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Search found 216 results on 9 pages for 'preg'.

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  • Regex to get rid of everything past the first sentence in a string in php

    - by andufo
    I need to get rid of everything after the first dot (if there is more than 1 sentence), but at the same time, cases like e.g. have to be omited. Some line e.g., when people do something. Extra content. Some line (some parenthesis). Extra content. I need to get rid of the "Extra content.". The returning value should be: Some line e.g., when people do something. Some line (some parenthesis). So far I've come with this regex taken from other threads, but it only finds the dots and split the string into an array. preg_replace('/(?<!\.)\.(?!(\s|$|\,|\w\.))/','',$text); Any ideas? Thanks.

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  • preg_replace not working for charachter \

    - by krike
    I'm trying to replace \' with ' but it won't work This is the text I want to replace from Using Twitter\'s @Anywhere Service in 6 Steps and this is the code $tutorial = "Using Twitter\'s @Anywhere Service in 6 Steps "; echo $tutorial."<br /><br />"; $tut_title = preg_replace("/\\'/", "'", $tutorial); echo $tut_title;

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  • php preg_replace, regexp

    - by Michael
    I'm trying to extract the postal codes from yell.com using php and preg_replace. I successfully extracted the postal code but only along with the address. Here is an example $URL = "http://www.yell.com/ucs/UcsSearchAction.do?scrambleSeed=17824062&keywords=shop&layout=&companyName=&location=London&searchType=advance&broaderLocation=&clarifyIndex=0&clarifyOptions=CLOTHES+SHOPS|CLOTHES+SHOPS+-+LADIES|&ooa=&M=&ssm=1&lCOption32=RES|CLOTHES+SHOPS+-+LADIES&bandedclarifyResults=1"; //get yell.com page in a string $htmlContent = $baseClass-getContent($URL); //get postal code along with the address $result2 = preg_match_all("/(.*)/", $htmlContent, $matches); print_r($matches); The above code ouputs something like Array ( [0] = Array ( [0] = 7, Royal Parade, Chislehurst, Kent BR7 6NR [1] = 55, Monmouth St, London, WC2H 9DG .... the problem that I have is that I don't know how to extract the the postal code because it doesn't have an exact number of digits (sometimes it has 6 digits and sometimes has only 5 times). Basically I should extract the lasted 2 words from each array . Thank you in advance for any help !

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  • DOM manipulation in PHP

    - by bluedaniel
    Hello everyone, Im trying to use the DOM in PHP to do a pretty specific job and Ive got no luck so far, the objective is to take a string of HTML from a Wordpress blog post (from the DB, this is a wordpress plugin). And then out of that HTML replace <div id="do_not_edit">old content</div>" with <div id="do_not_edit">new content</div>" in its place. Saving anything above and below that div in its structure. Then save the HTML back into the DB, should be simple really, I have read that a regex wouldnt be the right way to go here so Ive turned to the DOM instead. The problem is I just cant get it to work, cant extract the div or anything. Help me!! UPDATE The HTML coming out of the wordpress table looks like: Congratulations on finding us here on the world wide web, we are on a mission to create a website that will show off your culinary skills better than any other website does. <div id="do_not_edit">blah blah</div> We want this website to be fun and easy to use, we strive for simple elegance and incredible functionality.We aim to provide a 'complete package'. By this we want to create a website where people can meet, share ideas and help each other out. After several different (incorrect) workings all Ive got below is: $content = ($wpdb->get_var( "SELECT `post_content` FROM $wpdb->posts WHERE ID = {$article[post_id]}" )); $doc = new DOMDocument(); $doc->validateOnParse = true; $doc->loadHTMLFile($content); $element = $doc->getElementById('do_not_edit'); echo $element;

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  • PHP - preg_replace with multiple matches

    - by Neil
    Let's say I have a string like: $text = "<object>item_id1a2b3</object>xxx<object>item_id4c5d6</object>" I want to convert it to: %ITEM:1a2b3xxx%ITEM:4c5d6 Here's what I've got: $text = preg_replace("/<object.*item_id([a-zA-Z0-9]+).*<\/object/","%ITEM:$1",$text); This isn't quite right, as the search is greedy. Thoughts? Thanks!

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  • Using regular expressions

    - by Tom
    What is wrong with this regexp? I need it to make $name to be letter-number only. Now it doens't seem to work at all. if (!preg_match("/^[A-Za-z0-9]$/",$name)) { $e[]="name must contain only letters or numbers"; }

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  • PHP & Regular expression: keyword just occurs once

    - by lauthiamkok
    Hi, how can I make sure a certain keyword just occurs once in the input with regular expression? I think there is some mistakes in the expression below as I can repeat the same keywords, if (!preg_match('/\b(.php?){1}\b/', $cfg_path)) { $error = true; echo '<error elementid="cfg_path" message="PATH - make sure you have a \'.php?\' in the path."/>'; } I just want this to be true, form.php?category=something or form.php? but not this, form.php?.php?category=something or form.php?.php? please let me know how to fix it. thanks.

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  • Using preg_replace to replace all occurrences in php

    - by Greg-J
    Regex is absolutely my weak point and this one has me completely stumped. I am building a fairly basic search functionality and I need to be able to alter my user input based on the following pattern: Subject: %22first set%22 %22second set%22-drupal -wordpress Desired output: +"first set" +"second set" -drupal -wordpress I wish I could be more help as I normally like to at least post the solution I have so far, but on this one I'm at a loss. Any help is appreciated. Thank you.

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  • preg_replace only replaces first occurrence then skips to next line

    - by Dom
    Got a problem where preg_replace only replaces the first match it finds then jumps to the next line and skips the remaining parts on the same line that I also want to be replaced. What I do is that I read a CSS file that sometimes have multiple "url(media/pic.gif)" on a row and replace "media/pic.gif" (the file is then saved as a copy with the replaced parts). The content of the CSS file is put into the variable $resource_content: $resource_content = preg_replace('#(url\((\'|")?)(.*)((\'|")?\))#i', '${1}'.url::base(FALSE).'${3}'.'${4}', $resource_content); Does anyone know a solution for why it only replaces the first match per line?

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  • php cURL. preg_match , extract text from xhtml

    - by Michael
    I'm trying to extract the price from the bellow html page/link using php cURL and preg_match . Basically I'm expecting for this code to output 4,550 but for some reasons I get Notice: Undefined offset: 1 in C:\wamp\www\test.php on line 22 I think that the pattern is correct because if I put the html itself in a variable and escape the "" it works ! . Also if I output (echo $result;) it displays the html properly grabbed from foxtons website so I just can't figure it out why the whole thing doesn't work . I need to make this work and also I would appreciate if you would tell me why is that notice generated and why my current script doesn't work. $url = "http://www.foxtons.co.uk/search?bedrooms_from=0&property_id=727717"; $ch = curl_init($url); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch,CURLOPT_RETURNTRANSFER, 1); $result = curl_exec($ch); curl_exec($ch); curl_close($ch); $result2 = str_replace('"', '\"', $result); $tagname1= ");<\/script "; $tagname2= "<\/noscript per month<\/a"; $pattern = "/$tagname1(.*?)$tagname2/"; preg_match($pattern, $result, $matches); $prices = $matches[1]; print_r($prices); ?

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  • preg_match_all image source

    - by David
    I have the following regex expression which is to extract the source of any img tag in HTML. /(<img).*(src\s*=\s*"([a-zA-Z0-9\.;:\/\?&=\-_|\r|\n]{1,})")/isxmU However, it doesn't appear to be matching the following: <IMG SRC='http://www.mysite.com/pix/lens/mtf/CAEF8512L.gif'> How can I build it to match this as well?

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  • php: regex remove bracket in string

    - by apis17
    hi, similiar like this example, http://stackoverflow.com/questions/1336672/php-remove-brackets-contents-from-a-string i have no idea to replace $str = '(ABC)some text' into $str = 'ABC'; currently use $str = preg_replace('/(.)/','',$str); but not works. how to fix this?

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  • How to use backreferences in PHP

    - by Slinky
    I want to add a character to the end of each file extension found in a body of text using preg_replace(). Here is some sample text: $string='http://www.mysite.com/expert/images/imageone.jpghttp://www.mysite.com/expert/images/imagetwo.jpg'; This search & replace works fine in TextWrangler, appending a semi colon to file extensions: (\.(jpg|gif|html?|php|tiff?|pdf|png)) \1; Translated to PHP, however does not work, having no effect; no errors. preg_replace("/(\.(jpg|gif|html|php|tif|tiff|pdf|htm|png))/","\\1;",$string);

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  • Preg_match class name from PHP file

    - by talentedmrjones
    I have a script that recursively scans a directory pulling out class names from php files, and storing those classes names in an array. This is working nicely even through the rather large Zend Framework library folders. The issue is that classes that extend other classes are not being included in the array. Here is my current preg_match: if (preg_match("/class\s*(\w*)\s*\{/i",strip_comments(file_get_contents($file)),$matches)) $classes[] = $matches[1]; I know that the last \s* is not right; there should be something there that can catch "{" or " extends Some_Other_Class {" .

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  • PHP preg_replace - Very quick question

    - by RC
    Masters of regular expressions, please help! See this string: $string = "http://www.url.com/?fieldA=123&fieldB=456&fieldC=789"; Assuming "fieldB" always has a positive non-decimal numerical value (but not necessarily three digits long), what preg_replace command do I need to remove it completely, such that the string will then read: $string = "http://www.url.com/?fieldA=123&fieldC=789"; Thanks!

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  • preg_match_all problems

    - by NeoNmaN
    i use preg_match_all and need to grab all a href="" tags in my code, but i not relly understand how to its work. i have this reg. exp. ( /(<([\w]+)[^])(.?)(<\/\2)/ ) its take all html codes, i need only all a href tags. i hobe i can get help :)

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  • Complex pattern replacement using PHP preg_replace function ignoring quoted strings

    - by Saiful
    Consider the following string: this is a STRING WHERE some keywords ARE available. 'i need TO format the KEYWORDS from the STRING' In the above string keywords are STRING and WHERE Now i need to get an output as follows: this is a <b>STRING</b> <b>WHERE</b> some keywords ARE available. 'i need TO format the KEYWORDS from the STRING' So that the html output will be like: this is a STRING WHERE some keywords ARE available. 'i need TO format the KEYWORDS from the STRING' Note that the keywords within a quoted ('...') string will be ignored. in the above example i ignored the STRING keyword within the quoted string. Please give a modified version of the following PHP script so that I can have my desired result as above : $patterns = array('/STRING/','/WHERE/'); $replaces = array('<b>STRING</b>', '<b>WHERE</b>'); $string = "this is a STRING WHERE some keywords ARE available. 'i need TO format the KEYWORDS from the STRING'"; preg_replace($patterns, $replaces, $string);

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  • Regular Expression Sanitize (PHP)

    - by atif089
    Hello, I would like to sanitize a string in to a URL so this is what I basically need. Everything must be removed except alphanumeric characters and spaces and dashed. Spaces should be converter into dashes. Eg. This, is the URL! must return this-is-the-url Thanks

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  • PHP regex to search across multiple lines

    - by Gaz
    I'm using preg_* in PHP to search for the pattern <!-- %{data=THIS GETS MATCHED}% --> and pull out the matched text. The pattern for this is: preg_match('#<!-- %{' . $knownString . '\s*=\s*(.*?)}% -->#', ...) What I would like it to do is search across multiple lines for the string. For example: <!-- %{data= THIS GETS MATCHED AND RETURNED }% --> How can I edit my current pattern to have this search ability?

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  • Regex to replace 'li' with 'option' without losing class and id attributes

    - by Earthman Web
    I am looking for a solution using preg_replace or similar method to change: <li id="id1" class="authorlist" /> <li id="id2" class="authorlist" /> <li id="id3" class="authorlist" /> to <option id="id1" class="authorlist" /> <option id="id2" class="authorlist" /> <option id="id3" class="authorlist" /> I think I have the pattern correct, but not sure how to do the replacement part... Here is the (wordpress) php code: $string = wp_list_authors( $args ); //returns list as noted above $pattern = '<li ([^>]*)'; $replacement = '?????'; echo preg_replace($pattern, $replacement, $string); Suggestions, please?

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  • Correct syntax for matching a string inside a variable against an array

    - by Jamex
    Hi, I have a variable, $var, that contains a string of characters, this is a dynamic variable that contains the values from inputs. $var could be 'abc', or $var could be 'blu', I want to match the string inside variable against an array, and return all the matches. $array = array("blue", "red", "green"); What is the correct syntax for writing the code in php, my rough code is below $match = preg_grep($var, $array); (incorrect syntax of course) I tried to put quotes and escape slashes, but so far no luck. Any suggestion? TIA

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  • PHP preg_match: a pattern which satisfies all MySQL field names (including 'table.field' formations)

    - by gsquare567
    i need a pattern which satisfies mysql field names, but also with the option of having a table name before it examples: mytable.myfield myfield my4732894__7289FiEld here's what i tried: $pattern = "/^[a-zA-Z0-9_]*?[\.[a-zA-Z0-9_]]?$/"; this worked for what i needed before, which was just the field name: $pattern = "/^[a-zA-Z0-9_]*$/"; any ideas why my addition isnt working? maybe i'm making up regex, so i'll explain what i added... the first '?' is to say that it isn't greedy, ie. it will stop if the next part, namely "[.[a-zA-Z0-9_]]?" is satisfied. now, that second part is just the same as the first except it is optional (hence the '?' at the end) and it starts with a period (hence the '[.' and ']' wrapping my old clause. and obviously, the "^" and "$" rep the beginning and end of the string so... any ideas? (also, i'm a tad confused as to why i need to put in those "/"s in the begining/end anyways, so if you could tell me why it's required, that'd be awesome) thanks a lot! (and thanks for reading this all if you actually did... it's quite a ramble)

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