Search Results

Search found 16602 results on 665 pages for 'directory'.

Page 594/665 | < Previous Page | 590 591 592 593 594 595 596 597 598 599 600 601  | Next Page >

  • SQL Agent Logon - What is going on?

    - by James Wiseman
    I have a DTSX package that is called from a SQL Agent Job. The DTSX package references a file at a fixed location (e.g. e:\mssql\myfile.txt). On most machines, this location exists, but on some I have to manually map this (which is not a problem - I know a better solution would be to use package conifgurations to dynamically pull the file location, but this is not an option here - and anyway I'd like to understand what is going on) I have set up the agent service to run as a specific user (e.g. myuser) When I log on as this user and map the directory, then run the dtsx package directly, then all goes well. When I run the package through a SQL Agent Job, the file cannot be found. If I add a command line job step to the agent job to map the drive: net use e: \\svr\location Then all works file also. So what is going on in the backgound? How come the SQL Agent user requries the drive mapping even when I am logged in as this user.

    Read the article

  • Why can't nvcc find my Visual C++ installation?

    - by Jack Lloyd
    I'm running Windows 7 Pro x64 on a Core i5 with a NVIDIA 3100m, which is CUDA compatible. I've tried installing both the 32-bit and 64-bit CUDA toolkits from NVIDIA, unfortunately from with either of them I cannot compile anything; nvcc says "cannot find a supported cl version. Only MSVC 8.0 and MSVC 9.0 are supported". I have the x86 and x86-64 compilers installed via the Windows 7 SDK (compiler version 15.00.30729.01 for both arches). Both compilers are operating correctly; I've built and tested C and C++ code using them. I've tried running nvcc from command shells set up for both 32 bit and 64 bit compilation, and using the -ccbin command line option to nvcc to point it at the Visual C++ install directory. What is the right way of handling this setup? Is there some way I make nvcc be more verbose about what is going on? The -v flag isn't terrible helpful. Ideally some way to make it show what it is finding versus what it's expecting to find. Will this work better if I install Visual C++ Express instead? Or is only a commercial version of VC++ supported for use with CUDA?

    Read the article

  • Why are my attempts to open a file using open for writing failing? Ada 95

    - by mat_geek
    When I attempt to open a file to write to I get an Ada.IO_Exceptions.Name_Error. The procedure call is Ada.Text_IO.Open The file name is "C:\CC_TEST_LOG.TXT". This file does not exist. This is on Windows XP on an NTFS partition. The user has permissions to create and write to the directory. The filename is well under the WIN32 max path length. name_2 : String := "C:\CC_TEST_LOG.TXT" if name_2'last > name_2'first then begin Ada.Text_IO.Open(file, Ada.Text_IO.Out_File, name_2); Ada.Text_IO.Put_Line( "CC_Test_Utils: LogFile: ERROR: Open, File " & name_2); return; exception when The_Error : others => Ada.Text_IO.Put_Line( "CC_Test_Utils: LogFile: ERROR: Open Failed; " & Ada.Exceptions.Exception_Name(The_Error) & ", File " & name_2); end; end if;

    Read the article

  • Kohana 3, themes outside application.

    - by Marek
    Hi all I read http://forum.kohanaframework.org/comments.php?DiscussionID=5744&page=1#Item_0 and I want to use similar solution, but with db. In my site controller after(): $theme = $page->get_theme_name(); //Orange Kohana::set_module_path('themes', Kohana::get_module_path('themes').'/'.$theme); $this->template = View::factory('layout') I checked with firebug: fire::log(Kohana::get_module_path('themes')); // D:\tools\xampp\htdocs\kohana\themes/Orange I am sure that path exists. I have directly in 'Orange' folder 'views' folder with layout.php file. But I am getting: The requested view layout could not be found Extended Kohana_Core is just: public static function get_module_path($module_key) { return self::$_modules[$module_key]; } public static function set_module_path($module_key, $path) { self::$_modules[$module_key] = $path; } Could anybody help me with solving that issue? Maybe it is a .htaccess problem: # Turn on URL rewriting RewriteEngine On # Put your installation directory here: # If your URL is www.example.com/kohana/, use /kohana/ # If your URL is www.example.com/, use / RewriteBase /kohana/ # Protect application and system files from being viewed RewriteCond $1 ^(application|system|modules) # Rewrite to index.php/access_denied/URL RewriteRule ^(.*)$ / [PT,L] RewriteRule ^(media) - [PT,L] RewriteRule ^(themes) - [PT,L] # Allow these directories and files to be displayed directly: # - index.php (DO NOT FORGET THIS!) # - robots.txt # - favicon.ico # - Any file inside of the images/, js/, or css/ directories RewriteCond $1 ^(index\.php|robots\.txt|favicon\.ico|static) # No rewriting RewriteRule ^(.*)$ - [PT,L] # Rewrite all other URLs to index.php/URL RewriteRule ^(.*)$ index.php/$1 [PT,L] Could somebody help? What I am doing wrong? Regards

    Read the article

  • Adobe AIR non-Administrator application installation/upgrade on Windows

    - by bzlm
    Is there any way to allow non-Administrator users to install, upgrade or uninstall an Adobe AIR application on Windows? I've made an Adobe AIR application and packaged it as a .air package using the standard AIR mechanism for creating deployment packages. If a normal or Power user tries to install this AIR application, the Application Event Log shows an error saying administrative rights are required. And even if the user elevates during installation, administrative rights are still required for an upgrade using the automated AIR upgrade system (since an upgrade is essentially, behind the scenes, an uninstallation of a .msi package followed by an installation of another .msi package). Is there any way around this? What I've tried so far is: Using the Group Policy editor, setting Windows Installer to elevate during installations. Doesn't work, since AIR attempts a "for all users" installation. Specifying My Documents as the installation directory. Doesn't work, since AIR attempts a "for all users" installation. Giving the user Modify access to the Program Files folder where the application would usually reside. Doesn't work, since this isn't a file permissions issue. Making the user a Power User. Doesn't work, since AIR attempts a "for all users" installation. I'm guessing that both installing and upgrading would work fine for a user if the AIR installer would attempt to make an "only for me" application installation instead of a "for all users" installation, and the user was a Power User, and possibly the application was installed to My Documents I'm also guessing that this problem doesn't exist on OSX and Linux, since they have more intuitive concepts for per-user application installations.

    Read the article

  • Iterating through folders and files in batch file?

    - by Will Marcouiller
    Here's my situation. A project has as objective to migrate some attachments to another system. These attachments will be located to a parent folder, let's say "Folder 0" (see this question's diagram for better understanding), and they will be zipped/compressed. I want my batch script to be called like so: BatchScript.bat "c:\temp\usd\Folder 0" I'm using 7za.exe as the command line extraction tool. What I want my batch script to do is to iterate through the "Folder 0"'s subfolders, and extract all of the containing ZIP files into their respective folder. It is obligatory that the files extracted are in the same folder as their respective ZIP files. So, files contained in "File 1.zip" are needed in "Folder 1" and so forth. I have read about the FOR...DO command on Windows XP Professional Product Documentation - Using Batch Files. Here's my script: @ECHO OFF FOR /D %folder IN (%%rootFolderCmdLnParam) DO FOR %zippedFile IN (*.zip) DO 7za.exe e %zippedFile I guess that I would also need to change the actual directory before calling 7za.exe e %zippedFile for file extraction, but I can't figure out how in this batch file (through I know how in command line, and even if I know it is the same instruction "cd"). Anyone's help is gratefully appreciated.

    Read the article

  • How to migrate project from RCS to git? (SOLVED)

    - by Norman Ramsey
    I have a 20-year-old project that I would like to migrate from RCS to git, without losing the history. All web pages suggest that the One True Path is through CVS. But after an hour of Googling and trying different scripts, I have yet to find anything that successfully converts my RCS project tree to CVS. I'm hoping the good people at Stackoverflow will know what actually works, as opposed to what is claimed to work and doesn't. (I searched Stackoverflow using both the native SO search and a Google search, but if there's a helpful answer in the database, I missed it.) UPDATE: The rcs-fast-export tool at http://git.oblomov.eu/rcs-fast-export was repaired on 14 April 2009, and this version seems to work for me. This tool converts straight to git with no intermediate CVS. Thanks Giuseppe and Jakub!!! Things that did not work that I still remember: The rcs-to-cvs script that ships in the contrib directory of the CVS sources The rcs-fast-export tool at http://git.oblomov.eu/rcs-fast-export in versions before 13 April 2010 The rcs2cvs script found in a document called "CVS-RCS- HOW-TO Document for Linux"

    Read the article

  • Red5 Unable to Start Distribution.

    - by Iscariot
    I have installed subclipse, Ant, IvyDE, Red5 Plugin for eclipse, All of the Environmental variables are set and the necessary elements have been added to the path. I am attempting to create a Red5 Distribution by using eclipse, opening Build.xml right clicking dist [default] in the outline window and running as and selecting Ant Builder. Eclipse says that the build is Successful. I first stop the Red5 Service, and then I attempt to run the build I create in eclipse it fails, below are the errors that display in the command prompt. I was hoping someone else might have run into a similar issue before. Starting Red5 Red5 root: C:/Users/Admin/workspace/temp/red5_server/dist Configuation root: C:/Users/Admin/workspace/temp/red5_server/dist/conf Setting temp directory to C:\Users\Admin\AppData\localLow Exception in thread "main" java.lang.Error: Unresolved compilation problems: The import org.slf4j.bridge cannot be resolved The import org.springframework.context.support.FileSystemXmlApplicationC ontext cannot be resolved SLF4JBridgeHandler cannot be resolved FileSystemXmlApplicationContext cannot be resolved to a type FileSystemXmlApplicationContext cannot be resolved to a type at org.red5.server.Launcher.<init>(Launcher.java:25) at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstruct orAccessorImpl.java:39) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingC onstructorAccessorImpl.java:27) at java.lang.reflect.Constructor.newInstance(Constructor.java:513) at java.lang.Class.newInstance0(Class.java:355) at java.lang.Class.newInstance(Class.java:308) at org.red5.server.Bootstrap.bootStrap(Bootstrap.java:132) at org.red5.server.Bootstrap.main(Bootstrap.java:50) Press any key to continue . . .

    Read the article

  • Invalid iPhone Application Binary

    - by Kristopher Johnson
    I'm trying to upload an application to the iPhone App Store, but I get this error message from iTunes Connect: The binary you uploaded was invalid. The signature was invalid, or it was not signed with an Apple submission certificate. My guess is that it is not properly signed. I have downloaded my App Store distribution certficate, but I can't figure out how to "sign" my application with it. The SDK's documentation about code signing is not very helpful. (FWIW, I can install the app on my iPhone just fine using the development provisioning profile.) However, it is possible that I screwed things up on a more basic level. Here's what I did to try to prepare it for upload: In Xcode, select the Device|Release target Select the target and click the Info button. Change "Code Signing Identity" to "iPhone Distribution", and change "Code Signing Provisioning Profile" to my App Store distribution profile. Build Go to the directory where the built MyApp.app bundle is, control-click and choose "Compress" to create MyApp.zip Upload MyApp.zip to the App Store via iTunes Connect (which resulted in the above error message). Can anybody give me any hints? Edit: Found someone with the same problem. Unfortunately, he won't tell us how he fixed it. http://www.rhonabwy.com/wp/2008/07/18/seattlebus-diary-ongoing-update-saga/#comments http://www.rhonabwy.com/wp/2008/07/22/seattlebus-diary-update-is-pending-review/ (Note: For general information on submitting iPhone applications to the App Store, see Steps to upload an iPhone application to the AppStore.)

    Read the article

  • Where to put external archives to configure running in Eclipse?

    - by Buggieboy
    As a Java/Eclipse noob coming from a Visual Studio .NET background, I'm trying to understand how to set up my run/debug environment in the Eclipse IDE so I can start stepping through code. I have built my application with separate src and bin hierarchies for each library project, and each project has its own jar. For example, in a Windows environment, I have something like: c:\myapp\myapp_main\src\com\mycorp\myapp\main ...and a parallel "bin" tree like this: c:\myapp\myapp_main\bin\com\mycorp\myapp\main Other supporting projects are, similarly: **c:\myapp\myapp_util\src\com\mycorp\myapp\uti**l (and a parallel "bin" tree.) ... etc. So, I end up with, e.g., myapp_util.jar in the ...\myapp_util\bin... path and then add that as an external archive to my myapp_main project. I also use utilities like gluegen-rt.jar, which I add ad external dependencies to the projects requiring them. I have been able to run outside of the Eclipse environment, by copying all my project jars, gluegen-rt DLL, etc., into a "lib" subfolder of some directory and executing something like: java -Djava.library.path=lib -DfullScreen=false -cp lib/gluegen-rt.jar;lib/myapp_main.jar;lib/myapp_util.jar; com.mycorp.myapp.Main When I first pressed F11 to debug, however, I got a message about something like /com/sun/../glugen... not being found by the class loader. So, to debug, or even just run, in Ecplipse, I tried setting up my VM arguments in the Galileo Debug - (Run/Debug) Configurations to be the command line above, beginning at "-Djava.libary.path...". I've put a lib subdirectory - just like the above with all jars and the native gluegen DLL - in various places, such as beneath the folder that my main jar is built in and as a subfolder of my Ecplipse starting workspace folder, but now Eclipse can't find the main class: java.lang.NoClassDefFoundError: com.mycorp.myapp.Main Although the Classpath says that it is using the "default classpath", whatever that is. Bottom line, how do I assemble the constituent files of a multi-project application so that I can run or debug in Ecplipse?

    Read the article

  • Codeigniter: Base_url doesn't seem to be working

    - by Dwayne
    I have developed a simple site that fetches tweets from the Twitter public timeline, caches them for 60 seconds and so on. I have recently moved hosts from Hostgator to Mediatemple and my site was previously working fine on Hostgator. My application doesn't use a database connection, nor does it use any form of flat-file database either. Tweets are cached in an XML file stored in the root directory, not that most of that is important. The url helper is being included as can be seen below (this is my helpers line from autoload.php): $autoload['helper'] = array('url'); I have also removed my index.php file from the URL using .htaccess directives and once again this was previously working on Hostgator (see my .htaccess code below): RewriteEngine On RewriteRule ^(application) - [F,L] RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule .* index.php/$0 [PT,L] In my home.php view file which is in the views folder inside of application, I am using the function base_url() which was previously working on Hostgator inside of my view files and appending it a base href value in my header: <base href="<?php echo base_url(); ?>" /> Here is what my base_url value looks like in the config.php file: $config['base_url'] = "http://threetune.com/"; Although what appears to be happening is that the base_url is not to be seen at all. It doesn't appear to be echoing out the value of base_url as it appears to be empty for some reason. What makes things weirder is that I have a link in another view file called 'fetch.php' and for some reason it appears to be stripping out the value (XSS filtering is off): <a href="threetune/show"><img src="assets/images/cookie.jpg" /></a> The threetune/show part is not to be seen and I only see an empty href value like this <a href=""><img src="assets/images/cookie.jpg" /></a> Can anyone possibly see anything wrong that I may have done, some kind of Mediatemple server limitation or PHP.ini flag that needs to be set? Thank you and I hope I was descriptive enough.

    Read the article

  • Error Log states that I have MySQL connect error, yet script runs fine

    - by rob - not a robber
    Hello All, First, thanks for all the help I've received so far from StackOverflow. I've learned much. Once again, I'm posing a rudimentary question that I've searched on, but cannot find the exact answer to. Here or on PHP.net. It's sort of like what this guy asked, but not exactly: http://stackoverflow.com/questions/288603/mysql-throwing-query-error-yet-finishing-query-just-fine-why So, I saw my errorlog ballooning up when I checked my site directory and opened to notice that a bunch of errors have been recorded since I wrote this new Admin area. I know something is obviously awry with my scripting for the error to be thrown, but the weird thing is, the script actually runs through and pulls all the data I need without breaking. The log contains: PHP Warning: mysql_query() [function.mysql-query]: Access denied for user 'someuser'@'localhost' (using password: NO) in /home/mysite/adminconsole.php on line 15 I don't get that because that very line is where I setup my connection... the exact same way I do it everywhere else on the site with no problem. After that error, I have these thrown at the same time [09-Apr-2010 08:44:18] PHP Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in /home/mysite/adminconsole.php on line 15 [09-Apr-2010 08:44:18] PHP Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/mysite/adminconsole.php on line 16 From what I read in the other guys thread, the problem is the contents of the query maybe? Maybe my query is malformed? Thanks so much for any guidance you can provide. -Rob

    Read the article

  • perl dynamic path given to 'use lib'

    - by Ed Hyer
    So, my code (Perl scripts and Perl modules) sits in a tree like this: trunk/ util/ process/ scripts/ The 'util' directory has, well, utilities, that things in the 'process/' dir need. They get access like this: use FindBin; use lib "$FindBin::Bin/../util"; use UtilityModule qw(all); That construct doesn't care where you start, as long as you're at the same level in the tree as "util/". But I decided that 'scripts/' was getting too crowded, so I created scripts/scripts1 scripts/scripts2 Now I see that this doesn't work. If I run a script 'trunk/scripts/scripts1/call_script.pl', and it calls '/trunk/process/process_script.pl', then 'process_script.pl' will fail trying to get the routines from UtilityModule(), because the path that FindBin returns is the path of the top-level calling script. The first ten ways I thought of to solve this all involved something like: use lib $path_that_came_from_elsewhere; but that seems to be something Perl doesn't like to do, except via that FindBin trick. I tried some things involving BEGIN{} blocks, but i don't really know what I'm doing there, and will likely just end up refactoring. But if someone has some clever insight into this type of problem, this would be a good chance to earn some points!

    Read the article

  • VBScript Catching Erroring Varialble Value

    - by Soren
    I have a VB Script (.vbs file) that is just a simple directory listing of a drive. It will the base of a drive back up script. But when running it as it is below, I am getting a Permission Denied error on some folder. What I need to find is what that folder is so I can figure out what the problem is with the folder. The line that is giving the error is "For Each TempFolder In MoreFolders". So what I am trying to figure out is how to WScript.Echo the current path (objDirectory) if there is an error. I am not sure if it matters much, but just in case, the error that I am getting is Permission Denied 800A0046 on line 12. So some folder, I do not know which one, is not letting me look inside. Set WSShell = WScript.CreateObject("WScript.Shell") Set objFSO = CreateObject ("Scripting.FileSystemObject") Dim FolderArr() FolderCount = 0 TopCopyFrom = "G:\" Sub WorkWithSubFolders(objDirectory) Set MoreFolders = objDirectory.SubFolders 'The next line is where the error occurs (line 12) For Each TempFolder In MoreFolders FolderCount = FolderCount + 1 ReDim Preserve FolderArr(FolderCount) FolderArr(FolderCount) = TempFolder.Path ' WScript.Echo TempFolder.Path WorkWithSubFolders(TempFolder) Next End Sub ReDim Preserve FolderArr(FolderCount) FolderArr(FolderCount) = TopCopyFrom Set objDirectory = objFSO.GetFolder(TopCopyFrom) WorkWithSubFolders(objDirectory) Set objDirectory = Nothing WScript.Echo "FolderCount = " & FolderCount WScript.Sleep 30000 Set objFSO = Nothing Set WSShell = Nothing

    Read the article

  • ClassNotFoundException when connecting to Mysql with JDBC

    - by Jacob Lyles
    I'm getting the following error when I try to run a simple Java JDBC program at the command line: Exception in thread "main" java.lang.NoClassDefFoundError: LoadDriver/java Caused by: java.lang.ClassNotFoundException: LoadDriver.java at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:315) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:330) at java.lang.ClassLoader.loadClass(ClassLoader.java:250) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:398) Here's the simple Java program, copied right out of the JDBC docs: import java.sql.Connection; import java.sql.DriverManager; import java.sql.SQLException; // Notice, do not import com.mysql.jdbc.* // or you will have problems! public class LoadDriver { public static void main(String[] args) { try { // The newInstance() call is a work around for some // broken Java implementations Class.forName("com.mysql.jdbc.Driver").newInstance(); } catch (Exception ex) { throw ex; // handle the error } } } Problem is, I'm bloody sure my bash shell $ClASSPATH variable is pointed at the correct .jar file. To be sure, I copied the JDBC .jar to the same directory as my program and ran it as follows: java -classpath ./mysql-connector-java-5.1.12-bin.jar LoadDriver.java I still get the same error. I'm running under Mac OSX, if it matters.

    Read the article

  • h2 (embedded mode ) database files problem

    - by aeter
    There is a h2-database file in my src directory (Java, Eclipse): h2test.db The problem: starting the h2.jar from the command line (and thus the h2 browser interface on port 8082), I have created 2 tables, 'test1' and 'test2' in h2test.db and I have put some data in them; when trying to access them from java code (JDBC), it throws me "table not found exception". A "show tables" from the java code shows a resultset with 0 rows. Also, when creating a new table ('newtest') from the java code (CREATE TABLE ... etc), I cannot see it when starting the h2.jar browser interface afterwards; just the other two tables ('test1' and 'test2') are shown (but then the newly created table 'newtest' is accessible from the java code). I'm inexperienced with embedded databases; I believe I'm doing something fundamentally wrong here. My assumption is, that I'm accessing the same file - once from the java app, and once from the h2 console-browser interface. I cannot seem to understand it, what am I doing wrong here?

    Read the article

  • FlashBuilder 4 and Zend Framework error

    - by sig
    I am trying to use adobe flash builder 4 with a php service. I had it set up an older macbook running leopard, but just tried to set it up on my new laptop running snow leopard. I did all the same steps.. set the Flex Server to be PHP, set the web root and url. Then I go to Data-Connect To PHP and point it to a php file I have in my web root. It says it needs to install Zend, and claims it does so successfully, but then when I try to continue, I get an error. I don't understand.. this same setup works on my older laptop. (Yes, I checked the amf.production was false) Unable to retrieve operations and entities from the file Make sure that Zend Framework is installed correctly and the parameter "amf.production" is not set to true in the amf_config.ini file located in the project output folder. false), true);$default_config-merge(new Zend_Config_Ini($configfile, 'zendamf'));$default_config-setReadOnly();$amf = $default_config-amf;// Store configuration in the registryZend_Registry::set("amf-config", $amf);// Initialize AMF Server$server = new Zend_Amf_Server();$server-setProduction($amf-production);if(isset($amf-directories)) { $dirs = $amf-directories-toArray(); foreach($dirs as $dir) { // get the first character of the path. // If it does not start with slash then it implies that the path is relative to webroot. Else it will be treated as absolute path $length = strlen($dir); $firstChar = $dir; if($length = 1) $firstChar = $dir[0]; if($firstChar != "/"){ // if the directory is ./ path then we add the webroot only. if($dir == "./"){ $server-addDirectory($webroot); }else{ $tempPath = $webroot . "/" . $dir; $server-addDirectory($tempPath); } }else{ $server-addDirectory($dir); } }}// Initialize introspector for non-productionif(!$amf-production) { $server-setClass('Zend_Amf_Adobe_Introspector', '', array("config" = $default_config, "server" = $server)); $server-setClass('Zend_Amf_Adobe_DbInspector', '', array("config" = $default_config, "server" = $server));}// Handle requestecho $server-handle();

    Read the article

  • Receiving DB update events in .NET from SQLite

    - by Dan Tao
    I've recently discovered the awesomeness of SQLite, specifically the .NET wrapper for SQLite at http://sqlite.phxsoftware.com/. Now, suppose I'm developing software that will be running on multiple machines on the same network. Nothing crazy, probably only 5 or 6 machines. And each of these instances of the software will be accessing an SQLite database stored in a file in a shared directory (is this a bad idea? If so, tell me!). Is there a way for each instance of the app to be notifiied if one instance updates the database file? One obvious way would be to use the FileSystemWatcher class, read the entire database into a DataSet, and then ... you know ... enumerate through the entire thing to see what's new ... but yeah, that seems pretty idiotic, actually. Is there such a thing as a provider of SQLite updates? Does this even make sense as a question? I'm also pretty much a newbie when it comes to ADO.NET, so I might be approaching the problem from the entirely wrong angle.

    Read the article

  • Apache local configuration to resolve files correctly

    - by Alex E.
    Hello, I am new at this so bare with me. I have just configured Apache and PHP to work on my local Mac OS X computer. Now PHP works fine, except when I try to load the files for my live sites. The live sites have separate directories and are sorted by client name etc. I've created symlinks in the default root for the local web server documents. My issue is that Apache doesn't seem to want to load any of the relative paths that are found in the HTML pages. For example, I have src="/css/main.css" but Apache doesn't load the file, similarly for images, it just resolves as a file not found 404 error. I then thought it might be the symlinks so I copied the full directory into the Apache document root, and still had the same result. I would really love to setup my local development environment to run Apache, PHP, MySQL to develop locally then publish when ready. I also tried the MAMP installation, and had the same issues. Any help at all in this would be greatly appreciated. If my explanation wasn't clear please let me know. Thanks! Alex.

    Read the article

  • Ruby on Rails - Static page as start page

    - by meetraghu28
    Hello! I am developing an app in RoR which has static and dynamic parts. The static portion is placed in the public/ folder of the app. Now if i have an index.html in my public folder then i will not be able to use the routes configured in my routes.rb The default configurations like map.connect /:controller/:action will not be usable if i have an index.html. So i removed the index html. Now i have a static page startpage.html in my public/ folder which has to be the starting page of the app. And the i have links in it for other static/dynamic pages. The RoR app is hosted in apache and i tried to configure the Virtual Host configuration by adding the DirectoryIndex param so that when ever a request comes for the site it will direct it to the startpage.html but still it takes me to the default controller that i have specified in routes.rb with map.root I dont want to add a dummy controller and action and create a view which has the startpage and configure routes.rb to use it as the root. What i am looking to do here is Basically startpage.html should be my first page in the app served as a static page from the public/ folder. This will then have links to other pages and controllers/actions Here i am not able to apache to redirect to the html page instead of passing on the control to rails application. Directory listing is also enabled by using Options Indexes but still no change. Any pointers anyone?

    Read the article

  • php get, random records, and the back button

    - by Andrew Heath
    My site has a library full of games, nations, game scenarios, etc. library.php is given a type=___ & id=___ for example library.php?type=scenario&id=ABCD001 library.php saves the id to a session variable and loads an include appropriate for the type This all works just dandy. Now, I wanted to give my users the option of pulling up a random scenario. To do that, I added a special id to the logic within lib-scenario.php (the include) such that if given library.php?type=scenario&id=random the include knows to run an alternate query for a random record rather than for the actual id This also works just dandy... unless someone hits the Random Scenario button two+ times in a row, and decides that the previous random scenario was way cooler, I want to go back to that. Because the http address is always directory/library.php?type=scenario&id=random no matter how many times you click Random Scenario, as soon as you click back you'll be taken to the last page with an alternate address you visited. So, if you start at the Home page, and hit Random Scenario 35 times, then decide the 34th one was what you wanted and click BACK, you'll be put back onto the Home page. I must admit this was not a problem I had anticipated. One of my testers was the first to have the urge to back-up in the random scenario stream and here we are. How can I add back-up functionality to my script?

    Read the article

  • How to install PySide v0.3.1 on Mac OS X?

    - by ivo
    I'm trying to install PySide v0.3.1 in Mac OS X, for Qt development in python. As a pre-requisite, I have installed CMake and the Qt SDK. I have gone through the documentation and come up with the following installation script: export PYSIDE_BASE_DIR="<my_dir>" export APIEXTRACTOR_DIR="$PYSIDE_BASE_DIR/apiextractor-0.5.1" export GENERATORRUNNER_DIR="$PYSIDE_BASE_DIR/generatorrunner-0.4.2" export SHIBOKEN_DIR="$PYSIDE_BASE_DIR/shiboken-0.3.1" export PYSIDE_DIR="$PYSIDE_BASE_DIR/pyside-qt4.6+0.3.1" export PYSIDE_TOOLS_DIR="$PYSIDE_BASE_DIR/pyside-tools-0.1.3" pushd . cd $APIEXTRACTOR_DIR cmake . cd $GENERATORRUNNER_DIR cmake -DApiExtractor_DIR=$APIEXTRACTOR_DIR . cd $SHIBOKEN_DIR cmake -DApiExtractor_DIR=$APIEXTRACTOR_DIR -DGeneratorRunner_DIR=$GENERATORRUNNER_DIR . cd $PYSIDE_DIR cmake -DShiboken_DIR=$SHIBOKEN_DIR/libshiboken -DGENERATOR=$GENERATORRUNNER_DIR . cd $PYSIDE_TOOLS_DIR cmake . popd Now, I don't know if this installation script is ok, but apparently everything works fine. Each component (apiextractor, generatorrunner, shiboken, pyside-qt and pyside-tools) gets compiled into its own directory. The problem is that I don't quite understand how PySide gets into the system's python environment. In fact, when I start a python shell, I cannot import PySide: >>> import PySide Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named PySide Note: I am aware of the Installing PySide - OSX question, but that question is not relevant anymore, because it is about a specific a dependency on the Boost libraries, but with version 0.3.0 PySide moved from a Boost based source code to a CPython one.

    Read the article

  • Rails 2.3.11 Server Crashing After 4 Requests

    - by Taka
    I have a Rails 2.3.11 application running on my local Windows machine using InstantRails. I cd to my application directory, run ruby script/server to start the server running, and point my browser to localhost:3000. I get the page I expect, and am able to click a few links to other pages (all of them are static). The problem starts when I load the 4th page or so. My server crashes, with this message: Processing HomeController#index (for 127.0.0.1 at 2012-06-23 15:48:40) [GET] Rendering template within layouts/application Rendering home/index Completed in 11ms (View: 9, DB: 1) | 200 OK [http://localhost/index] C:/rails/ruby/lib/ruby/gems/1.8/gems/activesupport-2.3.11/lib/active_support/memoizable.rb:46: [BUG] Segmentation fault ruby 1.8.7 (2012-02-08 patchlevel 358) [i386-mingw32] This application has requested the Runtime to terminate it in an unusual way. Please contact the application's support team for more information. I've uninstalled this gem and reinstalled it, which didn't help. It doesn't seem to be the gem though, because the segmentation fault sometimes occurs in C:/rails/ruby/lib/ruby/gems/1.8/gems/mongrel-1.1.2-x86-mswin32/lib/mongrel.rb:114 or C:/rails/ruby/lib/ruby/1.8/benchmark.rb:306 Versions: >ruby -v ruby 1.8.7 (2012-02-08 patchlevel 358) [i386-mingw32] >rails -v Rails 2.3.11 I'd like to get this fixed so while I'm developing I don't have to keep restarting my server. Any suggestions?

    Read the article

  • Getting all new messages from a Maildir in python

    - by Jesper
    I have a mail dir: foo@foo:~/Maildir$ ls -l total 288 drwx------ 2 foo foo 155648 2010-04-19 15:19 cur -rw------- 1 foo foo 440 2010-03-20 08:50 dovecot.index.log -rw------- 1 foo foo 112 2010-03-20 08:49 dovecot-uidlist -rw------- 1 foo foo 8 2010-03-20 08:49 dovecot-uidvalidity -rw------- 1 foo foo 0 2010-03-20 08:49 dovecot-uidvalidity.4ba48c0e drwx------ 2 foo foo 114688 2010-04-19 16:07 new drwx------ 2 foo foo 4096 2010-04-19 16:07 tmp And in python I'm trying to get all new messages (Python 2.6.5rc2). First, getting "Maildir" works: >>> import mailbox >>> md = mailbox.Maildir('/home/foo/Maildir') >>> md.iterkeys().next() '1269924477.Vfc01I4249fM708004.foo' But how do I access "Maildir/new"? This does not work: >>> md = mailbox.Maildir('/home/foo/Maildir/new') >>> md.iterkeys().next() Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.6/mailbox.py", line 346, in iterkeys self._refresh() File "/usr/lib/python2.6/mailbox.py", line 467, in _refresh for entry in os.listdir(subdir_path): OSError: [Errno 2] No such file or directory: '/home/foo/Maildir/new/new' >>> Any ideas?

    Read the article

  • How does this Switch statement know which case to execute? (PHP/MySQL)

    - by ggfan
    Here is a code form a PHP+MySQL book I am reading and I am having trouble understanding this code. This code is about checking a file uploaded into a database. (Please excuse any spelling errors if any, I was typing it in) Q1: How does it know which case to echo? In the whole code, there is no mention of each case. Q2: Why do they skip case 5?! Or does it not matter which numbers you use(so I can have case 1, case 18, case 2?) if($_FILES['userfile']['error']>0) { echo 'Problem: '; switch($_FILES['userfile']['error']) { case 1: echo 'File exceeded upload_max_filesize'; break; case 2: echo 'File exceeded max_file_size'; break; case 3: echo 'File only partially uploaded'; break; case 4: echo 'No file uploaded'; break; case 6: echo 'Cannot upload file: no temp directory specified'; break; case 7: echo 'Upload failed: Cannot write to disk'; break; } exit; }

    Read the article

< Previous Page | 590 591 592 593 594 595 596 597 598 599 600 601  | Next Page >