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• Best practices for (over)using Azure queues

  - by John

  Hi, I'm in the early phases of designing an Azure-based application. One of the things that attracts me to Azure is the scalability, given the variability of the demand I'm likely to expect. As such I'm trying to keep things loosely coupled so I can add instances when I need to. The recommendations I've seen for architecting an application for Azure include keeping web role logic to a minimum, and having processing done in worker roles, using queues to communicate and some sort of back-end store like SQL Azure or Azure Tables. This seems like a good idea to me as I can scale up either or both parts of the application without any issue. However I'm curious if there are any best practices (or if anyone has any experiences) for when it's best to just have the web role talk directly to the data store vs. sending data by the queue? I'm thinking of the case where I have a simple insert to do from the web role - while I could set this up as a message, send it on the queue, and have a worker role pick it up and do the insert, it seems like a lot of double-handling. However I also appreciate that it may be the case that this is better in the long run, in case the web role gets overwhelmed or more complex logic ends up being required for the insert. I realise this might be a case where the answer is "it depends entirely on the situation, check your perf metrics" - but if anyone has any thoughts I'd be very appreciative! Thanks John

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• Making a Function-Activated Link Appear Without Having to Refresh Browser

  - by John

  Hello, I'm trying to use the code below to make the <a href='http://www...com/.../footervote.php'>Vote</a> link appear if a user logs in and a user shows up in the function getEditorsList(). The vote link only appears if the browser is refreshed. Any idea how I could make the vote link appear without having to refresh the browser? Thanks in advance, John index.php: <?php require_once "header.php"; //content include "login.php"; // more content require_once "footer.php"; ?> In header.php: <?php error_reporting(0); session_start(); require_once ('db_connect.inc.php'); require_once ("function.inc.php"); $seed="0dAfghRqSTgx"; $domain = "...com"; $editors = getEditorsList(); foreach($editors as $editor) { $editorids[] = $editor['loginid']; } if(in_array($_SESSION['loginid'], $editorids)) { echo "<div class='footervote'><a href='http://www...com/.../footervote.php'>Vote</a></div>"; } ?> login.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?>

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• Join with Three Tables

  - by John

  Hello, In MySQL, I am using the following three tables (their fields are listed after their titles): comment: commentid loginid submissionid comment datecommented login: loginid username password email actcode disabled activated created points submission: submissionid loginid title url displayurl datesubmitted I would like to display "datecommented" and "comment" for a given "username," where "username" equals a variable called $profile. I would also like to make the "comment" a hyperlink to http://www...com/.../comments/index.php?submission='.$rowc["title"].'&submissionid='.$rowc["submissionid"].'&url='.$rowc["url"].'&countcomments='.$rowc["countComments"].'&submittor='.$rowc["username"].'&submissiondate='.$rowc["datesubmitted"].'&dispurl='.$rowc["displayurl"].' where countComments equals COUNT(c.commentid) and $rowc is part of the query listed below. I tried using the code below to do what I want, but it didn't work. How could I change it to make it do what I want? Thanks in advance, John $sqlStrc = "SELECT s.loginid ,s.title ,s.url ,s.displayurl ,s.datesubmitted ,l.username ,l.loginid ,s.title ,s.submissionid ,c.comment ,c.datecommented ,COUNT(c.commentid) countComments FROM submission s INNER JOIN login l ON s.loginid = l.loginid LEFT OUTER JOIN comment c ON c.loginid = l.loginid WHERE l.username = '$profile' GROUP BY c.loginid ORDER BY s.datecommented DESC LIMIT 10"; $resultc = mysql_query($sqlStrc); $arrc = array(); echo "<table class=\"samplesrec1c\">"; while ($rowc = mysql_fetch_array($resultc)) { $dtc = new DateTime($rowc["datecommented"], $tzFromc); $dtc->setTimezone($tzToc); echo '<tr>'; echo '<td class="sitename3c">'.$dtc->format('F j, Y &\nb\sp &\nb\sp g:i a').'</a></td>'; echo '<td class="sitename1c"><a href="http://www...com/.../comments/index.php?submission='.$rowc["title"].'&submissionid='.$rowc["submissionid"].'&url='.$rowc["url"].'&countcomments='.$rowc["countComments"].'&submittor='.$rowc["username"].'&submissiondate='.$rowc["datesubmitted"].'&dispurl='.$rowc["displayurl"].'">'.stripslashes($rowc["comment"]).'</a></td>'; echo '</tr>'; } echo "</table>";

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• In Silverlight 3 how can I get the call to HtmlPage.Plugin.SetStyleAttribute() call to call other co

  - by John Rennemeyer

  I'm trying to take a snapshot of my Silverlight control using WriteableBitmap and it works fine, however, it only takes a snapshot of what is showing. I'm trying to resize the Silverlight control so it will show everything and then take a screenshot, however, the code doesn't resize the control until after the code after the call all runs which is the snapshot code... I can get this work using a timer to fire the snapshot after the other code has caused the resize but I'm wondering if there is a better way. The HtmlPage.Plugin.SetStyleAttribute call has to be called from the UI thread so I'm assuming that's where the problem is. The fact that it is being dispatched onto the UI thread while the rest of the code is not and so the other code is being run first. Is there anyway to create a new event or attach to the call to determine when it has been run to then fire off my snapshot code? I have the following code: private void btnTakeSnapshot_Click(object sender, System.Windows.RoutedEventArgs e) { if (CurrentContractAction != null) { string heightBefore = HtmlPage.Plugin.GetStyleAttribute("height"); HtmlPage.Plugin.SetStyleAttribute("height", string.Format("{0}px", "1800")); //this line doesn't change the height until after the "TakeSnapshot" code is run for some reason, I'm thinking it is because it is most likely dispatched to the UI thread :( and the following code is not run on the UI thread Snapshot snapshot = new Snapshot(string.Format("Action_Schedule_{0}", CurrentContractAction.Title), LayoutRoot, LayoutRoot, busyIndicatorDataGrid); snapshot.HideElements(btnViewGanttChart, btnSave, btnEditAction, btnFullScreen, btnTakeSnapshot, btnLockAndSubmit); snapshot.TakeSnapshot(); snapshot.ResetElementsVisibility(); HtmlPage.Plugin.SetStyleAttribute("height", string.Format("{0}px", heightBefore)); } } Thanks, John

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• In Ruby or Python can the very idea of Class be rewritten?

  - by John Berryman

  Howdy All... first time at stack overflow. I'm looking into using some of the metaprogramming features provided by Ruby or Python, but first I need to know the extent to which they will allow me to extend the language. The main thing I need to be able to do is to rewrite the concept of Class. This doesn't mean that I want to rewrite a specific class during run time, but rather I want to make my own conceptualization of what a Class is. To be a smidge more specific here, I want to make something that is like what people normally call a Class, but I want to follow an "open world" assumption. In the "closed world" of normal Classes, if I declare Poodle to be a subclass of Dog to be a subclass of Animal, then I know that Poodle is not going to also be a type of FurCoat. However, in an open world Class, then the Poodle object I've defined may or may not be and object of type FurCoat and we won't know for sure until I explain that I can wear the poodle. (Poor poodle.) This all has to do with a study I'm doing concerning OWL ontologies. Just so you know, I've tried to find information online, but due to the overloading of terms here I haven't found anything helpful. Super thanks, John

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• Positioning a Comment Input Field

  - by John

  Hello, What is a good way to give the input field below the three characteristics listed? Characteristics: -Always 30 px from the left side of the browser window. -Always 30 px below the words "Add a comment" if no comments have been added. -Always 30 px below the preceding comment if one or more comment has been added. Thanks in advance, John HTML / PHP Code: <div class="addacomment"><label for="title">Add a comment:</label></div> <div class="commentbox"><input class="commentsubfield" name="title" type="title" id="title" maxlength="1000"></div> CSS (thusfar I have no declarations for the "commentbox" selector): .commentsubfield { width: 390px; height: 90px; border: 1px solid #999999; padding: 5px; } .addacomment { position:absolute; width:250px; left:30px; top:180px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; }

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• Using a Form With Variables as Part of a Function

  - by John

  Hello, Could the form below be part of a function? I am wondering if it might not be able to be part of a function since it has variables. Thanks in advance, John echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> ';

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• Creating a Variable From Two Others

  - by John

  Hello, In the HTML table below, I would like to add a third column that equals $row["countSubmissions"] times 10 plus $row["countComments"]. How could I do this? Thanks in advance, John $sqlStr = "SELECT l.loginid, l.username, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY countSubmissions DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.stripslashes($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.stripslashes($row["countComments"]).'</td>'; echo '</tr>'; } echo "</table>";

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• Insert names into table if not already existing

  - by John

  I am trying to build an application that allows users to submit names to be added to a db table (runningList). Before the name is added tho, I would like to check firstname and lastname against another table (controlList). It must exist in (controlList) or reply name not valid. If the name is valid I would like to then check firstname and lastname against (runningList) it make sure it isnt already there. If it isnt there, then insert firstname & lastname. If it is there, reply name already used. Below is code that worked before I tried to add the test against the controlList, I somehow broke it altogether while trying to add the extra step. if (mysql_num_rows(mysql_query('SELECT * FROM runninglist WHERE firstname=\'' .$firstname . '\' AND lastname=\'' . $lastname . '\' LIMIT 1')) == 0) { $sql="INSERT INTO runninglist (firstname, lastname) VALUES ('$_POST[firstname]','$_POST[lastname]')"; } else { echo "This name has been used."; } Any direction would be appreciated. Thanx John

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• Apache2, FastCGI, PHP-FPM, APC on virtualmin panel with nginx front end reverse proxy

  - by Ünsal Korkmaz

  My dream setup: php 5.3.6 + mysql 5.5.10 on Apache2, FastCGI, PHP-FPM, APC with nginx 1.0 front end reverse proxy. And as free server management panel: Virtualmin GPL on centos 5.6 In a new centos 5.6 setup. Using this code for installing virtualmin: wget http://software.virtualmin.com/gpl/scripts/install.sh chmod +x install.sh ./install.sh After setup, i see php is 5.1 and mysql is 5.0 version. And system not supporting php-fpm but supporting fcgid wrapper. I did following changes: wget http://dl.iuscommunity.org/pub/ius/stable/Redhat/5/x86_64/ius-release-1.0-6.ius.el5.noarch.rpm wget http://dl.iuscommunity.org/pub/ius/stable/Redhat/5/x86_64/epel-release-1-1.ius.el5.noarch.rpm rpm -Uvh ius-release*.rpm epel-release*.rpm yum install yum-plugin-replace yum remove mysql.i386 yum replace mysql --replace-with mysql55 service mysqld restart chkconfig mysqld on mysql_upgrade --password=1234 yum replace php --replace-with php53u yum install php53u-fpm php53u-pecl-apc service httpd restart chkconfig php-fpm on service php-fpm start I am not sure why virtualmin installing both mysql.i386 and 64 bit version together but needed to remove one of them for using yum replace. So i had php 5.3.6 + mysql 5.5.10 with PHP-FPM, APC installed. But virtualmin not supporting PHP-FPM + fastcgi and its still running on fcgid. I am ultra newbie on server management so i couldnt find workaround after this. I want to switch fcgid wrapper to PHP-FPM + fastcgi at least for 1 virtual server. And if i can find a fix for this section, i want to setup nginx 1.0 as front end reverse proxy for serving static files and passing php files to apache. http://nginxcp.com/ is what i want but its for cpanel.

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• Where is vmlinux on my Ubuntu installation?

  - by Jason Baker

  I'm trying to work with starting up oprofile, and I'm running into a problem at this step: opcontrol --vmlinux=/path/to/vmlinux Ubuntu has no package called vmlinux, and when I do a locate vmlinux, I get a lot of files: /usr/src/linux-headers-2.6.28-14/arch/h8300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-14/arch/m68k/kernel/vmlinux-std.lds /usr/src/linux-headers-2.6.28-14/arch/m68k/kernel/vmlinux-sun3.lds /usr/src/linux-headers-2.6.28-14/arch/mn10300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-14/arch/sh/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-14/arch/x86/boot/compressed/vmlinux_32.lds /usr/src/linux-headers-2.6.28-14/arch/x86/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-14/include/asm-generic/vmlinux.lds.h /usr/src/linux-headers-2.6.28-15/arch/h8300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-15/arch/m68k/kernel/vmlinux-std.lds /usr/src/linux-headers-2.6.28-15/arch/m68k/kernel/vmlinux-sun3.lds /usr/src/linux-headers-2.6.28-15/arch/mn10300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-15/arch/sh/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-15/arch/x86/boot/compressed/vmlinux_32.lds /usr/src/linux-headers-2.6.28-15/arch/x86/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-15/include/asm-generic/vmlinux.lds.h /usr/src/linux-headers-2.6.28-16/arch/h8300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-16/arch/m68k/kernel/vmlinux-std.lds /usr/src/linux-headers-2.6.28-16/arch/m68k/kernel/vmlinux-sun3.lds /usr/src/linux-headers-2.6.28-16/arch/mn10300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-16/arch/sh/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-16/arch/x86/boot/compressed/vmlinux_32.lds /usr/src/linux-headers-2.6.28-16/arch/x86/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-16/include/asm-generic/vmlinux.lds.h Which one of these is the one I'm looking for?

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• Access Control Lists in Debian Lenny

  - by arbales

  So, for my clients to who have sites hosted on my server, I create user accounts, with standard home folders inside /home. I setup an SSH jail for all the collective users, because I really am against using a separate FTP server. Then, I installed ACL and added acl to my /etc/fstab — all good. I cd into /home and chmod 700 ./*. At this point users cannot see into other users home directories (yay), but apache can't see them either (boo) . I ran setfacl u:www-data:rx ./*. I also tried individual directories. Now apache can see the sites again, but so can all the users. ACL changed the permissions of the home folders to 750. How do I setup ACL's so that Apache can see the sites hosted in user's home folders AND 2. Users can't see outside their home and into others' files. Edit: more details: Output after chmod -R 700 ./* sh-3.2# chmod 700 ./* sh-3.2# ls -l total 72 drwx------+ 24 austin austin 4096 Jul 31 06:13 austin drwx------+ 8 jeremy collective 4096 Aug 3 03:22 jeremy drwx------+ 12 josh collective 4096 Jul 26 02:40 josh drwx------+ 8 joyce collective 4096 Jun 30 06:32 joyce (Not accessible to others users OR apache) setfacl -m u:www-data:rx jeremy (Now accessible to members apache and collective — why collective, too?) sh-3.2# getfacl jeremy # file: jeremy # owner: jeremy # group: collective user::rwx user:www-data:r-x group::r-x mask::r-x other::--- Solution Ultimately what I did was: chmod 755 * setfacl -R -m g::--- * setfacl -R -m u:www-data:rx *

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• mdadm cron job sends email that cron has run

  - by Andrew

  I've got an Ubuntu 8.04 server using mdadm to create several RAID1 arrays. I created /etc/cron.hourly/mdadm as follows: #! /bin/sh set -e mdadm --monitor /dev/md0 /dev/md3 /dev/md4 --oneshot (Yes, the array numbers are not sequential, and I'm not using --scan beacuse I have a degraded array that may or may not have been used as swap and I can't delete, but I think that's a separate issue. If it's the underlying cause of this, I need to fix it.) mdadm sends me email (configured in the /etc/mdadm/mdadm.conf) on DegradedArray etc. events. This is the desired behaviour. What is not desired, and I can't work out, is why cron is sending me (relatively pointless) emails, via an alias in /etc/aliases: From: root@<hostname> (Cron Daemon) To: root@<hostname> Subject: Cron <root@<hostname>> cd / && run-parts --report /etc/cron.hourly Content-Type: text/plain; charset=ANSI_X3.4-1968 X-Cron-Env: <SHELL=/bin/sh> X-Cron-Env: <PATH=/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin> X-Cron-Env: <HOME=/root> X-Cron-Env: <LOGNAME=root> Message-Id: <id@hostname> Date: Fri, 7 May 2010 13:17:01 +0930 (CST) /etc/cron.hourly/mdadm: mdadm: Monitor using email address "<root_alias@domain>" from config file I've got a dozen other servers behaving correctly (mdadm sends email, cron doesnt') with identical /etc/crontab files: # /etc/crontab: system-wide crontab # <snip comments> SHELL=/bin/sh PATH=/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin # m h dom mon dow user command 17 * * * * root cd / && run-parts --report /etc/cron.hourly <snip anacron jobs> Should I simply remove the --report, or is there something else in my cron config somewhere causing this?

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• How can I make Mac OS X Address Book display a person’s home address from an LDAP server?

  - by Arcturus

  Hi, (I've posted this question on Stack Overflow first, but someone told me it belonged here.) I have a custom LDAP server, which I can customize to generate whichever object class and attributes I need. I'm trying to display people from that server in the Mac OS X address book. Names and organizations display correctly, as well as work-related phone and address. However, I've never been able to have a home address displayed in the address book. This is an example of output from running a ldapsearch: # extended LDIF # # LDAPv3 # base <dc=example,dc=com> with scope subtree # filter: (givenName=Joh*) # requesting: ALL # # 10041, example.com dn: uid=10041,dc=example,dc=com objectclass: top objectclass: person objectclass: organizationalPerson objectclass: inetOrgPerson objectclass: mozillaOrgPerson uid: 10041 cn: John Doe givenName: John sn: Doe o: Acme telephoneNumber: 500 00 00 mobile: 500 00 00 mail: john[email protected] street: Baker St postalCode: 10098 l: New York c: US homePostalAddress: White St mozillaHomePostalCode: 10098 mozillaHomeLocalityName: New York mozillaHomeCountryName: US # search result search: 2 result: 0 Success # numResponses: 2 # numEntries: 1 Every piece of information shows up in the address book up to here: homePostalAddress: White St mozillaHomePostalCode: 10098 mozillaHomeLocalityName: New York mozillaHomeCountryName: US Which object class or attribute name should I use to have the home address show up in the Mac OS X address book?

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• Use an environment variable in a launchd script

  - by sirlancelot

  I'm curious if it's possible to specify an envrionment variable in the ProgramArguments portion of a luanchd script on Mac OS X Leopard. <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd"> <plist version="1.0"> <dict> <key>Label</key> <string>me.mpietz.MountDevRoot</string> <key>ProgramArguments</key> <array> <string>/bin/sh</string> <string>$HOME/bin/attach-devroot.sh</string> <!-- Instead of using... <string>/Users/mpietz/bin/attach-devroot.sh</string --> </array> <key>RunAtLoad</key> <true/> </dict> </plist>

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• Startup script for Red5 on Ubuntu 9.04

  - by user49249

  I am creating startup script for Red5 on Ubuntu. Red5 is installed in /opt/red5 Following is a working script on a CentOS Box on which Red5 is running [code] ==========Start init script ========== #!/bin/sh PROG=red5 RED5_HOME=/opt/red5/dist DAEMON=$RED5_HOME/$PROG.sh PIDFILE=/var/run/$PROG.pid # Source function library . /etc/rc.d/init.d/functions [ -r /etc/sysconfig/red5 ] && . /etc/sysconfig/red5 RETVAL=0 case "$1" in start) echo -n $"Starting $PROG: " cd $RED5_HOME $DAEMON >/dev/null 2>/dev/null & RETVAL=$? if [ $RETVAL -eq 0 ]; then echo $! > $PIDFILE touch /var/lock/subsys/$PROG fi [ $RETVAL -eq 0 ] && success $"$PROG startup" || failure $"$PROG startup" echo ;; stop) echo -n $"Shutting down $PROG: " killproc -p $PIDFILE RETVAL=$? echo [ $RETVAL -eq 0 ] && rm -f /var/lock/subsys/$PROG ;; restart) $0 stop $0 start ;; status) status $PROG -p $PIDFILE RETVAL=$? ;; *) echo $"Usage: $0 {start|stop|restart|status}" RETVAL=1 esac exit $RETVAL [/code] What do I need to replace for Ubuntu in the above script. My Red5 is in /opt/red5/ and to start it manually I always do /opt/red5/dist/red5.sh from Ubuntu As I did not find rc.d/functions on Ubuntu on my laptop also /etc/init.d/functions I did not existed. I would like to be able to use them with service as Red hat distributions do. I checked /lib/lsb/init-functions.

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• Where is vmlinux on my Ubuntu installation?

  - by Jason Baker

  I'm trying to work with starting up oprofile, and I'm running into a problem at this step: opcontrol --vmlinux=/path/to/vmlinux Ubuntu has no package called vmlinux, and when I do a locate vmlinux, I get a lot of files: /usr/src/linux-headers-2.6.28-14/arch/h8300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-14/arch/m68k/kernel/vmlinux-std.lds /usr/src/linux-headers-2.6.28-14/arch/m68k/kernel/vmlinux-sun3.lds /usr/src/linux-headers-2.6.28-14/arch/mn10300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-14/arch/sh/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-14/arch/x86/boot/compressed/vmlinux_32.lds /usr/src/linux-headers-2.6.28-14/arch/x86/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-14/include/asm-generic/vmlinux.lds.h /usr/src/linux-headers-2.6.28-15/arch/h8300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-15/arch/m68k/kernel/vmlinux-std.lds /usr/src/linux-headers-2.6.28-15/arch/m68k/kernel/vmlinux-sun3.lds /usr/src/linux-headers-2.6.28-15/arch/mn10300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-15/arch/sh/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-15/arch/x86/boot/compressed/vmlinux_32.lds /usr/src/linux-headers-2.6.28-15/arch/x86/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-15/include/asm-generic/vmlinux.lds.h /usr/src/linux-headers-2.6.28-16/arch/h8300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-16/arch/m68k/kernel/vmlinux-std.lds /usr/src/linux-headers-2.6.28-16/arch/m68k/kernel/vmlinux-sun3.lds /usr/src/linux-headers-2.6.28-16/arch/mn10300/boot/compressed/vmlinux.lds /usr/src/linux-headers-2.6.28-16/arch/sh/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-16/arch/x86/boot/compressed/vmlinux_32.lds /usr/src/linux-headers-2.6.28-16/arch/x86/boot/compressed/vmlinux_64.lds /usr/src/linux-headers-2.6.28-16/include/asm-generic/vmlinux.lds.h Which one of these is the one I'm looking for?

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• Linux group permissions getting overwritten by owner

  - by Andy

  I am not a user of Linux, but I am encountering some permissions problems with it that I hope someone can shed some light on. Bit of background: A colleague of mine has a Linux box (running Debian I believe) with an SVN repository on it. The repository directory and files 'owner' is my colleauge. We are both members of a group called 'users'. He manages several projects both Linux and Windows apps, while I have one Windows app. For the Windows apps, we both use TortoiseSVN via an SSH link to commit/update. Performing the command 'ls -l' shows the repository files and folders on the Linux box to have the following permissions: -rwxrwx--- john users However, when my colleauge commits to the repository, the permissions change to: -rwxrwx--- john john This then means I get 'Permission denied' when trying to access the repository myself as it appears that the group permissions have been overwritten with only 'owner' permissions. To fix this, a 'chown -R' command is applied to the files/folders to set the permissions back to owner/group, but each time he writes to the repository, the issue repeats. I'm not sure if this is solely an SVN problem, or a more fundamental owner/group issue. Anyone any clue on how to stop this happening, or where to go and look? I'm trying to help out my colleague who is having some trouble resolving this issue. Apologies for the vague info, I hope I have conveyed the problem clear enough. Like I say, I am not a Linux user, I have only put down what I have managed to pick up from looking over his shoulder. Thanks for any pointers I can pass on!

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• Monit - script not being executed as expected

  - by Thaís

  I'm working on a Windows 7 machine, having a VM for Ubuntu (image disk: 12.04-desktop-i386.iso). On the VM I installed Monit 5.3.2, and configured some processes and applications. So I created a script to run my application. This application should display some content on the screen (Im basically displaying two images, using Feh). The thing is: if I call my script through the command line, it runs ok, and display the images. But if I run through monit, it seems to be running ok, but it doesn't display the images.In the case I try to debug it (remote debug), then I can see the images. So I was supposing this could be some kind of configuration, but didn't find out what (even using the option -I wou'ldn't work). I"m showing below more details: -Piece of script on Monit---- check program runMediaHandler with path "/usr/bin/runMediaHandler.sh" if status == 1 then alert -runMediaHandler.sh ---- #!/bin/bash java -jar /home/thais/Desktop/MediaHandler_RC2.jar Summarizing: 1.What works: if I run java directly: java -jar /home/thais/Desktop/MediaHandler_RC2.jar if I run the script directly: runMediaHandler.sh if I remote debug putting a breakpoint where the image should be displayed 2.What does not work: putting that piece of information on Monit to "check program", writen above (even if calling monit -I start runMediaHandler) Thank you in advance, Thaís

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• Cisco ASA5505 won't sync with NTP

  - by Martijn Heemels

  Today I noticed that the clock my Cisco ASA 5505 firewall was running about 15 minutes late, which surprised me since I've set up the NTP client. My two NTP servers 10.10.0.1 and 10.10.0.2 are virtualized Windows Server 2008 R2 domain controllers, and both have the correct time. As shown below, the ASA knows about the two servers, can ping them and seems to poll them periodically, so I suppose it can reach them both. The ASA claims its time source is NTP, however the clock is unsynchronized. Neither host is marked as synced. Result of the command: "ping 10.10.0.1" Type escape sequence to abort. Sending 5, 100-byte ICMP Echos to 10.10.0.1, timeout is 2 seconds: !!!!! Success rate is 100 percent (5/5), round-trip min/avg/max = 1/1/1 ms Result of the command: "sh ntp ass" address ref clock st when poll reach delay offset disp ~10.10.0.1 .LOCL. 1 78 1024 377 0.5 643.69 17.0 ~10.10.0.2 10.10.0.1 2 190 1024 377 0.9 655.91 58.4 * master (synced), # master (unsynced), + selected, - candidate, ~ configured Result of the command: "sh ntp stat" Clock is unsynchronized, stratum 16, no reference clock nominal freq is 99.9984 Hz, actual freq is 99.9984 Hz, precision is 2**6 reference time is 00000000.00000000 (07:28:16.000 CEST Thu Feb 7 2036) clock offset is 0.0000 msec, root delay is 0.00 msec root dispersion is 0.00 msec, peer dispersion is 0.00 msec Result of the command: "sh clock detail" 10:33:23.769 CEDT Tue Jun 26 2012 Time source is NTP UTC time is: 08:33:23 UTC Tue Jun 26 2012 Summer time starts 02:00:00 CEST Sun Mar 25 2012 Summer time ends 03:00:00 CEDT Sun Oct 28 2012 I've tried the basic steps of manually setting the time and removing and adding the timeservers, to no avail. My ASA's ntp config is simply: ntp server 10.10.0.1 ntp server 10.10.0.2 Do I need to enable authentication to use a Windows NTP server? Any thoughts?

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• Installing Tomcat on CentOS 5

  - by andybaird

  Disclaimer: I am not a server admin, I am a windows user that has lead a life of sinful installation wizards and drag and drop I'm attempting to install Tomcat on CentOS 5 hosted by a MediaTemple dedicated virtual server. I basically followed this guide: Installed jpackage and configured the yum.repo.d jpackage file to set enabled=1 Used yum to install java (yum install java) Downloaded the binary distribution of tomcat with "wget http://archive.apache.org/dist/tomcat/tomcat-6/v6.0.14/bin/apache-tomcat-6.0.14.tar.gz" set JAVA_HOME to point at the jdk location I found with "export JAVA_HOME=/usr/lib/jvm/java-1.6.0-openjdk-1.6.0.0/" I gunzip/untar the Tomcat files and run ./startup.sh to start the Tomcat server. That is supposed to put the Tomcat server at myserver.com:8080 - however, I just get a could not contact host error when I try to browse to it (or when I try 'curl localhost:8080' from SSH) After I type ./startup.sh, here is the console output: [root@myserver bin]# ./startup.sh Using CATALINA_BASE: /root/apache-tomcat-6.0.14 Using CATALINA_HOME: /root/apache-tomcat-6.0.14 Using CATALINA_TMPDIR: /root/apache-tomcat-6.0.14/temp Using JRE_HOME: /usr/lib/jvm/java-1.6.0-openjdk-1.6.0.0/ [root@myserver bin]# Is there a step I have missed here? Edit: I've now discovered by looking at the log the following error is occuring: Error occurred during initialization of VM Could not reserve enough space for object heap

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• How to stop Cron from sending messages about errors

  - by Beck

  I have this strange mails comming from cron: Return-Path: <[email protected]> Delivered-To: [email protected] Received: by domain.com (Postfix, from userid 0) id 6F944264D0; Mon, 10 Jan 2011 10:35:01 +0000 (UTC) From: [email protected] (Cron Daemon) To: [email protected] Subject: Cron <root@domain> lynx -dump http://www.domain.com/cron/realqueue Content-Type: text/plain; charset=ANSI_X3.4-1968 X-Cron-Env: <SHELL=/bin/sh> X-Cron-Env: <PATH=/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin> X-Cron-Env: <HOME=/root> X-Cron-Env: <LOGNAME=root> Message-Id: <[email protected]> Date: Mon, 10 Jan 2011 10:35:01 +0000 (UTC) /bin/sh: lynx: not found I have this cron settings in crontab file: SHELL=/bin/sh PATH=/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin */5 * * * * lynx -dump http://www.domain.com/cron/realqueue 17 * * * * root cd / && run-parts --report /etc/cron.hourly 25 6 * * * root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.daily ) 47 6 * * 7 root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.weekly ) 52 6 1 * * root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.monthly ) Lynx is installed on my Ubuntu as well. Ofc in place of domain.com is my domain, just replaced. Thanks ;)

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• How to populate RRD database with CPU and MEM usage data?

  - by Tomaszs

  I have a Lighttpd server (on Centos) and would like to display 4 graphs: lighttpd traffic, lighttpd requests per second, CPU usage and MEM usage. I've set place for rrd database for lighttpd config like this: rrdtool.binary = "/usr/bin/rrdtool" rrdtool.db-name = "/var/www/lighttpd.rrd" And put into my WWW cgi-bin sh file that gets data from lighttpd RRD file and creates graphs of traffic and requests per second like this: #!/bin/sh RRDTOOL=/usr/bin/rrdtool OUTDIR=//var/www/graphs INFILE=/var/www/lighttpd.rrd OUTPRE=lighttpd-traffic WIDTH=400 HEIGHT=100 DISP="-v bytes --title TrafficWebserver \ DEF:binraw=$INFILE:InOctets:AVERAGE \ DEF:binmaxraw=$INFILE:InOctets:MAX \ DEF:binminraw=$INFILE:InOctets:MIN \ DEF:bout=$INFILE:OutOctets:AVERAGE \ DEF:boutmax=$INFILE:OutOctets:MAX \ DEF:boutmin=$INFILE:OutOctets:MIN \ CDEF:bin=binraw,-1,* \ CDEF:binmax=binmaxraw,-1,* \ CDEF:binmin=binminraw,-1,* \ CDEF:binminmax=binmaxraw,binminraw,- \ CDEF:boutminmax=boutmax,boutmin,- \ AREA:binmin#ffffff: \ STACK:binmax#f00000: \ LINE1:binmin#a0a0a0: \ LINE1:binmax#a0a0a0: \ LINE2:bin#efb71d:incoming \ GPRINT:bin:MIN:%.2lf \ GPRINT:bin:AVERAGE:%.2lf \ GPRINT:bin:MAX:%.2lf \ AREA:boutmin#ffffff: \ STACK:boutminmax#00f000: \ LINE1:boutmin#a0a0a0: \ LINE1:boutmax#a0a0a0: \ LINE2:bout#a0a735:outgoing \ GPRINT:bout:MIN:%.2lf \ GPRINT:bout:AVERAGE:%.2lf \ GPRINT:bout:MAX:%.2lf \ " $RRDTOOL graph $OUTDIR/$OUTPRE-hour.png -a PNG --start -14400 $DISP -w $WIDTH -h $HEIGHT $RRDTOOL graph $OUTDIR/$OUTPRE-day.png -a PNG --start -86400 $DISP -w $WIDTH -h $HEIGHT $RRDTOOL graph $OUTDIR/$OUTPRE-month.png -a PNG --start -2592000 $DISP -w $WIDTH -h $HEIGHT OUTPRE=lighttpd-requests DISP="-v req --title RequestsperSecond -u 1 \ DEF:req=$INFILE:Requests:AVERAGE \ DEF:reqmax=$INFILE:Requests:MAX \ DEF:reqmin=$INFILE:Requests:MIN \ CDEF:reqminmax=reqmax,reqmin,- \ AREA:reqmin#ffffff: \ STACK:reqminmax#00f000: \ LINE1:reqmin#a0a0a0: \ LINE1:reqmax#a0a0a0: \ LINE2:req#00a735:requests" $RRDTOOL graph $OUTDIR/$OUTPRE-hour.png -a PNG --start -14400 $DISP -w $WIDTH -h $HEIGHT $RRDTOOL graph $OUTDIR/$OUTPRE-day.png -a PNG --start -86400 $DISP -w $WIDTH -h $HEIGHT $RRDTOOL graph $OUTDIR/$OUTPRE-month.png -a PNG --start -2592000 $DISP -w $WIDTH -h $HEIGHT Basically it's not my script, i get it from somewhere from the internet. Now i would like to do the same for CPU usage and MEM usage. I don't like to use any additional packages! As you can see lighttpd populates lighttpd.rrd file with traffic data and requests per second. Now i would like to the system to populate second rrd file with CPU and MEM usage, so i can add to sh file code to generate graphs for this data. How can I populate RRD file with CPU and MEM usage data? Please, NO THIRD-PARTY tools !

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• How to start using twill?

  - by brilliant

  How do I start using twill? I have just downloaded it, unpacked it and clicked on the setup .py file in the folder. The black window (terminal) appeared for a moment and vanished. (I do have Python 2.5 installed on my computer - along with SDK from Google App Engine) In the twill documentation section it says: Downloading twill The latest release of twill is twill 0.9, released Thursday, December 27th, 2007; it is available for download at http://darcs.idyll.org/~t/projects/twill-0.9.tar.gz. You can also use Python's easy_install to install or upgrade twill. twill works with Python 2.3 or later. To start using twill, install it and then type twill-sh. At the prompt type: go http://www.slashdot.org/ show showforms showhistory I am not clear from this passage what I am supposed to type (only "twill-sh" or "twill-sh" and all the words under that line) and where (I tried typing it in the command prompt window of my computer - to no avail) Can, anyone, please, help me out here? Thank You in advance.

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• Rsync when run in cron doesnt work. Rsync between Mac Os x Server and Linux Centos

  - by Brady

  I have a working rsync setup between Mac OS X Server and Linux Centos when run manually in a terminal. I enter the rsync command, it asks for the password, I enter it and off it goes, runs and completes. Now I know thats working I set out to fully automate it via cron. First off I create an SSH authorized key by running this command on the Mac server: ssh-keygen -t dsa -b 1024 -f /Users/admin/Documents/Backup/rsync-key Entering the password and then confirming it. I then copy the rsync-key.pub file accross to the linux server and place in the rsync user .ssh folder and rename to authorized_keys: /home/philosophy/.ssh/authorized_keys I then make sure that the authorized_keys file is chmod 600 in the folder chmod 700. I then setup a shell script for cron to run: #!/bin/bash RSYNC=/usr/bin/rsync SSH=/usr/bin/ssh KEY=/Users/admin/Documents/Backup/rsync-key RUSER=philosophy RHOST=example.com RPATH=data/ LPATH="/Volumes/G Technology G Speed eS/Backup" $RSYNC -avz --delete --progress -e "$SSH -i $KEY" "$LPATH" $RUSER@$RHOST:$RPATH Then give the shell file execute permissions and then add the following to the crontab using crontab -e: 29 12 * * * /Users/admin/Documents/Backup/backup.sh I check my crontab log file after the above command should run and I get this in the log and nothing else: Feb 21 12:29:00 fileserver /usr/sbin/cron[80598]: (admin) CMD (/Users/admin/Documents/Backup/backup.sh) So I asume everything has run as it should. But when I check the remote server no files have been copied accross. If I run the backup.sh file in a terminal as normal it still prompts for a password but this time its through the Mac Key chain system rather than typing into the console window. With the Mac Key Chain I can set it to save the password so that it doesnt ask for it again but Im sure when run with cron this password isnt picked up. This is where I'm asuming where rsync in cron is failing because it needs a password to connect but I thought the whole idea of making the SSH keys was to prevent the use of a password. Have I missed a step or done something wrong here? Thanks Scott

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