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• Does anyone really understand how HFSC scheduling in Linux/BSD works?

  - by Mecki

  I read the original SIGCOMM '97 PostScript paper about HFSC, it is very technically, but I understand the basic concept. Instead of giving a linear service curve (as with pretty much every other scheduling algorithm), you can specify a convex or concave service curve and thus it is possible to decouple bandwidth and delay. However, even though this paper mentions to kind of scheduling algorithms being used (real-time and link-share), it always only mentions ONE curve per scheduling class (the decoupling is done by specifying this curve, only one curve is needed for that). Now HFSC has been implemented for BSD (OpenBSD, FreeBSD, etc.) using the ALTQ scheduling framework and it has been implemented Linux using the TC scheduling framework (part of iproute2). Both implementations added two additional service curves, that were NOT in the original paper! A real-time service curve and an upper-limit service curve. Again, please note that the original paper mentions two scheduling algorithms (real-time and link-share), but in that paper both work with one single service curve. There never have been two independent service curves for either one as you currently find in BSD and Linux. Even worse, some version of ALTQ seems to add an additional queue priority to HSFC (there is no such thing as priority in the original paper either). I found several BSD HowTo's mentioning this priority setting (even though the man page of the latest ALTQ release knows no such parameter for HSFC, so officially it does not even exist). This all makes the HFSC scheduling even more complex than the algorithm described in the original paper and there are tons of tutorials on the Internet that often contradict each other, one claiming the opposite of the other one. This is probably the main reason why nobody really seems to understand how HFSC scheduling really works. Before I can ask my questions, we need a sample setup of some kind. I'll use a very simple one as seen in the image below: Here are some questions I cannot answer because the tutorials contradict each other: What for do I need a real-time curve at all? Assuming A1, A2, B1, B2 are all 128 kbit/s link-share (no real-time curve for either one), then each of those will get 128 kbit/s if the root has 512 kbit/s to distribute (and A and B are both 256 kbit/s of course), right? Why would I additionally give A1 and B1 a real-time curve with 128 kbit/s? What would this be good for? To give those two a higher priority? According to original paper I can give them a higher priority by using a curve, that's what HFSC is all about after all. By giving both classes a curve of [256kbit/s 20ms 128kbit/s] both have twice the priority than A2 and B2 automatically (still only getting 128 kbit/s on average) Does the real-time bandwidth count towards the link-share bandwidth? E.g. if A1 and B1 both only have 64kbit/s real-time and 64kbit/s link-share bandwidth, does that mean once they are served 64kbit/s via real-time, their link-share requirement is satisfied as well (they might get excess bandwidth, but lets ignore that for a second) or does that mean they get another 64 kbit/s via link-share? So does each class has a bandwidth "requirement" of real-time plus link-share? Or does a class only have a higher requirement than the real-time curve if the link-share curve is higher than the real-time curve (current link-share requirement equals specified link-share requirement minus real-time bandwidth already provided to this class)? Is upper limit curve applied to real-time as well, only to link-share, or maybe to both? Some tutorials say one way, some say the other way. Some even claim upper-limit is the maximum for real-time bandwidth + link-share bandwidth? What is the truth? Assuming A2 and B2 are both 128 kbit/s, does it make any difference if A1 and B1 are 128 kbit/s link-share only, or 64 kbit/s real-time and 128 kbit/s link-share, and if so, what difference? If I use the seperate real-time curve to increase priorities of classes, why would I need "curves" at all? Why is not real-time a flat value and link-share also a flat value? Why are both curves? The need for curves is clear in the original paper, because there is only one attribute of that kind per class. But now, having three attributes (real-time, link-share, and upper-limit) what for do I still need curves on each one? Why would I want the curves shape (not average bandwidth, but their slopes) to be different for real-time and link-share traffic? According to the little documentation available, real-time curve values are totally ignored for inner classes (class A and B), they are only applied to leaf classes (A1, A2, B1, B2). If that is true, why does the ALTQ HFSC sample configuration (search for 3.3 Sample configuration) set real-time curves on inner classes and claims that those set the guaranteed rate of those inner classes? Isn't that completely pointless? (note: pshare sets the link-share curve in ALTQ and grate the real-time curve; you can see this in the paragraph above the sample configuration). Some tutorials say the sum of all real-time curves may not be higher than 80% of the line speed, others say it must not be higher than 70% of the line speed. Which one is right or are they maybe both wrong? One tutorial said you shall forget all the theory. No matter how things really work (schedulers and bandwidth distribution), imagine the three curves according to the following "simplified mind model": real-time is the guaranteed bandwidth that this class will always get. link-share is the bandwidth that this class wants to become fully satisfied, but satisfaction cannot be guaranteed. In case there is excess bandwidth, the class might even get offered more bandwidth than necessary to become satisfied, but it may never use more than upper-limit says. For all this to work, the sum of all real-time bandwidths may not be above xx% of the line speed (see question above, the percentage varies). Question: Is this more or less accurate or a total misunderstanding of HSFC? And if assumption above is really accurate, where is prioritization in that model? E.g. every class might have a real-time bandwidth (guaranteed), a link-share bandwidth (not guaranteed) and an maybe an upper-limit, but still some classes have higher priority needs than other classes. In that case I must still prioritize somehow, even among real-time traffic of those classes. Would I prioritize by the slope of the curves? And if so, which curve? The real-time curve? The link-share curve? The upper-limit curve? All of them? Would I give all of them the same slope or each a different one and how to find out the right slope? I still haven't lost hope that there exists at least a hand full of people in this world that really understood HFSC and are able to answer all these questions accurately. And doing so without contradicting each other in the answers would be really nice ;-)

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• how to instantiate template of template

  - by aaa

  hello I have template that looks like this: 100 template<size_t A0, size_t A1, size_t A2, size_t A3> 101 struct mask { 103 template<size_t B0, size_t B1, size_t B2, size_t B3> 104 struct compare { 105 static const bool value = (A0 == B0 && A1 == B1 && A2 == B2 && A3 == B3); 106 }; 107 }; ... 120 const typename boost::enable_if_c< 121 mask<a,b,c,d>::compare<2,3,0,1>::value || ...>::type I am trying to instantiate compare structure. How do I do get value in line 121?

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• LINQ to read XML (C#)

  - by aximili

  I got this XML file <root> <level1 name="A"> <level2 name="A1" /> <level2 name="A2" /> </level1> <level1 name="B"> <level2 name="B1" /> <level2 name="B2" /> </level1> <level1 name="C" /> </root> Could someone give me a C# code using LINQ, the simplest way to print this result: (Note the extra space if it is a level2 node) A A1 A2 B B1 B2 C Currently I got this code XDocument xdoc = XDocument.Load("data.xml")); var lv1s = from lv1 in xdoc.Descendants("level1") select lv1.Attribute("name").Value; foreach (var lv1 in lv1s) { result.AppendLine(lv1); var lv2s = from lv2 in xdoc...??? } Thank you!

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• Theme confusion in SpreadsheetML.

  - by dmaruca

  I've been fighting this all day. Inside my styles.xml file I have color information given like so: <fgColor theme="0" tint="-0.249977111117893" / ECMA 376 defines a theme color reference as: Index into the <clrScheme collection, referencing a particular <sysClr or <srgbClr value expressed in the Theme part. Ok, that sounds easy. Here is an excerpt from my clrScheme xml: <a:clrScheme name="Office" <a:dk1 <a:sysClr val="windowText" lastClr="000000" / </a:dk1 <a:lt1 <a:sysClr val="window" lastClr="FFFFFF" / </a:lt1 Index zero is black, and they are wanting to darken it? I can tell you that after the tint is applied, the color should be #F2F2F2. My confusion is what does theme="0" really mean? It can't possible mean to darken #000000. Checking MSDN only confuses me even more. From http://msdn.microsoft.com/en-us/library/dd560821.aspx note that the theme color integer begins counting from left to right in the palette starting with zero. Theme color 3 is the dark 2 text/background color. Actually, if you start counting at zero the third entry is Light 2. Dark 2 is the second one. Can anyone here shed some light on this subject for me? What does theme="0" really mean? Here is the VB6 code I have been working with to apply the tint. You can paste it into your vba editor and run the test sub. Public Type tRGB R As Byte G As Byte B As Byte End Type Public Type tHSL H As Double S As Double L As Double End Type Sub TestRgbTint() Dim c As tRGB RGB_Hex2Type "ffffff", c RGB_ApplyTint c, -0.249977111117893 Debug.Print Hex(c.R) & Hex(c.G) & Hex(c.B) End Sub Public Sub RGB_Hex2Type(ByVal HexString As String, RGB As tRGB) 'Remove the alpha channel if it exists If Len(HexString) = 8 Then HexString = mID(HexString, 3) End If RGB.R = CByte("&H" & Left(HexString, 2)) RGB.G = CByte("&H" & mID(HexString, 3, 2)) RGB.B = CByte("&H" & Right(HexString, 2)) End Sub Public Sub RGB_ApplyTint(RGB As tRGB, tint As Double) Const HLSMAX = 1# Dim HSL As tHSL If tint = 0 Then Exit Sub RGB2HSL RGB, HSL If tint < 0 Then HSL.L = HSL.L * (1# + tint) Else HSL.L = HSL.L * (1# - tint) + (HLSMAX - HLSMAX * (1# - tint)) End If HSL2RGB HSL, RGB End Sub Public Sub HSL2RGB(HSL As tHSL, RGB As tRGB) HSL2RGB_ByVal HSL.H, HSL.S, HSL.L, RGB End Sub Private Sub HSL2RGB_ByVal(ByVal H As Double, ByVal S As Double, ByVal L As Double, RGB As tRGB) Dim v As Double Dim R As Double, G As Double, B As Double 'Default color to gray R = L G = L B = L If L < 0.5 Then v = L * (1# + S) Else v = L + S - L * S End If If v > 0 Then Dim m As Double, sv As Double Dim sextant As Integer Dim fract As Double, vsf As Double, mid1 As Double, mid2 As Double m = L + L - v sv = (v - m) / v H = H * 6# sextant = Int(H) fract = H - sextant vsf = v * sv * fract mid1 = m + vsf mid2 = v - vsf Select Case sextant Case 0 R = v G = mid1 B = m Case 1 R = mid2 G = v B = m Case 2 R = m G = v B = mid1 Case 3 R = m G = mid2 B = v Case 4 R = mid1 G = m B = v Case 5 R = v G = m B = mid2 End Select End If RGB.R = R * 255# RGB.G = G * 255# RGB.B = B * 255# End Sub Public Sub RGB2HSL(RGB As tRGB, HSL As tHSL) Dim R As Double, G As Double, B As Double Dim v As Double, m As Double, vm As Double Dim r2 As Double, g2 As Double, b2 As Double R = RGB.R / 255# G = RGB.G / 255# B = RGB.B / 255# 'Default to black HSL.H = 0 HSL.S = 0 HSL.L = 0 v = IIf(R > G, R, G) v = IIf(v > B, v, B) m = IIf(R < G, R, G) m = IIf(m < B, m, B) HSL.L = (m + v) / 2# If HSL.L < 0 Then Exit Sub End If vm = v - m HSL.S = vm If HSL.S > 0 Then If HSL.L <= 0.5 Then HSL.S = HSL.S / (v + m) Else HSL.S = HSL.S / (2# - v - m) End If Else Exit Sub End If r2 = (v - R) / vm g2 = (v - G) / vm b2 = (v - B) / vm If R = v Then If G = m Then HSL.H = 5# + b2 Else HSL.H = 1# - g2 End If ElseIf G = v Then If B = m Then HSL.H = 1# + r2 Else HSL.H = 3# - b2 End If Else If R = m Then HSL.H = 3# + g2 Else HSL.H = 5# - r2 End If End If HSL.H = HSL.H / 6# End Sub

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• JavaScript inline events syntax

  - by Mic

  Is there any reason to use one of the following more than the others: <input type="button" value="b1" onclick="manageClick(this)" /> <input type="button" value="b2" onclick="manageClick(this);" /> <input type="button" value="b2" onclick="manageClick(this);return false;" /> <input type="button" value="b3" onclick="return manageClick(this);" /> <input type="button" value="b4" onclick="javascript:return manageClick(this);" /> And please do not spend your valuable time to tell me to use jQuery or attachEvent/addEventListener. It's not really the objective of my question.

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• Help Understanding the Mork File Format

  - by Sumit Ghosh

  Hi, I have a name value pair in a Java HashMap and this in continuation to my earlier question - here NickName=,LastModifiedDate=4ac18267,FaxNumberType=,BirthMonth=,LastName=,HomePhone=,WorkCountry=,HomePhoneType=,PreferMailFormat=0,CellularNumber=,FamilyName=,[email protected],AnniversaryMonth=,HomeCity=,WorkState=,HomeCountry=,PhoneticFirstName=,PhoneticLastName=,HomeState=,WorkAddress=,WebPage1=,WebPage2=,HomeAddress2=,WorkZipCode=,_AimScreenName=,AnniversaryYear=,WorkPhoneType=,Notes=,WorkAddress2=,WorkPhone=,Custom3=,Custom4=,Custom1=,Custom2=,PagerNumber=,AnniversaryDay=,WorkCity=,AllowRemoteContent=0,CellularNumberType=,FaxNumber=,PopularityIndex=2,FirstName=,SpouseName=,CardType=,Department=,Company=,HomeAddress=,BirthDay=,SecondEmail=,RecordKey=1,DisplayName=,DefaultEmail=,DefaultAddress=,BirthYear=,Category=,PagerNumberType=,[email protected],JobTitle=,HomeZipCode=, NickName=,LastModifiedDate=0,FaxNumberType=,BirthMonth=,LastName=Ghosh,HomePhone=+504-9907-1342,WorkCountry=USA,HomePhoneType=,PreferMailFormat=2,CellularNumber=512-282-2512,FamilyName=,[email protected],AnniversaryMonth=,HomeCity=Siguatepeque,WorkState=TX,HomeCountry=Honduras,PhoneticFirstName=,PhoneticLastName=,HomeState=Comayagua,WorkAddress=9309 HeatherwoodDr,WebPage1=http://www.mpcsol.com,WebPage2=http://www.jesuslovesthelittlechildren.org,HomeAddress2=VillaAlicia,WorkZipCode=78748,_AimScreenName=rentaprogrammer,AnniversaryYear=,WorkPhoneType=,Notes=Some notes go here.,WorkAddress2=Apartment 1,WorkPhone=512-282-2509,Custom3=Faith,Custom4=Timothy,Custom1=Hannah,Custom2=John,PagerNumber=512-282-2511,AnniversaryDay=,WorkCity=Austin,AllowRemoteContent=1,CellularNumberType=,FaxNumber=512-282-2510,PopularityIndex=0,FirstName=Sumit,SpouseName=,CardType=,Department=Programming,Company=MPC Solutions,HomeAddress=Two Blocks Past Oxen Team,BirthDay=,[email protected],RecordKey=2,DisplayName=Sumit,DefaultEmail=,DefaultAddress=,BirthYear=,Category=,PagerNumberType=,[email protected],JobTitle=Programmer,HomeZipCode=NA, NickName=,LastModifiedDate=0,FaxNumberType=,BirthMonth=,LastName=,HomePhone=,WorkCountry=,HomePhoneType=,PreferMailFormat=0,CellularNumber=,FamilyName=,[email protected],AnniversaryMonth=,HomeCity=,WorkState=,HomeCountry=,PhoneticFirstName=,PhoneticLastName=,HomeState=,WorkAddress=,WebPage1=,WebPage2=,HomeAddress2=,WorkZipCode=,_AimScreenName=,AnniversaryYear=,WorkPhoneType=,Notes=,WorkAddress2=,WorkPhone=,Custom3=,Custom4=,Custom1=,Custom2=,PagerNumber=,AnniversaryDay=,WorkCity=,AllowRemoteContent=0,CellularNumberType=,FaxNumber=,PopularityIndex=0,FirstName=,SpouseName=,CardType=,Department=,Company=,HomeAddress=,BirthDay=,SecondEmail=,RecordKey=3,DisplayName=,DefaultEmail=,DefaultAddress=,BirthYear=,Category=,PagerNumberType=,[email protected],JobTitle=,HomeZipCode=, I want to write it to a Mork file , using the Mork file format, can someone tell me how to decode the name value pair to this format given below. <(A9=3)(81=)([email protected])(80=0)(85=2)(86=4ac18267)(83=1) (87=Sumit)(88=Ghosh)(89=Sumit)([email protected])(8B [email protected])(8C=512-282-2509)(8D=+504-9907-1342)(8E=512-282-2510) (8F=512-282-2511)(90=512-282-2512)(91=Two Blocks Past Oxen Team)(92 =Villa Alicia)(93=Siguatepeque)(94=Comayagua)(95=NA)(96=Honduras) (97=9309 Heatherwood Dr)(98=Apartment 1)(99=Austin)(9A=TX)(9B=78748) (9C=USA)(9D=Programmer)(9E=Programming)(9F=MPC Solutions)(A0 =rentaprogrammer)(A1=http://www.mpcsol.com)(A2 =http://www.jesuslovesthelittlechildren.org)(A3=Hannah)(A4=John) (A5=Faith)(A6=Timothy)(A7=Some notes go here.)(A8 [email protected])> {1:^80 {(k^C0:c)(s=9)} [1:^82(^BF=3)] [1(^83=)(^84=)(^85=)(^86=)(^87=)(^88=)(^89^82)(^8A^82)(^8B=)(^8C=) (^8D=)(^8E=0)(^8F=2)(^90=0)(^91=)(^92=)(^93=)(^94=)(^95=)(^96=) (^97=)(^98=)(^99=)(^9A=)(^9B=)(^9C=)(^9D=)(^9E=)(^9F=)(^A0=)(^A1=) (^A2=)(^A3=)(^A4=)(^A5=)(^A6=)(^A7=)(^A8=)(^A9=)(^AA=)(^AB=)(^AC=) (^AD=)(^AE=)(^AF=)(^B0=)(^B1=)(^B2=)(^B3=)(^B4=)(^B5=)(^B6=)(^B7=) (^B8=)(^B9=)(^BA=)(^BB=)(^BC^86)(^BD=1)] [2(^83^87)(^84^88)(^85=)(^86=)(^87^89)(^88=)(^89^8A)(^8A^8A)(^8B^8B) (^8C=)(^8D=)(^8E=2)(^8F=0)(^90=1)(^91^8C)(^92^8D)(^93^8E)(^94^8F) (^95^90)(^96=)(^97=)(^98=)(^99=)(^9A=)(^9B^91)(^9C^92)(^9D^93)(^9E^94) (^9F=NA)(^A0^96)(^A1^97)(^A2^98)(^A3^99)(^A4=TX)(^A5^9B)(^A6^9C) (^A7^9D)(^A8^9E)(^A9^9F)(^AA^A0)(^AB=)(^AC=)(^AD=)(^AE=)(^AF=)(^B0=) (^B1=)(^B2^A1)(^B3^A2)(^B4=)(^B5=)(^B6=)(^B7^A3)(^B8^A4)(^B9^A5) (^BA^A6)(^BB^A7)(^BC=0)(^BD=2)] [3(^83=)(^84=)(^85=)(^86=)(^87=)(^88=)(^89^A8)(^8A^A8)(^8B=)(^8C=) (^8D=)(^8E=0)(^8F=0)(^90=0)(^91=)(^92=)(^93=)(^94=)(^95=)(^96=) (^97=)(^98=)(^99=)(^9A=)(^9B=)(^9C=)(^9D=)(^9E=)(^9F=)(^A0=)(^A1=) (^A2=)(^A3=)(^A4=)(^A5=)(^A6=)(^A7=)(^A8=)(^A9=)(^AA=)(^AB=)(^AC=) (^AD=)(^AE=)(^AF=)(^B0=)(^B1=)(^B2=)(^B3=)(^B4=)(^B5=)(^B6=)(^B7=) (^B8=)(^B9=)(^BA=)(^BB=)(^BC=0)(^BD=3)]}

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• Setting Background of a Jbutton

  - by mithun1538

  Hello there, I have 5 JButtons: b1, b2, b3, b4, b5. By default, their color is gray. When I click on any button, the background of that button changes to white. When I click another button, I want that previous clicked button to change its background to gray, and this newly clicked button to change its background to white. Here is the code that I wrote: int liveButton = 0; //holds the value of the button that is last clicked. //0 indicates no button clicked (in the beginning) private void ChangeInUsersList(int clickedButton) { switch(liveButton) { case 1 : b1.setBackground(Color.GRAY); break; case 2 : b2.setBackground(Color.GRAY); break; case 3 : b3.setBackground(Color.GRAY); break; case 4 : b4.setBackground(Color.GRAY); break; case 5 : b5.setBackground(Color.GRAY); break; default: System.out.println("No button to change"); } liveButton = clickedButton;// store the clicked button to change its //background later } private void b1ActionPerformed(java.awt.event.ActionEvent evt) { ChangeInUsersList(1); b1.setBackground(new java.awt.Color(255,255,255)); } private void b2ActionPerformed(java.awt.event.ActionEvent evt) { ChangeInUsersList(2); b2.setBackground(new java.awt.Color(255,255,255)); } private void b3ActionPerformed(java.awt.event.ActionEvent evt) { ChangeInUsersList(3); b3.setBackground(new java.awt.Color(255,255,255)); } private void b4ActionPerformed(java.awt.event.ActionEvent evt) { ChangeInUsersList(4); b4.setBackground(new java.awt.Color(255,255,255)); } private void b5ButtonActionPerformed(java.awt.event.ActionEvent evt) { ChangeInUsersList(5); b5.setBackground(new java.awt.Color(255,255,255)); } However, its not working as expected. When i click on a button, its background does change to white. However, if i click on some other button after that, the former button's background doesnt change to grey. I tried replacing Color.GREY with new java.awt.Color(236,233,216) - the rgb for grey but it still doesnt work.

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• Perform selector on parent NSOperation

  - by user326943

  I extend NSOperation (call it A) which contains NSOperationQueue for other NSOperations (which is another extended class different from A, call these operations B). When operation A is running (executing B operations) how do i call a specific function/method on operation A when certain event takes place on B operations? For example every operation B that finishes it calls a function on operation A returning itself? *Nested NSOperation and NSOperationQueue(s) Hope this mockup pseudo code can help to draw the picture. //My classes extended from NSOperation NSOperation ClassA NSOperation ClassB //MainApp -(void)applicationDidFinishLaunching:(NSNotification *)aNotification { ClassA A1; ClassA A2; NSOperationQueue Queue; Queue AddOperation: A1; Queue AddOperation: A2; } //Main of ClassA -(void)main { ClassB B1; ClassB B2; NSOperationQueue Queue; Queue AddOperation: B1; Queue AddOperation: B2; } //Main of ClassB -(void)main { //Do some work and when done call selector on ClassA above }

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• Populate new row with VBA button click

  - by AME

  Hi, I am trying to create a list that adds a new row of data each time a button is clicked. I have the following code assigned to the button when clicked: PurchaseDate = InputBox("Enter Purchase Date:") Sheets("TrackRecord").Select i = 0 Row = i + 1 Range("A2").Select ActiveCell.FormulaR1C1 = Row Range("B2").Select ActiveCell.FormulaR1C1 = "=Dashboard!R26C4*(1/Dashboard!R26C12)" Range("C2").Select ActiveCell.FormulaR1C1 = "=Dashboard!R26C2" Range("D2").Select ActiveCell.FormulaR1C1 = PurchaseDate Range("E2").Select ActiveCell.FormulaR1C1 = "=Dashboard!R26C8 + R2C4" Range("F2").Select ActiveCell.FormulaR1C1 = "=Waterfall!R[8]C[5]" Range("F2").Select Selection.AutoFill Destination:=Range("F2:I2"), Type:=xlFillDefault Range("F2:I2").Select End Sub This code works fine, but I'd like it populate the next row below instead of overwriting the same row each time the button is clicked. I know that I have to iterate through the "Range("A2").select" section, e.g. "Range("A2").select" -- "Range("B2").select" .. But I don't know how to do this in VBA for Excel. That's why I am asking you folks ; ) . Thanks,

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• mysqldump generating an empty file

  - by chupinette

  Hello all! Im trying to use mysqldump like below: mysqldump -hlocalhost -uadmin -padmin shop> D:\b2\shop3.sql When i execute it in command prompt, the file shop3 is generated with all the tables from the shop database. But, when I use it in my php file like below, it generates an empty file. $cmd = 'mysqldump -hlocalhost -uadmin -padmin shop > D:\b2\shop3.sql'; system($cmd); Can anyone help me find my error please? Thanks

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• Clearcase: findmerge usage.

  - by Keshav

  Hi, I have a branch B1 and another branch B2. I want all files/subfolders (recursively) inside a particular folder X (and not on entire VOB) on B1 to be merged onto B2. What exact findmerge command do I need to use? The below commands will work for entire vob or if I run them by getting into the directory in question, that will suffice for me? cleartool findmerge . -type dir -nc -fver .../dev/LATEST -merge cleartool findmerge . -nc -type file -fver .../dev/LATEST -print Thanks a lot in advance.

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• CSS Rollovers: how to maintain "hit area" size when hidden image is larger than anchor area

  - by nukefusion

  I have a small problem and I don't think what I want to do can be achieved with just pure CSS, but I figured I'd ask anyway. Basically, I have one DIV which contains a hyperlinked element that is smaller in size to it's parent DIV. So in effect I have a square within a square with the inner square being the "hit area". When I mouse over this inner square I want the background of the outer square to change. I know it's not possible to change the parent DIV's background on a:hover, but I figured I could give the illusion of it happening by nesting a hidden image inside the anchor. This works great until I want to "roll off". The problem is that I want the image to disappear when I leave the area of the anchor tag, not the larger hidden image. Is this possible? For the benefit of everyone I've provided an example to demonstrate what I mean: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>Test Rollover</title> <link href="main.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="d1"> <a href="#nogo"> <b id="b1"></b> <b id="b2"></b> </a> </div> </body> And the css: #b1 { width: 200px; height: 200px; top: 100px; left: 100px; background-color:aqua; position: absolute; z-index: 100; } #b2 { width: 400px; height: 400px; background-color:lime; position: absolute; display: none; z-index: 90; } #d1 { width: 400px; height: 400px; background-color:fuchsia; position: relative; } #d1 a:hover #b2 { display: block; } In this example I want the green outer square to disappear when I leave the bounds of the hidden inner blue square.

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• Css simple style dont work on IE but yes in any other browser

  - by DomingoSL

  Hello guys, i have a simple css file called Titulos.css who contain this: h1 { font: 50px Tahoma, Helvetica, Arial, Sans-Serif; text-align: center; color: #111; text-shadow: 0px 2px 3px #555; } h2 { font: 14px Tahoma, Helvetica, Arial, Sans-Serif; text-align: center; color: #CCC; text-shadow: 0px 1px 2px #555; } h3 { font: 10px Tahoma, Helvetica, Arial, Sans-Serif; text-align: center; color: #CCC; } b1 { font: 16px Tahoma, Helvetica, Arial, Sans-Serif; color: #DDD; } b2 { font: 10px Tahoma, Helvetica, Arial, Sans-Serif; color: #F9F7ED; } .caja { width: 690px; height: 40px; background-color: transparent; border: 0px solid #000000; font-size:x-large; color: #222; font-family: 'Trebuchet MS', 'Lucida Sans Unicode', 'Lucida Grande', 'Lucida Sans', Arial, sans-serif; font-weight: bold;" size="299"; } .style1 { text-align: right; } And a page who call this file like: <link rel="stylesheet" type="text/css" href="LIB/titulos.css" /> Later in this page im trying to use some of the styles like: <div id="todo" align="center" > <div id="cabeza" style="width:850px;height:100px"> </div> <div id="contenido" style="width:850px;height:420px;background-image: url(IMG/cuadro.png)" > <div id="titulo" style="width:765px;height:75px;padding-top: 18px;margin: auto;text-align: left;"> <b1>Bienvenido <b><?php echo($username); ?></b></b1><br> <?php $check = mysql_query("SELECT * FROM sms WHERE ref = '".$username."' ORDER BY fecha DESC LIMIT 0, 1") or die(mysql_error()); while($info = mysql_fetch_array( $check )) { echo("<b1> Tu ultimo mensaje enviado fue: </b1><b2>" . $info['texto'] . " enviado el " . $info['fecha'] . "</b2>"); That only a part of the code of course, the think is, Firefox and Chrome display the code above like this: that as you can see have the styles applied. But when i see the code from IE 8 (even 7 or 6) this is what you see: So, what do you think?

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• Excel > Microsoft Query > SQL Server > Multiple Parameters

  - by pojomx

  Hi, Im relatively new to sql server and excel/microsoft query, I have a query like this Select ...[data]...B1.b,B2.b,B3.b From TABLEA Inner join ( SELECT ---[data]...sum(...) as b From TABLEB WHERE Date between [startdate] and [enddate] ) as B1 Inner join ( SELECT ---[data]...sum(...) as b From TABLEB WHERE Date between [startdate-1week] and [enddate] ) as B2 Inner join ( SELECT ---[data]...sum(...) as b From TABLEB WHERE Date between [startdate-2weeks] and [enddate] ) as B3 Where Date between [startdate] and [enddate] It works, when i introduce the dates manually, but i need them to be "Dynamic" (introduced from excel) but, when I put the "?" (for parameters) on all the dates, it throws an error. "Invalid Parameter Number" :D How can i make this work, within excel? Im using SQL Server and Microsoft Query Connection Data.

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• CSS Rollovers: how to main "hit area" size when hidden image is larger than anchor area

  - by nukefusion

  I have a small problem and I don't think what I want to do can be achieved with just pure CSS, but I figured I'd ask anyway. Basically, I have one DIV which contains a hyperlinked element that is smaller in size to it's parent DIV. So in effect I have a square within a square with the inner square being the "hit area". When I mouse over this inner square I want the background of the outer square to change. I know it's not possible to change the parent DIV's background on a:hover, but I figured I could give the illusion of it happening by nesting a hidden image inside the anchor. This works great until I want to "roll off". The problem is that I want the image to disappear when I leave the area of the anchor tag, not the larger hidden image. Is this possible? For the benefit of everyone I've provided an example to demonstrate what I mean: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>Test Rollover</title> <link href="main.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="d1"> <a href="#nogo"> <b id="b1"></b> <b id="b2"></b> </a> </div> </body> And the css: #b1 { width: 200px; height: 200px; top: 100px; left: 100px; background-color:aqua; position: absolute; } #b2 { width: 400px; height: 400px; background-color:lime; position: absolute; display: none; } #d1 { width: 400px; height: 400px; background-color:fuchsia; position: relative; } #d1 a:hover #b2 { display: block; } In this example I want the green outer square to disappear when I leave the bounds of the hidden inner blue square.

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• Equivalent of Switch Statement in MySql 5

  - by Robert Gowland

  Using MySql 5, I have a task where I need to update one table based on the contents of another table. For example, I need to add 'A1' to table 'A' if table 'B' contains 'B1'. I need to add 'A2a' and 'A2b' to table 'A' if table 'B' contains 'B2', etc.. In our case, the value in table 'B' we're interested is an enum. Right now I have a stored procedure containing a series of statements like: INSERT INTO A SELECT 'A1' FROM B WHERE B.Value = 'B1'; --Repeat for 'B2' -> 'A2a', 'A2b'; 'B3' -> 'A3', etc... Is there a nicer more DRY way of accomplishing this?

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• Need help with developing a class for my JUnit test

  - by alpdog14

  I have this JUnit test that I need help developing a Interface and Class for, here is the test: Box b1 = new DefaultBox( "abc" ); Box b2 = new DefaultBox( "def" ); Box b3 = new DefaultBox( "" ); assertEquals("abc", b1.contents()); assertEquals("[abc]", b1.toString()); assertTrue(b1.equals(b1)); assertFalse(b1.equals(b2)); assertFalse(b1.equals(null)); assertEquals("cba", b1.flip().contents()); assertEquals("", b3.flip().contents()); can anyone help me in developing a Default box class and a box interface to make these test pass? Any help would be most appreciated.

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• Generate combinations by order and fixed length.

  - by roconmachine

  Suppose there is array main[] = [a,b,c,....z]; a[] = [a1,a2,a3,....] , b[] = [b1,b2,b3,....] and so on. So if we generate combination in main.length of ordered then it looks like ..... a1 b1 c1, a1 b1 c2, a1 b1 c3 ...... a1 b2 c1, a1 b3 c1, ..... a2 b1 c1, a3 b1 c1, ..... and total count will be a.length * b.length * c.length ........ = ? So write a code in any language to generate those combination. all the best. alex

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• How to call same method for a list of objects?

  - by Dmitry

  Suppose code like this: class Base: def start(self): pass def stop(self) pass class A(Base): def start(self): ... do something for A def stop(self) .... do something for A class B(Base): def start(self): def stop(self): a1 = A(); a2 = A() b1 = B(); b2 = B() all = [a1, b1, b2, a2,.....] Now I want to call methods start and stop (maybe also others) for each object in the list all. Is there any elegant way for doing this except of writing a bunch of functions like def start_all(all): for item in all: item.start() def stop_all(all): .....

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• Excel - Counting unique values that meet multiple criteria

  - by wotaskd

  I'm trying to use a function to count the number of unique cells in a spreadsheet that, at the same time, meet multiple criteria. Given the following example: A B C QUANT STORE# PRODUCT 1 75012 banana 5 orange 6 56089 orange 3 89247 orange 7 45321 orange 2 apple 4 45321 apple In the example above, I need to know how many unique stores with a valid STORE# have received oranges OR apples. In the case above, the result should be 3 (stores 56089, 89247 and 45321). This is how I started to try solving the problem: =SUM(IF(FREQUENCY(B2:B9,B2:B9)>0,1)) The above formula will yield the number of unique stores with a valid store#, but not just the ones that have received oranges or bananas. How can I add that extra criteria?

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• runtime/compile time polymorphism

  - by dmadhavaraj

  Hi , In the below code , why b1.subtract() fails . Please explain me the reason ie., what happens in JVM while invoking that method . class Base { public void add() { System.out.println("Base ADD"); } } class Child extends Base { public void add(){ System.out.println("Child ADD"); } public void subtract() { System.out.println("Child Subtract"); } } class MainClass { public static void main(String args[]) { Base b1 = new Base(); Base b2 = new Child(); Child b3 = new Child(); b1.add(); b1.subtract(); // ?????????** b2.add(); b3.subtract(); } }

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• Detecting coincident subset of two coincident line segments

  - by Jared Updike

  This question is related to: How do I determine the intersection point of two lines in GDI+? (great explanation of algebra but no code) How do you detect where two line segments intersect? (accepted answer doesn't actually work) But note that an interesting sub-problem is completely glossed over in most solutions which just return null for the coincident case even though there are three sub-cases: coincident but do not overlap touching just points and coincident overlap/coincident line sub-segment For example we could design a C# function like this: public static PointF[] Intersection(PointF a1, PointF a2, PointF b1, PointF b2) where (a1,a2) is one line segment and (b1,b2) is another. This function would need to cover all the weird cases that most implementations or explanations gloss over. In order to account for the weirdness of coincident lines, the function could return an array of PointF's: zero result points (or null) if the lines are parallel or do not intersect (infinite lines intersect but line segments are disjoint, or lines are parallel) one result point (containing the intersection location) if they do intersect or if they are coincident at one point two result points (for the overlapping part of the line segments) if the two lines are coincident

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• Insert consecutive numbers

  - by Markus

  Hi. I have a table A (Acons, A1, A2, A3) in which I should insert information from another table B with columns (B1, B2, B3). The Acons is a column in which should contain some consecutive numbers (it is not an identity and I cannot make it identity). I know xmin - starting the from number the sequence has to be computed. How can I insert the rows into the table A, using a single Insert statement? I tried like the following, but it didn't work: DECLARE @i AS INT; SET @i = xmin; INSERT INTO A(Acons, A1, A2, A3) SELECT @i = (Bcons = (@i + 1)), B1, B2, B3 FROM B Unfortunatelly, the above solution does not work;

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• function to efficiently check a change of value in a nested hashmap

  - by zcaudate

  the motivation is for checking what has changed in a deeply nest map, kind of like a reverse of update-in. This is a simple example: (def p1 {:a {:a1 :1 :a2 :2} :b {:b1 :1 :b2 :2}}) (def p2 (update-in p1 [:a :a1] (constantly :updated)) ;; => {:a {:a1 :updated :a2 :2} ;; :b {:b1 :1 :b2 :2}} (what-changed? p1 p2) ;; => {:keys [:a :a1] :value :updated) (what-changed? p2 p1) ;; => {:keys [:a :a1] :value :2) I'm hoping that because clojure maps are persistent data-structures, there may be a smart algorithm to figure this out by looking at the underlying structure as opposed to walking through the nested maps and comparing the difference.

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• How to insert a value based on lookup from another table [SQL]?

  - by Shaitan00

  I need to find a way to do an INSERT INTO table A but one of the values is something that comes from a lookup on table B, allow me to illustrate. I have the 2 following tables: Table A: A1: String A2: Integer value coming from table B A3: More Data Table B: B1: String B2: Integer Value Example row of A: {"Value", 101, MoreData} Example row of B: {"English", 101} Now, I know I need to INSERT the following into A {"Value2", "English", MoreData} but obviously that won't work because it is expecting an Integer in the second column not the word "English", so I need to do a lookup in Table B first. Something like this: INSERT INTO tableA (A1, A2, A3) VALUES ("Value2", SELECT B2 FROM tableB where B1="English", MoreData); Obviously this doesn't work as-is ... Any suggestions?

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