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  • submit form problem

    - by basma
    hi I have a problem with "all" of my form submition "search form, login form, regester form,.." the problem shows when I submit the form it doesnt take me to the action page, insted it tack me to my root page :"http://localhost/project/Home/" this is a sample of my search form witch search members or groups as the user choose and it can be submitted by clicking search.jpg <form name="searchform" action='Searchb.php' method='GET' > <a href=""><img src="img/search.jpg" width="60" height="49" onClick="searchform.submit()" style="border-style: none"></a> <input type="text" name="Search" />&nbsp;<label>member</label><input name="radio1" type="radio" value="Member" />&nbsp;<label>Group</label> &nbsp; <input name="radio1" type="radio" value="Group" /> </form>"

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  • ajax->form submit onchage event on selectTag keeping submit button on form without click

    - by prashant
    Hi, I am using cakephp 1.1. for my project.I used ajax-form for form creation.In one form, form submitted using onchange event of selectTag taking submit button and giving submit.click for that button.But it peroperly not redirect to view file gives error "cake/libs/model/datasources/dbo_source.php" and submit that form,but I am not getting to which view it is submitting(submittied form to itself).

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  • POST a form in an iframe.

    - by Stavros Korokithakis
    I would like to POST a form in an iframe, generated like so: My JS loads an iframe inside the page, adds a form to the iframe and submits the form. What I would like to happen is the iframe to load the result of that request. So, I would effectively like to post a form and render the result inside the iframe, without touching the parent (apart from putting the iframe up for display in the first place). I am using the code from this answer: http://stackoverflow.com/questions/133925/javascript-post-request-like-a-form-submit/134003#134003 but I can't get it to not reload the parent. I post the form, and instead of the iframe refreshing, the entire parent refreshes. I don't know why that is, since the url it's posting to is different and would at least redirect there. Can anyone help me with this problem? I just want a post inside an iframe and only within the iframe, basically. EDIT: After some more research, apparently the form is not being created properly. I'm using document.createElement("form") and then document.getElementById("my_iframe_id").appendChild(form) to append it, but it does not seem to be working correctly.

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  • Selecting a form which is in an iframe using jQuery

    - by Khnle
    I have a form inside an iframe which is inside a jQuery UI dialog box. The form contains a file input type. The jQuery UI dialog contains an Upload button. When this button is clicked, I would like to programmatically call the submit method. My question is how I could select the form which is in a iframe using jQuery. The following code should clarify the picture: <div id="upload_file_picker_dlg" title="Upload file"> <iframe id="upload_file_iframe" src="/frame_src_url" frameborder=0 width=100% scrolling=no></iframe> </div> frame_src_url contains: <form action="/UploadTaxTable" enctype="multipart/form-data" method="post" id="upload-form"> <p>Select a file to be uploaded:</p> <p> <input type="file" name="datafile" size="60"> </p> The jQueryUI dialog box javascript code: $('#upload_file_picker_dlg').dialog({ ... buttons: { 'Close': function() { $(this).dialog('close'); }, 'Upload': function() { $('#upload-form').submit(); //question is related to this line $(this).dialog('close'); } }, .... }); From the javascript code snippet above, how can I select the form with id upload-form that is in the iframe whose id is upload_file_iframe ?

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  • Django - partially validating form

    - by aeter
    I'm new to Django, trying to process some forms. I have this form for entering information (creating a new ad) in one template: class Ad(models.Model): ... category = models.CharField("Category",max_length=30, choices=CATEGORIES) sub_category = models.CharField("Subcategory",max_length=4, choices=SUBCATEGORIES) location = models.CharField("Location",max_length=30, blank=True) title = models.CharField("Title",max_length=50) ... I validate it with "is_valid()" just fine. Basically for the second validation (another template) I want to validate only against "category" and "sub_category": In another template, I want to use 2 fields from the same form ("category" and "sub_category") for filtering information - and now the "is_valid()" method would not work correctly, cause it validates the entire form, and I need to validate only 2 fields. I have tried with the following: ... if request.method == 'POST': # If a filter for data has been submitted: form = AdForm(request.POST) try: form = form.clean() category = form.category sub_category = form.sub_category latest_ads_list = Ad.objects.filter(category=category) except ValidationError: latest_ads_list = Ad.objects.all().order_by('pub_date') else: latest_ads_list = Ad.objects.all().order_by('pub_date') form = AdForm() ... but it doesn't work. How can I validate only the 2 fields category and sub_category?

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  • javascript unable to locate a form using the ID tag

    - by ihake
    Here's my problem: I'm trying to set up a simple mobile contact form with a captcha built in. The page I'm working on can be found here: http://m.lancasterpainting.com/contact.php I'm using the following php contact form: http://www.html-form-guide.com/contact-form/php-email-contact-form.html I want to first say that I'm not the only one to run into this problem. After googling the issue, I've found multiple people struggling with this, but no-one seems to have an answer. Now for the problem... As you can see if you visit the page, each time the page is accessed, an error appears that says "Error: couldnot get Form object contact_form". I cannot--for the life of me--figure out why the javascript can't find the form I pass it. I call the function that generates this error at the top of the page: var frmvalidator = new Validator("contact_form"); The form I'm referencing is as follows in the HTML code: <div data-role="page" data-theme="e" id="contact_form" name="contact_form" data-position="inline"> ... And the function that is called that generates the error can be found in an external .js file here: http://m.lancasterpainting.com/scripts/gen_validatorv31.js Is there something that I am simply not seeing? Why can't the javascript locate the form? Thanks so much to anyone that helps with this.

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  • Manual Directory Submission Service a Long Way to Go But Effective

    Yes you heard it right Manual Directory Submission Service is really a long way to go but very effective for your business. In fact this is a process of registering or submitting your website with its details to an online web directory. The advantage of this listing is that when a customer needs any service or product, he will search for business on a web directory for assistance and when your expertise meet with the keywords that he typed in search bar, you website link will be visible to him and he will click that link from where he will be redirected to your website.

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  • How can web form content be preserved for the back button

    - by Peter Howe
    When a web form is submitted and takes the user to another page, it is quite often the case that the user will click the Back button in order to submit the form again (the form is an advanced search in my case.) How can I reliably preserve the form options selected by the user when they click Back (so they don't have to start from scratch with filling the form in again if they are only changing one of many form elements?) Do I have to go down the route of storing the form options in session data (cookies or server-side) or is there a way to get the browser to handle this for me? (Environment is PHP/JavaScript - and the site must work on IE6+ and Firefox2+)

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  • Server-side validation and form action

    - by phenry
    I have a page (call it form.php) with a form for users to fill out. When the form is submitted, I want to validate it with a server-side script (call it validate.php if necessary, although the code could also go in one of the other pages if that would be better). If any part of the form fails validation, I want to kick back to form.php with the fields the user needs to fix highlighted. If the form passes validation, I want to go to another page, success.php. Which page should I put in the "action" attribute of the <form> element, and what's the best way to get from that page to one of the others?

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  • C# property in a form class only accessable after formload event

    - by Spooky2010
    using vs2008, c# Howdy, Im instantiating and calling Form B from Form A. FormB has some custom properties, to allow me to pass it things like sqlAdaptors and dataset instances. When i instantiate and show Form B from Form A as a dialog form with a Using statement, it all works fine, but i find the properties i pass are not available in Form B until after the form_load event has fired. I was under the impression the properties when passed to a instantiated class should be available from a constructor, but this is not the case. If it try to access the properties before the form load event i get a null reference exception. Is this correct behavior ? It is very annoying. thanks for any help

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  • Using C# to iterate form fields with same name

    - by itsatrp
    I have a section of a form that I need to handle differently from the rest of form results. In the section that needs special handling I need to iterate over 3 form fields that have the same name. They have to have the same name, I can't change it. The section of the form I am referring to looks something like this: <td><input name="Color" size="20" value="" type="text"></td> Using C# I try something like this: I try to handle it like this: int i; for (i = 1; i <= Request.Form["Color"][i]; i++) { colorName.Text += Request.Form["Color"]; } Which leads to the following exception: System.NullReferenceException: Object reference not set to an instance of an object. How should I be handling form fields with the same name?

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  • PDF form created in Libre Office - trouble with form fields and font sizing

    - by soawesomejohn
    I am trying to create a PDF Form using LibreOffice. I can create the form elements and export as PDF. However, the form fields are giving me problems. The text in these fields always centers on the bottom, and often the text you input is cut off at the bottom. I found that if I make the fields larger, the text no longer cuts off, but the field is exceptionally large with lots of space above the text. I have made an odt (source) and a pdf (export) file to show what I'm running into. I tried a number of different fonts and sizes, but to make things easier, I made the field names all "field1" so that once you fill out one entry, all fields show as filled in. http://ytnoc.net/files/sampleapp.odt http://ytnoc.net/files/sampleapp.pdf My main question is how do I make form fields that don't cut off the text without having to make the fields way oversized? Made with LibreOffice 3.3.0

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  • jQuery: modify hidden form field value before submit

    - by Jason Miesionczek
    I have the following code in a partial view (using Spark): <span id="selectCount">0</span> video(s) selected. <for each="var video in Model"> <div style="padding: 3px; margin:2px" class="video_choice" id="${video.YouTubeID}"> <span id="video_name">${video.Name}</span><br/> <for each="var thumb in video.Thumbnails"> <img src="${thumb}" /> </for> </div> </for> # using(Html.BeginForm("YouTubeVideos","Profile", FormMethod.Post, new { id = "youTubeForm" })) # { <input type="hidden" id="video_names" name="video_names" /> <input type="submit" value="add selected"/> # } <ScriptBlock> $(".video_choice").click(function() { $(this).toggleClass('selected'); var count = $(".selected").length; $("#selectCount").html(count); }); var options = { target: '#videos', beforeSubmit: function(arr, form, opts) { var names = []; $(".selected").each(function() { names[names.length] = $(this).attr('id'); }); var namestring = names.join(","); $("#video_names").attr('value',namestring); //alert(namestring); //arr["video_names"] = namestring; //alert($.param(arr)); //alert($("#video_names").attr('value')); return true; } }; $("#youTubeForm").ajaxForm(options); </ScriptBlock> Essentially i display a series of divs that contain information pulled from the YouTube API. I use jQuery to allow the the user to select which videos they would like to add to their profile. When i submit the form i would like to populate the hidden field with a comma separated list of video ids. Everything works except that when i try to set the value of the field, in the controller on post, the field comes back empty. I am using the jQuery ajax form plugin. What am i doing wrong that is not allowing the value i set in the field to be sent to the server?

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  • form validation without reset

    - by Paulo Bueno
    Hi guys Is there a way to check the data sent by a form to a PHP page return to the form page WITHOUT resetting the data sent and show a error? The form has 20 fields and I need to check one of them on a bd. If it fails the user may be redirected to the form page with the form populated and displaying a error message on the field which is 'wrong'. I would like any advice of a technique instead of populating each field using PHP.

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  • scripting a google docs form submission

    - by justSteve
    I'm trying to create a bookmarklet that parses a page and sends the results to a googledocs spreadsheet via a form that I've defined. The relevent bit of the script is: var form = document.createElement("form"); form.action = "http://spreadsheets.google.com/formResponse?formkey=Fd0SHgwQ3YwSFd5UHZpM1QxMlNOdlE6MA&ifq"; form.method = "POST"; form.id="ss-form"; form.innerHTML = ["<input id='entry_0' name = 'entry.0.single' value = '" + orderDate + "'/>", "<input name = 'entry.2.single' value = '" + email + "'/>", "<input name = 'entry.3.single' value = '" + customerID + "'/>", ].join(""); form.submit(); alert(form.innerHTML); // returns: Nothing is being saved to the form via the bookmarklet - any way to capture google's response in my bookmarklet's code? (fwiw, i've injected jQuery via jQueryify) EDIT: Firebug's Net panel isn't hearing any of the activity triggered by the bookmarklet - How about i approach this from goolgle's viewform method instead of formresponse. The form i'm trying to submit is located at: http://spreadsheets.google.com/viewform?hl=en&formkey=dFd0SHgwQ3YwSFd5UHZpM1QxMlNOdlE6MA How can I go about injecting the script values into that form and then submitting that - again...via script within the bookmarklet that would have been triggered while on the page being parsed?

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  • How do I write a custom validator for a zend form element with customized error messages?

    - by Mallika Iyer
    I have a question field with a list of allowed characters : A-Z,0-9,colon (:), question mark (?), comma(,), hyphen(-), apostrophe ('). I have the regex which works fine, in the fashion : $question->addValidator('regex', true, array(<regular expresstion>)) The default error message is something like ''' does not match against pattern '' I want to write a custom error message that says ' is not allowed in this field' Is there a simple way to do it using the existing zend components that I'm missing? Is writing a custom validator the only way to achieve what I'm trying to achieve? If yes, how do I write a custom validator (I looked at the documentation and didn't quite understand how I can customize the error messages) If there is any other way, I'd most appreciate that input too. Thanks for taking the time to answer this!

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  • Javascript onunload form submit isn't submitting data

    - by Kevin
    I currently have form that checks if a user has unsubmitted changes when they leave the page with a function called through the onunload event. Here's the function: function saveOnExit() { var answer = confirm("You are about to leave the page. All unsaved work will be lost. Would you like to save now?"); if (answer) { document.main_form.submit(); } } And here's the form: <body onunload="saveOnExit()"> <form name="main_form" id="main_form" method="post" action="submit.php" onsubmit="saveScroll()"> <textarea name="comments"></textarea> <input type="submit" name="submit2" value="Submit!"/> </form> I'm not sure what I'm doing wrong here. The data gets submitted and saved in my database if I just press the submit button for the form. However, trying to submit the form through the onunload event doesn't result in anything being stored, from what I can tell. I've tried adding onclick alerts to the submitt button and onsubmit alerts to the form elements and I can verify that the submit button is being triggered and that the form does get submitted. However, nothing gets passed stored in the database. Any ideas as to what I'm doing wrong? Thanks.

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  • Strange issue with fixed form border styles in Vista

    - by Nazgulled
    My previous post about this issue didn't got too many answers and it was kinda specific and hard to understand. I think I've managed to understand the problem better and I now believe it to be a Vista issue... The problem lies on all types of fixed border styles like FixedDialog, Fixed3D, FixedSingle and FixedToolWindow. It does not happen on the sizable ones. This problem, like I said, it also happens only on Vista. Let's say you have a form with any of the fixed border styles and set the starting location to 0,0. What you want here is for the form to be snapped to the top left corner of the screen. This works just fine if the form border style is one of the sizable options, if it's fixed, well, the form will be a little bit outside of the screen working area both to the left and top. What's more strange about this is that the form location does not change, it sill is 0,0, but a few pixels of the form are still drawn outside of the working screen area. I tested this on XP and it didn't happen, the problem is Vista specific. On XP, the only difference was the border size that change a bit between any of the styles. But the form was always perfectly snapped to position 0,0. If possible, without finding how many pixels are being drawn outside of the working area and then add that to the form location, is there a possible way to fix or workaround this?

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  • Refresh page in browser without resubmitting form

    - by Michael
    I'm an ASP.NET developer, and I usually find myself leaving the webpage that I'm working on open in my browser (Chrome is my browser of choice, but this question is relevant for any browser). My workflow typically goes like this: I write code, I rebuild my project in Visual Studio, and then I flip back to my browser with Alt-Tab and hit F5 to refresh the page. This is fine and dandy if a form hasn't been submitted since the page was opened. But if I've been clicking around on ASP.NET form controls, the page has posted form data a number of times, so hitting F5 causes the browser to (sensibly) pop up a confirmation message, e.g., "Confirm Form Resubmission: The page that you're looking for used information that you entered...". Sometimes I do want to resubmit the form, but more often than not, I just want to start over with the page (rather than resubmit form data). The way I usually get around this is to simply add some query string data to the URL so that the browser sees it as a fresh page request, e.g.: page.aspx becomes page.aspx? (or vice-versa). My question is: Is there a better way to quickly request a fresh version of a webpage (and not submit form data) in any of the major browsers? It seems like a no-brainer to me for web development, but maybe I'm missing something. What I'd love to see is something like the last item in this list: F5: refresh page Ctrl-F5: refresh page (and force cache refresh) Alt-F5: request fresh copy of the page without resubmitting the form

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  • FireFox: strange behavior on submiting a form

    - by ilnur777
    Can anyone help with this strange form submiting in FireFox? So this form should be submitted after pushing "go to submit" button. There is an onclick event on the button that should submit form through JavaScript. In the form there is another button "test" without any onclick event. Following the script, the form should be submitted only after pushing the "go to submit" button, but it submits even pushing at "test" button. In the Internet Explorer it works well! But this stupid FireFox browser behaves different. Here is example of HTML page: <script> function func(){ document.form1.submit(); } </script> <form name="form1" method="post" action="somewhere.php"> <button>test</button> <input type="button" value="go to submit" onclick="func();"> </form> I have several buttons with <button onclick="...">option 1</button> options. I want to fix strange submiting a form in FireFox. Help please!

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  • PDF form (not) saving

    - by gregseth
    Hi, I've created a form in a PDF with Adobe Acrobat Pro. When empy, I want to use it as a template which the user opens, fills in, and saves as a copy to preserve the blank state of the template. Here's the trick : I found both ways to make the document read only - the user can't save the form value, only print them make the document writeable, but in this case the document acting as a template can be modified too. Any ideas? Thanks.

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  • Using a checkbox input on a form to send the form data to different email addresses

    - by Cody Thomas
    I am building a form for a client. Here is the rundown. The form will be used as a request to have a staff member contact the person filling out the form. However, there is a list of staff members that will contact them depending on what the subject matter is. So, I want to create a checkbox input section on the form with each staff person's email address attached to a corresponding checkbox. So, the person filling out the form can check only the staff people necessary for their needs. Finally, when the person clicks "submit", the form will be emailed to only the staff members who were checked in the form. I'm at a loss of how to set this up.

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