Search Results

Search found 5154 results on 207 pages for 'expression evaluation'.

Page 59/207 | < Previous Page | 55 56 57 58 59 60 61 62 63 64 65 66  | Next Page >

  • .Net lambda expression-- where did this parameter come from?

    - by larryq
    I'm a lambda newbie, so if I'm missing vital information in my description please tell me. I'll keep the example as simple as possible. I'm going over someone else's code and they have one class inheriting from another. Here's the derived class first, along with the lambda expression I'm having trouble understanding: class SampleViewModel : ViewModelBase { private ICustomerStorage storage = ModelFactory<ICustomerStorage>.Create(); public ICustomer CurrentCustomer { get { return (ICustomer)GetValue(CurrentCustomerProperty); } set { SetValue(CurrentCustomerProperty, value); } } private int quantitySaved; public int QuantitySaved { get { return quantitySaved; } set { if (quantitySaved != value) { quantitySaved = value; NotifyPropertyChanged(p => QuantitySaved); //where does 'p' come from? } } } public static readonly DependencyProperty CurrentCustomerProperty; static SampleViewModel() { CurrentCustomerProperty = DependencyProperty.Register("CurrentCustomer", typeof(ICustomer), typeof(SampleViewModel), new UIPropertyMetadata(ModelFactory<ICustomer>.Create())); } //more method definitions follow.. Note the call to NotifyPropertyChanged(p => QuantitySaved) bit above. I don't understand where the "p" is coming from. Here's the base class: public abstract class ViewModelBase : DependencyObject, INotifyPropertyChanged, IXtremeMvvmViewModel { public event PropertyChangedEventHandler PropertyChanged; protected virtual void NotifyPropertyChanged<T>(Expression<Func<ViewModelBase, T>> property) { MvvmHelper.NotifyPropertyChanged(property, PropertyChanged); } } There's a lot in there that's not germane to the question I'm sure, but I wanted to err on the side of inclusiveness. The problem is, I don't understand where the 'p' parameter is coming from, and how the compiler knows to (evidently?) fill in a type value of ViewModelBase from thin air? For fun I changed the code from 'p' to 'this', since SampleViewModel inherits from ViewModelBase, but I was met with a series of compiler errors, the first one of which statedInvalid expression term '=>' This confused me a bit since I thought that would work. Can anyone explain what's happening here?

    Read the article

  • How to detect what allowed character in current Regular Expression by using JavaScript?

    - by Soul_Master
    In my web application, I create some framework that use to bind model data to control on page. Each model property has some rule like string length, not null and regular expression. Before submit page, framework validate any binded control with defined rules. So, I want to detect what character that is allowed in each regular expression rule like the following example. "^[0-9]$" allow only digit characters like 1, 2, 3. "^[a-zA-Z_][a-zA-Z_-0-9]+$" allow only a-z, - and _ characters However, this function should not care about grouping, positioning of allowed character. It just tells about possible characters only. By the way, complex regular expression like find two words near(\bword1\W+(?:\w+\W+){1,6}?word2\b) must be ignore to verify and it should return any characters is possible. Do you have any idea for creating this function? PS. I know it easy to create specified function like numeric only for allowing only digit characters. But I need share/reuse same piece of code both data tier(contains all model validator) and UI tier without modify anything. Thanks

    Read the article

  • Which is more maintainable -- boolean assignment via if/else or boolean expression?

    - by Bret Walker
    Which would be considered more maintainable? if (a == b) c = true; else c = false; or c = (a == b); I've tried looking in Code Complete, but can't find an answer. I think the first is more readable (you can literally read it out loud), which I also think makes it more maintainable. The second one certainly makes more sense and reduces code, but I'm not sure it's as maintainable for C# developers (I'd expect to see this idiom more in, for example, Python).

    Read the article

  • Python 3.4 adds re.fullmatch()

    - by Jan Goyvaerts
    Python 3.4 does not bring any changes to its regular expression syntax compared to previous 3.x releases. It does add one new function to the re module called fullmatch(). This function takes a regular expression and a subject string as its parameters. It returns True if the regular expression can match the string entirely. It returns False if the string cannot be matched or if it can only be matched partially. This is useful when using a regular expression to validate user input. Do note that fullmatch() will return True if the subject string is the empty string and the regular expression can find zero-length matches. A zero-length match of a zero-length string is a complete match. So if you want to check whether the user entered a sequence of digits, use \d+ rather than \d* as the regex.

    Read the article

  • Regular Expression for any number divisible by 60 using C# .Net ?

    - by Steve Johnson
    Hi there, I need to apply validation on input time intervals that are taken in as seconds. Now i am not really good at Regular expressions. So can any body help making a regular expression that can test whether a number is divisible by 60. I was wondering if i could use to test one that check that the number is divisible by 10 and then check whether the same is divisible by 6. For number divisible by 10 here [\d*0] is the expression i guess. Please correct me if i am wrong. Hope somebody solves my problem. Thanks

    Read the article

  • Can a repeated piece of regular expression create multiple groups? Such as this example...

    - by Yousui
    Hi guys, I'm using RUBY 's regular expression to deal with text such as ${1:aaa|bbbb} ${233:aaa | bbbb | ccc ccccc } ${34: aaa | bbbb | cccccccc |d} ${343: aaa | bbbb | cccccccc |dddddd ddddddddd} ${3443:a aa|bbbb|cccccccc|d} ${353:aa a| b b b b | c c c c c c c c | dddddd} I want to get the trimed text between each pipe line. For example, for the first line of my upper example, I want to get the result aaa and bbbb, for the second line, I want aaa, bbbb and ccc ccccc. Now I have wrote a piece of regular expression and a piece of ruby code to test it: array = "${33:aaa|bbbb|cccccccc}".scan(/\$\{\s*(\d+)\s*:(\s*[^\|]+\s*)(?:\|(\s*[^\|]+\s*))+\}/) puts array Now my problem is the (?:\|(\s*[^\|]+\s*))+ part can't create multiple groups. I don't know how to solve this problem, because the number of text I need in each line is variable. Anyone can help? Great thanks.

    Read the article

  • What is the MM/DD/YYYY regular expression and how do I use it in php?

    - by zeckdude
    I found the regular expression for MM/DD/YYYY at http://www.regular-expressions.info/regexbuddy/datemmddyyyy.html but I don't think I am using it correctly. Here's my code: $date_regex = '(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d'; $test_date = '03/22/2010'; if(preg_match($date_regex, $test_date)) { echo 'this date is formatted correctly'; } else { echo 'this date is not formatted correctly'; } When I run this, it still echoes 'this date is not formatted correctly', when it should be saying the opposite. How do I set this regular expression up in php?

    Read the article

  • Is it possible to "learn" a regular expression by user-provided examples?

    - by DR
    Is it possible to "learn" a regular expression by user-provided examples? To clarify: I do not want to learn regular expressions. I want to create a program which "learns" a regular expression from examples which are interactively provided by a user, perhaps by selecting parts from a text or selecting begin or end markers. Is it possible? Are there algorithms, keywords, etc. which I can Google for? EDIT: Thank you for the answers, but I'm not interested in tools which provide this feature. I'm looking for theoretical information, like papers, tutorials, source code, names of algorithms, so I can create something for myself.

    Read the article

  • Can I compile and execute C# expression without saving the assembly to disk?

    - by Sasha
    I can compile, get an instance and invoke a method of any C# type programmaticaly. There lots of info on that, including the StackOverflow (http://stackoverflow.com/questions/53844/how-can-i-evaluate-a-c-expression-dynamically). My problem is that I'm in the web environment and cannot save anything to /bin directory. I can compile "in-memory" as the above mentioned link suggests but then I won't be able to "unload" my custom assembly from the current AppDomain. After a while that will become a huge memory problem. Is it possible to open a new AppDomain, compile new assembly "in-memory", evaluate some expression or access some member of that assembly inside of that new AppDomain and kill that AppDomain safely when done, all that without saving anything to a hard drive? Thanks in advance for any links, suggestions, etc.

    Read the article

  • How do we match any single character including line feed in Perl regular expression?

    - by bobo
    I would like to use UltraEdit regular expression (perl) to replace the following text with some other text in a bunch of html files: <style type="text/css"> #some-id{} .some-class{} //many other css styles follow </style> I tried to use <style type="text/css">.*</style> but of course it wouldn't match anything because the dot matches any character except line feed. I would like to match line feed as well and the line feed maybe either \r\n or \n. How should the regular expression look like? Many thanks to you all.

    Read the article

  • Why isn't 'ether proto \ip host host' a legal tcpdump expression?

    - by Ezequiel Garzon
    In its description of valid tcpdump expressions, the pcap-filter man pages state: The filter expression consists of one or more primitives. Primitives usually consist of an id (name or number) preceded by one or more qualifiers. In turn, these qualifiers are type, dir and proto. So far so good, but further down we find this: ip host host which is equivalent to: ether proto \ip and host host In the first case, ip and host are, respectively, proto and type. What pattern does ether proto \ip follow? Isn't that, as a whole, a proto qualifier? If so, why isn't (a properly escaped) 'ether proto \ip host host' legal (no and)?

    Read the article

  • Shoes packager problem

    - by DorianG
    Hi, I used packager to make an executable file for the following code: Shoes.app do stack :margin => 10 do @edit = edit_box :width => 1.0 do @para.text = @edit.text end @para = para "" end end then I got error message: Error in C:/Program Files/Common Files/Shoes/0.r1134/lib/shoes.rb line 394utf.rb: 10: compiler error utf.rb: 10: Invalid char '\377' in expression utf.rb: 10: Invalid char '\337' in expression utf.rb: 10: Invalid char '\337' in expression utf.rb: 10: Invalid char '\331' in expression utf.rb: 10: Invalid char '\377' in expression utf.rb: 10: Invalid char '\270' in expression utf.rb: 10: Invalid char '\304' in expression Could someone give me a hand? BR, DorianG

    Read the article

  • F# return type coercion

    - by Alex
    Hi, In F# I have a function that returns System.Linq.Expression instances: and System.Object with member this.ToExpression() = match this with | :? System.Int32 -> Expression.Constant(this) :> Expression | :? System.Boolean -> Expression.Constant(this) :> Expression | :? Tml.Runtime.Seq as s -> s.ToExpression() | _ -> failwith "bad expression" If I omit the type coercions on the return values F# will infer the return type of the function to ConstantExpression. My first thought was to explicitly mark the return type as being : #Expression, but that didn't work. Is there a more elegant way of doing this that doesn't involve manually casting return types to the most generic type? Thanks.

    Read the article

  • delayed evaluation of code in subroutines - 5.8 vs. 5.10 and 5.12

    - by Brock
    This bit of code behaves differently under perl 5.8 than it does under perl 5.12: my $badcode = sub { 1 / 0 }; print "Made it past the bad code.\n"; [brock@chase tmp]$ /usr/bin/perl -v This is perl, v5.8.8 built for i486-linux-gnu-thread-multi [brock@chase tmp]$ /usr/bin/perl badcode.pl Illegal division by zero at badcode.pl line 1. [brock@chase tmp]$ /usr/local/bin/perl -v This is perl 5, version 12, subversion 0 (v5.12.0) built for i686-linux [brock@chase tmp]$ /usr/local/bin/perl badcode.pl Made it past the bad code. Under perl 5.10.1, it behaves as it does under 5.12: brock@laptop:/var/tmp$ perl -v This is perl, v5.10.1 (*) built for i486-linux-gnu-thread-multi brock@laptop:/var/tmp$ perl badcode.pl Made it past the bad code. I get the same results with a named subroutine, e.g. sub badcode { 1 / 0 } I don't see anything about this in the perl5100delta pod. Is this an undocumented change? A unintended side effect of some other change? (For the record, I think 5.10 and 5.12 are doing the Right Thing.)

    Read the article

  • Is dynamic evaluation of xpath variable string possible using .net 2.0 xslt implementation?

    - by Crocked
    Hi, I'm trying to evaluate an xpath varable I'm building dynamically based on the position of the node. I can create the xpath string in a variable but when I select the value of this just get the string and not the node set I need. I use the following to create the xpath <xsl:variable name="xpathstring" select="normalize-space(concat(&quot;//anAttribute[@key='pos&quot;,position(),&quot;']&quot;))"/> and try to output the value with the following. <xsl:value-of select="$xpathstring"/> If I execute the xpath in my debugger I get the nodeset but in my xml output only get the xpath string which looks like this //anAttribute[@key='pos1'] I had a look at exslt dyn:evaluate which seems to enable this but this seems to be only supported by certain processors and doesn't provide a standalone implementation or at least as far as I could see (currently using the standard .net 2.0 xslt whihc is only xslt 1.0 as far as I recall) Is there anyway to handle this without changing processor? Kind Regards, Crocked

    Read the article

  • ODI 11g - Scripting a Reverse Engineer

    - by David Allan
    A common question is related to how to script the reverse engineer using the ODI SDK. This follows on from some of my posts on scripting in general and accelerated model and topology setup. Check out this viewlet here to see how to define a reverse engineering process using ODI's package. Using the ODI SDK, you can script this up using the OdiPackage and StepOdiCommand classes as follows;  OdiPackage pkg = new OdiPackage(folder, "Pkg_Rev"+modName);   StepOdiCommand step1 = new StepOdiCommand(pkg,"step1_cmd_reset");   step1.setCommandExpression(new Expression("OdiReverseResetTable \"-MODEL="+mod.getModelId()+"\"",null, Expression.SqlGroupType.NONE));   StepOdiCommand step2 = new StepOdiCommand(pkg,"step2_cmd_reset");   step2.setCommandExpression(new Expression("OdiReverseGetMetaData \"-MODEL="+mod.getModelId()+"\"",null, Expression.SqlGroupType.NONE));   StepOdiCommand step3 = new StepOdiCommand(pkg,"step3_cmd_reset");   step3.setCommandExpression(new Expression("OdiReverseSetMetaData \"-MODEL="+mod.getModelId()+"\"",null, Expression.SqlGroupType.NONE));   pkg.setFirstStep(step1);   step1.setNextStepAfterSuccess(step2);   step2.setNextStepAfterSuccess(step3); The biggest leap of faith for users is getting to know which SDK classes have to be used to build the objects in the design, using StepOdiCommand isn't necessarily obvious, once you see it in action though it is very simple to use. The above snippet uses an OdiModel variable named mod, its a snippet I added to the accelerated model creation script in the post linked above.

    Read the article

  • Design mode in Visual studio 2010 sp1 beta

    - by anirudha
    in MVC3 razor we found that their is no way to watch the design in Visual studio as well we can see aspx file by going to design mode. their is a little trick to solve this issue first is that if you have Expression web or Vs 2008 then open the file on them how see here in expression web 4 you need to add the extension .cshtml and open them as html as we open other. in Visual studio 2008 you need to add the extension .cshtml and set them open as html. well their is no big trouble if design not worked. but in some case when you need to get this issue solved this need to be work for configuration do this: Expression Web 4 > tools > application options > configure editor > click on new extension icon show in exact left put the cshtml in the window they show you and choose expression web [open as html] after that you can see the design in expression web. by default Expression web not have cshtml as known extension so you need to do that to add them because without it they never handle cshtml file and refer them to Visual studio. after setting this you  EW4 open the cshtml file as html and show you design in design mode. in Visual studio 2008 you can use same trick to solve this issue just follow this step > options > text editors > file extension put cshtml in textbox and set the option html editor from dropdown and click on add and ok this will open your cshtml file as html.

    Read the article

< Previous Page | 55 56 57 58 59 60 61 62 63 64 65 66  | Next Page >