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  • MD5 hash differences between Python and other file hashers

    - by Sam
    I have been doing a bit of programming in Python (still a n00b at it) and came across something odd. I made a small program to find the MD5 hash of a filename passed to it on the command line. I used a function I found here on SO. When I ran it against a file, I got a hash "58a...113". But when I ran Microsoft's FCIV or the md5sum.py in \Python26\Tools\Scripts\, I get a different hash, "591...ae6". The actual hashing part of the md5sum.py in Scripts is m = md5.new() while 1: data = fp.read(bufsize) if not data: break m.update(data) out.write('%s %s\n' % (m.hexdigest(), filename)) This looks functionally identical to the code in the function given in the other answer... What am I missing? (This is my first time posting to stackoverflow, please let me know if I am doing it wrong.)

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  • How can I extract and save values from an XML file in Perl?

    - by Freddy
    Here is what I am trying to do in a Perl script: $data=""; sub loadXMLConfig() { $filename="somexml.xml" $data = $xml-XMLin($filename); } sub GetVariable() { ($FriendlyName) = @_; switch($FriendlyName) { case "My Friendly Name" {print $data-{my_xml_tag_name}} .... .... .... } } The problem is I am using Perl just because I am reading from an XML file, but I need to get these variables by a shell script. So, here is what I am using: $ perl -e 'require "scrpt.pl"; loadConfigFile(); GetVariable("My Variable")' This works exactly as expected, but I need to read the XML file every time I am getting a variable. Is there a way I could "preserve" $data across shell calls? The idea is that I read the XML file only once. If no, is there is a more simple way I could do this? These are the things I can't change: Config File is an XML Need the variables in a shell script

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  • OpenGL Shader Compile Error

    - by Tomas Cokis
    I'm having a bit of a problem with my code for compiling shaders, namely they both register as failed compiles and no log is received. This is the shader compiling code: /* Make the shader */ Uint size; GLchar* file; loadFileRaw(filePath, file, &size); const char * pFile = file; const GLint pSize = size; newCashe.shader = glCreateShader(shaderType); glShaderSource(newCashe.shader, 1, &pFile, &pSize); glCompileShader(newCashe.shader); GLint shaderCompiled; glGetShaderiv(newCashe.shader, GL_COMPILE_STATUS, &shaderCompiled); if(shaderCompiled == GL_FALSE) { ReportFiler->makeReport("ShaderCasher.cpp", "loadShader()", "Shader did not compile", "The shader " + filePath + " failed to compile, reporting the error - " + OpenGLServices::getShaderLog(newCashe.shader)); } And these are the support functions: bool loadFileRaw(string fileName, char* data, Uint* size) { if (fileName != "") { FILE *file = fopen(fileName.c_str(), "rt"); if (file != NULL) { fseek(file, 0, SEEK_END); *size = ftell(file); rewind(file); if (*size > 0) { data = (char*)malloc(sizeof(char) * (*size + 1)); *size = fread(data, sizeof(char), *size, file); data[*size] = '\0'; } fclose(file); } } return data; } string OpenGLServices::getShaderLog(GLuint obj) { int infologLength = 0; int charsWritten = 0; char *infoLog; glGetShaderiv(obj, GL_INFO_LOG_LENGTH,&infologLength); if (infologLength > 0) { infoLog = (char *)malloc(infologLength); glGetShaderInfoLog(obj, infologLength, &charsWritten, infoLog); string log = infoLog; free(infoLog); return log; } return "<Blank Log>"; } and the shaders I'm loading: void main(void) { gl_FragColor = vec4(1.0, 0.0, 0.0, 1.0); } void main(void) { gl_Position = ftransform(); } In short I get From: ShaderCasher.cpp, In: loadShader(), Subject: Shader did not compile Message: The shader Data/Shaders/Standard/standard.vs failed to compile, reporting the error - <Blank Log> for every shader I compile I've tried replacing the file reading with just a hard coded string but I get the same error so there must be something wrong with how I'm compiling them. I have run and compiled example programs with shaders, so I doubt my drivers are the issue, but in any case I'm on a Nvidia 8600m GT. Can anyone help?

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  • How can one cache bust files referenced in a LESS file when using Symfony2, Twig, and Assetic?

    - by user3719083
    I have a web site built on Symfony2 which uses twig templates, LESS, and assetic. In order to cache bust assets, I'm simply using this in my config.yml: framework: templating: engines: ['twig'] assets_version: 'asset-version-here' And then I use the asset() function to load the asset and the cache busting is handled for me. However, the concern I have is when I load my LESS (css) file, there are references to other files, and I would like to know how these files can be cache busted as well. Example: .someSelector { background:url('../images/filename.png'); } How can I make sure that the referenced file, filename.png is cache busted upon deployment? The asset files referenced in Twig using asset() are cache busted automatically upon deployment (I use a deployment script hook that updates the assets_version in the framework's config), but those referenced in a stylesheet are not. How can I do this?

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  • PHP write file... need help

    - by Jordan Pagaduan
    <?php $title = $_POST['title']; $filename = $title , ".php"; $fh = fopen($filename, 'w') or die ("can't open file"); $stringData = $title; fwrite($fh, $stringData); $stringData = $blog; fwrite($fh, $stringData); fclose($fh); ?> This is only a sample. What is the correct code for that?

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  • Joining remote paths in Java

    - by Mickael Marrache
    I'm using the FTP library provided by Apache (commons-net). I want to check if a file exists on the FTP server so I use the listFiles method of FTPClient: ftpClient.listFiles(remoteFileDir + "\\" + fileName); The current directory is the FTP server root directory. So, the value of remoteFileDir is a path relative to this root directory. My question concerns the merge between the remote directory path and the file name. What is the right way to do it? For a local file, I would do: File file = new File(remoteFileDir,fileName); but here it doesn't work since when I call file.getAbsolutePath(), I get an absolute path for the file in the local current directory which is not what I want. Also, I guess the merging has been done according to my local environment. PS: I looked at How are paths determined on a remote machines? but it doesn't help me. Thanks

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  • ASP.NET DropDownList Replacement

    - by user302004
    Currently, I'm populating a drop down list when a file is created in a configurable folder. if (!downloadRspDropDown.Items.Contains(new ListItem(txt, fileData.FullName)) Then, I add the file and remove "No Responses Available". However, if the same file is resubmitted (i.e., the file name is the same but the timestamp is different), then I want to remove the older entry and replace it with a new entry in the drop down list. I have the filename, so I go into the "else" block from the line of code above. From there, I'm checking to see if I have the same filename and a different creation time. if (downloadRspDropDown.Items.Contains(new ListItem(txt, fileData.FullName) && downloadRspDropDown.Items.Contains(new ListItem(txt, fileData.CreationTime) From here, I want to find the position, remove it, and add the new text. This approach isn't working. Can anyone offer an alternate approach?

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  • std::map insert segmentation fault

    - by Jakub Czaplicki
    Why does this code stop with segmentation fault : class MapFile { public: /* ... */ std::map <unsigned int, unsigned int> inToOut; }; bool MapFile::LoadMapFile( const wxString& fileName ) { /* ... */ inToOut.insert( std::make_pair(input,output) ); } but this one works fine : class MapFile { public: /* ... */ }; bool MapFile::LoadMapFile( const wxString& fileName ) { /* ... */ std::map <unsigned int, unsigned int> inToOut; inToOut.insert( std::make_pair(input,output) ); } ?

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  • How to count the length (number of lines) of a csv file in Rails?

    - by Mathias
    Hello, I have a form (Rails) which allows me to load a .csv file using the file_field. In the view: <% form_for(:upcsv, :html => {:multipart => true}) do |f| %> <table> <tr> <td><%= f.label("File:") %></td> <td><%= f.file_field(:filename) %></td> </tr> </table> <%= f.submit("Submit") %> <% end %> Clicking Submit redirects me to another page (create.html.erb). The file was loaded fine, and I was able to read the contents just fine in this second page. I am trying to show the number of lines in the .csv file in this second page. My controller (semi-pseudocode): class UpcsvController < ApplicationController def index end def create file = params[:upcsv][:filename] ... #params[:upcsv][:file_length] = file.length # Show number of lines in the file #params[:upcsv][:file_length] = file.size ... end end Both file.length and file.size returns '91' when my file only contains 7 lines. From the Rails documentation that I read, once the Submit button is clicked, Rails creates a temp file of the uploaded file, and the params[:upcsv][:filename] contains the contents of the temp/uploaded file and not the path to the file. And I don't know how to extract the number of lines in my original file. What is the correct way to get the number of lines in the file? My create.html.erb: <table> <tr> <td>File length:</td> <td><%= params[:upcsv][:file_length] %></td> </tr> </table> I'm really new at Rails (just started last week), so please bear with my stupid questions. Thank you!

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  • Ruby string encoding problem

    - by John Prideaux
    I've looked at the other ruby/encoding related posts but haven't been able to figure out why the following is not working. Likely just because I'm dense, but here's the situation. Using Ruby 1.9 on windows. I have a set of CSV files that need some data appended to the end of each line. Whenever I run my script, the appended characters are gibberish. The input text appears to be IBM437 encoding, whereas my string I'm appending starts as US-ASCII. Nothing I've tried with respect to forcing encoding on the input strings or the append string seems to change the resultant output. I'm stumped. The current encoding version is simply the last that I tried. def append_salesperson(txt, salesperson) if txt.length > 2 return txt.chomp.force_encoding('US-ASCII') + %(, "", "", "#{salesperson}") end end salespeople = Hash[ "fname", "Record Manager"] outfile = File.open("ActData.csv", "w:US-ASCII") salespeople.each do | filename, recordManager | infile = File.open("#{filename}.txt") infile.each do |line| outfile.puts append_salesperson(line, recordManager) end infile.close end outfile.close

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  • Fetch image from folder via datatable does not work after placing image in subdirectory

    - by Arnold Bishkoff
    I am having trouble wrapping my head around the following I have code that fetches an image via smarty in a line img src="getsnap.php?picid={$data[$smarty.section.sec.index].picno|default:$nextpic}&typ=pic&width={$config.disp_snap_width}&height={$config.disp_snap_height}" class="smallpic" alt="" / this works if i pull the image from /temp/userimages/userid/imageNo.ext but because an OS can segfault if you store too many folders or images in a directory i have code that assigns the user image to a subdirectory based upon division of a subdir per 1000 userids. so in thise case i have user id 94 whos images get stored in /siteroot/temp/userimages/000000/94/pic_1.jpg (through 10) or tn_1 (through 10).jpg here is the code for getsnap.php <?php ob_start(); if ( !defined( 'SMARTY_DIR' ) ) { include_once( 'init.php' ); } include('core/snaps_functions.php'); if (isset($_REQUEST['username']) && $_REQUEST['username'] != '') { $userid = $osDB-getOne('select id from ! where username = ?',array(USER_TABLE, $_REQUEST['username']) ); } else { // include ( 'sessioninc.php' ); if( !isset($_GET['id']) || (isset($_GET['id'])&& (int)$_GET['id'] <= 0 ) ) { $userid = $_SESSION['UserId']; } else { $userid = $_GET['id']; } } if (!isset($_GET['picid']) ) { if ((isset($_REQUEST['type']) && $_REQUEST['type'] != 'gallery') || !isset($_REQUEST['type']) ) { $defpic = $osDB-getOne('select picno from ! where userid = ? and ( album_id is null or album_id = ?) and default_pic = ? and active = ? ',array(USER_SNAP_TABLE, $userid,'0','Y','Y' ) ); if ($defpic != '') { $picid = $defpic; } else { $picid = $osDB-getOne('select picno from ! where userid = ? and ( album_id is null or album_id = ?) and active=? order by rand()',array(USER_SNAP_TABLE, $userid,'0','Y' ) ); } unset( $defpic); } } else { $picid = $_GET['picid']; } $typ = isset( $_GET['typ'])?$_GET['typ']:'pic' ; $cond = ''; if ( ($config['snaps_require_approval'] == 'Y' || $config['snaps_require_approval'] == '1') && $userid != $_SESSION['UserId'] ) { $cond = " and active = 'Y' "; } $sql = 'select * from ! where userid = ? and picno = ? '.$cond; //Get the pic $row =& $osDB-getRow ( $sql, array( USER_SNAP_TABLE, $userid, $picid ) ); //Okay pic was found in the DB, Lets actually do something // $id = $userid; $dir = str_pad(($id - ($id % 1000))/100000,6,'0',STR_PAD_LEFT); $zimg = USER_IMAGES_DIR.$dir; $img = getPicture($zimg, $userid, $picid, $typ, $row); //$img = getPicture($userid, $picid, $typ, $row); //$img = getPicture($dir, $userid, $picid, $typ, $row); $ext = ($typ = 'tn')?$row['tnext']:$row['picext']; // Now pic is built as // something pic_x.ext ie pic_2.jpg if ( $img != '' && ( ( hasRight('seepictureprofile') && ( $config['snaps_require_approval'] == 'Y' && $row['active'] == 'Y' ) ||$config['snaps_require_approval'] == 'N' ) || $userid == $_SESSION['UserId'] ) ) { $img2 = $img; //$img2 = $dir.'/'.$img; } else { $gender = $osDB-getOne( 'select gender from ! where id = ?', array( USER_TABLE, $userid ) ) ; if ($gender == 'M') { $nopic = SKIN_IMAGES_DIR.'male.jpg'; } elseif ($gender == 'F') { $nopic = SKIN_IMAGES_DIR.'female.jpg'; } elseif ($gender == 'D') { $nopic = SKIN_IMAGES_DIR.'director.jpg'; } $img2 = imagecreatefromjpeg($nopic); $ext = 'jpg'; } ob_end_clean(); header("Pragma: public"); header("Content-Type: image/".$ext); header("Content-Transfer-Encoding: binary"); header("Cache-Control: must-revalidate"); $ExpStr = "Expires: " . gmdate("D, d M Y H:i:s", time() - 30) . " GMT"; header($ExpStr); $id = $userid; $dir = str_pad(($id - ($id % 1000))/100000,6,'0',STR_PAD_LEFT); $zimg = USER_IMAGES_DIR.$dir; //header("Content-Disposition: attachment; filename=profile_".$userid."_".$typ.".".$ext); //header("Content-Disposition: attachment; filename=$dir.'/'.profile_".$userid."".$typ.".".$ext); //header("Content-Disposition: attachment; filename=profile"$dir".'/'.".$userid."_".$typ.".".$ext); header("Content-Disposition: attachment; filename=profile_".$userid."_".$typ.".".$ext); /* if ($_SESSION['browser'] != 'MSIE') { header("Content-Disposition: inline" ); } */ if ($ext == 'jpg') { imagejpeg($img2); } elseif ($ext == 'gif') { imagegif($img2); } elseif ($ext == 'png') { imagepng($img2); } elseif ($ext == 'bmp') { imagewbmp($img2); } imagedestroy($img2); ?

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  • How does Windows' 'Open with' work?

    - by Frederick
    I was under the impression that when you double click a file (or choose 'Open With' from the right click menu), Windows simply calls the application with the filename as the parameter. Something like this: C: App.exe file.abc However, I just double clicked an .xls file and then checked the PEB of the Excel instance that sprang up. To my surprise the commandline did not contain the filename as a parameter. So that set me wondering. What exactly is mechanism Windows uses to have a file opened by a relevant application? Is there a special API that each application that supports such facility must expose?

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  • How to get file path using FileUpload to be read by FileStream?

    - by john ryan
    I have a Method that open excel file and read it through exceldatareaderClass that i have downloaded in codeplex by using filestream. Currently I just declared the exact directory where the filestream open an excel file.And it works fine. Stream stream = new FileStream("C:\\" + FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Now i need to read the excel file wherever location the user place it like on windows forms fileupload.FileStream needs the exact location where the file is located. How to do this.? Example: Sample.xls is located on My Documents the file path should be like : C:\Documents and Settings\user\My Documents\ string openpath ="" ;//filepath Stream stream = new FileStream(openpath+ FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Thanks in Regards

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  • Conditional Batch file renaming with mysql data

    - by Paul Stevens
    Hello, I wonder if anyone knows how could I rename multiple files, all of them originally named with same structure, and add some data extracted from a mysql DB according to specifics rules. For example I have 500 files named with this vars: ID NAME ADDRESS PHONE.wav = 1234567 PAULSIMON WESTDR122 9942213456.wav Now I need to rename files taking some data from the databases for each file, and append the data from a query appended to the filename. For example add the data resulting from a query Where some conditions match, and the data to build the query is taked from original file name, as ID or NAME. i other words, lets say that I want to build a query taking ID & NAME from file 1234567 PAULSIMON WESTDR123 9942213456.wav as WHERE statements to take another value as BirthDATE and add this to new filename, so final result should be: ID NAME ADDRESS PHONE BIRTHDATE.wav I will appreciate any help on this. I need this to be done on a LINUX server.

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  • Python having problems writing/reading and testing in a correct format

    - by Ionut
    I’m trying to make a program that will do the following: check if auth_file exists if yes - read file and try to login using data from that file - if data is wrong - request new data if no - request some data and then create the file and fill it with requested data So far: import json import getpass import os import requests filename = ".auth_data" auth_file = os.path.realpath(filename) url = 'http://example.com/api' headers = {'content-type': 'application/json'} def load_auth_file(): try: f = open(auth_file, "r") auth_data = f.read() r = requests.get(url, auth=auth_data, headers=headers) if r.reason == 'OK': return auth_data else: print "Incorrect login..." req_auth() except IOError: f = file(auth_file, "w") f.write(req_auth()) f.close() def req_auth(): user = str(raw_input('Username: ')) password = getpass.getpass('Password: ') auth_data = (user, password) r = requests.get(url, auth=auth_data, headers=headers) if r.reason == 'OK': return user, password elif r.reason == "FORBIDDEN": print "Incorrect login information..." req_auth() return False I have the following problems(understanding and applying the correct way): I can't find a correct way of storing the returned data from req_auth() to auth_file in a format that can be read and used in load_auth file PS: Of course I'm a beginner in Python and I'm sure I have missed some key elements here :(

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  • hyperlink in firefox to windows share

    - by Eds
    I am having trouble creating a hyperlink to a windows share, that works correctly in firefox and IE9. The original line was this: <a href="\\10.1.3.33\sharename\filename.txt" target="_new">Link</a> This works correctly in IE9, andopens the file as you would expect. However, this does not seem to work in firefox, as it just appends the above to the root directory, so it ends up looking in: /\10.1.3.33/sharename/filename I have tried as someone suggested and appending file:// to the pathname, but this does not seem to load anything in firefox, but does work in IE. Can anyone advise on what I should be using the get a link to a network share working in all browsers? Many thanks, Eds

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  • Creating an HTML file by combining multiple PHP files via the command line?

    - by FishOrDie
    Is it possible to combine multiple PHP files via the command line and create an HTML file? For example, this will save the rendered version of a single PHP file as HTML: php /path/to/my/file/filename.php > /path/to/my/file/test.html I need it to combine multiple files, but I can't seem to get it it to work. Ideally, it would be something like this: php /path/to/my/file/filename.php + /path/to/my/file/filename2.php + /path/to/my/file/filename3.php > /path/to/my/file/test.html Is this possible? If so, how?

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  • load a word document inside window browser

    - by netNewbi3
    Hi, I have a page that dynamically links to a document that opens in a new page (the document is stored in a database as binary data and I loaded using the following code: Response.ClearContent() Response.ContentType = myReader("MIMEType").ToString() Response.AddHeader("Content-Disposition", "inline; filename=" & myReader("Filename")) Response.BinaryWrite(myReader("DocBD")) Response.End() This works ok. However some documents have restricted access and before loading the document the user is redirected to a login page. After entering username and passowrd the document is loaded. If it is a pdf file for example, it loads in the same login page, but when it is a word or excel document it opens outside the browser window and the login page remains in the background. Is ther a way to force a word or excel document to open inside the browser window? Many thanks.

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  • Downloading a csv file in django

    - by spyder
    I am trying to download a CSV file using HttpResponse to make sure that the browser treats it as an attachment. I follow the instructions provided here but my browser does not prompt a "Save As" dialog. I cannot figure out what is wrong with my function. All help is appreciated. dev savefile(request): try: myfile = request.GET['filename'] filepath = settings.MEDIA_ROOT + 'results/' destpath = os.path.join(filepath, myfile) response = HttpResponse(FileWrapper(file(destpath)), mimetype='text/csv' ) response['Content-Disposition'] = 'attachment; filename="%s"' %(myfile) return response except Exception, err: errmsg = "%s"%(err) return HttpResponse(errmsg) Happy Pat's day!

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  • Write data into .txt file created by CFileDialog, in C++

    - by younevertell
    I wanna Write data into .txt file created by CFileDialog, in C++. The problem I am facing is that below codes doesn't work, although there is no build error. The .txt file created by CFileDialog can not be found for some reason. What's wrong the code? what's the efficient way to Write data into .txt file created by CFileDialog, in C++? Thanks CFileDialog dlg(FALSE, NULL, NULL, OFN_OVERWRITEPROMPT, _T("My Data File (*.txt)|*.txt||")); if(dlg.DoModal() != IDOK) return; CString filename = dlg.GetPathName(); ofstream outfile (filename); int mydata = 10; outfile << "my data:" << mydata << endl; outfile.close();

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  • Access files (.wav) in java package

    - by Highmastdon
    I want to access my .wav files which are in a package inside my project. For example I got two packages: package program package sounds From inside the program/something.class I'd like to play the sounds/asound.wav. How is this possible. clip.open(AudioSystem.getAudioInputStream(new File(filename))); clip.start(); //.... something inbetween clip.stop(); Here filename is C:\\projects\\something\\sounds\\, but how is it possible to just give a relative path to the asound.wav in the package?

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  • creating an array of objects in c++

    - by tim22
    I'm trying to create an array of objects in c++. I'm creating a employee object, from my constructor in my company class here: employee obj(int tempIdNum, double tempBase, double tempSales, double tempRate); emp[tempcount]=obj; (this doesn't work?) Emp is the name of the array which is defined here, located in my company h file. Employee emp[4]; more code: Company::Company(string name, string fileName){ string str; int tempcount; int tempIdnum; double tempBase; double tempSales; double tempRate; double num; double arr[16]; this->name=name; //Commission temp; ifstream readFile; readFile.open("fileName"); int inc=0; while(tempcount<4){ for(int i=0+inc; i<4+inc; i++){ readFile>>num; arr[i-inc]=num; } tempIdnum=(int)(arr[0]); tempBase=arr[1]; tempSales=arr[2]; tempRate=arr[3]; Employee obj(int tempIdNum, double tempBase, double tempSales, double tempRate); emp[tempcount]=obj; inc+=4; tempcount++; } readFile.close(); } Here is some more from my h file #include <string> include "Commission.h" using namespace std; ifndef Company_H define Company_H class Company{ private: string name; //name of company Employee emp[4]; //array of payrool info about 4 commission employees int numEmp; //number of employees public: Company(); Company(string name, string fileName); ~Company(); string getName(); Commission getEmployee(int element); int getNumEmp(); }; endif enter code here Does not compile: 46 E:\exercise2\Company.cpp no match for 'operator=' in '((Company*)this)-Company::emp[tempcount] = obj'

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  • Python implementation of avro slow?

    - by lazy1
    I'm reading some data from avro file using the avro library. It takes about a minute to load 33K objects from the file. This seem very slow to me, specially with the Java version reading the same file in about 1sec. Here is the code, am I doing something wrong? import avro.datafile import avro.io from time import time def load(filename): fo = open(filename, "rb") reader = avro.datafile.DataFileReader(fo, avro.io.DatumReader()) for i, record in enumerate(reader): pass return i + 1 def main(argv=None): import sys from argparse import ArgumentParser argv = argv or sys.argv parser = ArgumentParser(description="Read avro file") start = time() num_records = load("events.avro") end = time() print("{0} records in {1} seconds".format(num_records, end - start)) if __name__ == "__main__": main()

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  • JQuery Ajax Always Fires Error Function

    - by CccTrash
    AddFileToDB.ashx: public void ProcessRequest (HttpContext context) { context.Response.ContentType = "application/json"; context.Response.Write("{ \"filename\": \"test.jpg\" }"); } JQuery: $.ajax({ url: 'AddFileToDB.ashx', dataType: 'json', success: function(data) { alert(data.filename); }, error: function(data) { alert('error'); }, }); This always results in the error function being called. I don't know why? Thoughts? AddFileToDB.ashx gets fired, but success never gets run.

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  • How can I deal with the ICE60 warning in WiX?

    - by Scott Boettger
    Good Afternoon, I have created a WiX project that installs a bunch of different EXEs and DLLs. Unfortunatly when I build the project I receive the following warning for each one of them: ICE60: The file fileName is not a Font, and its version is not a companion file reference. It should have a language specified in the Language column. I have found examples and possible solutions for this and each time it is suggested to set the DefaultLanguage tag to 0 in order to fix the warning. Once doing that I then get this warning: The DefaultLanguage '0' was used for file 'fileName' which has no language or version. For unversioned files, specifying a value for DefaultLanguage is not neccessary and it will not be used when determining file versions. Remove the DefaultLanguage attribute to eliminate this warning. So this leads me to the question of how can I handle this warning? Thanks in advance for any and all help given.

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