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  • sort given set of colors in VIBGYOR order

    - by Vijay Selvaraj
    Hi, how do i order a given set of colors from the rainbow in VIBGYOR order. say i input the seven colors in the following order { red, blue, green, yellow, indigo, violet, orange} and i should print the output as {violet, indigo, blue, green, yellow, orange, red}, irrespective of the order i give the output should be as above. Can someone suggest me about implementing this in java program? Thanks, -Vijay

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  • How to group items by date range in XSLT?

    - by glenatron
    I have a bunch of data that looks a little like this: <item> <colour>Red</colour> <date_created>2009-10-10 12:01:55</date_created> <date_sold>2009-10-20 22:32:12</date_sold> </item> <item> <colour>Blue</colour> <date_created>2009-11-01 13:21:00</date_created> <date_sold>2009-11-21 12:32:12</date_sold> </item> <item> <colour>Blue</colour> <date_created>2009-10-29 21:23:02</date_created> <date_sold>2009-10-20 02:02:22</date_sold> </item> <item> <colour>Red</colour> <date_created>2009-11-02 09:11:51</date_created> <date_sold>2009-11-20 09:15:53</date_sold> </item> <item> <colour>Red</colour> <date_created>2009-10-18 11:00:55</date_created> <date_sold>2009-10-20 11:12:22</date_sold> </item> Now what I would like to be able to do is to run that through an XSLT stylesheet such that I get ouput looking like this: Colour | In stock 1 week | In stock 2 weeks | In stock 3 weeks Red | 1 | 3 | 2 Blue | 0 | 2 | 1 Currently I have a stylesheet that uses basic muenchian grouping to show that 30% of stock was Red and 70% blue, but I can't see a way to find the number of nodes withing a given date range. Is there a way to use keys to select a range? Do I need to create some kind of intermediate data node? Is there a different route that shows I'm barking up the wrong tree with both those suggestions? Is this even possible with XSLT or do I need to find a way to change the data source?

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  • Having to hit the site login button twice after first turning on computer

    - by John
    Hello, The code below is for a login that I'm using. It works fine, but when I first try logging in after turning on my computer, it only works the second time that I hit the "Login" button. Any idea how I can make it not require hitting the "Login" button twice in this situation? Thanks in advance, John function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; } if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; } EDIT: Here is another function that is used. function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; }

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  • Any Name Entity Recognition - web services available

    - by Gublooo
    Hello I wanted to know if there are any paid or free named entity recognition web services available. Basically I'm looking for something - where if I pass a text like: "John had french fries at Burger King" It should be identify - something along the lines: Person: John Organization: Burger King I've heard of Annie from GATE - but I dont think it has a web service available. Thanks

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  • Positioning Text Triggered by a Function

    - by John
    Hello, I would like the text below classed with "logintocomment" to appear 30 px below the bottom of the table classed with "commentecho." Instead, with the CSS and code below, the text classed with "logintocomment" is appearing at the bottom of the browser window. Any idea how I can make it do what I want? Thanks in advance, John In index file: include "comments.php"; include "commentformonoff.php"; In the file comments.php: echo "<table class=\"commentecho\">"; The file: commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } ?> The CSS: table.commentecho { margin-top: 230px; margin-left: 30px; text-align: left; font-family: "Times New Roman", Times, serif; font-weight: normal; font-size: 15px; color: #000000; width: 600px; table-layout:fixed; background-color: #FFFFFF; border: 2px #FFFFFF; border-collapse: collapse; border-spacing: 2px; padding: 1px; text-decoration: none; vertical-align: text-bottom; margin-bottom: 30px; } table.commentecho td { border: 2px solid #fff; text-align: left; height: 18px; overflow:hidden; } table.commentecho td a{ padding: 2px; color: #000000; text-decoration: none; overflow:hidden; height: 18px; } table.commentecho td a:hover{ background-color: #FFFFFF; padding: 2px; color: #FF0000; text-decoration: none; overflow:hidden; height: 18px; } .logintocomment { margin-top: 30px; margin-left: 30px; width:250px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 20px; color:#000000; }

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  • How to find index of an object by key and value in an javascript array

    - by return1.at
    Given: var peoples = [ { "attr1": "bob", "attr2": "pizza" }, { "attr1": "john", "attr2": "sushi" }, { "attr1": "larry", "attr2": "hummus" } ]; Wanted: Index of object where attr === value for example attr1 === "john" or attr2 === "hummus" Update: Please, read my question carefully, i do not want to find the object via $.inArray nor i want to get the value of a specific object attribute. Please consider this for your answers. Thanks!

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  • Get list of duplicate rows in MySql

    - by user347033
    Hi, i have a table like this ID nachname vorname 1 john doe 2 john doe 3 jim doe 4 Michael Knight I need a query that will return all the fields (select *) from the records that have the same nachname and vorname (in this case, records 1 and 2). Can anyone help me with this? Thanks

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  • Need help with SQL Query

    - by StackOverflowNewbie
    Say I have 2 tables: Person - Id - Name PersonAttribute - Id - PersonId - Name - Value Further, let's say that each person had 2 attributes (say, gender and age). A sample record would be like this: Person->Id = 1 Person->Name = 'John Doe' PersonAttribute->Id = 1 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Gender' PersonAttribute->Value = 'Male' PersonAttribute->Id = 2 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Age' PersonAttribute->Value = '30' Question: how do I query this such that I get a result like this: 'John Doe', 'Male', '30'

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  • Trying to style the first tbody different than others without introducing another class.

    - by mwiik
    I have a table with multiple tbody's, each of which has a classed row, and I want it so that the classed row in the first tbody has style differences, but am unable to get tbody:first-child to work in any browser. Perhaps I am missing something, or maybe there is a workaround. Ideally, I would like to provide the programmers with a single tbody section they can use as a template, but will otherwise have to add a class to the first tbody, making for an extra test in the programming. The html is straightforward: <tbody class="subGroup"> <tr class="subGroupHeader"> <th colspan="8">All Grades: Special Education</th> <td class="grid" colspan="2"><!-- contains AMO line --></td> <td><!-- right 100 --></td> </tr> <tr>...</tr> <!-- several more rows of data --> </tbody> There are several tbody's per table. I want to style the th and td's within tr.subGroupHeader in the very first tbody differently than the rest. Just to illustrate, I want to add a border-top to the tr.subGroupHeader cells. The tr.subGroupHeader will be styled with a border-top, such as: table.databargraph.continued tr.subGroupHeader th, table.databargraph.continued tr.subGroupHeader td { border-top: 6px solid red; } For the first tbody, I am trying: table.databargraph.continued tbody:first-child tr.subGroupHeader th { border-top: 6px solid blue ; } However, this doesn't seem to work in any browser (I've tested in Safari, Opera, Firefox, and PrinceXML, all on my Mac) Curiously, the usually excellent Xyle Scope tool indicates that the blue border should be taking precedence, though it obviously is not. See the screenshot at http://s3.amazonaws.com/ember/kUD8DHrz06xowTBK3qpB2biPJrLWTZCP_o.png This screenshot shows (top left) the American Indian th is selected, and (bottom right), shows (via black instead of gray text for the css declaration), that, indeed, the blue border should be given precedence. Yet the border is red. I may be missing something fundamental, like pseudo-classes not working for tbodys at all... This really only needs to work in PrinceXML, and maybe Safari so I can see what I'm doing with webkit-based css tools. Note I did try a selector like tr.subGroupHeader:first-child, but such tr's apparently consider the tbody the parent (as I would suspect), thus made every border blue. Thanks...

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  • Using GET Method to Maintain Variables After Logging In

    - by John
    Hello, I am using a login system. When I navigate to comments/index.php without logging in, some variables get passed along using the GET method just fine. Then, if I log in while I am on this page, these variables disappear. The variables that disappear are $submission, $submissionid, and $url. I thought I could use the GET method to keep them live after logging in by appending ?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.' to the URL of the login form action as seen below. But the variables still disappeared after I made this addition. The relevant code I am trying to use is below. Any idea what I can do to make it do what I want? Thanks in advance, John In comments/index.php: require_once "header.php"; include "login.php"; include "comments.php"; In login.php: if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } In comments.php: $url = mysql_real_escape_string($_GET['url']); echo '<div class="subcommenttitle"><a href="http://www.'.$url.'">'.$submission.'</a></div>'; $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); The login function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • Can Ejabberd Support Offline File Transfer?

    - by user359277
    Hi, I am working on a xmpp client, using eJabberd as server. My question is How can I support offline file transferring? I only want to do the offline file transferring for Image file. For example, I can transfer an image to John even he is offline. When John come back Online, the server will send him the image. How can I do that? Thanks

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  • Passing Variables Along in a Function

    - by John
    Hello, In the function show_commentbox() below, I would like to pass along the variables $_SESSION['loginid'], $submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl. With the setup below, it's not working. How could I change it to make show_commentbox() pass the variables along? Thanks in advance, John index.php: <?php $submission = $_GET['submission']; require_once "header.php"; include "login.php"; include "comments.php"; include "commentformonoff.php"; ?> In header.php: require_once ("function.inc.php"); In comments.php: $uid = $_SESSION['loginid']; $submissiondate = mysql_real_escape_string($_GET['submissiondate']); $submittor = mysql_real_escape_string($_GET['submittor']); $countcomments = mysql_real_escape_string($_GET['countcomments']); $dispurl = mysql_real_escape_string($_GET['dispurl']); $url = mysql_real_escape_string($_GET['url']); $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox(); } else { echo "Login to comment"; } } else { echo "Login to comment"; } } else { show_commentbox(); } ?> In display.functions.inc.php: function show_commentbox() { echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; }

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  • Document-oriented database - What if the document definitions change?

    - by Sebastian Hoitz
    As I understand it, you can enter any non-structured information into a document-oriented database. Let's imagine a document like this: { name: 'John Blank', yearOfBirth: 1960 } Later, in a new version, this structure is refactored to { firstname: 'John', lastname: 'Blank', yearOfBirth: 1960 } How do you do this with Document-Oriented databases? Do you have to prepare merge-scripts, that alter all your entries in the database? Or are there better ways you can handle changes in the structure?

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  • Converting OpenGL co-ordinates to lower UIView (and UIImagePickerController)

    - by John Qualis
    Hi, I am new to OpenGL over iPhone. I am developing an iPhone app similar to a barcode reader but with an extra OpenGL layer. The bottommost layer is UIImagePickerController, then I use UIView on top and draw a rectangle at certain co-ordinates on the iphone screen. So far everything is OK. Then I am trying to draw an OpenGL 3-D model in that rectangle. I am able to load a 3-D model in the iPhone based on this code here - http://iphonedevelopment.blogspot.com/2008/12/start-of-wavefront-obj-file-loader.html I am not able to transform the co-ordinates of the rectangle into OpenGL co-ordinates. Appreciate any help. Do I need to use a matrix to translate the currentPosition of the 3-D model so it is drawn within myRect? The code is given below.. Appreciate any help/pointers in this regards. John -(void)setupView:(GLView*)view { const GLfloat zNear = 0.01, zFar = 1000.0, fieldOfView = 45.0; GLfloat size; glEnable(GL_DEPTH_TEST); glMatrixMode(GL_PROJECTION); size = zNear * tanf(DEGREES_TO_RADIANS(fieldOfView) / 2.0); CGRect rect = view.bounds; glFrustumf(-size, size, -size / (rect.size.width / rect.size.height), size / (rect.size.width / rect.size.height), zNear, zFar); glViewport(0, 0, rect.size.width, rect.size.height); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); glClearColor(0.0f, 0.0f, 0.0f, 0.0f); NSString *path = [[NSBundle mainBundle] pathForResource:@"plane" ofType:@"obj"]; OpenGLWaveFrontObject *theObject = [[OpenGLWaveFrontObject alloc] initWithPath:path]; Vertex3D position; position.z = -8.0; position.y = 3.0; position.x = 2.0; theObject.currentPosition = position; self.plane = theObject; [theObject release]; } (void)drawView:(GLView*)view; { static GLfloat rotation = 0.0; glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glLoadIdentity(); glColor4f(0.0, 0.5, 1.0, 1.0); // the coordinates of the rectangle are // myRect.x, myRect.y, myRect.width, myRect.height // Do I need to use a matrix to translate the currentPosition of the // 3-D model so it is drawn within myRect? //glOrthof(-160.0f, 160.0f, -240.0f, 240.0f, -1.0f, 1.0f); [plane drawSelf]; }

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  • How to recreate the UITabBarItem image filter?

    - by boliva
    Hi, I'm writing a custom UITabBar replacement, and I would like to know how to recreate the filter that the built-in implementation does with the UITabBarItem image - that blue shining on selected tabs and gray gradient on unselected ones. I guess it's a matter of using the source image alpha value as a mask and overlay it with a pre-made blue (or whatever color) shining image and another one grayed out, but I would like to know what is the best approach from a code point of view. Best,

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  • CSS: remove stubborn underline from link

    - by dmr
    I am attempting to have a link show up in white, without an underline. The text color shows up correctly as white, but the blue underline is stubbornly persisting. I tried text-decoration: none; and text-decoration: none !important; in the CSS to remove the link underline. Neither worked. How can I remove the blue underline from the link?

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  • How to order by last name on a full name column?

    - by GateKiller
    I have a SQL Table with a column called FullName which contains, for example, "John Smith". How can order the data by the last name that appears in the FullName column? For a long name like "Laurence John Fishburne", I would like to order the data by the word "Fishburne". Thus, names are stored in the order First Name Middle Names Last Name I am using Microsoft SQL Server 2005.

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  • How can I use a php array in a mysql search query?

    - by ThinkingInBits
    I was going to use the scuttle solution on: http://www.pui.ch/phred/archives/2005/04/tags-database-schemas.html for handling searches on my website. I was wondering how I could take the search input from a user and turn it into a single query. For instance, let's say a user inputted 'blue dogs' in their search query... How could I dynamically update the query to include ('blue', 'dogs') in union and intersection queries?

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  • Making a Login Work After Cache, Cookies, etc. Have Been Cleared

    - by John
    Hello, I am using the code below for a user login. The first I try to login after cache / cookies, etc. have been cleared, the browser refreshes and the user name is not logged in. After that, logging in works fine. Any idea how I can make it work the first time? Thanks in advance, John index.php: <?php if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../index.php?username='.$username.'&password='.$password.'');} require_once "header.php"; include "login.php"; require_once "footer.php"; ?> login.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?> show_loginform function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?'.$_SERVER['QUERY_STRING'].'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/.../register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/.../lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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