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  • Creating problem-sets with answers in Latex

    - by ARV
    Hello everyone. I want to typeset Mathematical problem-sets in Latex. My requirements are as follows: When I type them in, I want the questions and the answers to be next to each other in the source-code so that fixing errors, etc. can be done easily. However, when the document is typeset, I want the answers to appear in a separate "Answers" section just the way they do in textbooks. Does anyone know of a way to do this? Many thanks in advance!

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  • Loop through different sets of unique permutations

    - by user558610
    Hi I'm having a hard time getting started to layout code for this problem. I have a fixed amount of random numbers, in this case 8 numbers. R[] = { 1, 2, 3, 4, 5, 6, 7, 8 }; That are going to be placed in 3 sets of numbers, with the only constraint that each set contain minimum one value, and each value can only be used once. For example: R1[] = { 1, 4 } R2[] = { 2, 8, 5, 6 } R3[] = { 7, 4 } I need to loop through all possible combinations of a set R1, R2, R3. Order is not important, so if the above example happened, I don't need R1[] = { 4, 1 } R2[] = { 2, 8, 5, 6 } R3[] = { 7, 4 } NOR R1[] = { 2, 8, 5, 6 } R2[] = { 7, 4 } R3[] = { 1, 4 } What is a good method?

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  • Working with sets of rows in (My)SQL and comparing values

    - by Pep.
    Hello, I am trying to figure out the SQL for doing some relatively simple operations on sets of records in a table but I am stuck. Consider a table with multiple rows per item, all identified by a common key. For example: serial model color XX1 A blue XX2 A blue XX3 A green XX5 B red XX6 B blue XX1 B blue What I would for example want to do is: Assuming that all model A rows must have the same color, find the rows which dont. (for example, XX3 is green). Assuming that a given serial number can only point to a single type of model, find out the rows which that does not occur (for example XX1 points both to A and B) These are all simple logically things to do. To abstract it, I want to know how to group things by using a single key (or combination of keys) and then compare the values of those records. Should I use a join on the same table? should i use some sort of array or similar? thanks for your help

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  • Get all sets of list in prolog

    - by garm0nboz1a
    How can I generate all the possible sets of the elements of a list with current length? get_set(X, [1,2,3]). X = [1,1,1], X = [1,1,2], X = [1,1,3], X = [1,2,1], X = [1,2,2], X = [1,2,3], X = [1,3,1], X = [1,3,2], X = [1,3,3], ..... X = [3,3,2], X = [3,3,3]. UPD: there is good answer given by Sharky. But maybe it's not the best. Here is another: get_set(X,L) :- get_set(X,L,L). get_set([],_). get_set([X|Xs],[_|T],L) :- member(X,L), get_set(Xs,T,L).

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  • Exchange Web Services and Property Sets

    - by Sam
    I need to retrieve calendar information by invoking the Exchange Web Service in BPOS. I'm using a CalendarView with a PropertySet to retrieve as little data as possible. However, property sets seems to be limited. I need the EmailAddress of the one who made the calendar appointment so I thought I could use the AppointmentSchema.Organizer in the PropertySet. When fetching a whole Appointment I can get the e-mail through appt.Organizer.EmailAddress. But with the code below the Organizer.EmailAddress is always null. I've enabled the trace and checked it and only the Organizer.Name property is sent, nothing else. Does anyone have a solution on how to get the EmailAddress when using a PropertySet? CalendarView view = new CalendarView(dtFrom, dtTo); view.PropertySet = new PropertySet(ItemSchema.Subject); view.PropertySet.Add(ItemSchema.Id); view.PropertySet.Add(AppointmentSchema.Start); view.PropertySet.Add(AppointmentSchema.End); view.PropertySet.Add(AppointmentSchema.Organizer); // This should contain EmailAddress but it doesn't Mailbox mailbox = new Mailbox("[email protected]"); FolderId id = new FolderId(WellKnownFolderName.Calendar, mailbox); CalendarFolder folder = CalendarFolder.Bind(service, id); FindItemsResults findResults = folder.FindAppointments(view);

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  • jQuery tabs - multiple sets on on page

    - by Jonny Wood
    This is kind of a follow on from a previous question I posted but I've not been able to get it to work.. I'm trying to use multiple sets of tabs (jQuery) on one page. This is the code I had for one set of tabs which works great: $('div.tabs div.tab').hide(); $('div.tabs div:first').show(); $('div.tabs ul.htabs li:first a').addClass('current'); $('div.tabs ul.htabs li a').click(function(){ $('div.tabs ul.htabs li a').removeClass('current'); $(this).addClass('current'); var currentTab = $(this).attr('href'); $('div.tabs div.tab').hide(); $(currentTab).show(); return false; }); To use more than one set on the page I assigned #id's to each tab-set and tried to impliment this with: $.each(['#tabs-1', '#tabs-2', '#tabs-3' ], function(id) { $(id + 'div.tab').hide(); $(id + 'div:first').show(); $(id + 'ul.htabs li:first a').addClass('current'); $(id + 'ul.htabs li a').click(function(){ $(id + 'ul.htabs li a').removeClass('current'); $(this).addClass('current'); var currentTab = $(this).attr('href'); $(id + 'div.tab').hide(); $(currentTab).show(); return false; }); }); Obviously I'm doing something wrong here but as a jQuery newcomer I'm stumped!

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  • Turning on multiple result sets in an ODBC connection to SQL Server

    - by David Griffiths
    I have an application that originally needed to connect to Sybase (via ODBC), but I've needed to add the ability to connect to SQL Server as well. As ODBC should be able to handle both, I thought I was in a good position. Unfort, SQL Server will not let me, by default, nest ODBC commands and ODBCDataReaders - it complains the connection is busy. I know that I had to specify that multiple active result sets (MARS) were allowed in similar circumstances when connecting to SQL Server via a native driver, so I thought it wouldn't be an issue. The DSN wizard has no entr y when creating a SystemDSN. Some people have provided registry hacks to get around this, but this did not work (add a MARS_Connection with a value of Yes to HKEY_LOCAL_MACHINE\SOFTWARE\ODBC\ODBC.INI\system-dsn-name). Another suggestion was to create a file-dsn, and add "MARS_Connection=YES" to that. Didn't work. Finally, a DSN-less connection string. I've tried this one (using MultipleActiveResultSets - same variable as a Sql Server connection would use), "Driver={SQL Native Client};Server=xxx.xxx.xxx.xxx;Database=someDB;Uid=u;Pwd=p;MultipleActiveResultSets=True;" and this one: "Driver={SQL Native Client};Server=192.168.75.33\\ARIA;Database=Aria;Uid=sa;Pwd=service;MARS_Connection=YES;" I have checked the various connection-string sites - they all suggest what I've already tried.

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  • Combining two data sets and plotting in matlab

    - by bautrey
    I am doing experiments with different operational amplifier circuits and I need to plot my measured results onto a graph. I have two data sets: freq1 = [.1 .2 .5 .7 1 3 4 6 10 20 35 45 60 75 90 100]; %kHz Vo1 = [1.2 1.6 1.2 2 2 2.4 14.8 20.4 26.4 30.4 53.6 68.8 90 114 140 152]; %mV V1 = 19.6; Acm = Vo1/(1000*V1); And: freq2 = [.1 .5 1 30 60 70 85 100]; %kHz Vo1 = [3.96 3.96 3.96 3.84 3.86 3.88 3.88 3.88]; %V V1 = .96; Ad = Vo1/(2*V1); (I would show my plots but apparently I need more reps for that) I need to plot the equation, CMRR vs freq: CMRR = 20*log10(abs(Ad/Acm)); The size of Ad and Acm are different and the frequency points do not match up, but the boundaries of both of these is the same, 100Hz to 100kHz (x-axis). On the line of CMRR, Matlab says that Ad and Acm matrix dimensions do not agree. How I think I would solve this is using freq1 as the x-axis for CMRR and then taking approximated points from Ad according to the value on freq1. Or I could do function approximations of Ad and Acm and then do the divide operator on those. I do not know how I would code up this two ideas. Any other ideas would helpful, especially simpler ones. Thanks

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  • How to separate sets of numbers onto separate lines

    - by Fred
    About the script: The script below will create 300 sets of random characters. What is presently happening, is that it creates them but shows them all on one line, in one big chunk. With all the searching and testing I've done to try and achieve this, I have had no success. I would like to know which code and where to put it, so that each SET (300) of 15 characters long, will show and be saved to file. Here is my script: <?php function GetID($x){ $characters = array_merge(range('A','Z'),range('a','z'),range(2,9)); shuffle($characters); for($x=0;$x<=299;$x++){ } for (; strlen($ReqID)<$x;){ $ReqID .= $characters[mt_rand(0, count($characters))]; } return $ReqID; } $ReqID .= GetID(5); $ReqID .= "-"; $ReqID .= GetID(5); $ReqID .= "-"; $ReqID .= GetID(5); echo $ReqID; $fh = fopen("file.txt","a+"); fwrite($fh, ("$ReqID")."\n"); fclose($fh); ?>

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  • What is the best way to add and order to Doctrine Nested Set Trees?

    - by murze
    What is the best way to add a sense of order in Doctrine Nested Sets? The documention contains several examples of how to get al the childeren of a specific node $category->getNode()->getSiblings() But how can I for example: change the position of the fourth sibling to the second position get only the second sibling add a sibling between the second and third child etc... Do I have to manually add and ordercolumn to the model to do these operations?

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  • python set difference

    - by user1311992
    I'm doing a set difference operation in Python: from sets import Set from mongokit import ObjectId x = [ObjectId("4f7aba8a43f1e51544000006"), ObjectId("4f7abaa043f1e51544000007"), ObjectId("4f7ac02543f1e51a44000001")] y = [ObjectId("4f7acde943f1e51fb6000003")] print list(Set(x).difference(Set(y))) I'm getting: [ObjectId('4f7abaa043f1e51544000007'), ObjectId('4f7ac02543f1e51a44000001'), ObjectId('4f7aba8a43f1e51544000006')] I need to get the first element for next operation which is important. How can I retain the list x in original format?

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  • Unable to get set intersection to work

    - by chavanak
    Sorry for the double post, I will update this question if I can't get things to work :) I am trying to compare two files. I will list the two file content: File 1 File 2 "d.complex.1" "d.complex.1" 1 4 5 5 48 47 65 21 d.complex.10 d.complex.10 46 6 21 46 109 121 192 192 TI am trying to compare the contents of the two file but not in a trivial way. I will explain what I want with an example. If you observe the file content I have typed above, the d.complex.1 of file_1 has "5" similar to d.complex.1 in file_2; the same d.complex.1 in file_1 has nothing similar to d.complex.10 in file_2. What I am trying to do is just to print out those d.complex. which has nothing in similar with the other d.complex. Consider the d.complex. as a heading if you want. But all I am trying is compare the numbers below each d.complex. and if nothing matches, I want that particular d.complex. from both files to be printed. If even one number is present in both d.complex. of both files, I want it to be rejected. My Code: The method I chose to achieve this was to use sets and then do a difference. Code I wrote was: first_complex=open( "file1.txt", "r" ) first_complex_lines=first_complex.readlines() first_complex_lines=map( string.strip, first_complex_lines ) first_complex.close() second_complex=open( "file2.txt", "r" ) second_complex_lines=second_complex.readlines() second_complex_lines=map( string.strip, second_complex_lines ) second_complex.close() list_1=[] list_2=[] res_1=[] for line in first_complex_lines: if line.startswith( "d.complex" ): res_1.append( [] ) res_1[-1].append( line ) res_2=[] for line in second_complex_lines: if line.startswith( "d.complex" ): res_2.append( [] ) res_2[-1].append( line ) h=len( res_1 ) k=len( res_2 ) for i in res_1: for j in res_2: print i[0] print j[0] target_set=set ( i ) target_set_1=set( j ) for s in target_set: if s not in target_set_1: if s[0] != "d": print s The above code is giving an output like this (just an example): d.complex.1.dssp d.complex.1.dssp 1 48 65 d.complex.1.dssp d.complex.10.dssp 46 21 109 What I would like to have is: d.complex.1 d.complex.1 (name from file2) d.complex.1 d.complex.10 (name from file2) I am sorry for confusing you guys, but this is all that is required. I am so new to python so my concept above might be flawed. Also I have never used sets before :(. Can someone give me a hand here?

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  • Can I have a set containing identical elements?

    - by Roman
    It is convenient for me to use a set. I like how I can "add" ("remove") an element to (from) the set. It is also convenient to check if a given element is in the set. The only problem, I found out that I cannot add a new element to a set if the set has already such an element. Is it possible to have "sets" which can contain several identical elements.

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  • Finding minimum cut-sets between bounded subgraphs

    - by Tore
    If a game map is partitioned into subgraphs, how to minimize edges between subgraphs? I have a problem, Im trying to make A* searches through a grid based game like pacman or sokoban, but i need to find "enclosures". What do i mean by enclosures? subgraphs with as few cut edges as possible given a maximum size and minimum size for number of vertices for each subgraph that act as a soft constraints. Alternatively you could say i am looking to find bridges between subgraphs, but its generally the same problem. Given a game that looks like this, what i want to do is find enclosures so that i can properly find entrances to them and thus get a good heuristic for reaching vertices inside these enclosures. So what i want is to find these colored regions on any given map. My Motivation The reason for me bothering to do this and not just staying content with the performance of a simple manhattan distance heuristic is that an enclosure heuristic can give more optimal results and i would not have to actually do the A* to get some proper distance calculations and also for later adding competitive blocking of opponents within these enclosures when playing sokoban type games. Also the enclosure heuristic can be used for a minimax approach to finding goal vertices more properly. A possible solution to the problem is the Kernighan-Lin algorithm: function Kernighan-Lin(G(V,E)): determine a balanced initial partition of the nodes into sets A and B do A1 := A; B1 := B compute D values for all a in A1 and b in B1 for (i := 1 to |V|/2) find a[i] from A1 and b[i] from B1, such that g[i] = D[a[i]] + D[b[i]] - 2*c[a][b] is maximal move a[i] to B1 and b[i] to A1 remove a[i] and b[i] from further consideration in this pass update D values for the elements of A1 = A1 / a[i] and B1 = B1 / b[i] end for find k which maximizes g_max, the sum of g[1],...,g[k] if (g_max > 0) then Exchange a[1],a[2],...,a[k] with b[1],b[2],...,b[k] until (g_max <= 0) return G(V,E) My problem with this algorithm is its runtime at O(n^2 * lg(n)), i am thinking of limiting the nodes in A1 and B1 to the border of each subgraph to reduce the amount of work done. I also dont understand the c[a][b] cost in the algorithm, if a and b do not have an edge between them is the cost assumed to be 0 or infinity, or should i create an edge based on some heuristic. Do you know what c[a][b] is supposed to be when there is no edge between a and b? Do you think my problem is suitable to use a multi level problem? Why or why not? Do you have a good idea for how to reduce the work done with the kernighan-lin algorithm for my problem?

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  • How to page multiple data sets in ASP.NET MVC

    - by REA_ANDREW
    On a single view I will have three sets of paged data. Which means for each model I will have The Objects The Page Index The Page Size My initial thought was for example: public class PagedModel<T> where T:class { public IList<T> Objects { get; set; } public int ModelPageIndex { get; set; } public int ModelPageSize { get; set; } } Then having a model which is to be supplied to the action as for example: public class TypesViewModel { public PagedModel<ObjectA> Types1 { get; set; } public PagedModel<ObjectB> Typed2 { get; set; } public PagedModel<ObjectC> Types3 { get; set; } } So if I then for example have the Index view inherit from the type: System.Web.Mvc.ViewPage<uk.co.andrewrea.forum.Web.Models.TypesViewModel> Now my initial aciton method for the index is simply: public ActionResult Index() { var forDisplayPurposes = new TypesViewModel(); return View(forDisplayPurposes); } If I then want to page, it is here where I am struggling to decide which action to take. Lets say that I select the next page of the Types2 PageModel. What should the action look like for this in order to return the new view showing the second page of the Types2 PageModel I was thinking possibly to duplicate the action but use it with POST [AcceptVerbs(HttpVerbs.Post)] public ActionResult Index(TypesViewModel model) { return View(model); } Is this a good way to approach it. I understand there is always Session, but I was just wondering how such a thing is achieved currently out there. If any best methods have been mutually accepted and things. So simply, one page with multiple paged models. How to persist the data for each using a wrapper model. Which way should you pass in the model and which way should you page the data, i.e. Form Post Lastly, I have seen the routes take this into account i.e. {controller}/{action}/{id}/{pageindex}/{pagesize} but this only accounts for one model and I do not really wwant to repeat the pagesize and pageindex values for the number of models I have inside the wrapper model. Thanks for your time!! Andrew

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  • prolog sets problem, stack overflow

    - by garm0nboz1a
    Hi. I'm gonna show some code and ask, what could be optimized and where am I sucked? sublist([], []). sublist([H | Tail1], [H | Tail2]) :- sublist(Tail1, Tail2). sublist(H, [_ | Tail]) :- sublist(H, Tail). less(X, X, _). less(X, Z, RelationList) :- member([X,Z], RelationList). less(X, Z, RelationList) :- member([X,Y], RelationList), less(Y, Z, RelationList), \+less(Z, X, RelationList). lessList(X, LessList, RelationList) :- findall(Y, less(X, Y, RelationList), List), list_to_set(List, L), sort(L, LessList), !. list_mltpl(List1, List2, List) :- findall(X, ( member(X, List1), member(X, List2)), List). chain([_], _). chain([H,T | Tail], RelationList) :- less(H, T, RelationList), chain([T|Tail], RelationList), !. have_inf(X1, X2, RelationList) :- lessList(X1, X1_cone, RelationList), lessList(X2, X2_cone, RelationList), list_mltpl(X1_cone, X2_cone, Cone), chain(Cone, RelationList), !. relations(List, E) :- findall([X1,X2], (member(X1, E), member(X2, E), X1 =\= X2), Relations), sublist(List, Relations). semilattice(List, E) :- forall( (member(X1, E), member(X2, E), X1 < X2), have_inf(X1, X2, List) ). main(E) :- relations(X, E), semilattice(X, E). I'm trying to model all possible graph sets of N elements. Predicate relations(List, E) connects list of possible graphs(List) and input set E. Then I'm describing semilattice predicate to check relations' List for some properties. So, what I have. 1) semilattice/2 is working fast and clear ?- semilattice([[1,3],[2,4],[3,5],[4,5]],[1,2,3,4,5]). true. ?- semilattice([[1,3],[1,4],[2,3],[2,4],[3,5],[4,5]],[1,2,3,4,5]). false. 2) relations/2 is working not well ?- findall(X, relations(X,[1,2,3,4]), List), length(List, Len), writeln(Len),fail. 4096 false. ?- findall(X, relations(X,[1,2,3,4,5]), List), length(List, Len), writeln(Len),fail. ERROR: Out of global stack ^ Exception: (11) setup_call_catcher_cleanup('$bags':'$new_findall_bag'(17852886), '$bags':fa_loop(_G263, user:relations(_G263, [1, 2, 3, 4|...]), 17852886, _G268, []), _G835, '$bags':'$destroy_findall_bag'(17852886)) ? abort % Execution Aborted 3) Mix of them to finding all possible semilattice does not work at all. ?- main([1,2]). ERROR: Out of local stack ^ Exception: (15) setup_call_catcher_cleanup('$bags':'$new_findall_bag'(17852886), '$bags':fa_loop(_G41, user:less(1, _G41, [[1, 2], [2, 1]]), 17852886, _G52, []), _G4767764, '$bags':'$destroy_findall_bag'(17852886)) ?

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  • jquery: find common elements in 2 sets of divs

    - by tsiger
    For a markup like this: <div id="set1"> <div id="100">a div</div> <div id="101">another div</div> <div id="102">another div 2</div> <div id="120">same div</div> </div> <div id="set2"> <div id="105">a different div> <div id="101">another div</div> <div id="110">more divs</div> <div id="120">same div</div> </div> As you can see both #set1 and #set2 contain 2 divs with the same id (101, 120). Is it possible somehow with jQuery to find the common elements and add a class to the divs in #set1 that have the same id with divs in #set2? In other words after the script run the above code would look like this: <div id="set1"> <div id="100">a div</div> <div id="101" class="added">another div</div> <div id="102">another div 2</div> <div id="120" class="added">same div</div> </div> <div id="set2"> <div id="105">a different div> <div id="101">another div</div> <div id="110">more divs</div> <div id="120">same div</div> </div> EDIT playing around with it i did something but i am not sure it can go anywhere. I created an array with the ids in both sets and in Firebug i can see an array with the values var arrEl = []; $('#set1 div, #set2 div').each( function(index) { var id = $(this).attr('id'); arrEl.push(id); //maybe somehow check the array for the values that appear twice, and add the class to the //matching divs? });

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  • being able to solve google code jam problem sets

    - by JPro
    This is not a homework question, but rather my intention to know if this is what it takes to learn programming. I keep loggin into TopCoder not to actually participate but to get the basic understand of how the problems are solved. But to my knowledge I don't understand what the problem is and how to translate the problem into an algorithm that can solve it. Just now I happen to look at ACM ICPC 2010 World Finals which is being held in china. The teams were given problem sets and one of them is this: Given at most 100 points on a plan with distinct x-coordinates, find the shortest cycle that passes through each point exactly once, goes from the leftmost point always to the right until it reaches the rightmost point, then goes always to the left until it gets back to the leftmost point. Additionally, two points are given such that the the path from left to right contains the first point, and the path from right to left contains the second point. This seems to be a very simple DP: after processing the last k points, and with the first path ending in point a and the second path ending in point b, what is the smallest total length to achieve that? This is O(n^2) states, transitions in O(n). We deal with the two special points by forcing the first path to contain the first one, and the second path contain the second one. Now I have no idea what I am supposed to solve after reading the problem set. and there's an other one from google code jam: Problem In a big, square room there are two point light sources: one is red and the other is green. There are also n circular pillars. Light travels in straight lines and is absorbed by walls and pillars. The pillars therefore cast shadows: they do not let light through. There are places in the room where no light reaches (black), where only one of the two light sources reaches (red or green), and places where both lights reach (yellow). Compute the total area of each of the four colors in the room. Do not include the area of the pillars. Input * One line containing the number of test cases, T. Each test case contains, in order: * One line containing the coordinates x, y of the red light source. * One line containing the coordinates x, y of the green light source. * One line containing the number of pillars n. * n lines describing the pillars. Each contains 3 numbers x, y, r. The pillar is a disk with the center (x, y) and radius r. The room is the square described by 0 = x, y = 100. Pillars, room walls and light sources are all disjoint, they do not overlap or touch. Output For each test case, output: Case #X: black area red area green area yellow area Is it required that people who program should be should be able to solve these type of problems? I would apprecite if anyone can help me interpret the google code jam problem set as I wish to participate in this years Code Jam to see if I can do anthing or not. Thanks.

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  • Improving the running time of Breadth First Search and Adjacency List creation

    - by user45957
    We are given an array of integers where all elements are between 0-9. have to start from the 1st position and reach end in minimum no of moves such that we can from an index i move 1 position back and forward i.e i-1 and i+1 and jump to any index having the same value as index i. Time Limit : 1 second Max input size : 100000 I have tried to solve this problem use a single source shortest path approach using Breadth First Search and though BFS itself is O(V+E) and runs in time the adjacency list creation takes O(n2) time and therefore overall complexity becomes O(n2). is there any way i can decrease the time complexity of adjacency list creation? or is there a better and more efficient way of solving the problem? int main(){ vector<int> v; string str; vector<int> sets[10]; cin>>str; int in; for(int i=0;i<str.length();i++){ in=str[i]-'0'; v.push_back(in); sets[in].push_back(i); } int n=v.size(); if(n==1){ cout<<"0\n"; return 0; } if(v[0]==v[n-1]){ cout<<"1\n"; return 0; } vector<int> adj[100001]; for(int i=0;i<10;i++){ for(int j=0;j<sets[i].size();j++){ if(sets[i][j]>0) adj[sets[i][j]].push_back(sets[i][j]-1); if(sets[i][j]<n-1) adj[sets[i][j]].push_back(sets[i][j]+1); for(int k=j+1;k<sets[i].size();k++){ if(abs(sets[i][j]-sets[i][k])!=1){ adj[sets[i][j]].push_back(sets[i][k]); adj[sets[i][k]].push_back(sets[i][j]); } } } } queue<int> q; q.push(0); int dist[100001]; bool visited[100001]={false}; dist[0]=0; visited[0]=true; int c=0; while(!q.empty()){ int dq=q.front(); q.pop(); c++; for(int i=0;i<adj[dq].size();i++){ if(visited[adj[dq][i]]==false){ dist[adj[dq][i]]=dist[dq]+1; visited[adj[dq][i]]=true; q.push(adj[dq][i]); } } } cout<<dist[n-1]<<"\n"; return 0; }

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  • Scheme: Detecting duplicate elements in a list

    - by Kyle Krull
    Does R6RS or Chez Scheme v7.9.4 have a library function to check if a list contains duplicate elements? Alternatively, do either have any built in functionality for sets (which dis-allow duplicate elements)? So far, I've only been able to find an example here. The problem with that is that it doesn't appear to actually be part of the Chez Scheme library. Although I could write my own version of this, I'd much rather use a well known, tested, and maintained library function - especially given how basic an operation this is. So a simple "use these built-in functions" or a "no built-in library implements this" will suffice. Thanks!

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  • Update ancestors in a nested set?

    - by Travis
    I am using nested sets to represent a tree in mysql, like so: Tree ID title lft rgt Given the ID of a node in the tree, what is the easiest / best way to UPDATE that node as well as all of it's ancestors? For example, let's say that the node ID (36) is 4 levels deep in the tree. I would like to update its title, as well as every parent node's title, all the way to the root, to the word "fish". (Should be four updates in all.) Thanks for your help!

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  • Why doesn't java.util.Set have get(int index)?

    - by Marty Pitt
    I'm sure there's a good reason, but could someone please explain why the java.util.Set interface lacks get(int Index), or any similar get() method? It seems that sets are great for putting things into, but I can't find an elegant way of retrieving a single item from it. If I know I want the first item, I can use set.iterator().next(), but otherwise it seems I have to cast to an Array to retrieve an item at a specific index? What are the appropriate ways of retrieving data from a set? (other than using an iterator) I'm sure the fact that it's excluded from the API means there's a good reason for not doing this -- could someone please enlighten me? EDIT: Some extremely great answers here, and a few saying "more context". The specific scneario was a dbUnit test, where I could reasonalby assert that the returned set from a query had only 1 item, and I was trying to access that item. However, the question is more valid without the scenario, as it remains more focussed : What's the difference between set & list. Thanks to all for the fantastic answers below.

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  • How do you convert a parent-child (adjacency) table to a nested set using PHP and MySQL?

    - by mrbinky3000
    I've spent the last few hours trying to find the solution to this question online. I've found plenty of examples on how to convert from nested set to adjacency... but few that go the other way around. The examples I have found either don't work or use MySQL procedures. Unfortunately, I can't use procedures for this project. I need a pure PHP solution. I have a table that uses the adjacency model below: id parent_id category 1 0 ROOT_NODE 2 1 Books 3 1 CD's 4 1 Magazines 5 2 Books/Hardcover 6 2 Books/Large Format 7 4 Magazines/Vintage And I would like to convert it to a Nested Set table below: id left right category 1 1 14 Root Node 2 2 7 Books 3 3 4 Books/Hardcover 4 5 6 Books/Large Format 5 8 9 CD's 6 10 13 Magazines 7 11 12 Magazines/Vintage Here is an image of what I need: I have a function, based on the pseudo code from this forum post (http://www.sitepoint.com/forums/showthread.php?t=320444) but it doesn't work. I get multiple rows that have the same value for left. This should not happen. <?php /** -- -- Table structure for table `adjacent_table` -- CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'ROOT'), (2, 1, 'Books'), (3, 1, 'CD''s'), (4, 1, 'Magazines'), (5, 2, 'Hard Cover'), (6, 2, 'Large Format'), (7, 4, 'Vintage'); -- -- Table structure for table `nested_table` -- CREATE TABLE IF NOT EXISTS `nested_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `lft` int(11) DEFAULT NULL, `rgt` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; */ mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); adjacent_to_nested(0); /** * adjacent_to_nested * * Reads a "adjacent model" table and converts it to a "Nested Set" table. * @param integer $i_id Should be the id of the "root node" in the adjacent table; * @param integer $i_left Should only be used on recursive calls. Holds the current value for lft */ function adjacent_to_nested($i_id, $i_left = 0) { // the right value of this node is the left value + 1 $i_right = $i_left + 1; // get all children of this node $a_children = get_source_children($i_id); foreach ($a_children as $a) { // recursive execution of this function for each child of this node // $i_right is the current right value, which is incremented by the // import_from_dc_link_category method $i_right = adjacent_to_nested($a['id'], $i_right); // insert stuff into the our new "Nested Sets" table $s_query = " INSERT INTO `nested_table` (`id`, `lft`, `rgt`, `category`) VALUES( NULL, '".$i_left."', '".$i_right."', '".mysql_real_escape_string($a['category'])."' ) "; if (!mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } echo "<p>$s_query</p>\n"; // get the newly created row id $i_new_nested_id = mysql_insert_id(); } return $i_right + 1; } /** * get_source_children * * Examines the "adjacent" table and finds all the immediate children of a node * @param integer $i_id The unique id for a node in the adjacent_table table * @return array Returns an array of results or an empty array if no results. */ function get_source_children($i_id) { $a_return = array(); $s_query = "SELECT * FROM `adjacent_table` WHERE `father_id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } if (mysql_num_rows($i_result) > 0) { while($a = mysql_fetch_assoc($i_result)) { $a_return[] = $a; } } return $a_return; } ?> This is the output of the above script. INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '5', 'Hard Cover' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '7', 'Large Format' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '8', 'Books' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '10', 'CD\'s' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '10', '13', 'Vintage' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '14', 'Magazines' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '0', '15', 'ROOT' ) As you can see, there are multiple rows sharing the lft value of "1" same goes for "2" In a nested-set, the values for left and right must be unique. Here is an example of how to manually number the left and right ID's in a nested set: UPDATE - PROBLEM SOLVED First off, I had mistakenly believed that the source table (the one in adjacent-lists format) needed to be altered to include a source node. This is not the case. Secondly, I found a cached page on BING (of all places) with a class that does the trick. I've altered it for PHP5 and converted the original author's mysql related bits to basic PHP. He was using some DB class. You can convert them to your own database abstraction class later if you want. Obviously, if your "source table" has other columns that you want to move to the nested set table, you will have to adjust the write method in the class below. Hopefully this will save someone else from the same problems in the future. <?php /** -- -- Table structure for table `adjacent_table` -- DROP TABLE IF EXISTS `adjacent_table`; CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'Books'), (2, 0, 'CD''s'), (3, 0, 'Magazines'), (4, 1, 'Hard Cover'), (5, 1, 'Large Format'), (6, 3, 'Vintage'); -- -- Table structure for table `nested_table` -- DROP TABLE IF EXISTS `nested_table`; CREATE TABLE IF NOT EXISTS `nested_table` ( `lft` int(11) NOT NULL DEFAULT '0', `rgt` int(11) DEFAULT NULL, `id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`lft`), UNIQUE KEY `id` (`id`), UNIQUE KEY `rgt` (`rgt`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; */ /** * @class tree_transformer * @author Paul Houle, Matthew Toledo * @created 2008-11-04 * @url http://gen5.info/q/2008/11/04/nested-sets-php-verb-objects-and-noun-objects/ */ class tree_transformer { private $i_count; private $a_link; public function __construct($a_link) { if(!is_array($a_link)) throw new Exception("First parameter should be an array. Instead, it was type '".gettype($a_link)."'"); $this->i_count = 1; $this->a_link= $a_link; } public function traverse($i_id) { $i_lft = $this->i_count; $this->i_count++; $a_kid = $this->get_children($i_id); if ($a_kid) { foreach($a_kid as $a_child) { $this->traverse($a_child); } } $i_rgt=$this->i_count; $this->i_count++; $this->write($i_lft,$i_rgt,$i_id); } private function get_children($i_id) { return $this->a_link[$i_id]; } private function write($i_lft,$i_rgt,$i_id) { // fetch the source column $s_query = "SELECT * FROM `adjacent_table` WHERE `id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } $a_source = array(); if (mysql_num_rows($i_result)) { $a_source = mysql_fetch_assoc($i_result); } // root node? label it unless already labeled in source table if (1 == $i_lft && empty($a_source['category'])) { $a_source['category'] = 'ROOT'; } // insert into the new nested tree table // use mysql_real_escape_string because one value "CD's" has a single ' $s_query = " INSERT INTO `nested_table` (`id`,`lft`,`rgt`,`category`) VALUES ( '".$i_id."', '".$i_lft."', '".$i_rgt."', '".mysql_real_escape_string($a_source['category'])."' ) "; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } else { // success: provide feedback echo "<p>$s_query</p>\n"; } } } mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); // build a complete copy of the adjacency table in ram $s_query = "SELECT `id`,`father_id` FROM `adjacent_table`"; $i_result = mysql_query($s_query); $a_rows = array(); while ($a_rows[] = mysql_fetch_assoc($i_result)); $a_link = array(); foreach($a_rows as $a_row) { $i_father_id = $a_row['father_id']; $i_child_id = $a_row['id']; if (!array_key_exists($i_father_id,$a_link)) { $a_link[$i_father_id]=array(); } $a_link[$i_father_id][]=$i_child_id; } $o_tree_transformer = new tree_transformer($a_link); $o_tree_transformer->traverse(0); ?>

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  • JPQL IN clause: Java-Arrays (or Lists, Sets...)?

    - by Bernd Haug
    I would like to load all objects that have a textual tag set to any of a small but arbitrary number of values from our database. The logical way to go about this in SQL would be to build an "IN" clause. JPQL allows for IN, but it seems to require me to specify every single parameter to IN directly (as in, "in (:in1, :in2, :in3)"). Is there some way to specify an array, or a list (or some other container) that should be unrolled to the values of an IN clause?

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  • Side effect of calling ValidatorEnable method: sets focus to control associated with validator

    - by Velika2
    When I called this function to enable a validator from client javascript: `ValidatorEnable(document.getElementById('<%=valPassportOtherText.ClientID%>'), true); //enable` validation control The side effect was that focus was shifted to the txtSpecifyOccupation textbox (the control associated with the Validation control) <asp:TextBox ID="txtSpecifyOccupation" runat="server" AutoCompleteType="Disabled" CssClass="DefaultTextBox DefaultWidth" MaxLength="24" Rows="2"></asp:TextBox> <asp:RequiredFieldValidator ID="valSpecifyOccupation" runat="server" ControlToValidate="txtSpecifyOccupation" ErrorMessage="1.14b Please specify your &lt;b&gt;Occupation&lt;/b&gt;" SetFocusOnError="True">&nbsp;Required</asp:RequiredFieldValidator> Perhaps there is a way to enable the (required) validator without having it simultaneously perform the validation (at least until the user has tabbed off of it?)

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