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  • [Django] One single page to create a Parent object and its associated child objects

    - by ahmoo
    Hi all, This is my very first post on this awesome site, from which I have been finding answers to a handful of challenging questions. Kudos to the community! I am new to the Django world, so am hoping to find help from some Django experts here. Thanks in advance. Item model: class Item(models.Model): name = models.CharField(max_length=50) ItemImage model: class ItemImage(models.Model): image = models.ImageField(upload_to=get_unique_filename) item = models.ForeignKey(Item, related_name='images') As you can tell from the model definitions above, every Item object can have many ItemImage objects. My requirements are as followings: A single web page that allows users to create a new Item while uploading the images associated with the Item. The Item and the ItemImages objects should be created in the database all together, when the "Save" button on the page is clicked. I have created a variable in a custom config file, called NUMBER_OF_IMAGES_PER_ITEM. It is based on this variable that the system generates the number of image fields per item. Questions: What should the forms and the template be like? Can ModelForm be used to achieve the requirements? For the view function, what do I need to watch out other than making sure to save Item before ItemImage objects?

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  • JavaScript two-dimensional Array to PHP

    - by vi
    Hi I have to send a two-dimensional JavaScript Array to a PHP page. Indeed, I'm working on a form-builder, in which the user can add or remove fields. These fields are added (or removed) using JavaScript (jQuery). When the user is done and hit a 'publish' button, I have to get all the fields concerned and send them to a PHP page which would build a real form with it. I found a way to do it but I'm pretty sure it's not very clean : addedFields = new Array(); $("#add-info .field").each(function() { addedFields.push(new Array($(this).find('.name').val(), $(this).find('.type').val(), $(this).find('.size').val())); }); Basically, the ".field" class objects are <tr> and the ".name", ".type" and ".size" objects are inputs. So I get an array of [name, type, size], then I convert it into a string using addedFields = addedFields.join(";"); Finally, I go to the PHP form that way ; document.location.href = "create.php?addedfields=" + addedFields; Concerning the PHP code, I create a PHP array using the explode() function: $addedFields = explode(";", $_GET['addedfields']); and then I use it again for each element in the array: foreach ($addedFields as $field) { $field = explode(",", $field); echo "<li>Field with name : '$field[0]', of '$field[1]' type and with a size of $field[2]"; }

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  • How to return a variable from a javascript function into html body.

    - by anthr
    Hi there, I am still new to javascript, and I am trying to get a function to return a variable using html & javascript. Basically the function should just return whichever radio button that the user clicks on, although at the moment I don't see anything being returned at all. The function is here: <script type="text/javascript"> function GetSelectedItem() { var chosen = "" len = document.f1.r1.length for (i = 0; i <len; i++) { if (document.f1.r1[i].checked) { chosen = document.f1.r1[i].value } } } return chosen </script> And then in the html section I have these radio buttons, and my attempt to get the variable "chosen" output to the screen. <form name = f1><Input type = radio Name = r1 Value = "ON" onClick=GetSelectedItem()>On <Input type = radio Name = r1 Value = "OFF" onClick =GetSelectedItem()>Off</form> <script type ="text/javascript">document.write(chosen)</script> At the moment nothing seems to be getting returned from the function (although if I output the variable 'chosen' inside the function then it is working correctly. Thanks in advance!

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  • How to write data option in jQuery.ajax() function when it include in a mysql_query?

    - by cj333
    I modify a php comment system. I want add it after every article witch are query from database. this is the php part <?php ... while($result = mysql_fetch_array($resultset)) { $article_title = $result['article_title']; ... ?> <form id="postform" class="postform"> <input type="hidden" name="title" id="title" value="<?=$article_title;?>" /> <input type="text" name="content" id="content" /> <input type="button" value="Submit" class="Submit" /> </form> ... <?php } ?> this is the ajax part. $.ajax({ type: "POST", url: "ajax_post.php", data: {title:$('#title').val(), content:$('#content').val() ajax_post.php echo $title; echo $content; How to modify the ajax data part that each article's comment can send each data to the ajax_post.php? thanks a lot.

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  • Problem with changing td's html in JQuery.

    - by bugbug
    I want to change text in table td from 1,1,1 to 1,2,3 with following code, But it not seem to work. what is wrong in my code? This is my JavaScript function. function reorder(targetId){ var i = 1; jQuery.find(targetId).each(function(){ jQuery(this).attr("innerHTML", i); i ++; }); } My html code. <form> <input type="button" onClick="reorder('#index');" value="test"/> <table> <tr><td id="index">1</td></tr> <tr><td id="index">1</td></tr> <tr><td id="index">1</td></tr> </table> </form>

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  • How to make link become inactive?

    - by Konstantin Vasilcov
    The idea was simple: change li background color on hover to one color ul#menu li a:hover {...} change it on mouse press to the other color ul#menu li a:active {...} return the color to the original (normal) if the link is neither hover nor pressed The problem appeared to be that, if user rejected his intention and lets the mouse up away from the link, the back color stays as if it was pressed. Then I tried to research and came up with this: ul#menu li a:hover:active {...} It became better, and the link is not marked with special back color in a normal state after user presses the link and rejects. But the "on-hover" back color became equal to the active one. So it looks like the link gets "active" state and stays in it even after user releases mouse button. Hate to write this, but I am very new to html and css. So I may be missing something very basic here. Could you, please, suggest any way, how to achieve my goal? EDIT I've read this source CSS Styling links (thought there could be some other state to use instead of active), but found nothing suitable there...

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  • Can I use a UINavigationController as the detail view of a UISplitViewController?

    - by B Sweigard
    I'm running into a problem with an iPad app where I would like to have UINavigationControllers in both of the views within a UISplitView. I've looked through other similar questions here, but most link to a tutorial online that doesn't completely solve the problem. Here's a 2-minute walkthrough to re-create the problem I'm having: Create a New Project in XCode, starting from the Split View-based Application template. Add the following NSLog statement as the first line within the DetailViewController's willHideViewController method: NSLog(@"toolbar: %@", toolbar); If you run the application now, the log will show that the DetailViewController's toolbar is alive and well. Now... Open MainWindow.xib and expand the SplitViewController. Drag a Navigation Controller from the library on top of the DetailViewController. Expand the new Navigation Controller and change the class of the UIViewController within to a DetailViewController. Ctrl-drag from the SplitViewController to the DetailViewController and assign it as the delegate. Save MainWindow.xib and run the app again. At this point, the detail view has a navigation bar and an empty toolbar. If you view the logs, you should find that the toolbar is null. Why is this? Am I missing some sort of connection in Interface Builder? Is the navigation bar the problem for some reason? Unlike the tutorial at http://www.cimgf.com/2010/05/24/fixing-the-uisplitviewcontroller-template/, I would like to keep both the navigation bar and the toolbar (preferably with the toolbar at the top when in portrait and not visible when in landscape), so that I still have a functional "Back" button when the iPad is in portrait orientation. Does anyone have any suggestions for fixing this problem? An example project with this sort of set-up would be ideal.

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  • Display error message at top of form

    - by moustafa
    Hello, I'm trying to get the following error to show when some once presses the submit button and has not filled in the required field/s. My PHP code is. <?php require_once("includes/database.php"); require_once("includes/functions.php"); if(isset($_POST['full_name'])) { $required = array('full_name','user_name','email','pwd','pwd2'); $missing = array(); $validation = array( 'full_name' => 'Please provide your full name', 'user_name' => 'Please provide your username', 'email' => 'Please provide your valid email address', 'pwd' => 'Please provide your password', 'pwd2' => 'Please confirm your password', 'userdup' => 'Username already registered', 'emaildup' => 'Email address already registered', 'mismatch' => 'Passwords do not match' ); //Sanitise and clean function $full_name = escape($_POST['full_name']); $user_name = escape($_POST['user_name']); $email = escape($_POST['email']); $pwd = escape($_POST['pwd']); $pwd2 = escape($_POST['pwd2']); foreach($_POST as $key => $value) { $value = trim($value); if(empty($value) && in_array($key,$required)) { array_push($missing,$key); } else { ${$key} = escape($value); } }

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  • Google Anlytics event not firing

    - by yar1
    I am not getting and event data in GA. I installed Google Analytics Debugger Chrome extension and I see nothing happening (same goes when looking at Network panel in developer tools). I Googled it and read many (many) other answers and it looks like I'm doing things right. Page views, etc. are registering correctly... I have this code as the last thing before my closing tag: <script> (function(i,s,o,g,r,a,m){i['GoogleAnalyticsObject']=r;i[r]=i[r]||function(){ (i[r].q=i[r].q||[]).push(arguments)},i[r].l=1*new Date();a=s.createElement(o), m=s.getElementsByTagName(o)[0];a.async=1;a.src=g;m.parentNode.insertBefore(a,m) })(window,document,'script','//www.google-analytics.com/analytics.js','ga'); ga('create', 'UA-MYREALCODE', 'mybna.net'); ga('send', 'pageview'); var _gaq = _gaq || []; _gaq.push(['_setAccount', 'UA-MYREALCODE']); _gaq.push(['_trackPageview']); </script> My event handlers are done using jQuery, all inside an external js file, loaded before the closing tag. For example: $(function () { $('#show-less').click(function (e) { pbr.showHideMore(e); _gaq.push(['_trackEvent', 'ShowMore', 'Hide', 'top button']); }); }); Any ideas anyone?

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  • Displaying a message after adding duplicate records in database

    - by user1770370
    I wrote program in C# winforms and SQL server and LINQ to SQL. I use user control instead of form. In my user control, I put 3 textbox, txtStartNumber, txtEndNumber, txtQuantity. user define value of textboxes, when clicked button, it will insert some records according to the value of txtQuantity. I want to when duplicate number is created, it won't add to database and display message. how do i do? I must write code in code behind or server side? i must set this in store procedure or trigger? private void btnSave_Click(object sender, EventArgs e) { long from = Convert.ToInt64(txt_barcode_f.Text); long to = Convert.ToInt64(txt_barcode_t.Text); long quantity = Convert.ToInt64(to - from); int card_Type_ID=Convert.ToInt32(cmb_BracodeType .SelectedValue); long[] arrCardNum = new long[(to - from)]; arrCardNum[0]=from; for (long i = from; i < to; i++) { for(int j=0; j<(to-from) ;j++) { arrCardNum[j]=from+j; string r = arrCardNum[j].ToString(); sp.SaveCards(r, 2, card_Type_ID, SaveDate, 2); } } } Stored Procedure code. ALTER PROCEDURE dbo.SaveCards @Barcode_Num int ,@Card_Status_ID int ,@Card_Type_ID int ,@SaveDate varchar(10) ,@Save_User_ID int AS BEGIN INSERT INTO [Parking].[dbo].[TBL_Cards] ([Barcode_Num] ,[Card_Status_ID] ,[Card_Type_ID] ,[Save_User_ID]) VALUES (@Barcode_Num ,@Card_Status_ID ,@Card_Type_ID ,@Save_User_ID) END

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  • How to check whether data is stored in core data ?

    - by Warrior
    i am new to iphone development. I am trying to save a static values in to core data database.I want to check whether the data is stored to the database, i am not able to retrieve the data from the database, so i want to check myself whether i made mistake in retrieving the data or in storing the data itself. NSManagedObjectContext *context = [self managedObjectContext]; NSManagedObject *event = [NSEntityDescription insertNewObjectForEntityForName:@"Event" inManagedObjectContext:context]; [event setValue:fname forKey:@"firstname"]; [event setValue:lname forKey:@"lastname"]; i put the above code in the submit button of my formclass. when i restart the app i fetch the data in main view class using this code NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"Event" inManagedObjectContext:self.managedObjectContext]; [fetchRequest setEntity:entity]; NSError *error; NSArray *items = [self.managedObjectContext executeFetchRequest:fetchRequest error:&error]; for (Event *info in items) { NSLog(@"the selected value is : %@", [info valueForKey:@"firstname"]); } [fetchRequest release]; i dont know where i am going wrong.Please help me out.Thanks.

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  • Usability for notification messages, colors

    - by metrobalderas
    In each app I develop, I like to add three types of messages: Green/blue for success messages Yellow for warnings Red for errors And perhaps, a neutral one for information, which is gray or blue if the success one is green. The success one is used for when an item is created or updated, the yellow one is when there's something wrong, but not we-are-going-to-die wrong and the red one is when something is blocked or we are going to die. However, there's one thing I can't figure out, when I delete an object, what kind of notification should I use? I think the success one is not because it is not expected, altough the deletion was successful, the user tends not to read the message, just to see the color. The red one might be, but it can be misunderstood (I tried to delete it but there was an error), the warning and the information one might be good choices, but I'm not really sure. Also, when you ask for confirmation about deleting something, the 'cancel' button should be green or red? I'm just curious how you guys handle this. Thanks.

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  • Delete file using a link

    - by user329394
    Hi all, i want to have function like delete file from database by using link instead of button. how can i do that? do i need to use href/unlink or what? Can i do like popup confirmation wther yes or no. i know how to do that, but where should i put the code? this is the part how where system will display all filename and do direct upload. Beside each files, there will be a function for 'Remove': $qry = "SELECT * FROM table1 a, table2 b WHERE b.id = '".$rs[id]."' AND a.ptkid = '".$rs[id]."' "; $sql = get_records_sql($qry); foreach($sql as $rs){ ?> <?echo '<a href="download.php?f='.$rs->faillampiran.'">'. basename($rs->faillampiran).'</a>'; ?><td><?echo '<a href=""> [Remove]</a>';?></td><? ?><br> <? } ?> thankz all

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  • Which approach is better in term of saving the data? How to handle this?

    - by dewacorp.alliances
    Hi there I have Telerik grid within a Telerik grid. Due to I have a different view between insert and edit mode, so as per suggested I have to use UserControl instead. Inside this control, it could have another Telerik grid plus bunch of ASP.NET textboxes. This thing works well. My dilemma is this: Scenario 1: Handling the save in the user control - OnClick event I have a button to save this. I need to get the value of the "selected grid" so I am using this snippet below and again works well. foreach (GridDataItem dataItem in radgrdTariffNetworkDistributorRateItems.SelectedItems) { string ID = dataItem.OwnerTableView.DataKeyValues[dataItem.ItemIndex]["SupplierRateItemID"].ToString(); } But then how do I get the id of the parent grid where this control sit? I use the following this event to save: protected void bttnNetworkTariffReviewItemInsert_Click(object sender, EventArgs e) the e of course not the right one though?!?!? GridDataItem parentItem = (GridDataItem)e.Item.OwnerTableView.ParentItem; string reviewID = parentItem.OwnerTableView.DataKeyValues[parentItem.ItemIndex]["ID"].ToString(); Scenario 2: Handling the save in the page instead (OnInsertCommand on the master grid) With this approach works well to get id of the grid etc BUT I am having a problem to get selected grid in the UserControl and plus couple controls value. How do I make this feasible? Logically, I should handle this at the user control level to save but again because the user control relying on the child grid I am having trouble to get this value. I am appreciated your suggestion.

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  • Show dialog while loading new screen

    - by darkdusky
    I have a front screen with a button which opens a second screen. The second screen can take a few seconds to load so I want to display a dialog while loading. My problem is the dialog does not display while loading second screen, but it displays when I return to first page from the second page. If I comment out the "startActivity" to open second page the dialog shows fine. I'm fairly new to android programming - I guess it has something to do with threads. //code snippet from inside onCreate: NewGame.setOnClickListener(new View.OnClickListener() { public void onClick(View arg0) { //does not get displayed before 2nd page opens showDialog(DIALOG2_KEY); //shows fine if next 2 lines commented out Intent i = new Intent(screen1.this, SudukuXL.class); startActivity(i); I've dealt with the dialog showing on returning to the front screen using onPause(). I've tried using threads to seperate the dialog from the startActivity but I've had no luck. Any help would be appreciated. I used code from Android examples to create dialog. I include below for reference: protected Dialog onCreateDialog(int id) { switch (id) { case DIALOG2_KEY: { ProgressDialog dialog = new ProgressDialog(this); dialog.setMessage("Loading..."); dialog.setIndeterminate(true); dialog.setCancelable(true); return dialog; } } return null; }

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  • Flex Setting form height dynamically

    - by Daryl
    I'm not sure if this is possible, is there a way to get the <mx:Form> to set its own height based on the position of an element within it? For example something like this: <mx:Form height="{submitBtn.y + submitBtn.height}"> <mx:FormItem>... </mx:FormItem> <mx:FormItem>... </mx:FormItem> <mx:FormItem>... </mx:FormItem> <mx:FormItem> <s:Button id="submitBtn" label="Submit" /> </mx:FormItem> </mx:Form> where the form height is dynamically set based on submitBtn's y position and its height. I tried using Alert.show to show these values and turned out submitBtn.y = 0 and submitBtn.height = 21. height sounds reasonable, but I know the y of submitBtn can't be 0 since it's below several other Is it possible to set the form height dynamically?

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  • Smarty/PHP loop not being passed to IE(Pc) or Chrome/FF(Mac)

    - by Kyle Sevenoaks
    Hi, I've been working on a site that has a lot of PHP/Smarty involved, I've been asked to re-skin a webstore checkout process, but during this we've discovered this issue. This particular quirk is one part of a tax calculation that doesn't get sent to the browser in IE for PC and Chrome/FF for the Mac. It's NOT in the output source in the browsers, but is in FF, Chrome and Opera on the PC. Here is the code that doesn't "work:" {foreach $cart.taxes.$currency as $tax} <div id="subTotalCaption2"><p style="width:100px;">{$tax.name_lang}:</p></div> <div id="taxAmount2"><p>{$tax.formattedAmount}</p></div> {/foreach} It's not a CSS issue as if you go all the way through the checkout process and then back to the order page (Not using the back button, using the on-site links) it works. There is another calculation on the last page of the process that does the same thing: {foreach from=$order.taxes.$currency item="tax"} <tr> <td colspan="{$colspan}" class="tax">{$tax.name_lang}:</td> <td>{$tax.formattedAmount}</td> </tr> {/foreach} I guess my question is what could cause this to not be read (Parsed?) in IE and the mac but other browsers do it fine on the PC. Thanks.

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  • Make a div content (googlemap) fullscreen

    - by lena2211
    Hi iam trying to make a button that will turn the googlemap div into fullscreen.. this is what i have untill now, but it is not working correctly .. problem is: the map will only half loaded the code is below, and a screenshot how can i repair this? where is the problem? thanks in advance http://img32.imageshack.us/img32/9365/halfload.gif <html> <head> <meta name="viewport" content="initial-scale=1.0, user-scalable=no" /> <script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false"></script> <script type="text/javascript"> function initialize() { var latlng = new google.maps.LatLng(-34.397, 150.644); var myOptions = { zoom: 8, center: latlng, mapTypeId: google.maps.MapTypeId.ROADMAP }; var map = new google.maps.Map(document.getElementById("map_canvas"), myOptions); } function fs() { var elem = document.getElementById("map_canvas"); elem.style.position="absolute"; elem.style.width="100%"; elem.style.height="100%"; elem.style.top="0px"; document.body.style.overflow = "hidden"; } </script> </head> <body onload="initialize()"> <div id="map_canvas" style="width:400px; height:300px"></div> <a href="#" onclick ="fs()">makefullscreen</a> </body> </html>

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  • How to pass values from array into mysql with php

    - by moustafa
    my original code is this <tr> <th> <label for="user_level"> User Level: * <?php echo isset($valid_user_level) ? $valid_user_level : NULL; ?> </label> </th> </tr> <td> <select name="user_level" id="user_level" class="sel"> <option value="">Select one…</option> <option value="1">User</option> <option value="5">Admin</option> </select> </td> this give me the option to select one of choice from the drop down menu i.e. user and when user is selected and the submit button is pressed this will insert the value 1 into the database which will when the user logs in tell the system that they are are normal user. I want to change the code to the following <tr> <td> <select name="user_level" id="user_level" class="sel"> <option value="">Select one…</option> <?php if(!empty($level)) { foreach($level as $value) { echo "<option value='{$value}'"; echo getSticky(2,'user_level',$value); echo ">{$value}</option>"; } } ?> </select> </td> </tr> With this being my array query $level = array('User','Admin'); How can I pass the values of 1 for user level and 5 for admin in this code so when the user is selected it inouts 1 into the database?

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  • Create modal form dialog in function

    - by Hainlp
    My app works with many modal form dialogs, i want to create modal form dialog by call a function, but i get error when i click OK button on dialog "i.apply is not a function". My code below html: <div id="dlg_srch_acnt"> <table cellpadding="0" cellspacing="0" border="0" class="display" id="dtl_acnt_srch" style=" padding-bottom:0px;"> <thead> <tr> <th>Id</th> <th>Account name</th> </tr> </thead> <tbody> </tbody> </table> </div> Script function init_dlg(id, autoOpen, height, width, modal, fn_button1) { id.dialog({ autoOpen:autoOpen, height:height, width:width, modal:modal, buttons:{ 'OK':fn_button1, }, close:fn_close }); } function fn_ok() { $('#parnt_acnt').val(acnt_name); $('#dlg_srch_acnt').('close'); } init_dlg($('#dlg_srch_acnt'), false, '440', '480', true, 'fn_ok()');

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  • How do i use Form.ShowDialog?

    - by Daniel Lip
    private void button2_Click(object sender, EventArgs e) { ChangeLink cl = new ChangeLink(); // Show testDialog as a modal dialog and determine if DialogResult = OK. if (cl.ShowDialog() == DialogResult.OK) { // Read the contents of testDialog's TextBox. // cl.AcceptButton.DialogResult = DialogResult.OK; this.label4.Text = cl.textBox1Text; } else { this.label4.Text = "Cancelled"; } cl.Dispose(); } When i click the button i see the new Form and the textBox1 in the new Form and i can type in the textBox1 something but i dont see anywhere an OK or CANCEL buttons. Should i add them manualy in the new Form designer ? And how to use them then ? This is the code in my new Form what i wanted to do is to type something in the new Form textBox1 and pass the text in the textBox1 to Form1 label4. using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace GatherLinks { public partial class ChangeLink : Form { public ChangeLink() { InitializeComponent(); } public string textBox1Text { get { return textBox1Text = textBox1.Text; } set { } } } } So where are the OK and CANCEL buttons of the Form.ShowDialog ?

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  • NSTimer won't stop it only resets when invalidated & released

    - by J Fries
    When I press my stop button to stop the timer it just resets to the original time and begins counting down again. I have looked everywhere and all I have found is "invalidate" and it isn't working. I want the time to stop when I hit stop and the label to display the original time. I also turned off automatic counting so I could try releasing and it is giving me an error: 0x10e20a5: movl 16(%edx), %edx EXC_BAD_ACCESS (code=2, address=0x10) `NSTimer *rockettTimer; int rocketCount; @interface FirstViewController () @property (strong, nonatomic) IBOutlet UILabel *rocketTimer; - (IBAction)stopButton:(id)sender; - (IBAction)startButton:(id)sender; @end @implementation FirstViewController @synthesize rocketTimer; -(void) rocketTimerRun{ rocketCount = rocketCount - 1; int minuts = rocketCount / 60; int seconds = rocketCount - (minuts * 60); NSString *timerOutput = [NSString stringWithFormat:@"%d:%.2d", minuts, seconds]; rocketTimer.text = timerOutput; } - (IBAction)startButton:(id)sender { rocketCount = 180; rockettTimer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(rocketTimerRun) userInfo:nil repeats:YES]; - (IBAction)stopButton:(id)sender { [rockettTimer invalidate]; //[rockettTimer release]; } - (void)viewDidLoad { [super viewDidLoad]; // Do any additional setup after loading the view, typically from a nib. } - (void)viewDidUnload { [self setRocketTimer:nil]; [super viewDidUnload]; // Release any retained subviews of the main view. } - (BOOL)shouldAutorotateToInterfaceOrientation: (UIInterfaceOrientation)interfaceOrientation { if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) { return (interfaceOrientation != UIInterfaceOrientationPortraitUpsideDown); } else { return YES; } } @end`

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  • pass parameter from $.post() callback to outer variable

    - by Nazmin
    basically i want to hold a parameter that retrieve value from $.post() call like this: init = function(){ var lastpage = getLastPage(); } function getLastPage(){ $.post("getInfo.php",{ last: "yes" }, function(data){ setLast(data.last); },'json'); return function setLast(data){ return data; } } so when reach at last post (last page) i should check with lastpage variable that has a value returned from getLastPage() function. I'm pretty blur with javascript pointer and all. Please help guys. update (20/4/2010): I've done the other way around, like this: init = function(){ getLastPage(); if((page+1) == $("#lastpage").val()){ alert("this is last post"); }else{ page++; //get info and display to the page here } } function getLastPage(){ $.post("getInfo.php",{ last: "yes" }, function(data){ $("#lastpage").val(data.last); },'json'); } first run the function to temporarily store the value in hidden input tag (lastpage) and then grab the value again to check it whenever i click forward button. if you all have more appropriate way please tell me.

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  • “User Control” uses an incorrect event

    - by Lijo
    Hi, I am using two instances of a user control. But when I click on a button in the user control, both of the instances calls the function corresponding to the first event (AcknowledgeReceipt()) However, when I remove the first user control and clicks on the btnRequestClarification, it calls the correct method (RequestClarification()) Is there a way to correct this behavior? acknowledgeModificationPopupCtrl = (ConfirmationPopup)this.LoadControl("~/ConfirmationPopup.ascx"); plHConfirmationPopup.Controls.Add(acknowledgeModificationPopupCtrl); acknowledgeModificationPopupCtrl.ContinueClick += new EventHandler(AcknowledgeReceipt); RequiredFieldValidator reqFValidatorAcknowledge = (RequiredFieldValidator)acknowledgeModificationPopupCtrl.FindControl("reqValidatorTxt"); reqFValidatorAcknowledge.ValidationGroup = "AcknowledgeReceipt"; acknowledgeModificationPopupCtrl.ValidationGroup = "AcknowledgeReceipt"; btnAcknowledgeReceipt.Attributes.Add("onclick", "validateconfirmPopup('true','xx' ,’yyy','Note' ,'true'); return false;"); requestModificationPopupCtrl = (ConfirmationPopup)this.LoadControl("~/ConfirmationPopup.ascx"); plHConfirmationPopup.Controls.Add(requestModificationPopupCtrl); requestModificationPopupCtrl.ContinueClick += new EventHandler(RequestClarification); RequiredFieldValidator reqFValidator = (RequiredFieldValidator)requestModificationPopupCtrl.FindControl("reqValidatorTxt"); reqFValidator.ValidationGroup = "request"; requestModificationPopupCtrl.ValidationGroup = "request"; btnRequestClarification.Attributes.Add("onclick", "validateconfirmPopup('true',’kkk' ,’lll','ff' ,'true'); return false;"); Thanks Lijo

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  • jQuery removeClass(), how it works

    - by centro
    I have images on my page. User can add more images onto the page by clicking a button. New images are added asynchronously. Initially, each image on page use a special class to be used when the image is loaded. After the image is loaded, that class is removed. Each image being loaded has the class imageLoading: <img class="imageLoading" scr="someimage.png"> After those images are loaded, I remove that class (simplified code without details): $('img.imageLoading') .each(function(){ $(this) .load(function(){ $(this) .removeClass('imageloading'); });}); Visually, I see that style is removed. But when I run the query again: $('img.imageLoading') I see via debugging that all images, not just loading ones, are returned, i.e. it works like I didn't remove the class for the images that were already loaded. I had a look into the page source, and I saw that actually in HTML the class was not removed, though removeClass() was called. Is that behavior by design that all visual changes are applied but the class attribute is not removed in HTML code? If so, how it can be workarounded in this case. Or, probably, I missed something.

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