink link WHERE link.Id = qa.QuestionId AND link.DateEffective <= qs.DateEffective AND link.StaticQuestionId IN (1, 2) ORDER BY link.DateEffective DESC LIMIT 1) AS StaticQuestionId, a.Text, qa.QuestionSetId FROM QuestionSet qs INNER JOIN QuestionAnswerLink qa ON qs.Id = qa.QuestionSetId INNER JOIN Answer a ON qa.AnswerId = a.Id WHERE qs.Id IN (1)) x) y 2: - working query but undesired results on multiple sets of data. SELECT MAX(QuestionSetId) AS QuestionSetId, GROUP_CONCAT(Forename) AS Forename, GROUP_CONCAT(Surname) AS Surname FROM (SELECT x.QuestionSetId, CASE x.StaticQuestionId WHEN 1 THEN Text END AS Forename, CASE x.StaticQuestionId WHEN 2 THEN Text END AS Surname FROM (SELECT (SELECT link.StaticQuestionId FROM StaticQuestionQuestionLink link WHERE link.Id = qa.QuestionId AND link.DateEffective <= qs.DateEffective AND link.StaticQuestionId IN (1, 2) ORDER BY link.DateEffective DESC LIMIT 1) AS StaticQuestionId, a.Text, qa.QuestionSetId FROM QuestionSet qs INNER JOIN QuestionAnswerLink qa ON qs.Id = qa.QuestionSetId INNER JOIN Answer a ON qa.AnswerId = a.Id WHERE qs.Id IN (1, 2, 3)) x) y 3: - working query on multiple sets of data only on 1 field (answer) though. SELECT qs.Id AS QuestionSet, a.Text AS Answer FROM QuestionSet qs INNER JOIN QuestionAnswerLink qalink ON qs.Id = qalink.QuestionSetId INNER JOIN StaticQuestionQuestionLink sqqlink ON qalink.QuestionId = sqqlink.QuestionId INNER JOIN Answer a ON qalink.AnswerId = a.Id WHERE sqqlink.StaticQuestionId = 1 /* FirstName */ AND sqqlink.DateEffective = (SELECT DateEffective FROM StaticQuestionQuestionLink WHERE StaticQuestionId = 1 AND DateEffective <= qs.DateEffective ORDER BY DateEffective DESC LIMIT 1)

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