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  • Adobe Plugin in Firefox showing grey screen; something to do with range requests on Apache?

    - by Sam Minnée
    I have a web page with a link to a PDF file (target="_blank"). If I click the link, the PDF reader just shows a grey screen within the Firefox browser. If I copy that link and manually open it in a new tab, the PDF will display correctly, and subsequent requests made by clicking the original link now work, suggesting that the problem occurs when loading the file into the cache. It appears as though the Adobe PDF reader plugin is making byte-range requests (I see lots of 206 responses) and I suspect that this may be the cause of the issue. I am running an Apache webserver. Has anyone had problems with Apache and Adobe's byte-range requests? Are there any workarounds?

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  • calling concurrently Graphics.Draw and new Bitmap from memory in thread take long time

    - by Abdul jalil
    Example1 public partial class Form1 : Form { public Form1() { InitializeComponent(); pro = new Thread(new ThreadStart(Producer)); con = new Thread(new ThreadStart(Consumer)); } private AutoResetEvent m_DataAvailableEvent = new AutoResetEvent(false); Queue<Bitmap> queue = new Queue<Bitmap>(); Thread pro; Thread con ; public void Producer() { MemoryStream[] ms = new MemoryStream[3]; for (int y = 0; y < 3; y++) { StreamReader reader = new StreamReader("image"+(y+1)+".JPG"); BinaryReader breader = new BinaryReader(reader.BaseStream); byte[] buffer=new byte[reader.BaseStream.Length]; breader.Read(buffer,0,buffer.Length); ms[y] = new MemoryStream(buffer); } while (true) { for (int x = 0; x < 3; x++) { Bitmap bmp = new Bitmap(ms[x]); queue.Enqueue(bmp); m_DataAvailableEvent.Set(); Thread.Sleep(6); } } } public void Consumer() { Graphics g= pictureBox1.CreateGraphics(); while (true) { m_DataAvailableEvent.WaitOne(); Bitmap bmp = queue.Dequeue(); if (bmp != null) { // Bitmap bmp = new Bitmap(ms); g.DrawImage(bmp,new Point(0,0)); bmp.Dispose(); } } } private void pictureBox1_Click(object sender, EventArgs e) { con.Start(); pro.Start(); } } when Creating bitmap and Drawing to picture box are in seperate thread then Bitmap bmp = new Bitmap(ms[x]) take 45.591 millisecond and g.DrawImage(bmp,new Point(0,0)) take 41.430 milisecond when i make bitmap from memoryStream and draw it to picture box in one thread then Bitmap bmp = new Bitmap(ms[x]) take 29.619 and g.DrawImage(bmp,new Point(0,0)) take 35.540 the code is for Example 2 is why it take more time to draw and bitmap take time in seperate thread and how to reduce the time when processing in seperate thread. i am using ANTS performance profiler 4.3 public Form1() { InitializeComponent(); pro = new Thread(new ThreadStart(Producer)); con = new Thread(new ThreadStart(Consumer)); } private AutoResetEvent m_DataAvailableEvent = new AutoResetEvent(false); Queue<MemoryStream> queue = new Queue<MemoryStream>(); Thread pro; Thread con ; public void Producer() { MemoryStream[] ms = new MemoryStream[3]; for (int y = 0; y < 3; y++) { StreamReader reader = new StreamReader("image"+(y+1)+".JPG"); BinaryReader breader = new BinaryReader(reader.BaseStream); byte[] buffer=new byte[reader.BaseStream.Length]; breader.Read(buffer,0,buffer.Length); ms[y] = new MemoryStream(buffer); } while (true) { for (int x = 0; x < 3; x++) { // Bitmap bmp = new Bitmap(ms[x]); queue.Enqueue(ms[x]); m_DataAvailableEvent.Set(); Thread.Sleep(6); } } } public void Consumer() { Graphics g= pictureBox1.CreateGraphics(); while (true) { m_DataAvailableEvent.WaitOne(); //Bitmap bmp = queue.Dequeue(); MemoryStream ms= queue.Dequeue(); if (ms != null) { Bitmap bmp = new Bitmap(ms); g.DrawImage(bmp,new Point(0,0)); bmp.Dispose(); } } } private void pictureBox1_Click(object sender, EventArgs e) { con.Start(); pro.Start(); }

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  • Cannot Create New Team Project TFS2010 TF249063 TF218017

    - by Kodicus
    Server: Windows 2008 R2 Standard Team Foundation Server 2010 WSS 3.0 TFS Configuration: Single Server instalation (including SharePoint) The following error occurs when trying to create a new team project from my local machine. The ://sourcecontrol site and ://sourcecontrol/sites/DefaultCollection/ site appears to be functioning fine and my user is a Site collection administrator on both. I can navigate both sites through a browser on my local machine. Thanks for your help! 2010-04-23T10:01:42 | Module: Internal | Team Foundation Server proxy retrieved | Completion time: 0 seconds 2010-04-23T10:01:42 | Module: Wizard | Retrieved IAuthorizationService proxy | Completion time: 0 seconds 2010-04-23T10:01:42 | Module: Wizard | TF30227: Project creation permissions retrieved | Completion time: 0.109382 seconds 2010-04-23T10:01:42 | Module: Internal | The template information for Team Foundation Server "sourcecontrol\DefaultCollection" was retrieved from the Team Foundation Server. | Completion time: 0.15626 seconds ---begin Exception entry--- Time: 2010-04-23T10:03:24 Module: Wizard Exception Message: TF218017: A SharePoint site could not be created for use as the team project portal. The following error occurred: TF249063: The following Web service is not available: ://sourcecontrol/_vti_bin/TeamFoundationIntegrationService.asmx. This Web service is used for the Team Foundation Server Extensions for SharePoint Products. The underlying error is: The underlying connection was closed: A connection that was expected to be kept alive was closed by the server.. Verify that the following URL points to a valid SharePoint Web application and that the application is available: ://sourcecontrol. If the URL is correct and the Web application is operating normally, verify that a firewall is not blocking access to the Web application. (type TeamFoundationServerException) Exception Stack Trace: at Microsoft.VisualStudio.TeamFoundation.WssSiteCreator.CheckCreateSite(TfsTeamProjectCollection tfsServer, Uri adminUri, Uri siteUri) at Microsoft.VisualStudio.TeamFoundation.WssSiteCreator.ValidateSettings(ProjectCreationContext context) at Microsoft.VisualStudio.TeamFoundation.PortfolioProjectForm.OnFinish() Inner Exception Details: Exception Message: TF249063: The following Web service is not available: ://sourcecontrol/_vti_bin/TeamFoundationIntegrationService.asmx. This Web service is used for the Team Foundation Server Extensions for SharePoint Products. The underlying error is: The underlying connection was closed: A connection that was expected to be kept alive was closed by the server.. Verify that the following URL points to a valid SharePoint Web application and that the application is available: ://sourcecontrol. If the URL is correct and the Web application is operating normally, verify that a firewall is not blocking access to the Web application. (type TeamFoundationServiceUnavailableException) Exception Stack Trace: at Microsoft.TeamFoundation.Client.SharePoint.SharePointTeamFoundationIntegrationService.HandleException(Exception e) at Microsoft.TeamFoundation.Client.SharePoint.SharePointTeamFoundationIntegrationService.CheckUrl(String absolutePath, CheckUrlOptions options, Guid configurationServerId, Guid projectCollectionId) at Microsoft.TeamFoundation.Client.SharePoint.WssUtilities.CheckUrl(ICredentials credentials, Uri adminUrl, Uri siteUrl, CheckUrlOptions options, Guid configurationServerId, Guid projectCollectionId) at Microsoft.TeamFoundation.Client.SharePoint.WssUtilities.CheckCreateSite(TfsConnection tfs, Uri adminUrl, Uri siteUrl) at Microsoft.VisualStudio.TeamFoundation.WssSiteCreator.CheckCreateSite(TfsTeamProjectCollection tfsServer, Uri adminUri, Uri siteUri) Inner Exception Details: Exception Message: The underlying connection was closed: A connection that was expected to be kept alive was closed by the server. (type WebException) Exception Stack Trace: at System.Net.WebRequest.GetResponse() at Microsoft.TeamFoundation.Client.TeamFoundationClientProxyBase.AsyncWebRequest.ExecRequest(Object obj) Inner Exception Details: Exception Message: Unable to read data from the transport connection: An existing connection was forcibly closed by the remote host. (type IOException) Exception Stack Trace: at System.Net.Sockets.NetworkStream.Read(Byte[] buffer, Int32 offset, Int32 size) at System.Net.PooledStream.Read(Byte[] buffer, Int32 offset, Int32 size) at System.Net.Connection.SyncRead(WebRequest request, Boolean userRetrievedStream, Boolean probeRead) Inner Exception Details: Exception Message: An existing connection was forcibly closed by the remote host (type SocketException) Exception Stack Trace: at System.Net.Sockets.Socket.Receive(Byte[] buffer, Int32 offset, Int32 size, SocketFlags socketFlags) at System.Net.Sockets.NetworkStream.Read(Byte[] buffer, Int32 offset, Int32 size) --- end Exception entry ---

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  • C# Asynchronous Network IO and OutOfMemoryException

    - by The.Anti.9
    I'm working on a client/server application in C#, and I need to get Asynchronous sockets working so I can handle multiple connections at once. Technically it works the way it is now, but I get an OutOfMemoryException after about 3 minutes of running. MSDN says to use a WaitHandler to do WaitOne() after the socket.BeginAccept(), but it doesn't actually let me do that. When I try to do that in the code it says WaitHandler is an abstract class or interface, and I can't instantiate it. I thought maybe Id try a static reference, but it doesnt have teh WaitOne() method, just WaitAll() and WaitAny(). The main problem is that in the docs it doesn't give a full code snippet, so you can't actually see what their "wait handler" is coming from. its just a variable called allDone, which also has a Reset() method in the snippet, which a waithandler doesn't have. After digging around in their docs, I found some related thing about an AutoResetEvent in the Threading namespace. It has a WaitOne() and a Reset() method. So I tried that around the while(true) { ... socket.BeginAccept( ... ); ... }. Unfortunately this makes it only take one connection at a time. So I'm not really sure where to go. Here's my code: class ServerRunner { private Byte[] data = new Byte[2048]; private int size = 2048; private Socket server; static AutoResetEvent allDone = new AutoResetEvent(false); public ServerRunner() { server = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); IPEndPoint iep = new IPEndPoint(IPAddress.Any, 33333); server.Bind(iep); Console.WriteLine("Server initialized.."); } public void Run() { server.Listen(100); Console.WriteLine("Listening..."); while (true) { //allDone.Reset(); server.BeginAccept(new AsyncCallback(AcceptCon), server); //allDone.WaitOne(); } } void AcceptCon(IAsyncResult iar) { Socket oldserver = (Socket)iar.AsyncState; Socket client = oldserver.EndAccept(iar); Console.WriteLine(client.RemoteEndPoint.ToString() + " connected"); byte[] message = Encoding.ASCII.GetBytes("Welcome"); client.BeginSend(message, 0, message.Length, SocketFlags.None, new AsyncCallback(SendData), client); } void SendData(IAsyncResult iar) { Socket client = (Socket)iar.AsyncState; int sent = client.EndSend(iar); client.BeginReceive(data, 0, size, SocketFlags.None, new AsyncCallback(ReceiveData), client); } void ReceiveData(IAsyncResult iar) { Socket client = (Socket)iar.AsyncState; int recv = client.EndReceive(iar); if (recv == 0) { client.Close(); server.BeginAccept(new AsyncCallback(AcceptCon), server); return; } string receivedData = Encoding.ASCII.GetString(data, 0, recv); //process received data here byte[] message2 = Encoding.ASCII.GetBytes("reply"); client.BeginSend(message2, 0, message2.Length, SocketFlags.None, new AsyncCallback(SendData), client); } }

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  • Seeking (somewhat) better explanations about supporting > 2.1 TB hard drives.

    - by irrational John
    Today while Googling about I stumbled across posts claiming that Seagate plans to ship a 3TB drive sometime later in 2010. Unfortunately, the stuff I looked at all seemed to contain tidbits of info which I didn't think fit together properly. (I would link to some examples, but I'm only allowed 1 link per post at the moment). Now I really don't have any "need" to better understand the underlying tedious details of this. I am just curious. And confused. So ... some questions I'm hoping someone better informed than I might answer. The talk about a potential addressing problem in both the hardware and the software confused me. The assertion is that something called something called Long LBA addressing (LLBA) is needed in the Command Descriptor Block as a way to get around the current limits to access a hard drive bigger than ~2.1 (or ~2.2?) TB. OK, fine. But I thought the last time this problem came up it was solved by extending the length of the LBA field from 28 to 48 bits. (Remember this website? www.48bitlba.com) A 6 byte LBA is clearly large enough, so what's up with this LLBA talk. I thought this was all fixed back by Win XP SP2, if not sooner? And certainly all the hardware should be up to the task, shouldn't it? The real problem as I understand it with drives much bigger than 2 TB are the 4 byte LBA fields in the Master Boot Record (MBR) used to partition just about all hard drives at the moment. The most likely solution is to migrate to Intel's GUID Partition Table (GPT). A GPT uses 8 byte fields for the LBA. What I don't understand in this context is what is the problem with booting say Windows from a 3TB drive that uses a GPT. Granted, the current PC BIOS wouldn't know how to recognize or work with a GPT. But every GPT comes with a so-called "Safety" or "Guarding" MBR in sector 0.Apple already uses a hybrid version of the MBR to allow them to boot Windows on their Intel Macs (aka Boot Camp). Couldn't something similar be done to allow the PC BIOS to recognize and boot from a partition in, say, the first 1 GB of a 3GB or larger drive? I've got more questions such as where do 4K sectors fit into all of this. But it's probably time I just shut up and posted this. ;-) -irrational john

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  • UI not updated while using ProgressMonitorInputStream in Swing to monitor compressed file decompress

    - by Bozhidar Batsov
    I'm working on swing application that relies on an embedded H2 database. Because I don't want to bundle the database with the app(the db is frequently updated and I want new users of the app to start with a recent copy), I've implemented a solution which downloads a compressed copy of the db the first time the application is started and extracts it. Since the extraction process might be slow I've added a ProgressMonitorInputStream to show to progress of the extraction process - unfortunately when the extraction starts, the progress dialog shows up but it's not updated at all. It seems like to events are getting through to the event dispatch thread. Here is the method: public static String extractDbFromArchive(String pathToArchive) { if (SwingUtilities.isEventDispatchThread()) { System.out.println("Invoking on event dispatch thread"); } // Get the current path, where the database will be extracted String currentPath = System.getProperty("user.home") + File.separator + ".spellbook" + File.separator; LOGGER.info("Current path: " + currentPath); try { //Open the archive FileInputStream archiveFileStream = new FileInputStream(pathToArchive); // Read two bytes from the stream before it used by CBZip2InputStream for (int i = 0; i < 2; i++) { archiveFileStream.read(); } // Open the gzip file and open the output file CBZip2InputStream bz2 = new CBZip2InputStream(new ProgressMonitorInputStream( null, "Decompressing " + pathToArchive, archiveFileStream)); FileOutputStream out = new FileOutputStream(ARCHIVED_DB_NAME); LOGGER.info("Decompressing the tar file..."); // Transfer bytes from the compressed file to the output file byte[] buffer = new byte[1024]; int len; while ((len = bz2.read(buffer)) > 0) { out.write(buffer, 0, len); } // Close the file and stream bz2.close(); out.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException ex) { ex.printStackTrace(); } try { TarInputStream tarInputStream = null; TarEntry tarEntry; tarInputStream = new TarInputStream(new ProgressMonitorInputStream( null, "Extracting " + ARCHIVED_DB_NAME, new FileInputStream(ARCHIVED_DB_NAME))); tarEntry = tarInputStream.getNextEntry(); byte[] buf1 = new byte[1024]; LOGGER.info("Extracting tar file"); while (tarEntry != null) { //For each entry to be extracted String entryName = currentPath + tarEntry.getName(); entryName = entryName.replace('/', File.separatorChar); entryName = entryName.replace('\\', File.separatorChar); LOGGER.info("Extracting entry: " + entryName); FileOutputStream fileOutputStream; File newFile = new File(entryName); if (tarEntry.isDirectory()) { if (!newFile.mkdirs()) { break; } tarEntry = tarInputStream.getNextEntry(); continue; } fileOutputStream = new FileOutputStream(entryName); int n; while ((n = tarInputStream.read(buf1, 0, 1024)) > -1) { fileOutputStream.write(buf1, 0, n); } fileOutputStream.close(); tarEntry = tarInputStream.getNextEntry(); } tarInputStream.close(); } catch (Exception e) { } currentPath += "db" + File.separator + DB_FILE_NAME; if (!currentPath.isEmpty()) { LOGGER.info("DB placed in : " + currentPath); } return currentPath; } This method gets invoked on the event dispatch thread (SwingUtilities.isEventDispatchThread() returns true) so the UI components should be updated. I haven't implemented this as an SwingWorker since I need to wait for the extraction anyways before I can proceed with the initialization of the program. This method get invoked before the main JFrame of the application is visible. I don't won't a solution based on SwingWorker + property changed listeners - I think that the ProgressMonitorInputStream is exactly what I need, but I guess I'm not doing something right. I'm using Sun JDK 1.6.18. Any help would be greatly appreciated.

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  • UUID in Mountain Lion

    - by Naji
    I am trying to find my external HDD UUID in Mountain Lion but diskutil info /dev/disk1s1 returns: Najis-MacBook-Air:~ ****$ diskutil info disk1s1 Device Identifier: disk1s1 Device Node: /dev/disk1s1 Part of Whole: disk1 Device / Media Name: Untitled 1 Volume Name: My Book Escaped with Unicode: My%FF%FE%20%00Book Mounted: Yes Mount Point: /Volumes/My Book Escaped with Unicode: /Volumes/My%FF%FE%20%00Book File System Personality: NTFS Type (Bundle): ntfs Name (User Visible): Windows NT File System (NTFS) Partition Type: Windows_NTFS OS Can Be Installed: No Media Type: Generic Protocol: USB SMART Status: Not Supported Total Size: 2.0 TB (2000364240896 Bytes) (exactly 3906961408 512-Byte-Blocks) Volume Free Space: 212.5 GB (212506509312 Bytes) (exactly 415051776 512-Byte-Blocks) Device Block Size: 512 Bytes Read-Only Media: No Read-Only Volume: Yes Ejectable: Yes Whole: No Internal: No And there is no UUID. What is wrong exactly? Thank you.

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  • IIS FTP service - download timeouts and restarts getting the data twice

    - by accel229
    We have an IIS FTP site on a Windows Server 2003 x64 machine. Application Layer Gateway service is disabled (so http://support.microsoft.com/kb/931130 does not apply). Windows Firewall service is disabled as well. Connection timeout for the FTP site (there is only one) is set to 1,200 seconds = 20 minutes. An external client can connect to the site, list directory contents and download small files. When a client attempts to download a large file (eg, if the download continues for 3 minutes, which is still under 20 minutes, but relatively long), the server sends all data, then the connection times out, the client issues REST / RETR commands attempting to restart the download since after the last byte (which I believe should succeed and receive exactly 0 bytes), and the server behaves as if the client tried to restart after byte 0, that is, it sends the entire file all over. Any ideas on how to fix this?

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  • IOException during blocking network NIO in JDK 1.7

    - by Bass
    I'm just learning NIO, and here's the short example I've written to test how a blocking NIO can be interrupted: class TestBlockingNio { private static final boolean INTERRUPT_VIA_THREAD_INTERRUPT = true; /** * Prevent the socket from being GC'ed */ static Socket socket; private static SocketChannel connect(final int port) { while (true) { try { final SocketChannel channel = SocketChannel.open(new InetSocketAddress(port)); channel.configureBlocking(true); return channel; } catch (final IOException ioe) { try { Thread.sleep(1000); } catch (final InterruptedException ie) { } continue; } } } private static byte[] newBuffer(final int length) { final byte buffer[] = new byte[length]; for (int i = 0; i < length; i++) { buffer[i] = (byte) 'A'; } return buffer; } public static void main(final String args[]) throws IOException, InterruptedException { final int portNumber = 10000; new Thread("Reader") { public void run() { try { final ServerSocket serverSocket = new ServerSocket(portNumber); socket = serverSocket.accept(); /* * Fully ignore any input from the socket */ } catch (final IOException ioe) { ioe.printStackTrace(); } } }.start(); final SocketChannel channel = connect(portNumber); final Thread main = Thread.currentThread(); final Thread interruptor = new Thread("Inerruptor") { public void run() { System.out.println("Press Enter to interrupt I/O "); while (true) { try { System.in.read(); } catch (final IOException ioe) { ioe.printStackTrace(); } System.out.println("Interrupting..."); if (INTERRUPT_VIA_THREAD_INTERRUPT) { main.interrupt(); } else { try { channel.close(); } catch (final IOException ioe) { System.out.println(ioe.getMessage()); } } } } }; interruptor.setDaemon(true); interruptor.start(); final ByteBuffer buffer = ByteBuffer.allocate(32768); int i = 0; try { while (true) { buffer.clear(); buffer.put(newBuffer(buffer.capacity())); buffer.flip(); channel.write(buffer); System.out.print('X'); if (++i % 80 == 0) { System.out.println(); Thread.sleep(100); } } } catch (final ClosedByInterruptException cbie) { System.out.println("Closed via Thread.interrupt()"); } catch (final AsynchronousCloseException ace) { System.out.println("Closed via Channel.close()"); } } } In the above example, I'm writing to a SocketChannel, but noone is reading from the other side, so eventually the write operation hangs. This example works great when run by JDK-1.6, with the following output: Press Enter to interrupt I/O XXXX Interrupting... Closed via Thread.interrupt() — meaning that only 128k of data was written to the TCP socket's buffer. When run by JDK-1.7 (1.7.0_25-b15 and 1.7.0-u40-b37), however, the very same code bails out with an IOException: Press Enter to interrupt I/O XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX XXXXXXXXXXX Exception in thread "main" java.io.IOException: Broken pipe at sun.nio.ch.FileDispatcherImpl.write0(Native Method) at sun.nio.ch.SocketDispatcher.write(SocketDispatcher.java:47) at sun.nio.ch.IOUtil.writeFromNativeBuffer(IOUtil.java:93) at sun.nio.ch.IOUtil.write(IOUtil.java:65) at sun.nio.ch.SocketChannelImpl.write(SocketChannelImpl.java:487) at com.example.TestBlockingNio.main(TestBlockingNio.java:109) Can anyone explain this different behaviour?

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  • Java RMI Proxy issue

    - by Antony Lewis
    i am getting this error : java.lang.ClassCastException: $Proxy0 cannot be cast to rmi.engine.Call at Main.main(Main.java:39) my abstract and call class both extend remote. call: public class Call extends UnicastRemoteObject implements rmi.engine.Abstract { public Call() throws Exception { super(Store.PORT, new RClient(), new RServer()); } public String getHello() { System.out.println("CONN"); return "HEY"; } } abstract: public interface Abstract extends Remote { String getHello() throws RemoteException; } this is my main: public static void main(String[] args) { if (args.length == 0) { try { System.out.println("We are slave "); InetAddress ip = InetAddress.getLocalHost(); Registry rr = LocateRegistry.getRegistry(ip.getHostAddress(), Store.PORT, new RClient()); Object ss = rr.lookup("FILLER"); System.out.println(ss.getClass().getCanonicalName()); System.out.println(((Call)ss).getHello()); } catch (Exception e) { e.printStackTrace(); } } else { if (args[0].equals("master")) { // Start Master try { RMIServer.start(); } catch (Exception e) { e.printStackTrace(); } } Netbeans says the problem is on line 39 which is System.out.println(((Call)ss).getHello()); the output looks like this: run: We are slave Connecting 10.0.0.212:5225 $Proxy0 java.lang.ClassCastException: $Proxy0 cannot be cast to rmi.engine.Call at Main.main(Main.java:39) BUILD SUCCESSFUL (total time: 1 second) i am running a master in cmd listening on port 5225.

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  • UTF-8 bit representation

    - by Yanick Rochon
    I'm learning about UTF-8 standards and this is what I'm learning : Definition and bytes used UTF-8 binary representation Meaning 0xxxxxxx 1 byte for 1 à 7 bits chars 110xxxxx 10xxxxxx 2 bytes for 8 à 11 bits chars 1110xxxx 10xxxxxx 10xxxxxx 3 bytes for 12 à 16 bits chars 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx 4 bytes for 17 à 21 bits chars And I'm wondering, why 2 bytes UTF-8 code is not 10xxxxxx instead, thus gaining 1 bit all the way up to 22 bits with a 4 bytes UTF-8 code? The way it is right now, 64 possible values are lost (from 1000000 to 10111111). I'm not trying to argue the standards, but I'm wondering why this is so? ** EDIT ** Even, why isn't it UTF-8 binary representation Meaning 0xxxxxxx 1 byte for 1 à 7 bits chars 110xxxxx xxxxxxxx 2 bytes for 8 à 13 bits chars 1110xxxx xxxxxxxx xxxxxxxx 3 bytes for 14 à 20 bits chars 11110xxx xxxxxxxx xxxxxxxx xxxxxxxx 4 bytes for 21 à 27 bits chars ...? Thanks!

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  • OpenGL texture misaligned on quad

    - by user308226
    I've been having trouble with this for a while now, and I haven't gotten any solutions that work yet. Here is the problem, and the specifics: I am loading a 256x256 uncompressed TGA into a simple OpenGL program that draws a quad on the screen, but when it shows up, it is shifted about two pixels to the left, with the cropped part appearing on the right side. It has been baffling me for the longest time, people have suggested clamping and such, but somehow I think my problem is probably something really simple, but I just can't figure out what it is! Here is a screenshot comparing the TGA (left) and how it appears running in the program (right) for clarity. Also take note that there's a tiny black pixel on the upper right corner, I'm hoping that's related to the same problem. Here's the code for the loader, I'm convinced that my problem lies in the way that I'm loading the texture. Thanks in advance to anyone who can fix my problem. bool TGA::LoadUncompressedTGA(char *filename,ifstream &texturestream) { cout << "G position status:" << texturestream.tellg() << endl; texturestream.read((char*)header, sizeof(header)); //read 6 bytes into the file to get the tga header width = (GLuint)header[1] * 256 + (GLuint)header[0]; //read and calculate width and save height = (GLuint)header[3] * 256 + (GLuint)header[2]; //read and calculate height and save bpp = (GLuint)header[4]; //read bpp and save cout << bpp << endl; if((width <= 0) || (height <= 0) || ((bpp != 24) && (bpp !=32))) //check to make sure the height, width, and bpp are valid { return false; } if(bpp == 24) { type = GL_RGB; } else { type = GL_RGBA; } imagesize = ((bpp/8) * width * height); //determine size in bytes of the image cout << imagesize << endl; imagedata = new GLubyte[imagesize]; //allocate memory for our imagedata variable texturestream.read((char*)imagedata,imagesize); //read according the the size of the image and save into imagedata for(GLuint cswap = 0; cswap < (GLuint)imagesize; cswap += (bpp/8)) //loop through and reverse the tga's BGR format to RGB { imagedata[cswap] ^= imagedata[cswap+2] ^= //1st Byte XOR 3rd Byte XOR 1st Byte XOR 3rd Byte imagedata[cswap] ^= imagedata[cswap+2]; } texturestream.close(); //close ifstream because we're done with it cout << "image loaded" << endl; glGenTextures(1, &texID); // Generate OpenGL texture IDs glBindTexture(GL_TEXTURE_2D, texID); glPixelStorei(GL_UNPACK_ALIGNMENT, 1); glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_WRAP_S, GL_REPEAT); glTexParameteri (GL_TEXTURE_2D, GL_TEXTURE_WRAP_T, GL_REPEAT); glTexParameteri (GL_TEXTURE_2D, GL_TEXTURE_MAG_FILTER, GL_NEAREST); glTexParameteri (GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_NEAREST); glTexEnvf(GL_TEXTURE_ENV, GL_TEXTURE_ENV_MODE, GL_MODULATE); glTexImage2D(GL_TEXTURE_2D, 0, type, width, height, 0, type, GL_UNSIGNED_BYTE, imagedata); delete imagedata; return true; } //Public loading function for TGA images. Opens TGA file and determines //its type, if any, then loads it and calls the appropriate function. //Returns: TRUE on success, FALSE on failure bool TGA::loadTGA(char *filename) { cout << width << endl; ifstream texturestream; texturestream.open(filename,ios::binary); texturestream.read((char*)header,sizeof(header)); //read 6 bytes into the file, its the header. //if it matches the uncompressed header's first 6 bytes, load it as uncompressed LoadUncompressedTGA(filename,texturestream); return true; }

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  • Resumable upload from Java client to Grails web application?

    - by dersteps
    After almost 2 workdays of Googling and trying several different possibilities I found throughout the web, I'm asking this question here, hoping that I might finally get an answer. First of all, here's what I want to do: I'm developing a client and a server application with the purpose of exchanging a lot of large files between multiple clients on a single server. The client is developed in pure Java (JDK 1.6), while the web application is done in Grails (2.0.0). As the purpose of the client is to allow users to exchange a lot of large files (usually about 2GB each), I have to implement it in a way, so that the uploads are resumable, i.e. the users are able to stop and resume uploads at any time. Here's what I did so far: I actually managed to do what I wanted to do and stream large files to the server while still being able to pause and resume uploads using raw sockets. I would send a regular request to the server (using Apache's HttpClient library) to get the server to send me a port that was free for me to use, then open a ServerSocket on the server and connect to that particular socket from the client. Here's the problem with that: Actually, there are at least two problems with that: I open those ports myself, so I have to manage open and used ports myself. This is quite error-prone. I actually circumvent Grails' ability to manage a huge amount of (concurrent) connections. Finally, here's what I'm supposed to do now and the problem: As the problems I mentioned above are unacceptable, I am now supposed to use Java's URLConnection/HttpURLConnection classes, while still sticking to Grails. Connecting to the server and sending simple requests is no problem at all, everything worked fine. The problems started when I tried to use the streams (the connection's OutputStream in the client and the request's InputStream in the server). Opening the client's OutputStream and writing data to it is as easy as it gets. But reading from the request's InputStream seems impossible to me, as that stream is always empty, as it seems. Example Code Here's an example of the server side (Groovy controller): def test() { InputStream inStream = request.inputStream if(inStream != null) { int read = 0; byte[] buffer = new byte[4096]; long total = 0; println "Start reading" while((read = inStream.read(buffer)) != -1) { println "Read " + read + " bytes from input stream buffer" //<-- this is NEVER called } println "Reading finished" println "Read a total of " + total + " bytes" // <-- 'total' will always be 0 (zero) } else { println "Input Stream is null" // <-- This is NEVER called } } This is what I did on the client side (Java class): public void connect() { final URL url = new URL("myserveraddress"); final byte[] message = "someMessage".getBytes(); // Any byte[] - will be a file one day HttpURLConnection connection = url.openConnection(); connection.setRequestMethod("GET"); // other methods - same result // Write message DataOutputStream out = new DataOutputStream(connection.getOutputStream()); out.writeBytes(message); out.flush(); out.close(); // Actually connect connection.connect(); // is this placed correctly? // Get response BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream())); String line = null; while((line = in.readLine()) != null) { System.out.println(line); // Prints the whole server response as expected } in.close(); } As I mentioned, the problem is that request.inputStream always yields an empty InputStream, so I am never able to read anything from it (of course). But as that is exactly what I'm trying to do (so I can stream the file to be uploaded to the server, read from the InputStream and save it to a file), this is rather disappointing. I tried different HTTP methods, different data payloads, and also rearranged the code over and over again, but did not seem to be able to solve the problem. What I hope to find I hope to find a solution to my problem, of course. Anything is highly appreciated: hints, code snippets, library suggestions and so on. Maybe I'm even having it all wrong and need to go in a totally different direction. So, how can I implement resumable file uploads for rather large (binary) files from a Java client to a Grails web application without manually opening ports on the server side?

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  • Reduce durability in MySQL for performance

    - by Paul Prescod
    My site occasionally has fairly predictable bursts of traffic that increase the throughput by 100 times more than normal. For example, we are going to be featured on a television show, and I expect in the hour after the show, I'll get more than 100 times more traffic than normal. My understanding is that MySQL (InnoDB) generally keeps my data in a bunch of different places: RAM Buffers commitlog binary log actual tables All of the above places on my DB slave This is too much "durability" given that I'm on an EC2 node and most of the stuff goes across the same network pipe (file systems are network attached). Plus the drives are just slow. The data is not high value and I'd rather take a small chance of a few minutes of data loss rather than have a high probability of an outage when the crowd arrives. During these traffic bursts I would like to do all of that I/O only if I can afford it. I'd like to just keep as much in RAM as possible (I have a fair chunk of RAM compared to the data size that would be touched over an hour). If buffers get scarce, or the I/O channel is not too overloaded, then sure, I'd like things to go to the commitlog or binary log to be sent to the slave. If, and only if, the I/O channel is not overloaded, I'd like to write back to the actual tables. In other words, I'd like MySQL/InnoDB to use a "write back" cache algorithm rather than a "write through" cache algorithm. Can I convince it to do that? If this is not possible, I am interested in general MySQL write-performance optimization tips. Most of the docs are about optimizing read performance, but when I get a crowd of users, I am creating accounts for all of them, so that's a write-heavy workload.

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  • Arduino Ethernet Shield Not Connecting to WebServer

    - by new user
    I have a problem making my Arduino Ethernet shield to communicate with the server, the result on the serial monitor is always: my arduino code is #include <Ethernet.h> //library for ethernet functions #include <SPI.h> #include <Dns.h> #include <Client.h> //library for client functions #include <DallasTemperature.h> //library for temperature sensors // Ethernet settings byte mac[] = {0x09,0xA2,0xDA,0x00,0x01,0x26}; //Replace with your Ethernet shield MAC byte ip[] = { 192,168,0,54}; //The Arduino device IP address byte subnet[] = { 255,255,255,0}; byte gateway[] = { 192,168,0,1}; IPAddress server(192,168,0,53); // IP-adress of server arduino sends data to EthernetClient client; bool connected = false; void setup(void) { Serial.begin(9600); Serial.println("Initializing Ethernet."); delay(1000); Ethernet.begin(mac, ip , gateway , subnet); } void loop(void) { if(!connected) { Serial.println("Not connected"); if (client.connect(server, 80)) { connected = true; int temp =analogRead(A1); Serial.print("Temp is "); Serial.println(temp); Serial.println(); Serial.println("Sending to Server: "); client.print("GET /formSubmit.php?t0="); Serial.print("GET /formSubmit.php?t0="); client.print(temp); Serial.print(temp); client.println(" HTTP/1.1"); Serial.println(" HTTP/1.1"); client.println("Host: http://localhost/PhpProject1/"); Serial.println("Host: http://localhost/PhpProject1/"); client.println("User-Agent: Arduino"); Serial.println("User-Agent: Arduino"); client.println("Accept: text/html"); Serial.println("Accept: text/html"); //client.println("Connection: close"); //Serial.println("Connection: close"); client.println(); Serial.println(); delay(10000); } else{ Serial.println("Cannot connect to Server"); } } else { delay(1000); while (client.connected() && client.available()) { char c = client.read(); Serial.print(c); } Serial.println(); client.stop(); connected = false; } } the server is an Apache server running on a pc, the server ip address in the code is the pc ip address. For testing purposes I work at my homes network, there's no proxy or firewall, and I also turned of the antivirus and firewall on my pc. the result in the serial monitor is always: Not connected Cannot connect to Server Any thoughts??

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  • Database implementation question?

    - by gundam
    consider a disk with a sector size of 512 bytes, 2000 tracks/surface, 50 sectors/track, 5 doubled sided platters, average seek time is 10 msec. Assume a block size of 1024-byte is selected. Assume a file that contains 100,000 records of 100-byte each is to be stored on the disk, and NONE of the reocd can be spanned 2 blocks. How many blocks are needed to store the entire file?? If the file is arranged sequentially on disk, how many surfaces are required?? Now, i have calculated that 10,000 blocks are needed to store 100,000 records. But i am not sure how to find out the answer of the surfaces required. I only calculated the capacity of track is 25KB and capacity of surface is 50,000 KB But I don't know how to calculate the number of surfaces... Could anyone help me how to get the answer? Thanks a lot!!

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  • How to generalize a method call in Java (to avoid code duplication)

    - by dln385
    I have a process that needs to call a method and return its value. However, there are several different methods that this process may need to call, depending on the situation. If I could pass the method and its arguments to the process (like in Python), then this would be no problem. However, I don't know of any way to do this in Java. Here's a concrete example. (This example uses Apache ZooKeeper, but you don't need to know anything about ZooKeeper to understand the example.) The ZooKeeper object has several methods that will fail if the network goes down. In this case, I always want to retry the method. To make this easy, I made a "BetterZooKeeper" class that inherits the ZooKeeper class, and all of its methods automatically retry on failure. This is what the code looked like: public class BetterZooKeeper extends ZooKeeper { private void waitForReconnect() { // logic } @Override public Stat exists(String path, Watcher watcher) { while (true) { try { return super.exists(path, watcher); } catch (KeeperException e) { // We will retry. } waitForReconnect(); } } @Override public byte[] getData(String path, boolean watch, Stat stat) { while (true) { try { return super.getData(path, watch, stat); } catch (KeeperException e) { // We will retry. } waitForReconnect(); } } @Override public void delete(String path, int version) { while (true) { try { super.delete(path, version); return; } catch (KeeperException e) { // We will retry. } waitForReconnect(); } } } (In the actual program there is much more logic and many more methods that I took out of the example for simplicity.) We can see that I'm using the same retry logic, but the arguments, method call, and return type are all different for each of the methods. Here's what I did to eliminate the duplication of code: public class BetterZooKeeper extends ZooKeeper { private void waitForReconnect() { // logic } @Override public Stat exists(final String path, final Watcher watcher) { return new RetryableZooKeeperAction<Stat>() { @Override public Stat action() { return BetterZooKeeper.super.exists(path, watcher); } }.run(); } @Override public byte[] getData(final String path, final boolean watch, final Stat stat) { return new RetryableZooKeeperAction<byte[]>() { @Override public byte[] action() { return BetterZooKeeper.super.getData(path, watch, stat); } }.run(); } @Override public void delete(final String path, final int version) { new RetryableZooKeeperAction<Object>() { @Override public Object action() { BetterZooKeeper.super.delete(path, version); return null; } }.run(); return; } private abstract class RetryableZooKeeperAction<T> { public abstract T action(); public final T run() { while (true) { try { return action(); } catch (KeeperException e) { // We will retry. } waitForReconnect(); } } } } The RetryableZooKeeperAction is parameterized with the return type of the function. The run() method holds the retry logic, and the action() method is a placeholder for whichever ZooKeeper method needs to be run. Each of the public methods of BetterZooKeeper instantiates an anonymous inner class that is a subclass of the RetryableZooKeeperAction inner class, and it overrides the action() method. The local variables are (strangely enough) implicitly passed to the action() method, which is possible because they are final. In the end, this approach does work and it does eliminate the duplication of the retry logic. However, it has two major drawbacks: (1) it creates a new object every time a method is called, and (2) it's ugly and hardly readable. Also I had to workaround the 'delete' method which has a void return value. So, here is my question: is there a better way to do this in Java? This can't be a totally uncommon task, and other languages (like Python) make it easier by allowing methods to be passed. I suspect there might be a way to do this through reflection, but I haven't been able to wrap my head around it.

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  • Find duplicate images?

    - by stefan.at.wpf
    I need a software (for Windows) that finds duplicate images by comparing the actual image content. I have duplicates of images, once with metadata, one without, so the image is the same, but the file is not, so comparing the files byte by byte is not enough. Another requirement is, that I can delete all / several duplicates at once - I don't want to click 100 times "delete"! That is, what I actually would have to do using XnView ): I also checked the other topics here and Google, but if a programscompares the images in a perfect way (like XnView) it doesn't allow the deletion of several duplicates at once

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  • Database implementation question? [closed]

    - by gundam
    consider a disk with a sector size of 512 bytes, 2000 tracks/surface, 50 sectors/track, 5 doubled sided platters, average seek time is 10 msec. Assume a block size of 1024-byte is selected. Assume a file that contains 100,000 records of 100-byte each is to be stored on the disk, and NONE of the reocd can be spanned 2 blocks. How many blocks are needed to store the entire file?? If the file is arranged sequentially on disk, how many surfaces are required?? Now, i have calculated that 10,000 blocks are needed to store 100,000 records. But i am not sure how to find out the answer of the surfaces required. I only calculated the capacity of track is 25KB and capacity of surface is 50,000 KB But I don't know how to calculate the number of surfaces... Could anyone help me how to get the answer? Thanks a lot!!

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  • Sync video play over network

    - by Nemesis
    Hi, I have made a media player that plays basically anything that's scheduled to it via a text file. The player can also play the exact same clip on multiple machines(PC's). The problem is the syncing. The same video starts playing on each of the machines, but they are out by about 400ms, which looks crap and if there's sound it's even worse. What I do at the moment is: One machine is set up as the master and all other machines are set up as slaves. The master decides what item will be played. It waits for a message from each of the slaves, once all slaves are connected (or after the timeout), it broadcasts the item id of the file that needs to be played. All machines then start playing that file. What I also tried: I thought that the file loading time might be the major driving factor in the sync mismatch, so I chankged the code to do the following. The master still decides what file to play. It waits for the connect message from each slave (or timeout) and transmits the item id of the file to play. All machines start playing that file but pauses it immediately. The master then again waits for a ready message from each of the slaves. As soon as all slaves responded the master sends a play message to all slaves. All machines then continue the file. This unfortunately did not improve the problem. I am now pretty sure the sync mismatch is due to network delay. How can I compensate for this? Or maybe determine the delay to each slave? All network comms are done with winsock. Any thoughts or ideas is much appreciated.

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  • Java.lang.NullPointerException when using retreived Image (Unless method is used statically!)

    - by Emdiesse
    Hi there, This has been doing my head in all day and I have finally decided to resort to asking for help! In my MIDLet I have an instance of the java class ImageFetcher called anImg. Also within my MIDLet I have a command that simply say's fetch, a CommandListener that when detects fetch was clicked runs the function below. This function should simply run public getImage() from the anImg instance of class ImageFetcher which returns an image and then appends/sets this Image onto the form on the display. (You may recognise the getImage() function from the Nokia JavaME Wiki!!!) Instead of any image being displayed this is written to the output terminal in netbeans: Msg: Java.lang.NullPointerException HOWEVER, If I change public getImage() to public static getImage() and replace anImg.getImage() with ImageFetcher.getImage() the image is successfully displayed!!! Thank you for your replies on this issue :) I look forward to going my hair back after this ordeal! FetchImageApp.java ... ... ... private doThis(){ try { Image im; if ((im = anImg.getImage()) != null) { ImageItem ii = new ImageItem(null, im, ImageItem.LAYOUT_DEFAULT, null); // If there is already an image, set (replace) it if (form.size() != 0) { form.set(0, ii); } else // Append the image to the empty form { form.append(ii); } } else { form.append("Unsuccessful download."); } // Display the form with the image display.setCurrent(form); } catch (Exception e) { System.err.println("Msg: " + e.toString()); } } ... ... ... ImageFetcher.java ... ... ... /*-------------------------------------------------- * Open connection and download png into a byte array. *-------------------------------------------------*/ public Image getImage() throws IOException { String url = "http://kenai.com/attachments/wiki_images/chessgame/java-duke-logo.png"; ContentConnection connection = (ContentConnection) Connector.open(url); // * There is a bug in MIDP 1.0.3 in which read() sometimes returns // an invalid length. To work around this, I have changed the // stream to DataInputStream and called readFully() instead of read() // InputStream iStrm = connection.openInputStream(); DataInputStream iStrm = connection.openDataInputStream(); ByteArrayOutputStream bStrm = null; Image im = null; try { // ContentConnection includes a length method byte imageData[]; int length = (int) connection.getLength(); if (length != -1) { imageData = new byte[length]; // Read the png into an array // iStrm.read(imageData); iStrm.readFully(imageData); } else // Length not available... { bStrm = new ByteArrayOutputStream(); int ch; while ((ch = iStrm.read()) != -1) { bStrm.write(ch); } imageData = bStrm.toByteArray(); bStrm.close(); } // Create the image from the byte array im = Image.createImage(imageData, 0, imageData.length); } finally { // Clean up if (iStrm != null) { iStrm.close(); } if (connection != null) { connection.close(); } if (bStrm != null) { bStrm.close(); } } return (im == null ? null : im); } ... ... ...

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  • How can i get more than one jpg. or txt file from any folder?

    - by Phsika
    Dear Sirs; i have two Application to listen network Stream : Server.cs on the other hand; send file Client.cs. But i want to send more files on a stream from any folder. For example. i have C:/folder whish has got 3 jpg files. My client must run. Also My server.cs get files on stream: Client.cs: private void btn_send2_Click(object sender, EventArgs e) { string[] paths= null; paths= System.IO.Directory.GetFiles(@"C:\folder" + @"\", "*.jpg", System.IO.SearchOption.AllDirectories); byte[] Dizi; TcpClient Gonder = new TcpClient("127.0.0.1", 51124); FileStream Dosya; FileInfo Dos; NetworkStream Akis; foreach (string path in paths) { Dosya = new FileStream(path , FileMode.OpenOrCreate); Dos = new FileInfo(path ); Dizi = new byte[(int)Dos.Length]; Dosya.Read(Dizi, 0, (int)Dos.Length); Akis = Gonder.GetStream(); Akis.Write(Dizi, 0, (int)Dosya.Length); Gonder.Close(); Akis.Flush(); Dosya.Close(); } } Also i have Server.cs void Dinle() { TcpListener server = null; try { Int32 port = 51124; IPAddress localAddr = IPAddress.Parse("127.0.0.1"); server = new TcpListener(localAddr, port); server.Start(); Byte[] bytes = new Byte[1024 * 250000]; // string ReceivedPath = "C:/recieved"; while (true) { MessageBox.Show("Waiting for a connection... "); TcpClient client = server.AcceptTcpClient(); MessageBox.Show("Connected!"); NetworkStream stream = client.GetStream(); if (stream.CanRead) { saveFileDialog1.ShowDialog(); // burasi degisecek string pathfolder = saveFileDialog1.FileName; StreamWriter yaz = new StreamWriter(pathfolder); string satir; StreamReader oku = new StreamReader(stream); while ((satir = oku.ReadLine()) != null) { satir = satir + (char)13 + (char)10; yaz.WriteLine(satir); } oku.Close(); yaz.Close(); client.Close(); } } } catch (SocketException e) { Console.WriteLine("SocketException: {0}", e); } finally { // Stop listening for new clients. server.Stop(); } Console.WriteLine("\nHit enter to continue..."); Console.Read(); } Please look Client.cs: icollected all files from "c:\folder" paths= System.IO.Directory.GetFiles(@"C:\folder" + @"\", "*.jpg", System.IO.SearchOption.AllDirectories); My Server.cs how to get all files from stream?

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  • Image Preview in ASP.NET MVC

    - by imran_ku07
      Introduction :         Previewing an image is a great way to improve the UI of your site. Also it is always best to check the file type, size and see a preview before submitting the whole form. There are some ways to do this using simple JavaScript but not work in all browsers (like FF3).In this Article I will show you how do this using ASP.NET MVC application. You also see how this will work in case of nested form.   Description :          Create a new ASP.NET MVC project and then add a file upload and image control into your View. <form id="form1" method="post" action="NerdDinner/ImagePreview/AjaxSubmit">            <table>                <tr>                    <td>                        <input type="file" name="imageLoad1" id="imageLoad1"  onchange="ChangeImage(this,'#imgThumbnail')" />                    </td>                </tr>                <tr>                    <td align="center">                        <img src="images/TempImage.gif" id="imgThumbnail" height="200px" width="200px">                     </td>                </tr>            </table>        </form>           Note that here NerdDinner is refers to the virtual directory name, ImagePreview is the Controller and ImageLoad is the action name which you will see shortly          I will use the most popular jQuery form plug-in, that turns a form into an AJAX form with very little code. Therefore you must get these from Jquery site and then add these files into your page.          <script src="NerdDinner/Scripts/jquery-1.3.2.js" type="text/javascript"></script>        <script src="NerdDinner/Scripts/jquery.form.js" type="text/javascript"></script>            Then add the javascript function. <script type="text/javascript">function ChangeImage(fileId,imageId){ $("#form1").ajaxSubmit({success: function(responseText){ var d=new Date(); $(imageId)[0].src="NerdDinner/ImagePreview/ImageLoad?a="+d.getTime(); } });}</script>             This function simply submit the form named form1 asynchronously to ImagePreviewController's method AjaxSubmit and after successfully receiving the response, it will set the image src property to the action method ImageLoad. Here I am also adding querystring, preventing the browser to serve the cached image.           Now I will create a new Controller named ImagePreviewController. public class ImagePreviewController : Controller { [AcceptVerbs(HttpVerbs.Post)] public ActionResult AjaxSubmit(int? id) { Session["ContentLength"] = Request.Files[0].ContentLength; Session["ContentType"] = Request.Files[0].ContentType; byte[] b = new byte[Request.Files[0].ContentLength]; Request.Files[0].InputStream.Read(b, 0, Request.Files[0].ContentLength); Session["ContentStream"] = b; return Content( Request.Files[0].ContentType+";"+ Request.Files[0].ContentLength ); } public ActionResult ImageLoad(int? id) { byte[] b = (byte[])Session["ContentStream"]; int length = (int)Session["ContentLength"]; string type = (string)Session["ContentType"]; Response.Buffer = true; Response.Charset = ""; Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.ContentType = type; Response.BinaryWrite(b); Response.Flush(); Session["ContentLength"] = null; Session["ContentType"] = null; Session["ContentStream"] = null; Response.End(); return Content(""); } }             The AjaxSubmit action method will save the image in Session and return content type and content length in response. ImageLoad action method will return the contents of image in response.Then clear these Sessions.           Just run your application and see the effect.   Checking Size and Content Type of File:          You may notice that AjaxSubmit action method is returning both content type and content length. You can check both properties before submitting your complete form.     $(myform).ajaxSubmit({success: function(responseText)            {                                var contentType=responseText.substring(0,responseText.indexOf(';'));                var contentLength=responseText.substring(responseText.indexOf(';')+1);                // Here you can do your validation                var d=new Date();                $(imageId)[0].src="http://weblogs.asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime();            }        });  Handling Nested Form Case:          The above code will work if you have only one form. But this is not the case always.You may have a form control which wraps all the controls and you do not want to submit the whole form, just for getting a preview effect.           In this case you need to create a dynamic form control using JavaScript, and then add file upload control to this form and submit the form asynchronously  function ChangeImage(fileId,imageId)         {            var myform=document.createElement("form");                    myform.action="NerdDinner/ImagePreview/AjaxSubmit";            myform.enctype="multipart/form-data";            myform.method="post";            var imageLoad=document.getElementById(fileId).cloneNode(true);            myform.appendChild(imageLoad);            document.body.appendChild(myform);            $(myform).ajaxSubmit({success: function(responseText)                {                                    var contentType=responseText.substring(0,responseText.indexOf(';'));                    var contentLength=responseText.substring(responseText.indexOf(';')+1);                    var d=new Date();                    $(imageId)[0].src="http://weblogs.asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime();                    document.body.removeChild(myform);                }            });        }            You also need append the child in order to send request and remove them after receiving response.

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  • "const char *" is incompatible with parameter of type "LPCWSTR" error

    - by N0xus
    I'm trying to incorporate some code from Programming an RTS Game With Direct3D into my game. Before anyone says it, I know the book is kinda old, but it's the particle effects system he creates that I'm trying to use. With his shader class, he intialise it thusly: void SHADER::Init(IDirect3DDevice9 *Dev, const char fName[], int typ) { m_pDevice = Dev; m_type = typ; if(m_pDevice == NULL)return; // Assemble and set the pixel or vertex shader HRESULT hRes; LPD3DXBUFFER Code = NULL; LPD3DXBUFFER ErrorMsgs = NULL; if(m_type == PIXEL_SHADER) hRes = D3DXCompileShaderFromFile(fName, NULL, NULL, "Main", "ps_2_0", D3DXSHADER_DEBUG, &Code, &ErrorMsgs, &m_pConstantTable); else hRes = D3DXCompileShaderFromFile(fName, NULL, NULL, "Main", "vs_2_0", D3DXSHADER_DEBUG, &Code, &ErrorMsgs, &m_pConstantTable); } How ever, this generates the following error: Error 1 error C2664: 'D3DXCompileShaderFromFileW' : cannot convert parameter 1 from 'const char []' to 'LPCWSTR' The compiler states the issue is with fName in the D3DXCompileShaderFromFile line. I know this has something to do with the character set, and my program was already running with a Unicode Character set on the go. I read that to solve the above problem, I need to switch to a multi-byte character set. But, if I do that, I get other errors in my code, like so: Error 2 error C2664: 'D3DXCreateEffectFromFileA' : cannot convert parameter 2 from 'const wchar_t *' to 'LPCSTR' With it being accredited to the following line of code: if(FAILED(D3DXCreateEffectFromFile(m_pD3DDevice9,effectFileName.c_str(),NULL,NULL,0,NULL,&m_pCurrentEffect,&pErrorBuffer))) This if is nested within another if statement checking my effectmap list. Though it is the FAILED word with the red line. Like wise I get the another error with the following line of code: wstring effectFileName = TEXT("Sky.fx"); With the error message being: Error 1 error C2440: 'initializing' : cannot convert from 'const char [7]' to 'std::basic_string<_Elem,_Traits,_Ax' If I change it back to a Uni code character set, I get the original (fewer) errors. Leaving as a multi-byte, I get more errors. Does anyone know of a way I can fix this issue?

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  • OAF Page to Upload Files into Server from local Machine

    - by PRajkumar
    1. Create a New Workspace and Project File > New > General > Workspace Configured for Oracle Applications File Name – PrajkumarFileUploadDemo   Automatically a new OA Project will also be created   Project Name -- FileUploadDemo Default Package -- prajkumar.oracle.apps.fnd.fileuploaddemo   2. Create a New Application Module (AM) Right Click on FileUploadDemo > New > ADF Business Components > Application Module Name -- FileUploadAM Package -- prajkumar.oracle.apps.fnd.fileuploaddemo.server Check Application Module Class: FileUploadAMImpl Generate JavaFile(s)   3. Create a New Page Right click on FileUploadDemo > New > Web Tier > OA Components > Page Name -- FileUploadPG Package -- prajkumar.oracle.apps.fnd.fileuploaddemo.webui   4. Select the FileUploadPG and go to the strcuture pane where a default region has been created   5. Select region1 and set the following properties --     Attribute Property ID PageLayoutRN AM Definition prajkumar.oracle.apps.fnd.fileuploaddemo.server.FileUploadAM Window Title Uploading File into Server from Local Machine Demo Window Title Uploading File into Server from Local Machine Demo     6. Create Stack Layout Region Under Page Layout Region Right click PageLayoutRN > New > Region   Attribute Property ID MainRN AM Definition messageComponentLayout   7. Create a New Item messageFileUpload Bean under MainRN Right click on MainRN > New > messageFileUpload Set Following Properties for New Item --   Attribute Property ID MessageFileUpload Item Style messageFileUpload   8. Create a New Item Submit Button Bean under MainRN Right click on MainRN > New > messageLayout Set Following Properties for messageLayout --   Attribute Property ID ButtonLayout   Right Click on ButtonLayout > New > Item   Attribute Property ID Submit Item Style submitButton Attribute Set /oracle/apps/fnd/attributesets/Buttons/Go   9. Create Controller for page FileUploadPG Right Click on PageLayoutRN > Set New Controller Package Name: prajkumar.oracle.apps.fnd.fileuploaddemo.webui Class Name: FileUploadCO   Write Following Code in FileUploadCO processFormRequest   import oracle.cabo.ui.data.DataObject; import java.io.FileOutputStream; import java.io.InputStream; import oracle.jbo.domain.BlobDomain; import java.io.File; import oracle.apps.fnd.framework.OAException; public void processFormRequest(OAPageContext pageContext, OAWebBean webBean) { super.processFormRequest(pageContext, webBean);    if(pageContext.getParameter("Submit")!=null)  {   upLoadFile(pageContext,webBean);      } }   -- Use Following Code if want to Upload Files in Local Machine -- ----------------------------------------------------------------------------------- public void upLoadFile(OAPageContext pageContext,OAWebBean webBean) { String filePath = "D:\\PRajkumar";  System.out.println("Default File Path---->"+filePath);  String fileUrl = null;  try  {   DataObject fileUploadData =  pageContext.getNamedDataObject("MessageFileUpload"); //FileUploading is my MessageFileUpload Bean Id   if(fileUploadData!=null)   {    String uFileName = (String)fileUploadData.selectValue(null, "UPLOAD_FILE_NAME");  // include this line    String contentType = (String) fileUploadData.selectValue(null, "UPLOAD_FILE_MIME_TYPE");  // For Mime Type    System.out.println("User File Name---->"+uFileName);    FileOutputStream output = null;    InputStream input = null;    BlobDomain uploadedByteStream = (BlobDomain)fileUploadData.selectValue(null, uFileName);    System.out.println("uploadedByteStream---->"+uploadedByteStream);                               File file = new File("D:\\PRajkumar", uFileName);    System.out.println("File output---->"+file);    output = new FileOutputStream(file);    System.out.println("output----->"+output);    input = uploadedByteStream.getInputStream();    System.out.println("input---->"+input);    byte abyte0[] = new byte[0x19000];    int i;         while((i = input.read(abyte0)) > 0)    output.write(abyte0, 0, i);    output.close();    input.close();   }  }  catch(Exception ex)  {   throw new OAException(ex.getMessage(), OAException.ERROR);  }     }   -- Use Following Code if want to Upload File into Server -- ------------------------------------------------------------------------- public void upLoadFile(OAPageContext pageContext,OAWebBean webBean) { String filePath = "/u01/app/apnac03r12/PRajkumar/";  System.out.println("Default File Path---->"+filePath);  String fileUrl = null;  try  {   DataObject fileUploadData =  pageContext.getNamedDataObject("MessageFileUpload");  //FileUploading is my MessageFileUpload Bean Id     if(fileUploadData!=null)   {    String uFileName = (String)fileUploadData.selectValue(null, "UPLOAD_FILE_NAME");   // include this line    String contentType = (String) fileUploadData.selectValue(null, "UPLOAD_FILE_MIME_TYPE");   // For Mime Type    System.out.println("User File Name---->"+uFileName);    FileOutputStream output = null;    InputStream input = null;    BlobDomain uploadedByteStream = (BlobDomain)fileUploadData.selectValue(null, uFileName);    System.out.println("uploadedByteStream---->"+uploadedByteStream);                               File file = new File("/u01/app/apnac03r12/PRajkumar", uFileName);    System.out.println("File output---->"+file);    output = new FileOutputStream(file);    System.out.println("output----->"+output);    input = uploadedByteStream.getInputStream();    System.out.println("input---->"+input);    byte abyte0[] = new byte[0x19000];    int i;         while((i = input.read(abyte0)) > 0)    output.write(abyte0, 0, i);    output.close();    input.close();   }  }  catch(Exception ex)  {   throw new OAException(ex.getMessage(), OAException.ERROR);  }     }   10. Congratulation you have successfully finished. Run Your page and Test Your Work           -- Used Code to Upload files into Server   -- Before Upload files into Server     -- After Upload files into Server       -- Used Code to Upload files into Local Machine   -- Before Upload files into Local Machine       -- After Upload files into Local Machine

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