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• Sendmail - preventing aliased users from receiving multiple copies of the same email

  - by MikeQ

  Is there any way to prevent a user from receiving multiple copies of the same email if an email is sent to both an alias for the user as well as the user themselves? For example, suppose bob.smith is a included in the alias list for developers (@company.com) If I send the email to both the user and an alias for the user: To: [email protected], [email protected] ... is there any way to prevent user Bob from receiving the same email two times? EDIT: I've observed that if Bob is a member of two different alias groups, and I send an email just to those two groups (not the user directly), sendmail correctly expands the groups and removes the duplicate. The behavior I want to fix occurs when you send directly to the user AND a group they belong to.

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• SQL 2000 and group names

  - by Nasa

  I have a SQL 2000 server which has databases, under user section of the database object, I have some NT 4.0 groups. These groups were migrated over to Active Directory some time ago using ADMT with SID history. The original source domain groups have since been deleted. The access shown is olddomain\groupname. I don't know why, if they were ntfs permissions they would update automatically to target\groupname. The users in the AD domain still have access to the database as they are a member of the migrated group (Target\groupname). I was wondering 1) Why does the old group (source\groupname) show up as it doesn't exist anymore. But access is still granted to the target group? 2) Is there any easy way to update the group name from source\groupname to target\groupname? Thanks for any help.

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• NTFS Permission Structure to allow Traversal but no Modification except in Leaf Nodes?

  - by pepoluan

  Assume there's this folder structure: D:\ --+-- Acctg --+-- Payable | +-- Receivable | +-- Fin --+-- Inv | +-- Tax | +-- Treas | +-- Mrktg --+-- Ads +-- Promo Users are not allowed to change the structure, but they are free to create & delete files & folders in the leaf nodes (i.e., the rightmost folders). AGDLP principle said that I should assign permissions on the above folders to DL-Groups. Let's say I have a G-Group of users, G-Accounting-Payable, containing users that have access to the D:\Acctg\Payable folder. The way I see it, I have two strategies: - Strategy 1 Create three DL-Groups and assign them permissions: DL-D-Acctg_T -- allowed traversal of D:\Acctg folder DL-D-Acctg-Pay_LF -- allowed listing of D:\Acctg\Payable folder contents DL-D-Acctg-Pay__RW -- allowed full permissions to the contents of D:\Acctg\Payable folder Add G-Accounting-Payable as member to all the above DL-Groups - Strategy 2 Create just one DL-Group DL-D-Acctg-Pay__RW, and assign it the proper permissions for each level of the folder. Then, add G-Accounting-Payable as member to that DL-Group. - Which strategy is the Recommended Best Practice, and why?

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• Windows Server 2008: How to tell if a user is a 'local' use or a 'domain' user

  - by David

  I'm a developer, not a server admin, so please bear with me! I've been tasked with checking the installation of some software on a Windows Server 2008 R2 machine in the cloud, within two scenarios: There is no domain, the software will use local users and groups for authentication There is a domain, the software will use domain users and groups for authentication I've done part 1, but I'm puzzled about part 2. I've just installed the Active Directory Domain Services role on the server, so now I have a domain of one computer. When I look in Active Directory Users and Computers, I see all my original local users and groups. Have they now been 'promoted' to domain users? Or do I not have any domain users yet? Is there a way I can tell the difference between domain users and local users now? Thanks

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• Projections.count() and Projections.countDistinct() both result in the same query

  - by Kim L

  EDIT: I've edited this post completely, so that the new description of my problem includes all the details and not only what I previously considered relevant. Maybe this new description will help to solve the problem I'm facing. I have two entity classes, Customer and CustomerGroup. The relation between customer and customer groups is ManyToMany. The customer groups are annotated in the following way in the Customer class. @Entity public class Customer { ... @ManyToMany(mappedBy = "customers", fetch = FetchType.LAZY) public Set<CustomerGroup> getCustomerGroups() { ... } ... public String getUuid() { return uuid; } ... } The customer reference in the customer groups class is annotated in the following way @Entity public class CustomerGroup { ... @ManyToMany public Set<Customer> getCustomers() { ... } ... public String getUuid() { return uuid; } ... } Note that both the CustomerGroup and Customer classes also have an UUID field. The UUID is a unique string (uniqueness is not forced in the datamodel, as you can see, it is handled as any other normal string). What I'm trying to do, is to fetch all customers which do not belong to any customer group OR the customer group is a "valid group". The validity of a customer group is defined with a list of valid UUIDs. I've created the following criteria query Criteria criteria = getSession().createCriteria(Customer.class); criteria.setProjection(Projections.countDistinct("uuid")); criteria = criteria.createCriteria("customerGroups", "groups", Criteria.LEFT_JOIN); List<String> uuids = getValidUUIDs(); Criterion criterion = Restrictions.isNull("groups.uuid"); if (uuids != null && uuids.size() > 0) { criterion = Restrictions.or(criterion, Restrictions.in( "groups.uuid", uuids)); } criteria.add(criterion); When executing the query, it will result in the following SQL query select count(*) as y0_ from Customer this_ left outer join CustomerGroup_Customer customergr3_ on this_.id=customergr3_.customers_id left outer join CustomerGroup groups1_ on customergr3_.customerGroups_id=groups1_.id where groups1_.uuid is null or groups1_.uuid in ( ?, ? ) The query is exactly what I wanted, but with one exception. Since a Customer can belong to multiple CustomerGroups, left joining the CustomerGroup will result in duplicated Customer objects. Hence the count(*) will give a false value, as it only counts how many results there are. I need to get the amount of unique customers and this I expected to achieve by using the Projections.countDistinct("uuid"); -projection. For some reason, as you can see, the projection will still result in a count(*) query instead of the expected count(distinct uuid). Replacing the projection countDistinct with just count("uuid") will result in the exactly same query. Am I doing something wrong or is this a bug? === "Problem" solved. Reason: PEBKAC (Problem Exists Between Keyboard And Chair). I had a branch in my code and didn't realize that the branch was executed. That branch used rowCount() instead of countDistinct().

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• "ldap_add: Naming violation (64)" error when configuring OpenLDAP

  - by user3215

  I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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• How to Configure OpenLDAP on Ubuntu 10.04 Server

  - by user3215

  I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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• How to configure ldap on ubuntu 10.04 server

  - by user3215

  I am following the link to configure ldap on ubuntu 10.04 server but could not. when I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Anybody could help me?

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• Examples of permission-based authorization systems in .Net?

  - by Rachel

  I'm trying to figure out how to do roles/permissions in our application, and I am wondering if anyone knows of a good place to get a list of different permission-based authorization systems (preferably with code samples) and perhaps a list of pros/cons for each method. I've seen examples using simple dictionaries, custom attributes, claims-based authorization, and custom frameworks, but I can't find a simple explanation of when to use one over another and what the pros/cons are to using each method. (I'm sure there's other ways than the ones I've listed....) I have never done anything complex with permissions/authorization before, so all of this seems a little overwhelming to me and I'm having trouble figuring out what what is useful information that I can use and what isn't. What I DO know is that this is for a Windows environment using C#/WPF and WCF services. Some permission checks are done on the WCF service and some on the client. Some are business rules, some are authorization checks, and others are UI-related (such as what forms a user can see). They can be very generic like boolean or numeric values, or they can be more complex such as a range of values or a list of database items to be checked/unchecked. Permissions can be set on the group-level, user-level, branch-level, or a custom level, so I do not want to use role-based authorization. Users can be in multiple groups, and users with the appropriate authorization are in charge of creating/maintaining these groups. It is not uncommon for new groups to be created, so they can't be hard-coded.

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• How Service Component Architecture (SCA) Can Be Incorporated Into Existing Enterprise Systems

  After viewing Rob High’s presentation “The SOA Component Model” hosted on InfoQ.com, I can foresee how Service Component Architecture (SCA) can be incorporated in to an existing enterprise. According to IBM’s DeveloperWorks website, SCA is a set of conditions which outline a model for constructing applications/systems using a Service-Oriented Architecture (SOA). In addition, SCA builds on open standards such as Web services. In the future, I can easily see how some large IT shops could potently divide development teams or work groups up into Component/Data Object Groups, and Standard Development Groups. The Component/Data Object Group would only work on creating and maintaining components that are reused throughout the entire enterprise. The Standard Development Group would work on new and existing projects that incorporate the use of various components to accomplish various business tasks. In my opinion the incorporation of SCA in to any IT department will initially slow down the number of new features developed due to the time needed to create the new and loosely-coupled components. However once a company becomes more mature in its SCA process then the number of program features developed will greatly increase. I feel this is due to the fact that the loosely-coupled components needed in order to add the new features will already be built and ready to incorporate into any new development feature request. References: BEA Systems, Cape Clear Software, IBM, Interface21, IONA Technologies PLC, Oracle, Primeton Technologies Ltd, Progress Software, Red Hat Inc., Rogue Wave Software, SAP AG, Siebel Systems, Software AG, Sun Microsystems, Sybase, TIBCO Software Inc. (2006). Service Component Architecture. Retrieved 11 27, 2011, from DeveloperWorks: http://www.ibm.com/developerworks/library/specification/ws-sca/ High, R. (2007). The SOA Component Model. Retrieved 11 26, 2011, from InfoQ: http://www.infoq.com/presentations/rob-high-sca-sdo-soa-programming-model

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• South Florida Stony Brook Alumni &amp; Friends Reception 2011

  - by Sam Abraham

  It’s official, we are kicking off a local South Florida Chapter for Stony Brook alumni and friends in the area to keep in touch.  Our first networking event will be taking place at Champps, Ft Lauderdale on November 17th, 6:00-8:00 PM. Admission is free and open for everyone, whether or not they are Stony Brook Alums. The team at Champps is offering us great specials (Happy hour deals, half-price appetizers,etc.) that we can choose to enjoy while we network and catch up. (Event Announcement: http://alumniandfriends.stonybrook.edu/page.aspx?pid=299&cid=1&ceid=171&cerid=0&cdt=11%2f17%2f2011) I look forward to share and revive my college experience which I believe was the starting line of my ongoing life journey. It would be also great to hear others’ take as they reflect on their experiences throughout their college years. I invite anyone interested in keeping in touch with friends and alums of Stony Brook to join our LinkedIn or Facebook groups.   The Stony Brook Alumni Association – South Florida Chapter LinkedIn Group: http://www.linkedin.com/groups?gid=3665306&trk=myg_ugrp_ovr The Stony Brook Alumni Association – South Florida Chapter Facebook Group: http://www.facebook.com/#!/groups/114760941910314/

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• Tracking feature requests for small-scale components

  - by DXM

  I'm curious how other development teams (especially those that work in moderate to large development groups) track "future" features/wishlists for functionality for internally developed frameworks or components. I know the standard advice is that a development team should find one good tool for tracking bugs/features and use that for everything and I agree with that if the future requests are for the product itself. In my company we have an engineering department, which is broken up into multiple groups and within each there can be one to several agile teams. The bug tracking product we use has been "a leader since 1997" (their UI/usability seems to also be evaluated against that year even today) but my agile team or even group doesn't really control what is being used by the whole department. What we are looking to track is not necessarily product features but expansion/nice to have functionality for internal components that go into our product. So to name a few for example... framework/utility library on top of CppUnit which our developers share low-level IPC communications framework Common development SDK that myself and several other team leads started to help share some common code/tools at the department-wide level (this SDK is released as internal "product" to each of the groups). Is the standard practice to use the one bug tracking tool? Or would it make more sense to setup something more localized specifically for our needs and maintain it ourselves? It's also unclear how management will feel if developers start performing "IT" roles of maintaining software and servers. At the same time, right now, we use excel files, internal wiki and MS OneNote for this kind of stuff and that just doesn't feel right. (I'm afraid to ask for actual software recommendations, since that might make this question more localized or something. Also developers needs this way more than management, so it would be nice to find something either free or no more than the cost of a happy hour).

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• Using Computer Management (MMC) with the Solaris CIFS Service (August 25, 2009)

  - by user12612012

  One of our goals for the Solaris CIFS Service is to provide seamless Windows interoperability: not just to deliver ubiquitous, multi-protocol file sharing, which is obviously a major part of this project, but to support Windows services at a fundamental level.  It's an ongoing mission and our latest update includes support for Windows remote management. Remote management is extremely important to Windows administrators and one of the mainstay tools is Computer Management. Computer Management is a Windows administration application, actually a collection of Microsoft Management Console (MMC) tools, that can be used to configure, monitor and manage local and remote services and resources.  The MMC is an extensible framework of registered components, known as snap-ins, which allows Computer Management to provide comprehensive management features for both the local system and remote systems on the network. Supported Computer Management features include: Share ManagementSupport for share management is relatively complete.  You can create, delete, list and configure shares.  It's not yet possible to change the maximum allowed or number of users properties but other properties, including the Share Permissions, can be managed via the MMC. Users, Groups and ConnectionsYou can view local SMB users and groups, monitor user connections and see the list of open files. If necessary, you can also disconnect users and/or close files. ServicesYou can view the SMF services running on an OpenSolaris system.  This is a read-only view - we don't support service management (the ability to start or stop) SMF services from Computer Management (yet). To ensure that only the appropriate users have access to administrative operations there are some access restrictions on these remote management features. Regular users can: List shares Only members of the Administrators or Power Users groups can: Manage shares List connections Only members of the Administrators group can: List open files and close files Disconnect users View SMF services View the EventLog Here's a screenshot when I was using Computer Management and Server Manager (another Windows remote management application) on Windows XP to view some open files on an OpenSolaris system to prepare a slide presentation on MMC support.

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• Oracle India Provides Choices For Students

  - by user769227

  For next year's graduating class of computer science and engineering students, the world is their oyster. I believe that in today's day and age the opportunities for graduates are truly endless. Many students have a misconception that Oracle is mainly a Database Company. While we certainly are leaders in the database space, there is so much more that we do. If you look a little bit deeper you will find we have business groups within Oracle creating technical solutions across all areas of the business world. I think that the opportunities available at Oracle can be those 'life changing' roles that students are looking for where they will learn, develop, be challenged and still have the opportunity to be themselves. What other company provides as many choices for students as Oracle. The range of business and technical solutions we provide is enormous. At Oracle India we hire students across a range of different business groups. Below is a presentation showing you just some of the different business groups that hire graduates in Oracle India. The theme is 'choices' because we believe with the variety of work we do we provide the choice to allow you to be you. .prezi-player { width: 550px; } .prezi-player-links { text-align: center; } Oracle Campus Recruitment India: Choices on Prezi As you can see, here at Oracle you get the chance to allow 'You to be You'. If Cloud Computing is what you are interested in, great explore opportunities in our Cloud Services Team. Have you always wanted to work as a Systems Engineer, maybe a role in our Systems/Hardware Business is right for you. With Oracle you have the choice to carve out your career in the path you want it to take. Do you want to find our more, send us your details at [email protected] 

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• Frustrated with MythTV 0.26

  - by Mike

  I've been using MythTV for a while now. Until a hardware crash I had a 0.25 box running without problems. Had to get new hardware and am now in the process of setting up 0.26. Every time I pick a menu option, it hangs for 1 minute. Every time I try to start the backend, same thing. I pick a new theme in the frontend, but it never gets used. I try to test audio, but all I get is static (from the proper channels though). I've setup the storage groups in the backend and put a video in /storage/videos but the front end won't see it when I scan for changes. I make changes in the front end configuration and they don't get saved (or get lost randomly 2-3 reloads later). Obviously there is something I am doing catastrophically wrong, but I have no idea what. Are the storage groups not working yet? Maybe I need to delete all the storage group entries and just use the front end override to set the path? I'm currently using lvm across 3 hard disks, and this has worked well for me in the past. I'd like to use storage groups, but frankly I don't see them working yet at all - especially not for videos (which is what we watch 99% of the time). Anyone have any suggestions for me to try before I just call 0.26 bad names and wipe the system?

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• Algorithm for grouping friends at the cinema [closed]

  - by Tim Skauge

  I got a brain teaser for you - it's not as simple as it sounds so please read and try to solve the issue. Before you ask if it's homework - it's not! I just wish to see if there's an elegant way of solving this. Here's the issue: X-number of friends want's to go to the cinema and wish to be seated in the best available groups. Best case is that everyone sits together and worst case is that everyone sits alone. Fewer groups are preferred over more groups. Sitting alone is least preferred. Input is the number of people going to the cinema and output should be an array of integer arrays that contains: Ordered combinations (most preferred are first) Number of people in each group Below are some examples of number of people going to the cinema and a list of preferred combinations these people can be seated: 1 person: 1 2 persons: 2, 1+1 3 persons: 3, 2+1, 1+1+1 4 persons: 4, 2+2, 3+1, 2+1+1, 1+1+1+1 5 persons: 5, 3+2, 4+1, 2+2+1, 3+1+1, 2+1+1+1, 1+1+1+1+1 6 persons: 6, 3+3, 4+2, 2+2+2, 5+1, 3+2+1, 2+2+1+1, 2+1+1+1+1, 1+1+1+1+1+1 Example with more than 7 persons explodes in combinations but I think you get the point by now. Question is: What does an algorithm look like that solves this problem? My language by choice is C# so if you could give an answer in C# it would be fantastic!

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• Mahout - Clustering - "naming" the cluster elements

  - by Mark Bramnik

  I'm doing some research and I'm playing with Apache Mahout 0.6 My purpose is to build a system which will name different categories of documents based on user input. The documents are not known in advance and I don't know also which categories do I have while collecting these documents. But I do know, that all the documents in the model should belong to one of the predefined categories. For example: Lets say I've collected a N documents, that belong to 3 different groups : Politics Madonna (pop-star) Science fiction I don't know what document belongs to what category, but I know that each one of my N documents belongs to one of those categories (e.g. there are no documents about, say basketball among these N docs) So, I came up with the following idea: Apply mahout clustering (for example k-mean with k=3 on these documents) This should divide the N documents to 3 groups. This should be kind of my model to learn with. I still don't know which document really belongs to which group, but at least the documents are clustered now by group Ask the user to find any document in the web that should be about 'Madonna' (I can't show to the user none of my N documents, its a restriction). Then I want to measure 'similarity' of this document and each one of 3 groups. I expect to see that the measurement for similarity between user_doc and documents in Madonna group in the model will be higher than the similarity between the user_doc and documents about politics. I've managed to produce the cluster of documents using 'Mahout in Action' book. But I don't understand how should I use Mahout to measure similarity between the 'ready' cluster group of document and one given document. I thought about rerunning the cluster with k=3 for N+1 documents with the same centroids (in terms of k-mean clustering) and see whether where the new document falls, but maybe there is any other way to do that? Is it possible to do with Mahout or my idea is conceptually wrong? (example in terms of Mahout API would be really good) Thanks a lot and sorry for a long question (couldn't describe it better) Any help is highly appreciated P.S. This is not a home-work project :)

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• Zend_Form MultiCheckbox not checking boxes

  - by azz0r

  $groups = Model_UserGroup::load_links($object->id); foreach ($groups as $item) { $object->group[$item->group_id] = $item->enabled; } $array_object = (array) $object;//turn the object to an array so zend_form can use it $form->populate($array_object); enabled = 1 or 0 In the form class: $group = new Zend_Form_Element_MultiCheckbox('group'); $groups = Model_Group::load_all(); $new_item = array(); foreach ($groups as $item) { $group->addMultiOption($item->id, $item->name); } However the top group is the only one ever checked. Anyone spot anything glaringly wrong? I know its difficult to get a grasp of my layout/setup for this. Here is the array_object: Array ( [table_name] => User [id] => 112 [updated] => 1269428783 [created] => 1153237813 [group] => Array ( [1] => 1 [3] => 1 ) ) Here is the html zend_form is creating: <dd id="group-element"> <label for="group-1"><input name="group[]" id="group-1" value="1" checked="checked" type="checkbox">Administrator Access</label><br> <label for="group-2"><input name="group[]" id="group-2" value="2" type="checkbox">Content Admin</label><br> <label for="group-3"><input name="group[]" id="group-3" value="3" type="checkbox">Administrator</label><br> <label for="group-4"><input name="group[]" id="group-4" value="4" type="checkbox">Studio</label> </dd> edit: just done a small test and made the $groups (in the first set of code tags) empty and it still ticks the first box. hm Fixed this by doing: // $selected_groups = Model_UserGroup::load_links($object->id); $group_ticks = array(); foreach ($selected_groups as $item) { if ($item->enabled == 1) { $group_ticks[] = $item->group_id;//$form->group->setValue($item->group_id); } } $form->group->setValue($group_ticks); //

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• how to pass data when using MenuItem.ItemContainerStyle

  - by black sensei

  Hello Experts! i've been trying to have a dynamic ContextMenu to show the name property of each of the object in its collection of objects. here is concrete example ,i'm connecting to a webservice to pull contacts and groups of a particular account.so i have those as global variables.i display the contacts in a listbox and i want to show on right click of a contact in the listbox the list of groups that it can be added to. to be able to add a contact to a group i need the id of the contact(which i have) and the id of the group which i'm looking for here is my code. xmlns:serviceAdmin="clr-namespace:MyWpfApp.serviceAdmin" ...... <ListBox.ContextMenu> <ContextMenu> <MenuItem Header="Refresh" Click="RefreshContact_Click"></MenuItem> <MenuItem Header="Add New Contact" Click="ContactNew_Click"></MenuItem> <MenuItem Header="Add to Group" Name="groupMenus"> //<!--<MenuItem.Resources> // <DataTemplate DataType="{x:Type serviceAdmin:groupInfo}" x:Key="groupMenuKey" > // <MenuItem> // <TextBlock Text="{Binding name}" /> // </MenuItem> // </DataTemplate> // </MenuItem.Resources>--> <MenuItem.ItemContainerStyle> <Style> <Setter Property="MenuItem.Header" Value="{Binding name}"/> <Setter Property="MenuItem.Tag" Value="{Binding id}" /> </Style> </MenuItem.ItemContainerStyle> </MenuItem> <MenuItem Header="Delete Selected" Click="ContactDelete_Click"></MenuItem> </ContextMenu> </ListBox.ContextMenu> ...... and on xaml.cs //this code is in the method that loads the groups loadedgroup = service.getGroups(session.key, null); groupListBox.ItemsSource = loadedgroup; groupMenus.ItemsSource = loadedgroup.ToList(); this code is showing the name of the groups alright but i need the id of the group clicked on. If you've noticed i commented a portion of the xaml code. with that i could bind(with ease) the id to the tag.But it won't work and the MenuItem.ItemContainerStyle is the one working but then i'm lost: Question 1 : how do i create a handler method for a click event of a submenu that has the names of the groups? Question 2 : how do i get the clicked group id to work with? thanks for reading and kindly help me in this

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• LINQ to SQL and missing Many to Many EntityRefs

  - by Rick Strahl

  Ran into an odd behavior today with a many to many mapping of one of my tables in LINQ to SQL. Many to many mappings aren’t transparent in LINQ to SQL and it maps the link table the same way the SQL schema has it when creating one. In other words LINQ to SQL isn’t smart about many to many mappings and just treats it like the 3 underlying tables that make up the many to many relationship. Iain Galloway has a nice blog entry about Many to Many relationships in LINQ to SQL. I can live with that – it’s not really difficult to deal with this arrangement once mapped, especially when reading data back. Writing is a little more difficult as you do have to insert into two entities for new records, but nothing that can’t be handled in a small business object method with a few lines of code. When I created a database I’ve been using to experiment around with various different OR/Ms recently I found that for some reason LINQ to SQL was completely failing to map even to the linking table. As it turns out there’s a good reason why it fails, can you spot it below? (read on :-}) Here is the original database layout: There’s an items table, a category table and a link table that holds only the foreign keys to the Items and Category tables for a typical M->M relationship. When these three tables are imported into the model the *look* correct – I do get the relationships added (after modifying the entity names to strip the prefix): The relationship looks perfectly fine, both in the designer as well as in the XML document: <Table Name="dbo.wws_Item_Categories" Member="ItemCategories"> <Type Name="ItemCategory"> <Column Name="ItemId" Type="System.Guid" DbType="uniqueidentifier NOT NULL" CanBeNull="false" /> <Column Name="CategoryId" Type="System.Guid" DbType="uniqueidentifier NOT NULL" CanBeNull="false" /> <Association Name="ItemCategory_Category" Member="Categories" ThisKey="CategoryId" OtherKey="Id" Type="Category" /> <Association Name="Item_ItemCategory" Member="Item" ThisKey="ItemId" OtherKey="Id" Type="Item" IsForeignKey="true" /> </Type> </Table> <Table Name="dbo.wws_Categories" Member="Categories"> <Type Name="Category"> <Column Name="Id" Type="System.Guid" DbType="UniqueIdentifier NOT NULL" IsPrimaryKey="true" IsDbGenerated="true" CanBeNull="false" /> <Column Name="ParentId" Type="System.Guid" DbType="UniqueIdentifier" CanBeNull="true" /> <Column Name="CategoryName" Type="System.String" DbType="NVarChar(150)" CanBeNull="true" /> <Column Name="CategoryDescription" Type="System.String" DbType="NVarChar(MAX)" CanBeNull="true" /> <Column Name="tstamp" AccessModifier="Internal" Type="System.Data.Linq.Binary" DbType="rowversion" CanBeNull="true" IsVersion="true" /> <Association Name="ItemCategory_Category" Member="ItemCategory" ThisKey="Id" OtherKey="CategoryId" Type="ItemCategory" IsForeignKey="true" /> </Type> </Table> However when looking at the code generated these navigation properties (also on Item) are completely missing: [global::System.Data.Linq.Mapping.TableAttribute(Name="dbo.wws_Item_Categories")] [global::System.Runtime.Serialization.DataContractAttribute()] public partial class ItemCategory : Westwind.BusinessFramework.EntityBase { private System.Guid _ItemId; private System.Guid _CategoryId; public ItemCategory() { } [global::System.Data.Linq.Mapping.ColumnAttribute(Storage="_ItemId", DbType="uniqueidentifier NOT NULL")] [global::System.Runtime.Serialization.DataMemberAttribute(Order=1)] public System.Guid ItemId { get { return this._ItemId; } set { if ((this._ItemId != value)) { this._ItemId = value; } } } [global::System.Data.Linq.Mapping.ColumnAttribute(Storage="_CategoryId", DbType="uniqueidentifier NOT NULL")] [global::System.Runtime.Serialization.DataMemberAttribute(Order=2)] public System.Guid CategoryId { get { return this._CategoryId; } set { if ((this._CategoryId != value)) { this._CategoryId = value; } } } } Notice that the Item and Category association properties which should be EntityRef properties are completely missing. They’re there in the model, but the generated code – not so much. So what’s the problem here? The problem – it appears – is that LINQ to SQL requires primary keys on all entities it tracks. In order to support tracking – even of the link table entity – the link table requires a primary key. Real obvious ain’t it, especially since the designer happily lets you import the table and even shows the relationship and implicitly the related properties. Adding an Id field as a Pk to the database and then importing results in this model layout: which properly generates the Item and Category properties into the link entity. It’s ironic that LINQ to SQL *requires* the PK in the middle – the Entity Framework requires that a link table have *only* the two foreign key fields in a table in order to recognize a many to many relation. EF actually handles the M->M relation directly without the intermediate link entity unlike LINQ to SQL. [updated from comments – 12/24/2009] Another approach is to set up both ItemId and CategoryId in the database which shows up in LINQ to SQL like this: This also work in creating the Category and Item fields in the ItemCategory entity. Ultimately this is probably the best approach as it also guarantees uniqueness of the keys and so helps in database integrity. It took me a while to figure out WTF was going on here – lulled by the designer to think that the properties should be when they were not. It’s actually a well documented feature of L2S that each entity in the model requires a Pk but of course that’s easy to miss when the model viewer shows it to you and even the underlying XML model shows the Associations properly. This is one of the issue with L2S of course – you have to play by its rules and once you hit one of those rules there’s no way around them – you’re stuck with what it requires which in this case meant changing the database.© Rick Strahl, West Wind Technologies, 2005-2010Posted in ADO.NET  LINQ  

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• Incremental Statistics Maintenance – what statistics will be gathered after DML occurs on the table?

  - by Maria Colgan

  Incremental statistics maintenance was introduced in Oracle Database 11g to improve the performance of gathering statistics on large partitioned table. When incremental statistics maintenance is enabled for a partitioned table, oracle accurately generated global level  statistics by aggregating partition level statistics. As more people begin to adopt this functionality we have gotten more questions around how they expected incremental statistics to behave in a given scenario. For example, last week we got a question around what partitions should have statistics gathered on them after DML has occurred on the table? The person who asked the question assumed that statistics would only be gathered on partitions that had stale statistics (10% of the rows in the partition had changed). However, what they actually saw when they did a DBMS_STATS.GATHER_TABLE_STATS was all of the partitions that had been affected by the DML had statistics re-gathered on them. This is the expected behavior, incremental statistics maintenance is suppose to yield the same statistics as gathering table statistics from scratch, just faster. This means incremental statistics maintenance needs to gather statistics on any partition that will change the global or table level statistics. For instance, the min or max value for a column could change after just one row is inserted or updated in the table. It might easier to demonstrate this using an example. Let’s take the ORDERS2 table, which is partitioned by month on order_date.  We will begin by enabling incremental statistics for the table and gathering statistics on the table. After the statistics gather the last_analyzed date for the table and all of the partitions now show 13-Mar-12. And we now have the following column statistics for the ORDERS2 table. We can also confirm that we really did use incremental statistics by querying the dictionary table sys.HIST_HEAD$, which should have an entry for each column in the ORDERS2 table. So, now that we have established a good baseline, let’s move on to the DML. Information is loaded into the latest partition of the ORDERS2 table once a month. Existing orders maybe also be update to reflect changes in their status. Let’s assume the following transactions take place on the ORDERS2 table this month. After these transactions have occurred we need to re-gather statistic since the partition ORDERS_MAR_2012 now has rows in it and the number of distinct values and the maximum value for the STATUS column have also changed. Now if we look at the last_analyzed date for the table and the partitions, we will see that the global statistics and the statistics on the partitions where rows have changed due to the update (ORDERS_FEB_2012) and the data load (ORDERS_MAR_2012) have been updated. The column statistics also reflect the changes with the number of distinct values in the status column increase to reflect the update. So, incremental statistics maintenance will gather statistics on any partition, whose data has changed and that change will impact the global level statistics.

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• MDM 2010 Summit in San Francisco

  - by Tony Ouk

  Since 2006, the MDM Global Summit Series has brought master data expertise to more than 5,000 delegates worldwide. The Series is designed to reinforce the importance of data governance as a key factor to your MDM program's success while providing real-world experience and all-in-one access to solutions providers. Come join us June 2-3, 2010 at the Hyatt Regency in San Francisco.  For more information including registration details, visit the MDM Global Summit Series website.

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• Mozilla Thunderbird

  - by sadik khan

  I am a frequent user of Ubuntu and recently upgraded from Lucid to Ubuntu 11.10. I was not able to properly configure Thunderbird, so I switched to Evolution. First of all what I want is smooth way to configure Thunderbird with all features enabled, like global address list and calendar setting. I also want to know how to remove Thunderbird from global appmenu email icon, and how to insert Evolution email icon in its place. Thanks Sadik khan

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• Why a graduate program in South Africa?

  - by anca.rosu

  South Africa, like many other countries, is desperate for skills. Good, solid, technical skills – together with a get-up-and-go attitude – and the desire to work for a world-class organization that is leading the way! In addition, we have made a commitment in South Africa that we need to transform our organization and develop and empower Black individuals who historically have not had the opportunity to participate in the global economy. It is through this investment in our country's people that we contribute to the development of a nation capable of competing on the global stage. This makes for an exciting recipe! We have: Plenty of young and talented individuals who are eager to get stuck in and learn. Formal, recognized qualifications that form the basis for further development. A huge big global organization – Oracle – that is committed to developing these graduates and giving them an opportunity that is out of this world! Mix the above ‘ingredients’ together Tackle and remove potential “lumps & bumps” along the way as we learn and grow together Nurture and care for each other in a warm but tough environment What have we achieved? In most cases, the outcome is an awesome bunch of new talent that is well equipped to face the IT world. Where we have the opportunity and suitable headcount available to employ these graduates at Oracle we snap them up – alternatively our business partners and customers are always eager to recruit Oracle graduates into their organizations! These individuals go through real-life work place experience whilst at Oracle. In some cases they get to travel internationally. The excitement and buzz gets into their system and their blood becomes truly RED! Oracle RED! This is valuable talent and expertise to have in our eco-system and it’s an exciting program to be a part of not only as a graduate but as an Oracle employee too!   If you have any questions related to this article feel free to contact  [email protected].  You can find our job opportunities via http://campus.oracle.com. Technorati Tags: South Africa,technical skills,graduate program,opportunity,global organization,new talent

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• Giving a Zone "More Power"

  - by Brian Leonard

  In addition to the traditional virtualization benefits that Solaris zones offer, applications running in zones are also running in a more secure environment. One way to quantify this is compare the privileges available to the global zone with those of a local zone. For example, there a 82 distinct privileges available to the global zone: bleonard@solaris:~$ ppriv -l | wc -l 82 You can view the descriptions for each of those privileges as follows: bleonard@solaris:~$ ppriv -lv contract_event Allows a process to request critical events without limitation. Allows a process to request reliable delivery of all events on any event queue. contract_identity Allows a process to set the service FMRI value of a process contract template. ... Or for just one or more privileges: bleonard@solaris:~$ ppriv -lv file_dac_read file_dac_write file_dac_read Allows a process to read a file or directory whose permission bits or ACL do not allow the process read permission. file_dac_write Allows a process to write a file or directory whose permission bits or ACL do not allow the process write permission. In order to write files owned by uid 0 in the absence of an effective uid of 0 ALL privileges are required. However, in a non-global zone, only 43 of the 83 privileges are available by default: root@myzone:~# ppriv -l zone | wc -l 43 The missing privileges are: cpc_cpu dtrace_kernel dtrace_proc dtrace_user file_downgrade_sl file_flag_set file_upgrade_sl graphics_access graphics_map net_mac_implicit proc_clock_highres proc_priocntl proc_zone sys_config sys_devices sys_ipc_config sys_linkdir sys_dl_config sys_net_config sys_res_bind sys_res_config sys_smb sys_suser_compat sys_time sys_trans_label virt_manage win_colormap win_config win_dac_read win_dac_write win_devices win_dga win_downgrade_sl win_fontpath win_mac_read win_mac_write win_selection win_upgrade_sl xvm_control However, just like Tim Taylor, it is possible to give your zones more power. For example, a zone by default doesn't have the privileges to support DTrace: root@myzone:~# dtrace -l ID PROVIDER MODULE FUNCTION NAME The DTrace privileges can be added, however, as follows: bleonard@solaris:~$ sudo zonecfg -z myzone Password: zonecfg:myzone> set limitpriv="default,dtrace_proc,dtrace_user" zonecfg:myzone> verify zonecfg:myzone> exit bleonard@solaris:~$ sudo zoneadm -z myzone reboot Now I can run DTrace from within the zone: root@myzone:~# dtrace -l | more ID PROVIDER MODULE FUNCTION NAME 1 dtrace BEGIN 2 dtrace END 3 dtrace ERROR 7115 syscall nosys entry 7116 syscall nosys return ... Note, certain privileges are never allowed to be assigned to a zone. You'll be notified on boot if you attempt to assign a prohibited privilege to a zone: bleonard@solaris:~$ sudo zoneadm -z myzone reboot privilege "dtrace_kernel" is not permitted within the zone's privilege set zoneadm: zone myzone failed to verify Here's a nice listing of all the privileges and their zone status (default, optional, prohibited): Privileges in a Non-Global Zone.

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