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  • Installer downloads wrong version of sql server compact edition

    - by MartinStettner
    I have a Visual Studio setup project which defines SQL Server 3.5 as prerequisite. I also set it up to download the required files from the source (i.e. Microsoft). My project uses Sql Server 3.5 SP1. If I create the installer on my development machine, everything works fine. When the installer is built on the build machine, it downloads the "old" 3.5 version (without SP1) which makes my application crash. (If I install SP1 on the test system manually, the application just works find...) I installed both Visual Studio 2008 SP1 and Sql Server 3.5 SP1 on the build machine. This seems to be some issue with the prerequisite packages but they look the same on the development and the build machines. Any idea what goes wrong here? EDIT Ok, I rechecked it and the package descriptions are'nt the sames. Oddly enough, the .msi file is the right one on the build machine but the old one on the development machine, so I guess if I tried to build an installer which includes the prerequisites, I'd get the wrong result on the dev machine and the right one on the build machine. Extended question: How are the prerequesite packages (under C:\Program Files\Microsoft SDKs\Windows\v6.0A\Bootstrapper\Packages\SQL Server Compact Edition) meant to be updated to SP1? Is the SQL Server CE SP1 installer responsible for this?

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  • How to set up django-admin.py on windows vista?

    - by shin
    I manage to install Django after some struggles by using setup.py install on Windows Vista Now I tried to use django-admin.py but it is not working. According to this document, http://docs.djangoproject.com/en/dev/ref/django-admin/ The django-admin.py script should be on your system path if you installed Django via its setup.py utility. If it’s not on your path, ... For Windows users, who do not have symlinking functionality available, you can copy django-admin.py to a location on your existing path or edit the PATH settings (under Settings - Control Panel - System - Advanced - Environment...) to point to its installed location. I checked ComputerpropertiesEnvironment Variables, but path to django-admin.py is not in anywhere. So I added C:\Python25\Lib\site-packages\django\bin which is the folder of django-admin.py in User variables for shin Variable PATH, Value C:\Program Files\Google\google_appengine\;C:\Python25\Lib\site-packages\django\bin\ Am I supposed to add to System variables?? But it still does not work. Could anyone tell me how to add the Path in Environment Variables please? Thanks in advance.

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  • Is Git ready to be recommended to my boss?

    - by Mike Weller
    I want to recomment Git to my boss as a new source control system, since we're stuck in the 90s with VSS (ouch), but are the tools and 3rd party support good enough yet? Specifically I'm talking about GUI front-ends similar to TortoiseSVN, decent visual diff/merge support, as well as stuff like email commit notifications and general support from 3rd parties like IDEs and build systems. Even though this will be used by programmers, we really need this kind of stuff in our team. I don't want to leave everyone stuck with a new tool, and even a new source control paradigm (distributed), with nothing but a command-line app and some online tutorials. This would be a step backwards. So what do you think... is Git ready? What decent tools exist for Git and what third party development apps support it? EDIT: My original question was pretty vague so I'm updating it to specifically ask for a list of available tools and 3rd party support for Git. Maybe we can get a community wiki post with a list of stuff. I also do not consider 'use subversion' to be an adequate answer. There are other reasons to use a distributed source control system other than offline editing - private and cheap branches being one of them.

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  • git rebase without changing commit timestamps

    - by Olivier
    Would it make sense to perform git rebase while preserving the commit timestamps? I believe a consequence would be that the new branch will not necessarily have commit dates chronologically. Is that theoretically possible at all? (e.g. using plumbing commands; just curious here) If it is theoretically possible, then is it possible in practice with rebase, not to change the timestamps? For example, assume I have the following tree: master <jun 2010> | : : : oldbranch <feb 1984> : / oldcommit <jan 1984> Now, if I rebase oldbranch on master, the date of the commit changes from feb 1984 to jun 2010. Is it possible to change that behaviour so that the commit timestamp is not changed? In the end I would thus obtain: oldbranch <feb 1984> / master <jun 2010> | : Would that make sense at all? Is it even allowed in git to have a history where an old commit has a more recent commit as a parent? Edit A crucial question of Von C helped me understand what is going on: when your rebase, the committer's timestamp changes, but not the author's timestamp, which suddenly all makes sense. So my question was actually not precise enough. The answer is that rebase actually doesn't change the author's timestamps (you don't need to do anything for that), which suits me perfectly.

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  • Flash Player scripting + IE8

    - by Joel Alejandro
    I've developed a small control bar for a Flash viewer generated by a third-party software. It has a First, Prev, Next & Last button, and a Zoom command. While Zoom works fine in all browsers, the navigation buttons seem to fail at Internet Explorer 8. I use at least two functions. This one locates the Flash object I want to manipulate: function getFlashMovieObject(movieName) { if (window.document[movieName]) { return window.document[movieName]; } if (navigator.appName.indexOf("Microsoft Internet")==-1) { if (document.embeds && document.embeds[movieName]) return document.embeds[movieName]; } else // if (navigator.appName.indexOf("Microsoft Internet")!=-1) { return document.getElementById(movieName); } } ...and any of these ones handles the frame navigation: var currentFrame = 0; function gotoFirst(id) { getFlashMovieObject(id + "Blueprints").Rewind(); currentFrame = 0; $("currentFrame").innerHTML = currentFrame + 1; $("frameTitle").innerHTML = frameTitles[id][currentFrame]; } function gotoPrev(id) { var movie = getFlashMovieObject(id + "Blueprints"); if (currentFrame 0) { currentFrame--; } movie.GotoFrame(currentFrame); $("currentFrame").innerHTML = currentFrame + 1; $("frameTitle").innerHTML = frameTitles[id][currentFrame]; } function gotoNext(id) { var movie = getFlashMovieObject(id + "Blueprints"); if (currentFrame < movie.TotalFrames() - 1) { currentFrame++; } movie.GotoFrame(currentFrame); $("currentFrame").innerHTML = currentFrame + 1; $("frameTitle").innerHTML = frameTitles[id][currentFrame]; } function gotoLast(id) { var movie = getFlashMovieObject(id + "Blueprints"); currentFrame = movie.TotalFrames() - 1; movie.GotoFrame(currentFrame); $("currentFrame").innerHTML = currentFrame + 1; $("frameTitle").innerHTML = frameTitles[id][currentFrame]; } Btw, that $ is MooTools, not jQuery. Anyway, IE dies on the movie.TotalFrames() call. What can I do to solve this? Keep in mind I need this to be done via JavaScript, as I cannot edit the SWF.

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  • writing CMS in ZEND

    - by Neoman
    Hello guys, I'm trying to write my own CMS using Zend framework and I created modular structure. I have modules like 'news', 'blog' and etc. Also I have "admin" module which has different layout and this is like the administrator panel where admin can edit all the content and etc. But the problem is that I'm looking for the best practice and solution to solve the problem. I don't like the idea that my admin module will have a lot of controllers which will be for administer all the other modules. So I want to ask you all, maybe you have some tuts or just have an advice how to implement admin module separated from other modules as much as it can be done. Because I just want to copy one module for example from one project to another and I want it will work same. I don't want to search the right admin controller, view or something like this in admin module and copy this part seperatelly into new admin module. Hope the question and situation is clear enough and I will be happy to hear any advice or see any tutorials how to do it. Thanks guys!

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  • JSF don't find component in view root with the form id

    - by kenzokujpn
    I have a t:inputFileUpload inside the form, in the html of the display page the id of this component is form:inputFile but when I tried to get the component from the view root using "form:inputFile" the return is null, but when the "form:" is removed the return is the component. The component don't set the value in my managed bean, someone have this problem? EDIT: <h:form id="form" enctype="multipart/form-data"> <t:inputFileUpload id="inputFile" size="40" value="#{managedBean.inputFile}"/> </h:form> In the managed bean: private UploadedFile inputFile; with the gets and sets provided by Eclipse. //This method scans the view root and returns the component with the id passed as parameter findComponentInRoot("form:inputFile"); This returns null, but when I use: //This method scans the view root and returns the component with the id passed as parameter findComponentInRoot("inputFile"); The return is the component I'm looking for, but when I use the View Source in Internet Explorer the id of this component is "form:inputFile". I don't know if this is related, but the component don't set the value in my managed bean and it's strange the fact that the id of the component is different from the HTML source. I'm using JSF 1.2 Mojarra. Someone else has this problem? Or know why this happens?

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  • Use ini/appconfig file or sql server file to store user config?

    - by h2g2java
    I know that the preference for INI or appconfig XML is their human readability. Let's say user preferences stored for my app are hierarchical and numbers about a thousand items and it would be really confusing for a user to edit an INI to change things anyway. I have always been using a combination of INI with appconfig. I am leaning towards using sql server db file, now. Every time the user changes a preference while using the app, it would be stored into the db file - that's my line of thought. I am also thinking that such a config db file could move around with the app too, just like an INI. Before I do that, any advice 1. If there are any disadvantages against using a db file over INI or appconfig. 2. If a shop uses mysql or oracle, do you think your colleagues would lift up their pro-mysql or pro-oracle eyebrow questioning why you would use sql server technology in a mysql or oracle shop? I mean, I am just using it like an INI file or app.config anyway, right?

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  • How does the CheckBox obtain it's respective drawables?

    - by alex2k8
    The CheckBox class extends the CompoundButton, but add nothing to it. But some how it obtains it's respective look. I found some declarations in Android sources, but wonder how they are mapped to CheckBox class? public class CheckBox extends CompoundButton { public CheckBox(Context context) { this(context, null); } public CheckBox(Context context, AttributeSet attrs) { this(context, attrs, com.android.internal.R.attr.checkboxStyle); } public CheckBox(Context context, AttributeSet attrs, int defStyle) { super(context, attrs, defStyle); } } Styles <style name="Theme"> <item name="checkboxStyle">@android:style/Widget.CompoundButton.CheckBox</item> </style> <style name="Widget.CompoundButton.CheckBox"> <item name="android:background">@android:drawable/btn_check_label_background</item> <item name="android:button">@android:drawable/btn_check</item> </style> EDIT: Probably I was not clear... I understand how the drawable assigned to Widget.CompoundButton.CheckBox style, but how this style assigned to CheckBox class? I see the ".CheckBox" in the style name, but is this naming convention really what makes the trick? If so, what are the rules? If I derive MyCheckBox from CompoundButton, can I just define the Widget.CompoundButton.MyCheckBox style and it will work?

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  • Persistant Http client connections in java

    - by Akusete
    I am trying to write a simple Http client application in Java and am a bit confused by the seemingly different ways to establish Http client connections, and efficiently re-use the objects. Current I am using the following steps (I have left out exception handling for simplicity) Iterator<URI> uriIterator = someURIs(); HttpClient client = new DefaultHttpClient(); while (uriIterator.hasNext()) { URI uri = uriIterator.next(); HttpGet request = new HttpGet(uri); HttpResponse response = client.execute(request); HttpEntity entity = response.getEntity(); InputStream s = entity.getContent(); processStream (); s.close(); } In regard to the code above, my questions is: Assuming all URI's are pointing to the same host (but different resources on that host). What is the recommended way to use a single http connection for all requests? And how do you close the connection after the last request? --edit: Also what is the difference between using uri.openConnection(), versus HttpClient? Which is preferable, and what other methods exist?

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  • Is there an ORM that supports composition w/o Joins

    - by Ken Downs
    EDIT: Changed title from "inheritance" to "composition". Left body of question unchanged. I'm curious if there is an ORM tool that supports inheritance w/o creating separate tables that have to be joined. Simple example. Assume a table of customers, with a Bill-to address, and a table of vendors, with a remit-to address. Keep it simple and assume one address each, not a child table of addresses for each. These addresses will have a handful of values in common: address 1, address 2, city, state/province, postal code. So let's say I'd have a class "addressBlock" and I want the customers and vendors to inherit from this class, and possibly from other classes. But I do not want separate tables that have to be joined, I want the columns in the customer and vendor tables respectively. Is there an ORM that supports this? The closest question I have found on StackOverflow that might be the same question is linked below, but I can't quite figure if the OP is asking what I am asking. He seems to be asking about foregoing inheritance precisely because there will be multiple tables. I'm looking for the case where you can use inheritance w/o generating the multiple tables. Model inheritance approach with Django's ORM

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  • Drupal-- How to place an image in Panels 3 panels and mini-panels, w/o views or nodes?

    - by msumme
    Is it possible, through any modular functionality, to insert an image into a (mini-)panel, either through token replacement, or through an upload dialog, or through a file selection menu? Do I have to use views? Do I have to create nodes? Would the best way be to make a panel node, and then embed it in a mini-node, if I want a block-like panel that can be placed on multiple pages? I want to build a site with images in a particular layout as a small block, and make it very easy for my client to change those images in the future. I can think of some other ways to make this work, but it's driving me crazy that there seems to be no way to simply PUT an image in a mini-panel without having to upload it and hard-code an image tag. And since my client knows no HTML, coding it this way makes it un-helpful for him. And this mini-panel block is going to be used on a number of pages, and needs to be easily modified. I have been googling for about 45 minutes, and come up with nothing useful. EDIT: OR EVEN just put ONLY one image from an image field w/ multiple values in a panel region on a panel node?

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  • EOFException in ObjectInputStream Only happens with Webstart not by java(w).exe ?!

    - by Houtman
    Hi, Anyone familiar with the differences in starting with Webstart(javaws.exe) compared to starting the app. using java.exe or javaw.exe regarding streams ? This is the exception which i ONLY get when using Webstart : java.io.EOFException at java.io.ObjectInputStream$PeekInputStream.readFully(Unknown Source) at java.io.ObjectInputStream$BlockDataInputStream.readShort(Unknown Source) at java.io.ObjectInputStream.readStreamHeader(Unknown Source) at java.io.ObjectInputStream.<init>(Unknown Source) at fasttools.jtools.dss.api.core.remoting.thinclient.RemoteSocketChannel.<init>(RemoteSocketChannel.java:77) This is how i setup the connections on both sides //==Server side== //Thread{ Socket mClientSocket = cServSock.accept(); new DssServant(mClientSocket).start(); //} DssServant(Socket socket) throws DssException { try { OutputStream mOutputStream = new BufferedOutputStream( socket.getOutputStream() ); cObjectOutputStream = new ObjectOutputStream(mOutputStream); cObjectOutputStream.flush(); //publish streamHeader InputStream mInputStream = new BufferedInputStream( socket.getInputStream() ); cObjectInputStream = new ObjectInputStream(mInputStream); .. } catch (IOException e) { .. } .. } //==Client side== public RemoteSocketChannel(String host, int port, IEventDispatcher eventSubscriptionHandler) throws DssException { cHost = host; port = (port == 0 ? DssServer.PORT : port); try { cSocket = new Socket(cHost, port); OutputStream mOutputStream = new BufferedOutputStream( cSocket.getOutputStream() ); cObjectOut = new ObjectOutputStream(mOutputStream); cObjectOut.flush(); //publish streamHeader InputStream mInputStream = new BufferedInputStream( cSocket.getInputStream() ); cObjectIn = new ObjectInputStream(mInputStream); } catch (IOException e) { .. } .. } Thanks [EDIT] Webstart console says: Java Web Start 1.6.0_19 Using JRE version 1.6.0_19-b04 Java HotSpot(TM) Client VM Server is running same 1.6u19

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  • Rails: generating URLs for actions in JSON response

    - by Chris Butler
    In a view I am generating an HTML canvas of figures based on model data in an app. In the view I am preloading JSON model data in the page like this (to avoid an initial request back): <script type="text/javascript" charset="utf-8"> <% ActiveRecord::Base.include_root_in_json = false -%> var objects = <%= @objects.to_json(:include => :other_objects) %>; ... Based on mouse (or touch) interaction I want to redirect to other parts of my app that are model specific (such as view, edit, delete, etc.). Rather than hard code the URLs in my JavaScript I want to generate them from Rails (which means it always adapts the latest routes). It seems like I have one of three options: Add an empty attr to the model that the controller fills in with the appropriate URL (we don't want to use routes in the model) before the JSON is generated Generate custom JSON where I add the different URLs manually Generate the URL as a template from Rails and replace the IDs in JavaScript as appropriate I am starting to lean towards #1 for ease of implementation and maintainability. Are there any other options that I am missing? Is #1 not the best? Thanks! Chris

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  • Access Flash Symbol Via Code from an .as Class

    - by David
    Hi, I've got a movie clip symbol in my .fla file that I need to reference in an .as file which is in a subfolder in the project. I select the symbol in the library and edit its properties. Its name is bubble; I Export for ActionScript and Export in frame 1. I give it a class name of Bubble. Now I need to go to my .as class, called SomeClass.as There, I need to reference the symbol, because I want to move it from within related code in that .as file. But if I try bubble.x I get an error. If I try var myBubble:Bubble = new Bubble(); I get 'Access of undefined property myBubble'. I was told that I might try 'importing the document class' but how do you import a class which is in the root directory of your app from within a class that's in a subfolder? (Don't know if this would provide the solution anyway)... Tanks.

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  • Is there a good way to execute MySQL statements atomically via JDBC?

    - by javanix
    Suppose I have a table that contains valid data. I would like to modify this data in some way, but I'd like to make sure that if any errors occur with the modification, the table isn't changed and the method returns something to that effect. For instance, (this is kind of a dumb example, but it illustrates the point so bear with me) suppose I want to edit all the entries in a "name" column so that they are properly capitalized. For some reason, I want either ALL of the names to have proper capitalization, or NONE of them to have proper capitalization (and the starting state of the table is that NONE of them do). Is there an already-implemented way to run a batch update on the table and be assured that, if any one of the updates fails, all changes are rolled back and the table remains unchanged? I can think of a few ways to do this by hand (though suggestions are welcomed), but it'd be nice if there was some method I could use that would function this way. I looked at the java.sql.statement.executeBatch() command, but I'm not convinced by the documentation that my table wouldn't be changed if it failed in some manner.

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  • Transitioning from Domain Authentication to SQL Server Authentication

    - by Albert Perrien
    Greetings all, I've run into a problem that has me stumped. I've put together a database in SQL Server Express, and I'm having a strange permissions problem. The database is on my development machine with a domain user: DOMAIN\albertp. My development database server is set for "SQL Server and Windows Authentication" mode. I can edit and query my database without any problems when I log in using Windows Authentication. However, when I log in to any user that uses SQL Server authentication (Including sa) I get this message when I run queries against my database. SELECT * FROM [Testing].[dbo].[AuditingReport] I get: Msg 18456, Level 14, State 1, Line 1 Login failed for user 'auditor'. I'm logged into the server from SQL Server Management Studio as 'auditor' and I don't see anything in the error log about the login failure. I've already run: Use Testing; Grant All to auditor; Go And I still get the same error. What permissions do I have to set for the database to be usable by others outside of my personal domain login? Or am I looking at the wrong problem? My ultimate goal is to have the database be accessible from a set of PHP pages, using a either a common login (hence 'auditor') or a login specific to a set of individual users.

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  • Passing arguments and values from HTML to jQuery (events)

    - by Jaroslav Moravec
    What is the practice to pass arguments from HTML to jQuery events function. For example getting id of row from db: <tr class="jq_killMe" id="thisItemId-id"> ... </tr> and jQuery: $(".jq_killMe").click(function () { var tmp = $(this).attr('id).split("-"); var id = tmp[0] // ... } What's the best practise, if I want to pass more than one argument? Is it better not to use jQuery? For example: <tr onclick="killMe('id')"> ... </tr> I didn't find the answer on my question, I will be glad even for links. Thanks. Edit (pre solution) So you suggested two methods to do that: Add custom attributes to element (XHTML) Use attribute ID and parse it by regex Attribute data-* attributes in HTML5 Use hidden children elements I like first solution, but... I would like to (I have to (employer)) produce valid code. Here is a nice question and answers: http://stackoverflow.com/questions/994856/so-what-if-custom-html-attributes-arent-valid-xhtml And the second is not so pretty as the first, but valid. So the compromise is... The third is the solution for future, but here is a lot of CMS where we have to use XHTML or HTML4. (And HTML5 is the long process)

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  • Disable control in .aspx from Masterpage conditionally

    - by miccet
    Ok, this might be a bit weird, so I'll start with explaining what I'm trying to do. I have several masterpages for my site, and in they inherit each other. In the second of them (4 in total) I have a background image. Here comes the trick, I'd like to override this image from the final aspx page. I can't change the position of this image, it has to be in masterpage 2, since some pages uses that very page as masterpage. One idea I had was to create a ContentPlaceHolder next to the image and if there are any images in that (check in Page_Load) then the main image would be hidden. I did this with a recursive function, that finds the image by looping through the ContentPlaceHolder's controls. When I set the visibility property to false though, nothing happens. Any other ideas to how this could be done, or why the above doesn't work? Edit: It's not about changing items in the master pages, rather the other way around, that from the Masterpages codebehind dig down into the page that is displayed currently and see if it has controls in a specific ContentPlaceHolder.

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  • Requirements for connecting to Oracle with JDBC?

    - by Lord Torgamus
    I'm a newbie to Java-related web development, and I can't seem to get a simple program with JDBC working. I'm using off-the-shelf Oracle 10g XE and the Eclipse EE IDE. From the books and web pages I've checked so far, I've narrowed the problem down to either an incorrectly written database URL or a missing JAR file. I'm getting the following error: java.sql.SQLException: No suitable driver found for jdbc:oracle://127.0.0.1:8080 with the following code: import java.sql.*; public class DatabaseTestOne { public static void main(String[] args) { String url = "jdbc:oracle://127.0.0.1:8080"; String username = "HR"; String password = "samplepass"; String sql = "SELECT EMPLOYEE_ID FROM EMPLOYEES WHERE LAST_NAME='King'"; Connection connection; try { connection = DriverManager.getConnection(url, username, password); Statement statement = connection.createStatement(); System.out.println(statement.execute(sql)); connection.close(); } catch (SQLException e) { System.err.println(e); } } } What is the proper format for a database URL, anyways? They're mentioned a lot but I haven't been able to find a description. Thanks! EDIT (the answer): Based on duffymo's answer, I got ojdbc14.jar from http://www.oracle.com/technology/software/tech/java/sqlj_jdbc/htdocs/jdbc_10201.html and dropped it in the Eclipse project's Referenced Libraries. Then I changed the start of the code to ... try { Class.forName("oracle.jdbc.driver.OracleDriver"); } catch (ClassNotFoundException e) { System.err.println(e); } // jdbc:oracle:thin:@<hostname>:<port>:<sid> String url = "jdbc:oracle:thin:@GalacticAC:1521:xe"; ... and it worked.

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  • Why rails app is redirecting unexpectedly instead of matching the route?

    - by ruevaughn
    I asked this question earlier and thought it was fixed, but it's not. Previous question here My problem is I am trying to set my routes so that when I type in localhost:3000/sites/admin It should redirect to localhost:3000/en/sites/admin here is my routes.rb file scope ":locale", locale: /#{I18n.available_locales.join("|")}/ do get "log_out" => "sessions#destroy", as: "log_out" get "log_in" => "sessions#new", as: "log_in" resources :sites, except: [:new, :edit, :index, :show, :update, :destroy, :create] do collection do get :home get :about_us get :faq get :discounts get :services get :contact_us get :admin get :posts end end resources :users resources :abouts resources :sessions resources :coupons resources :monthly_posts resources :reviews resources :categories do collection { post :sort } resources :children, :controller => :categories, :only => [:index, :new, :create, :new_subcategory] end resources :products do member do put :move_up put :move_down end end resources :faqs do collection { post :sort } end root :to => 'sites#home' match "/savesort" => 'sites#savesort' end match '', to: redirect("/#{I18n.default_locale}") match '*path', to: redirect("/#{I18n.default_locale}/%{path}") But as of right now, it redirects to /en/en/en/en/en/en/en/en/en/en/sites/admin (adds en until browser complains). Any thoughts why it keeps adding /en?

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  • How to use associated Model as datasource for DataView

    - by Chris Gilbert
    I have a Model structure as shown below and I want to know how to use the Bookings array as the datasource of my DataView. Model Structure: Client ClientId Name Bookings (HasManyAssociation) Contacts (HasManyAssociation) AjaxProxy JsonReader (ImplicitIncludes is set to true so child models are created with one call) Booking BookingNodeId BookingDetails Contact ContactNodeId ContactDetails The above gives me a data structure as follows: Client Bookings[ Booking Booking ] Contacts[ Contact Contact ] What I want to be able to do is either, create a Store from my Bookings array and then use that store as the datasource for my DataView OR directly use the Bookings array as the datasource (I don't really care how I do it to be honest). If I setup the AjaxProxy on my Booking model it works fine but then obviously I cannot automatically create my Client and Contacts when I load my JSON. It seems to me to make sense that the Client model, being the top level model hierarchically, is the one to load the data. EDIT: I figured it out as follows (with special thanks to handet87 below for his dataview.setStore() pointer). The key in this case is to know that creating the relationship actually sets up another store called, in this case BookingsStore and ContactsStore. All I needed to do was dataview.setStore("BookingsStore")

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  • Issue calling superclass method in subclass constructor

    - by stormin986
    I get a NullPointerException calling a Superclass Method in Subclass Inner Class Constructor... What's the Deal? In my application's main class (subclass of Application), I have a public inner class that simply contains 3 public string objects. In the parent class I declare an object of that inner class. public class MainApplication extends Application { public class Data { public String x; public String y; public String z; } private Data data; MainApplication() { data = new Data() data.x = SuperClassMethod(); } } After I instantiate the object in the constructor, I get a runtime error when I try to assign a value in the inner class with a superclass method. Any idea what's up here?? Can you not call superclass methods in the subclass constructor? ** Edit ** Original question was about inner class member assignment in outer class constructor. Turned out the issue was with calling a superclass method in the class's constructor. It was giving me a null pointer exception. Thus, the question has changed.

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  • Question about decorator pattern and the abstract decorator class?

    - by es11
    This question was asked already here, but rather than answering the specific question, descriptions of how the decorator pattern works were given instead. I'd like to ask it again because the answer is not immediately evident to me just by reading how the decorator pattern works (I've read the wikipedia article and the section in the book Head First Design Patterns). Basically, I want to know why an abstract decorator class must be created which implements (or extends) some interface (or abstract class). Why can't all the new "decorated classes" simply implement (or extend) the base abstract object themselves (instead of extending the abstract decorator class)? To make this more concrete I'll use the example from the design patterns book dealing with coffee beverages: There is an abstract component class called Beverage Simple beverage types such as HouseBlend simply extend Beverage To decorate beverage, an abstract CondimentDecorator class is created which extends Beverage and has an instance of Beverage Say we want to add a "milk" condiment, a class Milk is created which extends CondimentDecorator I'd like to understand why we needed the CondimentDecorator class and why the class Milk couldn't have simply extended the Beverage class itself and been passed an instance of Beverage in its constructor. Hopefully this is clear...if not I'd simply like to know why is the abstract decorator class necessary for this pattern? Thanks. Edit: I tried to implement this, omitting the abstract decorator class, and it seems to still work. Is this abstract class present in all descriptions of this pattern simply because it provides a standard interface for all of the new decorated classes?

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  • Using bash to copy file to spec folders

    - by Franko
    I have a folder with a fair amount of subfolders. In some of the subfolders do I have a folder.jpg picture. What I try to do find that folder(s) and copy it to all other subfolders that got the same artist and album information then continue on to the next album etc. The structure of all the folders are "artist - year - album - [encoding information]". I have made a really simple one liner that find the folders that got the file but there am I stuck. ls -F | grep / | while read folders;do find "$folders" -name folder.jpg; done Anyone have any good tip or ideas how to solve this or pointers how to proceed? Edit: First of all, i´m real new to this (like you cant tell) so please have patience. Ok, let me break it down even more. I have a folder structure that looks like this: artist1 - year - album - [flac] artist1 - year - album - [mp3] artist1 - year - album - [AAC] artist2 - year - album - [flac] etc I like to loop over the set of folders that have the same artist and album information and look for a folder.jpg file. When I find that file do I like to copy it to all of the other folders in the same set. Ex if I find one folder.jpg in artist1 - year - album - [flac] folder do I like to have that folder.jpg copied to artist1 - year - album - [mp3] & artist1 - year - album - [AAC] but not to artist2 - year - album - [flac]. The continue the loop until all the sets been processed. I really hope that makes it a bit more easy to understand what I try to do :)

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