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  • Finding object count where a field is unique in Django

    - by Johnd
    I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

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  • Looking for a simple CMS with WYSIWYG and image gallery

    - by abeger
    I'm building a new site that consists entirely of: 8-10 pages of static content that rarely changes (like once every few months or once every year) An image gallery Since I don't plan to be the primary maintainer of the site, I'd like to use a CMS with some security and a WYSIWYG editor so non-web-savvy people can tweak the site when necessary. I started out using Drupal, but started wondering if it was overkill. So, two questions: 1) is it overkill? 2) What CMS would you recommend for a project this simple?

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  • Tool for sql refactoring?

    - by C. Ross
    Is there a refactoring tool available for SQL (TSQL in particular). Is there any tool that can do automatic simplification of SQL? I have a set of views where only the top two are used, and I'd like to refactor this into only two views, hence 10+ queries into two queries.

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  • Endless scroll paging in jquery Safari

    - by socheata
    I'm using : $(window).scroll(function () { if ($(window).scrollTop() + 10 >= ($(document).height() - $(window).height())) { loadContent(); } } It works fine with Chrome, IE, Firefox but except in Safari. In function loadContent, I used JSON to load data, as this tutorial. But while I test in Safari, It takes the content twice from JSON. If the other takes 9 items, then Safari takes 18 items. Does anyone know how to solve this problem? Thanks.

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  • Format String become 0001, 0010 etc

    - by trycatch4j
    Hi all.., I have number : 1, 2, 3, 4, 10 But I wanna print that number 0001 0002 0003 0004 0010 I have search in google, the keyword is number format. but I've got nothing, I just get, frmat decimal such ass 1,000,000.00. hope you can suggest me a reference or give me some problem solving. Thanks,

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  • continuously fetch data from database using JAVA

    - by deathcaller
    Hi all, I've a scenario where my java program has to continuously communicate with the database table, example my java program has to get the data of my table when new rows are added to it at runtime. There should be continuous communication between my program and database. if the table has 10 rows initially and 2 rows are added by the user, it must detect this and return the rows. My program shouldn't use AJAX and timers. Please Help.

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  • Sleep Function Error In C

    - by Arman
    I have a file of data Dump, in with different timestamped data available, I get the time from timestamp and sleep my c thread for that time. But the problem is that The actual time difference is 10 second and the data which I receive at the receiving end is almost 14, 15 second delay. I am using window OS. Kindly guide me. Sorry for my week English.

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  • How effecient is a details table?

    - by Jeffrey Lott
    At my job, we have pseudo-standard of creating one table to hold the "standard" information for an entity, and a second table, named like 'TableNameDetails', which holds optional data elements. On average, for every row in the main table will have about 8-10 detail rows in it. My question is: What kind of performance impacts does this have over adding these details as additional nullable columns on the main table?

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  • how can I create macro definitions for the lines commented in the code.

    - by yaprak
    #include <stdio.h> //Here use a macro definition that assigns a value to SIZE (for example 5) int main() { int i; int array[SIZE]; int sum=0; for(i=0; i<SIZE; i++) { //Here use a macro definition named as CALCSUM to make the //following addition operation for the array printf("Enter a[%d] = ",i); scanf("%d", &array[i]); sum+=array[i]; //Here use a macro definition named as VERBOSE to print //what program does to the screen printf("The user entered %d\n", array[i]); // // //If the macro definition CALCSUM is not used, the program //should assign 0 to the i-th element of the array array[i]=0; //Here, again use VERBOSE to print what program does to the screen printf("a[%d] is assigned to zero\n", i); // // } //If CALCSUM is defined, print the summation of the array elements to the screen printf("Summation of the array is %d\n",sum); // //If CALCSUM is not defined, but VERBOSE mode is used, print the following printf("All the elements in the array are assigned to zero\n"); // printf("Program terminated\n"); return 0; } When CALCSUM is defined, the program will sum up the values of each element in the given array. If CALCSUM is not defined, each array element will be assigned to zero. Besides, when VERBOSE mode is defined, the program will make print statements pointed out active. [root@linux55]# gcc code.c [root@linux55]# ./a.out Program terminated [root@linux55]# gcc code.c -D CALCSUM [root@linux55]# ./a.out Enter a[0] = 3 Enter a[1] = 0 Enter a[2] = 2 Enter a[3] = 5 Enter a[4] = 9 Summation of the array is 19 Program terminated [root@linux55]# gcc code.c -D CALCSUM -D VERBOSE [root@linux55]# ./a.out Enter a[0] = 2 The user entered 2 Enter a[1] = 10 The user entered 10 Enter a[2] = 3 The user entered 3 Enter a[3] = 8 The user entered 8 Enter a[4] = 1 The user entered 1 Summation of the array is 24 Program terminated [root@linux55]# gcc code.c -D VERBOSE [root@linux55]# ./a.out a[0] is assigned to 0 a[1] is assigned to 0 a[2] is assigned to 0 a[3] is assigned to 0 a[4] is assigned to 0 All the elements in the array is assigned to zero Program terminated

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  • Missing $ on loop variable

    - by k0re
    Hi, 1 #!/usr/bin/perl 2 use strict; 3 use warnings; 4 5 my @array = qw[a b c]; 6 foreach my($a,$b,$c) (@array) { 7 print "$a , $b , $c\n"; 8 } I receive following error: Missing $ on loop variable What is wrong? I am using: perl v5.10.1 (*) built for x86_64-linux-thread-multi

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  • How can I show just the icon of the currently selected option?

    - by Paul Tomblin
    Is it possible to have a bunch of <select> dropdowns in html that only display a small (say 10 pixels wide) icon, but when you click it the drop down has a list with the icons beside a descriptive string. (Let's see if ASCII art works on SO): [X] | X - Disable | | v/ - Enable | | O - Ignore | +-------------+ [O] [v] [X] Can that be done in CSS? Or in jQuery?

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  • vector does not erase content correctly (infite amount run of copy asignment operator untill crash [BEX])?

    - by Gam Erix
    Well my problem is that after I want to "unload" loaded DLL's the copy assignmnent operator is called an unlimited amount of times until crash. The code from which I remove the vector data looks like this: void UnloadPlugins() { dbg(("[DBG]UnloadPlugins()")); for(std::vector<DLLInfo>::iterator it = plugins.begin(); it != plugins.end(); ++it) { plugins.erase(it); } dbg(("[DBG]UnloadPlugins()::Done")); } however "[DBG]UnloadPlugins()::Done" gets never printed. this is my copy assignmnent operator: // 2. copy assignment operator DLLInfo& operator=(const DLLInfo& that) { dbg(("[DBG]Start-DLLInfo& operator=(const DLLInfo& that)")); Instance = that.Instance;//hinstance dbg(("[DBG]DLLInfo 1")); //Identifier.assign(that.Identifier);//string dbg(("[DBG]DLLInfo 2")); IsAMX = that.IsAMX;//integer dbg(("[DBG]DLLInfo 3")); dwSupportFlags = that.dwSupportFlags;//integer dbg(("[DBG]DLLInfo 4")); Load = that.Load;//integer dbg(("[DBG]DLLInfo 5")); Unload = that.Unload;//integer dbg(("[DBG]DLLInfo 6")); Supports = that.Supports;//integer dbg(("[DBG]DLLInfo 7")); ProcessTick = that.ProcessTick;//integer dbg(("[DBG]DLLInfo 8")); AmxLoad = that.AmxLoad;//integer dbg(("[DBG]DLLInfo 9")); AmxUnload = that.AmxUnload;//integer dbg(("[DBG]DLLInfo 10")); UseDestructor = that.UseDestructor;//bool dbg(("[DBG]DLLInfo 11")); KeyboardHit = that.KeyboardHit;//integer dbg(("[DBG]End-DLLInfo& operator=(const DLLInfo& that)")); return *this; } So the log looks like: [17:50:50] [DBG]UnloadPlugins() [17:50:50] [DBG]~DLLInfo [17:50:50] [DBG]~DLLInfo::if(this->UseDestructor) passed [17:50:50] [DBG]~DLLInfo::if(this->UseDestructor)::if(this->Unload != NULL && this->IsAMX) passed [17:50:50] [DBG]~DLLInfo::end [17:50:50] [DBG]Start-DLLInfo& operator=(const DLLInfo& that) [17:50:50] [DBG]DLLInfo 1 [17:50:50] [DBG]DLLInfo 2 [17:50:50] [DBG]DLLInfo 3 [17:50:50] [DBG]DLLInfo 4 [17:50:50] [DBG]DLLInfo 5 [17:50:50] [DBG]DLLInfo 6 [17:50:50] [DBG]DLLInfo 7 [17:50:50] [DBG]DLLInfo 8 [17:50:50] [DBG]DLLInfo 9 [17:50:50] [DBG]DLLInfo 10 [17:50:50] [DBG]DLLInfo 11 [17:50:50] [DBG]End-DLLInfo& operator=(const DLLInfo& that) [17:50:50] [DBG]Start-DLLInfo& operator=(const DLLInfo& that) ... [17:50:50] [DBG]End-DLLInfo& operator=(const DLLInfo& that) ...repeat until crash What could the problem be?

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  • Taking MySql backup from my Java application

    - by dhiraj
    I am developing a Java application with MySql as the database. I have to dump the MySql database from my application periodically(let say every day at 10 a.m.) and I have written a batch (.bat) file for dumping the database. The batch file is working fine, but the problem is that it is asking for password each time during its execution. Is there any way to dump MySql database without prompting for password and achieve it from Java application periodically?

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  • Can java do a timer on command line by overwriting the time on the same line?

    - by javaLearner.java
    HI I am a new java programmer (very new). What I want to do/test is (not sure if its recommendable or doable?), we know that System.out.println("Message"); will output the "Message" in command prompt. Is it possible to display the current time, without having to repeatly use the system.out.println()? Name, like instead of displaying: 10:00:01 10:00:02 10:00:03 I wand to have liek this: 10:00:0X where X will continue counting

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