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  • Django: How can I delete a formset entry if one of it's data is blank?

    - by mkret
    Hi, I have the following scenario: I have a form with data that does not need translation and a formset with a textfield that should be translated into an undefined amount of languages. Both parts are bound to a model. Each translated text is kept in a model with a foreign key that binds it to the untranslatable data. Something like: class Person(models.Model): name = models.CharField(max_length=60) birth_date = models.DateField() class PersonBio(models.Model): person = models.ForeignKey(Person) locale = models.CharField(max_length=10) bio = models.TextField() Each form in the formset has 2 fields: A textfield (with the translated text) A locale field (with the language into which the text was translated) I've got it working with no problems until I tryed to change it's normal behaviour. I wanted to eliminate the need for the DELETE field by deleting an instance of the translated text if the textfield was left blank. I've googled quite a lot now and read the whole documentation for forms, formsets and model validation but had no luck. To be honest, I couldn't even think of a solution. Where should I implement this? On a Form clean() method? On the view? Somewhere in the Fieldset? Fieldset's save() method, maybe? I'll keep trying to find a way to do that, but any help/tip/clue is appreciated. Thanks in advance.

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  • Sorting and indexing into a list in a Django template?

    - by slypete
    How can you perform complex sorting on an object before passing it to the template? For example, here is my view: @login_required def overview(request): physicians = PhysicianGroup.objects.get(pk=physician_group).physicians for physician in physicians.all(): physician.service_patients.order_by('bed__room__unit', 'bed__room__order', 'bed__order') return render_to_response('hospitalists/overview.html', RequestContext(request, {'physicians': physicians,})) The physicians object is not ordered correctly in the template. Why not? Additionally, how do you index into a list inside the template? For example, (this doesn't work): {% for note_type in note_types %} <div><h3>{{ note_type }}</h3> {% for notes in note_sets.index(parent.forloop.counter0) %} #only want to display the notes of this note_type! {% for note in notes %} <p>{{ note }}</p> {% endfor %} {% endfor %} </div> {% endfor %}

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  • Can I filter a django model with a python list?

    - by Rhubarb
    Say I have a model object 'Person' defined, which has a field called 'Name'. And I have a list of people: l = ['Bob','Dave','Jane'] I would like to return a list of all Person records where the first name is not in the list of names defined in l. What is the most pythonic way of doing this?

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  • How do I memoize expensive calculations on Django model objects?

    - by David Eyk
    I have several TextField columns on my UserProfile object which contain JSON objects. I've also defined a setter/getter property for each column which encapsulates the logic for serializing and deserializing the JSON into python datastructures. The nature of this data ensures that it will be accessed many times by view and template logic within a single Request. To save on deserialization costs, I would like to memoize the python datastructures on read, invalidating on direct write to the property or save signal from the model object. Where/How do I store the memo? I'm nervous about using instance variables, as I don't understand the magic behind how any particular UserProfile is instantiated by a query. Is __init__ safe to use, or do I need to check the existence of the memo attribute via hasattr() at each read? Here's an example of my current implementation: class UserProfile(Model): text_json = models.TextField(default=text_defaults) @property def text(self): if not hasattr(self, "text_memo"): self.text_memo = None self.text_memo = self.text_memo or simplejson.loads(self.text_json) return self.text_memo @text.setter def text(self, value=None): self.text_memo = None self.text_json = simplejson.dumps(value)

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  • How do I flag only one of the formsets in django admin ?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). My first solution was to override the validation of the formset but did understand how to do this. (is_correct is displayed as checkbox, and I'd display an error that only one is_correct should be selected.)

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  • How do I modify the HttpResponse object in django ?

    - by Rohit
    I need the html returned using render_to_response to be escaped. I am unable to find any suitable documentation. Can someone point in some direction ? the code is : return render_to_response(template_name, {return render_to_response(template_name, { 'form': form, redirect_field_name: redirect_to, 'site': current_site, 'site_name': current_site.name, }, context_instance=RequestContext(request)) Here I need the response html text to be escaped. I way I know is reading template file in string and escaping it with re.escape() and then rendering it. whats a cleaner and simpler way to do that ??

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  • Django, Redirecting staff from login to the admin site.

    - by Francisco Gomez
    So my site basically has 2 kinds of ways to login, one of them is for the common users, who get the regular screen that asks them for username and password, the other way its for staff. The staff login should redirect them to the admin site after logging in, but for some reason the redirect doesnt happen, it stays on the same login page. I use this condition on the login view. if user is not None and user.is_active and user.is_staff: auth.login(request,user) return HttpResponseRedirect("/admin/") The admin site its up and running in my url configuration and everything, but i dont know if this is the correct way to redirect to the admin site already on session. Thanks, any help would be appreciated.

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  • Django: How to iterate over formsets and access cleaned data?

    - by Mark
    What if I want to do something with my formset other than immediately saving it? How can I do this? for form in vehicles_formset.forms: listing.id = None listing.vehicle_year = form.cleaned_data['year'] listing.vehicle_make = form.cleaned_data['make'] listing.vehicle_model = form.cleaned_data['model'] listing.vin = form.cleaned_data['vin'] listing.vehicle_runs = form.cleaned_data['runs'] listing.vehicle_convertible = form.cleaned_data['convertible'] listing.vehicle_modified = form.cleaned_data['modified'] listing.save() (Thus creating multiple listings) Apparently cleaned_data does not exist. There's a bunch of stuff in the data dict like form-0-year but it's pretty useless to me like that.

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  • How to preprocess a Django model field value before return?

    - by Satoru.Logic
    Hi, all. I have a Note model class like this: class Note(models.Model): author = models.ForeignKey(User, related_name='notes') content = NoteContentField(max_length=256) NoteContentField is a custom sub-class of CharField that override the to_python method in purpose of doing some twitter-text-conversion processing. class NoteContentField(models.CharField): __metaclass__ = models.SubfieldBase def to_python(self, value): value = super(NoteContentField, self).to_python(value) from ..utils import linkify return mark_safe(linkify(value)) However, this doesn't work. When I save a Note object like this: note = Note(author=request.use, content=form.cleaned_data['content']) The conversed value is saved into the database, which is not what I wanna see. Would you please tell me what's wrong with this? Thanks in advance.

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  • How to extend models of other applications in Django?

    - by culebrón
    I have a small app with Category model and want to make a required foreign key referencing it from Photologue Gallery model. What's the right approach? I can make many-to-many field in Category, but this way it will not be required in Gallery. Use "register" and modify the Gallery model? Inherit it in my app?

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  • Django Querysets -- need a less expensive way to do this..

    - by rh0dium
    Hi all, I have a problem with some code and I believe it is because of the expense of the queryset. I am looking for a much less expensive (in terms of time) way to to this.. log.info("Getting Users") employees = Employee.objects.filter(is_active = True) log.info("Have Users") if opt.supervisor: if opt.hierarchical: people = getSubs(employees, " ".join(args)) else: people = employees.filter(supervisor__name__icontains = " ".join(args)) else: log.info("Filtering Users") people = employees.filter(name__icontains = " ".join(args)) | \ employees.filter(unix_accounts__username__icontains = " ".join(args)) log.info("Filtered Users") log.info("Processing data") np = [] for person in people: unix, p4, bugz = "No", "No", "No" if len(person.unix_accounts.all()): unix = "Yes" if len(person.perforce_accounts.all()): p4 = "Yes" if len(person.bugzilla_accounts.all()): bugz = "Yes" if person.cell_phone != "": exphone = fixphone(person.cell_phone) elif person.other_phone != "": exphone = fixphone(person.other_phone) else: exphone = "" np.append({ 'name':person.name, 'office_phone': fixphone(person.office_phone), 'position': person.position, 'location': person.location.description, 'email': person.email, 'functional_area': person.functional_area.name, 'department': person.department.name, 'supervisor': person.supervisor.name, 'unix': unix, 'perforce': p4, 'bugzilla':bugz, 'cell_phone': fixphone(exphone), 'fax': fixphone(person.fax), 'last_update': person.last_update.ctime() }) log.info("Have data") Now this results in a log which looks like this.. 19:00:55 INFO phone phone Getting Users 19:00:57 INFO phone phone Have Users 19:00:57 INFO phone phone Processing data 19:01:30 INFO phone phone Have data As you can see it's taking over 30 seconds to simply iterate over the data. That is way too expensive. Can someone clue me into a more efficient way to do this. I thought that if I did the first filter that would make things easier but seems to have no effect. I'm at a loss on this one. Thanks To be clear this is about 1500 employees -- Not too many!!

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  • Django says the "id may not be NULL" but why is it?

    - by Oli
    I'm going crazy today. I just tried to insert a new record and it threw back a "post_blogpost.id may not be NULL" error. Here's my model: class BlogPost(models.Model): title = models.CharField(max_length=100) slug = models.SlugField(max_length=100) who = models.ForeignKey(User, default=1) when = models.DateTimeField() intro = models.TextField(blank=True, null=True) content = models.TextField(blank=True, null=True) counter = models.PositiveIntegerField(default=0) published = models.BooleanField(default=False) css = models.TextField(blank=True, null=True) class Meta: ordering = ('-when', 'id') There are a number of functions beneath the model too but I won't include them in full here. Their names are: content_cache_key, clear_cache, __unicode__, reads, read, processed_content. I'm adding through the admin... And I'm running out of hair.

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  • How to limit fields in django-admin depending on user?

    - by minder
    I suppose similar problem would have been discussed here, but I couldn't find it. Let's suppose I have an Editor and a Supervisor. I want the Editor to be able to add new content (eg. a news post) but before publication it has to be acknowledged by Supervisor. When Editor lists all items, I want to set some fields on the models (like an 'ack' field) as read-only (so he could know what had been ack'ed and what's still waiting approval) but the Supervisor should be able to change everything (list_editable would be perfect) What are the possible solutions to this problem?

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  • Django admin breaking with non-default primary_key for model with a m2m relationship ?

    - by Gj
    I have a simple Post model with a m2m field to a Tag model. The Tag had for some reason to use a non default primary key. Inside the admin page for a Post, the labels for the multiple selection field for Tags appear, but not the input field itself. I also tried using the filter_horizontal for the tags, but still only the labels appear without the actual field. Any ideas why it breaks and/or workarounds? Thanks!

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  • How do I store multiple copies of the same field in Django?

    - by Alistair
    I'm storing OLAC metadata which describes linguistic resources. Many of the elements of the metadata are repeatable -- for example, a resource can have two languages, three authors and four dates associated with it. Is there any way of storing this in one model? It seems like overkill to define a model for each repeatable metadata element -- especially since the models will only have one field: it's value.

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  • Django many-to-many relationship to self with extra data, how do I select from a certain direction?

    - by Jake
    I have some hierarchical data where each Set can have many members and can belong to more than one Set(group) Here are the models: class Set(models.Model): ... groups = models.ManyToManyField('self', through='Membership', symmetrical=False) members = models.ManyToManyField('self', through='Membership', symmetrical=False) class Membership(models.Model): group = models.ForeignKey( Set, related_name='Members' ) member = models.ForeignKey( Set, related_name='Groups' ) order = models.IntegerField( default=-1 ) I want to know how to get all the members or all the groups for a Set instance. I think I can do it as follows, but it's not very logical, can anyone tell me what's going on and how I should be doing it? # This gives me a set of Sets # Which seems to be the groups this Set belongs to set_instance.set_set.all() # These give me a set of Memberships, not Sets set_instance.Members.all() set_instance.Groups.all() # These they both return a set of Sets # which seem to be the members of this one set_instance.members.all() set_instance.groups.all()

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  • How can you dispatch on request method in Django URLpatterns?

    - by rcampbell
    It's clear how to create a URLPattern which dispatches from a URL regex: (r'^books/$', books), where books can further dispatch on request method: def books(request): if request.method == 'POST': ... else ... I'd like to know if there is an idiomatic way to include the request method inside the URLPattern, keeping all dispatch/route information in a single location, such as: (r'^books/$', GET, retrieve-book), (r'^books/$', POST, update-books), (r'^books/$', PUT, create-books),

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  • Right way to return proxy model instance from a base model instance in Django ?

    - by sotangochips
    Say I have models: class Animal(models.Model): type = models.CharField(max_length=255) class Dog(Animal): def make_sound(self): print "Woof!" class Meta: proxy = True class Cat(Animal): def make_sound(self): print "Meow!" class Meta: proxy = True Let's say I want to do: animals = Animal.objects.all() for animal in animals: animal.make_sound() I want to get back a series of Woofs and Meows. Clearly, I could just define a make_sound in the original model that forks based on animal_type, but then every time I add a new animal type (imagine they're in different apps), I'd have to go in and edit that make_sound function. I'd rather just define proxy models and have them define the behavior themselves. From what I can tell, there's no way of returning mixed Cat or Dog instances, but I figured maybe I could define a "get_proxy_model" method on the main class that returns a cat or a dog model. Surely you could do this, and pass something like the primary key and then just do Cat.objects.get(pk = passed_in_primary_key). But that'd mean doing an extra query for data you already have which seems redundant. Is there any way to turn an animal into a cat or a dog instance in an efficient way? What's the right way to do what I want to achieve?

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  • why isn't my id showing up in django admin list?

    - by FurtiveFelon
    Hi all, I have a class Task(models.Model), and i didn't define id field explicitly (since it defines automatically for you). I checked in the database, it exists for the Task. Now i would like to display it in the list via list_display property in admin.ModelAdmin. I have a bunch of things in there, only id is not showing up for any of the rows i have. Everything else works fine. Anyone know anything special i have to do to get id to display? Thanks a lot! Jason

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  • How to add default value on django save form?

    - by Ignacio
    I have an object Task and a form that saves it. I want to automatically asign created_by field to the currently logged in user. So, my view is this: def new_task(request, task_id=None): message = None if task_id is not None: task = Task.objects.get(pk=task_id) message = 'TaskOK' submit = 'Update' else: task = Task(created_by = GPUser(user=request.user)) submit = 'Create' if request.method == 'POST': # If the form has been submitted... form = TaskForm(request.POST, instance=task) if form.is_valid(): task = form.save(commit=False); task.created_by = GPUser(user=request.user) task.save() if message == None: message = 'taskOK' return tasks(request, message) else: form = TaskForm(instance=task) return custom_render('user/new_task.html', {'form': form, 'submit': submit, 'task_id':task.id}, request) The problem is, you guessed, the created_by field doesn't get saved. Any ideas? Thanks

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