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  • How to take a collection of bytes and pull typed values out of it?

    - by Pat
    Say I have a collection of bytes var bytes = new byte[] {0, 1, 2, 3, 4, 5, 6, 7}; and I want to pull out a defined value from the bytes as a managed type, e.g. a ushort. What is a simple way to define what types reside at what location in the collection and pull out those values? One (ugly) way is to use System.BitConverter and a Queue or byte[] with an index and simply iterate through, e.g.: int index = 0; ushort first = System.BitConverter.ToUint16(bytes, index); index += 2; // size of a ushort int second = System.BitConverter.ToInt32(bytes, index); index += 4; ... This method gets very, very tedious when you deal with a lot of these structures! I know that there is the System.Runtime.InteropServices.StructLayoutAttribute which allows me to define the locations of types inside a struct or class, but there doesn't seem to be a way to import the collection of bytes into that struct. If I could somehow overlay the struct on the collection of bytes and pull out the values, that would be ideal. E.g. Foo foo = (Foo)bytes; // doesn't work because I'd need to implement the implicit operator ushort first = foo.first; int second = foo.second; ... [StructLayout(LayoutKind.Explicit, Size=FOO_SIZE)] public struct Foo { [FieldOffset(0)] public ushort first; [FieldOffset(2)] public int second; } Any thoughts on how to achieve this?

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  • Balanced Search Tree Query, Asymtotic Analysis..

    - by AGeek
    Hi, The situation is as follows:- We have n number and we have print them in sorted order. We have access to balanced dictionary data structure, which supports the operations serach, insert, delete, minimum, maximum each in O(log n) time. We want to retrieve the numbers in sorted order in O(n log n) time using only the insert and in-order traversal. The answer to this is:- Sort() initialize(t) while(not EOF) read(x) insert(x,t); Traverse(t); Now the query is if we read the elements in time "n" and then traverse the elements in "log n"(in-order traversal) time,, then the total time for this algorithm (n+logn)time, according to me.. Please explain the follow up of this algorithm for the time calculation.. How it will sort the list in O(nlogn) time?? Thanks.

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  • why IEEE floating point number calculate exponent using a biased form?

    - by lenatis
    let's say, for the float type in c, according to the IEEE floating point specification, there are 8-bit used for the fraction filed, and it is calculated as first taken these 8-bit and translated it into an unsigned number, and then minus the BIASE, which is 2^7 - 1 = 127, and the result is an exponent ranges from -127 to 128, inclusive. But why can't we just treat these 8-bit pattern as a signed number, since the resulting range is [-128,127], which is almost the same as the previous one.

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  • Worst Case number of rotations for BST to AVL algorithm?

    - by spacker_lechuck
    I have a basic algorithm below and I know that the worst case input BST is one that has degenerated to a linked list from inserts to only one side. How would I compute the worst case complexity in terms of number of rotations for this BST to AVL conversion algorithm? IF tree is right heavy { IF tree's right subtree is left heavy { Perform Double Left rotation } ELSE { Perform Single Left rotation } } ELSE IF tree is left heavy { IF tree's left subtree is right heavy { Perform Double Right rotation } ELSE { Perform Single Right rotation } }

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  • How to optimize class for viewstate

    - by Jeremy
    If I have an object I need to store in viewstate, what kinds of things can I do to optimize the size it takes to store the object? Obviously storing the least amount of data will take less space, but aside from that, are there ways to architect the class, properties, attrbutes etc, that will effect how large the serialized output is?

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  • Bitwise operations in BC?

    - by user355926
    $ bc BC> ibase=2 BC> 110&101 // wanna get 100 (standar_in) 8: syntax error Wikipedia informs that the ops are "|, & and ^". It may be that they work only in certain BC-types or I misread something.

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  • Read/Write Files from the Content Provider

    - by drum
    I want to be able to create a file from the Content Provider, however I get the following error: java.io.Filenotfoundexception: /0: open file failed: erofs (read-only file system) What I am trying to do is create a file whenever an application calls the insert method from my Provider. This is the excerpt of the code that does the file creation: FileWriter fstream = new FileWriter(valueKey); BufferedWriter out = new BufferedWriter(fstream); out.write(valueContent); out.close(); Originally I wanted to use openFileOutput() but the function appears to be undefined. Anyone has a workaround to this problem? EDIT: I found out that I had to specify the directory as well. Here is a more complete snippet of the code: File file = new File("/data/data/Project.Package.Structure/files/"+valueKey); file.createNewFile(); FileWriter fstream = new FileWriter(file); BufferedWriter out = new BufferedWriter(fstream); out.write(valueContent); out.close(); I also enabled the permission <uses-permission android:name="android.permission.WRITE_INTERNAL_STORAGE" /> This time I got an error saying: java.io.IOException: open failed: ENOENT (No such file or directory)

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  • Delete an object from a tree

    - by mqpasta
    I have a Find function in order to find an element from a BST private Node Find(ref Node n, int e) { if (n == null) return null; if (n.Element == e) return n; if (e > n.Element) return Find(ref n.Right, e); else return Find(ref n.Left, e); } and I use following code in order to get a node and then set this node to null. Node x = bsTree.Find(1); x = null; bsTree.Print(); supposedly, this node should be deleted from Tree as it is set to null but it still exists in tree. I had done this before but this time missing something and no idea what.

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  • iPhone - How to use #define in Universal app

    - by Satyam svv
    I'm creating universal app that runs oniphone and ipad. I'm using #define to create CGRect. And I want to use two different #define - one for iPhone and one for iPad. How can I declare them so that correct one will be picked by universal app.......... I think I've to update little more description to avoid confusion. I've a WPConstants.h file where I'm declaring all the #define as below #define PUZZLE_TOPVIEW_RECT CGRectMake(0, 0, 480, 100) #define PUZZLE_MIDDLEVIEW_RECT CGRectMake(0, 100, 480, 100) #define PUZZLE_BOTTOMVIEW_RECT CGRectMake(0, 200, 480, 100) The above ones are for iphone. Similarly for iPad I want to have different #define How can I proceed further?

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  • Write to the second line of a PHP file

    - by Woz
    I have a php file that I want to add an include path to on the second line. I need to open the file and inset a line of code on line 2. I have tried a few techniques none of which are working but I think it has something to do with the text I am trying to write and possibly not escaping character correctly as I am not too familiar with file writing. So here is the file I want to write to: $file = $_SERVER['DOCUMENT_ROOT'].'/'.$domaindir.'/test.php'; Here is the piece of text I want to insert into the file: $dbfile = "include('".$_SERVER['DOCUMENT_ROOT']."/".$domaindir."/web_".$dbname.".inc.php');"; Then what I was doing was a string replace but all it did was bump the "session_start();" bit to a newline! Can anyone point me in the direction of a tutorial that might tell me how to insert this into the second line of my php file or indeed if anyone has any ideas? I can say for sure that the path to the PHP file is fully tested so i know its not that the file is not being open or written to. Any ideas would be much appreciated. Thanks in advance.

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  • How to find kth minimal element in the union of two sorted arrays?

    - by Michael
    This is a homework question. They say it takes O(logN + logM) where N and M are the arrays lengths. Let's name the arrays a and b. Obviously we can ignore all a[i] and b[i] where i k. First let's compare a[k/2] and b[k/2]. Let b[k/2] a[k/2]. Therefore we can discard also all b[i], where i k/2. Now we have all a[i], where i < k and all b[i], where i < k/2 to find the answer. What is the next step?

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  • Help me understand why page sizes are a power of 2?

    - by eric
    Answer I need help with is: Recall that paging is implemented by breaking up an address into a page and offset number. It is most efficient to break the address into X page bits and Y offset bits, rather than perform arithmetic on the address to calculate the page number and offset. Because each bit position represents a power of 2, splitting an address between bits results in a page size that is a power of 2. i don't quite understand this answer, can anyone give a simpler explanation?

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  • Write file need to optimised for heavy traffic part 2

    - by Clayton Leung
    For anyone interest to see where I come from you can refer to part 1, but it is not necessary. write file need to optimised for heavy traffic Below is a snippet of code I have written to capture some financial tick data from the broker API. The code will run without error. I need to optimize the code, because in peak hours the zf_TickEvent method will be call more than 10000 times a second. I use a memorystream to hold the data until it reaches a certain size, then I output it into a text file. The broker API is only single threaded. void zf_TickEvent(object sender, ZenFire.TickEventArgs e) { outputString = string.Format("{0},{1},{2},{3},{4}\r\n", e.TimeStamp.ToString(timeFmt), e.Product.ToString(), Enum.GetName(typeof(ZenFire.TickType), e.Type), e.Price, e.Volume); fillBuffer(outputString); } public class memoryStreamClass { public static MemoryStream ms = new MemoryStream(); } void fillBuffer(string outputString) { byte[] outputByte = Encoding.ASCII.GetBytes(outputString); memoryStreamClass.ms.Write(outputByte, 0, outputByte.Length); if (memoryStreamClass.ms.Length > 8192) { emptyBuffer(memoryStreamClass.ms); memoryStreamClass.ms.SetLength(0); memoryStreamClass.ms.Position = 0; } } void emptyBuffer(MemoryStream ms) { FileStream outStream = new FileStream("c:\\test.txt", FileMode.Append); ms.WriteTo(outStream); outStream.Flush(); outStream.Close(); } Question: Any suggestion to make this even faster? I will try to vary the buffer length but in terms of code structure, is this (almost) the fastest? When memorystream is filled up and I am emptying it to the file, what would happen to the new data coming in? Do I need to implement a second buffer to hold that data while I am emptying my first buffer? Or is c# smart enough to figure it out? Thanks for any advice

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  • Python list recursion type error

    - by Jacob J Callahan
    I can't seem to figure out why the following code is giving me a TypeError: 'type' object is not iterable pastebin: http://pastebin.com/VFZYY4v0 def genList(self): #recursively generates a sorted list of child node values numList = [] if self.leftChild != 'none': numList.extend(self.leftChild.genList()) #error numList.extend(list((self.Value,))) if self.rightChild != 'none': numList.extend(self.rightChild.genList()) #error return numList code that adds child nodes (works correctly) def addChild(self, child): #add a child node. working if child.Value < self.Value: if self.leftChild == 'none': self.leftChild = child child.parent = self else: self.leftChild.addChild(child) elif child.Value > self.Value: if self.rightChild == 'none': self.rightChild = child child.parent = self else: self.rightChild.addChild(child) Any help would be appreciated. Full interpreter session: >>> import BinTreeNode as BTN >>> node1 = BTN.BinaryTreeNode(5) >>> node2 = BTN.BinaryTreeNode(2) >>> node3 = BTN.BinaryTreeNode(12) >>> node3 = BTN.BinaryTreeNode(16) >>> node4 = BTN.BinaryTreeNode(4) >>> node5 = BTN.BinaryTreeNode(13) >>> node1.addChild(node2) >>> node1.addChild(node3) >>> node1.addChild(node4) >>> node1.addChild(node5) >>> node4.genList() <class 'list'> >>> node1.genList() Traceback (most recent call last): File "<interactive input>", line 1, in <module> File "C:...\python\BinTreeNode.py", line 47, in genList numList.extend(self.leftChild.genList()) #error File "C:...\python\BinTreeNode.py", line 52, in genList TypeError: 'type' object is not iterable

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  • How do you ensure a mimetype in asp.net?

    - by Sem Dendoncker
    Hello, I have the following code to export a zip file: byte[] buffer = FileUtil.FileToByteArray(zipLocation, true); // push the memory data to the client. _ctx.Response.ContentType = "application/zip"; _ctx.Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", String.Format("map{0}.zip", mapId))); _ctx.Response.BinaryWrite(buffer); This code works great. After every export I get a perfectly made zipfile. The problem however is that when I try to import it, the mimetype sometimes is "application/empty". Now I wonder how can I ensure that the mimetype is always added? Cheers, M.

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  • Upon USB insert, record unique identifer sting, format drive to FAT32 and copy a file. Bash or Pytho

    - by samsixty
    Hello, This is what I want to do, insert USB flash drive. mount it. record uniquie identifer string to a file. format the drive to FAT32. copy a text file to the drive. unmount it. remove the drive. 30 times The situation is this, I have bought 30 usb drives. I need to format each one to ensure they are clean, I need the unique string from each device. I need to put the same txt file on each one. I am not great at writing scripts but can read and follow bash and python. Any pointers would be appreciated.

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  • Java: Writing a DOM to an XML file (formatting issues)

    - by Vhaerun
    I'm using org.w3c XML API to open an existing XML file. I'm removing some nodes , and I'm adding others instead . The problem is that the new nodes that are added are written one after another , with no newline and no indentation what so ever. While it's true that the XML file is valid , it is very hard for a human to examnine it. Is there anyway to add indentation , or at least a newline after each node ?

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  • Problem with underscore(_) in Collections.binarySearch (Java)

    - by Alex Cheng
    Hi all. Problem: I am using Java Tutorials™ sourcecode for this. This is the source code. I tried this: --following with another section of sorted words-- words.add("count"); words.add("cvs"); words.add("dce"); words.add("depth"); --following with another section of sorted words-- and it works perfectly. However when I use this: --just a section of sorted words-- words.add("count"); words.add("cvs"); words.add("dce_iface"); words.add("dce_opnum"); words.add("dce_stub_data"); words.add("depth"); --following with another section of sorted words-- It does show dce_iface when I type dce, but when I type _ then following with o or s it shows me something else like dce_offset where the offset comes from words.add("fragoffset"); somewhere in the list. What can I do to solve this problem? Thank you in advance.

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  • Can you write files in Chrome 8?

    - by greggory.hz
    I'm wondering if, with the new File API exposed in Chrome (I'm not concerned with cross-browser support at this time), it would be possible to write back to files opened via a file input. You can see an example of what I'm trying to accomplish here: http://www.grehz.com/ide. I know I can use server side scripts to dynamically create the files and allow the user to download them normally. I'm hoping that there's a way to accomplish this purely client side. I had read somewhere that you can write to files opened via a file input. I haven't been able to find any examples of this, though I have seen passing references to a FileWriter class. I would be completely not surprised if this wasn't possible though (it seems likely that there are security issues with this). Just looking for some guidance or resources. UPDATE: I was reading here: http://dev.w3.org/2009/dap/file-system/file-writer.html As I was playing around in Chrome, it looks like FileSaver and FileWriter are not implemented, but BlobBuilder is. I can call getBlob() on the BB object, is there any way I can then save that without FileSave or FileWriter?

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  • Insertion into BST without header Node JAVA

    - by Petiatil
    I am working on a recursive insertion method for a BST. This function is suppose to be a recursive helper method and is in a private class called Node. The Node class is in a class called BinarySearchTree which contains an instance variable for the root. When I am trying to insert an element, I get a NullPointerException at : this.left = insert(((Node)left).element); I am unsure about why this occurs. If I understand correctly, in a BST, I am suppose to insert the item at the last spot on the path transversed. Any help is appreciated! private class Node implements BinaryNode<E> { E item; BinaryNode<E> left, right; public BinaryNode<E> insert(E item) { int compare = item.compareTo(((Node)root).item); if(root == null) { root = new Node(); ((Node)root).item = item; } else if(compare < 0) { this.left = insert(((Node)left).item); } else if(compare > 0) { this.right = insert(((Node)right).item); } return root; } }

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  • The internal storage of a DATETIME2 value

    - by Peter Larsson
    Today I went for investigating the internal storage of DATETIME2 datatype. What I found out was that for a datetime2 value with precision 0 (seconds only), SQL Server need 6 bytes to represent the value, but stores 7 bytes. This is because SQL Server add one byte that holds the precision for the datetime2 value. Start with this very simple repro declare @now datetime2(7) = '2010-12-15 21:04:03.6934231'   select  cast(cast(@now as datetime2(0)) as binary(7)),         cast(cast(@now as datetime2(1)) as binary(7)),         cast(cast(@now as datetime2(2)) as binary(7)),         cast(cast(@now as datetime2(3)) as binary(8)),         cast(cast(@now as datetime2(4)) as binary(8)),         cast(cast(@now as datetime2(5)) as binary(9)),         cast(cast(@now as datetime2(6)) as binary(9)),         cast(cast(@now as datetime2(7)) as binary(9)) Now we are going to copy and paste these binary values and investigate which value is representing what time part. Prefix  Ticks       Ticks         Days    Days    Original value ------  ----------  ------------  ------  ------  -------------------- 0x  00  442801             75844  A8330B  734120  0x00442801A8330B 0x  01  A5920B            758437  A8330B  734120  0x01A5920BA8330B  0x  02  71BA73           7584369  A8330B  734120  0x0271BA73A8330B 0x  03  6D488504        75843693  A8330B  734120  0x036D488504A8330B 0x  04  46D4342D       758436934  A8330B  734120  0x0446D4342DA8330B 0x  05  BE4A10C401    7584369342  A8330B  734120  0x05BE4A10C401A8330B 0x  06  6FEBA2A811   75843693423  A8330B  734120  0x066FEBA2A811A8330B 0x  07  57325D96B0  758436934231  A8330B  734120  0x0757325D96B0A8330B Let us use the following color schema Red - Prefix Green - Time part Blue - Day part What you can see is that the date part is equal in all cases, which makes sense since the precision doesm't affect the datepart. What would have been fun, is datetime2(negative) just like round accepts a negative value. -1 would mean rounding to 10 second, -2 rounding to minute, -3 rounding to 10 minutes, -4 rounding to hour and finally -5 rounding to 10 hour. -5 is pretty useless, but if you extend this thinking to -6, -7 and so on, you could actually get a datetime2 value which is accurate to the month only. Well, enough ranting about this. Let's get back to the table above. If you add 75844 second to midnight, you get 21:04:04, which is exactly what you got in the select statement above. And if you look at it, it makes perfect sense that each following value is 10 times greater when the precision is increased one step too. //Peter

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  • The internal storage of a DATETIMEOFFSET value

    - by Peter Larsson
    Today I went for investigating the internal storage of DATETIME2 datatype. What I found out was that for a datetime2 value with precision 0 (seconds only), SQL Server need 6 bytes to represent the value, but stores 7 bytes. This is because SQL Server add one byte that holds the precision for the datetime2 value. Start with this very simple repro declare    @now datetimeoffset(7) = '2010-12-15 21:04:03.6934231 +03:30'   select     cast(cast(@now as datetimeoffset(0)) as binary(9)),            cast(cast(@now as datetimeoffset(1)) as binary(9)),            cast(cast(@now as datetimeoffset(2)) as binary(9)),            cast(cast(@now as datetimeoffset(3)) as binary(10)),            cast(cast(@now as datetimeoffset(4)) as binary(10)),            cast(cast(@now as datetimeoffset(5)) as binary(11)),            cast(cast(@now as datetimeoffset(6)) as binary(11)),            cast(cast(@now as datetimeoffset(7)) as binary(11)) Now we are going to copy and paste these binary values and investigate which value is representing what time part. Prefix  Ticks       Ticks         Days    Days    Suffix  Suffix  Original value ------  ----------  ------------  ------  ------  ------  ------  ------------------------ 0x  00  0CF700             63244  A8330B  734120  D200       210  0x000CF700A8330BD200 0x  01  75A609            632437  A8330B  734120  D200       210 0x0175A609A8330BD200 0x  02  918060           6324369  A8330B  734120  D200       210  0x02918060A8330BD200 0x  03  AD05C503        63243693  A8330B  734120  D200       210  0x03AD05C503A8330BD200 0x  04  C638B225       632502470  A8330B  734120  D200       210  0x04C638B225A8330BD200 0x  05  BE37F67801    6324369342  A8330B  734120  D200       210  0x05BE37F67801A8330BD200 0x  06  6F2D9EB90E   63243693423  A8330B  734120  D200       210  0x066F2D9EB90EA8330BD200 0x  07  57C62D4093  632436934231  A8330B  734120  D200       210  0x0757C62D4093A8330BD200 Let us use the following color schema Red - Prefix Green - Time part Blue - Day part Purple - UTC offset What you can see is that the date part is equal in all cases, which makes sense since the precision doesn't affect the datepart. If you add 63244 seconds to midnight, you get 17:34:04, which is the correct UTC time. So what is stored is the UTC time and the local time can be found by adding "utc offset" minutes. And if you look at it, it makes perfect sense that each following value is 10 times greater when the precision is increased one step too. //Peter

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