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  • Why some user functions don't get recognised by bash?

    - by strapakowsky
    I can define a function like: myfunction () { ls -R "$1" ; } And then myfunction . just works. But if I do echo "myfunction ." | sh echo "myfunction ." | bash the messages are: sh: myfunction: not found bash: line 1: myfunction: command not found Why? And how can I call a function that comes from a string if not by piping it to sh or bash? I know there is this command source, but I am confused of when I should use source and when sh or bash. Also, I cannot pipe through source. To add to confusion, there is this command . that seems to have nothing to do with the "." that means "current directory".

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  • Why does this script not open parallel gnome-terminals on a server?

    - by broiyan
    Why am I not able to have parallel gnome-terminals on my server while I can on my client. Here is a test that illustrates the problem. #!/bin/bash # this is the parent script gnome-terminal --command "./left.sh" sleep 10 gnome-terminal --command "./right.sh" #!/bin/bash echo "this is the left script" read -p "press any key to close this terminal" key #!/bin/bash echo "this is the right script" read -p "press any key to close this terminal" key When I run this on a regular ubuntu desktop (maverick) I see two terminals after 10 seconds. When I run this on a maverick server at a server farm, the second window does not appear until after I close the first one and wait 10 seconds. I am using tightvncserver to view the server desktop. (I could have simplified a bit more. The 10 second sleep is extraneous to the problem. In my real world application I need the first terminal to do some real work before starting the second. The problem probably still exists even if there is no sleep.)

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  • rc.local is not always executed upon boot

    - by starcorn
    Hey, I have some weird problem with the rc.local file which is located in /etc/rc.local the thing is that it is not always running when I boot up the laptop. Maybe every second time, I haven't counted. Anyway when that happens I have to manually go to terminal and type sudo /etc/init.d/rc.local start, which kinda kills the purpose of having this script. Anyone know what the problem could be? EDIT Since this wasn't obvious. This is an issue where I make a fresh boot up. Which mean I have shut down the computer. And next time when I boot up the computer, the rc.local file is randomly deciding whether it will automatically start or not. Here's a copy of what my rc.local file contains echo -n 255 > /sys/devices/platform/i8042/serio1/serio2/sensitivity echo level 2 > /proc/acpi/ibm/fan touch /home/starcorn/Desktop/foo rfkill block bluetooth exit 0

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  • genisoimage and exec bit preservation

    - by user92187
    Maybe I'm just not doing right, but I can't seem to get genisoimage to produce a UDF image and preserve the exec bit. $ genisoimage --version genisoimage 1.1.11 (Linux) $ echo "echo 'Hello world'" > script.sh $ chmod +x script.sh $ ./script.sh Hello world $ genisoimage -input-charset utf-8 -r -udf -volid minimal -o minimal.iso script.sh Total translation table size: 0 Total rockridge attributes bytes: 250 Total directory bytes: 0 Path table size(bytes): 10 Max brk space used 0 420 extents written (0 MB) $ mkdir mount $ sudo mount minimal.iso $PWD/mount -o ro,loop -t udf $ ls -l script.sh mount/script.sh -r--r--r-- 1 root root 19 Sep 21 18:40 mount/script.sh -rwxrwxr-x 1 kip kip 19 Sep 21 18:40 script.sh You'll note in the last command that script.sh was executable at the time it was injected into the image, but does not appear to be inside of the mounted image. Is this a bug in genisoimage, a problem with the way I am mounting the image, or a problem in my usage of genisoimage?

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  • grid layout default on wordpress theme

    - by nathan philpott
    I'm having trouble with a multi-layout option on a wordpress theme sight http://sight.wpshower.com/ the traffic have the option of a grid or a list layout at the click of a button. at present the list layout is default. I am interested in making the grid layout default . this is some of the php, i tried simply swapping the word grid for list but although this does work to an extent , if done on the loop.php page it removes the a:hover functions on the post boxes in the grid format. also if done on the index.php it switches buttons on the main index page. any ideas?? loop.php <div id="loop" class="<?php if ($_COOKIE['mode'] == 'grid') echo 'grid'; else echo 'list'; ?> clear"> <?php while ( have_posts() ) : the_post(); ?> <div <?php post_class('post clear'); ?> id="post_<?php the_ID(); ?>"> <?php if ( has_post_thumbnail() ) :?> <a href="<?php the_permalink() ?>" class="thumb"><?php the_post_thumbnail('thumbnail', array( 'alt' => trim(strip_tags( $post->post_title )), 'title' => trim(strip_tags( $post->post_title )), )); ?></a> <?php endif; ?> <div class="post-category"><?php the_category(' / '); ?></div> <h2><a href="<?php the_permalink() ?>"><?php the_title(); ?></a></h2> <!-- <div class="post-meta">by <span class="post-author"><a href="<?php echo get_author_posts_url(get_the_author_meta('ID')); ?>" title="Posts by <?php the_author(); ?>"><?php the_author(); ?></a></span> on <span class="post-date"><?php the_time(__('M j, Y')) ?></span> <em>&bull; </em><?php comments_popup_link(__('No Comments'), __('1 Comment'), __('% Comments'), '', __('Comments Closed')); ?> <?php edit_post_link( __( 'Edit entry'), '<em>&bull; </em>'); ?> </div> --> <?php edit_post_link( __( 'Edit entry'), '<em>&bull; </em>'); ?> <div class="post-content"><?php if (function_exists('smart_excerpt')) smart_excerpt(get_the_excerpt(), 55); ?></div> </div> <?php endwhile; ?> </div> <?php endif; ?> index.php <?php get_header(); ?> <div class="content-title"> Projects <a href="javascript: void(0);" id="mode"<?php if ($_COOKIE['mode'] == 'grid') echo ' class="flip"'; ?>></a> </div> <?php query_posts(array( 'post__not_in' => $exl_posts, 'paged' => $paged, ) ); ?> <?php get_template_part('loop'); ?> <?php wp_reset_query(); ?> <?php get_template_part('pagination'); ?> <?php get_footer(); ?>

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  • Setting a display's backlight brightness to be lower than is possible via the normal brightness controls

    - by Drew Noakes
    By normal brightness controls I mean the accelerators on my laptop's keyboard that seem to integrate with Unity. In a dark room, my screen is quite bright, even on the lowest setting. Can I override this? I tried setting it explicitly via both: sudo echo 500 > /sys/class/backlight/acpi_video0/actual_brightness sudo echo 500 > /sys/class/backlight/intel_backlight/actual_brightness But I get a permission denied error. When at the lower bounds via my keyboard's brighness controls, acpi_video0/actual_brightness is 0, and intel_backlight/actual_brightness is 729. Can I set the latter value to be even lower?

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  • php/dos : How do you parse a regedit export file?

    - by phill
    My objective is to look for Company key-value in the registry hive and then pull the corresponding Guid and other keys and values following it. So I figured i would run the regedit export command and then parse the file with php for the keys I need. So after running the dos batch command >regedit /E "output.txt" "HKLM\System....\Company1" The output textfile seems to be in some kind of UNICODE format which isn't regex friendly. I'm using php to parse the file and pull the keys. Here is the php code i'm using to parse the file <?php $regfile = "output.txt"; $handle = fopen ("c:\\\\" . $regfile,"r"); //echo "handle: " . $file . "<br>"; $row = 1; while ((($data = fgets($handle, 1024)) !== FALSE) ) { $num = count($data); echo "$num fields in line $row: \n"; $reg_section = $data; //$reg_section = "[HKEY_LOCAL_MACHINE\SOFTWARE\TECHNOLOGIES\MEDIUS\CONFIG MANAGER\SYSTEM\COMPANIES\RECORD11]"; $pattern = "/^(\[HKEY_LOCAL_MACHINE\\\SOFTWARE\\\TECHNOLOGIES\\\MEDIUS\\\CONFIG MANAGER\\\SYSTEM\\\COMPANIES\\\RECORD(\d+)\])$/"; if ( preg_match($pattern, $reg_section )) { echo "<font color=red>Found</font><br>"; } else { echo "not found<br>"; echo $data . "<br>"; } $row++; } //end while fclose($handle); ?> and the output looks like this.... 1 fields in line 1: not found ÿþW?i?n?d?o?w?s? ?R?e?g?i?s?t?r?y? ?E?d?i?t?o?r? ?V?e?r?s?i?o?n? ?5?.?0?0? ? 1 fields in line 2: not found 1 fields in line 3: not found [?H?K?E?Y??L?O?C?A?L??M?A?C?H?I?N?E?\?S?O?F?T?W?A?R?E?\?I?N?T?E?R?S?T?A?R? ?T?E?C?H?N?O?L?O?G?I?E?S?\?X?M?E?D?I?U?S?\?C?O?N?F?I?G? ?M?A?N?A?G?E?R?\?S?Y?S?T?E?M?\?C?O?M?P?A?N?I?E?S?]? ? 1 fields in line 4: not found "?N?e?x?t? ?R?e?c?o?r?d? ?I?D?"?=?"?4?1?"? ? 1 fields in line 5: not found Any ideas how to approach this? thanks in advance

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  • How do I get long command lines to wrap to the next line?

    - by BrianH
    Edit It was my .bashrc file. I've copied the same profile from machine to machine, and I used special characters in my $PS1 that are somehow throwing it off. I'm now sticking with the standard bash variables for my $PS1. Thanks to @ændrük for the tip on the .bashrc! ...End Edit... Something I have noticed in Ubuntu for a long time that has been frustrating to me is when I am typing a command at the command line that gets longer (wider) than the terminal width, instead of wrapping to a new line, it goes back to column 1 on the same line and starts over-writing the beginning of my command line. (It doesn't actually overwrite the actual command, but visually, it is overwriting the text that was displayed). It's hard to explain without seeing it, but let's say my terminal was 20 characters wide (Mine is more like 120 characters - but for the sake of an example), and I want to echo the English alphabet. What I type is this: echo abcdefghijklmnopqrstuvwxyz But what my terminal looks like before I hit the key is: pqrstuvwxyzghijklmno When I hit enter, it echos abcdefghijklmnopqrstuvwxyz so I know the command was received properly. It just wrapped my typing after the "o" and started over on the same line. What I would expect to happen, if I typed this command in on a terminal that was only 20 characters wide would be this: echo abcdefghijklmno pqrstuvwxyz Background: I am using bash as my shell, and I have this line in my ~/.bashrc: set -o vi to be able to navigate the command line with VI commands. I am currently using Ubuntu 10.10 server, and connecting to the server with Putty. In any other environment I have worked in, if I type a long command line, it will add a new line underneath the line I am working on when my command gets longer than the terminal width and when I keep typing I can see my command on 2 different lines. But for as long as I can remember using Ubuntu, my long commands only occupy 1 line. This also happens when I am going back to previous commands in the history (I hit Esc, then 'K' to go back to previous commands) - when I get to a previous command that was longer than the terminal width, the command line gets mangled and I cannot tell where I am at in the command. The only work-around I have found to see the entire long command is to hit "Esc-V", which opens up the current command in a VI editor. I don't think I have anything odd in my .bashrc file. I commented out the "set -o vi" line, and I still had the problem. I downloaded a fresh copy of Putty and didn't make any changes to the configuration - I just typed in my host name to connect, and I still have the problem, so I don't think it's anything with Putty (unless I need to make some config changes) Has anyone else had this problem, and can anyone think of how to fix it? Thanks in advance! Brian

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  • ThinkPad fan control via procfs

    - by asebian
    My ThinkPad W500 used to crash sometimes under heavy load because the automatic control is not speeding up the fan far enough. But I was able to disengage the fan and let it run at full speed in Ubuntu 10.10. But this does not work in my new nice and shiny Ubuntu 11.10. Have a glimpse at fan control device. % ls -l /proc/acpi/ibm/fan -rw-r--r-- 1 root root 0 2012-03-18 15:46 /proc/acpi/ibm/fan % cat /proc/acpi/ibm/fan status: enabled speed: 3056 level: auto Now become super user in a fresh and clean environment and send control sequence. % exec sudo env -i bash -l $ echo 'level disengaged' >/proc/acpi/ibm/fan bash: echo: write error: Invalid argument What did I miss? Thanks for suggests.

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  • Receive the Broadcast program with XML [on hold]

    - by bitmez4
    I have a channel publishing sites and I wanna get into the channel CNN broadcast program.. CNN broadcast the program here: (you can see in source - xml File) http://tvprofil.net/xmltv/data/cnn.info/weekly_cnn.info_tvprofil.net.xml How the data according to the time of withdrawal? For example: Now program: "bitmez's table" next program: "stack's table" in 30 minute Is this possible? UPDATE 1 // -I can take the XML data but to all of XML file- <?php if(!$xml=simplexml_load_file('http://tvprofil.net/xmltv/data/cnn.info/weekly_cnn.info_tvprofil.net.xml')){ trigger_error('XML file -- read error',E_USER_ERROR); } echo 'X-'; foreach($xml as $programme){ echo 'Now: '.$programme->title.' <br/>'; } ?>

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  • How can I keep directories in sync

    - by Guillaume Boudreau
    I have a directory, dirA, that users can work in: they can create, modify, rename and delete files & sub-directores in dirA. I want to keep another directory, dirB, in sync with dirA. What I'd like, is a discussion on finding a working algorithm that would achieve the above, with the limitations listed below. Requirements: 1. Something asynchronous - I don't want to stop file operations in dirA while I work in dirB. 2. I can't assume that I can just blindly rsync dirA to dirB on regular interval - dirA could contain millions of files & directories, and terrabytes of data. Completely walking the dirA tree could take hours. Those two requirements makes this really difficult. Having it asynchronous means that when I start working on a specific file from dirA, it might have moved a lot since it appeared. And the second limitation means that I really need to watch dirA, and work on atomic file operations that I notice. Current (broken) implementation: 1. Log all file & directory operations in dirA. 2. Using a separate process, read that log, and 'repeat' all the logged operations in dirB. Why is it broken: echo 1 > dirA/file1 # Allow the 'log reader' process to create dirB/file1: log = "write dirA/file1"; action = cp dirA/file1 dirB/file1; result = OK echo 1 > dirA/file2 mv dirA/file1 dirA/file3 mv dirA/file2 dirA/file1 rm dirA/file3 # End result: file1 contains '1' # 'log reader' process starts working on the 4 above file operations: log = "write file2"; action = cp dirA/file2 dirB/file2; result = failed: there is no dirA/file2 log = "rename file1 file3"; action = mv dirB/file1 dirB/file3; result = OK log = "rename file2 file1"; action = mv dirB/file2 dirB/file1; result = failed: there is no dirB/file2 log = "delete file3"; action = rm dirB/file3; result = OK # End result in dirB: no more files! Another broken example: echo 1 > dirA/dir1/file1 mv dirA/dir1 dirA/dir2 # 'log reader' process starts working on the 2 above file operations: log = "write file1"; action = cp dirA/dir1/file1 dirB/dir1/file1; result = failed: there is no dirA/dir1/file1 log = "rename dir1 dir2"; action = mv dirB/dir1 dirB/dir2; result = failed: there is no dirA/dir1 # End result if dirB: nothing!

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  • PATH command not found

    - by joslinm
    Hi, I'm not experienced with PATH (Any good reference would be appreciated), but I made a mistake and did PATH=/google_appengine, which I'm assuming completely overrid PATH. Still, I restarted bash and echo'd PATH and found that the folders were back. mark@mark-laptop:~$ echo $PATH /usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games However, when I then tried to append to it, I got an error that PATH wasn't found. I've looked around Google and couldn't find a good answer. Any help would be appreciated mark@mark-laptop:~$ PATH = $PATH:/google_appengine PATH: command not found

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  • How do I get long command lines to wrap to the next line?

    - by BrianH
    Edit It was my .bashrc file. I've copied the same profile from machine to machine, and I used special characters in my $PS1 that are somehow throwing it off. I'm now sticking with the standard bash variables for my $PS1. Thanks to @ændrük for the tip on the .bashrc! ...End Edit... Something I have noticed in Ubuntu for a long time that has been frustrating to me is when I am typing a command at the command line that gets longer (wider) than the terminal width, instead of wrapping to a new line, it goes back to column 1 on the same line and starts over-writing the beginning of my command line. (It doesn't actually overwrite the actual command, but visually, it is overwriting the text that was displayed). It's hard to explain without seeing it, but let's say my terminal was 20 characters wide (Mine is more like 120 characters - but for the sake of an example), and I want to echo the English alphabet. What I type is this: echo abcdefghijklmnopqrstuvwxyz But what my terminal looks like before I hit the key is: pqrstuvwxyzghijklmno When I hit enter, it echos abcdefghijklmnopqrstuvwxyz so I know the command was received properly. It just wrapped my typing after the "o" and started over on the same line. What I would expect to happen, if I typed this command in on a terminal that was only 20 characters wide would be this: echo abcdefghijklmno pqrstuvwxyz Background: I am using bash as my shell, and I have this line in my ~/.bashrc: set -o vi to be able to navigate the command line with VI commands. I am currently using Ubuntu 10.10 server, and connecting to the server with Putty. In any other environment I have worked in, if I type a long command line, it will add a new line underneath the line I am working on when my command gets longer than the terminal width and when I keep typing I can see my command on 2 different lines. But for as long as I can remember using Ubuntu, my long commands only occupy 1 line. This also happens when I am going back to previous commands in the history (I hit Esc, then 'K' to go back to previous commands) - when I get to a previous command that was longer than the terminal width, the command line gets mangled and I cannot tell where I am at in the command. The only work-around I have found to see the entire long command is to hit "Esc-V", which opens up the current command in a VI editor. I don't think I have anything odd in my .bashrc file. I commented out the "set -o vi" line, and I still had the problem. I downloaded a fresh copy of Putty and didn't make any changes to the configuration - I just typed in my host name to connect, and I still have the problem, so I don't think it's anything with Putty (unless I need to make some config changes) Has anyone else had this problem, and can anyone think of how to fix it? Thanks in advance! Brian

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  • How to get the selected option value of a drop down box in PHP code

    - by Angeline Aarthi
    I have a dropdown box which lists a set of logos,like flower,butterfly etc. <p class="title1">Logo</p> <select name="logoMenu" class="select" size="7"> <?php foreach($logos as $logo):?> <option id="<?php echo $logo['Subproperty']['id'];?>" value="<?php echo $logo['Subproperty']['values'];?>"><?php echo $logo['Subproperty']['values'];?> </option> <?php endforeach;?> </select> Suppose If I select the logo 'Flower' from the drop down box, I want the flower pic to be displayed in a div.This is the div that I have to display the pictures. <div id="theme_logos" class="float_left spaceleft" style="display:none;"> <?php foreach($defaultLogos as $logo): //if($logo['Subproperty']['values']==clicked option value){?> <img height="50" width="50" src="/FormBuilder/app/webroot/img/themes/<?php echo $logo['Subproperty']['images'];?>" class="float_left user_profile_image user_profile_image" alt="Default50"/> <?php endforeach;?> </div> The problem with this code is that it displaya all the pictures found in the table. Because im My controller code, I give only the property id as that of 'Logo',but do not give which logo. $this->set('defaultLogos',$this->Subproperty->find('all',array('conditions'=>array('Subproperty.property_id'=>1,'Subproperty.values'=>"Flower")))); Here I have hard coded as 'flower' so that I get the flower picture alone.. If I select the logo from the drop down box, how to pass that selected value to the controller code? Or if I get the selected logo name thro' jquery,how to use that value in the if condition inside the for each loop? someone help me out with this.. I'm using CakePHP framework. $("#logoMenu option").click(function(){ selectedLogo=$(this).attr("value"); $('#subproperty_id').val($(this).attr("id")); if(selectedLogo=="Your logo"){ $("#themes_upload").show(); } else{ alert(selectedLogo); $("#themes_upload").hide(); $("#theme_logos").show(); } }); EDIT Now I have tried an ajax post where I pass the selected logo to the same action of the controller. I get the value when I alert the passed value in the success function of the ajax function. I the picture doesn't appear. $("#logoMenu option").click(function(){ selectedLogo=$(this).attr("value"); $('#subproperty_id').val($(this).attr("id")); if(selectedLogo=="Your logo"){ $("#themes_upload").show(); } else{ alert(selectedLogo); $.ajax({ type: "POST", url: "http://localhost/FormBuilder/index.php/themes/themes/", async: false, data: "selectedLogo="+selectedLogo, success: function(msg){ alert( "Data Saved: " + msg); } }); $("#themes_upload").hide(); $("#theme_logos").show(); } }); function themes(){ $this->set('themes',$this->Theme->find('all')); $logo=$this->params['form']['selectedLogo']; echo "logo:".$logo; $this->set('defaultLogos',$this->Subproperty->find('all',array('conditions'=>array('Subproperty.property_id'=>1,'Subproperty.values'=>$logo)))); } But when I trry to display the img in the page,it doesn't appear. Is it because the div show command is after the ajax request?

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  • Not recognize JDK after installation in ubuntu 12.10

    - by HFDev
    I did these steps without error: 1-JDK path : Downloads/jdk-6u37-linux-x64.bin 2-Commands in Terminal : mkdir Programs cd Programs bash ../Downloads/jdk-6u37-linux-x64.bin ln -s jdk-6u37-linux-x64 jdk 3-Set JAVA_HOME and Path: in HomeView MenuShow Hidden Files Then open .bashrc in text editor. I added the following lines to end of file. export JAVA_HOME=$Home/Programs/jdk export PATH=:$JAVA_HOME/bin:$PATH --------------------------------------------------------------------------------------- This is the result of executing the command echo $JAVA_HOME : /Programs/jdk This is the result of executing the command echo $PATH : :/Programs/jdk/bin:/usr/lib/lightdm/lightdm:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games1 ---------------------------------------------------------------------------------------- And problem is : This is the result of executing the command java -version : The program 'java' can be found in the following packages: * default-jre * gcj-4.6-jre-headless * gcj-4.7-jre-headless * openjdk-7-jre-headless * openjdk-6-jre-headless Try: sudo apt-get install

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  • disable shutdown/suspend if there is other user logged in via ssh

    - by Denwerko
    I remember that in versions of ubuntu around 9.04 was possible to disable user to shutdown ( and maybe suspend too ) system if there was other user logged in.Something like policykit or similar. Is it possible to do in 11.04 ? Thanks edit: if someone needs ( for own risk ), little change in /usr/lib/pm-utils/bin/pm-action will allow user to suspend machine if he is only user logged in or when user will run sudo pm-suspend. Probably not best piece of code, but for now works. diff -r 805887c5c0f6 pm-action --- a/pm-action Wed Jun 29 23:32:01 2011 +0200 +++ b/pm-action Wed Jun 29 23:37:23 2011 +0200 @@ -47,6 +47,14 @@ exit 1 fi +if [ "$(id -u )" == 0 -o `w -h | cut -f 1 -d " " | sort | uniq | wc -l` -eq 1 ]; then + echo "either youre root or root isnt here and youre only user, continuing" 1&2 + else + echo "Not suspending, root is here or there is more users" 1&2 + exit 2 + fi + + remove_suspend_lock() { release_lock "${STASHNAME}.lock" Question still stands, is it possible to forbid shutdown or suspend when there is more than one user logged in ( without rewriting system file )?

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  • How to select all options from a drop list in php / mysql

    - by Mirage81
    Thanks to stackoverflow.com's frienly experts I've managed to create my first php + mysql application. The code searches a mysql database for last names and cities. The choices are made through two drop lists like these: Choose city: All cities Liverpool Manchester Choose last name: All last names Lennon Gallagher The code would return eg. all the Lennons living in Liverpool. However, I haven't been able to make the options "All cities" and "All last names" to work so that the code would return eg. all the Lennons living in any city or all the people living in Liverpool. So, how can that be done? The code so far: index.php <?php $conn = mysql_connect('localhost', 'user', 'password') or die("Connection failed"); mysql_select_db("database", $conn) or die("Switch database failed"); //this gets the cities from the database to the drop list $query = "SELECT DISTINCT city FROM user".mysql_real_escape_string($city); $result = mysql_query($query, $conn); $options=""; while ($row=mysql_fetch_array($result)) { $city=$row["city"]; $options.="<OPTION VALUE=\"$city\">".$city; } //this gets the last names from the database to the drop list $query2 = "SELECT DISTINCT lastname FROM user".mysql_real_escape_string($lastname); $result2 = mysql_query($query2, $conn); $options2=""; while ($row2=mysql_fetch_array($result2)) { $lastname=$row2["lastname"]; $options2.="<OPTION VALUE=\"$lastname\">".$lastname; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta content="text/html; charset=ISO-8859-1" http-equiv="content-type"> <title>test</title> </head> <body> <form action="get.php" method="post"> <p> <select name="city"> <option value=0>Choose <option value=1>All cities <?=$options?> </select> </p> <p> <select name="lastname"> <option value=0>Choose <option value=1>All last names <?=$options2?> </select> </p> <p> <input value="Search" type="submit"> </p> </form> <br> </body> </html> get.php <?php $conn = mysql_connect('localhost', 'user', 'password') or die("Connection failed"); mysql_select_db("database", $conn) or die("Switch database failed"); $query = "SELECT * FROM user WHERE city = '".mysql_real_escape_string($_POST['city'])."' AND lastname = '".mysql_real_escape_string($_POST['lastname'])."'"; $result = mysql_query($query, $conn); echo $rowcount; $zerorows=true; while ($row = mysql_fetch_assoc($result)) { $zerorows=false; echo '<b>City: </b>'.htmlspecialchars($row[city]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[lastname]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[information]).'<br />'.'<br />'; } if($zerorows) echo "No results"; mysql_close($conn); ?>

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  • What's the equivalent name of "procedure" in OOP?

    - by AeroCross
    In several of my programming courses in the University, my teachers always told me the following: A function and a procedure are basically the same thing: the only difference is that a function returns a value, and the procedure doesn't. That means that this: function sum($a, $b) { return $a + $b; } ... is a function, and this: function sum($a, $b) { echo $a + $b; } ... is a procedure. In the same train of thought, I've seen that a method is the equivalent of a function in the OOP world. That means that this: class Example { function sum($a, $b) { return $a + $b; } } Is a method — but how do you call this? class Example { function sum($a, $b) { echo $a + $b; } } What's the equivalent name, or how do you call a method that doesn't returns anything?

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  • Internet Connectivity Indicicator on Unity

    - by Sathish
    How can I check whether my internet connection is active on Ubuntu. If I am connected to a wired or wi-fi network, the indicator applet shows that I'm connected. But there is now way to find out the internet is working or not. I have some problem in my internet connectivity and I frequently lose my connection. I found this link is useful Internet connectivity indicator applet But I don't know that where should I use this code! #!/bin/bash if ping -c 1 -W 2 google.com > /dev/null; then echo "Up" else echo "Down" fi

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  • Form Not Submitting

    - by John
    Hello, When I try to click on the "submit" button for the form below, nothing happens. Any ideas why not? Thanks in advance, John submit.php: <?php require_once "header.php"; $u = $_SESSION['username']; if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox2(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { . show_userbox2(); } echo '<div class="submittitle">Submit an item.</div>'; echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; ?> submit2.php: <?php //if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../submit2.php');} require_once "header.php"; if (isLoggedIn() == true) { $remove_array = array('http://www.', 'http://', 'https://', 'https://www.', 'www.'); $cleanurl = str_replace($remove_array, "", $_POST['url']); $cleanurl = strtolower($cleanurl); $cleanurl = preg_replace('/\/$/','',$cleanurl); $title = $_POST['title']; //$url = $_POST['url']; $uid = $_POST['uid']; $title = mysql_real_escape_string($title); $cleanurl = mysql_real_escape_string($cleanurl); $site1 = 'http://' . $cleanurl; $displayurl = parse_url($site1, PHP_URL_HOST); function isURL($url1 = NULL) { if($url1==NULL) return false; $protocol = '(http://|https://)'; $allowed = '[-a-z0-9]{1,63}'; $regex = "^". $protocol . // must include the protocol '(' . $allowed . '\.)'. // 1 or several sub domains with a max of 63 chars '[a-z]' . '{2,6}'; // followed by a TLD if(eregi($regex, $url1)==true) return true; else return false; } if(isURL($site1)==true) mysql_query("INSERT INTO submission VALUES (NULL, '$uid', '$title', '$cleanurl', '$displayurl', NULL)"); else echo "<p class=\"topicu\">Not a valid URL.</p>\n"; } else { // user is not loggedin show_loginform(); } if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { // User is not logged in and has not pressed the login button // so we show him the loginform show_loginform(); } } else { // The user is already loggedin, so we show the userbox. show_userbox(); } require_once "footer.php"; ?>

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  • How to pass results of bc to a variable

    - by shaolin
    I'm writing a script and I would like to pass the results from bc into a variable. I've declared 2 variables (var1 and var2) and have given them values. In my script I want to pass the results from bc into another variable say var3 so that I can work with var3 for other calculations. So far I have been able write the result to a file which is not what I'm looking for and also I've been able to echo the result in the terminal but I just want to pass the result to a variable at moment so that I can work with that variable. echo "scale=2;$var1/var2" | bc

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  • Joomla 2.5 -- Adding a custom field to menu-item-edit-form

    - by philipp
    I would like to add a new Field (Select list of all menu-items) to the menu item-edit form. To do so I was setting up an system plugin with the following directory structure: languageroot/languageroot.php languageroot/form/form.xml As you can see in the posted code, that is all very basic to try out. Only after adding the following lines: <li <?php echo $this-form-getLabel( 'langroot-text', 'main' )? <?php echo $this-form-getInput('langroot-text', 'main' ); ? </li to: /admininstrator/components/com_menus/views/item/tmpl/edit.php a textfield shows up. Is it possible to inject the field without touching the edit.php? Is there anywhere a good tutorial about the JForm api? Is a system-plugin the right kind, or could it be a content plugin, or should it even be a component?

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  • Sudo Non-Password access to /sys/power/state

    - by John
    On my computer, pm-hibernate appears to be broken, however using the command echo disk > /sys/power/state appears to work perfectly. Now I just need regular user access to it, using sudo. How do I do this? The command sudo echo disk > /sys/power/state simply returns bash: /sys/power/state: Permission denied. Also, I need this in a regularly used script, how can I make it so that I don't have to type in my password for it to work???

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  • XMLHttpRequest not working, trying to test database connection [closed]

    - by Frederick Marcoux
    I'm currently creating my own CMS for personnal use but I'm blocked at a code. I'm trying to make a installation script but the AJAX request to test if database works, doesn't work... There's my JS code: function testDB() { "use strict"; var host = document.getElementById('host').value; var username = document.getElementById('username').value; var password = document.getElementById('password').value; var db = document.getElementById('db_name').value; var xmlhttp = new XMLHttpRequest(); var url = "test_db.php"; var params = "host="+host+"&username="+username+"&password="+password+"&db="+db; xmlhttp.open("POST", url, true); xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xmlhttp.setRequestHeader("Content-length", params.length); xmlhttp.setRequestHeader("Connection", "close"); xmlhttp.send(params); $('#loader').removeAttr('style'); if (xmlhttp.responseText !== '') { if (xmlhttp.readyState===4 && xmlhttp.status===200) { $('#next').removeAttr('disabled'); $('#test').attr('disabled', 'disabled'); $('#test').text('Connection Successful!'); $('#test').addClass('btn-success'); $('#login').addClass('success'); $('#login1').addClass('success'); $('#db').addClass('success'); $('#loader').attr('style', 'display: none;'); } else { $('#next').attr('disabled', 'disabled'); $('#test').removeClass('btn-success'); $('#test').removeAttr('disabled'); $('#test').text('Test Connection'); $('#login').removeClass('success'); $('#login1').removeClass('success'); $('#db').removeClass('success'); $('#loader').attr('style', 'display: none;'); } } else { $('#next').attr('disabled', 'disabled'); $('#next').attr('disabled', 'disabled'); $('#test').removeClass('btn-success'); $('#test').removeAttr('disabled'); $('#test').text('Test Connection'); $('#login').removeClass('success'); $('#login1').removeClass('success'); $('#db').removeClass('success'); $('#loader').attr('style', 'display: none;'); } } And there's my PHP code: <?php $link = mysql_connect($_POST['host'], $_POST['username'], $_POST['password']); if (!$link) { echo ''; } else { if (mysql_select_db($_POST['db'])) { echo 'Connection Successful!'; } else { echo ''; } } mysql_close($link); ?> I don't know why it doesn't work but I tried with JQuery $.ajax, $.get, $.post but nothing work...

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  • Macbook Pro late 2011 screen brightness issue

    - by buchzumlesen
    The keys to set the screen brightness work properly but everytime I reboot, the screen brightness is reverted to 100%, which is very annoying. I've already tried to add the following lines to /etc/rc.local but with no success (only the keyboard backlight stays off): #!/bin/sh -e # # rc.local # # This script is executed at the end of each multiuser runlevel. # Make sure that the script will "exit 0" on success or any other # value on error. # # In order to enable or disable this script just change the execution # bits. # # By default this script does nothing. echo '1' > /sys/devices/platform/applesmc.768/leds/smc::kbd_backlight/brightness echo '6' > /sys/class/backlight/acpi_video0/brightness rfkill block bluetooth exit 0` This worked for me when I was using Ubuntu 12.04 and also did after the upgrade to 12.10 but then after rebooting the screen brightness always reverted to 100%. Would be nice if anyone knows how to fix this. My device: Macbook Pro 13" Late 2011 Thanks in advance!

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