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  • Encrypting password in compiled C or C++ code

    - by Daniel
    Hello!, I know how to compile C and C++ Source files using GCC and CC in the terminal, however i would like to know if its safe to include passwords in these files, once compiled. For example.. i check user input for a certain password e.g 123, but it appears compiled C/C++ programs is possible to be decompiled. Is there anyway to compile a C/C++ source file, while keeping the source completely hidden.. If not, could anyone provide a small example of encrypting the input, then checking against the password e.g: (SHA1, MD5)

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  • Regular Expression - Password Validation is not working

    - by Kesavan
    Hi, I have to validate the password using regex. The password rule is like at least 1 uppercase and at least 2 numeric. It works fine except if the character comes at the end of the string. The regular expression which i am using is "^(?=.*\d.{2})(?=.*[A-Z].{1})(?=.*[@#$%^&+=].{2}).{8,12}$" Rules: minimum length = 8 minimum uppercase = 1 minimum numeric = 2 minimum special character = 1 It works for Test123$$, Test$123, TEST123$s, Test123$1, Test12$3 but it fails if the character specified comes at the end of the string like Test123$, Test$a12, Test12aa@, 123aa@@T. Please let me know if there is any fix for this.

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  • Pop up password protect

    - by steve
    Please not that I fully understand this is a dumb ass idea, but its not my idea. We need to deter people visiting a certain page on our site. It's written in ASP and I don'tknow ASP! Can anyone tell me how I can have a pop up box load when the URL is visited where by people have to enter a username / password. The user name / password should be stored in the javascript. (Yes I know) The only real requirement is that this happen anytime the page is loaded and it stays on that page. So the page is test.asp - javascript pops up they enter credentials and if right remain on test.asp Thanks

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  • Capistrano SSH::AuthenticationFailed, not prompting for password

    - by Sparkmasterflex
    I've been using capistrano successfully for a while now and all of a sudden in every project I've lost the ability to deploy. Environment: os X (Mavericks) ruby 1.9.3p194 rvm (locally, not on server) rails 3.2 and up RubyGems 1.8.25 I'm not using rsa_keys or anything I want capistrano to prompt for user and password. Suddenly it has decided not to ask for a password, but does ask for user. Then it rolls back and gives me the following error. [deploy:update_code] exception while rolling back: Capistrano::ConnectionError, connection failed for: sub.example.com (Net::SSH::AuthenticationFailed: Authentication failed for user [email protected]) connection failed for: sub.example.com (Net::SSH::AuthenticationFailed: Authentication failed for user [email protected]) This has occurred on my personal laptop and my iMac at work. It occurs when deploying to two different servers (both linux) I'm completely at a loss here. Any ideas?

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  • Clearing a form field when page goes back (html / javascript)

    - by DomingoSL
    Do you know when you use in a form the password field, like this: <input type="password" name="pass"> And you do a GET or POST submit to the same page who have the form and if the user hit back in the browser the password field gets blank. Well thats good, but i need to get blank another form field when the user hit back. Thats because i asking for a captcha and the text field who hold the information entered by the user ramain fill when he hit back, but the captcha image change, and if i dont blank the field the user (sometimes) dont get that he needs to re-enter the captcha. Thanks!

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  • Random password variable disappears

    - by snaken
    Hi, I'm using the following to generate a random password in a shell script: DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) When i run this in a file on its own like this: #!/bin/sh DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) echo $DBPASS A password is echoed. When i incorporate it into a larger script though the variable never seems to get created for some reason, so for example this doesn't work: DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) sed -i s/oldpass/$DBPASS/ mysql_connect.php If i manually set the variable though everything is fine.. can anyone see why?

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  • Password Hash Implementation

    - by oyerli
    I am developing a new application using Symfony. I want to store the passwords hashed, so I overridded the save method in my User model: public function save(Doctrine_Connection $conn = null) { $this->setUserPassword( md5($this->getUserPassword()) ); return parent::save($conn); } This works good when a new user created. However, this causes problems when we edit a user without changing his password. This causes Doctrine to hash the already hashed password. So, I need to check that whether the UserPassword is modified in this DoctrineRecord instance. How can I manage to do that?

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  • .htaccess password and forced login

    - by Boco
    I have password protected website with .htaccess. What I want to do now is to force users to login from the index.html page and not from any other which they can do now. ie. I have index.html (the main page) and I have two other pages 1.html and 2. html also protected with .htaccess password. Users can now type http://www.mypage.com/1.html and they will be asked for login data but I would like to force them (before they are asked for login details) to index.html to login. After they are loggedin they can use any link (ie.1.html or 2.html) as they want. Can this be done by using .htaccess? I would need the whole code. Thank you!

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  • Password Protected Android App

    - by Caution Continues
    I wana make a security app and in case of stolen or lost my app must not be uninstalled without taking password. yes It is possible to make such an app that can take password before getting uninstall.. My friend Aditya Nikhade has made this app :) .But he is not giving me this secrete recipe:( Install this app Findroid from google Play. In this app first you need to unlock your app then only u can uninstall it. So please help me how to crack this technique.. I searched and got some incomplete answer in that we can declare a receiver of type PACKAGED_REMOVED but i want to know how can I stop if my app is being uninstalled. I am little close to solution of it. I am working/studying on Device Administrator. Please paste code snippet if anyone have. Thanks a Ton in advanced....!!!

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  • Using php to create a password system with chinese characters

    - by WillDonohoe
    Hi guys, I'm having an issue with validating chinese characters against other chinese characters, for example I'm creating a simple password script which gets data from a database, and gets the user input through get. The issue I'm having is for some reason, even though the characters look exactly the same when you echo them out, my if statement still thinks they are different. I have tried using the htmlentities() function to encode the characters, the password from the database encodes nicely, giving me a working '& #35441;' (I've put a space in it to stop it from converting to a chinese character!). The other user input value gives me a load of funny characters. The only thing which I believe must be breaking it, is it encodes in a different way and therefore the php thinks it's 2 completely different strings. Does anybody have any ideas? Thanks in advance, Will

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  • Reset array keys in multidimensional array

    - by nbaumann
    I've been looking around for a solution to this with no real success. I have a multidimensional array of parents and children with no limits on depth. This is generated from a database but the issue is that the item ID becomes the key using my way of arranging a flat array into a multidimensional array like so: Array( [28] => Array ( [id] => 28 [color] => #ff24e5 [name] => Personal [parent_id] => [children] => Array ( [23] => Array ( [id] => 23 [color] => #41c3a3 [name] => Shopping [parent_id] => 28 [children] => Array ( [22] => Array ( [id] => 22 [color] => #8be32b [name] => Deals [parent_id] => 23 [children] => Array ( ) ) ) ) [150] => Array ( [id] => 150 [color] => #e9a3f0 [name] => Orders [parent_id] => 28 [children] => Array ( ) ) ) ) ) What I would like, is a function that does the following: Array ( [0] => Array ( [id] => 28 [color] => #ff24e5 [name] => Personal [parent_id] => [children] => Array ( [0] => Array ( [id] => 23 [color] => #41c3a3 [name] => Shopping [parent_id] => 28 [children] => Array ( [0] => Array ( [id] => 22 [color] => #8be32b [name] => Deals [user_id] => 1 [selected] => 0 [parent_id] => 23 [children] => Array ( ) ) ) ) [1] => Array ( [id] => 150 [color] => #e9a3f0 [name] => Orders [parent_id] => 28 [children] => Array ( ) ) ) ) ) Essentially reassign keys starting from 0. I've tried numerous methods, but I'm assuming that I need to find a recursive solution and when I tried that, it destroyed my array. I was reading up on the array_walk_recursive() function, but I don't quite know what to do beyond that. Essentially, is there a way to reset numeric keys in a multidimensional array? Thanks for the help!

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  • How do you reset a USB device from the command line?

    - by Casey
    Is it possible to reset the connection of a USB device, without physically disconnecting/connecting from the PC? Specifically, my device is a digital camera. I'm using gphoto2, but lately I get "device read errors", so I'd like to try to do a software-reset of the connection. From what I can tell, there are no kernel modules being loaded for the camera. The only one that looks related is usbhid.

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  • How do you reset a USB device from the command line?

    - by Casey
    Is it possible to reset the connection of a USB device, without physically disconnecting/connecting from the PC? Specifically, my device is a digital camera. I'm using gphoto2, but lately I get "device read errors", so I'd like to try to do a software-reset of the connection. From what I can tell, there are no kernel modules being loaded for the camera. The only one that looks related is usbhid.

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  • Logs show failed password for invalid user root from <IP Address> port 2924 ssh2

    - by Chris Hanson
    I'm getting a constant flow of these messages in my logs. The port is variable (seemingly between 1024 and 65535). I can simulate it myself by running sftp root@<my ip> I've commented out the sftp subsystem line in my sshd_config. These ports should be closed by provider's firewall. I don't understand: Why sftp would be selecting a random port like that. It seems to be behaving like FTP in passive mode, but I can't make any sense of why that would be. Why it can even hit my server in the first place if these ports are closed.

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  • Hide users from Mac OS X Snow Leopard logon screen.

    - by googletorp
    Somehow, I managed to set a passwd for my _postgres user on my OS instead of setting it on the postgres role I have as my superuser / root. Anyways since this, I've been struggling with that user showing up in the account section and login screen, which I really would like to avoid. I've read through some docs about this, and setting the password to * should be all that is needed to fix this. But after several attempts doing this with and without dscl to no avail, I'm gotten to a point where I don't know what to do anymore. I didn't think it would be even hard doing this, but clearly I'm missing something, so how do you do this?

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  • How to create a Linux user without a password but being able to set it?

    - by Leonid Shevtsov
    I have a username and an SSH key for a (hypothetical) guy and I need to give him admin access to a Linux (Ubuntu) server. I want him to be able to log in via SSH and then set his password by himself over a secure connection, instead of passing the password around. I know how to make the password expire and force him to reset it on first login. But this doesn't work unless he has some password already, which I then have to tell him. I thought about making the password blank - SSH wouldn't allow login, but then anyone can su into the user. My question is, is there some best practice to creating accounts in such a way? Or setting a default password is unavoidable?

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  • sftp and public keys

    - by Lizard
    I am trying to sftp into an a server hosted by someone else. To make sure this worked I did the standard sftp [email protected] i was promted with the password and that worked fine. I am setting up a cron script to send a file once a week so have given them our public key which they claim to have added to their authorized_keys file. I now try sftp [email protected] again and I am still prompted for a password, but now the password doesn't work... Connecting to [email protected]... [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied (publickey,password). Couldn't read packet: Connection reset by peer I did notice however that if I simply pressed enter (no password) it logged me in fine... So here are my questions: Is there a way to check what privatekey/pulbickey pair my sftp connection is using? Is it possible to specify what key pair to use? If all is setup correctly (using correct key pair and added to authorized files) why am I being asked to enter a blank password? Thanks for your help in advance! UPDATE I have just run sftp -vvv [email protected] .... debug1: Authentications that can continue: publickey,password debug3: start over, passed a different list publickey,password debug3: preferred gssapi-with-mic,publickey,keyboard-interactive,password debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug1: Next authentication method: publickey debug1: Offering public key: /root/.ssh/id_rsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Server accepts key: pkalg ssh-rsa blen 277 debug2: input_userauth_pk_ok: SHA1 fp 45:1b:e7:b6:33:41:1c:bb:0f:e3:c1:0f:1b:b0:d5:e4:28:a3:3f:0e debug3: sign_and_send_pubkey debug1: read PEM private key done: type RSA debug1: Authentications that can continue: publickey,password debug1: Trying private key: /root/.ssh/id_dsa debug3: no such identity: /root/.ssh/id_dsa debug2: we did not send a packet, disable method debug3: authmethod_lookup password debug3: remaining preferred: ,password debug3: authmethod_is_enabled password debug1: Next authentication method: password It seems to suggest that it tries to use the public key... What am I missing?

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  • Local Password Management

    - by ultimazombie88
    In our office (and I am sure many others) we access various websites and tend to share one account with our team. For example, we share credentials to Ebay and change them every few weeks to maintain some sense of security. However, we know this does not allow for any type of accountability for major changes. After some discussion we want to try to manage how we distribute credentials for sites that may not offer child accounts. Is there any smart and safe way to do this? If so how do you do it?

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  • Possible to get cleartext password?

    - by Farhan
    I have hosting service hosted on more than 20+ Plesk servers, version 11. As in the previous versions, the passwords were not encrypted, then if i had to design some tools to manage the hosting accounts, i just picked up the cleartext passwords from the Database. but as now the passwords are encrypted, is there any way i can decrypt the passwords? through API or any other way so that i can integrate my php based hosting management with plesk 11?

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  • Debian Simple Gui for adding/removing users for protective directories

    - by ErocM
    We have a hosted site with a directory that is password protected. I need to have a user who knows very little about computers, maintain the users that have access to this directory. The list is going to get big, according to our customer database. My question is 2 fold: Is there a simple gui program that I can have this user utilize to be able to maintain the users without having to teach them how to use ssh and UNIX? Am I going about this the right way? Is there a better way to do this? Thanks for your help!

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