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  • XPath and XML: Multiple namespaces

    - by emragins
    So I have a document that looks like <a xmlns="uri1" xmlns:pre2="uri2"> <b xmlns:pre3="uri3"> <pre3:c> <stuff></stuff> <goes></goes> <here></here> </pre3:c> <pre3:d xmlns="uri4"> <under></under> <the></the> <tree></tree> </pre3:d> </b> </a> I want an xpath expression that will get me <under>. This has a namespaceURI of uri4. Right now my expression looks like: //ns:a/ns:b/pre3:d/pre4:under I have the namespace manager add 'ns' for the default namespace (uri1 in this case) and I have it defined with pre2, pre3, and pre4 for uri2, uri3, and uri4 respectively. I get the error "Expression must evaluate to a node-set." I know that the node exists. I know that everything up until the pre4:under in my xpath works fine as I use it in the rest of the document with no issues. It's the additional pre4:under that causes the error, and I'm not sure why. Any ideas? Thanks.

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  • Iterate Through JSON Data for Specific Element - Similar to XPath

    - by Highroller
    I am working on an embedded system and my theory of the overall process follows this methodology: 1. Send a command to the back end asking for account information in JSON format. 2. The back end writes a JSON file with all accounts and associated information (there could be 0 to 16 accounts). 3. Here's where I get stuck - use JavaScript (we are using the JQuery library) to iterate through the returned information for a specific element (similar to XPath) and build an array based on the number of elements found to populate a drop-down box to select the account you want to view and then do stuff with the account info. So my code looks like this: loadAccounts = function() { $.getJSON('/info?q=voip.accounts[]', function(result) { var sipAcnts = $("#sipacnts"); $(sipAcnts).empty(); // empty the dropdown (if necessarry) // Get the 'label' element and stick it in an array // build the array and append it to the sipAcnts dropdown // use array index to ref the accounts info and do stuff with it } So what I need is the JSON version of XPath to build the array of voip.accounts.label. The first account info looks something like this: { "result_set": { "voip.accounts[0]": { "label": "Dispatch1", "enabled": true, "user": "1234", "name": "Jane Doe", "type": "sip", "sip": { "lots and lots of stuff": }, } } } Am I over complicating the issue? Any wisdom anyone could thrown down would be greatly appreciated.

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  • C# XPath Not Finding Anything

    - by ehdv
    I'm trying to use XPath to select the items which have a facet with Location values, but currently my attempts even to just select all items fail: The system happily reports that it found 0 items, then returns (instead the nodes should be processed by a foreach loop). I'd appreciate help either making my original query or just getting XPath to work at all. XML <?xml version="1.0" encoding="UTF-8" ?> <Collection Name="My Collection" SchemaVersion="1.0" xmlns="http://schemas.microsoft.com/collection/metadata/2009" xmlns:p="http://schemas.microsoft.com/livelabs/pivot/collection/2009" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <FacetCategories> <FacetCategory Name="Current Address" Type="Location"/> <FacetCategory Name="Previous Addresses" Type="Location" /> </FacetCategories> <Items> <Item Id="1" Name="John Doe"> <Facets> <Facet Name="Current Address"> <Location Value="101 America Rd, A Dorm Rm 000, Chapel Hill, NC 27514" /> </Facet> <Facet Name="Previous Addresses"> <Location Value="123 Anywhere Ln, Darien, CT 06820" /> <Location Value="000 Foobar Rd, Cary, NC 27519" /> </Facet> </Facets> </Item> </Items> </Collection> C# public void countItems(string fileName) { XmlDocument document = new XmlDocument(); document.Load(fileName); XmlNode root = document.DocumentElement; XmlNodeList xnl = root.SelectNodes("//Item"); Console.WriteLine(String.Format("Found {0} items" , xnl.Count)); } There's more to the method than this, but since this is all that gets run I'm assuming the problem lies here. Calling root.ChildNodes accurately returns FacetCategories and Items, so I am completely at a loss. Thanks for your help!

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  • Xpath and innerHTML

    - by Jonathan
    What Xpath expression can I use to find all the anchor (just 'a') elements whose actual text (the innerHTML) is Logout. something like //a[@innerHTML='Logout'] Would that be correct?

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  • How to use regular expression in lxml xpath?

    - by Arty
    I'm using construction like this: doc = parse(url).getroot() links = doc.xpath("//a[text()='some text']") But I need to select all links which have text beginning with "some text", so I'm wondering is there any way to use regexp here? Didn't find anything in lxml documentation

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  • XPath find element based on ancestor element

    - by martymcfly
    Hi, again I have Java AST which is created from public class Test { String o = new String("hh"); public void wrong1() { synchronized(o) { // huhu } } } I try to create a XPath query which finds the synchronized block in which the defined String variable o is used. As the definition is above it is an ancestor of the SynchronizedStatement, but I dont get it working //SynchronizedStatement[Expression/PrimaryExpression/PrimaryPrefix/Name[@Image=ancestor::ClassOrInterfaceBody[ClassOrInterfaceBodyDeclaration/FieldVariableDeclaratorId/@Image]]] I know that /SynchronizedStatement[Expression/PrimaryExpression/PrimaryPrefix/Name[@Image= is correct, my problem is how to address the ancestor ClassOrInterfaceBody part. Hope its clear what i mean ;-) Thanks

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  • Using Xpath With Default Namespace in C#

    - by macleojw
    I've got an XML document with a default namespace. I'm using a XPathNavigator to select a set of nodes using Xpath as follows: XmlElement myXML = ...; XPathNavigator navigator = myXML.CreateNavigator(); XPathNodeIterator result = navigator.Select("/outerelement/innerelement"); I am not getting any results back: I'm assuming this is because I am not specifying the namespace. How can I include the namespace in my select?

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  • access html element using xpath

    - by eclarke
    Hi, can you use xpath to access an html element? It must run in interenet explorer, and i am writing it in javascript I am trying to get the value of a specific input box in a specific row, but i don't want to have to iterate through all the cells to get the right one Any help would be appreciated Emma

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  • XPath query returning 'false' in SimpleXML

    - by Drew
    Hi all, I have an xml fragment as such: <meta_tree type="root"> <meta_data> <meta_cat>Content Provider</meta_cat> <data>Mammoth</data> </meta_data> <meta_data> <meta_cat>Genre</meta_cat> <data>Games</data> </meta_data> <meta_data> <meta_cat>Channel Name</meta_cat> <data>Games Trailers</data> </meta_data> <meta_data> <meta_cat>Collection</meta_cat> <data>Strategy</data> </meta_data> <meta_data> <meta_cat>Custom 1</meta_cat> <data>PC</data> </meta_data> <meta_data> <meta_cat>DRM Protected</meta_cat> <data>N</data> </meta_data> <meta_data> <meta_cat>Aspect Ratio</meta_cat> <data>16:9</data> </meta_data> <meta_data> <meta_cat>Streaming Type</meta_cat> <data>VOD</data> </meta_data> </meta_tree> which I garnered from the snippet of $meta_tree->asXML(). So given that, I need to have an xpath query for each element, so I'm using: $meta_tree->xpath("/meta_data[meta_cat='Content Provider']"); but this returns false. I have tried: "/meta_tree/meta_data[meta_cat='Content Provider']" "//meta_data[meta_cat='Content Provider']" I've been using AquaPath, which validates my query, so I'm not sure what I'm doing wrong. Anyone got any ideas? DJS.

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  • Lxml or Xpath content print

    - by Angelo
    function= def parseTitle(self, post): """ Returns title string with spaces replaced by dots "" return post.xpath('h2')[0].text.replace('.', ' ') i would to see the content of post. Tried all . How can i properly debug the content. ir is an webstite of movies where i rip links and tittle. So this one should parse the title.and i am sure H@ is not existing , how to print/debug it?

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  • XPATH: multiple negations in for-each

    - by Peter
    I have the following simplified XML: <?xml version="1.0" encoding="UTF-8" ?> <MATMAS05> <IDOC BEGIN="1"> <E1MARAM SEGMENT="1"> <MSGFN>005</MSGFN> <MATNR>000000000000401436</MATNR> <E1MARCM SEGMENT="1"> <MSGFN>005</MSGFN> <WERKS>A120</WERKS> <MMSTA>01</MMSTA> </E1MARCM> <E1MVKEM SEGMENT="1"> <VKORG>0120</VKORG> <VMSTA>04</VMSTA> </E1MVKEM> </E1MARAM> </IDOC> </MATMAS05> If <WERKS>=A120 and <MMSTA> is NOT '01' or '02' or '03' OR if <VKORG>=0120 and <VMSTA> is NOT '01' or '02' or '03' then the <MATNR> should be mapped to the target XML. I came up with the following XSLT: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output encoding="UTF-8" method="xml" indent="yes"/> <xsl:template match="/*"> <xsl:for-each select="IDOC[(E1MARAM/E1MVKEM[VKORG='0120'][not(VMSTA='01' or VMSTA='02' or VMSTA='03')]) or (E1MARAM/E1MARCM[WERKS = 'A120'][not(MMSTA='01' or MMSTA='02' or MMSTA='03')])]"> <Item> <ITEM_CODE> <xsl:value-of select="E1MARAM/MATNR"/> </ITEM_CODE> </Item> </xsl:for-each> </xsl:template> </xsl:stylesheet> But if I apply that XSLT I get the following unwanted output (because <MMSTA>='01'): <?xml version="1.0" encoding="UTF-8"?> <Item> <ITEM_CODE>000000000000401436</ITEM_CODE> </Item> How can I solve this? I have tried around with that XPATH expression but I can't get the wanted result. What am I doing wrong in my XPATH? Thank you for any ideas with this. Best regards, Peter

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  • PHP Getting XPath of a DOMNode

    - by user256007
    I am creating an XML document on the fly. and I need to know the XPath of the Node I've just created. I don't see any such function like DOMNode::calculateXPath(void):string and I am not willing to write one by my own. is there any known lite 3rd party Solution ??

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  • How does this XPATH query differentiate?

    - by Soham
    I am kind of repeating this question because mostly due to my own ignorance, I could not fully understand the innards. Given this HTML snippet <td valign=top class="tim_new"><a href="/stocks/company_info/pricechart.php?sc_did=MI42" class="tim_new">3M India</a></td> <td class="tim_new" valign=top><a href='/stocks/marketstats/indcomp.php?optex=NSE&indcode=Diversified' class=tim>Diversified</a></td> How does this XPATH //a[@class='tim_new'] differentiate between line 1 and line 2.

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  • dynamic xpath expression

    - by Ferol
    Good day, colleagues! Tell me please, how to make a dynamic xpath-parsing: for example, instead of writing $domXPath-query('//[(@id = "article-id-18")]'); - write something like that $domXPath-query('//[(@id = "article-id-*")]');, because in my case, the site's script generate (every time) a new id for block, that contains article's text? So question, is above.

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  • xpath - limit search to node not working?

    - by Mr W
    What am I doing wrong here? I am trying to limit my xpath search to a specific row in my table but my query always returns the content of the span in the first row: var query = "//span[contains(@id, 'timer')]"; var root = document.getElementById('movements').rows[1]; document.evaluate(query, root, null, XPathResult.FIRST_ORDERED_NODE_TYPE, null).singleNodeValue.textContent Please help!

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  • need help with xpath expression

    - by geoff swartz
    I have an xml node that looks like <slot highcount="20" lowcount="10" /> I've tried the following xpath expression: XmlNode node = xdoc.SelectSingleNode("slot[@lowcount>=12] && slot[@highcount <=12]"); but I get an invalid token error and I don't have enough experience with this to know what I'm doing wrong. Any ideas?

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  • Find all <a>s to who's href points to an image with XPath 1.0

    - by Jeffrey Aylesworth
    First, I can assume that all urls that end with jpeg, jpg, bmp, png or gif are images, and others aren't. I thought of, and tried two solutions: Matching the regular expression .(jpe?g|bmp|png|gif)$ Using ends-with to check each separately But, it appears that neither of these exist in XPath 1.0, or at least, they don't exist in Firefox (I am writing a greasemonkey script, so it is only important for the path to work in Firefox).

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  • Nokogiri (Ruby) and XPath

    - by JP
    Does Nokogiri only support XPath 1.0? I'm trying to do simple string replacement in a value-of cell, like so (where element contains something like '* My string (useless text)') <xsl:value-of select="replace(element,'^\*\ (.+)\ \(.*\)$','\\1')"> Is this poorly formed XSL? Or is there a limitation with Nokogiri?

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