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• Draw an Inset NSShadow and Inset Stroke

  - by Alexsander Akers

  I have an NSBezierPath and I want to draw in inset shadow (similar to Photoshop) inside the path. Is there anyway to do this? Also, I know you can -stroke paths, but can you stroke inside a path (similar to Stroke Inside in Photoshop)? Update This is the code I'm using. The first part makes a white shadow downwards. The second part draws the gray gradient. The third part draws the black inset shadow. Assume path is an NSBezierPath instance and that clr(...) returns an NSColor from a hex string. NSShadow * shadow = [NSShadow new]; [shadow setShadowColor: [NSColor colorWithDeviceWhite: 1.0f alpha: 0.5f]]; [shadow setShadowBlurRadius: 0.0f]; [shadow setShadowOffset: NSMakeSize(0, 1)]; [shadow set]; [shadow release]; NSGradient * gradient = [[NSGradient alloc] initWithColorsAndLocations: clr(@"#262729"), 0.0f, clr(@"#37383a"), 0.43f, clr(@"#37383a"), 1.0f, nil]; [gradient drawInBezierPath: path angle: 90.0f]; [gradient release]; [NSGraphicsContext saveGraphicsState]; [path setClip]; shadow = [NSShadow new]; [shadow setShadowColor: [NSColor redColor]]; [shadow setShadowBlurRadius: 0.0f]; [shadow setShadowOffset: NSMakeSize(0, -1)]; [shadow set]; [shadow release]; [path stroke]; [NSGraphicsContext restoreGraphicsState]; Here you can see a gradient fill, a white drop shadow downwards, and a black inner shadow downwards.

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• Any software transforming broken lines into curves?

  - by user32931

  Hello, do you know of any software that would help me transform a broken line into a curved line? For example, I have an octagon or a heptagon and I want it to be transformed into something resembling a circle. if you know such software, please, let me know. Thank You! Update A: Here is an image from the tutorial given to me by Jamie Keeling (right now it's the first answer below). At least the picture there represents what I want. In that tutorial this process is called "flattening paths". I will try to put that image right here, but if it doesn't get displayed, you can find it by this URL: http://msdn.microsoft.com/en-us/library/ms536364%28v=VS.85%29.aspx The red line in the picture is what I would want to submit, and the blue line is what I would want to get in the end:

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• Cocos2d rotating sprite while moving with CCBezierBy

  - by marcg11

  I've done my moving actions which consists of sequences of CCBezierBy. However I would like the sprite to rotate by following the direction of the movement (like an airplane). How sould I do this with cocos2d? I've done the following to test this out. CCSprite *green = [CCSprite spriteWithFile:@"enemy_green.png"]; [green setPosition:ccp(50, 160)]; [self addChild:green]; ccBezierConfig bezier; bezier.controlPoint_1 = ccp(100, 200); bezier.controlPoint_2 = ccp(400, 200); bezier.endPosition = ccp(300,160); [green runAction:[CCAutoBezier actionWithDuration:4.0 bezier:bezier]]; In my subclass: @interface CCAutoBezier : CCBezierBy @end @implementation CCAutoBezier - (id)init { self = [super init]; if (self) { // Initialization code here. } return self; } -(void) update:(ccTime) t { CGPoint oldpos=[self.target position]; [super update:t]; CGPoint newpos=[self.target position]; float angle = atan2(newpos.y - oldpos.y, newpos.x - oldpos.x); [self.target setRotation: angle]; } @end However it rotating, but not following the path...

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• Kink detection in drawn polylines

  - by David Rutten

  Users can sketch in my app using a very simple tool (move mouse while holding LMB). This results in a series of mousemove events and I record the cursor location at each event. The resulting polyline curve tends to be rather dense, with recorded points almost every other pixel. I'd like to smooth this pixelated polyline, but I don't want to smooth intended kinks. So how do I figure out where the kinks are? The image shows the recorded trail (red pixels) and the 'implied' shape as a human would understand it. People tend to slow down near corners, so there is usually even more noise here than on the straight bits.

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• Python fit polynomial, power law and exponential from data

  - by Nadir

  I have some data (x and y coordinates) coming from a study and I have to plot them and to find the best curve that fits data. My curves are: polynomial up to 6th degree; power law; and exponential. I am able to find the best fit for polynomial with while(i < 6): coefs, val = poly.polyfit(x, y, i, full=True) and I take the degree that minimizes val. When I have to fit a power law (the most probable in my study), I do not know how to do it correctly. This is what I have done. I have applied the log function to all x and y and I have tried to fit it with a linear polynomial. If the error (val) is lower than the others polynomial tried before, I have chosen the power law function. Am I correct? Now how can I reconstruct my power law starting from the line y = mx + q in order to draw it with the original points? I need also to display the function found. I have tried with: def power_law(x, m, q): return q * (x**m) using x_new = np.linspace(x[0], x[-1], num=len(x)*10) y1 = power_law(x_new, coefs[0], coefs[1]) popt, pcov = curve_fit(power_law, x_new, y1) but it seems not to work well.

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• trackroll does not works as i want or expect to do,blackberry

  - by SWATI

  i am working on blackberry curve 8300 i have added some components in the main screen,now i want to move the focus vertically when the trackball moves up or down and move the focus horizontally when track-Wheel moves left or right. ================================================================================== --Title area that contains a focusable field(BACK)-- --Non focusable Label field that indicates the name of the user-- --A horizontal field manager1 that contains 4 buttons-- --A horizontal field manager2 that contains 4 buttons-- --A horizontal field manager2 that contains 4 buttons-- ================================================================================== now suppose currently focus is on BACK button and i scroll the track-wheel downwards then, focus should come on 1st button of manager1 Again when i scroll downwards,then focus should come on the 1st button of manager2 and not the 2nd button of manager1(as its happening on device) my code is ::: protected boolean trackwheelRoll(int amount, int status, int time) { focusIndex = this.getFieldWithFocusIndex(); System.out.println("focus index ::::::::::::::::"+focusIndex); Field f; if(focusIndex!=0) { if(amount==-1) { //move up if(focusIndex>=0) { focusIndex = focusIndex-1; f = getField(focusIndex); f.setFocus(); } } if(amount==1) { //moving down if(focusIndex<=3) { f = getField(++focusIndex); f.setFocus(); } } } return super.trackwheelRoll(amount, status, time); } even after this control moves abruptly on simulator but on device no change took place

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• How to find "y" values of the already estimated monotone function of the non-monotone regression curve corresponding to the original "x" points?

  - by parenthesis

  The title sounds complicated but that is what I am looking for. Focus on the picture. ## data x <- c(1.009648,1.017896,1.021773,1.043659,1.060277,1.074578,1.075495,1.097086,1.106268,1.110550,1.117795,1.143573,1.166305,1.177850,1.188795,1.198032,1.200526,1.223329,1.235814,1.239068,1.243189,1.260003,1.262732,1.266907,1.269932,1.284472,1.307483,1.323714,1.326705,1.328625,1.372419,1.398703,1.404474,1.414360,1.415909,1.418254,1.430865,1.431476,1.437642,1.438682,1.447056,1.456152,1.457934,1.457993,1.465968,1.478041,1.478076,1.485995,1.486357,1.490379,1.490719) y <- c(0.5102649,0.0000000,0.6360097,0.0000000,0.8692671,0.0000000,1.0000000,0.0000000,0.4183691,0.8953987,0.3442624,0.0000000,0.7513169,0.0000000,0.0000000,0.0000000,0.0000000,0.1291901,0.4936121,0.7565551,1.0085108,0.0000000,0.0000000,0.1655482,0.0000000,0.1473168,0.0000000,0.0000000,0.0000000,0.1875293,0.4918018,0.0000000,0.0000000,0.8101771,0.6853480,0.0000000,0.0000000,0.0000000,0.0000000,0.4068802,1.1061434,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.6391678) fit1 <- c(0.5102649100,0.5153380934,0.5177234836,0.5255544980,0.5307668662,0.5068087080,0.5071001179,0.4825657520,0.4832969250,0.4836378194,0.4842147729,0.5004039310,0.4987301366,0.4978800742,0.4978042478,0.4969807064,0.5086987191,0.4989497612,0.4936121200,0.4922210302,0.4904593166,0.4775197108,0.4757040857,0.4729265271,0.4709141776,0.4612406896,0.4459316517,0.4351338346,0.4331439717,0.4318664278,0.3235179189,0.2907908968,0.1665721429,0.1474035158,0.1443999345,0.1398517097,0.1153991839,0.1142140393,0.1022584672,0.1002410843,0.0840033244,0.0663669309,0.0629119398,0.0627979240,0.0473336492,0.0239237481,0.0238556876,0.0084990298,0.0077970954,0.0000000000,-0.0006598571) fit2 <- c(-0.0006598571,0.0153328298,0.0228511733,0.0652889427,0.0975108758,0.1252414661,0.1270195143,0.1922510501,0.2965234797,0.3018551305,0.3108761043,0.3621749370,0.4184150225,0.4359301495,0.4432114081,0.4493565757,0.4510158144,0.4661865431,0.4744926045,0.4766574718,0.4796937554,0.4834718810,0.4836125426,0.4839450098,0.4841092849,0.4877317306,0.4930561638,0.4964939389,0.4970089201,0.4971376528,0.4990394601,0.5005881678,0.5023814257,0.5052125977,0.5056691690,0.5064254338,0.5115481820,0.5117259449,0.5146054557,0.5149729419,0.5184178197,0.5211542908,0.5216215426,0.5216426533,0.5239797875,0.5273573222,0.5273683002,0.5293994824,0.5295130266,0.5306236672,0.5307303109) ## picture plot(x, y) ## red regression curve points(x, fit1, col=2); lines(x, fit1, col=2) ## blue monotonic curve to the regression points(min(x) + cumsum(c(0, rev(diff(x)))), rev(fit2), col="blue"); lines(min(x) + cumsum(c(0, rev(diff(x)))), rev(fit2), col="blue") ## "x" original point matches with the regression estimated point ## but not with the estimated (fit2=estimate) monotonic curve abline(v=1.223329, lty=2, col="grey") Focus on the dashed grey line. The idea is to get y value of the monotonic blue curve corresponding to x original value. The grey line should cross three points (the original one "black", the regression estimate "red", the adjusted regression estimate "blue"). Can we do this? Methodology: The object "fit2" is the output of the function rearrangement(). It is always monotonically increasing. library(Rearrangement) fit2 <- rearrangement(x=as.data.frame(x), y=fit1)

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• Any software transforming broken lines into curves?

  - by brilliant

  Hello, do you know of any software that would help me transform a broken line into a curved line? For example, I have an octagon or a heptagon and I want it to be transformed into something resembling a circle. if you know such software, please, let me know. Thank You! Update A: Here is an image from the tutorial given to me by Jamie Keeling (right now it's the first answer below). At least the picture there represents what I want. In that tutorial this process is called "flattening paths". I will try to put that image right here, but if it doesn't get displayed, you can find it here: http://msdn.microsoft.com/en-us/library/ms536364%28v=VS.85%29.aspx The red line in the picture is what I would want to submit, and the blue line is what I would want to get in the end:

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• javascript-based rounded cornered fieldset with legend

  - by Jronny

  Is there any fieldset with legend that has curvy corners? I was looking on the internet for one, but too unlucky to find any.

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• Is it worth moving from stored procedures to linq ?

  - by Josef

  I'm looking at standardizing programming in an organisaiton. Half uses stored procedures and the other half Linq. From what i've read there is still some debate going on on this topic. My concern is that MS is trying to slip in it's own proprietry query language 'linq' to make SQL redundant. If a few years back microsoft had tried to win customers from oracle and sybase with their MSSQL database and stated that it didn't use SQL by their own proprietry query langues ie linq. I doubt many would have switched. I believe that is exactly what is happening now by introducting it into the applicaiton business layer. I have used MS for many years but there is one gripe that I have with them and that is that they change their direction a lot. By a lot I mean new releases of .net, silverlight etc are more than 30% different from previous version. So by the time you become productive a new release is on the way. As things stand now a web developer using .net would need to know either vb.net or c#, xml, xaml,javascript,html, sql and now linq. That doesn't make for good productivity in my books. My concern is that once we all start using linq MS will start changing it between releases. and it will become an ever changing landscape. I believe that 'linq to sql' has already been deprecated. At leas with SQL we are dealing with a more stable and standardized language. Are we looking at a programming revolution or a marketing campaign? As far as I know other languages like Cobol have stayed the same for years. A cobol program from 20 years ago could pick up todays code and start working on it. Could a Vb3 person work on a modern .net web app ? Would these large changes need to be made if the underlying original foundation had been sound ? I worry about following MS shaking roadmap with it's deadends and double backs. are there any architects out there who feel the same ? regards Josef

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• Starting work on a Pre-existing Project

  - by Toymakerii

  So this is more of a generic question. I seem to keep finding myself being put on larger and larger projects. Recently I have been assigned to a very large project written in C and VHDL. The goal is for me to become familiar with the code and eventually take the lead on the project. This is by far the largest project I have been assigned to work on that I didn't start. So here is my question: What methods/tools do you use to learn how everything works? Do you just increase and expand on comments? Do you make a UML representation of the project? Any tips would be great! Thanks

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• Use of Curve25519

  - by chmike

  I'm currently investigating the use of curve25519 for signing. Original distribution can be obtained here and a C code implementation here or here. Bernstein suggest to use ECDSA for this but I could not find any code.

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• variable row size list field in blackberry

  - by SWATI

  i have created an application that contains a list field(custom) i want if a certain condition is satisfied then rowheight should be 100 else it should be 50 how can i do that i tried setRowHeight(index,size); but it dnt worked.Moreover its undocumented toooooooooo.. any help will be appreciated

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• Curvey Redraw tabs working fine on Firefox , problem with IE

  - by Rohit

  Hi, I have used curvey redraw library from google code(http://code.google.com/p/curvycorners/) & it has solved my purpose, though now as per new req i am struggling with IE. I want to have two tab rows each containing 2 tabs. <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>curvyCorners - Tab demo</title> <style type="text/css">/*<![CDATA[*/ /* tab styles */ #tabrow { margin:0; padding-left:1ex; min-width:800px; font-size:small; letter-spacing:0.3pt; line-height:1; height:24px; } #tabrow ul { margin:0; padding:0; list-style:none; position:absolute; z-index:2; } #tabrow li { float:left; background-color:#E0DFE3; color:#000; margin-right:5px; padding:5px; -webkit-border-top-left-radius:5px; -webkit-border-top-right-radius:5px; -moz-border-radius-topleft:5px; -moz-border-radius-topright:5px; border-top:solid #9B9B9B 1px; border-left:solid #9B9B9B 1px; border-right:solid #9B9B9B 1px; border-bottom-width:0; border-bottom-color:transparent; cursor:pointer; font-family:verdana;font-weight:bold;font-style:italic } #tabrow li.select { background-color:#ffffff; color:#2470c4; height:14px; } /* page styles */ #midbox { width:220px; height:305px; -webkit-border-radius: 5px; -moz-border-radius: 5px; } #midbox { border: solid #9b9b9b 1px; background-color:#ffffff; } #midbox p { margin:0; padding-bottom:1ex; } h1, #topbox h2 { margin:0 15pt; padding: 5pt 0; } div.subpage { padding:1em; } /*]]>*/ </style> <script type="text/javascript" src="curvs.js"> </script> <script type="text/javascript">//<![CDATA[ var selectedTab = 0; function tabclick(n) { if (n === selectedTab) return; // nothing to do. var li = document.getElementById('tab' + selectedTab); curvyCorners.adjust(li, 'className', ''); // Remove the 'select' style li = document.getElementById('page' + selectedTab); li.style.display = 'none'; // hide the currently selected sub-page li = document.getElementById('page' + n); li.style.display = 'block'; // show the new sub-page li = document.getElementById('tab' + n); // get the new (clicked) tab curvyCorners.adjust(li, 'className', 'select'); // and update its style curvyCorners.redraw(); // Redraw all elements with className curvyRedraw selectedTab = n; // store for future reference } var selectedTab1 = 2; function tabclick1(n) { if (n === selectedTab1) return; // nothing to do. var li = document.getElementById('tab' + selectedTab1); curvyCorners.adjust(li, 'className', ''); // Remove the 'select' style li = document.getElementById('page' + selectedTab1); li.style.display = 'none'; // hide the currently selected sub-page li = document.getElementById('page' + n); li.style.display = 'block'; // show the new sub-page li = document.getElementById('tab' + n); // get the new (clicked) tab curvyCorners.adjust(li, 'className', 'select'); // and update its style curvyCorners.redraw(); // Redraw all elements with className curvyRedraw selectedTab1 = n; // store for future reference } //]]> </script> </head> <body> <div id="tabrow"> <ul> <li id="tab0" onclick="tabclick(0);" class="select curvyRedraw">Categories</li> <li id="tab1" onclick="tabclick(1);" class="curvyRedraw">Services</li> </ul> </div> <div id="midbox" class="curvyRedraw"> <div id="page0" class="subpage"> Category details </div> <div id="page1" class="subpage" style="display:none"> Service details </div> </div> <br/><br/> <div id="tabrow"> <ul> <li id="tab2" onclick="tabclick1(2);" class="select curvyRedraw">Recent Activiites</li> <li id="tab3" onclick="tabclick1(3);" class="curvyRedraw">News</li> </ul> </div> <div id="midbox" class="curvyRedraw"> <div id="page2" class="subpage"> Activities </div> <div id="page3" class="subpage" style="display:none"> News </div> </div> </body> </html> Can you please help me out in this? Thanks, Rohit.

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• How long a desktop programmer able to convert himsleft on mastering PHP ?

  - by justjoe

  i know it depends on many thing. But can anybody tell me how long it should be ? I just want to draw a boundaries between successful and failed attempt to convert myself ?

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• Function fitting in MatLab

  - by gnome90

  How do you fit the same type of function to different parts of an array?

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• "too many threads error" in blackberry OS-4.5

  - by SWATI

  hi in my application i have 20 icons(bitmap fields) on the home screen When i click on any icon an HTTP request is made in a separate thread. I have used invoke later method wherever necessary to take care of multi-threading problems. But still the number of threads goes beyond 16 and an error pops up indicating too many threads error and applications needs to be restarted!! can anybody tell me how to destroy these threads when they are no longer in use. I don't understand why they don't destroy on their own as usually they do.

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• How to create a level with curved lines with cocos2d + Box2d on the iphone?

  - by Steven

  I'd like to create a game that has levels such as this: http://img169.imageshack.us/img169/7294/picdq.png The Player moves "flies" through the level and mustn't collide with the walls. How can I create such levels? I found that piece of software: http://www.sapusmedia.com/levelsvg/ It's not that cheap, so I wonder whether there is another way to create such a level as shown in the picture above...?

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• different brainpoolP521r1 parameters for flexiProvider. Why?

  - by user182846

  I am trying to generate ECC public private key pairs using flexiProvider. I have noticed that values for parameters like p and q are different in brainpoolP521r1 of flexiProvider than those which are specified in many sites. Values specified are Q= AADD.... but what I get is Q=8948... Any idea why flexiProvider does not use specified values and whether having different values is affectes security. I am new to ECC. Any help will be greatly appreciated.

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• Do any well-known CAs issue Elliptic Curve certificates?

  - by erickson

  Background I've seen that Comodo has an elliptic curve root ("COMODO ECC Certification Authority"), but I don't see mention of EC certificates on their web site. Does Certicom have intellectual property rights that prevent other issuers from offering EC certificates? Does a widely-used browser fail to support ECC? Is ECC a bad fit for traditional PKI use like web server authentication? Or is there just no demand for it? I'm interested in switching to elliptic curve because of the NSA Suite B recommendation. But it doesn't seem practical for many applications. Bounty Criteria To claim the bounty, an answer must provide a link to a page or pages at a well-known CA's website that describes the ECC certificate options they offer, prices, and how to purchase one. In this context, "well-known" means that the proper root certificate must be included by default in Firefox 3.5 and IE 8. If multiple qualifying answers are provided (one can hope!), the one with the cheapest certificate from a ubiquitous CA will win the bounty. If that doesn't eliminate any ties (still hoping!), I'll have to choose an answer at my discretion. Remember, someone always claims at least half of the bounty, so please give it a shot even if you don't have all the answers.

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• How do I prevent a curve snapping to a straight line in Flash CS4?

  - by Kelix

  I am trying to do some vector drawing in Flash but am having trouble when "curving" lines. At the moment, unless the curve is significant, it snaps back to a straight line meaning I am finding it impossible to draw shallow curves. Any idea how to turn this snapping off? I have tried turning everything off in View Snapping and it makes no difference.

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• Does the term "Learning Curve" include the knowing of the gotchas?

  - by voroninp

  When you learn new technology you spend time understanding its concepts and tools. But when technology meets real life strange and not pleasant things happen. Reuqirements are often far from ideal and differ from 'classic' scenario. And soon I find myself bending the technology to my real needs. At this point I begin to know bugs of the system or that is is not so flexible as it seemed at the very begining. And this 'fighting' with technology consumes a great part of the time while developing. What is more depressing is that the bunch of such gotchas and workarounds are not concentrated at one place (book, site, etc.) And before you really confront it you cannot really ask the correct question because you do not even suspect the reason for the problem to occur (unknown-unknown). So my question consiststs of three: 1) Do you really manage (and how) to predict possible future problems? 2) How much time do you spend for finding the workaround/fix/solution before you leave it and switch to other problems. 3) What are the criteria for you to think about yourself as experienced in the tecnology. Do you take these gotchas into account?

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• Is Ruby on Rails supposed to have a steep learning curve or is it just me?

  - by Anita

  I'm a self-taught programmer. I've been learning RoR since October with varying intensity (sometimes all day, sometimes nothing for several weeks). Before that I knew only Java, but knew it pretty well. I've heard so much hype about RoR and how it's supposed to make you happy, productive, etc. So far it's only made me frustrated. I learned it out of the Agile book, and I suspect part of the difficulty might have to do with my not knowing JavaScript and CSS, and having only a shaky grasp of databases and HTML. But apparently it took me much longer to complete the project in the Agile book than other people, and I still don't remember much of it. There are some things about Rails that I just can't seem to get, e.g. when to use symbols and when NOT to, or how dynamic methods are called. Recently I was given a small Rails assignment where I'm asked to make a small change to the interface. It's taken me around 25 hours and although I've made some progress in understanding the code, I still have no idea how to proceed. I can't even ask Stack Overflow because there is so much code I'll have to provide to give context. So my question is in the title: is RoR supposed to take a long time to learn or am I just slow? Can it be that I've been learning from the wrong book? My learning style is such that I either understand nothing or understand everything, if that makes sense. Thanks!

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• How do I rotate a sprite with ccbezierTo in cocos2d-x?

  - by user1609578

  In cocos2d-x, I move a sprite with ccbezierTo like this: // use for ccbezierTo bezier.controlPoint_1 = ccp(m_fish->getPositionX() + 200, visibleSize.height/2 + 300); bezier.controlPoint_2 = ccp(m_fish->getPositionX() + 400, visibleSize.height/2 - 300); bezier.endPosition = ccp(m_fish->getPositionX() + 600,visibleSize.height/2); bezier1.controlPoint_1 = ccp(m_fish->getPositionX() + 800, visibleSize.height/2 + 300); bezier1.controlPoint_2 = ccp(m_fish->getPositionX() + 1000, visibleSize.height/2 - 300); bezier1.endPosition = ccp(m_fish->getPositionX() + 1200,visibleSize.height/2); bezierForward = CCBezierTo::create(6, bezier); nextBezier = CCBezierTo::create (6,bezier1); m_fish->runAction(CCSequence::create( bezierForward, nextBezier, NULL)); How can I make my sprite rotate while moving it with CCBezierTo?

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• How to implement curved movement while tracking the appropriate angle?

  - by Vexille

  I'm currently coding a 2D top-down car game which will be turn-based. And since it's turn-based, the cars won't be controlled directly (i.e. with a simple velocity vector that adjusts its angle when the player wants to turn), but instead it's movement path has to be planned beforehand, and then the car needs to follow the path when the turn ends (think Steambirds). This question has some interesting information, but its focus is on homing-missile behaviour, which I kinda had figured out, but doesn't really apply to my case, I think, since I need to show a preview of the path when the player is planning his turn, then have the car follow that path. In that same question, there's an excellent answer by Andrew Russel which mentions Equations of Motion and Bézier's Curve. Some of his other suggestions of implementation are specific to XNA though, so they don't help much (I'm using Marmalade SDK). If I assume Bézier's Curve as the solution of choice, I'm left with one specific problem: I'll have the car's position (the first endpoint) and the target/final position (the last endpoint), but what should I use as the control point (assuming a square/quadratic curve)? And whether I use Bézier's Curve or another parametric equation, I'd still be left with another issue: the car can't just follow the curve, it must turn (i.e. adjust its angle) accordingly. So how can I figure out which way the car should be pointing to at any given point in the curve?

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