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Search found 505 results on 21 pages for 'minus'.

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  • Why does multiplying a double by -1 not give the negative of the current answer

    - by Ankur
    I am trying to multiply a double value by -1 to get the negative value. It continues to give me a positive value double man = Double.parseDouble(mantissa); double exp; if(sign.equals("plus")){ exp = Double.parseDouble(exponent); } else { exp = Double.parseDouble(exponent); exp = exp*-1; } System.out.println(man+" - "+sign+" - "+exp); The printed result is 13.93 - minus - 2.0 which is correct except that 2.0 should be -2.0

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  • String format or REGEX.

    - by ThePower
    I need an simple way to check whether a string that is sent to my function is of the form: (x + n)(x + m) //the +'s can be minus' //n and m represent a double //x represents the char 'x' Is there a simple string format that I can use to check that this is the form. As opposed to checking each character singularly. The whitespace will be removed to save any confusion. Regards Lloyd

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  • Check for a string format...

    - by ThePower
    I need an simple way to check whether a string that is sent to my function is of the form: (x + n)(x + m) //the +'s can be minus' //n and m represent a double //x represents the char 'x' Is there a simple string format that I can use to check that this is the form. As opposed to checking each character singularly. The whitespace will be removed to save any confusion. Regards Lloyd

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  • Has anyone got the vim taglist plugin working with Scala?

    - by Eric Hauser
    I'm having trouble getting the taglist plugin working properly with Scala. I've installed the plugin and ctags and verified that it works properly with Java and C++. I then followed the instructions on this page (minus the Lift specific instructuions), but was nothing shows up in the taglist window when I open it while editing a Scala file. Has anyone got this working and what are the proper steps? Thanks.

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  • NetBeans shortcut key for collapsing/expanding a method

    - by Stefanos Kargas
    JAVA - NETBEANS This is an IDE question I am always working with collapsed methods, because I want to be able to see my methods all together. This is a little time consuming because I have to use the mouse to scroll up to the declaration of the method and click on the - (minus) icon. And then respectively go to the method I want to work on and click on the + (plus) icon. Is there a way through a keyboard shortcut to do the collapse (and respectively the expand)?

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  • UITableView : detecting click on '-' button in edit mode

    - by synthez84
    Hi all, On my iphone app, I have a UITableView in edit mode, containing custom UITableViewCell. I would like to detect when user has clicked on the left button of each cell (minus circular red button, the one that is animated with a rotation), just before the "Delete" button appears. I would like to be able to change my cell content in that case... Is that possible ? Thanks !

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  • The best way to do :not in jQuery?

    - by Smickie
    Hi, I have a menu in jQuery when you click on a link it opens up, but I want it so when you click somewhere else, anywhere else that is not the menu, it becomes hidden. At the moment I'm binding a click event to $(':not(#the_menu)') But this seems like I'm binding a click event to the entire minus the menu, is there a more efficient way of doing something like this?

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  • How to reduce redundant code when adding new c++0x rvalue reference operator overloads

    - by Inverse
    I am adding new operator overloads to take advantage of c++0x rvalue references, and I feel like I'm producing a lot of redundant code. I have a class, tree, that holds a tree of algebraic operations on double values. Here is an example use case: tree x = 1.23; tree y = 8.19; tree z = (x + y)/67.31 - 3.15*y; ... std::cout << z; // prints "(1.23 + 8.19)/67.31 - 3.15*8.19" For each binary operation (like plus), each side can be either an lvalue tree, rvalue tree, or double. This results in 8 overloads for each binary operation: // core rvalue overloads for plus: tree operator +(const tree& a, const tree& b); tree operator +(const tree& a, tree&& b); tree operator +(tree&& a, const tree& b); tree operator +(tree&& a, tree&& b); // cast and forward cases: tree operator +(const tree& a, double b) { return a + tree(b); } tree operator +(double a, const tree& b) { return tree(a) + b; } tree operator +(tree&& a, double b) { return std::move(a) + tree(b); } tree operator +(double a, tree&& b) { return tree(a) + std::move(b); } // 8 more overloads for minus // 8 more overloads for multiply // 8 more overloads for divide // etc which also has to be repeated in a way for each binary operation (minus, multiply, divide, etc). As you can see, there are really only 4 functions I actually need to write; the other 4 can cast and forward to the core cases. Do you have any suggestions for reducing the size of this code? PS: The class is actually more complex than just a tree of doubles. Reducing copies does dramatically improve performance of my project. So, the rvalue overloads are worthwhile for me, even with the extra code. I have a suspicion that there might be a way to template away the "cast and forward" cases above, but I can't seem to think of anything.

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  • Calculate total time between Dates in Hours and Minutes

    - by matthew parkes
    Hi I’m trying to resolve a problem using VB and I need some assistance. I’m very new to the language (1 week). The problem is I have created a user form to show how many hours and minutes has elapsed between two different times similar to a time sheet. The user form consists of two calendars, and under each calendar there are two text boxes; one box each to record the Hour and Minute they left and two further boxes to record the time they arrived back. I have used the code to minus the calendars together (e.g calendar in – calendar out) then times this by 24 to indicate the hours away. Then under the calendar out I have a text box for the user to type in the hour they left. Then I minus the 24 by the Hour out e.g. if it was 24 -15 it will appear 9 ( 9 hours of that day ) then I would add that to the figure they inserted in the text box Hour in (Return Time). e.g 14. Then I would add them to together e.g. 9 + 14 = 23 and have this displayed in another text box Total Hours. Therefore it would display 23 meaning 23 hours. I have then want to show another two text boxes to indicate minutes. One for Minutes Out then Minutes In. I have the problem to convert these minutes for instance if it is the out time is 15:50 and the in time the next day is at 15:55 it displays as 24 (in one text box) and 105 minutes (in the other text box). I would like the minutes added to the hour and have the balance of the remaining minutes in the minute text box. This should display 24 (in one text box) and 5 (in another text box). The ultimate aim is to get a result that shows a person was absent for a number of days, hours and minutes, eg, 2 days, 5 hours and 10 minutes. Any ideas on how I can modify my code to achieve this? Here’s my code. Please Help Dim number1 As Date Dim number2 As Date Dim number3 As Integer Dim number4 As Integer Dim Number5 As Integer Dim Number6 As Integer Dim answer As Integer Dim answer2 As Integer Dim answer3 As Integer Dim answer4 As Integer Dim answer5 As String number1 = DTPicker1 number2 = DTPicker2 number3 = Txthourout number4 = TxtHourin Number5 = TxtMinuteout Number6 = TxtMinuetIn answer = number2 - number1 answer2 = answer * 24 answer3 = answer2 - number3 answer4 = answer3 + number4 answer5 = Number5 + Number6 TextBox1.Text = answer4 TextBox2.Text = answer5 End Sub

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  • Converting a list into a select with jquery

    - by Davemof
    I'm trying to convert the following list into a select list so it can be submitted via a form - the element within the lists will become the value of each option: <ul class="selected connected-list ui-sortable" style="height: 279px;"> <li class="ui-helper-hidden-accessible" style=""></li> <li title="Owner Name 1 - " class="ui-state-default ui-element ui-draggable" style="display: block; position: relative; top: 0px; left: 0px;"><span class="ui-icon-arrowthick-2-n-s ui-icon"></span>Owner Name 1 - <em class="thenumber">4.4796E+11</em><a class="action" href="#"><span class="ui-corner-all ui-icon ui-icon-minus"></span></a></li> <li title="David Moffat - " class="ui-state-default ui-element" style="display: block; position: relative; top: 0px; left: 0px;"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>David Moffat - <em class="thenumber">07730423005</em><a class="action" href="#"><span class="ui-corner-all ui-icon ui-icon-minus"></span></a></li> </ul> This should convert to the following format: <select style="display:none" class="selectoption" name="p_num[]" multiple="multiple"> <option value="">4.4796E+11</option> <option value="">07730423007</option> </select> I have tried the following jquery code, but after many hours I'm pulling my hair out: $('a.sendform').click(function(){ $('ul.selected').each(function() { var $select = $('<select />'); $(this).find('li').each(function() { var $option = $('<option />'); $option.attr('value', $(this).('em')).html($(this).html()); $select.append($option); }); $(this).replaceWith($select); }); }); Any help might save my remaining hair. Many thanks David

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  • how do I make my submenu position dynamic based on the distance to the edge of the window?

    - by Mario Antoci
    I'm trying to write a jQuery script that will find the distance to the right edge of the browser window from my css class element and then position the child submenu dropdowns to the right or left depending on the available space to the right. Also it needs to revert to the default settings on hoverout. Here is what I have so far but it's not calculating properly. $(document).ready(function(){ $('#dnnMenu .subLevel').hover(function(){ if ($(window).width() - $('#dnnMenu .subLevel').offset().left - '540' >= '270') { $('#dnnMenu .subLevelRight').css('left', '270px');} else {$('#dnnMenu .subLevelRight').css('left', '-270px');} }); $(document).ready(function () { function HoverOver() { $(this).addClass('hover'); } function HoverOut() { $(this).removeClass('hover'); } var config = { sensitivity: 2, interval: 100, over: HoverOver, timeout: 100, out: HoverOut }; $("#dnnMenu .topLevel > li.haschild").hoverIntent(config); $(".subLevel li.haschild").hover(HoverOver, HoverOut); }); Basically I tried to take the width of the current window, minus the distance to the left edge of the browser of the first level submenu, minus the width of both elements together which would equal 540px, to calculate the distance to the right edge of the window when the first level submenu is hovered over. if the distance to the right of my first level submenu element is less than 540px then the second level sub menu css property is changed to position to the left instead of right. I also know that it needs to revert back to default after hover out so it can recalculate the distance from other positions within the menu structure and still have those second level submenus with enough room to still display on the right of the first level. here is css for the elements in question. #dnnMenu .subLevel{ display: none; position: absolute; margin: 0; z-index: 1210; background: #639ec8; text-transform: none;} #dnnMenu .subLevelRight{ position: absolute; display: none; left: 270px; top: 0px;} The site's not live yet and I tried to create a jsfiddle but it doesn't look right. Any help would be greatly appreciated! Best Regards, Mario

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  • Merging list problem

    - by Martin Malmstrøm
    Sorry about the bad heading, but the question was not easy to compress into one sentence... I have two lists of contigs (list1 and list2). They contain mostly unique contigs, but with some overlap. I want to compare list1 and list2 and then create a list3 that contains all contigs in list1 minus those also present in list2. Is this possible with a simple cat/paste/grep/sort/uniq kind of batch command? Thanks!

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  • MySQL: difference of two result sets

    - by Zombies
    How can I get the set difference of two result sets? Say I have a result set (just one column in each): result1: 'a' 'b' 'c' result2: 'b' 'c' I want to minus what is in result1 by result2: result1 - result2 such that it equals: difference of result1 - result2: 'a'

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  • How to convert rows returned by a query into columns in oracle?

    - by Piyush Lohana
    I have to display the results of the below query as columns. select to_char(sysdate + 1 - rownum,'MON-YYYY') as d from all_objects where trunc(sysdate + 1 - rownum,'MM') = trunc(to_date(:from_date,'MON-YYYY'),'MM') minus select to_char(sysdate + 1 - rownum,'MON-YYYY') as d from all_objects where trunc(sysdate + 1 - rownum,'MM') trunc(to_date(':to_date','MON-YYYY'),'MM') Please help me in figuring that out.

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  • why IEEE floating point number calculate exponent using a biased form?

    - by lenatis
    let's say, for the float type in c, according to the IEEE floating point specification, there are 8-bit used for the fraction filed, and it is calculated as first taken these 8-bit and translated it into an unsigned number, and then minus the BIASE, which is 2^7 - 1 = 127, and the result is an exponent ranges from -127 to 128, inclusive. But why can't we just treat these 8-bit pattern as a signed number, since the resulting range is [-128,127], which is almost the same as the previous one.

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