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  • Security measures for CentOS

    - by cappuccinodrinker
    I have been tightening up my web server security and wanted to know what else I can do. I am running CentOS 5 with these measures: - All passwords to FTP, MySQL etc are generated from grc.com/passwords.htm and microsoft.com/protect/fraud/passwords/create.aspx (for the ones which cannot be too long). - Running iptables with all ports shut off except for http mail and smtp, the important ports like FTP SSH are blocked to all except my static office IP. There is also no response to pings. - Rootkit Hunter running daily - The server is PCI compliant according to Comodo - Not running any crappy made php apps, we use Zend Framework for our stuff and do have kayako installed and keep them up to date. Can't really think of anything else I can do... I could implement a brute force measure, but I think I already have by simply changing my SSH port to a number above 10000 and blocking it off with iptables.

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  • Using a AWS EC2 Server to host a busy website and I need to set up a loadbalancing

    - by Philip Isaacs
    My company has one EC2 server running on AWS with a MYSQL-DB and Apache on the same instance. This one instance hosts a website built on PHP Zend Framework. The site runs like crap when it starts to get busy with a lot of traffic so I'm looking for some advice on how to set up something that can handle the load better. My first question is should I move the mysql DB on to a separate EC2 instance or perhaps use AWS's RDS service which looks like a nice option. I'm sort of new to some of this but I'm guessing I'll need at least two EC2 instances for serving the website from and some sort of load balancing mechanism to distribute traffic. But maybe not, I'm not sure. Also what are some best practices for how to replicate the data so that they stay in sync on both instances? Okay I know these are a lot of questions. But I don't know where to start so any advice will help.

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  • How to follow up new technologies and software releases as they come out

    - by Developer
    I don't know if this is right place to ask question, if not please move it to right area please. Is there a website/app/forum/newsletter where I can followup different softwares or technology and feature soon after their new releases. i.e. ipad iphone ios 7 release as soon as it will release with its feature. andriod next version soon after it release with its feature. coreldraw x7 whenever it will rlease zend framework new version when ever it will release. mac php new version photoshop new version ....... there are lot more list than that which goes on and on and Its difficult to follow up new technology as they come out. Any better and less time consuming way to follow up.

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  • Setting a mapped drive in Virtual hosts causes apache to not start

    - by darksoulsong
    I´m trying to set a virtual host on my windows 7 machine. The folder I want to point to is located on a centOS machine and the folder path is Z:\Websites\Online\MyClient\Site. But something strange happens when I set the document root like this: DocumentRoot "Z:\Websites\Online\MyClient\Site" Apache do not restarts after that. When I take a look at the log, there is an error pointing to that line, where I added the path to the folder: Syntax error on line 48 of C:/Program Files/Zend/Apache2/conf/extra/httpd-vhosts.conf: DocumentRoot must be a directory. There must be a way to make it work like this, by setting an Apache Installation on a machine and pointing it to a folder located on another computer, right? My hosts file is set like this: 172.17.10.1\Data\Websites\Online\MyClient\Site MyClient.local ANY HELP would be VERY appreciated.

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  • Webserver - Memory-bound or CPU-bound? [closed]

    - by JJP
    Possible Duplicate: How do you do Load Testing and Capacity Planning for Web Sites I'm installing a social network using Zend Framework & MySql, with lots of plugins & queries. I want Webserver & Sql server on one box. I'm trying to choose between two machines (on hetzner.de): A) intel i7-2600 3.4 GHz 16 GB DDR3 RAM B) intel i7-920 2.6 GHz 24 GB DDR3 RAM B has 50% more RAM but 30% slower clock speed. Q is: is it obvious where the bottleneck will be? Would I ever need 24GB of RAM, even with lots of concurrent users?

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  • How to declare dependent style names with UiBinder

    - by Eduard Wirch
    I have a simple UiBinder widget containing a TextArea: <!DOCTYPE ui:UiBinder SYSTEM "http://dl.google.com/gwt/DTD/xhtml.ent"> <ui:UiBinder xmlns:ui="urn:ui:com.google.gwt.uibinder" xmlns:g="urn:import:com.google.gwt.user.client.ui"> <g:TextArea visibleLines="3" /> </ui:UiBinder> I want to control the background color of this textarea for writeable and read only states. GWT uses the "-readonly" style name decorator to achieve this. So I try this: <!DOCTYPE ui:UiBinder SYSTEM "http://dl.google.com/gwt/DTD/xhtml.ent"> <ui:UiBinder xmlns:ui="urn:ui:com.google.gwt.uibinder" xmlns:g="urn:import:com.google.gwt.user.client.ui"> <ui:style> .textBoxStyle { background-color:yellow; } .textBoxStyle-readonly { background-color:lightgray; } </ui:style> <g:TextArea styleName="{style.textBoxStyle}" visibleLines="3" /> </ui:UiBinder> Obviously this won't work because style names are obfuscated for CssResources resulting in something like this: .G1x26wpeN { background-color:yellow } .G1x26wpeO { background-color: lightgray; } The result HTML for writeable textarea looks like this: <textarea tabindex="0" class="G1x26wpeN" rows="3"/> The read only textarea looks like this: <textarea tabindex="0" class="G1x26wpeN G1x26wpeN-readonly" readonly="" rows="3"/> How do I declare the style so GWT will obfuscate the primary part but not the "-readonly" decdorator? I know that I can disable the obfuscation for the entire style name. But I'd like to keep the obfuscation while making use of the decorators.

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  • sitemesh vs jsp-config (<include-prelude>)

    - by Nrj
    Please help clarifying : In web.xml I have the following <jsp-config> <jsp-property-group> <url-pattern>*.jsp</url-pattern> <el-ignored>false</el-ignored> <page-encoding>utf-8</page-encoding> <include-prelude>/jstlTaglibs.jspf</include-prelude> </jsp-property-group> </jsp-config> Also in decorators.xml I have <decorator name="footer" page="footer.jsp"> <pattern>*.action</pattern> </decorator> which is used via sitemesh.xml. The footer.jsp which says ... <decorator:body /> <@include .. "footer.jsp"/> So what I gather is, both of the codes above in a sense inject some jspf. Please help highlighting the differences and benefits of both the approaches. Also which one is more used across industry ?

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  • Login URL using authentication information in Django

    - by fuSi0N
    I'm working on a platform for online labs registration for my university. Login View [project views.py] from django.http import HttpResponse, HttpResponseRedirect, Http404 from django.shortcuts import render_to_response from django.template import RequestContext from django.contrib import auth def index(request): return render_to_response('index.html', {}, context_instance = RequestContext(request)) def login(request): if request.method == "POST": post = request.POST.copy() if post.has_key('username') and post.has_key('password'): usr = post['username'] pwd = post['password'] user = auth.authenticate(username=usr, password=pwd) if user is not None and user.is_active: auth.login(request, user) if user.get_profile().is_teacher: return HttpResponseRedirect('/teachers/'+user.username+'/') else: return HttpResponseRedirect('/students/'+user.username+'/') else: return render_to_response('index.html', {'msg': 'You don\'t belong here.'}, context_instance = RequestContext(request) return render_to_response('login.html', {}, context_instance = RequestContext(request)) def logout(request): auth.logout(request) return render_to_response('index.html', {}, context_instance = RequestContext(request)) URLS #========== PROJECT URLS ==========# urlpatterns = patterns('', (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT }), (r'^admin/', include(admin.site.urls)), (r'^teachers/', include('diogenis.teachers.urls')), (r'^students/', include('diogenis.students.urls')), (r'^login/', login), (r'^logout/', logout), (r'^$', index), ) #========== TEACHERS APP URLS ==========# urlpatterns = patterns('', (r'^(?P<username>\w{0,50})/', labs), ) The login view basically checks whether the logged in user is_teacher [UserProfile attribute via get_profile()] and redirects the user to his profile. Labs View [teachers app views.py] from django.http import HttpResponse, HttpResponseRedirect, Http404 from django.shortcuts import render_to_response from django.template import RequestContext from django.contrib.auth.decorators import user_passes_test from django.contrib.auth.models import User from accounts.models import * from labs.models import * def user_is_teacher(user): return user.is_authenticated() and user.get_profile().is_teacher @user_passes_test(user_is_teacher, login_url="/login/") def labs(request, username): q1 = User.objects.get(username=username) q2 = u'%s %s' % (q1.last_name, q1.first_name) q2 = Teacher.objects.get(name=q2) results = TeacherToLab.objects.filter(teacher=q2) return render_to_response('teachers/labs.html', {'results': results}, context_instance = RequestContext(request)) I'm using @user_passes_test decorator for checking whether the authenticated user has the permission to use this view [labs view]. The problem I'm having with the current logic is that once Django authenticates a teacher user he has access to all teachers profiles basically by typing the teachers username in the url. Once a teacher finds a co-worker's username he has direct access to his data. Any suggestions would be much appreciated.

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  • Tracking Down a Stack Overflow in My Linq Query

    - by Lazarus
    I've written the following Linq query: IQueryable<ISOCountry> entries = (from e in competitorRepository.Competitors join c in countries on e.countryID equals c.isoCountryCode where !e.Deleted orderby c.isoCountryCode select new ISOCountry() { isoCountryCode = e.countryID, Name = c.Name }).Distinct(); The objective is to retrieve a list of the countries represented by the competitors found in the system. 'countries' is an array of ISOCountry objects explicitly created and returned as an IQueryable (ISOCountry is an object of just two strings, isoCountryCode and Name). Competitors is an IQueryable which is bound to a database table through Linq2SQL though I created the objects from scratch and used the Linq data mapping decorators. For some reason this query causes a stack overflow when the system tries to execute it. I've no idea why, I've tried trimming the Distinct, returning an anonymous type of the two strings, using 'select c', all result in the overflow. The e.CountryID value is populated from a dropdown that was in itself populated from the IQueryable so I know the values are appropriate but even if not I wouldn't expect a stack overflow. Can anyone explain why the overflow is occurring or give good speculation as to why it might be happening? EDIT As requested, code for ISOCountry: public class ISOCountry { public string isoCountryCode { get; set; } public string Name { get; set; } }

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  • python-social-auth AuthCanceled exception

    - by vero4ka
    I'm using python-social-auth in my Django application for authentication via Facebook. But when a user tries to login and when it's been refirected to Facebook app page clicks on "Cancel" button, appears the following exception: ERROR 2014-01-03 15:32:15,308 base :: Internal Server Error: /complete/facebook/ Traceback (most recent call last): File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/django/core/handlers/base.py", line 114, in get_response response = wrapped_callback(request, *callback_args, **callback_kwargs) File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/django/views/decorators/csrf.py", line 57, in wrapped_view return view_func(*args, **kwargs) File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/social/apps/django_app/utils.py", line 45, in wrapper return func(request, backend, *args, **kwargs) File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/social/apps/django_app/views.py", line 21, in complete redirect_name=REDIRECT_FIELD_NAME, *args, **kwargs) File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/social/actions.py", line 54, in do_complete *args, **kwargs) File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/social/strategies/base.py", line 62, in complete return self.backend.auth_complete(*args, **kwargs) File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/social/backends/facebook.py", line 63, in auth_complete self.process_error(self.data) File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/social/backends/facebook.py", line 56, in process_error super(FacebookOAuth2, self).process_error(data) File "/home/vera/virtualenv/myapp/local/lib/python2.7/site-packages/social/backends/oauth.py", line 312, in process_error raise AuthCanceled(self, data.get('error_description', '')) AuthCanceled: Authentication process canceled Is the any way to catch it Django?

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  • Matplotlib canvas drawing

    - by Morgoth
    Let's say I define a few functions to do certain matplotlib actions, such as def dostuff(ax): ax.scatter([0.],[0.]) Now if I launch ipython, I can load these functions and start a new figure: In [1]: import matplotlib.pyplot as mpl In [2]: fig = mpl.figure() In [3]: ax = fig.add_subplot(1,1,1) In [4]: run functions # run the file with the above defined function If I now call dostuff, then the figure does not refresh: In [6]: dostuff(ax) I have to then explicitly run: In [7]: fig.canvas.draw() To get the canvas to draw. Now I can modify dostuff to be def dostuff(ax): ax.scatter([0.],[0.]) ax.get_figure().canvas.draw() This re-draws the canvas automatically. But now, say that I have the following code: def dostuff1(ax): ax.scatter([0.],[0.]) ax.get_figure().canvas.draw() def dostuff2(ax): ax.scatter([1.],[1.]) ax.get_figure().canvas.draw() def doboth(ax): dostuff1(ax) dostuff2(ax) ax.get_figure().canvas.draw() I can call each of these functions, and the canvas will be redrawn, but in the case of doboth(), it will get redrawn multiple times. My question is: how could I code this, such that the canvas.draw() only gets called once? In the above example it won't change much, but in more complex cases with tens of functions that can be called individually or grouped, the repeated drawing is much more obvious, and it would be nice to be able to avoid it. I thought of using decorators, but it doesn't look as though it would be simple. Any ideas?

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  • How to use Struts2-jQuery Plugin with sitemesh

    - by fayway
    Hi I have this error when I try to include the tag (http://code.google.com/p/struts2-jquery/wiki/HeadTag) in a sitemesh decorator main.jsp (decorator) <%@ taglib uri="http://www.opensymphony.com/sitemesh/decorator" prefix="decorator" %> <%@ taglib prefix="s" uri="/struts-tags"%> <%@ taglib prefix="sj" uri="/struts-jquery-tags"%> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>My Project- <decorator:title /></title> <sj:head compressed="false" jqueryui="true"></sj:head> </head> <body> <!-- head --> .... Tomcat Error exception java.lang.RuntimeException: org.apache.jasper.JasperException: An exception occurred processing JSP page /decorators/main.jsp at line 11 8: <head> 9: <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> 10: <title>My Project- <decorator:title /></title> 11: <sj:head compressed="false" jqueryui="true"></sj:head> 12: </head> 13: <body> 14: <!-- head --> Stacktrace: com.opensymphony.sitemesh.webapp.decorator.BaseWebAppDecorator.render(BaseWebAppDecorator.java:39) com.opensymphony.sitemesh.webapp.SiteMeshFilter.doFilter(SiteMeshFilter.java:84) Please any idea ? Thanks in advance

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  • Graph limitations - Should I use Decorator?

    - by Nick Wiggill
    I have a functional AdjacencyListGraph class that adheres to a defined interface GraphStructure. In order to layer limitations on this (eg. acyclic, non-null, unique vertex data etc.), I can see two possible routes, each making use of the GraphStructure interface: Create a single class ("ControlledGraph") that has a set of bitflags specifying various possible limitations. Handle all limitations in this class. Update the class if new limitation requirements become apparent. Use the decorator pattern (DI, essentially) to create a separate class implementation for each individual limitation that a client class may wish to use. The benefit here is that we are adhering to the Single Responsibility Principle. I would lean toward the latter, but by Jove!, I hate the decorator Pattern. It is the epitome of clutter, IMO. Truthfully it all depends on how many decorators might be applied in the worst case -- in mine so far, the count is seven (the number of discrete limitations I've recognised at this stage). The other problem with decorator is that I'm going to have to do interface method wrapping in every... single... decorator class. Bah. Which would you go for, if either? Or, if you can suggest some more elegant solution, that would be welcome. EDIT: It occurs to me that using the proposed ControlledGraph class with the strategy pattern may help here... some sort of template method / functors setup, with individual bits applying separate controls in the various graph-canonical interface methods. Or am I losing the plot?

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  • UnicodeDecodeError on attempt to save file through django default filebased backend

    - by Ivan Kuznetsov
    When i attempt to add a file with russian symbols in name to the model instance through default instance.file_field.save method, i get an UnicodeDecodeError (ascii decoding error, not in range (128) from the storage backend (stacktrace ended on os.exist). If i write this file through default python file open/write all goes right. All filenames in utf-8. I get this error only on testing Gentoo, on my Ubuntu workstation all works fine. class Article(models.Model): file = models.FileField(null=True, blank=True, max_length = 300, upload_to='articles_files/%Y/%m/%d/') Traceback: File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.6/site-packages/django/contrib/auth/decorators.py" in _wrapped_view 24. return view_func(request, *args, **kwargs) File "/var/www/localhost/help/wiki/views.py" in edit_article 338. new_article.file.save(fp, fi, save=True) File "/usr/lib/python2.6/site-packages/django/db/models/fields/files.py" in save 92. self.name = self.storage.save(name, content) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in save 47. name = self.get_available_name(name) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in get_available_name 73. while self.exists(name): File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in exists 196. return os.path.exists(self.path(name)) File "/usr/lib/python2.6/genericpath.py" in exists 18. st = os.stat(path) Exception Type: UnicodeEncodeError at /edit/ Exception Value: ('ascii', u'/var/www/localhost/help/i/articles_files/2010/03/17/\u041f\u0440\u0438\u0432\u0435\u0442', 52, 58, 'ordinal not in range(128)')

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  • Is this way the best solution to read and save images from Rss Feeds?

    - by Keyne
    Hi, I've build a "RSS Feed Reader" module to my application, and for every post with images in the content, I get the first that matches a specific size and then I save for future use as reference to the posts. When processing, everything works properly except when more then 10 images are saved at the same time (This value is variable). I got an 404 error after a while saving the images. Some images are saved, but not all of them. If I run the app in my local server, everything work as expected (using set_timeout(0) to avoid timeout errors). Currently my application is hosted at dreamhost and I'm using Zend Framework. I'm not sure if the problem is specif for Zend Framework applications, so I didn't put any tags about. I've had this problem another time with other projects hosted at dreamhost. They seems to limitate memory for operations like that. My question is: There is a better way to save images then this (maybe in background? a limited amount per operation?): require_once(APPLICATION_PATH . '/../library/simplehtmldom/simple_html_dom.php'); $TableFeeds = new Model_DbTable_Feeds(); $Feeds = $TableFeeds->fetchAll(); foreach($Feeds as $Feed) { $entries = Zend_Feed_Reader::import($Feed->link); $lastEntry = $this->getLastEntry($Feed->id); if($lastEntry) { $lastDate = new Zend_Date($lastEntry->created_at, Zend_Date::ISO_8601); } foreach ($entries as $entry) { if($lastDate) { if(strtotime($lastDate->get('y-M-d H:m:s')) >= strtotime($entry->getDateCreated()->get('y-M-d H:m:s'))) { break; } } $Category = new Model_DbTable_Categorias(); $availableCategories = $Category->getList('slug'); $categoria_id = false; foreach ($categories as $cat) { if(!empty($cat) && !$categoria_id) { $slug = Zf_Convert::slugfy($cat); if($availableCategories[$Feed->categoria_id] == $slug) { $categoria_id = $Feed->categoria_id; break; } if(in_array($slug,$availableCategories)) { $categoria_id = array_search($slug,$availableCategories); break; } } } if(!$categoria_id) { $categoria_id = $Feed->categoria_id; } // Cadastra a entrada $data = array( 'categoria_id' => $categoria_id, 'feed_id' => $Feed->id, 'titulo' => $entry->getTitle(), 'slug' => Zf_Convert::slugfy($entry->getTitle()), 'created_at' => $entry->getDateCreated()->get(Zend_Date::ISO_8601), 'link' => $entry->getLink(), 'html' => $entry->getContent(), 'tags' => $tags ); $entry_id = $this->insert($data); if($categoria_id == 2) { set_time_limit(0); $post_dom = str_get_dom($entry->getContent()); $img_tags = $post_dom->find('img'); $images = array(); foreach($img_tags as $image) { $images[] = $image->src; } if(count($images)) { $i = 0; $saved = false; while($images[$i] && !$saved) { $src = $images[$i]; $imagem = Zf_Image::create($src); $size = $imagem->getCurrentDimensions(); if($size['width'] >= 150 && $size['height'] >= 200) { $imagem->adaptiveResize(200,200); $imagem->save(PUBLIC_PATH . '/img/feeds/manchetes/' . $entry_id . '.jpg'); $saved = true; $this->update(array('imagemChamada' => 1),'id =' . $entry_id); } $i++; } } } } } }

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  • What makes this "declarator invalid"? C++

    - by nieldw
    I have Vertex template in vertex.h. From my graph.h: 20 template<class edgeDecor, class vertexDecor, bool dir> 21 class Vertex; which I use in my Graph template. I've used the Vertex template successfully throughout my Graph, return pointers to Vertices, etc. Now for the first time I am trying to declare and instantiate a Vertex object, and gcc is telling me that my 'declarator' is 'invalid'. How can this be? 81 template<class edgeDecor, class vertexDecor, bool dir> 82 Graph<edgeDecor,int,dir> Graph<edgeDecor,vertexDecor,dir>::Dijkstra(vertex s, bool print = false) const 83 { 84 /* Construct new Graph with apropriate decorators */ 85 Graph<edgeDecor,int,dir> span = new Graph<edgeDecor,int,dir>(); 86 span.E.reserve(this->E.size()); 87 88 typename Vertex<edgeDecor,int,dir> v = new Vertex(INT_MAX); 89 span.V = new vector<Vertex<edgeDecor,int,dir> >(this->V.size,v); 90 }; And gcc is saying: graph.h: In member function ‘Graph<edgeDecor, int, dir> Graph<edgeDecor, vertexDecor, dir>::Dijkstra(Vertex<edgeDecor, vertexDecor, dir>, bool) const’: graph.h:88: error: invalid declarator before ‘v’ graph.h:89: error: ‘v’ was not declared in this scope I know this is probably another noob question, but I'll appreciate any help.

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  • How can I return an object into PHP userspace from my extension?

    - by John Factorial
    I have a C++ object, Graph, which contains a property named cat of type Category. I'm exposing the Graph object to PHP in an extension I'm writing in C++. As long as the Graph's methods return primitives like boolean or long, I can use the Zend RETURN_*() macros (e.g. RETURN_TRUE(); or RETURN_LONG(123);. But how can I make Graph-getCategory(); return a Category object for the PHP code to manipulate? I'm following the tutorial over at http://devzone.zend.com/article/4486, and here's the Graph code I have so far: #include "php_getgraph.h" zend_object_handlers graph_object_handlers; struct graph_object { zend_object std; Graph *graph; }; zend_class_entry *graph_ce; #define PHP_CLASSNAME "WFGraph" ZEND_BEGIN_ARG_INFO_EX(php_graph_one_arg, 0, 0, 1) ZEND_END_ARG_INFO() ZEND_BEGIN_ARG_INFO_EX(php_graph_two_args, 0, 0, 2) ZEND_END_ARG_INFO() void graph_free_storage(void *object TSRMLS_DC) { graph_object *obj = (graph_object*)object; delete obj-graph; zend_hash_destroy(obj-std.properties); FREE_HASHTABLE(obj-std.properties); efree(obj); } zend_object_value graph_create_handler(zend_class_entry *type TSRMLS_DC) { zval *tmp; zend_object_value retval; graph_object *obj = (graph_object*)emalloc(sizeof(graph_object)); memset(obj, 0, sizeof(graph_object)); obj-std.ce = type; ALLOC_HASHTABLE(obj-std.properties); zend_hash_init(obj-std.properties, 0, NULL, ZVAL_PTR_DTOR, 0); zend_hash_copy(obj-std.properties, &type-default_properties, (copy_ctor_func_t)zval_add_ref, (void*)&tmp, sizeof(zval*)); retval.handle = zend_objects_store_put(obj, NULL, graph_free_storage, NULL TSRMLS_CC); retval.handlers = &graph_object_handlers; return retval; } PHP_METHOD(Graph, __construct) { char *perspectives; int perspectives_len; Graph *graph = NULL; zval *object = getThis(); if(zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "s", &perspectives, &perspectives_len) == FAILURE) { RETURN_NULL(); } graph = new Graph(perspectives); graph_object *obj = (graph_object*)zend_object_store_get_object(object TSRMLS_CC); obj-graph = graph; } PHP_METHOD(Graph, hasCategory) { long perspectiveId; Graph *graph; graph_object *obj = (graph_object*)zend_object_store_get_object(getThis() TSRMLS_CC); graph = obj-graph; if (graph == NULL) { RETURN_NULL(); } if(zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "l", &perspectiveId) == FAILURE) { RETURN_NULL(); } RETURN_BOOL(graph-hasCategory(perspectiveId)); } PHP_METHOD(Graph, getCategory) { // what to do here? RETURN_TRUE; } function_entry php_getgraph_functions[] = { PHP_ME(Graph,__construct,NULL,ZEND_ACC_PUBLIC|ZEND_ACC_CTOR) PHP_ME(Graph,hasCategory,php_graph_one_arg,ZEND_ACC_PUBLIC) PHP_ME(Graph,getCategory,php_graph_one_arg,ZEND_ACC_PUBLIC) { NULL, NULL, NULL } }; PHP_MINIT_FUNCTION(getgraph) { zend_class_entry ce; INIT_CLASS_ENTRY(ce, PHP_CLASSNAME, php_getgraph_functions); graph_ce = zend_register_internal_class(&ce TSRMLS_CC); graph_ce-create_object = graph_create_handler; memcpy(&graph_object_handlers, zend_get_std_object_handlers(), sizeof(zend_object_handlers)); graph_object_handlers.clone_obj = NULL; return SUCCESS; } zend_module_entry getgraph_module_entry = { #if ZEND_MODULE_API_NO = 20010901 STANDARD_MODULE_HEADER, #endif PHP_GETGRAPH_EXTNAME, NULL, /* Functions */ PHP_MINIT(getgraph), NULL, /* MSHUTDOWN */ NULL, /* RINIT */ NULL, /* RSHUTDOWN */ NULL, /* MINFO */ #if ZEND_MODULE_API_NO = 20010901 PHP_GETGRAPH_EXTVER, #endif STANDARD_MODULE_PROPERTIES }; #ifdef COMPILE_DL_GETGRAPH extern "C" { ZEND_GET_MODULE(getgraph) } #endif

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  • Celery / Django Single Tasks being run multiple times

    - by felix001
    I'm facing an issue where I'm placing a task into the queue and it is being run multiple times. From the celery logs I can see that the same worker is running the task ... [2014-06-06 15:12:20,731: INFO/MainProcess] Received task: input.tasks.add_queue [2014-06-06 15:12:20,750: INFO/Worker-2] starting runner.. [2014-06-06 15:12:20,759: INFO/Worker-2] collection started [2014-06-06 15:13:32,828: INFO/Worker-2] collection complete [2014-06-06 15:13:32,836: INFO/Worker-2] generation of steps complete [2014-06-06 15:13:32,836: INFO/Worker-2] update created [2014-06-06 15:13:33,655: INFO/Worker-2] email sent [2014-06-06 15:13:33,656: INFO/Worker-2] update created [2014-06-06 15:13:34,420: INFO/Worker-2] email sent [2014-06-06 15:13:34,421: INFO/Worker-2] FINISH - Success However when I view the actual logs of the application it is showing 5-6 log lines for each step (??). Im using Django 1.6 with RabbitMQ. The method for placing into the queue is via placing a delay on a function. This function (task decorator is added( then calls a class which is run. Has anyone any idea on the best way to troubleshoot this ? Edit : As requested heres the code, views.py In my view im sending my data to the queue via ... from input.tasks import add_queue_project add_queue_project.delay(data) tasks.py from celery.decorators import task @task() def add_queue_project(data): """ run project """ logger = logging_setup(app="project") logger.info("starting project runner..") f = project_runner(data) f.main() class project_runner(): """ main project runner """ def __init__(self,data): self.data = data self.logger = logging_setup(app="project") def self.main(self): .... Code settings.py THIRD_PARTY_APPS = ( 'south', # Database migration helpers: 'crispy_forms', # Form layouts 'rest_framework', 'djcelery', ) import djcelery djcelery.setup_loader() BROKER_HOST = "127.0.0.1" BROKER_PORT = 5672 # default RabbitMQ listening port BROKER_USER = "test" BROKER_PASSWORD = "test" BROKER_VHOST = "test" CELERY_BACKEND = "amqp" # telling Celery to report the results back to RabbitMQ CELERY_RESULT_DBURI = "" CELERY_IMPORTS = ("input.tasks", ) celeryd The line im running is to start celery, python2.7 manage.py celeryd -l info Thanks,

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  • Naming conventions: camelCase versus underscore_case ? what are your thoughts about it? [closed]

    - by poelinca
    I've been using underscore_case for about 2 years and I recently switched to camelCase because of the new job (been using the later one for about 2 months and I still think underscore_case is better suited for large projects where there are alot of programmers involved, mainly because the code is easier to read). Now everybody at work uses camelCase because (so they say) the code looks more elegant . What are you're thoughts about camelCase or underscore_case p.s. please excuse my bad english Edit Some update first: platform used is PHP (but I'm not expecting strict PHP platform related answers , anybody can share their thoughts on which would be the best to use , that's why I came here in the first place) I use camelCase just as everibody else in the team (just as most of you recomend) we use Zend Framework which also recommends camelCase Some examples (related to PHP) : Codeigniter framework recommends underscore_case , and honestly the code is easier to read . ZF recomends camelCase and I'm not the only one who thinks ZF code is a tad harder to follow through. So my question would be rephrased: Let's take a case where you have the platform Foo which doesn't recommend any naming conventions and it's the team leader's choice to pick one. You are that team leader, why would you pick camelCase or why underscore_case? p.s. thanks everybody for the prompt answers so far

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  • Which open source PHP project has the 'perfect' OOP design I can learn from?

    - by aditya menon
    I am a newbie to OOP, and I learn best by example. You could say this question is similar to Which Scala open source projects should I study to learn best coding practices - but in PHP. I have heard-tell that Symfony has the best 'architecture' (I will not pretend I know what that exactly means), as well as Doctrine ORM. Is it worth it to spend many months reading the source code of these projects, trying to deduce the patterns used and learning new tricks? I have seen equal number of web pages dissing and liking Zend's codebase (will provide links if deemed necessary). Do you know of any other project that would make any veteran OOP developer shed tears of joy? Please let me add that practicality and scope of use is not a concern at all here - I just want to do: Pick a project that has a codebase deemed awesome by devs way better and greater than me. Write code that achieves what the project does. Compare results and try to learn what I don't know. Basically, an academic interest codebase. Any recommendations please?

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  • reinstalling phpmyadmin

    - by explorex
    EDIT:: installed mysql-server but no phpmyadmin (since phpmyadmin was installed before mysql, that resulted an error). How to reinstall phpmyadmin with database (there is no phpmyadmin datbase)? unstalling it and reinstalling it didn't help. i was trying to install phpmyadmin (and zend framework) through synaptic manager but in the middle i was prompted for password i thought it was phpmyadmin password and i proceeded but i got error and i aborted. and then again i tried to reinstall, it reinstalled but i am not getting phpmyadmin. EDIT::The following is invalid so please don't bother apache is running but mysql is not some of it's characteristics are: santosh@explorer:~$ mysql ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) santosh@explorer:~$ sudo apt-get install mysql-server E: Could not get lock /var/lib/dpkg/lock - open (11: Resource temporarily unavailable) E: Unable to lock the administration directory (/var/lib/dpkg/), is another process using it? Should i be asking this question here or stackoverflow? UPDATES:: after restarting my computer santosh@explorer:~$ sudo service mysql start [sudo] password for santosh: mysql: unrecognized service UPDATES:: santosh@explorer:~$ sudo apt-get install mysql Reading package lists... Done Building dependency tree Reading state information... Done E: Unable to locate package mysql

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  • What do I need to develop a PHP extension in lampp?

    - by Fernando Costa
    Actually I'm dealing with a trouble in my system, I have to delivery the system to clients and it was built in PHP, JS, ShellScript and SQL. I would like to encrypt the code or obfuscate it from eyes of others! Then someone from the community told me about build my own PHP extension, it sounds to me as a great idea, since it will not be with the main code of the system. But I have a problem doing this way, if a programmer get in the extensions and find it, all the hard work has gone. Then I'm here to ask again about this matter. What is the best way to hide my Business Logic from third parties? I know that has stuffs like IonCube, Zend Guard, and many others. But I'm looking something that I can build myself. Is PHP extension the right way to follow? Or some Half SaaS system, with dependencies (Business Logic) in a remote server? About the environment OS: Kernel Linux 2.6.37.1-1.2 - LAMPP (Apache 2.2, MySQL 5.5 PHP 5.3.8) In php generally the extension is located at /php/ext/ but in lampp I have no idea where it is, I just found a folder /opt/lampp/lib/php/extensions/ is that right place?

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  • Is there any site which tells or highlights by zone developer income source? I think i am getting less yearly [closed]

    - by YumYumYum
    http://www.itjobswatch.co.uk/ Thats the only one good site i have found, but missing for Belgium and for other European countries. I was searching a site which can tell the income source details for European developer (specially for Belgium). But mostly not a single website exist who tells the true. My situation: As a programmer myself in one company i use all my knowledge, 20++ hours a day (office , home, office, home) because every-time its challenge/complex/stress/over-time feature-requests, at the end of the year in Europe i was getting in total not even the lowest amount shown here (UK pound vs Euro + high-tech most of the time they use + speed in development): http://www.itjobswatch.co.uk/ In one company i have to use my best performance knowledge for whole year with: C, Java, PHP (Zend Framework, Cakephp), BASH, MySQL/DB2, Linux/Unix, Javascript, Dojo, JQuery, Css, Html, Xml. Company wants to pay lesser but always it has to be perfect and it has to be solid gold and diamond like quality. And the total amount in Europe is not sufficient for me if i compare with other countries and living cost in Europe including taxes. Is there any developers/community site where we can see by country, zone what is minimum to maximum income source getting offered to the developers? So that some developers who is in troubles, they can shout and speak up louder with those references?

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  • PHP frameworks - should I use them?

    - by 30secondstosam
    First of all let me explain who I am: I am a PHP Developer working for a company developing their CMS which handles online stores, data feeds and other content like blogs. I have been programming for 6 years and 4 of those have been in PHP. (I used to be a C# developer). My question is regarding PHP frameworks. I see so many jobs asking for zend, cakephp and other MVC types of frameworks. However, even as an experienced developer I have never used a PHP framework. Should I start learning? If so where do I even start as there are so many. I am about to re-write so much of my work's CMS and I'm wondering whether I could help myself a lot by using a framework. What do people think? Considering I will be re-writing a lot of the online store stuff... I am experienced in OO and I have used the .NET framework in the past. Thanks in advance for the replies.

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  • Tomcat + Spring + CI workflow

    - by ex3v
    We're starting our very first project with Spring and java web stack. This project will be mainly about rewriting quite large ERP/CRM from Zend Framework to Java. Important factor in my question is that I come from php territory, where things (in terms of quality) tend to look different than in java world. Fatcs: there will be 2-3 developers, at least one of developers uses Windows, rest uses Linux, there is one remote linux-based machine, which should handle test and production instances, after struggling with buggy legacy code, we want to introduce good programming and development practices (CI, tests, clean code and so on) client: internal, frequent business logic changes, scrum, daily deployments What I want to achieve is good workflow on as many development stages as possible (coding - commiting - testing - deploying). The problem is that I've never done this before, so I don't know what are best practices to do this. What I have so far is: developers code locally, there is vagrant instance on every development machine, managed by puppet. It contains the same linux, jenkins and tomcat versions as production machine, while coding, developer deploys to vagrant machine, after local merge to test branch, jenkins on vagrant handles tests, when everything is fine, developer pushes commits and merges jenkins on remote machine pulls commit from test branch, runs tests and so on, if everything looks green, jenkins deploys to test tomcat instance Deployment to production is manual (altough it can be done using helping scripts) when business logic is tested by other divisions and everything looks fine to client. Now, the real question: does above make any sense? Things that I'm not sure about: Remote machine: won't there be any problems with two (or even three, as jenkins might need one) instances of same app on tomcat? Using vagrant to develop on php environment is just vise. Isn't this overkill while using Tomcat? I mean, is there higher probability that tomcat will act the same on every machine? Is there sense of having local jenkins on vagrant?

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