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  • What's the best/most efficent way to create a semi-intelligent AI for a tic tac toe game?

    - by Link
    basically I am attempting to make a a efficient/smallish C game of Tic-Tac-Toe. I have implemented everything other then the AI for the computer so far. my squares are basically structs in an array with an assigned value based on the square. For example s[1].value = 1; therefore it's a x, and then a value of 3 would be a o. My question is whats the best way to create a semi-decent game playing AI for my tic-tac-toe game? I don't really want to use minimax, since It's not what I need. So how do I avoid a a lot of if statments and make it more efficient. Here is the rest of my code: #include <stdio.h> #include <stdlib.h> #include <string.h> #include <time.h> struct state{ // defined int state; // 0 is tie, 1 is user loss, 2 is user win, 3 is ongoing game int moves; }; struct square{ // one square of the board int value; // 1 is x, 3 is o char sign; // no space used }; struct square s[9]; //set up the struct struct state gamestate = {0,0}; //nothing void setUpGame(){ // setup the game int i = 0; for(i = 0; i < 9; i++){ s[i].value = 0; s[i].sign = ' '; } gamestate.moves=0; printf("\nHi user! You're \"x\"! I'm \"o\"! Good Luck :)\n"); } void displayBoard(){// displays the game board printf("\n %c | %c | %c\n", s[6].sign, s[7].sign, s[8].sign); printf("-----------\n"); printf(" %c | %c | %c\n", s[3].sign, s[4].sign, s[5].sign); printf("-----------\n"); printf(" %c | %c | %c\n\n", s[0].sign, s[1].sign, s[2].sign); } void getHumanMove(){ // get move from human int i; while(1){ printf(">>:"); char line[255]; // input the move to play fgets(line, sizeof(line), stdin); while(sscanf(line, "%d", &i) != 1) { //1 match of defined specifier on input line printf("Sorry, that's not a valid move!\n"); fgets(line, sizeof(line), stdin); } if(s[i-1].value != 0){printf("Sorry, That moves already been taken!\n\n");continue;} break; } s[i-1].value = 1; s[i-1].sign = 'x'; gamestate.moves++; } int sum(int x, int y, int z){return(x*y*z);} void getCompMove(){ // get the move from the computer } void checkWinner(){ // check the winner int i; for(i = 6; i < 9; i++){ // check cols if((sum(s[i].value,s[i-3].value,s[i-6].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[i].value,s[i-3].value,s[i-6].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } for(i = 0; i < 7; i+=3){ // check rows if((sum(s[i].value,s[i+1].value,s[i+2].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[i].value,s[i+1].value,s[i+2].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } if((sum(s[0].value,s[4].value,s[8].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[0].value,s[4].value,s[8].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} if((sum(s[2].value,s[4].value,s[6].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[2].value,s[4].value,s[6].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } void playGame(){ // start playing the game gamestate.state = 3; //set-up the gamestate srand(time(NULL)); int temp = (rand()%2) + 1; if(temp == 2){ // if two comp goes first temp = (rand()%2) + 1; if(temp == 2){ s[4].value = 2; s[4].sign = 'o'; gamestate.moves++; }else{ s[2].value = 2; s[2].sign = 'o'; gamestate.moves++; } } displayBoard(); while(gamestate.state == 3){ if(gamestate.moves<10); getHumanMove(); if(gamestate.moves<10); getCompMove(); checkWinner(); if(gamestate.state == 3 && gamestate.moves==9){ printf("The game is a tie :p\n"); break; } displayBoard(); } } int main(int argc, const char *argv[]){ printf("Welcome to Tic Tac Toe\nby The Elite Noob\nEnter 1-9 To play a move, standard numpad\n1 is bottom-left, 9 is top-right\n"); while(1){ // while game is being played printf("\nPress 1 to play a new game, or any other number to exit;\n>>:"); char line[255]; // input whether or not to play the game fgets(line, sizeof(line), stdin); int choice; // user's choice about playing or not while(sscanf(line, "%d", &choice) != 1) { //1 match of defined specifier on input line printf("Sorry, that's not a valid option!\n"); fgets(line, sizeof(line), stdin); } if(choice == 1){ setUpGame(); // set's up the game playGame(); // Play a Game }else {break;} // exit the application } printf("\nThank's For playing!\nHave a good Day!\n"); return 0; }

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  • using ghostscript in server mode to convert pdfs to pngs

    - by emh
    while i am able to convert a specific page of a PDF to a PNG like so: gs -dSAFER -dBATCH -dNOPAUSE -sDEVICE=png16m -dGraphicsAlphaBits=4 -sOutputFile=gymnastics-20.png -dFirstPage=20 -dLastPage=20 gymnastics.pdf i am wondering if i can somehow use ghostscript's JOBSERVER mode to process several conversions without having to incur the cost of starting up ghostscript each time. from: http://pages.cs.wisc.edu/~ghost/doc/svn/Use.htm -dJOBSERVER Define \004 (^D) to start a new encapsulated job used for compatibility with Adobe PS Interpreters that ordinarily run under a job server. The -dNOOUTERSAVE switch is ignored if -dJOBSERVER is specified since job servers always execute the input PostScript under a save level, although the exitserver operator can be used to escape from the encapsulated job and execute as if the -dNOOUTERSAVE was specified. This also requires that the input be from stdin, otherwise an error will result (Error: /invalidrestore in --restore--). Example usage is: gs ... -dJOBSERVER - < inputfile.ps -or- cat inputfile.ps | gs ... -dJOBSERVER - Note: The ^D does not result in an end-of-file action on stdin as it may on some PostScript printers that rely on TBCP (Tagged Binary Communication Protocol) to cause an out-of-band ^D to signal EOF in a stream input data. This means that direct file actions on stdin such as flushfile and closefile will affect processing of data beyond the ^D in the stream. the idea is to run ghostscript in-process. the script would receive a request for a particular page of a pdf and would use ghostscript to generate the specified image. i'd rather not start up a new ghostscript process every time.

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  • How can I modify/merge Jinja2 dictionaries?

    - by Brian M. Hunt
    I have a Jinja2 dictionary and I want a single expression that modifies it - either by changing its content, or merging with another dictionary. >>> import jinja2 >>> e = jinja2.Environment() Modify a dict: Fails. >>> e.from_string("{{ x[4]=5 }}").render({'x':{1:2,2:3}}) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "jinja2/environment.py", line 743, in from_string return cls.from_code(self, self.compile(source), globals, None) File "jinja2/environment.py", line 469, in compile self.handle_exception(exc_info, source_hint=source) File "<unknown>", line 1, in template jinja2.exceptions.TemplateSyntaxError: expected token 'end of print statement', got '=' Two-stage update: Prints superfluous "None". >>> e.from_string("{{ x.update({4:5}) }} {{ x }}").render({'x':{1:2,2:3}}) u'None {1: 2, 2: 3, 4: 5}' >>> e.from_string("{{ dict(x.items()+ {3:4}.items()) }}").render({'x':{1:2,2:3}}) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "jinja2/environment.py", line 868, in render return self.environment.handle_exception(exc_info, True) File "<template>", line 1, in top-level template code TypeError: <lambda>() takes exactly 0 arguments (1 given) Use dict(x,**y): Fails. >>> e.from_string("{{ dict((3,4), **x) }}").render({'x':{1:2,2:3}}) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "jinja2/environment.py", line 868, in render return self.environment.handle_exception(exc_info, True) File "<template>", line 1, in top-level template code TypeError: call() keywords must be strings So how does one modify the dictionary x in Jinja2 by changing an attribute or merging with another dictionary? This question is similar to: How can I merge two Python dictionaries as a single expression? -- insofar as Jinja2 and Python are analogous.

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  • Endless problems with a very simple python subprocess.Popen task

    - by Thomas
    I'd like python to send around a half-million integers in the range 0-255 each to an executable written in C++. This executable will then respond with a few thousand integers. Each on one line. This seems like it should be very simple to do with subprocess but i've had endless troubles. Right now im testing with code: // main() u32 num; std::cin >> num; u8* data = new u8[num]; for (u32 i = 0; i < num; ++i) std::cin >> data[i]; // test output / spit it back out for (u32 i = 0; i < num; ++i) std::cout << data[i] << std::endl; return 0; Building an array of strings ("data"), each like "255\n", in python and then using: output = proc.communicate("".join(data))[0] ...doesn't work (says stdin is closed, maybe too much at one time). Neither has using proc.stdin and proc.stdout worked. This should be so very simple, but I'm getting constant exceptions, and/or no output data returned to me. My Popen is currently: proc = Popen('aux/test_cpp_program', stdin=PIPE, stdout=PIPE, bufsize=1) Advise me before I pull my hair out. ;)

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  • Yet another Python Windows CMD mklink problem ... can't get it to work!

    - by Felix Dombek
    OK I have just posted another question which outlined my program but the specific problem was different. Now, my program just stops working without any message whatsoever. I'd be grateful if someone could help me here. I want to create symlinks for each file in a directory structure, all in one large flat folder, and have the following code by now: # loop over directory structure: # for all items in current directory, # if item is directory, recurse into it; # else it's a file, then create a symlink for it def makelinks(folder, targetfolder, cmdprocess = None): if not cmdprocess: cmdprocess = subprocess.Popen("cmd", stdin = subprocess.PIPE, stdout = subprocess.PIPE, stderr = subprocess.PIPE) print(folder) for name in os.listdir(folder): fullname = os.path.join(folder, name) if os.path.isdir(fullname): makelinks(fullname, targetfolder, cmdprocess) else: makelink(fullname, targetfolder, cmdprocess) #for a given file, create one symlink in the target folder def makelink(fullname, targetfolder, cmdprocess): linkname = os.path.join(targetfolder, re.sub(r"[\/\\\:\*\?\"\<\>\|]", "-", fullname)) if not os.path.exists(linkname): try: os.remove(linkname) print("Invalid symlink removed:", linkname) except: pass if not os.path.exists(linkname): cmdprocess.stdin.write("mklink " + linkname + " " + fullname + "\r\n") So this is a top-down recursion where first the folder name is printed, then the subdirectories are processed. If I run this now over some folder, the whole thing just stops after 10 or so symbolic links. Here is the output: D:\Musik\neu D:\Musik\neu\# Electronic D:\Musik\neu\# Electronic\# tag & reencode D:\Musik\neu\# Electronic\# tag & reencode\ChillOutMix D:\Musik\neu\# Electronic\# tag & reencode\Unknown D&B D:\Musik\neu\# Electronic\# tag & reencode\Unknown D&B 2 The program still seems to run but no new output is generated. It created 9 symlinks for some files in the # tag & reencode and the first three files in the ChillOutMix folder. The cmd.exe Window is still open and empty, and shows in its title bar that it is currently processing the mklink command for the third file in ChillOutMix. I tried to insert a time.sleep(2) after each cmdprocess.stdin.write in case Python is just too fast for the cmd process, but it doesn't help. Does anyone know what the problem might be?

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  • Python access an object byref / Need tagging

    - by Aaron C. de Bruyn
    I need to suck data from stdin and create a object. The incoming data is between 5 and 10 lines long. Each line has a process number and either an IP address or a hash. For example: pid=123 ip=192.168.0.1 - some data pid=123 hash=ABCDEF0123 - more data hash=ABCDEF123 - More data ip=192.168.0.1 - even more data I need to put this data into a class like: class MyData(): pid = None hash = None ip = None lines = [] I need to be able to look up the object by IP, HASH, or PID. The tough part is that there are multiple streams of data intermixed coming from stdin. (There could be hundreds or thousands of processes writing data at the same time.) I have regular expressions pulling out the PID, IP, and HASH that I need, but how can I access the object by any of those values? My thought was to do something like this: myarray = {} for each line in sys.stdin.readlines(): if pid and ip: #If we can get a PID out of the line myarray[pid] = MyData().pid = pid #Create a new MyData object, assign the PID, and stick it in myarray accessible by PID. myarray[pid].ip = ip #Add the IP address to the new object myarray[pid].lines.append(data) #Append the data myarray[ip] = myarray[pid] #Take the object by PID and create a key from the IP. <snip>do something similar for pid and hash, hash and ip, etc...</snip> This gives my an array with two keys (a PID and an IP) and they both point to the same object. But on the next iteration of the loop, if I find (for example) an IP and HASH and do: myarray[hash] = myarray[ip] The following is False: myarray[hash] == myarray[ip] Hopefully that was clear. I hate to admit that waaay back in the VB days, I remember being able handle objects byref instead of byval. Is there something similar in Python? Or am I just approaching this wrong?

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  • Windows cmd encoding change causes Python crash.

    - by Alex
    First I chage Windows CMD encoding to utf-8 and run Python interpreter: chcp 65001 python Then I try to print a unicode sting inside it and when i do this Python crashes in a peculiar way (I just get a cmd prompt in the same window). >>> import sys >>> print u'ëèæîð'.encode(sys.stdin.encoding) Any ideas why it happens and how to make it work? UPD: sys.stdin.encoding returns 'cp65001' UPD2: It just came to me that the issue might be connected with the fact that utf-8 uses multi-byte character set (kcwu made a good point on that). I tried running the whole example with 'windows-1250' and got 'ëeaî?'. Windows-1250 uses single-character set so it worked for those characters it understands. However I still have no idea how to make 'utf-8' work here. UPD3: Oh, I found out it is a known Python bug. I guess what happens is that Python copies the cmd encoding as 'cp65001 to sys.stdin.encoding and tries to apply it to all the input. Since it fails to understand 'cp65001' it crushes on any input that contains non-ascii characters.

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  • Popen is no able to process a command that runs in shell

    - by IceMan85
    Hello everybody, I have already read the previous questions posted on the same argument but I really haven't figured it out yet. I am trying to run a command that works without issues from the command line : xyz@klm:~/python-remoteWorkspace/PyLogParser/src:18:43ush -o PPP -p PRD -n log 'pwd' 6:43PM PPP:prd:lgsprdppp:/ama/log/PRD/ppp but when I do the same in python I always get errors : stringa = Popen(["ush -o PPP -p PRD -n log 'pwd'"], stdout=PIPE, stdin=PIPE).communicate()[0] Here the error. Traceback (most recent call last): File "getStatData.py", line 134, in retrieveListOfFiles(infoToRetList) File "getStatData.py", line 120, in retrieveListOfFiles stringa = Popen(["ush -o PPP -p PRD -n log 'pwd'"], stdout=PIPE, stdin=PIPE).communicate()[0] File "/opt/python-2.6-64/lib/python2.6/subprocess.py", line 595, in init errread, errwrite) File "/opt/python-2.6-64/lib/python2.6/subprocess.py", line 1092, in _execute_child raise child_exception OSError: [Errno 2] No such file or directory I've tried also different solutions like stringa = Popen(["ush", "-o", "PPP", "-p" "PRD", "-n", "log", '"pwd"'], stdout=PIPE, stdin=PIPE).communicate()[0] but nothing seems to work. I have also tried to put the absolute path to ush but nothing... Can somebody please explain me what am I doing wrong ? Thanks in advance, AM.

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  • SSH with Perl using file handles, not Net::SSH

    - by jorge
    Before I ask the question: I can not use cpan module Net::SSH, I want to but can not, no amount of begging will change this fact I need to be able to open an SSH connection, keep it open, and read from it's stdout and write to its stdin. My approach thus far has been to open it in a pipe, but I have not been able to advance past this, it dies straight away. That's what I have in mind, I understand this causes a fork to occur. I've written code accordingly for this fork (or so I think). Below is a skeleton of what I want, I just need the system to work. #!/usr/bin/perl use warnings; $| = 1; $pid = open (SSH,"| ssh user\@host"); if(defined($pid)){ if(!$pid){ #child while(<>){ print; } }else{ select SSH; $| = 1; select STDIN; #parent while(<>){ print SSH $_; while(<SSH>){ print; } } close(SSH); } } I know, from what it looks like, I'm trying to recreate "system('ssh user@host')," that is not my end goal, but knowing how to do that would bring me much closer to the end goal. Basically, I need a file handle to an open ssh connection where I can read from it the output and write to it input (not necessarily straight from my program's STDIN, anything I want, variables, yada yada) This includes password input. I know about key pairs, part of the end goal involves making key pairs, but the connection needs to happen regardless of their existence, and if they do not exist it's part of my plan to make them exist.

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  • User input in Perl with IO::Socket

    - by David
    I am trying to make a perl program which allows a user to input the host and the port number of a foreign host to connect to using IO::Socket. It allows me to run the program and input a host and a port but it never connects and says "Could not connect to [host] at c:\users\USER\Documents\code\perl\sql.pl line 18, line 2." What am i doing wrong with this code shown below? And also, how can i have input validation on my host, which can either be a host name or an ip address? Thanks a bunch! Code Below use IO::Socket print "Host to connect to: "; chomp ($host = <STDIN>); print "Port to connect with: "; chomp ($port = <STDIN>); while(($port > 65535) || ($port <= 0)){ print "Port to connect with [Port > 0 < 65535] : "; chomp ($port = <STDIN>); } print "\nConnecting to host $host on port $port\n"; $socket = new IO::Socket::INET ( LocalHost => '$host', LocalPort => '$port', Proto => 'tcp', Listen => 5, Reuse => 1 ); die "Could not connect to $host";

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  • For each loop not reading in the last item

    - by Gandalf StormCrow
    I'm trying to read in a multi line string then split it then print it .. here is the string : 1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T 11X21b1X 4X1b1X When I split the string with ! I get this without the last line string : 1T1b5T 1T1b5T1T2b1T1b2T 1T2b1T1b2T1T1b1T2b2T 1T1b1T2b2T1T3b1T1b1T 1T3b1T1b1T3T3b1T 3T3b1T1T3b1T1b1T 1T3b1T1b1T5T1*1T 5T1*1T11X21b1X 11X21b1X Here is my code : import java.io.BufferedInputStream; import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner stdin = new Scanner(new BufferedInputStream(System.in)); while (stdin.hasNext()) { for (String line : stdin.next().split("!")) { System.out.println(line); for (int i = 0; i < line.length(); i++) { System.out.print(line.charAt(i)); } } } } } Where did I make the mistake, why is not reading in the last line? After I read in all lines properly I should go trough each line if I encounter number I should print the next char the n times the number I just read, but that is long way ahead first I need help with this. Thank you

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  • Stream buffering issue

    - by Kolyunya
    The mod_rewrite documentation states that it is a strict requirement to disable in(out)put buffering in a rewrite program. Keeping that in mind I've written a simple program (I do know that it lacks the EOF check but this is not an issue and it saves one condition check per loop): #include <stdio.h> #include <stdlib.h> int main ( void ) { setvbuf(stdin,NULL,_IOLBF,4200); setvbuf(stdout,NULL,_IOLBF,4200); int character; while ( 42 ) { character = getchar(); if ( character == '-' ) { character = '_'; } putchar(character); } return 42 - 42; } After making some measurements I was shocked - it was over 9,000 times slower than the demo Perl script provided by the documentation: #!/usr/bin/perl $| = 1; # Turn off I/O buffering while (<STDIN>) { s/-/_/g; # Replace dashes with underscores print $_; } Now I have two related questions: Question 1. I believe that the streams may be line buffered since Apache sends a new line after each path. Am I correct? Switching my program to setvbuf(stdin,NULL,_IOLBF,4200); setvbuf(stdout,NULL,_IOLBF,4200); makes it twice as fast as Perl one. This should not hit Apache's performance, should it? Question 2. How can one write a program in C which will use unbuffered streams (like Perl one) and will perform as fast as Perl one?

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  • vagrant up command very slow on OS X Lion

    - by Andy Hume
    When I run vagrant up to provision a new VM on Lion it takes an extremely long time, during which the entire Mac is very laggy and unresponsive. The output is as follows, the key point being the "notice: Finished catalog run in 754.28 seconds" > vagrant up [default] Importing base box 'lucid64'... [default] The guest additions on this VM do not match the install version of VirtualBox! This may cause things such as forwarded ports, shared folders, and more to not work properly. If any of those things fail on this machine, please update the guest additions and repackage the box. Guest Additions Version: 4.1.0 VirtualBox Version: 4.1.6 [default] Matching MAC address for NAT networking... [default] Clearing any previously set forwarded ports... [default] Forwarding ports... [default] -- ssh: 22 => 2222 (adapter 1) [default] -- web: 80 => 4567 (adapter 1) [default] Creating shared folders metadata... [default] Running any VM customizations... [default] Booting VM... [default] Waiting for VM to boot. This can take a few minutes. [default] VM booted and ready for use! [default] Mounting shared folders... [default] -- v-root: /vagrant [default] -- v-data: /var/www [default] -- manifests: /tmp/vagrant-puppet/manifests [default] Running provisioner: Vagrant::Provisioners::Puppet... [default] Running Puppet with lucid64.pp... [default] stdin: is not a tty [default] notice: /Stage[main]/Lucid64/Exec[apt-update]/returns: executed successfully [default] [default] notice: /Stage[main]/Lucid64/Package[apache2]/ensure: ensure changed 'purged' to 'present' [default] [default] notice: /Stage[main]/Lucid64/File[/etc/motd]/ensure: defined content as '{md5}a25e31ba9b8489da9cd5751c447a1741' [default] [default] notice: Finished catalog run in 754.28 seconds [default] [default] err: /File[/var/lib/puppet/rrd]/ensure: change from absent to directory failed: Could not find group puppet [default] [default] err: Could not send report: Got 1 failure(s) while initializing: change from absent to directory failed: Could not find group puppet [default] [default] Running provisioner: Vagrant::Provisioners::Puppet... [default] Running Puppet with lucid64.pp... [default] stdin: is not a tty [default] notice: /Stage[main]/Lucid64/Exec[apt-update]/returns: executed successfully [default] [default] notice: Finished catalog run in 2.05 seconds [default] [default] err: /File[/var/lib/puppet/rrd]: Could not evaluate: Could not find group puppet [default] [default] err: Could not send report: Got 1 failure(s) while initializing: Could not evaluate: Could not find group puppet [default] [default] Running provisioner: Vagrant::Provisioners::Puppet... [default] Running Puppet with lucid64.pp... [default] stdin: is not a tty [default] notice: /Stage[main]/Lucid64/Exec[apt-update]/returns: executed successfully [default] [default] notice: Finished catalog run in 1.36 seconds [default] [default] err: /File[/var/lib/puppet/rrd]: Could not evaluate: Could not find group puppet [default] [default] err: Could not send report: Got 1 failure(s) while initializing: Could not evaluate: Could not find group puppet [default] >

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  • Running command transparently over ssh

    - by jnsg
    By transparently I mean forwarding of: stdin, stdout and stderr standard signals (SIGHUP or SIGINT would be great for a start) As an example, consider these invocations of a (pointless) local and remote command: $ `cat - > /dev/null; sleep 10` < /local/file $ ssh user@host "cat - > /dev/null; sleep 10" < /local/file I can interrupt the first one with ^C just fine. But if I try this during the second one it only affects ssh, leaving the command running on the remote server if cat has already finished. I know about launching sshwith -t, but this way I can't send data via stdin. Is this possible with ssh alone at all?

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  • xauth error with ssh X Forwarding

    - by bdk
    From my (Debain) Desktop machine, I am trying to ssh into a Debian Server with ssh -X remote-ip After logging into the remote host, I get: /usr/bin/X11/xauth: creating new authority file /root/.Xauthority /usr/bin/X11/xauth: (stdin):1: bad display name "unix:10.0" in "remove" command /usr/bin/X11/xauth: (stdin):2: bad display name "unix:10.0" in "add" command And the X Forwarding doesn't work. From my Desktop I can ssh -X into other Debian servers and it works fine. I found a lot of threads discussing similar issues on google, but they all seem to fade out without a solution, and the simple things suggested there like exporting DISPLAY or setting xhost + don't seem to make a difference.

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  • Implementing a multilanguage AI contest platform

    - by Alejandro Piad
    This is a followup to this question. To sum: I'm implementing an AI contest site, where each user may submit several AI implementations for different games. Think about Google AI Challenge but instead of just having a big event once a year, I would like it more on a league fashion, with all virtual players playing with each other every some close period of time. I want to support as many programming languages as possible. I've seen that contest sites (like codeforces) ask you to submit a source code and interact through stdin and stdout. The first question is: what is the best way of supporting multiple languages? As I see it, I can either ask people to upload some binary/script, and interact either through stdin/*stdout*, or sockets, or the file system; or ask people to submit source code, and wrap it with whatever is necessary for the interaction. I would like to skip the need to compile the code by myself (in the server, I mean), but I am willing to do it if its the "best" choice. I need to comunicate virtual players with each other, or even better, with some intermediary arbiter. The second question is regarding security. If I'm going to be running user code in my server, I want to ensure strict security conditions, like no file system access, no networking, etc. Otherwise it would be a safe heaven for hackers. I will be implementing the engine/arbiter in .NET. I would like to support at least C#, C++, Java and Python for the user's implementations. I'm willing to write interfaces for each of these languages to simplify the user interaction with the system. Thanks in advance.

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  • Netcat I/O enhancements

    - by user13277689
    When Netcat integrated into OpenSolaris it was already clear that there will be couple of enhancements needed. The biggest set of the changes made after Solaris 11 Express was released brings various I/O enhancements to netcat shipped with Solaris 11. Also, since Solaris 11, the netcat package is installed by default in all distribution forms (live CD, text install, ...). Now, let's take a look at the new functionality: /usr/bin/netcat alternative program name (symlink) -b bufsize I/O buffer size -E use exclusive bind for the listening socket -e program program to execute -F no network close upon EOF on stdin -i timeout extension of timeout specification -L timeout linger on close timeout -l -p port addr previously not allowed usage -m byte_count Quit after receiving byte_count bytes -N file pattern for UDP scanning -I bufsize size of input socket buffer -O bufsize size of output socket buffer -R redir_spec port redirection addr/port[/{tcp,udp}] syntax of redir_spec -Z bypass zone boundaries -q timeout timeout after EOF on stdin Obviously, the Swiss army knife of networking tools just got a bit thicker. While by themselves the options are pretty self explanatory, their combination together with other options, context of use or boundary values of option arguments make it possible to construct small but powerful tools. For example: the port redirector allows to convert TCP stream to UDP datagrams. the buffer size specification makes it possible to send one byte TCP segments or to produce IP fragments easily. the socket linger option can be used to produce TCP RST segments by setting the timeout to 0 execute option makes it possible to simulate TCP/UDP servers or clients with shell/python/Perl/whatever script etc. If you find some other helpful ways use please share via comments. Manual page nc(1) contains more details, along with examples on how to use some of these new options.

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  • Recovering data from /

    - by Abhijit Gavas
    I accidentally installed Ubuntu to one of my data drives from Windows. The drive was a NTFS drive and contained about 80 GB of important data. The size of the drive is 110 GB. Its new file system is ext4. In an attempt to recover the data, I downloaded foremost and tried the following commands: foremost -i / -o /media/281C8DB01C8D7998/Recovery/ -T -v foremost -i /dev/sda7 -o /media/281C8DB01C8D7998/Recovery/ -T -v (sda7 is the drive in question.) It appears that with either command, foremost gets stuck reading some file. Here is the console output: abhi@abi-PC:/dev$ foremost -i /dev/sda7 -o /media/281C8DB01C8D7998/Recovery/ -T -v Foremost version 1.5.7 by Jesse Kornblum, Kris Kendall, and Nick Mikus Audit File Foremost started at Fri Sep 28 20:58:00 2012 Invocation: foremost -i /dev/sda7 -o /media/281C8DB01C8D7998/Recovery/ -T -v Output directory: /media/281C8DB01C8D7998/Recovery_Fri_Sep_28_20_58_00_2012 Configuration file: /etc/foremost.conf Processing: stdin |------------------------------------------------------------------ File: stdin Start: Fri Sep 28 20:58:00 2012 Length: Unknown Num Name (bs=512) Size File Offset Comment Killed As you can see I have to kill it from system monitor. This approach does not seem to be working. What else could I try to recover the files? Please help. The files are very important and I will be devastated if I cannot recover them.

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  • how can i find my usb2rs232 driver

    - by mefmef
    i have a device that is correctly connected to my PC . but i could not see it in /dev . what does it means? is it because of not installing my drive? $ /dev ls before connecting my device: agpgart mei sda1 tty28 tty59 ttyS30 autofs mem sda2 tty29 tty6 ttyS31 block net sda5 tty3 tty60 ttyS4 bsg network_latency sda6 tty30 tty61 ttyS5 btrfs-control network_throughput serial tty31 tty62 ttyS6 bus null sg0 tty32 tty63 ttyS7 char oldmem shm tty33 tty7 ttyS8 console parport0 snapshot tty34 tty8 ttyS9 core port snd tty35 tty9 ttyUSB0 cpu ppp stderr tty36 ttyprintk uinput cpu_dma_latency psaux stdin tty37 ttyS0 urandom disk ptmx stdout tty38 ttyS1 usbmon0 dri pts tty tty39 ttyS10 usbmon1 ecryptfs ram0 tty0 tty4 ttyS11 usbmon2 fb0 ram1 tty1 tty40 ttyS12 vcs fd ram10 tty10 tty41 ttyS13 vcs1 full ram11 tty11 tty42 ttyS14 vcs2 fuse ram12 tty12 tty43 ttyS15 vcs3 hidraw0 ram13 tty13 tty44 ttyS16 vcs4 hpet ram14 tty14 tty45 ttyS17 vcs5 input ram15 tty15 tty46 ttyS18 vcs6 kmsg ram2 tty16 tty47 ttyS19 vcsa log ram3 tty17 tty48 ttyS2 vcsa1 loop0 ram4 tty18 tty49 ttyS20 vcsa2 loop1 ram5 tty19 tty5 ttyS21 vcsa3 loop2 ram6 tty2 tty50 ttyS22 vcsa4 loop3 ram7 tty20 tty51 ttyS23 vcsa5 loop4 ram8 tty21 tty52 ttyS24 vcsa6 loop5 ram9 tty22 tty53 ttyS25 vga_arbiter loop6 random tty23 tty54 ttyS26 zero loop7 rfkill tty24 tty55 ttyS27 lp0 rtc tty25 tty56 ttyS28 mapper rtc0 tty26 tty57 ttyS29 mcelog sda tty27 tty58 ttyS3 $ /dev ls after connecting my device: agpgart mei sda1 tty28 tty59 ttyS30 autofs mem sda2 tty29 tty6 ttyS31 block net sda5 tty3 tty60 ttyS4 bsg network_latency sda6 tty30 tty61 ttyS5 btrfs-control network_throughput serial tty31 tty62 ttyS6 bus null sg0 tty32 tty63 ttyS7 char oldmem shm tty33 tty7 ttyS8 console parport0 snapshot tty34 tty8 ttyS9 core port snd tty35 tty9 ttyUSB0 cpu ppp stderr tty36 ttyprintk ttyUSB1 cpu_dma_latency psaux stdin tty37 ttyS0 uinput disk ptmx stdout tty38 ttyS1 urandom dri pts tty tty39 ttyS10 usbmon0 ecryptfs ram0 tty0 tty4 ttyS11 usbmon1 fb0 ram1 tty1 tty40 ttyS12 usbmon2 fd ram10 tty10 tty41 ttyS13 vcs full ram11 tty11 tty42 ttyS14 vcs1 fuse ram12 tty12 tty43 ttyS15 vcs2 hidraw0 ram13 tty13 tty44 ttyS16 vcs3 hpet ram14 tty14 tty45 ttyS17 vcs4 input ram15 tty15 tty46 ttyS18 vcs5 kmsg ram2 tty16 tty47 ttyS19 vcs6 log ram3 tty17 tty48 ttyS2 vcsa loop0 ram4 tty18 tty49 ttyS20 vcsa1 loop1 ram5 tty19 tty5 ttyS21 vcsa2 loop2 ram6 tty2 tty50 ttyS22 vcsa3 loop3 ram7 tty20 tty51 ttyS23 vcsa4 loop4 ram8 tty21 tty52 ttyS24 vcsa5 loop5 ram9 tty22 tty53 ttyS25 vcsa6 loop6 random tty23 tty54 ttyS26 vga_arbiter loop7 rfkill tty24 tty55 ttyS27 zero lp0 rtc tty25 tty56 ttyS28 mapper rtc0 tty26 tty57 ttyS29 mcelog sda tty27 tty58 ttyS3

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  • Run preseed commands as specific user / switching users

    - by pduersteler
    Beside the usual setup where I create a normal user foo, I want to run a few d-i preseed/late_command commands as that foo user. My initial thought was to simply call those commands with sudo, e.g: d-i preseed/late_command in-target echo "<pwd>" | sudo -Si <command>. This works for some sort of commands. However the problem is that some of the commands load up shell scripts which require to not be run with sudo. Issuing a su -c "<command>" would be an alternative, but su does not offer the possibility to read the password from stdin. Is it safe to jump around between the users using su (And if yes, how do I provide the stdin? and does it work or just result in a su: must be run from a terminal) or would this cause issues?

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  • In C what is the difference between null and a new line character? Guys help please [migrated]

    - by Siddhartha Gurjala
    Whats the conceptual difference and similarity between NULL and a newline character i.e between '\0' and '\n' Explain their relevance for both integer and character data type variables and arrays? For reference here is an example snippets of a program to read and write a 2d char array PROGRAM CODE 1: int main() { char sort(),stuname(),swap(),(*p)(),(*q)(); int n; p=stuname; q=swap; printf("Let the number of students in the class be \n"); scanf("%d",&n); fflush(stdin); sort(p,q,n); return 0; } char sort(p1,q1,n1) char (*p1)(),(*q1)(); int n1; { (*p1)(n1); (*q1)(); } char stuname(int nos) // number of students { char name[nos][256]; int i,j; printf("Reading names of %d students started--->\n\n",nos); name[0][0]='k'; //initialising as non NULL charecter for(i=0;i<nos;i++) // nos=number of students { printf("Give name of student %d\n",i); for(j=0;j<256;j++) { scanf("%c",&name[i][j]); if(name[i][j]=='\n') { name[i][j]='\0'; j=257; } } } printf("\n\nWriting student names:\n\n"); for(i=0;i<nos;i++) { for(j=0;j<256&&name[i][j]!='\0';j++) { printf("%c",name[i][j]); } printf("\n"); } } char swap() { printf("Will swap shortly after getting clarity on scanf and %c"); } The above code is working good where as the same logic given with slight diff is not giving appropriate output. Here's the code PROGRAM CODE 2: #include<stdio.h> int main() { char sort(),stuname(),swap(),(*p)(),(*q)(); int n; p=stuname; q=swap; printf("Let the number of students in the class be \n"); scanf("%d",&n); fflush(stdin); sort(p,q,n); return 0; } char sort(p1,q1,n1) char (*p1)(),(*q1)(); int n1; { (*p1)(n1); (*q1)(); } char stuname(int nos) // number of students { char name[nos][256]; int i,j; printf("Reading names of %d students started--->\n\n",nos); name[0][0]='k'; //initialising as non NULL charecter for(i=0;i<nos;i++) // nos=number of students { printf("Give name of student %d\n",i); ***for(j=0;j<256&&name[i][j]!='\0';j++)*** { scanf("%c",&name[i][j]); /*if(name[i][j]=='\n') { name[i][j]='\0'; j=257; }*/ } } printf("\n\nWriting student names:\n\n"); for(i=0;i<nos;i++) { for(j=0;j<256&&name[i][j]!='\0';j++) { printf("%c",name[i][j]); } printf("\n"); } } char swap() { printf("Will swap shortly after getting clarity on scanf and %c"); } Here one more instance of same program not giving proper output given below PROGRAM CODE 3: #include<stdio.h> int main() { char sort(),stuname(),swap(),(*p)(),(*q)(); int n; p=stuname; q=swap; printf("Let the number of students in the class be \n"); scanf("%d",&n); fflush(stdin); sort(p,q,n); return 0; } char sort(p1,q1,n1) char (*p1)(),(*q1)(); int n1; { (*p1)(n1); (*q1)(); } char stuname(int nos) // number of students { char name[nos][256]; int i,j; printf("Reading names of %d students started--->\n\n",nos); name[0][0]='k'; //initialising as non NULL charecter for(i=0;i<nos;i++) // nos=number of students { printf("Give name of student %d\n",i); ***for(j=0;j<256&&name[i][j]!='\n';j++)*** { scanf("%c",&name[i][j]); /*if(name[i][j]=='\n') { name[i][j]='\0'; j=257; }*/ } name[i][i]='\0'; } printf("\n\nWriting student names:\n\n"); for(i=0;i<nos;i++) { for(j=0;j<256&&name[i][j]!='\0';j++) { printf("%c",name[i][j]); } printf("\n"); } } char swap() { printf("Will swap shortly after getting clarity on scanf and %c"); } Why the program code 2 and program code 3 are not working as expected as that of the code 1?

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  • fgets and strcmp [C]

    - by Blackbinary
    I'm trying to compare two strings. One stored in a file, the other retrieved from the user (stdin). Here is a sample program: int main() { char targetName[50]; fgets(targetName,50,stdin); char aName[] = "bob"; printf("%d",strcmp(aName,targetName)); return 0; } In this program, strcmp returns a value of -1 when the input is 'bob'. Why is this? I thought they should be equal. How can i get it so that they are?

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  • How do I introspect things in Ruby?

    - by Jason Baker
    For instance, in Python, I can do things like this if I want to get all attributes on an object: >>> import sys >>> dir(sys) ['__displayhook__', '__doc__', '__excepthook__', '__name__', '__package__', '__stderr__', '__stdin__', '__stdout__', '_clear_type_cache', '_current_frames', '_getframe', 'api_version', 'argv', 'builtin_module_names', 'byteorder', 'call_tracing', 'callstats', 'copyright', 'displayhook', 'dont_write_bytecode', 'exc_clear', 'exc_info', 'exc_type', 'excepthook', 'exec_prefix', 'executable', 'exit', 'flags', 'float_info', 'getcheckinterval', 'getdefaultencoding', 'getdlopenflags', 'getfilesystemencoding', 'getprofile', 'getrecursionlimit', 'getrefcount', 'getsizeof', 'gettrace', 'hexversion', 'maxint', 'maxsize', 'maxunicode', 'meta_path', 'modules', 'path', 'path_hooks', 'path_importer_cache', 'platform', 'prefix', 'ps1', 'ps2', 'py3kwarning', 'pydebug', 'setcheckinterval', 'setdlopenflags', 'setprofile', 'setrecursionlimit', 'settrace', 'stderr', 'stdin', 'stdout', 'subversion', 'version', 'version_info', 'warnoptions'] Or if I want to view the documentation of something, I can use the help function: >>> help(str) Is there any way to do similar things in Ruby?

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  • Cheat sheet exhibiting bash shell stdout/stderr redirection behavior

    - by SetJmp
    Is there a good cheat sheet demonstrating the many uses of BASH shell redirection? I would love to give such a thing to my students. Some examples I'd like to see covered: cmd > output_file.txt #redirect stdout to output_file.txt cmd 2> output_file.txt #redirect stderr to output_file.txt cmd >& outpout_file.txt #redirect both stderr and stdout to output_file.txt cmd1 | cmd2 #pipe cmd1 stdout to cmd2's stdin cmd1 2>&1 | cmd2 #pipe cmd1 stdout and stderr to cmd2's stdin cmd1 | tee result.txt #print cmd1's stdout to screen and also write to result.txt cmd1 2>&1 | tee result.txt #print stdout,stderr to screen while writing to result.txt (or we could just make this a community wiki and enumerate such things here) Thanks! SetJmp

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