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  • Vaadin table hide columns and container customization

    - by Alex
    Hello I am testing a project, using Vaadin and Hibernate. I am trying to use the HbnContainer class to show data into table. The problem is that I do not want to show all the properties of the two classes in the table. For example: @Entity @Table(name="users") class User { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; private String name; @ManyToOne(cascade=CascadeType.PERSIST) private UserRole role; //getters and setters } and a second class: @Entity @Table(name="user_roles") class UserRole { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; private String name; //getters and setters } Next, I retrieve my data using the HbnContainer, and connect it to the table: HbnContainer container = new HbnContainer(User.class, app); table.setContainerDataSource(container); The Table will only display the columns from User, and for the "role" it will put the role id instead. How can I hide that column, and replace it with the UserRole.name ? I managed to use a ColumnGenerator() to get the string value in the table, for the UserRole - but I couldn't remove the previous column, with the numerical value. What am I missing? Or, what is the best way to "customize" your data, before displaying a table (if i want to show data in a table from more than one object type.. what do I do?) If I can't find a simple solution soon, I think I will just build the tables "by hand".. So, any advice on this matter? Thank you, Alex

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  • NetBeans generates JpaController with errors

    - by Xorty
    Hi, I am using NetBeans 6.8 for building Spring MVC application. Techonologies : Spring MVC 2.5 Derby DB Hibernate for ORM GlassFish v3 server I use New JPA Controller Classes from Entity Classes for adding ORM file. It is supposed to generate class for managing queries with my POJO files. Problem is, that NetBeans generates following code, and won't compile : public int getBrandCount() { EntityManager em = getEntityManager(); try { CriteriaQuery cq = em.getCriteriaBuilder().createQuery(); Root<Brand> rt = cq.from(Brand.class); cq.select(em.getCriteriaBuilder().count(rt)); Query q = em.createQuery(cq); return ((Long) q.getSingleResult()).intValue(); } finally { em.close(); } } At the picture, there is NetBeans error : It looks like method getCriteriaBuilder of Entity Manager Interface is unimplemented. Or some other reason why I can't use it in code. I don't know what other info should I provide, so please ask if anything comes to your mind. Thanks

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  • MySQL Connection Timeout Issue - Grails Application on Tomcat using Hibernate and ORM

    - by gav
    Hi Guys I have a small grails application running on Tomcat in Ubuntu on a VPS. I use MySql as my datastore and everything works fine unless I leave the application for more than half a day (8 hours?). I did some searching and apparently this is the default wait_timeout in mysql.cnf so after 8 hours the connection will die but Tomcat won't know so when the next user tries to view the site they will see the connection failure error. Refreshing the page will fix this but I want to get rid of the error altogether. For my version of MySql (5.0.75) I have only my.cnf and it doesn't contain such a parameter, In any case changing this parameter doesn't solve the problem. This Blog Post seems to be reporting a similar error but I still don't fully understand what I need to configure to get this fixed and also I am hoping that there is a simpler solution than another third party library. The machine I'm running on has 256MB ram and I'm trying to keep the number of programs/services running to a minimum. Is there something I can configure in Grails / Tomcat / MySql to get this to go away? Thanks in advance, Gav From my Catalina.out; 2010-04-29 21:26:25,946 [http-8080-2] ERROR util.JDBCExceptionReporter - The last packet successfully received from the server was 102,906,722 milliseconds$ 2010-04-29 21:26:25,994 [http-8080-2] ERROR errors.GrailsExceptionResolver - Broken pipe java.net.SocketException: Broken pipe at java.net.SocketOutputStream.socketWrite0(Native Method) ... 2010-04-29 21:26:26,016 [http-8080-2] ERROR util.JDBCExceptionReporter - Already closed. 2010-04-29 21:26:26,016 [http-8080-2] ERROR util.JDBCExceptionReporter - Already closed. 2010-04-29 21:26:26,017 [http-8080-2] ERROR servlet.GrailsDispatcherServlet - HandlerInterceptor.afterCompletion threw exception org.hibernate.exception.GenericJDBCException: Cannot release connection at java.lang.Thread.run(Thread.java:619) Caused by: java.sql.SQLException: Already closed. at org.apache.commons.dbcp.PoolableConnection.close(PoolableConnection.java:84) at org.apache.commons.dbcp.PoolingDataSource$PoolGuardConnectionWrapper.close(PoolingDataSource.java:181) ... 1 more

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  • Lazy-loading with Spring HibernateDaoSupport ?

    - by umanga
    Greetings I am developing a non-webapplication using Spring+Hibernate. My question is how the HibernateDaoSupport handles lazy-loading , because after a call do DAO , the Session is closed. Take a look at following psuedo-code: DAO is like: CommonDao extends HibernateDaoSupport{ Family getFamilyById(String id); SubFamily getSubFamily(String familyid,String subfamilyid); } Domain model is like: Family{ private List<SubFamily> subfamiles; public List<SubFamily> getSubFamiles(); } SubFamily{ private Family family; public Family getFamily(); } In the application I get DAO from app-context and want to following operations.Is this possible to do with lazy-loading because AFAIK after every method (getFamilyById() , getSubFamily() ) the session is closed. CommonDAO dao=//get bean from application context; Family famA=dao.getFamilyById(familyid); // //Do some stuff List<SubFamily> childrenA=fam.getSubFamiles(); SubFamily asubfamily=dao.getSubFamily(id,subfamilyid); // //Do some other stuff Family famB=asubfamily.getFamily();

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  • high performance hibernate insert

    - by luke
    I am working on a latency sensitive part of an application, basically i will receive a network event transform the data and then insert all the data into the DB. After profiling i see that basically all my time is spent trying to save the data. here is the code private void insertAllData(Collection<Data> dataItems) { long start_time = System.currentTimeMillis(); long save_time = 0; long commit_time = 0; Transaction tx = null; try { Session s = HibernateSessionFactory.getSession(); s.setCacheMode(CacheMode.IGNORE); s.setFlushMode(FlushMode.NEVER); tx = s.beginTransaction(); for(Data data : dataItems) { s.saveOrUpdate(data); } save_time = System.currentTimeMillis(); tx.commit(); s.flush(); s.clear(); } catch(HibernateException ex) { if(tx != null) tx.rollback(); } commit_time = System.currentTimeMillis(); System.out.println("Save: " + (save_time - start_time)); System.out.println("Commit: " + (commit_time - save_time)); System.out.println(); } The size of the collection is always less than 20. here is the timing data that i see: Save: 27 Commit: 9 Save: 27 Commit: 9 Save: 26 Commit: 9 Save: 36 Commit: 9 Save: 44 Commit: 0 This is confusing to me. I figure that the save should be quick and all the time should be spent on commit. but clearly I'm wrong. I have also tried removing the transaction (its not really necessary) but i saw worse times... I have set hibernate.jdbc.batch_size=20... i need this operation to be as fast as possible, ideally there would only be one roundtrip to the database. How can i do this?

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  • CF9 HQL Statement for many-to-many and Multiple Criteria

    - by Jeremy Battle
    I have the following setup: Listing.cfc component persistent="true" { property name="ListingId" column="ListingId" type="numeric" ormtype="int" fieldtype="id" generator="identity"; ... property name="Features" type="array" hint="Array of features" singularname="Feature" fieldtype="many-to-many" cfc="Feature" linktable="Listing_Feature" FKColumn="ListingId" inversejoincolumn="FeatureId"; } Feature.cfc component persistent="true" table="Feature" schema="dbo" output="false" { property name="FeatureId" column="FeatureId" type="numeric" ormtype="int" fieldtype="id" generator="identity"; property name="FeatureDescription" column="FeatureDescription" type="string" ormtype="string"; ... /*property name="Listings" fieldtype="many-to-many" cfc="Listing" linktable="Listing_Feature" fkcolumn="FeatureId" inversejoincolumn="ListingId" lazy="true" cascade="all" orderby="GroupOrder";*/ } I can select all listings that have a particular feature using: <cfset matchingListings = ormExecuteQuery("from Listing l left join l.Features as feature where feature.FeatureId = :feature",{feature = 110}) /> Which is fine, however, I'd like to be able to select all listings that have multiple features (for example a listing that has both "Dishwasher" AND "Garage") After a couple hours of googling and looking through hibernate documentation haven't been able to find a solution that won't give me an error. My guess is that the solution is pretty simple and I am just over-thinking it...anyone have any suggestions?

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  • ACL architechture for a Software As a service in Spring 3.0

    - by geoaxis
    I am making a software as a service using Spring 3.0 (Spring MVC, Spring Security, Spring Roo, Hibernate) I have to come up with a flexible access control list mechanism.I have three different kinds of users System (who can do any thing to the system, includes admin and internal daemons) Operations (who can add and delete users, organizations, and do maintenance work on behalf of users and organizations) End Users (they belong to one or more organization, for each organization, the user can have one or more roles, like being organization admin, or organization read-only member) (role like orgadmin can also add users for that organization) Now my question is, how should i model the entity of User? If I just take the End User, it can belong to one or more organizations, so each user can contain a set of references to its organizations. But how do we model the users role for each organization, So for example User UX belongs to organizations og1, og2 and og3, and for og1 he is both orgadmin, and org-read-only-user, where as for og2 he is only orgadmin and for og3 he is only org-read-only-user I have the possibility of making each user belong to one organization alone, but that's making the system bounded and I don't like that idea (although i would still satisfy the requirement) If you have a better extensible ACL architecture, please suggest it. Since its a software as a service, one would expect that alot of different organizations would be part if the same system. I had one concern that it is not a good idea to keep og1 and og2 data on the same DB (if og1 decides to spawn a 100 reports on the system, og2 should not suffer) But that is some thing advanced for now and is not directly related to ACL but to the physical distribution of data and setup of services based on those ACLs This is a community Wiki question, please correct any thing which you wish to do so. Thanks

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  • Nhibernate: distinct results in second level Collection

    - by Miguel Marques
    I have an object model like this: class EntityA { ... IList<EntityB> BList; ... } class EntityB { ... IList<EntityC> CList; } I have to fetch all the colelctions (Blist in EntityA and CList in EntityB), because if they all will be needed to make some operations, if i don't eager load them i will have the select n+1 problem. So the query was this: select a from EntityA a left join fetch a.BList b left join fetch b.CList c The fist problem i faced with this query, was the return of duplicates from the DB, i had EntityA duplicates, because of the left join fetch with BList. A quick read through the hibernate documentation and there were some solutions, first i tried the distinct keyword that supposelly wouldn't replicate the SQL distinct keyword except in some cases, maybe this was one of those cases because i had a SQL error saying that i cannot select distict text columns (column [Observations] in EntityA table). So i used one of the other solutions: query.SetResultTransformer(new DistinctRootEntityResultTransformer()); This worked fine. But the result of the operations were still not passing the tests. I checked further and i found out that now there were duplicates of EntityB, because of the left join fetch with CList. The question is, how can i use the distinct in a second level collection? I searched and i only find solutions for the root entity's direct child collection, but never for the second level child collections... Thank you for your time

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  • How to solve with using Flex Builder 3 and BlazeDS?

    - by Teerasej
    Hi, everyone. Thank you for interesting in my question, I think you can help me out from this little problem. I am using Flex builder 3, BlazeDS, and Java with Spring and Hibernate framework. I using the remote object to load a string from spring's configuration files. But in testing, I found this fault event like this: RPC Fault faultString="java.lang.NullPointerException" faultCode="Server.Processing" faultDetail="null" I have check the configuration in remote-config.xml and services-config.xml. But it looks good. There is some people talked about this problem around the internet and I think you can help me and them. I am using these environment: Flex Builder 3 BlazeDS 3.2.0 JBoss server Full stacktrace: [RPC Fault faultString="java.lang.NullPointerException" faultCode="Server.Processing" faultDetail="null"] at mx.rpc::AbstractInvoker/http://www.adobe.com/2006/flex/mx/internal::faultHandler()[C:\autobuild\3.2.0\frameworks\projects\rpc\src\mx\rpc\AbstractInvoker.as:220] at mx.rpc::Responder/fault()[C:\autobuild\3.2.0\frameworks\projects\rpc\src\mx\rpc\Responder.as:53] at mx.rpc::AsyncRequest/fault()[C:\autobuild\3.2.0\frameworks\projects\rpc\src\mx\rpc\AsyncRequest.as:103] at NetConnectionMessageResponder/statusHandler()[C:\autobuild\3.2.0\frameworks\projects\rpc\src\mx\messaging\channels\NetConnectionChannel.as:569] at mx.messaging::MessageResponder/status()[C:\autobuild\3.2.0\frameworks\projects\rpc\src\mx\messaging\MessageResponder.as:222]

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  • em.persist seems doesn't persist data on postgreSQL db

    - by Mario
    I've got a simple java main which must write bean data on a PostgreSQL database. I use Entity manager to persist or update object. I use hibernate and toplink driver connection which are specified in persistence.xml file. When I call em.persist(obj), nothing is saved on database, I don't know why. here is my simple code: private static void importa(FileReader f) throws IOException { EntityManagerFactory emf = Persistence .createEntityManagerFactory("orpt2"); EntityManager em = emf.createEntityManager(); dispositivoMedico = new DispositivoMedico(); dispositivoMedico.setCategoria("prova"); dispositivoMedico.setCodice("323"); em.persist(dispositivoMedico); And here is my persistence.xml http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" it.ariadne.orpt2.entities.AccessoriScheda it.ariadne.orpt2.entities.CampiSchede it.ariadne.orpt2.entities.CampiSchedeSalvati it.ariadne.orpt2.entities.CampoAggiuntivo it.ariadne.orpt2.entities.Categorie it.ariadne.orpt2.entities.CategorieCampi it.ariadne.orpt2.entities.CategorieCampiPK it.ariadne.orpt2.entities.ClasseCivab it.ariadne.orpt2.entities.DecodificaStato it.ariadne.orpt2.entities.DispositivoMedico it.ariadne.orpt2.entities.Ente it.ariadne.orpt2.entities.FormaNegoziazione it.ariadne.orpt2.entities.Fornitore it.ariadne.orpt2.entities.LogSession it.ariadne.orpt2.entities.Modello it.ariadne.orpt2.entities.Periodicita it.ariadne.orpt2.entities.Produttore it.ariadne.orpt2.entities.Ruolo it.ariadne.orpt2.entities.RuoloPK it.ariadne.orpt2.entities.RuoloUtente it.ariadne.orpt2.entities.Scheda it.ariadne.orpt2.entities.SchedaSalvata it.ariadne.orpt2.entities.Tipologia it.ariadne.orpt2.entities.Utente Thank you for your help. Mario

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  • archiving strategies and limitations of data in a table

    - by Samuel
    Environment: Jboss, Mysql, JPA, Hibernate Our web application will be catering to a large amount of users (~ 1,000,000) and there are a lots of child table where user specific data are stored (e.g. personal, health, forum contributions ...). What would be the best practice to archive user & user specific information. [a] Would it be wise to move the archived user & user specific information to their respective tables within the same database (e.g. user_archive, user_forum_comments_archive ...) OR [b] Would you just mark the database entries with a flag in the original table(s) and just query only non archived entries. We have a unique constraint on User.loginid, how do you handle this requirement if the users are archived via 1-[a] (i.e if a user with loginid 'samuel' gets moved into the archive table and if a new user gets added with the same name in the original table, how would you prevent this. What would be the best strategy to address the unique key constraints. We have a requirement to selectively archive records and bring it back if necessary, will you rely on database tools are would you handle this via your persistence APIs exposed by the JPA entity model.

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  • How to make safe frequent DataSource switches for AbstractRoutingDataSource?

    - by serg555
    I implemented Dynamic DataSource Routing for Spring+Hibernate according to this article. I have several databases with same structure and I need to select which db will run each specific query. Everything works fine on localhost, but I am worrying about how this will hold up in real web site environment. They are using some static context holder to determine which datasource to use: public class CustomerContextHolder { private static final ThreadLocal<CustomerType> contextHolder = new ThreadLocal<CustomerType>(); public static void setCustomerType(CustomerType customerType) { Assert.notNull(customerType, "customerType cannot be null"); contextHolder.set(customerType); } public static CustomerType getCustomerType() { return (CustomerType) contextHolder.get(); } public static void clearCustomerType() { contextHolder.remove(); } } It is wrapped inside some ThreadLocal container, but what exactly does that mean? What will happen when two web requests call this piece of code in parallel: CustomerContextHolder.setCustomerType(CustomerType.GOLD); //<another user will switch customer type here to CustomerType.SILVER in another request> List<Item> goldItems = catalog.getItems(); Is every web request wrapped into its own thread in Spring MVC? Will CustomerContextHolder.setCustomerType() changes be visible to other web users? My controllers have synchronizeOnSession=true. How to make sure that nobody else will switch datasource until I run required query for current user? Thanks.

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  • ACL architechture for a Software As a service in Sprgin 3.0

    - by geoaxis
    I am making a software as a service using Spring 3.0 (Spring MVC, Spring Security, Spring Roo, Hibernate) I have to come up with a flexible access control list mechanism.I have three different kinds of users System (who can do any thing to the system, includes admin and internal daemons) Operations (who can add and delete users, organizations, and do maintenance work on behalf of users and organizations) End Users (they belong to one or more organization, for each organization, the user can have one or more roles, like being organization admin, or organization read-only member) (role like orgadmin can also add users for that organization) Now my question is, how should i model the entity of User? If I just take the End User, it can belong to one or more organizations, so each user can contain a set of references to its organizations. But how do we model the users role for each organization, So for example User UX belongs to organizations og1, og2 and og3, and for og1 he is both orgadmin, and org-read-only-user, where as for og2 he is only orgadmin and for og3 he is only org-read-only-user I have the possibility of making each user belong to one organization alone, but that's making the system bounded and I don't like that idea (although i would still satisfy the requirement) If you have a better extensible ACL architecture, please suggest it. Since its a software as a service, one would expect that alot of different organizations would be part if the same system. I had one concern that it is not a good idea to keep og1 and og2 data on the same DB (if og1 decides to spawn a 100 reports on the system, og2 should not suffer) But that is some thing advanced for now and is not directly related to ACL but to the physical distribution of data and setup of services based on those ACLs This is a community Wiki question, please correct any thing which you wish to do so. Thanks

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  • Delete element from Set

    - by Blitzkr1eg
    Hi. I have 2 classes Tema(Homework) and Disciplina (course), where a Course has a Set of homeworks. In Hibernate i have mapped this to a one-to-many associations like this: <class name="model.Disciplina" table="devgar_scoala.discipline" > <id name="id" > <generator class="increment"/> </id> <set name="listaTeme" table="devgar_scoala.teme"> <key column="Discipline_id" not-null="true" ></key> <one-to-many class="model.Tema" ></one-to-many> </set> </class> <class name="model.Tema" table="devgar_scoala.teme" > <id name="id"> <generator class="increment" /> </id> <property name="titlu" type="string" /> <property name="cerinta" type="binary"> <column name="cerinta" sql-type="blob" /> </property> </class> The problem is that it will add (insert rows in the table 'Teme') but it won't delete any rows and i get no exceptions thrown. Im using the merge() method.

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  • Putting BigDecimal data into HSQLDB test database using DbUnit

    - by Denise
    Hi everyone, I'm using Hibernate JPA in my backend. I am writing a unit test using JUnit and DBUnit to insert a set of data into an in-memory HSQL database. My dataset contains: <order_line order_line_id="1" quantity="2" discount_price="0.3"/> Which maps to an OrderLine Java object where the discount_price column is defined as: @Column(name = "discount_price", precision = 12, scale = 2) private BigDecimal discountPrice; However, when I run my test case and assert that the discount price returned equals 0.3, the assertion fails and says that the stored value is 0. If I change the discount_price in the dataset to be 0.9, it rounds up to 1. I've checked to make sure HSQLDB isn't doing the rounding and it definitely isn't because I can insert an order line object using Java code with a value like 5.3 and it works fine. To me, it seems like DBUtils is for some reason rounding the number I've defined. Is there a way I can force this to not happen? Can anyone explain why it might be doing this? Thanks!

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  • Getting all objects with a certain element inside a collection of strings with criteria API.

    - by Jens Jansson
    Hey. I'm trying to build a Hibernate Criteria query to find entities that have a specific element inside a collection. We can take as an example a Book -object that looks like this: public class Book { private Long id; private String title; private Set<String> authors = new HashSet<String>(); } The entity is mapped like this: <class name="Book" table="Book"> <id name="id" column="BOOK_ID"> <generator class="native"/> </id> <property name="title"/> <set name="authors" table="Book_Authors"> <key column="BOOK_ID"/> <element type="string" column="AUTHORS"/> </set> </class> Now I would like to find out which books are written by Matt. With pure SQL I can do a query like this: String author = "Matt"; String query = "SELECT * FROM Book " + "WHERE BOOK_ID IN " + "(SELECT BOOK_ID FROM Book_Authors " + "WHERE authors = :author )"; List<Book> result = session.createSQLQuery(query) .addEntity(Book.class) .setParameter("author", author) .list(); This works all good and well, and I get out all books that Matt has been a part of writing. The project I work in, however, uses the Criteria API instead of raw SQL, and I haven't found a way to express the same query in that form. I've taken a look on the Restrictions API and the closest I've found is Restions.in(propertyName, collection) but that works the other way around (one value in object, many values to match against). Any ideas?

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  • Finding users whose birtday is today with JPA

    - by Jeduan Cornejo
    Hi, I have a table with users and are trying to get a list with the people who have birthday today so the app can send an email. The User is defined as @Entity public class User { @Size(max = 30) @NotNull private String name; [...] @Temporal(TemporalType.DATE) @DateTimeFormat(style = "S-") protected Date birthday; } and I've got a method which returns the people which were born today like so @SuppressWarnings("unchecked") public static List<User> findUsersWithBirthday() { List<User> users = entityManager().createQuery("select u from User u where u.birthday = :date") .setParameter("date", new Date(), TemporalType.DATE) .getResultList(); return users; } This is fine and all for finding people which were born today, however tha's not really that useful, so I've been struggling for a way to find all the users that were born today, independent of the year. Using MySQL there's functions I can use like select month(curdate()) as month, dayofmonth(curdate()) as day However I've been struggling to find a JPA equivalent to that. I'm using Spring 3.0.1 and Hibernate 3.3.2

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  • Total row count for pagination using JPA Criteria API

    - by ThinkFloyd
    I am implementing "Advanced Search" kind of functionality for an Entity in my system such that user can search that entity using multiple conditions(eq,ne,gt,lt,like etc) on attributes of this entity. I am using JPA's Criteria API to dynamically generate the Criteria query and then using setFirstResult() & setMaxResults() to support pagination. All was fine till this point but now I want to show total number of results on results grid but I did not see a straight forward way to get total count of Criteria query. This is how my code looks like: CriteriaBuilder builder = em.getCriteriaBuilder(); CriteriaQuery<Brand> cQuery = builder.createQuery(Brand.class); Root<Brand> from = cQuery.from(Brand.class); CriteriaQuery<Brand> select = cQuery.select(from); . . //Created many predicates and added to **Predicate[] pArray** . . select.where(pArray); // Added orderBy clause TypedQuery typedQuery = em.createQuery(select); typedQuery.setFirstResult(startIndex); typedQuery.setMaxResults(pageSize); List resultList = typedQuery.getResultList(); My result set could be big so I don't want to load my entities for count query, so tell me efficient way to get total count like rowCount() method on Criteria (I think its there in Hibernate's Criteria).

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  • Two entities with @ManyToOne should join the same table

    - by Ivan Yatskevich
    I have the following entities Student @Entity public class Student implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Teacher @Entity public class Teacher implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Task @Entity public class Task implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "student_id") }) private Student author; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "teacher_id") }) private Teacher curator; //getters and setters } Consider that author and curator are already stored in DB and both are in the attached state. I'm trying to persist my Task: Task task = new Task(); task.setAuthor(author); task.setCurator(curator); entityManager.persist(task); Hibernate executes the following SQL: insert into student_task (teacher_id, id) values (?, ?) which, of course, leads to null value in column "student_id" violates not-null constraint Can anyone explain this issue and possible ways to resolve it?

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  • OptimisticLockException in inner transaction ruins outer transaction

    - by Pace
    I have the following code (OLE = OptimisticLockException)... public void outer() { try { middle() } catch (OLE) { updateEntities(); outer(); } } @Transactional public void middle() { try { inner() } catch (OLE) { updateEntities(); middle(); } @Transactional public void inner() { //Do DB operation } inner() is called by other non-transactional methods which is why both middle() and inner() are transactional. As you can see, I deal with OLEs by updating the entities and retrying the operation. The problem I'm having is that when I designed things this way I was assuming that the only time one could get an OLE was when a transaction closed. This is apparently not the case as the call to inner() is throwing an OLE even when the stack is outer()->middle()->inner(). Now, middle() is properly handling the OLE and the retry succeeds but when it comes time to close the transaction it has been marked rollbackOnly by Spring. When the middle() method call finally returns the closing aspect throws an exception because it can't commit a transaction marked rollbackOnly. I'm uncertain what to do here. I can't clear the rollbackOnly state. I don't want to force create a transaction on every call to inner because that kills my performance. Am I missing something or can anyone see a way I can structure this differently? EDIT: To clarify what I'm asking, let me explain my main question. Is it possible to catch and handle OLE if you are inside of an @Transactional method? FYI: The transaction manager is a JpaTransactionManager and the JPA provider is Hibernate.

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  • Strange JPA one-to-many behavior when trying to set the "many" on the "one" entity

    - by errr
    I've mapped two entities using JPA (specifically Hibernate). Those entities have a one-to-many relationship (I've simplified for presentation): @Entity public class A { @ManyToOne public B getB() { return b; } } @Entity public Class B { @OneToMany(mappedBy="b") public Set<A> getAs() { return as; } } Now, I'm trying to create a relationship between two instances of these entities by using the setter of the one-side/not-owner-side of the relationship (i.e the table being referenced to): em.getTransaction().begin(); A a = new A(); B b = new B(); Set<A> as = new HashSet<A>(); as.add(a); b.setAs(as); em.persist(a); em.persist(b); em.getTransaction().commit(); But then, the relationship isn't persisted to the DB (the row created for entity A isn't referencing the row created for entity B). Why is it so? I'd excpect it to work. Also, if I remove the "mappedBy" property from the @OneToMany annotation it will work. Again - why is it so? and what are the possible effects for removing the "mappedBy" property?

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  • many to many and integrity when saving the null

    - by user369759
    I have two classes Software, Tag - they are related by ManyToMany. We CAN NOT create Software without putting the Tag to it. I want to write a test which check that: @Test public void createSoftwareWithNullTags() { List<Tag> tags = null; Software software = new Software("software1", "description1", tags); try { software.save(); fail("tags should not be null"); } catch (Exception ex) { // NEVER COME HERE !!! } } So, this test fails. I guess it is not good test for that case - because it even do not try to SAVE data to SOFTWARE_TAG table. Of course i could do validation manually but i want implement it with hibernate, using some annotation or something. Is it possible? Or how would you do this? My entities: @Entity public class Tag extends Model { public String title; public Tag(String title) { this.title = title; } @ManyToMany( cascade = {CascadeType.ALL}, mappedBy = "tags", targetEntity = Software.class ) public List<Software> softwares; } @Entity public class Software extends Model { public String title; public String description; @ManyToOne(optional = false) public Author author; @ManyToMany(cascade = CascadeType.ALL) @JoinTable( name = "SOFTWARE_TAG", joinColumns = @JoinColumn(name = "Software_id"), inverseJoinColumns = @JoinColumn(name = "Tag_id") ) public List<Tag> tags; public Software(String title, String description, Author author, List<Tag> tags) { this.title = title; this.description = description; this.author = author; this.tags = tags; } }

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  • Two entities with @ManyToOne joins the same table

    - by Ivan Yatskevich
    I have the following entities Student @Entity public class Student implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Teacher @Entity public class Teacher implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Task @Entity public class Task implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "student_id") }) private Student author; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "teacher_id") }) private Teacher curator; //getters and setters } Consider that author and curator are already stored in DB and both are in the attached state. I'm trying to persist my Task: Task task = new Task(); task.setAuthor(author); task.setCurator(curator); entityManager.persist(task); Hibernate executes the following SQL: insert into student_task (teacher_id, id) values (?, ?) which, of course, leads to null value in column "student_id" violates not-null constraint Can anyone explain this issue and possible ways to resolve it?

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  • Storing a jpa entity where only the timestamp changes results in updates rather than inserts (desire

    - by David Schlenk
    I have a JPA entity that stores a fk id, a boolean and a timestamp: @Entity public class ChannelInUse implements Serializable { @Id @GeneratedValue private Long id; @ManyToOne @JoinColumn(nullable = false) private Channel channel; private boolean inUse = false; @Temporal(TemporalType.TIMESTAMP) private Date inUseAt = new Date(); ... } I want every new instance of this entity to result in a new row in the table. For whatever reason no matter what I do it always results in the row getting updated with a new timestamp value rather than creating a new row. Even tried to just use a native query to run an insert but channel's ID wasn't populated yet so I gave up on that. I've tried using an embedded id class consisting of channel.getId and inUseAt. My equals and hashcode for are: public boolean equals(Object obj){ if(this == obj) return true; if(!(obj instanceof ChannelInUse)) return false; ChannelInUse ciu = (ChannelInUse) obj; return ( (this.inUseAt == null ? ciu.inUseAt == null : this.inUseAt.equals(ciu.inUseAt)) && (this.inUse == ciu.inUse) && (this.channel == null ? ciu.channel == null : this.channel.equals(ciu.channel)) ); } /** * hashcode generated from at, channel and inUse properties. */ public int hashCode(){ int hash = 1; hash = hash * 31 + (this.inUseAt == null ? 0 : this.inUseAt.hashCode()); hash = hash * 31 + (this.channel == null ? 0 : this.channel.hashCode()); if(inUse) hash = hash * 31 + 1; else hash = hash * 31 + 0; return hash; } } I've tried using hibernate's Entity annotation with mutable=false. I'm probably just not understanding what makes an entity unique or something. Hit the google pretty hard but can't figure this one out.

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  • application specific seed data population

    - by user339108
    Env: JBoss, (h2, MySQl, postgres), JPA, Hibernate 3.3.x @Id @GeneratedValue(strategy = IDENTITY) private Integer key; Currently our primary keys are created using the above annotation. We expect to support a large number of users (~million users), what key should be used. Should it be Integer or Long or should I use the unsigned versions of the above declarations. We have a j2ee application which needs to be populated with some seed data on installation. On purchase, the customer creates his own data on top of the application. We just want to make sure that there is enough room to ship, modify or add data for future releases. What would be the best mechanism to support this, we had looked at starting all table identifiers from a certain id (say 1000) but this mandates modifying primary key generation to have table or sequence based generators and we have around ~100 tables. We are not sure if this is the right strategy for this. If we use a signed integer approach for the key, would it make sense to have the seed data as everything starting from 0 and below (i.e -ve numbers), so that all customer specific data will be available on 0 and above (i.e. +ve numbers)

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