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  • How to execute commands in Command Prompt using c#

    - by karthik
    I want to execute these steps in CMD using c# 1 - CD C:\MySQL\MySQL Server 5.0\bin 2 - mysqldump -uroot -ppassword sample d:\Test\222.sql On manually doing this, i will get file named "222.sql" I am using the below code to do it, but missing something.. Nothing Happens public void CreateScript_AAR() { string commandLine = @"CD C:\MySQL\MySQL Server 5.0\bin\mysqldump -uroot -ppassword sample> d:\Test\222.sql"""; System.Diagnostics.ProcessStartInfo PSI = new System.Diagnostics.ProcessStartInfo("cmd.exe"); PSI.RedirectStandardInput = true; PSI.RedirectStandardOutput = true; PSI.RedirectStandardError = true; PSI.UseShellExecute = false; System.Diagnostics.Process p = System.Diagnostics.Process.Start(PSI); System.IO.StreamWriter SW = p.StandardInput; System.IO.StreamReader SR = p.StandardOutput; SW.WriteLine(commandLine); SW.Close(); }

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  • How do I extend the classpath used for 'grails run-app'

    - by Eric
    I have the following in my Config.groovy file: grails.config.locations = [ "classpath:env.groovy" ] Now, where exactly am I supposed to place "env.groovy" such that it is available on the CLASSPATH during grails run-app? The documentation here is sorely lacking. I am able to get it to work on the pure commandline by placing "env.groovy" in $APP_HOME/etc and then running: $ grails -classpath ./etc run-app This seems a little hackish, but I can live with it... However, I am unable to get any such configuration working when I launch run-app using the Grails eclipse plugin (STS): Unable to load specified config location classpath:env.groovy : class path resource [env.groovy] cannot be opened because it does not exist I've seen related posts here, here, here, and here but the answers have been unfulfilling. I am looking for a CLASSPATH-based solution that will work with 'run-app' in development mode (both commandline and from eclipse). I know how to set up the CLASSPATH for my deployment servlet container, so that is not an issue.

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  • system() not working in php using windows server 2003

    - by jazzy
    hi i have to extract the cabfile(.cab) on the server. i am Finding such script which extract cab file but i didn't get it yet. So now i am try to extract using cabarc.exe. But i face the problem that when i run command throuw commandline its work fine but when i give same command to system() or exec() function in php it is not work. code is as follow: $command = "c:\\exe\\cabarc X c:\\cab\\data.cab c:\\data\\"; if(($output = system($command,$return) != false) { echo "$return"; } it is not working when i use same string in commandline it works fine. please any body help me to why it not working what to do tomake it work is ther any rights issue. I had give the execute permission to the site. thanks

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  • Clojure warn-on-reflection and type hints

    - by Ralph
    In the following code, I am getting a warning on reflection: (ns com.example (:import [org.apache.commons.cli CommandLine Option Options PosixParser])) (def *help-option* "help") (def *host-option* "db-host") (def *options* (doto (Options.) (.addOption "?" *help-option* false "Show this usage information") (.addOption "h" *host-option* true "Name of the database host"))) (let [^CommandLine command-line (.. (PosixParser.) (parse *options* (into-array String args))) db-host (.getOptionValue command-line "h")] ; WARNING HERE ON .getOptionValue ; Do stuff with db-host ) I have a type hint on command-line. Why the warning? I am using Clojure 1.2 on OS X 10.6.6 (Apple VM). I assume that I do not get a warning on (.addOption ...) because the compiler knows that (Options.) is a org.apache.commons.cli.Options).

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  • mysql_connect() doesn't work when run by apache; works from command line.

    - by Skeeter
    Hi, I have a strange issue. I'm trying to write a simple php webpage on my server, but mysql_connect() doesn't connect to any server, either local or otherwise. Here's where it gets strange. If I take the same php script and run it from the commandline, the script works. phpinfo() indicates that both the file (being run by apache) and the commandline (run as root) are calling the same version of php, mysql is loaded, and the php.ini is the same. Furthermore, I'm running a MediaWiki installation on this same server, and it's using the mysqld installed locally and works just fine, so I'm completely at a loss as to why the code isn't working. The error I receive on runtime: Can't connect to MySQL server on 'xxx.xxx.xxx.xxx' (13) (The IP is x'd out for the privacy of the owner of the server I'm connecting to)

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  • How do I enable Scroll Lock?

    - by Anton Ciprian Vasilache
    I need to enable scroll lock so I can toggle lights on my keyboard. This works on Arch.Funny thing it doesn't work on Ubuntu. http://linuxtechie.wordpress.com/2008/04/07/getting-scroll-lock-to-work-in-ubuntu/ $ xmodmap -e ‘add mod3 = Scroll_Lock’ xmodmap: unknown command on line commandline:1 xmodmap: unable to open file 'mod3' for reading xmodmap: unable to open file '=' for reading xmodmap: unable to open file 'Scroll_Lock’' for reading xmodmap: 4 errors encountered, aborting.

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  • C Minishell Command Expansion Printing Gibberish

    - by Optimus_Pwn
    I'm writing a unix minishell in C, and am at the point where I'm adding command expansion. What I mean by this is that I can nest commands in other commands, for example: $> echo hello $(echo world! ... $(echo and stuff)) hello world! ... and stuff I think I have it working mostly, however it isn't marking the end of the expanded string correctly, for example if I do: $> echo a $(echo b $(echo c)) a b c $> echo d $(echo e) d e c See it prints the c, even though I didn't ask it to. Here is my code: msh.c - http://pastebin.com/sd6DZYwB expand.c - http://pastebin.com/uLqvFGPw I have a more code, but there's a lot of it, and these are the parts that I'm having trouble with at the moment. I'll try to tell you the basic way I'm doing this. Main is in msh.c, here it gets a line of input from either the commandline or a shellfile, and then calls processline (char *line, int outFD, int waitFlag), where line is the line we just got, outFD is the file descriptor of the output file, and waitFlag tells us whether or not we should wait if we fork. When we call this from main we do it like this: processline (buffer, 1, 1); In processline, we allocate a new line: char expanded_line[EXPANDEDLEN]; We then call expand, in expand.c: expand(line, expanded_line, EXPANDEDLEN); In expand, we copy the characters literally from line to expanded_line until we find a $(, which then calls: static int expCmdOutput(char *orig, char *new, int *oldl_ind, int *newl_ind) orig is line, and new is expanded line. oldl_ind and newl_ind are the current positions in the line and expanded line, respectively. Then we pipe, and recursively call processline, passing it the nested command(for example, if we had "echo a $(echo b)", we would pass processline "echo b"). This is where I get confused, each time expand is called, is it allocating a new chunk of memory EXPANDEDLEN long? If so, this is bad because I'll run out of stack room really quickly(in the case of a hugely nested commandline input). In expand I insert a null character at the end of the expanded string, so why is it printing past it? If you guys need any more code, or explanations, just ask. Secondly, I put the code in pastebin because there's a ton of it, and in my experience people don't like it when I fill up several pages with code. Thanks.

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  • mongodb with 13.10 service problems

    - by No_name
    I installed mongodb with the instructions here. Fresh installation of ubuntu btw. It installed without error, but upon attempting to start, stop or restart the service, I got start: Unknown job: mongodb Invoking "mongod" from the commandline seems to work, as I can view statistics of mongodb fine from localhost:28017. I've also attempted to use the official ubuntu package "mongodb" instead of "mongodb-10gen" but no luck there either.

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  • Chocolatey featured on LifeHacker!

    - by Robz / Fervent Coder
    Chocolatey was just featured on LifeHacker! http://lifehacker.com/5942417/chocolatey-brings-lightning-quick-linux+style-package-management-to-windows I was ecstatic to hear about this, of course now I need to write an actual comparison between chocolatey and other windows package managers. Comments on Reddit: http://www.reddit.com/r/commandline/comments/zqnj6/chocolatey_brings_lightning_quick_linuxstyle/

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  • Unity - Certain applications don't stay in Launcher

    - by user10669
    I can start up IntelliJ Idea using the commandline, which is a shell script that starts up a java process. It then appears in the launcher, as normal. I can select "Keep in Launcher", but it only remains there until I reboot, then it disapears again. This is the only application I've seen that does this - Stuff already in the applications menu stocks around fine if I tell it to stay in the launcher.

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  • Certain applications don't stay in Launcher

    - by user10669
    I can start up IntelliJ Idea using the commandline, which is a shell script that starts up a java process. It then appears in the launcher, as normal. I can select "Keep in Launcher", but it only remains there until I reboot, then it disapears again. This is the only application I've seen that does this - Stuff already in the applications menu stocks around fine if I tell it to stay in the launcher.

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  • Set Idle Time in Ubuntu 12.04 Server

    - by ssanj
    I recently installed Ubuntu 12.04 Server and am looking for away for get the server to suspend after an idle time. When using the desktop version I could use the Gnome powersaving tool to specify the idle time. As I have no GUI on the server is there a way to set the server idle time via the commandline/config file? I will send the server a wake-on-lan packet to wake it up, if it is suspended and I need to use it.

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  • Backup solution, or, how Duplicati duped me

    - by blarghmaster
    TL/DR version: Mono + Duplicati.commandline.exe restore etc. etc. spits this out for several files regardless of what I try. I am able to list sets, list files in said sets, even do a verify, but each time i do a restore of any kind, i get errors to the effect of : Failed to restore file: "snapshot/blahblah/2005-11-07.tar.gz", Error message: The partial file record for snapshot/blahblah/2005-11-07.tar.gz does not match the file Any advice here, or an idea of where to look for a better solution? FULL STORY: Ive recently put together an nice clean, friendly backup solution for several servers, predominantly Linux, but occasionally a windows box is added too. The solution as is meets all my requirements and does it well... save 1: cross-compatibility The solution is based on a combination of several elements, but eventually comes done to using Duplicity and Duplicati for the actual storage of files. The entire solution was ready to go before i realized that Duplicati, does not, in fact allow me to restore my files to a Linux box, regardless of what the commandline under Mono might tell you. It just spits out errors on random zip and image files, for apparently no good reason as i have tried several options to get it to restore, and several versions of Mono including installing it pretty much lib-for-lib. There is no effective log file for the reasons for these errors, and even the "--debug-output=true" flag does nothing. I am able to list sets, list files in said sets, even do a verify, but each time i do a restore of any kind, i get errors to the effect of : Failed to restore file: "snapshot/blahblah/2005-11-07.tar.gz", Error message: The partial file record for snapshot/blahblah/2005-11-07.tar.gz does not match the file Now i could most likely use the friendly instructions on Duplicati's site and script a bash equivalent of the restore, but that's not exactly ideal. Any advice on this? or possibly an alternative solution that presents the same benefits of Duplicati/Duplicity but that actually works across platforms?

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  • .lnk doesn't open, no errors

    - by MushinNoShin
    I have a shortcut (.LNK) on my desktop to a MS Access database out on a network drive. When I double click that shortcut I get an hour glass for about 10 seconds and then nothing. No errors, no access opening, nothing happens. It appears as if there's not even an MSAccess process running in the background. The file successfully opens from: The Open dialog in Access The commandline "C:\path\to\MSACCESS.EXE C:\path\to\shortcut.lnk" The commandline "C:\path\to\MSACCESS.EXE C:\path\to\whatTheShortcutPointsTo.mdb" The file silently fails to open from: Double clicking the shortcut.lnk Double clicking the mdb file that shortcut.lnk targets At first I thought it had to do with how the link handler operated but the fact that it does the same exact thing when I try to open the mdb directly in explorer makes me think it's an issue with explorer. I've tried restoring, deleting, and recreating the association with the extension. I've tried running MSACCESS.EXE /regserver. I've run out of things to throw at it. In case this is specific to MS Access 2007; I'm trying to use 2007 :)

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  • It's like I'm in recovery mode after update, but I'm not

    - by mawburn
    I used the Ubuntu software updater and updated to the most recent packages. After the last update today, it's like I have gone into recovery mode, but I haven't. I am running UbuntuGNOME First, everything looks like this: Switching to dark mode does nothing. Also, default applications do not work. Such as Startup and the default screenshot application. Everything was working fine before the latest software update. System Info Ubuntu 14.04 LTS Gnome-Shell 3.10.4 Kernel 3.13.0-29 I can't figure out how to get an update history, but this is almost a fresh install. It's about a week old install and this is the 3rd time I've used the Ubuntu Software Update. I am running AMD ATI HD6700 with the proprietary Catalyst drivers. I tried to provide all information that I thought would be useful, if you need any more please let me know. Edit - I believe something went wrong within these updates: Update Log: Start-Date: 2014-06-09 19:07:07 Commandline: aptdaemon role='role-commit-packages' sender=':1.68' Install: libgnome-desktop-3-10:amd64 (3.12.0-0~eugenesan~trusty2) Upgrade: gnome-session-common:amd64 (3.9.90-0ubuntu12, 3.12.0-0~eugenesan~trusty10), gnome-session-bin:amd64 (3.9.90-0ubuntu12, 3.12.0-0~eugenesan~trusty10), gir1.2-gnomedesktop-3.0:amd64 (3.8.4-0ubuntu3, 3.12.0-0~eugenesan~trusty2), gnome-session:amd64 (3.9.90-0ubuntu12, 3.12.0-0~eugenesan~trusty10), python-libxml2:amd64 (2.9.1+dfsg1-3ubuntu4.1, 2.9.1+dfsg1-3ubuntu4.2), libspice-server1:amd64 (0.12.4-0nocelt2, 0.12.4-0nocelt2.02~eugenesan~trusty1), gir1.2-mutter-3.0:amd64 (3.10.4-0ubuntu2, 3.10.4-0ubuntu2.1), xserver-xorg-video-qxl:amd64 (0.1.1-0ubuntu3, 0.1.1-0ubuntu3.01), libxml2:amd64 (2.9.1+dfsg1-3ubuntu4.1, 2.9.1+dfsg1-3ubuntu4.2), libxml2:i386 (2.9.1+dfsg1-3ubuntu4.1, 2.9.1+dfsg1-3ubuntu4.2), gnome-desktop3-data:amd64 (3.8.4-0ubuntu3, 3.12.0-0~eugenesan~trusty2), mutter:amd64 (3.10.4-0ubuntu2, 3.10.4-0ubuntu2.1), mutter-common:amd64 (3.10.4-0ubuntu2, 3.10.4-0ubuntu2.1), libxml2-utils:amd64 (2.9.1+dfsg1-3ubuntu4.1, 2.9.1+dfsg1-3ubuntu4.2), libmutter0c:amd64 (3.10.4-0ubuntu2, 3.10.4-0ubuntu2.1) End-Date: 2014-06-09 19:07:12 I also installed Citrix Receiver today, following the tutorial here: Citrix Receiver 12.1 on Ubuntu 14.04 64-bit Log Start-Date: 2014-06-09 18:59:06 Commandline: apt-get install libmotif4:i386 nspluginwrapper lib32z1 libc6-i386 libxp6:i386 libxpm4:i386 libasound2:i386 Install: libmotif-common:amd64 (2.3.4-5, automatic), libatk1.0-0:i386 (2.10.0-2ubuntu2, automatic), libxft2:i386 (2.3.1-2, automatic), libgraphite2-3:i386 (1.2.4-1ubuntu1, automatic), nspluginviewer:i386 (1.4.4-0ubuntu5, automatic), libpango-1.0-0:i386 (1.36.3-1ubuntu1, automatic), libxcursor1:i386 (1.1.14-1, automatic), libmotif4:i386 (2.3.4-5), libxm4:amd64 (2.3.4-5, automatic), libxm4:i386 (2.3.4-5, automatic), libxp6:i386 (1.0.2-1ubuntu1), libpangocairo-1.0-0:i386 (1.36.3-1ubuntu1, automatic), libxcb-render0:i386 (1.10-2ubuntu1, automatic), libthai0:i386 (0.1.20-3, automatic), libharfbuzz0b:i386 (0.9.27-1, automatic), libpixman-1-0:i386 (0.30.2-2ubuntu1, automatic), libpangoft2-1.0-0:i386 (1.36.3-1ubuntu1, automatic), libcairo2:i386 (1.13.0~20140204-0ubuntu1, automatic), lib32z1:amd64 (1.2.8.dfsg-1ubuntu1), libjasper1:i386 (1.900.1-14ubuntu3, automatic), libgtk2.0-0:i386 (2.24.23-0ubuntu1.1, automatic), nspluginwrapper:amd64 (1.4.4-0ubuntu5), libuil4:amd64 (2.3.4-5, automatic), libuil4:i386 (2.3.4-5, automatic), libxcb-shm0:i386 (1.10-2ubuntu1, automatic), libxmu6:i386 (1.1.1-1, automatic), libc6-i386:amd64 (2.19-0ubuntu6), libxinerama1:i386 (1.1.3-1, automatic), libgdk-pixbuf2.0-0:i386 (2.30.7-0ubuntu1, automatic), libxcomposite1:i386 (0.4.4-1, automatic), libmrm4:amd64 (2.3.4-5, automatic), libmrm4:i386 (2.3.4-5, automatic), libdatrie1:i386 (0.2.8-1, automatic), libxrandr2:i386 (1.4.2-1, automatic), libxpm4:i386 (3.5.10-1) End-Date: 2014-06-09 18:59:11

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  • Calling unmanaged dll from C#. Take 2

    - by Charles Gargent
    I have written a c# program that calls a c++ dll that echoes the commandline args to a file When the c++ is called using the rundll32 command it displays the commandline args no problem, however when it is called from within the c# it doesnt. I asked this question to try and solve my problem, but I have modified it my test environment and I think it is worth asking a new question. Here is the c++ dll #include "stdafx.h" #include "stdlib.h" #include <stdio.h> #include <iostream> #include <fstream> using namespace std; BOOL APIENTRY DllMain( HANDLE hModule, DWORD ul_reason_for_call, LPVOID lpReserved ) { return TRUE; } extern "C" __declspec(dllexport) int WINAPI CMAKEX( HWND hwnd, HINSTANCE hinst, LPCSTR lpszCommandLine, DWORD dwReserved) { ofstream SaveFile("output.txt"); SaveFile << lpszCommandLine; SaveFile.close(); return 0; } Here is the c# app using System; using System.Collections.Generic; using System.Text; using System.Security.Cryptography; using System.Runtime.InteropServices; using System.Net; namespace nac { class Program { [DllImport("cmakca.dll", SetLastError = true, CharSet = CharSet.Unicode)] static extern bool CMAKEX(IntPtr hwnd, IntPtr hinst, string lpszCmdLine, int nCmdShow); static void Main(string[] args) { string cmdLine = @"/source_filename proxy-1.txt /backup_filename proxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /profile ""C:\Documents and Settings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp"""; const int SW_SHOWNORMAL = 1; CMAKEX(IntPtr.Zero, IntPtr.Zero, cmdLine, SW_SHOWNORMAL).ToString(); } } } The output from the rundll32 command is rundll32 cmakex.dll,CMAKEX /source_filename proxy-1.txt /backup_filename proxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /profile ""C:\Documents and Settings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp" /source_filename proxy-1.txt /backup_filename proxy.bak /DialRasEntry NULL /TunnelRasEntry DSLVPN /profile ""C:\Documents and Settings\Administrator\Application Data\Microsoft\Network\Connections\Cm\dslvpn.cmp" however the output when the c# app runs is /

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  • Webstart omits cookie, resulting in EOFException in ObjectInputStream when accessing Servlets?!

    - by Houtman
    Hi, My app. is started from both the commandline and by using an JNLP file. Im running java version 1.6.0_14 First i had the problem that i created the Buffered input and output streams in incorrect order. Found the solution here at StackOverflow . So starting from the commandline works fine now. But when starting the app using Webstart, it ends here java.io.EOFException at java.io.ObjectInputStream$PeekInputStream.readFully(Unknown Source) at java.io.ObjectInputStream$BlockDataInputStream.readShort(Unknown Source) at java.io.ObjectInputStream.readStreamHeader(Unknown Source) at java.io.ObjectInputStream.<init>(Unknown Source) at <..>remoting.thinclient.RemoteSocketChannel.<init>(RemoteSocketChannel.java:76) I found some posts regarding similar problems; at ibm.com - identifies cookies problem at bugs.sun.com - identifies problem as solved in 6u10(b12)? The first suggests that there is a problem in Webstart with cookies. It doesn't seem to be acknowledged as a proper java bug though.. Still i am a bit lost in the solution provided regarding the cookies.(ibm link) Can anyone expand on the cookie solution? I can't find information on how the cookie is generated in the first place. Many thanks.

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  • Network Authentication when running exe from WMI

    - by Andy
    Hi, I have a C# exe that needs to be run using WMI and access a network share. However, when I access the share I get an UnauthorizedAccessException. If I run the exe directly the share is accessible. I am using the same user account in both cases. There are two parts to my application, a GUI client that runs on a local PC and a backend process that runs on a remote PC. When the client needs to connect to the backend it first launches the remote process using WMI (code reproduced below). The remote process does a number of things including accessing a network share using Directory.GetDirectories() and reports back to the client. When the remote process is launched automatically by the client using WMI, it cannot access the network share. However, if I connect to the remote machine using Remote Desktop and manually launch the backend process, access to the network share succeeds. The user specifed in the WMI call and the user logged in for the Remote Desktop session are the same, so the permissions should be the same, shouldn't they? I see in the MSDN entry for Directory.Exists() it states "The Exists method does not perform network authentication. If you query an existing network share without being pre-authenticated, the Exists method will return false." I assume this is related? How can I ensure the user is authenticated correctly in a WMI session? ConnectionOptions opts = new ConnectionOptions(); opts.Username = username; opts.Password = password; ManagementPath path = new ManagementPath(string.Format("\\\\{0}\\root\\cimv2:Win32_Process", remoteHost)); ManagementScope scope = new ManagementScope(path, opts); scope.Connect(); ObjectGetOptions getOpts = new ObjectGetOptions(); using (ManagementClass mngClass = new ManagementClass(scope, path, getOpts)) { ManagementBaseObject inParams = mngClass.GetMethodParameters("Create"); inParams["CommandLine"] = commandLine; ManagementBaseObject outParams = mngClass.InvokeMethod("Create", inParams, null); }

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  • CLI include paths to run zend framework via cron

    - by summerg
    I wrote a command line utility using Zend Framework to do some nightly reporting. It uses a ton of the same functionality the accompanying site. It works great when I run it by hand, but when I run it on cron I have include path issues. Seems like it should be easily fixed with set_include_path, but maybe I'm missing something? My directory structure looks like this: /var/www/clientname/ application Globals.php commandline commandline_bootstrap.php public_html public_bootstrap.php library Zend In public_bootstrap.php I use set_include_path without a problem, relative to the current directory: set_include_path('../library' . PATH_SEPARATOR . get_include_path()); If I understand correctly, in commandline_bootstrap.php I need to put in the absolute path, so cron knows where everything is. My file starts like this: error_reporting(E_ALL); set_include_path('/var/www/clientname/library' . PATH_SEPARATOR . get_include_path()); require_once "../application/Globals.php"; But when I run it via cron I get the following error: PHP Fatal error: require_once(): Failed opening required '../application/Globals.php' (include_path='/var/www/clientname/library/') in /var/www/clientname/commandline/zfcli.php on line 11 I think PHP is accepting my new path, because when I run it command line and dump the phpinfo I can see: include_path = /var/www/clientname/library/:.:/usr/share/pear:/usr/share/php = .:/usr/share/pear:/usr/share/php I admit the syntax here looks a little strange, but I can’t figure out how to fix it. Any suggestions would be greatly appreciated. Thanks summer

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  • EOFException in ObjectInputStream thrown accessing Servlet. Only for Webstart ?!

    - by Houtman
    Hi, My app. is started from both the commandline and by using an JNLP file. Im running java version 1.6.0_14 First i had the problem that i created the Buffered input and output streams in incorrect order. Found the solution here at StackOverflow . So starting from the commandline works fine now. But when starting the app using Webstart, it ends here java.io.EOFException at java.io.ObjectInputStream$PeekInputStream.readFully(Unknown Source) at java.io.ObjectInputStream$BlockDataInputStream.readShort(Unknown Source) at java.io.ObjectInputStream.readStreamHeader(Unknown Source) at java.io.ObjectInputStream.<init>(Unknown Source) at <..>remoting.thinclient.RemoteSocketChannel.<init>(RemoteSocketChannel.java:76) I found some posts regarding similar problems; at bugs.sun.com - identifies problem as solved in 6u10(b12)? at ibm.com - identifies cookies problem The latter suggests that there is a problem in Webstart with cookies. It doesn't seem to be acknowledged as a proper java bug though.. Still i am a bit lost in the solution provided regarding the cookies. Can anyone expand on the cookie solution? Many thanks.

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  • How can i use a commandlinetool (ie. sox) via subprocess.Popen with mod_wsgi?

    - by marue
    I have a custom django filefield that makes use of sox, a commandline audiotool. This works pretty well as long as i use the django development server. But as soon as i switch to the production server, using apache2 and mod_wsgi, mod_wsgi catches every output to stdout. This makes it impossible to use the commandline tool to evaluate the file, for example use it to check if the uploaded file really is an audio file like this: filetype=subprocess.Popen([sox,'--i','-t','%s'%self.path], shell=False,\ stdout=subprocess.PIPE, stderr=subprocess.PIPE) (filetype,error)=filetype.communicate() if error: raise EnvironmentError((1,'AudioFile error while determining audioformat: %s'%error)) Is there a way to workaround for this? edit the error i get is "missing filename". I am using mod_wsgi 2.5, standard with ubuntu 8.04. edit2 What exactly happens, when i call subprocess.Popen from within django in mod_wsgi? Shouldn't subprocess stdin/stdout be independent from django stdin/stdout? In that case mod_wsgi should not affect programms called via subprocess... I'm really confused right now, because the file i am trying to access is a temporary file, created via a filenamevariable that i pass to the file creation and the subprocess command. That file is being written to /tmp, where the rights are 777, so it can't be a rights issue. And the error message is not "file does not exist", but "missing filename", which suggests i am not passing a filename as parameter to the commandlinetool.

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  • How to use App.Xaml's ResourseDictionaries with own entry point

    - by Polaris
    Hello friends. I created some logic for singleInstance application and I must to use my own entry point (not App.xaml) for Application. I have some styles in App.xaml which now is not working. How can I use this ResourceDictionaries from my App.xaml for entire project in my situation? My class for manage Application Startup public class SingleInstanceManager : WindowsFormsApplicationBase { App app; public SingleInstanceManager() { this.IsSingleInstance = true; } protected override bool OnStartup(Microsoft.VisualBasic.ApplicationServices.StartupEventArgs e) { try { // First time app is launched app = new App(); App.Current.Properties["rcID"] = e.CommandLine; //IntroLibrary.OpenDocumentFromNotify(); app.Run(); return false; } catch (Exception ex) { MessageBox.Show(ex.Message); return false; } } protected override void OnStartupNextInstance(StartupNextInstanceEventArgs eventArgs) { // Subsequent launches base.OnStartupNextInstance(eventArgs); Intro win = (Intro)app.MainWindow; if (eventArgs != null) { App.Current.Properties["rcID"] = eventArgs.CommandLine[0]; } IntroLibrary.OpenDocumentFromNotify(); app.Activate(); } } and my own Entry Point: public class EntryPoint { [STAThread] public static void Main(string[] args) { SingleInstanceManager manager = new SingleInstanceManager(); manager.Run(args); } } And my App.Xaml code behind: public partial class App : Application { protected override void OnStartup(System.Windows.StartupEventArgs e) { base.OnStartup(e); // Create and show the application's main window Intro window = new Intro(); window.Show(); } public void Activate() { // Reactivate application's main window this.MainWindow.Activate(); } } And my App.xaml has some code which decribe ResourceDictionaries which doesnt work. Why?

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  • FortiClient SSL VPN Command Line Options

    - by user116036
    We had recently had a vendor switch to a fortinet firewall. We were given the FortinetSLVPNclient (version 4.0.2148) to use. This has some simple command line switches that allow you to connect from the commandline (cmd.exe this is on windows) but they seem to do nothing. Anyone have any luck with this or any alternative ssl vpn clients with scriptable installers? I have been through the documentation on the site and have seen my hopes dashed.

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