jquery use return data from 2 functions in another function ---always get undefined. why ??
- by user253530
Function socialbookmarksTableData(data) is called by another function to generate the content of a table -- data is a JSON object. Inside the function i call 2 other functions that use getJSON and POST (with json as a return object) to get some data. The problem is: though the functions execute correctly i get undefined value for the 2 variables (bookmarkingSites, bookmarkCategories). Help with a solution please.
function socialbookmarksGetBookmarkCategories(bookmarkID)
{
var toReturn = '';
$.post("php/socialbookmark-get-bookmark-categories.php",{
bookmarkID: bookmarkID
},function(data){
$.each(data,function(i,categID){
toReturn += '<option value ="' + data[i].categID + '">' + data[i].categName + '</option>';
})
return toReturn;
},"JSON");
}
function socialbookmarksGetBookmarkSites()
{
var bookmarkingSites = '';
$.getJSON("php/socialbookmark-get-bookmarking-sites.php",function(bookmarks){
for(var i = 0; i < bookmarks.length; i++){
//alert( bookmarks[i].id);
bookmarkingSites += '<option value = "' + bookmarks[i].id + '">' + bookmarks[i].title + '</option>';
}
return bookmarkingSites;
});
}
function socialbookmarksTableData(data)
{
var toAppend = '';
var bookmarkingSites = socialbookmarksGetBookmarkSites();
$.each(data.results, function(i, id){
var bookmarkCategories = socialbookmarksGetBookmarkCategories(data.results[i].bookmarkID);
//rest of the code is not important
});
$("#searchTable tbody").append(toAppend);
}
