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  • Oracle Hosts Successful PeopleSoft Customer Advisory Board Meetings

    - by Mark.Hoernemann
    Last week, Oracle hosted the annual Customer Advisory Board meetings for various PeopleSoft applications, including the PeopleTools CAB.  The three day event at the Oracle headquarters brought together over 90 customers, with over 170 representatives taking part.  This was the largest CAB event PeopleSoft has had to date.  The focus of the event was to share our vision for PeopleSoft, and gain valuable input from our customer base on our direction and focus areas.  The customer feedback we received for the event was extremely positive, matching the sentiment on our side.  The information our CAB members provided was excellent; it will help ensure that we focus on the areas that matter most to our customers.   I’d like to thank all the customers that took the time out of their schedules to hear where we’re looking to go in the future, and provide guidance on how we can best assist our customer base on remaining successful in the marketplace.

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  • PeopleSoft Mobile Company Directory

    - by Nancy Estell Zoder
    Oracle is pleased to announce the posting of our latest feature, Mobile Company Directory (click here for press release).  Our continued investment in innovation is demonstrated with the first release of our mobile solution. Now, from your tablet or smartphone, the PeopleSoft 9.1 Company Directory feature enables you to search for people, obtain contact details, reporting structure and personal information. The PeopleSoft Mobile solution enables you to email people in your organization, make phone calls as well as send text messages.   Both the tablet and smart phone provide quick and easy access to contact information to allow users to directly communicate with people in the organization while on the go.  Watch the Video Feature Overview on YouTube here:   PeopleSoft Mobile Company Directory For more information, please check out the datasheet available on oracle.com or contact your sales representative.   

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  • check if a tree is complete standard ml

    - by aizen92
    I want to make a function in standard ml that checks if a tree is complete or not, the function somehow works, but its giving me the wrong type and a warning of non-exhaustive cases The tree code: datatype 'data tree = EMPTY | NODE of 'data tree * 'data * 'data tree; fun isComplete EMPTY = true | isComplete (NODE(x, y, z)) = if (x = EMPTY andalso z <> EMPTY) orelse (x <> EMPTY andalso z = EMPTY) then false else true; Now the above function's type is: ''a tree -> bool but the required type is 'a tree -> bool The warning I'm having is: stdIn:169.8 Warning: calling polyEqual stdIn:169.26 Warning: calling polyEqual stdIn:169.45-169.47 Warning: calling polyEqual stdIn:169.64-169.66 Warning: calling polyEqual stdIn:124.1-169.94 Warning: match nonexhaustive NODE (x,y,z) => ... What is the problem I'm having?

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  • How to find largest common sub-tree in the given two binary search trees?

    - by Bhushan
    Two BSTs (Binary Search Trees) are given. How to find largest common sub-tree in the given two binary trees? EDIT 1: Here is what I have thought: Let, r1 = current node of 1st tree r2 = current node of 2nd tree There are some of the cases I think we need to consider: Case 1 : r1.data < r2.data 2 subproblems to solve: first, check r1 and r2.left second, check r1.right and r2 Case 2 : r1.data > r2.data 2 subproblems to solve: - first, check r1.left and r2 - second, check r1 and r2.right Case 3 : r1.data == r2.data Again, 2 cases to consider here: (a) current node is part of largest common BST compute common subtree size rooted at r1 and r2 (b)current node is NOT part of largest common BST 2 subproblems to solve: first, solve r1.left and r2.left second, solve r1.right and r2.right I can think of the cases we need to check, but I am not able to code it, as of now. And it is NOT a homework problem. Does it look like?

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  • Dojo JsonRest store and dijit.Tree

    - by user1427712
    I'm having a some problem making JSonRest store and dijit.Tree with ForestModel. I've tried some combination of JsonRestStore and json data format following many tips on the web, with no success. At the end, taking example form here http://blog.respondify.se/2011/09/using-dijit-tree-with-the-new-dojo-object-store/ I've made up this simple page (I'm using dojotolkit 1.7.2) <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Tree Model Explorer</title> <script type="text/javascript"> djConfig = { parseOnLoad : true, isDebug : true, } </script> <script type="text/javascript" djConfig="parseOnLoad: true" src="lib/dojo/dojo.js"></script> <script type="text/javascript"> dojo.require("dojo.parser"); dojo.require("dijit.Tree"); dojo.require("dojo.store.JsonRest"); dojo.require("dojo.data.ObjectStore"); dojo.require("dijit.tree.ForestStoreModel"); dojo.addOnLoad(function() { var objectStore = new dojo.store.JsonRest({ target : "test.json", labelAttribute : "name", idAttribute: "id" }); var dataStore = new dojo.data.ObjectStore({ objectStore : objectStore }); var treeModel = new dijit.tree.ForestStoreModel({ store : dataStore, deferItemLoadingUntilExpand : true, rootLabel : "Subjects", query : { "id" : "*" }, childrenAttrs : [ "children" ] }); var tree = new dijit.Tree({ model : treeModel }, 'treeNode'); tree.startup(); }); </script> </head> <body> <div id="treeNode"></div> </body> </html> My rest service responds the following json { data: [ { "id": "PippoId", "name": "Pippo", "children": [] }, { "id": "PlutoId", "name": "Pluto", "children": [] }, { "id": "PaperinoId", "name": "Paperino", "children": [] } ]} I've tried also with the following response (actually my final intention n is to use lazy loading for the tree) { data: [ { "id": "PippoId", "name": "Pippo", "$ref": "author0", "children": true }, { "id": "PlutoId", "name": "Pluto", "$ref": "author1", "children": true }, { "id": "PaperinoId", "name": "Paperino", "$ref": "author2", "children": true } ]} Neither of the two works. I see no error message in firebug. I simply see the root "Subject" on the page. Thanks to anybody could help in some way.

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  • F#: Recursive collect and filter over N-ary Tree

    - by RodYan
    This is hurting my brain! I want to recurse over a tree structure and collect all instances that match some filter into one list. Here's a sample tree structure type Tree = | Node of int * Tree list Here's a test sample tree: let test = Node((1, [Node(2, [Node(3,[]); Node(3,[])]); Node(3,[])])) Collecting and filtering over nodes with and int value of 3 should give you output like this: [Node(3,[]);Node(3,[]);Node(3,[])]

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  • In-order tree traversal

    - by Chris S
    I have the following text from an academic course I took a while ago about in-order traversal (they also call it pancaking) of a binary tree (not BST): In-order tree traversal Draw a line around the outside of the tree. Start to the left of the root, and go around the outside of the tree, to end up to the right of the root. Stay as close to the tree as possible, but do not cross the tree. (Think of the tree — its branches and nodes — as a solid barrier.) The order of the nodes is the order in which this line passes underneath them. If you are unsure as to when you go “underneath” a node, remember that a node “to the left” always comes first. Here's the example used (slightly different tree from below) However when I do a search on google, I get a conflicting definition. For example the wikipedia example: Inorder traversal sequence: A, B, C, D, E, F, G, H, I (leftchild,rootnode,right node) But according to (my understanding of) definition #1, this should be A, B, D, C, E, F, G, I, H Can anyone clarify which definition is correct? They might be both describing different traversal methods, but happen to be using the same name. I'm having trouble believing the peer-reviewed academic text is wrong, but can't be certain.

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  • Peoplesoft queries - performance

    - by DBa
    Hi, I'm facing a problem with PeopleSoft queries (using Oracle backend database): when a rather complex query involving multiple records is set off by a user, PS does an enforced join of security records, thus producing SQL like this: select .... from ps_job a, PS_EMPL_SRCQRY a1, ps_table2 b, ps_sec_rcd2 b1, ps_table3 c, ps_sec_rcd3 c1 where (...security joins a-a1, b-b1, c-c1...) and (...joins of a, b and c...) and a.setid_dept = 'XYZ'; (let's assume the last condition has a high selectivity and there is an index on the column) Obviously, due to the arrangement of the conditions, first a huge join is created, written to the temp segment, and when the last condition is finally applied, only a small subset is selected. A query formulated in this way is very likely to hit the preset timeout of the APPSRV, and even of the QRYSRV. When writing the query manually, I would rather move the most selective condition to the start, thus limiting the amount of the data being handled, to a considerable level. Any ideas on how to make PS behave like this? Actually, already rewriting "Oracle-styled" SQL to ANSI SQL seems to accelerate the queries - however, PS writes Oracle-style queries... Thanks in advance DBa

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  • Redpaper Available: Collaboration Platform in PeopleSoft

    - by matthew.haavisto
    With the availability of Related Content and Collaborative Workspaces as part of PeopleTools 8.50, there is increasing need and demand for understanding how to set up collaborative capabilities in the PeopleSoft platform. To help with that, we've recently published a redpaper that can help you understand how to set up Related Content sevices and Collaborative Workspaces for all your PeopleSoft applications. You can find it on My Oracle Support here. The redpaper is a nice guide, and you can also find more information on these subjects in PeopleBooks.

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  • Scene graphs and spatial partitioning structures: What do you really need?

    - by tapirath
    I've been fiddling with 2D games for awhile and I'm trying to go into 3D game development. I thought I should get my basics right first. From what I read scene graphs hold your game objects/entities and their relation to each other like 'a tire' would be the child of 'a vehicle'. It's mainly used for frustum/occlusion culling and minimizing the collision checks between the objects. Spatial partitioning structures on the other hand are used to divide a big game object (like the map) to smaller parts so that you can gain performance by only drawing the relevant polygons and again minimizing the collision checks to those polygons only. Also a spatial partitioning data structure can be used as a node in a scene graph. But... I've been reading about both subjects and I've seen a lot of "scene graphs are useless" and "BSP performance gain is irrelevant with modern hardware" kind of articles. Also some of the game engines I've checked like gameplay3d and jmonkeyengine are only using a scene graph (That also may be because they don't want to limit the developers). Whereas games like Quake and Half-Life only use spatial partitioning. I'm aware that the usage of these structures very much depend on the type of the game you're developing so for the sake of clarity let's assume the game is a FPS like Counter-Strike with some better outdoor environment capabilities (like a terrain). The obvious question is which one is needed and why (considering the modern hardware capabilities). Thank you.

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  • On Windows 7, dir or tree can't show unicode characters, even starting cmd with cmd /U

    - by Jian Lin
    On Windows 7, dir or tree can't show unicode characters, even starting cmd with cmd /U So I would press Window Key + R to run something, and type in cmd /U so that the content might handle Unicode. And then using dir or tree /F, the content in Unicode won't show as Unicode. (in Window Explorer (file manager), the Unicode will show) Is there a way to handle it? To get Unicode characters to test your filenames, you can go to http://news.google.com/news?edchanged=1&ned=tw and you will be able to get many Unicode characters there (UTF-8)

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  • How to Serialize Binary Tree

    - by Veljko Skarich
    I went to an interview today where I was asked to serialize a binary tree. I implemented an array-based approach where the children of node i (numbering in level-order traversal) were at the 2*i index for the left child and 2*i + 1 for the right child. The interviewer seemed more or less pleased, but I'm wondering what serialize means exactly? Does it specifically pertain to flattening the tree for writing to disk, or would serializing a tree also include just turning the tree into a linked list, say. Also, how would we go about flattening the tree into a (doubly) linked list, and then reconstructing it? Can you recreate the exact structure of the tree from the linked list? Thank you/

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  • recursion tree and binary tree cost calculation

    - by Tony
    Hi all, I've got the following recursion: T(n) = T(n/3) + T(2n/3) + O(n) The height of the tree would be log3/2 of 2. Now the recursion tree for this recurrence is not a complete binary tree. It has missing nodes lower down. This makes sense to me, however I don't understand how the following small omega notation relates to the cost of all leaves in the tree. "... the total cost of all leaves would then be Theta (n^log3/2 of 2) which, since log3/2 of 2 is a constant strictly greater then 1, is small omega(n lg n)." Can someone please help me understand how the Theta(n^log3/2 of 2) becomes small omega(n lg n)?

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  • SQL server - climb up in the tree structure

    - by Vytas999
    Hello. I have some sql table, named Object, which saves tree data in fields ObjectID, ParentID, and others. I have implemented recurse procedure, which select everything down by objectID from tree, like this: 1. 1.1. 1.2. 1.2.1. ... Now o need to "Climb up" - by some ObjectID i need to select everything Up, like this: 1.2.1. 1.2. 1. How i can do that? In example, my "down" procedure looks like: ALTER PROCEDURE [dbo].[Object_SelectDownByRoot_Simple] @ObjectID int AS WITH tree (ObjectID, ParentID, ObjectName, ObjectCode) AS ( SELECT ObjectID, ParentID, ObjectName, ObjectCode FROM dbo.[ObjectQ] ofs WHERE( ObjectID = @ObjectID ) UNION ALL SELECT ofs.ObjectID, ofs.ParentID, ofs.ObjectName, ofs.ObjectCode FROM dbo.[ObjectQ] ofs JOIN tree ON tree.ObjectID = ofs.ParentID ) SELECT ObjectID, ParentID, ObjectName, ObjectCode FROM tree

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  • how do i supply data to my gwt tree

    - by molleman
    Hello, So i need to create a tree with tree items for my gwt project. i am using the composite pattern to store all the information i need to be placed within a tree. A User has a root Folder that extends Hierarchy, this root Folder then has a list of Hierarchy objects, that can be FileLocations or Folders. Trouble i am having is building my tree based on this pattern. this data is all stored using hibernate in a mysql database How would i be able to implement this as a tree in gwt. Also the tree item that i create would have to reference back to the object so i can rename or move it.

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  • On Windows 7, dir or tree can't show unicode characters, even starting cmd with cmd /U

    - by ????
    On Windows 7, dir or tree can't show unicode characters, even starting cmd with cmd /U So I would press Window Key + R to run something, and type in cmd /U so that the content might handle Unicode. And then using dir or tree /F, the content in Unicode won't show as Unicode. (in Window Explorer (file manager), the Unicode will show) Is there a way to handle it? To get Unicode characters to test your filenames, you can go to http://news.google.com/news?edchanged=1&ned=tw and you will be able to get many Unicode characters there (UTF-8)

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  • Pure functional bottom up tree algorithm

    - by Axel Gneiting
    Say I wanted to write an algorithm working on an immutable tree data structure that has a list of leaves as its input. It needs to return a new tree with changes made to the old tree going upwards from those leaves. My problem is that there seems to be no way to do this purely functional without reconstructing the entire tree checking at leaves if they are in the list, because you always need to return a complete new tree as the result of an operation and you can't mutate the existing tree. Is this a basic problem in functional programming that only can be avoided by using a better suited algorithm or am I missing something?

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  • Correcting tree from messed up file tree in NTFS partition

    - by Fullmooninu
    It's a real messed situation, but I'm quite at the end of my options. It's my personal hardrive, so it's very important for me, and yes, I have no backup =( The short story: 1) I have two discs. One with Windows, and another where I had a bit of empty space at the front of the disk, so i could install Linux. The rest was occupied by a 1.8TB NTFS partition filled with data. 2) I installed Linux, and after a while realized there was not enough space for everything, so I tried using Gparted, and told it to re-size the NTFS partition, to a lesser size. 3) The system jammed. I had to reboot and broke the Resizing operation. Here's what I did to fix it: a) Rebooted into Linux Live, and used Testdisk,to deep analyze the disk, and recover the possible partitions. It found several versions of the NTFS partitions, probably made during the resizing. I told Testdisk to open every one of them, and only one could list its files. When trying to open the other options on Testdisk, it showed an error message. I assumed the one without errors, to be the correct one, and I told Testdisk to recover the partition, and write a new MBR. b) The partition had errors, and Linux has a NTFS fixing tool, used it, but the system still had errors. c) So I booted into windows and use chkdsk to correct all errors in the partition. d) Everything seems fine, but now, back in Windows, when I open one file, it opens another file, or part of another file. As in, some files took up the position of other files. What I think happened is that I recovered an old tree, and not the most current one. And that one just happened to be intact, while the most recent one was damaged. As such, the files that were moved during the failed resizing, were now, during the automatic correction, assumed wrongly to be in their correct places. So when I open a file, it tries to open another one. Radiohead - Creep.mp3 will open and it will actually be a bit from another song, or even code from a jpg. Some files seem to be all right, but others have seemed to have had their position taken by others. Anyone knows of something really powerful that can help me solve this?

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  • Array "tree" creation from db table

    - by Tural Teyyuboglu
    Trying to create array tree for db driven navigation. Getting following errur: array_key_exists() expects exactly 2 parameters, 1 given on line if (!array_key_exists($tree[$parent]['children'][$id])) Function looks like that $tree = array(); $sql = "SELECT id, parent, name FROM menu WHERE parent ... etc.... "; $results = mysql_query($sql) or die(mysql_error()); while(list($id, $parent, $name) = mysql_fetch_assoc($results)) { $tree[$id] = array('name' => $name, 'children' => array(), 'parent' => $parent); if (!array_key_exists($tree[$parent]['children'][$id])) { $tree[$parent]['children'][$id] = $id; } } Db structure How can I fix that? Whats wrong in this function?

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  • PeopleSoft and PeopleTools at Oracle OpenWorld 2012

    - by PeopleTools Strategy
    From Jeff Robbins PeopleTools 8.52 Gregory Sawyer October 12.00 Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Times New Roman","serif";} Oracle Open World is once again just around the corner.  This is a huge event for Oracle with thousands of individual sessions that cover all sorts of topics.  Here’s a link to a note from Paco Aubrejuan about PeopleSoft’s plans for this year’s conference: [link: http://www.oracle.com/us/industries/utilities/pfst-oow12-letter-1841052.pdf] Each year, PeopleTools sessions prove to be among the highest rated and best attended sessions of the conference. Once again we’ve put together a broad program of sessions and a great Hands on Lab, so be sure to use the Open World Schedule Builder to pre-register for the sessions you think will be of greatest value to you: [link: https://www.oracle.com/webapps/token/scheduler] Highlights of our program include: · Customer success with PeopleTools 8.52 · Great new features of the upcoming PeopleTools 8.53 · PeopleSoft’s new mobile solutions · Innovative technologies for your PeopleSoft system: Integration, User Experience, Lifecycle Management and more We’re excited about all that we have planned and look forward to seeing you there.  Stop by the DEMOGrounds to ask questions, see new features or just say hello. See you all there Jeff

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  • Most efficient Implementation a Tree in C++

    - by Topo
    I need to write a tree where each element may have any number of child elements, and because of this each branch of the tree may have any length. The tree is only going to receive elements at first and then it is going to use exclusively for iterating though it's branches in no specific order. The tree will have several million elements and must be fast but also memory efficient. My plan makes a node class to store the elements and the pointers to its children. When the tree is fully constructed, it would be transformed it to an array or something faster and if possible, loaded to the processor's cache. Construction and the search on the tree are two different problems. Can I focus on how to solve each problem on the best way individually? The construction of has to be as fast as possible but it can use memory as it pleases. Then the transformation into a format that give us speed when iterating the tree's branches. This should preferably be an array to avoid going back and forth from RAM to cache in each element of the tree. So the real question is which is the structure to implement a tree to maximize insert speed, how can I transform it to a structure that gives me the best speed and memory?

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  • Counting leaf nodes in hierarchical tree

    - by timn
    This code fills a tree with values based their depths. But when traversing the tree, I cannot manage to determine the actual number of children. node-cnt is always 0. I've already tried node-parent-cnt but that gives me lots of warnings in Valgrind. Anyway, is the tree type I've chosen even appropriate for my purpose? #include <string.h> #include <stdio.h> #include <stdlib.h> #ifndef NULL #define NULL ((void *) 0) #endif // ---- typedef struct _Tree_Node { // data ptr void *p; // number of nodes int cnt; struct _Tree_Node *nodes; // parent nodes struct _Tree_Node *parent; } Tree_Node; typedef struct { Tree_Node root; } Tree; void Tree_Init(Tree *this) { this->root.p = NULL; this->root.cnt = 0; this->root.nodes = NULL; this->root.parent = NULL; } Tree_Node* Tree_AddNode(Tree_Node *node) { if (node->cnt == 0) { node->nodes = malloc(sizeof(Tree_Node)); } else { node->nodes = realloc( node->nodes, (node->cnt + 1) * sizeof(Tree_Node) ); } Tree_Node *res = &node->nodes[node->cnt]; res->p = NULL; res->cnt = 0; res->nodes = NULL; res->parent = node; node->cnt++; return res; } // ---- void handleNode(Tree_Node *node, int depth) { int j = depth; printf("\n"); while (j--) { printf(" "); } printf("depth=%d ", depth); if (node->p == NULL) { goto out; } printf("value=%s cnt=%d", node->p, node->cnt); out: for (int i = 0; i < node->cnt; i++) { handleNode(&node->nodes[i], depth + 1); } } Tree tree; int curdepth; Tree_Node *curnode; void add(int depth, char *s) { printf("%s: depth (%d) > curdepth (%d): %d\n", s, depth, curdepth, depth > curdepth); if (depth > curdepth) { curnode = Tree_AddNode(curnode); Tree_Node *node = Tree_AddNode(curnode); node->p = malloc(strlen(s)); memcpy(node->p, s, strlen(s)); curdepth++; } else { while (curdepth - depth > 0) { if (curnode->parent == NULL) { printf("Illegal nesting\n"); return; } curnode = curnode->parent; curdepth--; } Tree_Node *node = Tree_AddNode(curnode); node->p = malloc(strlen(s)); memcpy(node->p, s, strlen(s)); } } void main(void) { Tree_Init(&tree); curnode = &tree.root; curdepth = 0; add(0, "1"); add(1, "1.1"); add(2, "1.1.1"); add(3, "1.1.1.1"); add(4, "1.1.1.1.1"); add(2, "1.1.2"); add(0, "2"); handleNode(&tree.root, 0); }

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