Search Results

Search found 337 results on 14 pages for 'adame doe'.

Page 6/14 | < Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >

  • jQuery Cycle Plugin - Content not cycling

    - by fmz
    I am setting up a page with jQuery's Cycle plugin and have four divs set to fade. I have the code in place, the images set, but it doesn't cycle properly. Firefox says there is a problem with the following code: <script type="text/javascript"> $(document).ready(function() { $('.slideshow').cycle({ fx: 'fade' }); }); </script> Here is the html: <div class="slideshow"> <div id="mainImg-1" class="slide"> <div class="quote"> <h2>Building Big Relationships with Small Business.</h2> <p>&ldquo;This is quote Number One.<br /> They are there when I need them the most.&rdquo;</p> <p><span class="author">Jane Doe &ndash; Charlotte Flower Shop</span></p> <div class="help"><a href="cb_services.html">Let Us Help You</a></div> </div> </div> <div id="mainImg-2" class="slide"> <div class="quote"> <h2>Building Big Relationships with Small Business.</h2> <p>&ldquo;This is quote Number Two.<br /> They are there when I need them the most.&rdquo;</p> <p><span class="author">Jane Doe &ndash; Charlotte Flower Shop</span></p> <div class="help"><a href="cb_services.html">Let Us Help You</a></div> </div> </div> <div id="mainImg-3" class="slide"> <div class="quote"> <h2>Building Big Relationships with Small Business.</h2> <p>&ldquo;This is quote Number three.<br /> They are there when I need them the most.&rdquo;</p> <p><span class="author">Jane Doe &ndash; Charlotte Flower Shop</span></p> <div class="help"><a href="cb_services.html">Let Us Help You</a></div> </div> </div> <div id="mainImg-4" class="slide"> <div class="quote"> <h2>Building Big Relationships with Small Business.</h2> <p>&ldquo;This is quote Number Fout.<br /> They are there when I need them the most.&rdquo;</p> <p><span class="author">Jane Doe &ndash; Charlotte Flower Shop</span></p> <div class="help"><a href="cb_services.html">Let Us Help You</a></div> </div> </div> Here is the CSS: .slideshow { width: 946px; height: 283px; border: 1px solid #c29c5d; margin: 8px; overflow: hidden; z-index: 1; } #mainImg-1 { width: 946px; height: 283px; background: url(../_images/main.jpg) no-repeat 9px 9px; } #mainImg-2 { width: 946px; height: 283px; background: url(../_images/main.jpg) no-repeat 9px 9px; } #mainImg-3 { width: 946px; height: 283px; background: url(../_images/main.jpg) no-repeat 9px 9px; } #mainImg-4 { width: 946px; height: 283px; background: url(../_images/main.jpg) no-repeat 9px 9px; } #mainImg-1 .quote, #mainImg-2 .quote, #mainImg-3 .quote, #mainImg-4 .quote { width: 608px; height: 168px; float: right; margin: 80px 11px 0 0; background: url(../_images/bg_quoteBox.png) repeat-x; } Before you go off and say, "hey, those images are all the same". You are right, the images are all the same right now, but the text should be rotating as well and there is a slight difference there. In addition, the fade should still show up. Anyway, you can see the dev page here: http://173.201.163.213/projectpath/first_trust/index.html I would appreciate some help to get this cycling through as it should. Thanks!

    Read the article

  • SQL 2005: Select top N, group by ID with joins

    - by Suzy Fresh
    I'm having real difficulty with a query involving 3 tables. I need to get the 3 newest users per department grouped by department names. The groups should be sorted by the users.dateadded so the department with the newest activity is first. The users can exist in multiple departments so Im using a lookup table that just contains the userID and deptID. My tables are as follows. Department - depID|name Users - userID|name|dateadded DepUsers - depID|userID The output I need would be Receiving John Doe - 4/23/2010 Bill Smith - 4/22/2010 Accounting Steve Jones - 4/22/2010 John Doe - 4/21/2010 Auditing Steve Jones - 4/21/2010 Bill Smith - 4/21/2010

    Read the article

  • How to use a proprety/value table in MySQL

    - by David
    I inherited a mysql database that has a table with columns like this: object_id, property, value It holds data like this: 1,first_name,Jane 1,last_name,Doe 1,age,10 1,color,red 2,first_name,Mike 2,last_name,Smith 2,age,20 2,color,blue 3,first_name,John 3,last_name,Doe 3,age,20 3,color,red ... Basically what I want to do is treat this table as a regular table. How would I get the id numbers (or all properties) of a person who is age 20 sorted by last and than first name? So far I have: SELECT object_id FROM table WHERE property = 'age' AND value = '20' union SELECT object_id FROM table WHERE property = 'color' AND value = 'red' But I'm not sure how to go about ordering the data. Thanks

    Read the article

  • How to get the position of a record in a table (SQL Server)

    - by Peter Siegmann
    Following problem: I need to get the position of a record in the table. Let's say I have five record in the table: Name: john doe, ID: 1 Name: jane doe, ID: 2 Name: Frankie Boy, ID: 4 Name: Johnny, ID: 9 Now, "Frankie Boy" is in the third position in the table. But How to get this information from the SQL server? I could count IDs, but they are not reliable, Frankie has the ID 4, but is in the third position because the record with the ID '3' was deleted. Is there a way? I am aware of ROW_RANK but it would be costly, because I need to select basically the whole set first before I can rank row_rank them. I am using MS SQL Server 2008 R2.

    Read the article

  • Javascript Split: without losing character

    - by Rohan
    I want to split certain text using JavaSscript. The text looks like: 9:30 pm The user did action A. 10:30 pm Welcome, user John Doe. 11:30 am Messaged user John Doe Now, I want to split the string into events. i.e.: 9:30 pm The user did action A. would be one event. I'm using RegEx for this: var split = journals.split(/\d*\d:/); Thing is, the first two characters are getting lost. The split appears like this: 30 pm The user did action A. How do I split so that the split maintains the first two/three characters (ie 9: or 10:) etc? Thanks!

    Read the article

  • Left Join works with table but fails with query

    - by Frank Martin
    The following left join query in MS Access 2007 SELECT Table1.Field_A, Table1.Field_B, qry_Table2_Combined.Field_A, qry_Table2_Combined.Field_B, qry_Table2_Combined.Combined_Field FROM Table1 LEFT JOIN qry_Table2_Combined ON (Table1.Field_A = qry_Table2_Combined.Field_A) AND (Table1.Field_B = qry_Table2_Combined.Field_B); is expected by me to return this result: +--------+---------+---------+---------+----------------+ |Field_A | Field_B | Field_A | Field_B | Combined_Field | +--------+---------+---------+---------+----------------+ |1 | | | | | +--------+---------+---------+---------+----------------+ |1 | | | | | +--------+---------+---------+---------+----------------+ |2 |1 |2 |1 |John, Doe | +--------+---------+---------+---------+----------------+ |2 |2 | | | | +--------+---------+---------+---------+----------------+ [Table1] has 4 records, [qry_Table2_Combined] has 1 record. But it gives me this: +--------+---------+---------+---------+----------------+ |Field_A | Field_B | Field_A | Field_B | Combined_Field | +--------+---------+---------+---------+----------------+ |2 |1 |2 |1 |John, Doe | +--------+---------+---------+---------+----------------+ |2 |2 |2 | |, | +--------+---------+---------+---------+----------------+ Really weird is that the [Combined_Field] has a comma in the second row. I use a comma to concatenate two fields in [qry_Table2_Combined]. If the left join query uses a table created from the query [qry_Table2_Combined] it works as expected. Why does this left join query not give the same result for a query and a table? And how can i get the right results using a query in the left join?

    Read the article

  • whats wrong with this peace of code for saving contacts

    - by Shadow
    Hi, i am using the latest Nokia Qt SDK. i have tried to add the contacts, its not getting added.. what is missing here.. // Construct contact manager for default contact backend QContactManager* cm = new QContactManager("simulator"); // QContactManager* cm = new QContactManager("memory"); // i tried this, its also not working // Create example contact QContact example; // Add contact name QContactName name; name.setFirstName("John"); name.setLastName("Doe"); example.saveDetail(&name); // Add contact email address //QContactEmailAddress email; // email.setContexts(QContactDetail::ContextHome); //email.setEmailAddress(“[email protected]”); // example.saveDetail(&email); // Finally, save the contact details cm->saveContact(&example); delete cm; Thanks

    Read the article

  • Why isn't my File.Move() working?

    - by yeahumok
    I'm not sure what exactly i'm doing wrong here...but i noticed that my File.Move() isn't renaming any files. Also, does anybody know how in my 2nd loop, i'd be able to populate my .txt file with a list of the path AND sanitized file name? using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.IO; using System.Text.RegularExpressions; namespace ConsoleApplication2 { class Program { static void Main(string[] args) { //recurse through files. Let user press 'ok' to move onto next step string[] files = Directory.GetFiles(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); foreach (string file in files) { Console.Write(file + "\r\n"); } Console.WriteLine("Press any key to continue..."); Console.ReadKey(true); //End section //Regex -- find invalid chars string pattern = " *[\\~#%&*{}/<>?|\"-]+ *"; string replacement = " "; Regex regEx = new Regex(pattern); string[] fileDrive = Directory.GetFiles(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); List<string> filePath = new List<string>(); //clean out file -- remove the path name so file name only shows string result; foreach(string fileNames in fileDrive) { result = Path.GetFileName(fileNames); filePath.Add(result); } StreamWriter sw = new StreamWriter(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing\File_Renames.txt"); //Sanitize and remove invalid chars foreach(string Files2 in filePath) { try { string sanitized = regEx.Replace(Files2, replacement); sw.Write(sanitized + "\r\n"); System.IO.File.Move(Files2, sanitized); System.IO.File.Delete(Files2); } catch (Exception ex) { Console.Write(ex); } } sw.Close(); } } } I'm VERY new to C# and trying to write an app that recurses through a specific drive, finds invalid characters (as specified in the RegEx pattern), removes them from the filename and then write a .txt file that has the path name and the corrected filename. Any ideas?

    Read the article

  • Linq to SQL inheritance and Table per Class - approach needed for multiple roles

    - by Ash Machine
    I am using L2S and an inheritance model for mapping Persons against certain roles. Guy Burstein's excellent blog post explains how to accomplish this: http://blogs.microsoft.co.il/blogs/bursteg/archive/2007/10/01/linq-to-sql-inheritance.aspx However, I have a specific case where a Person has multiple roles. For example 'Jane Doe' is a Contact and a Programmer. In this model, she would need two rows in the People table, one as Contact (PersonType = 1) and one as Programmer (PersonType = 3). If she changes her last name, and that update happens in her role as Contact, I would need to change all instances of 'Jane Doe' to reflect the name change everywhere. What sort of best approach (improved data structure) could be used to change last name within all roles? Finally, I am hoping to avoid overriding each general form update events to include all instances, but that may be the only way. Any suggestions or approaches appreciated.

    Read the article

  • String padding for a text template

    - by ndee
    I'm creating a PDF file from a txt-template with tcpdf ([Example 8][1]). The txt-template looks like this: SALUTATION FIRSTNAME LASTNAME STREET CURRENTDATE SOMEMOREINFORMATION MYWEBSITE I replace those markers with the correct value. So that it would look like this: Mr. John Doe Downingstreet 10 14th May, 2010 [email protected] www.stackoverflow.com In this example, when I replace the values, the indention of the date is dependent on the length of the street name (which I don't want). I could solve this issue with str_pad but the problem is, I normally use three columns and there are lines which only have content in col1 and col3 as in the last line. How can I solve that problem? Is there something like the "overwrite" function in Word, that when you write, the text just gets overwritten? Thanks in advance.

    Read the article

  • Use HTTP PUT to create new cache (ehCache) running on the same Tomcat?

    - by socal_javaguy
    I am trying to send a HTTP PUT (in order to create a new cache and populate it with my generated JSON) to ehCache using my webservice which is on the same local tomcat instance. Am new to RESTful Web Services and am using JDK 1.6, Tomcat 7, ehCache, and JSON. I have my POJOs defined like this: Person POJO: import javax.xml.bind.annotation.XmlRootElement; @XmlRootElement public class Person { private String firstName; private String lastName; private List<House> houses; // Getters & Setters } House POJO: import javax.xml.bind.annotation.XmlRootElement; @XmlRootElement public class House { private String address; private String city; private String state; // Getters & Setters } Using a PersonUtil class, I hardcoded the POJOs as follows: public class PersonUtil { public static Person getPerson() { Person person = new Person(); person.setFirstName("John"); person.setLastName("Doe"); List<House> houses = new ArrayList<House>(); House house = new House(); house.setAddress("1234 Elm Street"); house.setCity("Anytown"); house.setState("Maine"); houses.add(house); person.setHouses(houses); return person; } } Am able to create a JSON response per a GET request: @Path("") public class MyWebService{ @GET @Produces(MediaType.APPLICATION_JSON) public Person getPerson() { return PersonUtil.getPerson(); } } When deploying the war to tomcat and pointing the browser to http://localhost:8080/personservice/ Generated JSON: { "firstName" : "John", "lastName" : "Doe", "houses": [ { "address" : "1234 Elmstreet", "city" : "Anytown", "state" : "Maine" } ] } So far, so good, however, I have a different app which is running on the same tomcat instance (and has support for REST): http://localhost:8080/ehcache/rest/ While tomcat is running, I can issue a PUT like this: echo "Hello World" | curl -S -T - http://localhost:8080/ehcache/rest/hello/1 When I "GET" it like this: curl http://localhost:8080/ehcache/rest/hello/1 Will yield: Hello World What I need to do is create a POST which will put my entire Person generated JSON and create a new cache: http://localhost:8080/ehcache/rest/person And when I do a "GET" on this previous URL, it should look like this: { "firstName" : "John", "lastName" : "Doe", "houses": [ { "address" : "1234 Elmstreet", "city" : "Anytown", "state" : "Maine" } ] } So, far, this is what my PUT looks like: @PUT @Path("/ehcache/rest/person") @Produces(MediaType.APPLICATION_JSON) @Consumes(MediaType.APPLICATION_JSON) public Response createCache() { ResponseBuilder response = Response.ok(PersonUtil.getPerson(), MediaType.APPLICATION_JSON); return response.build(); } Question(s): (1) Is this the correct way to write the PUT? (2) What should I write inside the createCache() method to have it PUT my generated JSON into: http://localhost:8080/ehcache/rest/person (3) What would the command line CURL comment look like to use the PUT? Thanks for taking the time to read this...

    Read the article

  • whats wrong with this piece of code for saving contacts

    - by Shadow
    Hi, i am using the latest Nokia Qt SDK. i have tried to add the contacts, its not getting added.. what is missing here.. // Construct contact manager for default contact backend QContactManager* cm = new QContactManager("simulator"); // QContactManager* cm = new QContactManager("memory"); // i tried this, its also not working // Create example contact QContact example; // Add contact name QContactName name; name.setFirstName("John"); name.setLastName("Doe"); example.saveDetail(&name); // Add contact email address //QContactEmailAddress email; // email.setContexts(QContactDetail::ContextHome); //email.setEmailAddress(“[email protected]”); // example.saveDetail(&email); // Finally, save the contact details cm->saveContact(&example); delete cm; Thanks

    Read the article

  • Javascript split with RegEx

    - by Rohan
    Hey again, I just asked a question about Regex, and received a great answer: http://stackoverflow.com/questions/3047201/javascript-split-without-losing-character Now, I have another question. My current Regex looks like this: var split = text.split(/(?=\w*\d*\d:\d\d)/); Basically, I'm trying to split using the timestamps (eg - 9:30 or 10:30, the difference between them is the extra digit in the latter). How do I go about this? Currently, if I have these two: 9:30 pm The user did action A. 10:30 pm Welcome, user John Doe. The splits are : 9:30 pm The user did action A. ---- 1 ---- 0:30 pm Welcome, user John Doe. How do I add an optional check for the first character in the timestamp? Thanks!

    Read the article

  • Converting c++ string to int

    - by skazhy
    Hi! I have the following data in a c++ string John Doe 01.01.1970 I need to extract the date and time from it into int variables. I tried it like this: int last_space = text_string.find_last_of(' '); int day = int(text_string.substr(last_space + 1, 2)); But I got invalid cast from type ‘std::basic_string’ to type ‘int’. When I extract the "John Doe" part in another string variable, all works fine. What's wrong? I am trying to compile it with g++ -Wall -Werror.

    Read the article

  • Store data in an inconvenient table or create a derived table?

    - by user1705685
    I have a certain predefined database structure that I am stuck with. The question is whether this structure is OK for ORM or I whether should add a processing layer that would create a more convenient structure every time something is inserted into the original DB. To simplify, here's what it kind of looks like. I have a person table: PersonId Name And I have a properties table: PersonId PropertyType PropertyValue So, for person John Doe... (1, 'John Doe') ...I could have three properties: (1, 'phone', '555-55-55'), (1, 'email', '[email protected]), (1, 'type', 'employee') By using ORM I would like to get a "person" object that would have properties "name", "phone", "email", "type". Can Propel do that? How efficient is it? Is it a better idea to create a table with columns "phone", "email", "type" and fill it automatically as new rows are inserted into the properties table?

    Read the article

  • Sort a list numerically in Python

    - by Matthew
    So I have this list, we'll call it listA. I'm trying to get the [3] item in each list e.g. ['5.01','5.88','2.10','9.45','17.58','2.76'] in sorted order. So the end result would start the entire list over again with Santa at the top. Does that make any sense? [['John Doe', u'25.78', u'20.77', '5.01'], ['Jane Doe', u'21.08', u'15.20', '5.88'], ['James Bond', u'20.57', u'18.47', '2.10'], ['Michael Jordan', u'28.50', u'19.05', '9.45'], ['Santa', u'31.13', u'13.55', '17.58'], ['Easter Bunny', u'17.20', u'14.44', '2.76']]

    Read the article

  • font-smoothing not applied to buttons

    - by David
    I have used this snippet to prevent webkit from changing antialiasing when using CSS transforms: html{ -webkit-font-smoothing: antialiased; } This works fine for most cases, however I noticed some weirdness in chrome when playing around with Bootstrap using this HTML: <button class="btn btn-inverse">John Doe</button> <a class="btn btn-inverse">John Doe</a>? This is how it looks in OSX/Chrome: Fiddle: http://jsfiddle.net/hY2J7/. In fact, it seems that it is not applied to buttons at all. Is there a safer technique to trigger the same antialiasing in webkit for all elements?

    Read the article

  • ASP.NET ViewState Tips and Tricks #2

    - by João Angelo
    If you need to store complex types in ViewState DO implement IStateManager to control view state persistence and reduce its size. By default a serializable object will be fully stored in view state using BinaryFormatter. A quick comparison for a complex type with two integers and one string property produces the following results measured using ASP.NET tracing: BinaryFormatter: 328 bytes in view state IStateManager: 28 bytes in view state BinaryFormatter sample code: // DO NOT [Serializable] public class Info { public int Id { get; set; } public string Name { get; set; } public int Age { get; set; } } public class ExampleControl : WebControl { protected override void OnLoad(EventArgs e) { base.OnLoad(e); if (!this.Page.IsPostBack) { this.User = new Info { Id = 1, Name = "John Doe", Age = 27 }; } } public Info User { get { object o = this.ViewState["Example_User"]; if (o == null) return null; return (Info)o; } set { this.ViewState["Example_User"] = value; } } } IStateManager sample code: // DO public class Info : IStateManager { public int Id { get; set; } public string Name { get; set; } public int Age { get; set; } private bool isTrackingViewState; bool IStateManager.IsTrackingViewState { get { return this.isTrackingViewState; } } void IStateManager.LoadViewState(object state) { var triplet = (Triplet)state; this.Id = (int)triplet.First; this.Name = (string)triplet.Second; this.Age = (int)triplet.Third; } object IStateManager.SaveViewState() { return new Triplet(this.Id, this.Name, this.Age); } void IStateManager.TrackViewState() { this.isTrackingViewState = true; } } public class ExampleControl : WebControl { protected override void OnLoad(EventArgs e) { base.OnLoad(e); if (!this.Page.IsPostBack) { this.User = new Info { Id = 1, Name = "John Doe", Age = 27 }; } } public Info User { get; set; } protected override object SaveViewState() { return new Pair( ((IStateManager)this.User).SaveViewState(), base.SaveViewState()); } protected override void LoadViewState(object savedState) { if (savedState != null) { var pair = (Pair)savedState; this.User = new Info(); ((IStateManager)this.User).LoadViewState(pair.First); base.LoadViewState(pair.Second); } } }

    Read the article

  • Directx and Open Libraries list? [closed]

    - by OVERTONE
    I've just been looking for comparissons between open and proprietary frameworks and libraries. More so just to get an idea of what exists than how they compare. For example: We have DirectX (graphics) and its open counterpart OpenGL DirectX (sound) and OpenAL But there are other DirectX libraries that I can't find open alternatives to such as DirectInput DXGI Direct2D DirectWrite Doe's anyone have any list's or Comparisons between Directx and their open counterparts?

    Read the article

  • Excel 2007 - Adding line breaks in a cell and no line over 50 characters

    - by Richard Drew
    I have notes stored in an excel cell. I add line breaks and dates every time I add a new note. I need to copy this to another program, but it has a line limit of 50 characters. I want a line break for each new date and for when each date's comment goes over 50 characters. I'm able to do one or the other, but I can't figure out how to do both. I'd prefer words not to be split up, but at this point I don't care. Below is some sample input. If needed for a SUBSTITUTE or REPLACE function, I could add a ~ before each date in my input as a delimiter. Sample Input: 07/03 - FU on query. Copies and history included. CC to Jane Doe and John Public 06/29 - Cust claiming not to have these and wrong PO on query form. Responded with inv sent dates and locations, correct PO values, and copies. 06/27 - New ticket opened using query form 06/12 - Opened ticket with helpdesk asking status 05/21 - Copy submitted to [email protected] 05/14 - Copy sent to John Public and [email protected] Ideal Output: 07/03 - FU on query. Copies and history included. CC to Jane Doe and John Public 06/29 - Cust claiming not to have these and wrong PO on query form. Responded with inv sent dates an d locations, correct PO values, and copies. 06/27 - New ticket opened using query form 06/12 - Opened ticket with helpdesk asking status 05/21 - Copy submitted to [email protected] om 05/14 - Copy sent to John Public and email@custome r.com

    Read the article

  • CakePHP 3-level-deep model associatons

    - by user357452
    Hi, I am relatively new to CakePHP, I am doing fine with the documentation, but I've been trying to find a way out to this problem for weeks and I don't seem to find the solution, I am sure it is easy and maybe even automagicaly doable, but I just don't know how to find it (maybe I don't know the jargon for these kind of things) My model structure is like this: <?php class Trip extends AppModel { var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id' ), 'Start' => array( 'className' => 'Place', 'foreignKey' => 'start_id' ), 'End' => array( 'className' => 'Place', 'foreignKey' => 'end_id' ), 'Transport' => array( 'className' => 'Transport', 'foreignKey' => 'transport_id' ) ); } ?> <?php class Place extends AppModel { var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id' ), 'Country' => array( 'className' => 'Country', 'foreignKey' => 'country_id' ), 'State' => array( 'className' => 'State', 'foreignKey' => 'state_id' ), 'City' => array( 'className' => 'City', 'foreignKey' => 'city_id' ) ); var $hasMany = array( 'PlaceStart' => array( 'className' => 'trip', 'foreignKey' => 'start_id', 'dependent' => false ), 'PlaceEnd' => array( 'className' => 'trip', 'foreignKey' => 'end_id', 'dependent' => false ) ); } ?> <?php class State extends AppModel { var $belongsTo = array( 'Country' => array( 'className' => 'Country', 'foreignKey' => 'country_id', 'conditions' => '', 'fields' => '', 'order' => '' ) ); var $hasMany = array( 'City' => array( 'className' => 'City', 'foreignKey' => 'city_id', 'dependent' => false ) ); } ?> ... and so forth with User, City, Country, and Transport Models. What I am trying to achieve is to get all the information of the whole tree when I search for a Trip. <?php class TripController extends AppController { function index() { debug($this->Trip->find('first')); } } Outputs Array ( [Trip] => Array ( [id] => 6 [created] => 2010-05-04 00:23:59 [user_id] => 4 [start_id] => 2 [end_id] => 1 [title] => My trip [transport_id] => 1 ) [User] => Array ( [id] => 4 [name] => John Doe [email] => [email protected] ) [Start] => Array ( [id] => 2 [user_id] => 4 [country_id] => 1 [state_id] => 1 [city_id] => 1 [direccion] => Lincoln Street ) [End] => Array ( [id] => 1 [user_id] => 4 [country_id] => 1 [state_id] => 1 [city_id] => 4 [address] => Fifth Avenue ) [Transport] => Array ( [id] => 1 [name] => car ) ) Here is the question: How do I get in one query all the information down the tree? I would like to have something like Array ( [Trip] => Array ( [id] => 6 [created] => 2010-05-04 00:23:59 [User] => Array ( [id] => 4 [name] => John Doe [email] => [email protected] ) [Start] => Array ( [id] => 2 [user_id] => 4 [Country] => Array ( [id] => 1 [name] = Spain ) [State] => Array ( [id] => 1 [name] = Barcelona ) [City] => Array ( [id] => 1 [name] = La Floresta ) [address] => Lincoln Street ) [End] => (same as Start) [title] => My trip [Transport] => Array ( [id] => 1 [name] => car ) ) ) Can CakePHP create this kind of data? Not only for $this->Model->find() but also for $this->paginate() as for example: // filter by start if(isset($this->passedArgs['start'])) { //debug('isset '.$this->passedArgs['start']); $start = $this->passedArgs['start']; $this->paginate['conditions'][] = array( 'OR' => array( 'Start.address LIKE' => "%$start%", 'Start.State.name LIKE' => "%$start%", 'Start.City.name LIKE' => "%$start%", 'Start.Country.name LIKE' => "%$start%" ) ); $this->data['Search']['start'] = $start; } It seems like a rough question but I am sure this is extensively done and documented, I'd really appreciate any help. Thanks Cheers Naoise

    Read the article

  • JavaScript Browser Hacks

    Recently during one of my client side scripting classes, I was trying to show my students some basic examples of JavaScript as an introduction to the language.  My first basic example was to show an alert box using JavaScript via the address bar. The student’s reaction to my browser hack example really caught me off guard in a good way. After programming with a language for close to 10 years you start to lose the "Awe Cool!" effect that new learners of a language experience when writing code. New learns of JavaScript are the reason why I created this post. Please enjoy. Note: Place JavaScript in to address bar and then press the enter key. Example 1: JavaScript Alert box displaying My name: John Doe Javascript:alert('My name: \n John Doe') ; Example 2: JavaScript alert box displaying name entered by user. javascript:alert('My name: \n ' + prompt('Enter Name','Name')) ; Example 3: JavaScript alert box displaying name entered by user, and then displays the length of the name. javascript:var name= prompt('Enter Name','Name'); alert('My name: \n ' + name); alert(name.length); If you notice, the address bar will execute JavaScript on the current page loaded in the browser using the Document Object Model (DOM). Additionally, the address bar will allow multiple lines to be executed sequentially even though all of the code is contained within one line due to the fact that the JavaScript interpreter uses the “;” to indicate where a line of ends and a new one begins. After doing a little more research on the topic of JavaScript Browser Hacks I found a few other cool JavaScript hacks which I will list below. Example 4: Make any webpage editableSource: http://www.openjason.com/2008/09/02/browser-hack-make-any-web-page-editable/ javascript:document.body.contentEditable='true'; document.designMode='on'; void 0; Example 5: CHINESE DRAGON DANCING Source: http://nzeyi.wordpress.com/2009/06/01/dwrajaxjavascript-hacks-the-secrets-of-javascript-in-the-adress-bar/ javascript:R=0;x1=0.1;y1=0.05;x2=0.25;y2=0.24;x3=1.6; y3=0.24;x4=300;y4=200;x5=300;y5=200;DI=document.links; DIL=DI.length;A=function(){for(i=0;i-DIL;i++){DI[i].style. position='absolute';DI[i].style.left=Math.sin(R*x1+i*x2+x3)*x4+ x5;DI[i].style.top=Math.cos(R*y1+i*y2+y3)*y4+y5}R++;}; setInterval('A()',5);void(0); Example 6: Reveal content stored in password protected fields javascript:(function(){var s,F,j,f,i; s = “”; F = document.forms; for(j=0; j Example 7: Force user to close browser windowSource: http://forums.digitalpoint.com/showthread.php?t=767053 javascript:while(1){alert('Restart your brower to close this box!')} Learn more about JavaScript Browser Hacks.

    Read the article

  • Swift Mailer email sending problem

    - by air
    i have downloaded Swift Mailer from their website and try to send simple email with following code <?php require_once 'lib/swift_required.php'; $transport = Swift_SmtpTransport::newInstance('smtp.example.org', 25) ->setUsername('your username') ->setPassword('your password') ; $mailer = Swift_Mailer::newInstance($transport); //Create a message $message = Swift_Message::newInstance('Wonderful Subject') ->setFrom(array('[email protected]' => 'John Doe')) ->setTo(array('[email protected]', '[email protected]' => 'A name')) ->setBody('Here is the message itself') ; //Send the message $result = $mailer->send($message); ? once i run the page it gives error Warning: fsockopen() [function.fsockopen]: php_network_getaddresses: getaddrinfo failed: No such host is known. in E:\web_sites\swift_mail\lib\classes\Swift\Transport\StreamBuffer.php on line 233 Warning: fsockopen() [function.fsockopen]: unable to connect to smtp.fiveocean.net:25 (php_network_getaddresses: getaddrinfo failed: No such host is known. ) in E:\web_sites\swift_mail\lib\classes\Swift\Transport\StreamBuffer.php on line 233 Fatal error: Uncaught exception 'Swift_TransportException' with message 'Connection could not be established with host smtp.fiveocean.net [php_network_getaddresses: getaddrinfo failed: No such host is known. #0]' in E:\web_sites\swift_mail\lib\classes\Swift\Transport\StreamBuffer.php:235 Stack trace: #0 E:\web_sites\swift_mail\lib\classes\Swift\Transport\StreamBuffer.php(70): Swift_Transport_StreamBuffer->_establishSocketConnection() #1 E:\web_sites\swift_mail\lib\classes\Swift\Transport\AbstractSmtpTransport.php(101): Swift_Transport_StreamBuffer->initialize(Array) #2 E:\web_sites\swift_mail\lib\classes\Swift\Mailer.php(74): Swift_Transport_AbstractSmtpTransport->start() #3 E:\web_sites\swift_mail\test.php(33): Swift_Mailer->send(Object(Swift_Message)) #4 {main} thrown in E:\web_sites\swift_mail\lib\classes\Swift\Transport\StreamBuffer.php on line 235 if i remove the line $result = $mailer->send($message); then page execute and no error message display, as soon as i add above line to send email, i got error. my outgoing server, port and user id & passwords are correct in my file. Thanks

    Read the article

  • Reattaching an object graph to an EntityContext: "cannot track multiple objects with the same key"

    - by dkr88
    Can EF really be this bad? Maybe... Let's say I have a fully loaded, disconnected object graph that looks like this: myReport = {Report} {ReportEdit {User: "JohnDoe"}} {ReportEdit {User: "JohnDoe"}} Basically a report with 2 edits that were done by the same user. And then I do this: EntityContext.Attach(myReport); InvalidOperationException: An object with the same key already exists in the ObjectStateManager. The ObjectStateManager cannot track multiple objects with the same key. Why? Because the EF is trying to attach the {User: "JohnDoe"} entity TWICE. This will work: myReport = {Report} {ReportEdit {User: "JohnDoe"}} EntityContext.Attach(myReport); No problems here because the {User: "JohnDoe"} entity only appears in the object graph once. What's more, since you can't control how the EF attaches an entity, there is no way to stop it from attaching the entire object graph. So really if you want to reattach a complex entity that contains more than one reference to the same entity... well, good luck. At least that's how it looks to me. Any comments? UPDATE: Added sample code: // Load the report Report theReport; using (var context1 = new TestEntities()) { context1.Reports.MergeOption = MergeOption.NoTracking; theReport = (from r in context1.Reports.Include("ReportEdits.User") where r.Id == reportId select r).First(); } // theReport looks like this: // {Report[Id=1]} // {ReportEdit[Id=1] {User[Id=1,Name="John Doe"]} // {ReportEdit[Id=2] {User[Id=1,Name="John Doe"]} // Try to re-attach the report object graph using (var context2 = new TestEntities()) { context2.Attach(theReport); // InvalidOperationException }

    Read the article

< Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >