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  • Replace string with incremented value

    - by Andrei
    Hello, I'm trying to write a CSS parser to automatically dispatch URLs in background images to different subdomains in order to parallelize downloads. Basically, I want to replace things like url(/assets/some-background-image.png) with url(http://assets[increment].domain.com/assets/some-background-image.png) I'm using this inside a class that I eventually want to evolve into doing various CSS parsing tasks. Here are the relevant parts of the class : private function parallelizeDownloads(){ static $counter = 1; $newURL = "url(http://assets".$counter.".domain.com"; The counter needs to be reset when it reaches 4 in order to limit to 4 subdomains. if ($counter == 4) { $counter = 1; } $counter ++; return $newURL; } public function replaceURLs() { This is mostly nonsense, but I know the code I'm looking for looks somewhat like this. Note : $this-css contains the CSS string. preg_match("/url/i",$this->css,$match); foreach($match as $URL) { $newURL = self::parallelizeDownloads(); $this->css = str_replace($match, $newURL,$this->css); } }

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  • Removing a pattern from the beggining and end of a string in ruby

    - by seaneshbaugh
    So I found myself needing to remove <br /> tags from the beginning and end of strings in a project I'm working on. I made a quick little method that does what I need it to do but I'm not convinced it's the best way to go about doing this sort of thing. I suspect there's probably a handy regular expression I can use to do it in only a couple of lines. Here's what I got: def remove_breaks(text) if text != nil and text != "" text.strip! index = text.rindex("<br />") while index != nil and index == text.length - 6 text = text[0, text.length - 6] text.strip! index = text.rindex("<br />") end text.strip! index = text.index("<br />") while index != nil and index == 0 text = test[6, text.length] text.strip! index = text.index("<br />") end end return text end Now the "<br />" could really be anything, and it'd probably be more useful to make a general use function that takes as an argument the string that needs to be stripped from the beginning and end. I'm open to any suggestions on how to make this cleaner because this just seems like it can be improved.

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  • Efficient way in Python to remove an element from a comma-separated string

    - by ensnare
    I'm looking for the most efficient way to add an element to a comma-separated string while maintaining alphabetical order for the words: For example: string = 'Apples, Bananas, Grapes, Oranges' subtraction = 'Bananas' result = 'Apples, Grapes, Oranges' Also, a way to do this but while maintaining IDs: string = '1:Apples, 4:Bananas, 6:Grapes, 23:Oranges' subtraction = '4:Bananas' result = '1:Apples, 6:Grapes, 23:Oranges' Sample code is greatly appreciated. Thank you so much.

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  • How to find image width and height dynamically and specify height, width attibutes if over certain d

    - by Wbdvlpr
    Hi, I display some data on my website and one of the data feed elements is an image. [title] => Product title [description] => some description [image] => www.some-domain.com/product-image/p12345.jpg I then display this image using <img alt="product" src="<?=$data['image']?>" /> Most of the images are 80x80, 120x100 or other less than 150 in width, which perfectly fit in the website template, but some of them are quite large such as 800x600 which distort the layout. I want a control on these types. I tried to set WIDTH="150", but as the width vary they dont look good. I was thinking If I could set a fixed width to images, say, larger than 250px then I can live with it for now. Any ideas how to achieve this? Thanks

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  • Distributing a function over a single dimension of an array in MATLAB?

    - by Alex Feinman
    I often find myself wanting to collapse an n-dimensional matrix across one dimension, and can't figure out if there is a concise incantation I can use to do this. For example, when parsing an image, I often want to do something like this. (Note! Illustrative example only. I know about rgb2gray for this specific case.) img = imread('whatever.jpg'); s = size(img); for i=1:s(1) for j=1:s(2) bw_img = mean(img(i,j,:)); end end I would love to express this as something like: bw = on(color, 3, @mean); or bw(:,:,1) = mean(color); Is there a short way to do this?

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  • How to turn such string into a data grid? (C# .Net)

    - by Ole Jak
    So I have such string (recived from php server... normal print_r of array) Array ( [item_number_in_array] => Array ( [id] => id_value [title] title_value_as_string_vith_spaces [content] => content_value_as_string_vith_spaces ) [item_number_in_array]... ) I need any how to represent it as table like this in C# How to do such thing?

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  • How to lowercase every element of a collection efficiently?

    - by Chris
    Whats the most efficient way to lower case every element of a list or set? My idea for a List: final List<String> strings = new ArrayList<String>(); strings.add("HELLO"); strings.add("WORLD"); for(int i=0,l=strings.size();i<l;++i) { strings.add(strings.remove(0).toLowerCase()); } is there a better, faster way? How would this exmaple look like for a set? As there is currently no method for applying an operation to each element of a set (or list) can it be done without creating an additional temporary set? Something like this would be nice: Set<String> strings = new HashSet<String>(); strings.apply( function (element) { this.replace(element, element.toLowerCase();) } ); Thanks,

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  • Find a part of UNC path and put in a variable?

    - by Refracted Paladin
    I am trying to peel off the last part of a unc path that is being passed and put it in a variable to use in a method further down the line. Example path would be -- \\ourfileserver\remoteuploads\countyfoldername\personfoldername How do I peel just the countyfoldername out of that? I had thought to try var th = e.FullPath.LastIndexOf('\\'); var whichFolder = folderPath.Substring(th); but that is an escape character and it doesn't like @ either. Is this even the right direction?

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  • Splitting 25mb .txt file into smaller files using text delimiter

    - by user574141
    Regards, SO I am new to python and Perl. I have been trying to solve a simple problem and getting tied in knots with syntax. I hope someone has the time and patience to help. I have a 25mb file in ".txt" format which contains news-wire articles going back to 1970. Each news story is concatenated to the next, with only the "Copyright" statement to delimit. Each news story starts with "Item XX of XXX DOCUMENTS". There are certain metadata that are repeated throughout, I will use these for tagging later on. I wish to split this 25mb file into separate .txt files, each containing one news story (i.e. the text between "DOCUMENTS" and "Copyright", saving each with a different name (obviously). I am trying to 1 ) open the file... 2) iterate over lines in the file checking for the eof delimiter, and if it is not present writing the line to a list 3)write that list to a seperate small file. I'm having big problems with changing filenames using the counter, and how do I make Python start from where I left off, is the "seek" function appropriate? so far I have been trying this approach, completely unsuccessfully: myfile = open ("myfile.txt", 'r') filenumber = 0 for line in myfile.readline(): filenumber += 1 w=0 while myfile.readline() != '\s+DOCUMENTS\s*\n' ### read my line into a list mysmallfile()['w'] = [myfile.readline()] w += 1 output = open('C:\\Users\\dunner7\\Documents\###how do I change the filename each iteration???', 'w') output.writelines(mysmallfile) ###go back to start. Thank you for your time and patience. RD

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  • ruby - find and replace in a string for commonly used street suffix

    - by go minimal
    The post office actually publishes a list of commonly used street suffixes in addresses: http://www.usps.com/ncsc/lookups/abbr_suffix.txt I want to take this list and make a ruby function that takes a string, takes the last word ("183 main strt".split[' '].last) and if it matches any of the commonly used street suffixes ("strt"), replace it with the official Postal Service Standard Suffix ("st"). Is there a better way to approach this than a massive str.sub.sub.sub.sub.sub?

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  • Rich image scroll and zooming on android

    - by F0RR
    I'm looking for a way to implement image zoom and scrolling the way it is implemented in Droid Comic Viewer. Is there any quick way to do that? If not, then could you please give some advices at least on implementing kinetic scrolling.

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  • How do I select and group by a portion of a string?

    - by Russ Bradberry
    Given I have data like the following, how can I select and group by portions of a string? Version Users 1.1.1 1 1.1.23 3 1.1.45 1 2.1.24 3 2.1.12 1 2.1.45 3 3.1.10 1 3.1.23 3 What I want is to sum up the users using version 1.1.x and 2.2.x and 3.3.x etc, but I'm not sure how I can group on a partial string in a select statement. edit What the data should return like is this: Version Users 1.1.XX 5 2.1.XX 7 3.1.XX 4 There is an infinite variable number of versions, some are in this format (major, minor, build) some are just major, minor and some are just major, the only time I want to "roll up" the versions is when there is a build.

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  • Need to get pixel averages of a vector sitting on a bitmap...

    - by user346511
    I'm currently involved in a hardware project where I am mapping triangular shaped LED to traditional bitmap images. I'd like to overlay a triangle vector onto an image and get the average pixel data within the bounds of that vector. However, I'm unfamiliar with the math needed to calculate this. Does anyone have an algorithm or a link that could send me in the right direction? I'm not even clear what this type of math is called. I've created a basic image of what I'm trying to capture here: http://imgur.com/Isjip.gif

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  • How can I do the multiple replace in python?

    - by prosseek
    As asked and answered in HERE, I need to replace '[' with '[[]', and ']' with '[]]'. I tried to use s.replace(), but as it's not in place change, I ran as follows to get a wrong anwser. path1 = "/Users/smcho/Desktop/bracket/[10,20]" path2 = path1.replace('[','[[]') path3 = path2.replace(']','[]]') pathName = os.path.join(path3, "*.txt") print pathName -- /Users/smcho/Desktop/bracket/[[[]]10,20[]]/*.txt How can I do the multiple replace in python? Or how can I replace '[' and ']' at the same time?

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