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  • Require extended permissions in FBML pyfacebook app

    - by jlpp
    I'm trying to get my FBML canvas page to automatically prompt new app users for permission to publish_stream. Following Facebook's documentation I tried using the required_permissions argument to require_login. That is, I tried to use the pyfacebook require_login decorator like this: @facebook.require_login(required_permissions='publish_stream') as in: @decorator_from_middleware(FacebookMiddleware) @facebook.require_login(required_permissions='publish_stream') def canvas(request, template): ... Requesting extended permissions in a pyfacebook-based Facebook iFrame app has been discussed. Requesting extended permissions in an FBML app too. My objective is to require extended permissions in an FBML app. Am I missing something or can anyone suggest a workaround? Thanks.

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  • gunicorn + django + nginx unix://socket failed (11: Resource temporarily unavailable)

    - by user1068118
    Running very high volume traffic on these servers configured with django, gunicorn, supervisor and nginx. But a lot of times I tend to see 502 errors. So I checked the nginx logs to see what error and this is what is recorded: [error] 2388#0: *208027 connect() to unix:/tmp/gunicorn-ourapp.socket failed (11: Resource temporarily unavailable) while connecting to upstream Can anyone help debug what might be causing this to happen? This is our nginx configuration: sendfile on; tcp_nopush on; tcp_nodelay off; listen 80 default_server; server_name imp.ourapp.com; access_log /mnt/ebs/nginx-log/ourapp-access.log; error_log /mnt/ebs/nginx-log/ourapp-error.log; charset utf-8; keepalive_timeout 60; client_max_body_size 8m; gzip_types text/plain text/xml text/css application/javascript application/x-javascript application/json; location / { proxy_pass http://unix:/tmp/gunicorn-ourapp.socket; proxy_pass_request_headers on; proxy_read_timeout 600s; proxy_connect_timeout 600s; proxy_redirect http://localhost/ http://imp.ourapp.com/; #proxy_set_header Host $host; #proxy_set_header X-Real-IP $remote_addr; #proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; #proxy_set_header X-Forwarded-Proto $my_scheme; #proxy_set_header X-Forwarded-Ssl $my_ssl; } We have configure Django to run in Gunicorn as a generic WSGI application. Supervisord is used to launch the gunicorn workers: home/user/virtenv/bin/python2.7 /home/user/virtenv/bin/gunicorn --config /home/user/shared/etc/gunicorn.conf.py daggr.wsgi:application This is what the gunicorn.conf.py looks like: import multiprocessing bind = 'unix:/tmp/gunicorn-ourapp.socket' workers = multiprocessing.cpu_count() * 3 + 1 timeout = 600 graceful_timeout = 40 Does anyone know where I can start digging to see what might be causing the problem? This is what my ulimit -a output looks like on the server: core file size (blocks, -c) 0 data seg size (kbytes, -d) unlimited scheduling priority (-e) 0 file size (blocks, -f) unlimited pending signals (-i) 59481 max locked memory (kbytes, -l) 64 max memory size (kbytes, -m) unlimited open files (-n) 50000 pipe size (512 bytes, -p) 8 POSIX message queues (bytes, -q) 819200 real-time priority (-r) 0 stack size (kbytes, -s) 8192 cpu time (seconds, -t) unlimited max user processes (-u) 1024 virtual memory (kbytes, -v) unlimited file locks (-x) unlimited

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  • nginx+django serving static files

    - by avalore
    I have followed instruction for setting up django with nginx from the django wiki (https://code.djangoproject.com/wiki/DjangoAndNginx) and have nginx setup as follows (a few name changes to fit my setup). user nginx nginx; worker_processes 2; error_log /var/log/nginx/error_log info; events { worker_connections 1024; use epoll; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] ' '"$request" $status $bytes_sent ' '"$http_referer" "$http_user_agent" ' '"$gzip_ratio"'; client_header_timeout 10m; client_body_timeout 10m; send_timeout 10m; connection_pool_size 256; client_header_buffer_size 1k; large_client_header_buffers 4 2k; request_pool_size 4k; gzip on; gzip_min_length 1100; gzip_buffers 4 8k; gzip_types text/plain; output_buffers 1 32k; postpone_output 1460; sendfile on; tcp_nopush on; tcp_nodelay on; keepalive_timeout 75 20; ignore_invalid_headers on; index index.html; server { listen 80; server_name localhost; location /static/ { root /srv/static/; } location ~* ^.+\.(jpg|jpeg|gif|png|ico|css|zip|tgz|gz|rar|bz2|doc|xls|exe|pdf|ppt|txt|tar|mid|midi|wav|bmp|rtf|js|mov) { access_log off; expires 30d; } location / { # host and port to fastcgi server fastcgi_pass 127.0.0.1:8080; fastcgi_param PATH_INFO $fastcgi_script_name; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param QUERY_STRING $query_string; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; fastcgi_pass_header Authorization; fastcgi_intercept_errors off; fastcgi_param REMOTE_ADDR $remote_addr; } access_log /var/log/nginx/localhost.access_log main; error_log /var/log/nginx/localhost.error_log; } } Static files aren't being served (nginx 404). If I look in the access log it seems nginx is looking in /etc/nginx/html/static... rather than /srv/static/ as specified in the config. I've no clue why it's doing this, any help would be hugely appreciated.

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  • Request data from database using Django

    - by user21901
    I have somehow two variables for example x and y. I have also made a model with 3 fields (longitude,latitude,name) and have it activated in mysql database. I need to send these two variables(x,y) to the django server so as to search if there is an object with longitude=x and latitude=y.If there is one i want to get back it's name. How can i do this?

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  • Do all Mac OS X applications require Admin permissions to 'install'?

    - by Andy
    I'm new to the whole Mac OS X operating system. I'm trying to learn and I've got myself a MacBook running Mac OS X 10.7.3. I've created a test user that can not administrate so that I can test out permissions and I've found that I can not do anything in the Applications folder, which includes 'installing' applications (even those drag 'n' drop ones) and creating folders, without entering an Admin name and password. However, I was under the impression that this wasn't the case and you only needed Admin permissions to write to somewhere like Preferences, so can somebody please clarify why it is asking for Admin when I try to drag 'n' drop applications into the Applications folder.

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  • OSX Reset Home Permissions and ACLs - how long should it take?

    - by andyface
    Having screwwed up my permissions by trying to have two users accessing one home folder I'm now going through the process of reseting my main user home permissions via the OSX install disk utilities, which seems to be taking a while. Does this process take a while to do, though I assume it depends on how many files I have in the folder, which in my case is a good few 100 GBs. At what point should I be concerned that it may have got stuck and thus reset my computer and try again? I assume, though not sure that if the little circle indicator is still moving then it's not completely frozen, but as there's no progress bar or details I'm not sure how true that is.

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  • How do I set permissions structure for multiple users editing multiple sites in /var/www on Ubuntu 9

    - by Michael T. Smith
    I'm setting up an Ubuntu server that will have 3 or 4 VirtualHosts that I want users to be able to work in (add new files, edit old files, etc.). I currently plan on storing the sites in /var/www but wouldn't be opposed to moving it. I know how to add new users, I know how to add new groups. I'm unsure of the best way to handle users being only able to edit some sites. I read over the answers here in this question, so I was thinking I could setup a group and add users to that group, but then they'd all have essentially the same permissions. Am I just going to have to assign each user specific permissions? Or is there a better way of handling this? Added: I should also note, that I'll have each user login in via SSH/sFTP. The users would never need to do anything else on the server.

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  • Is a reboot required to refresh permissions after adding a user to a new group?

    - by Michael Prescott
    On ubuntu server, I've noticed more than once now that after adding a user to a group that user doesn't have group permissions until I reboot the system. For example: User 'hudson' needs permission to read directory 'root:shadow /etc/shadow' So I add hudson to the shadow group. hudson still cannot read. So, I 'sudo shutdown -h -r now' and when the system comes up again user hudson can read. Is a reboot required or is there a better way to get permissions applied after adding the user to the group?

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  • changing permissions for a network share takes longer on win2008 than on win2003, why is that?

    - by HugoRune
    Given a network share accessible for "everyone" in the domain, containing several 1000 files and folders When I change permissions for this share from read/write to only read (or vice versa) on windows 2003, the change takes effect instantly. When I do the same on a share on Windows 2008, the dialog stays open for a long time before closing when I click on OK, and the server appears to be accessing a lot of files. What is the reason for this delay? Does Windows 2008 also change ntfs permissions for all files inside the share? If so, why doesn't win2003 have to do that? I do not mind the delay, after all I do not have to change this stuff very often, but I am curious. What are the differences between 2003 and 2008 in this regard?

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  • OS X - Automatically Set Execute Permissions for New Files?

    - by i help X u
    I'm using OS X 10.6.4 and am trying to set a folder to automatically enable execute permissions on new script files copied or created in a directory. I have used Sandbox 2 to set every permission for the folder to enabled with sticky bits and the inherit flag set but I still have to manually set the execute flag using chmod for every new flag. I've done: chmod -R a+rwxs ~/scripts I've done: chmod 7777 ~/scripts And the permissions for the folder show as: drwsrwsrwt+ for the folder. But if I add a new script file it's set to "-rw-r--r--+" (the default) I looked at setting "unmask 000" in the .profile file but the default value for files is 666 with an unmask of 022 so that's not relevant since I would need a default value of 777 for files. I have figure out how to use chmod in an AppleScript triggered by a folder action to automate this but I'm wondering if there is a simple ACL or chmod setting I'm missing. So, is there a way to automatically set execute permission for new files? (Without using a folder action and AppleScript?)

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  • How to remove file permissions from an external hard drive?

    - by user2540416
    My macbook recently died and I am currently trying to figure out how to copy my data. What I did was, I took out the hard drive, put it in an enclosure and plugged it in to my other laptop that runs linux. The problem is, I cannot copy files from the hard drive due to file permissions. I tried to access the hard drive as root. But I still cannot copy files. How do I remove file permissions from the harddrive?

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  • How to configure permissions for win2008 task running as Network Service to stop/start a service on different system?

    - by weiji
    Well... title says it all, actually. We've got a Scheduled Task set up on a windows server 2003 box running as the Network Service, and the batch file it runs will invoke "sc" to stop and then start a service on another windows box, however sc reports: [SC] OpenService FAILED 5: Access is denied. Running the same batch file via the windows explorer has no issues, and my user account is part of the Administrators group so I believe this is why there are no issues when I try it manually. Is this a permissions thing I enable for Network Service on the first server? Or do I enable permissions for Network Service somehow on the target server? This question (http://serverfault.com/questions/19382/why-sc-query-fails-from-one-machine-but-works-from-another) touches on something similar, but I'm looking for enabling the Network Service to access the service via the scheduled task.

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  • How to build a Django form which requires a delay to be re-submitted ?

    - by pierre-guillaume-degans
    Hey, In order to avoid spamming, I would like to add a waiting time to re-submit a form (i.e. the user should wait a few seconds to submit the form, except the first time that this form is submitted). To do that, I added a timestamp to my form (and a security_hash field containing the timestamp plus the settings.SECRET_KEY which ensures that the timestamp is not fiddled with). This look like: class MyForm(forms.Form): timestamp = forms.IntegerField(widget=forms.HiddenInput) security_hash = forms.CharField(min_length=40, max_length=40, widget=forms.HiddenInput) # + some other fields.. # + methods to build the hash and to clean the timestamp... # (it is based on django.contrib.comments.forms.CommentSecurityForm) def clean_timestamp(self): """Make sure the delay is over (5 seconds).""" ts = self.cleaned_data["timestamp"] if not time.time() - ts > 5: raise forms.ValidationError("Timestamp check failed") return ts # etc... This works fine. However there is still an issue: the timestamp is checked the first time the form is submitted by the user, and I need to avoid this. Any idea to fix it ? Thank you ! :-)

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  • How do I relate two models/tables in Django based on non primary non unique keys?

    - by wizard
    I've got two tables that I need to relate on a single field po_num. The data is imported from another source so while I have a little bit of control over what the tables look like but I can't change them too much. What I want to do is relate these two models so I can look up one from the other based on the po_num fields. What I really need to do is join the two tables so I can do a where on a count of the related table. I would like to do filter for all Order objects that have 0 related EDI856 objects. I tried adding a foreign key to the Order model and specified the db_column and to_fields as po_num but django didn't like that the fact that Edi856.po_num wasn't unique. Here are the important fields of my current models that let me display but not filter for the data that I want. class Edi856(models.Model): po_num = models.CharField(max_length=90, db_index=True ) class Order(models.Model): po_num = models.CharField(max_length=90, db_index=True) def in_edi(self): '''Has the edi been processed?''' return Edi856.objects.filter(po_num = self.po_num).count() Thanks for taking the time to read about my problem. I'm not sure what to do from here.

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  • What kind of data do I pass into a Django Model.save() method?

    - by poswald
    Lets say that we are getting POSTed a form like this in Django: rate=10 items= [23,12,31,52,83,34] The items are primary keys of an Item model. I have a bunch of business logic that will run and create more items based on this data, the results of some db lookups, and some business logic. I want to put that logic into a save signal or an overridden Model.save() method of another model (let's call it Inventory). The business logic will run when I create a new Inventory object using this form data. Inventory will look like this: class Inventory(models.Model): picked_items = models.ManyToManyField(Item, related_name="items_picked_set") calculated_items = models.ManyToManyField(Item, related_name="items_calculated_set") rate = models.DecimalField() ... other fields here ... New calculated_items will be created based on the passed in items which will be stored as picked_items. My question is this: is it better for the save() method on this model to accept: the request object (I don't really like this coupling) the form data as arguments or kwargs (a list of primary keys and the other form fields) a list of Items (The caller form or view will lookup the list of Items and create a list as well as pass in the other form fields) some other approach? I know this is a bit subjective, but I was wondering what the general idea is. I've looked through a lot of code but I'm having a hard time finding a pattern I like.

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  • Django app that can provide user friendly, multiple / mass file upload functionality to other apps

    - by hopla
    Hi, I'm going to be honest: this is a question I asked on the Django-Users mailinglist last week. Since I didn't get any replies there yet, I'm reposting it on Stack Overflow in the hope that it gets more attention here. I want to create an app that makes it easy to do user friendly, multiple / mass file upload in your own apps. With user friendly I mean upload like Gmail, Flickr, ... where the user can select multiple files at once in the browse file dialog. The files are then uploaded sequentially or in parallel and a nice overview of the selected files is shown on the page with a progress bar next to them. A 'Cancel' upload button is also a possible option. All that niceness is usually solved by using a Flash object. Complete solutions are out there for the client side, like: SWFUpload http://swfupload.org/ , FancyUpload http://digitarald.de/project/fancyupload/ , YUI 2 Uploader http://developer.yahoo.com/yui/uploader/ and probably many more. Ofcourse the trick is getting those solutions integrated in your project. Especially in a framework like Django, double so if you want it to be reusable. So, I have a few ideas, but I'm neither an expert on Django nor on Flash based upload solutions. I'll share my ideas here in the hope of getting some feedback from more knowledgeable and experienced people. (Or even just some 'I want this too!' replies :) ) You will notice that I make a few assumptions: this is to keep the (initial) scope of the application under control. These assumptions are of course debatable: All right, my idea's so far: If you want to mass upload multiple files, you are going to have a model to contain each file in. I.e. the model will contain one FileField or one ImageField. Models with multiple (but ofcourse finite) amount of FileFields/ ImageFields are not in need of easy mass uploading imho: if you have a model with 100 FileFields you are doing something wrong :) Examples where you would want my envisioned kind of mass upload: An app that has just one model 'Brochure' with a file field, a title field (dynamically created from the filename) and a date_added field. A photo gallery app with models 'Gallery' and 'Photo'. You pick a Gallery to add pictures to, upload the pictures and new Photo objects are created and foreign keys set to the chosen Gallery. It would be nice to be able to configure or extend the app for your favorite Flash upload solution. We can pick one of the three above as a default, but implement the app so that people can easily add additional implementations (kinda like Django can use multiple databases). Let it be agnostic to any particular client side solution. If we need to pick one to start with, maybe pick the one with the smallest footprint? (smallest download of client side stuff) The Flash based solutions asynchronously (and either sequentially or in parallel) POST the files to a url. I suggest that url to be local to our generic app (so it's the same for every app where you use our app in). That url will go to a view provided by our generic app. The view will do the following: create a new model instance, add the file, OPTIONALLY DO EXTRA STUFF and save the instance. DO EXTRA STUFF is code that the app that uses our app wants to run. It doesn't have to provide any extra code, if the model has just a FileField/ImageField the standard view code will do the job. But most app will want to do extra stuff I think, like filling in the other fields: title, date_added, foreignkeys, manytomany, ... I have not yet thought about a mechanism for DO EXTRA STUFF. Just wrapping the generic app view came to mind, but that is not developer friendly, since you would have to write your own url pattern and your own view. Then you have to tell the Flash solutions to use a new url etc... I think something like signals could be used here? Forms/Admin: I'm still very sketchy on how all this could best be integrated in the Admin or generic Django forms/widgets/... (and this is were my lack of Django experience shows): In the case of the Gallery/Photo app: You could provide a mass Photo upload widget on the Gallery detail form. But what if the Gallery instance is not saved yet? The file upload view won't be able to set the foreignkeys on the Photo instances. I see that the auth app, when you create a user, first asks for username and password and only then provides you with a bigger form to fill in emailadres, pick roles etc. We could do something like that. In the case of an app with just one model: How do you provide a form in the Django admin to do your mass upload? You can't do it with the detail form of your model, that's just for one model instance. There's probably dozens more questions that need to be answered before I can even start on this app. So please tell me what you think! Give me input! What do you like? What not? What would you do different? Is this idea solid? Where is it not? Thank you!

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  • Implementing a popularity algorithm in Django

    - by TheLizardKing
    I am creating a site similar to reddit and hacker news that has a database of links and votes. I am implementing hacker news' popularity algorithm and things are going pretty swimmingly until it comes to actually gathering up these links and displaying them. The algorithm is simple: Y Combinator's Hacker News: Popularity = (p - 1) / (t + 2)^1.5` Votes divided by age factor. Where` p : votes (points) from users. t : time since submission in hours. p is subtracted by 1 to negate submitter's vote. Age factor is (time since submission in hours plus two) to the power of 1.5.factor is (time since submission in hours plus two) to the power of 1.5. I asked a very similar question over yonder http://stackoverflow.com/questions/1964395/complex-ordering-in-django but instead of contemplating my options I choose one and tried to make it work because that's how I did it with PHP/MySQL but I now know Django does things a lot differently. My models look something (exactly) like this class Link(models.Model): category = models.ForeignKey(Category) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add = True) modified = models.DateTimeField(auto_now = True) fame = models.PositiveIntegerField(default = 1) title = models.CharField(max_length = 256) url = models.URLField(max_length = 2048) def __unicode__(self): return self.title class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add = True) modified = models.DateTimeField(auto_now = True) karma_delta = models.SmallIntegerField() def __unicode__(self): return str(self.karma_delta) and my view: def index(request): popular_links = Link.objects.select_related().annotate(karma_total = Sum('vote__karma_delta')) return render_to_response('links/index.html', {'links': popular_links}) Now from my previous question, I am trying to implement the algorithm using the sorting function. An answer from that question seems to think I should put the algorithm in the select and sort then. I am going to paginate these results so I don't think I can do the sorting in python without grabbing everything. Any suggestions on how I could efficiently do this? EDIT This isn't working yet but I think it's a step in the right direction: from django.shortcuts import render_to_response from linkett.apps.links.models import * def index(request): popular_links = Link.objects.select_related() popular_links = popular_links.extra( select = { 'karma_total': 'SUM(vote.karma_delta)', 'popularity': '(karma_total - 1) / POW(2, 1.5)', }, order_by = ['-popularity'] ) return render_to_response('links/index.html', {'links': popular_links}) This errors out into: Caught an exception while rendering: column "karma_total" does not exist LINE 1: SELECT ((karma_total - 1) / POW(2, 1.5)) AS "popularity", (S... EDIT 2 Better error? TemplateSyntaxError: Caught an exception while rendering: missing FROM-clause entry for table "vote" LINE 1: SELECT ((vote.karma_total - 1) / POW(2, 1.5)) AS "popularity... My index.html is simply: {% block content %} {% for link in links %} karma-up {{ link.karma_total }} karma-down {{ link.title }} Posted by {{ link.user }} to {{ link.category }} at {{ link.created }} {% empty %} No Links {% endfor %} {% endblock content %} EDIT 3 So very close! Again, all these answers are great but I am concentrating on a particular one because I feel it works best for my situation. from django.db.models import Sum from django.shortcuts import render_to_response from linkett.apps.links.models import * def index(request): popular_links = Link.objects.select_related().extra( select = { 'popularity': '(SUM(links_vote.karma_delta) - 1) / POW(2, 1.5)', }, tables = ['links_link', 'links_vote'], order_by = ['-popularity'], ) return render_to_response('links/test.html', {'links': popular_links}) Running this I am presented with an error hating on my lack of group by values. Specifically: TemplateSyntaxError at / Caught an exception while rendering: column "links_link.id" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: ...karma_delta) - 1) / POW(2, 1.5)) AS "popularity", "links_lin... Not sure why my links_link.id wouldn't be in my group by but I am not sure how to alter my group by, django usually does that.

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  • List of Django model instance foreign keys losing consistency during state changes.

    - by Joshua
    I have model, Match, with two foreign keys: class Match(model.Model): winner = models.ForeignKey(Player) loser = models.ForeignKey(Player) When I loop over Match I find that each model instance uses a unique object for the foreign key. This ends up biting me because it introduces inconsistency, here is an example: >>> def print_elo(match_list): ... for match in match_list: ... print match.winner.id, match.winner.elo ... print match.loser.id, match.loser.elo ... >>> print_elo(teacher_match_list) 4 1192.0000000000 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 >>> teacher_match_list[0].winner.elo = 3000 >>> print_elo(teacher_match_list) 4 3000 # Object 4 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 # Object 4 >>> I solved this problem like so: def unify_refrences(match_list): """Makes each unique refrence to a model instance non-unique. In cases where multiple model instances are being used django creates a new object for each model instance, even if it that means creating the same instance twice. If one of these objects has its state changed any other object refrencing the same model instance will not be updated. This method ensure that state changes are seen. It makes sure that variables which hold objects pointing to the same model all hold the same object. Visually this means that a list of [var1, var2] whose internals look like so: var1 --> object1 --> model1 var2 --> object2 --> model1 Will result in the internals being changed so that: var1 --> object1 --> model1 var2 ------^ """ match_dict = {} for match in match_list: try: match.winner = match_dict[match.winner.id] except KeyError: match_dict[match.winner.id] = match.winner try: match.loser = match_dict[match.loser.id] except KeyError: match_dict[match.loser.id] = match.loser My question: Is there a way to solve the problem more elegantly through the use of QuerySets without needing to call save at any point? If not, I'd like to make the solution more generic: how can you get a list of the foreign keys on a model instance or do you have a better generic solution to my problem? Please correct me if you think I don't understand why this is happening.

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  • django image upload forms

    - by gramware
    I am having problems with django forms and image uploads. I have googled, read the documentations and even questions ere, but cant figure out the issue. Here are my files my models class UserProfile(User): """user with app settings. """ DESIGNATION_CHOICES=( ('ADM', 'Administrator'), ('OFF', 'Club Official'), ('MEM', 'Ordinary Member'), ) onames = models.CharField(max_length=30, blank=True) phoneNumber = models.CharField(max_length=15) regNo = models.CharField(max_length=15) designation = models.CharField(max_length=3,choices=DESIGNATION_CHOICES) image = models.ImageField(max_length=100,upload_to='photos/%Y/%m/%d', blank=True, null=True) course = models.CharField(max_length=30, blank=True, null=True) timezone = models.CharField(max_length=50, default='Africa/Nairobi') smsCom = models.BooleanField() mailCom = models.BooleanField() fbCom = models.BooleanField() objects = UserManager() #def __unicode__(self): # return '%s %s ' % (User.Username, User.is_staff) def get_absolute_url(self): return u'%s%s/%s' % (settings.MEDIA_URL, settings.ATTACHMENT_FOLDER, self.id) def get_download_url(self): return u'%s%s/%s' % (settings.MEDIA_URL, settings.ATTACHMENT_FOLDER, self.name) ... class reports(models.Model): repID = models.AutoField(primary_key=True) repSubject = models.CharField(max_length=100) repRecepients = models.ManyToManyField(UserProfile) repPoster = models.ForeignKey(UserProfile,related_name='repposter') repDescription = models.TextField() repPubAccess = models.BooleanField() repDate = models.DateField() report = models.FileField(max_length=200,upload_to='files/%Y/%m/%d' ) deleted = models.BooleanField() def __unicode__(self): return u'%s ' % (self.repSubject) my forms from django import forms from django.http import HttpResponse from cms.models import * from django.contrib.sessions.models import Session from django.forms.extras.widgets import SelectDateWidget class UserProfileForm(forms.ModelForm): class Meta: model= UserProfile exclude = ('designation','password','is_staff', 'is_active','is_superuser','last_login','date_joined','user_permissions','groups') ... class reportsForm(forms.ModelForm): repPoster = forms.ModelChoiceField(queryset=UserProfile.objects.all(), widget=forms.HiddenInput()) repDescription = forms.CharField(widget=forms.Textarea(attrs={'cols':'50', 'rows':'5'}),label='Enter Report Description here') repDate = forms.DateField(widget=SelectDateWidget()) class Meta: model = reports exclude = ('deleted') my views @login_required def reports_media(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) if request.user.is_staff== True: repmedform = reportsForm(request.POST, request.FILES) if repmedform.is_valid(): repmedform.save() repmedform = reportsForm(initial = {'repPoster':user.id,}) else: repmedform = reportsForm(initial = {'repPoster':user.id,}) return render_to_response('staffrepmedia.html', {'repfrm':repmedform, 'rep_media': reports.objects.all()}) else: return render_to_response('reports_&_media.html', {'rep_media': reports.objects.all()}) ... @login_required def settingchng(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) form = UserProfileForm(instance = user) if request.method == 'POST': form = UserProfileForm(request.POST, request.FILES, instance = user) if form.is_valid(): form.save() return HttpResponseRedirect('/settings/') else: form = UserProfileForm(instance = user) if request.user.is_staff== True: return render_to_response('staffsettingschange.html', {'form': form}) else: return render_to_response('settingschange.html', {'form': form}) ... @login_required def useradd(request): if request.method == 'POST': form = UserAddForm(request.POST,request.FILES ) if form.is_valid(): password = request.POST['password'] request.POST['password'] = set_password(password) form.save() else: form = UserAddForm() return render_to_response('staffadduser.html', {'form':form}) Example of my templates {% if form.errors %} <ol> {% for field in form %} <H3 class="title"> <p class="error"> {% if field.errors %}<li>{{ field.errors|striptags }}</li>{% endif %}</p> </H3> {% endfor %} </ol> {% endif %} <form method="post" id="form" action="" enctype="multipart/form-data" class="infotabs accfrm"> {{ repfrm.as_p }} <input type="submit" value="Submit" /> </form>

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  • Installation requirements of django installing in hostgator dedicated server

    - by jaypabs
    First, before I install OSQA on my dedicated server at hostgator, I want to know the requirements. I don't want to screw up my server so it's better to ask question first. I have read a lot of tutorial on the internet regarding Django but I want to clarify something before I proceed. On my dedicated server I don't use FCGI. Instead I use Mod SuPHP. A lot of tutorial is talking about installing python using FCGI. My question is if it is safe to install Python if I'm using SuPHP? Is it safe to use the tutorial on this link: http://wiki.osqa.net/display/docs/Installing+OSQA+on+CentOS6?focusedCommentId=4784144 Thanks in advance for your help.

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  • CentOS 6.5 as WebServer for Django Dev

    - by Charlesliam
    During CentOS 6.5 Installation I choose WebServer type for this computer. The server has a static IP address 192.168.111.100. The CentOS was updated I managed to install virtualenv with Python 2.7. Within the virtualenv, I'll be using Django Framework. After I tried to run the command using root user python manage.py runserver 0.0.0.0:8000 I can't see the website from other computer within the LAN when I try to type 192.168.111.100:8000/admin on my browser. I already disable firewall using service iptables stop I can ping the 192.168.111.100 and I have a good feedback with nslookup. What seems the problem of my config?

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