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  • Three ways to upload/post/convert iMovie to YouTube [closed]

    - by alexyu2010
    For Mac users, iMovie is probably a convenient tool for making, editing their own home movies so as to upload to YouTube for sharing with more people. However, uploading iMovie files to YouTube can't be always a smooth run, I did notice many people complaining about it. This article is delivered for guiding those who are haunted by the nightmare by providing three common ways to upload iMovie files to YouTube. YouTube and iMovie YouTube is the most popular video sharing website for users to upload, share and view videos. It empowers anyone with an Internet connection the ability to upload video clips and share them with friends, family and the world. Users are invited to leave comments, pick favourites, send messages to each other and watch videos sorted into subjects and channels. YouTube accepts videos uploaded in most container formats, including WMV (Windows Media Video), 3GP (Cell Phones), AVI (Windows), MOV (Mac), MP4 (iPod/PSP), FLV (Adobe Flash), MKV (H.264). These include video codecs such as MP4, MPEG and WMV. iMovie is a common video editing software application comes with every Mac for users to edit their own home movies. It imports video footage to the Mac using either the Firewire interface on most MiniDV format digital video cameras, the USB port, or by importing the files from a hard drive where users can edit the video clips, add titles, and add music. Since 1999, eight versions of iMovie have been released by Apple, each with its own functions and characteristic, and each of them deal with videos in a way more or less different. But the most common formats handled with iMovie if specialty discarded as far as to my research are MOV, DV, HDV, MPEG-4. Three ways for successful upload iMovie files to YouTube Solution one and solution two suitable for those who are 100 certainty with their iMovie files which are fully compatible with YouTube. For smooth uploading, you are required to get a YouTube account first. Solution 1: Directly upload iMovie to YouTube Step 1: Launch iMovie, select the project you want to upload in YouTube. Step 2: Go to the file menu, click Share, select Export Movie Step 3: Specify the output file name and directory and then type the video type and video size. Solution 2: Post iMovie to YouTube straightly Step 1: Launch iMovie, choose the project you want to post in YouTube Step 2: From the Share menu, choose YouTube Step 3: In the pop-up YouTube windows, specify the name of your YouTube account, the password, choose the Category and fill in the description and tags of the project. Tick Make this movie more private on the bottom of the window, if possible, to limit those who can view the project. Click Next, and then click Publish. iMovie will automatically export and upload the movie to YouTube. Step 4: Click Tell a Friend to email friends and your family about your film. You are also allowed to copy the URL from Tell a Friend window and paste it into an email you created in your favourite email application if you like. Anyone you send to email to will be able to follow the URL directly to your movie. Note: Videos uploaded to YouTube are limited to ten minutes in length and a file size of 2GB. Solution 3: Upload to iMovie after conversion If neither of the above mentioned method works, there is still a third way to turn to. Sometimes, your iMovie files may not be recognized by YouTube due to the versions of iMovie (settings and functions may varies among versions), video itself (video format difference because of file extension, resolution, video size and length), compatibility (videos that are completely incompatible with YouTube). In this circumstance, the best and reliable method is to convert your iMovie files to YouTube accepted files, iMovie to YouTube converter will be inevitably the ideal choice. iMovie to YouTube converter is an elaborately designed tool for convert iMovie files to YouTube workable WMV, 3GP, AVI, MOV, MP4, FLV, MKV for smooth uploading with hard-to-believe conversion speed and second to none output quality. It can also convert between almost all popular popular file formats like AVI, WMV, MPG, MOV, VOB, DV, MP4, FLV, 3GP, RM, ASF, SWF, MP3, AAC, AC3, AIFF, AMR, WAV, WMA etc so as to put on various portable devices, import to video editing software or play on vast amount video players. iMovie to YouTube converter can also served as an excellent video editing tool to meet your specific program requirements. For example, you can cut your video files to a certain length, or split your video files to smaller ones and select the proper resolution suitable for demands of YouTube by Clip or Settings separately. Crop allows you to cut off unwanted black edges from your videos. Besides, you can also have a good command of the whole process or snapshot your favourite pictures from the preview window. More can be expected if you have a try.

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  • haproxy not passing X_FORWARD_FOR on HTTP POST

    - by Mark L
    Hello, I've setup HAProxy with the option forwardfor option so it'll pass on the user's IP to PHP via $_SERVER[ "HTTP_X_FORWARDED_FOR" ]. If the page request isn't a POST it's populated fine but if it is then it won't be populated. Any ideas where I've gone wrong? Thanks everyone! My whole HAProxy conf file for reference: global log 127.0.0.1 local0 log 127.0.0.1 local1 notice #log loghost local0 info maxconn 4096 #chroot /usr/share/haproxy user haproxy group haproxy daemon #debug #quiet defaults log global mode http option httplog option dontlognull retries 3 option redispatch maxconn 4096 contimeout 5000 clitimeout 50000 srvtimeout 50000 listen webfarm :80 mode http balance roundrobin option forwardfor server webA 192.168.240.4 weight 1 maxconn 2048 check server webB 192.168.240.3 weight 1 maxconn 2048 check listen smtp :25 mode tcp option tcplog balance roundrobin server smtp 192.168.240.4:25 check

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  • mod_access for lighttpd causes a 403 error for all POST requests

    - by Sam
    I have found on my debian server that running the lighttpd module mod_access is causing the server to response with a 403 to all POST requests. It's very odd as I have two servers, one is running as I'd expect and the other keeps returning these 403's. They are running identical configs for lighttpd and php. My lighttpd.conf is: https://gist.github.com/4269500 There is also one other custom conf: https://gist.github.com/4269508 I've opened up the servers for requests until I get this fixed, the server that works is http://mercury.isitup.org/ and the one that fails is http://venus.isitup.org/. After working out that disabling mod_access resolves the problem I greped all my lighttpd configs for uses of it (docs). Disabling each line I found didn't help, leading me to think this is perhaps some default behaviour (or bug?)... Has anyone come across this before or know what configuration value I've got wrong? Versions Debian: Debian GNU/Linux 6.0.6 (squeeze) Lighttpd: lighttpd/1.4.28 (ssl) PHP: PHP 5.3.19-1~dotdeb.0 with Suhosin-Patch (cli)

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  • Bios wont post unless I restart power supply.

    - by remy
    I have an annoying problem with a computer. The BIOS wont post after it has been turned off and started again unless I turn the switch off/on on the power supply. The fans, cdrom hdd and everything starts running but the bios never beeps and the monitor stays black. I HAVE TRIED: reinstalling windows xp, flashed bios to latest, cmos clear, new power supply, other hdd, new memory sticks, graphics card. I also removed the motherboard from the computer case and laid it on a cardboard box and only connected the PSU, RAM and CPU. Other than this the computer works great but its annoying having to off/on the power supply switch before turning it on after its been off. My guess is that the motherboard is faulty but I would just like to hear what you guys think. Sorry for my english / Remy

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  • Winamp "Now Playing" POST to PHP script

    - by Brad
    I have tried/researched 8 or so different plugins for Winamp that allow this functionality, and none of them seem to work on Windows 7 x64! I need a plugin for Winamp that will send the current playing track information to a PHP script, via GET or POST. I have almost no requirements... it can be the name/artist, or the filename (preferred). No fancy functionality needed, just something basic! The four that I actually are: Now Playing XML HTML Server SongStat Currently Hearing Any suggestions? (Note to Moderators: No, I'm not looking for "shopping recommendations", I just need a plugin that works. There probably is only "one answer" to this question, and if there isn't, feel free to make it a CW.)

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  • Puppet:get real-time status of catalog evaluation and post to remote server

    - by txworking
    According to this article http://docs.puppetlabs.com/guides/puppet_internals.html There are four phases when puppet agent got a catalog from master. resource generation = relationships = evaluation = reporting Reporting As the transaction progresses, it collects logs and metrics on what it does. At the end of evaluation, it turns this information into a report, which it sends to the server (if requested). And at the end of evaluation puppet agent would generate a report and sent the report to the master. Is there a way to get real-time status of evaluation phase and post them to a remote logcollector? Glad for any suggestions.

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  • FTP Server with MySQL access, and POST notification

    - by TIW
    Im looking for an FTP server solution, that we can host either internally on a dedicated server, or on Rackspace Cloud/AWS, that provides a HTTP POST notification when a file is uploaded, and allows user accounts to be created either through an API or MySQL database. There are several offerings that provide email notification - but has anyone come across anything that matches the above requirements. BrickFTP being a IaaS system is an option, but we would prefer something hosted in house. I don't believe the standard FTP servers provided with Apache can do the above ... can they?

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  • Security Issues with Single Page Apps

    - by Stephen.Walther
    Last week, I was asked to do a code review of a Single Page App built using the ASP.NET Web API, Durandal, and Knockout (good stuff!). In particular, I was asked to investigate whether there any special security issues associated with building a Single Page App which are not present in the case of a traditional server-side ASP.NET application. In this blog entry, I discuss two areas in which you need to exercise extra caution when building a Single Page App. I discuss how Single Page Apps are extra vulnerable to both Cross-Site Scripting (XSS) attacks and Cross-Site Request Forgery (CSRF) attacks. This goal of this blog post is NOT to persuade you to avoid writing Single Page Apps. I’m a big fan of Single Page Apps. Instead, the goal is to ensure that you are fully aware of some of the security issues related to Single Page Apps and ensure that you know how to guard against them. Cross-Site Scripting (XSS) Attacks According to WhiteHat Security, over 65% of public websites are open to XSS attacks. That’s bad. By taking advantage of XSS holes in a website, a hacker can steal your credit cards, passwords, or bank account information. Any website that redisplays untrusted information is open to XSS attacks. Let me give you a simple example. Imagine that you want to display the name of the current user on a page. To do this, you create the following server-side ASP.NET page located at http://MajorBank.com/SomePage.aspx: <%@Page Language="C#" %> <html> <head> <title>Some Page</title> </head> <body> Welcome <%= Request["username"] %> </body> </html> Nothing fancy here. Notice that the page displays the current username by using Request[“username”]. Using Request[“username”] displays the username regardless of whether the username is present in a cookie, a form field, or a query string variable. Unfortunately, by using Request[“username”] to redisplay untrusted information, you have now opened your website to XSS attacks. Here’s how. Imagine that an evil hacker creates the following link on another website (hackers.com): <a href="/SomePage.aspx?username=<script src=Evil.js></script>">Visit MajorBank</a> Notice that the link includes a query string variable named username and the value of the username variable is an HTML <SCRIPT> tag which points to a JavaScript file named Evil.js. When anyone clicks on the link, the <SCRIPT> tag will be injected into SomePage.aspx and the Evil.js script will be loaded and executed. What can a hacker do in the Evil.js script? Anything the hacker wants. For example, the hacker could display a popup dialog on the MajorBank.com site which asks the user to enter their password. The script could then post the password back to hackers.com and now the evil hacker has your secret password. ASP.NET Web Forms and ASP.NET MVC have two automatic safeguards against this type of attack: Request Validation and Automatic HTML Encoding. Protecting Coming In (Request Validation) In a server-side ASP.NET app, you are protected against the XSS attack described above by a feature named Request Validation. If you attempt to submit “potentially dangerous” content — such as a JavaScript <SCRIPT> tag — in a form field or query string variable then you get an exception. Unfortunately, Request Validation only applies to server-side apps. Request Validation does not help in the case of a Single Page App. In particular, the ASP.NET Web API does not pay attention to Request Validation. You can post any content you want – including <SCRIPT> tags – to an ASP.NET Web API action. For example, the following HTML page contains a form. When you submit the form, the form data is submitted to an ASP.NET Web API controller on the server using an Ajax request: <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> </head> <body> <form data-bind="submit:submit"> <div> <label> User Name: <input data-bind="value:user.userName" /> </label> </div> <div> <label> Email: <input data-bind="value:user.email" /> </label> </div> <div> <input type="submit" value="Submit" /> </div> </form> <script src="Scripts/jquery-1.7.1.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { user: { userName: ko.observable(), email: ko.observable() }, submit: function () { $.post("/api/users", ko.toJS(this.user)); } }; ko.applyBindings(viewModel); </script> </body> </html> The form above is using Knockout to bind the form fields to a view model. When you submit the form, the view model is submitted to an ASP.NET Web API action on the server. Here’s the server-side ASP.NET Web API controller and model class: public class UsersController : ApiController { public HttpResponseMessage Post(UserViewModel user) { var userName = user.UserName; return Request.CreateResponse(HttpStatusCode.OK); } } public class UserViewModel { public string UserName { get; set; } public string Email { get; set; } } If you submit the HTML form, you don’t get an error. The “potentially dangerous” content is passed to the server without any exception being thrown. In the screenshot below, you can see that I was able to post a username form field with the value “<script>alert(‘boo’)</script”. So what this means is that you do not get automatic Request Validation in the case of a Single Page App. You need to be extra careful in a Single Page App about ensuring that you do not display untrusted content because you don’t have the Request Validation safety net which you have in a traditional server-side ASP.NET app. Protecting Going Out (Automatic HTML Encoding) Server-side ASP.NET also protects you from XSS attacks when you render content. By default, all content rendered by the razor view engine is HTML encoded. For example, the following razor view displays the text “<b>Hello!</b>” instead of the text “Hello!” in bold: @{ var message = "<b>Hello!</b>"; } @message   If you don’t want to render content as HTML encoded in razor then you need to take the extra step of using the @Html.Raw() helper. In a Web Form page, if you use <%: %> instead of <%= %> then you get automatic HTML Encoding: <%@ Page Language="C#" %> <% var message = "<b>Hello!</b>"; %> <%: message %> This automatic HTML Encoding will prevent many types of XSS attacks. It prevents <script> tags from being rendered and only allows &lt;script&gt; tags to be rendered which are useless for executing JavaScript. (This automatic HTML encoding does not protect you from all forms of XSS attacks. For example, you can assign the value “javascript:alert(‘evil’)” to the Hyperlink control’s NavigateUrl property and execute the JavaScript). The situation with Knockout is more complicated. If you use the Knockout TEXT binding then you get HTML encoded content. On the other hand, if you use the HTML binding then you do not: <!-- This JavaScript DOES NOT execute --> <div data-bind="text:someProp"></div> <!-- This Javacript DOES execute --> <div data-bind="html:someProp"></div> <script src="Scripts/jquery-1.7.1.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { someProp : "<script>alert('Evil!')<" + "/script>" }; ko.applyBindings(viewModel); </script>   So, in the page above, the DIV element which uses the TEXT binding is safe from XSS attacks. According to the Knockout documentation: “Since this binding sets your text value using a text node, it’s safe to set any string value without risking HTML or script injection.” Just like server-side HTML encoding, Knockout does not protect you from all types of XSS attacks. For example, there is nothing in Knockout which prevents you from binding JavaScript to a hyperlink like this: <a data-bind="attr:{href:homePageUrl}">Go</a> <script src="Scripts/jquery-1.7.1.min.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { homePageUrl: "javascript:alert('evil!')" }; ko.applyBindings(viewModel); </script> In the page above, the value “javascript:alert(‘evil’)” is bound to the HREF attribute using Knockout. When you click the link, the JavaScript executes. Cross-Site Request Forgery (CSRF) Attacks Cross-Site Request Forgery (CSRF) attacks rely on the fact that a session cookie does not expire until you close your browser. In particular, if you visit and login to MajorBank.com and then you navigate to Hackers.com then you will still be authenticated against MajorBank.com even after you navigate to Hackers.com. Because MajorBank.com cannot tell whether a request is coming from MajorBank.com or Hackers.com, Hackers.com can submit requests to MajorBank.com pretending to be you. For example, Hackers.com can post an HTML form from Hackers.com to MajorBank.com and change your email address at MajorBank.com. Hackers.com can post a form to MajorBank.com using your authentication cookie. After your email address has been changed, by using a password reset page at MajorBank.com, a hacker can access your bank account. To prevent CSRF attacks, you need some mechanism for detecting whether a request is coming from a page loaded from your website or whether the request is coming from some other website. The recommended way of preventing Cross-Site Request Forgery attacks is to use the “Synchronizer Token Pattern” as described here: https://www.owasp.org/index.php/Cross-Site_Request_Forgery_%28CSRF%29_Prevention_Cheat_Sheet When using the Synchronizer Token Pattern, you include a hidden input field which contains a random token whenever you display an HTML form. When the user opens the form, you add a cookie to the user’s browser with the same random token. When the user posts the form, you verify that the hidden form token and the cookie token match. Preventing Cross-Site Request Forgery Attacks with ASP.NET MVC ASP.NET gives you a helper and an action filter which you can use to thwart Cross-Site Request Forgery attacks. For example, the following razor form for creating a product shows how you use the @Html.AntiForgeryToken() helper: @model MvcApplication2.Models.Product <h2>Create Product</h2> @using (Html.BeginForm()) { @Html.AntiForgeryToken(); <div> @Html.LabelFor( p => p.Name, "Product Name:") @Html.TextBoxFor( p => p.Name) </div> <div> @Html.LabelFor( p => p.Price, "Product Price:") @Html.TextBoxFor( p => p.Price) </div> <input type="submit" /> } The @Html.AntiForgeryToken() helper generates a random token and assigns a serialized version of the same random token to both a cookie and a hidden form field. (Actually, if you dive into the source code, the AntiForgeryToken() does something a little more complex because it takes advantage of a user’s identity when generating the token). Here’s what the hidden form field looks like: <input name=”__RequestVerificationToken” type=”hidden” value=”NqqZGAmlDHh6fPTNR_mti3nYGUDgpIkCiJHnEEL59S7FNToyyeSo7v4AfzF2i67Cv0qTB1TgmZcqiVtgdkW2NnXgEcBc-iBts0x6WAIShtM1″ /> And here’s what the cookie looks like using the Google Chrome developer toolbar: You use the [ValidateAntiForgeryToken] action filter on the controller action which is the recipient of the form post to validate that the token in the hidden form field matches the token in the cookie. If the tokens don’t match then validation fails and you can’t post the form: public ActionResult Create() { return View(); } [ValidateAntiForgeryToken] [HttpPost] public ActionResult Create(Product productToCreate) { if (ModelState.IsValid) { // save product to db return RedirectToAction("Index"); } return View(); } How does this all work? Let’s imagine that a hacker has copied the Create Product page from MajorBank.com to Hackers.com – the hacker grabs the HTML source and places it at Hackers.com. Now, imagine that the hacker trick you into submitting the Create Product form from Hackers.com to MajorBank.com. You’ll get the following exception: The Cross-Site Request Forgery attack is blocked because the anti-forgery token included in the Create Product form at Hackers.com won’t match the anti-forgery token stored in the cookie in your browser. The tokens were generated at different times for different users so the attack fails. Preventing Cross-Site Request Forgery Attacks with a Single Page App In a Single Page App, you can’t prevent Cross-Site Request Forgery attacks using the same method as a server-side ASP.NET MVC app. In a Single Page App, HTML forms are not generated on the server. Instead, in a Single Page App, forms are loaded dynamically in the browser. Phil Haack has a blog post on this topic where he discusses passing the anti-forgery token in an Ajax header instead of a hidden form field. He also describes how you can create a custom anti-forgery token attribute to compare the token in the Ajax header and the token in the cookie. See: http://haacked.com/archive/2011/10/10/preventing-csrf-with-ajax.aspx Also, take a look at Johan’s update to Phil Haack’s original post: http://johan.driessen.se/posts/Updated-Anti-XSRF-Validation-for-ASP.NET-MVC-4-RC (Other server frameworks such as Rails and Django do something similar. For example, Rails uses an X-CSRF-Token to prevent CSRF attacks which you generate on the server – see http://excid3.com/blog/rails-tip-2-include-csrf-token-with-every-ajax-request/#.UTFtgDDkvL8 ). For example, if you are creating a Durandal app, then you can use the following razor view for your one and only server-side page: @{ Layout = null; } <!DOCTYPE html> <html> <head> <title>Index</title> </head> <body> @Html.AntiForgeryToken() <div id="applicationHost"> Loading app.... </div> @Scripts.Render("~/scripts/vendor") <script type="text/javascript" src="~/App/durandal/amd/require.js" data-main="/App/main"></script> </body> </html> Notice that this page includes a call to @Html.AntiForgeryToken() to generate the anti-forgery token. Then, whenever you make an Ajax request in the Durandal app, you can retrieve the anti-forgery token from the razor view and pass the token as a header: var csrfToken = $("input[name='__RequestVerificationToken']").val(); $.ajax({ headers: { __RequestVerificationToken: csrfToken }, type: "POST", dataType: "json", contentType: 'application/json; charset=utf-8', url: "/api/products", data: JSON.stringify({ name: "Milk", price: 2.33 }), statusCode: { 200: function () { alert("Success!"); } } }); Use the following code to create an action filter which you can use to match the header and cookie tokens: using System.Linq; using System.Net.Http; using System.Web.Helpers; using System.Web.Http.Controllers; namespace MvcApplication2.Infrastructure { public class ValidateAjaxAntiForgeryToken : System.Web.Http.AuthorizeAttribute { protected override bool IsAuthorized(HttpActionContext actionContext) { var headerToken = actionContext .Request .Headers .GetValues("__RequestVerificationToken") .FirstOrDefault(); ; var cookieToken = actionContext .Request .Headers .GetCookies() .Select(c => c[AntiForgeryConfig.CookieName]) .FirstOrDefault(); // check for missing cookie or header if (cookieToken == null || headerToken == null) { return false; } // ensure that the cookie matches the header try { AntiForgery.Validate(cookieToken.Value, headerToken); } catch { return false; } return base.IsAuthorized(actionContext); } } } Notice that the action filter derives from the base AuthorizeAttribute. The ValidateAjaxAntiForgeryToken only works when the user is authenticated and it will not work for anonymous requests. Add the action filter to your ASP.NET Web API controller actions like this: [ValidateAjaxAntiForgeryToken] public HttpResponseMessage PostProduct(Product productToCreate) { // add product to db return Request.CreateResponse(HttpStatusCode.OK); } After you complete these steps, it won’t be possible for a hacker to pretend to be you at Hackers.com and submit a form to MajorBank.com. The header token used in the Ajax request won’t travel to Hackers.com. This approach works, but I am not entirely happy with it. The one thing that I don’t like about this approach is that it creates a hard dependency on using razor. Your single page in your Single Page App must be generated from a server-side razor view. A better solution would be to generate the anti-forgery token in JavaScript. Unfortunately, until all browsers support a way to generate cryptographically strong random numbers – for example, by supporting the window.crypto.getRandomValues() method — there is no good way to generate anti-forgery tokens in JavaScript. So, at least right now, the best solution for generating the tokens is the server-side solution with the (regrettable) dependency on razor. Conclusion The goal of this blog entry was to explore some ways in which you need to handle security differently in the case of a Single Page App than in the case of a traditional server app. In particular, I focused on how to prevent Cross-Site Scripting and Cross-Site Request Forgery attacks in the case of a Single Page App. I want to emphasize that I am not suggesting that Single Page Apps are inherently less secure than server-side apps. Whatever type of web application you build – regardless of whether it is a Single Page App, an ASP.NET MVC app, an ASP.NET Web Forms app, or a Rails app – you must constantly guard against security vulnerabilities.

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  • No mapping found for HTTP request with URI: in a Spring MVC app

    - by Ravi
    Hello All, I'm getting this error. my web.xml has this <servlet> <servlet-name>springweb</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/web-application-config.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>springweb</servlet-name> <url-pattern>/app/*</url-pattern> </servlet-mapping> I have this in my web-application-config.xml <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> </bean> <bean name="/Scheduling.htm" class="com.web.SchedulingController"/> my com.web.SchedulingController looks like this /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package com.web; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.web.servlet.ModelAndView; import org.springframework.web.servlet.mvc.Controller; public class SchedulingController implements Controller{ public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView modelAndView = new ModelAndView("/jsp/Scheduling_main.jsp"); modelAndView.addObject("message","Hello World MVC!!"); return modelAndView; } } When I hit this controller with the URL http://localhost:8080/project1/app/Scheduling.htm The Scheduling_main.jsp gets displayed but the images are not displayed properly. Also the js and css file are not getting rendered. I'm accessing the images like this <img src="jquerylib/images/save_32x32.png" title="Save Appointment"> If I change the URL mapping in the servlet definition to *.htm, the images get displayed fine. Can you point out where I'm missing out. Here is complete error message WARN [PageNotFound] No mapping found for HTTP request with URI [/mavenproject1/app/jquerylib/images/save_32x32.png] in DispatcherServlet with name 'springweb' Thanks a lot. Ravi

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  • C# remote web request certificate error

    - by Ben
    Hi. I am currently integrating a payment gateway into an application. Following a successful transaction the remote payment gateway posts details of the transaction back to my application (ITN). It posts to a HttpHandler that is used to read and validate the data. Part of the validation performed is a POST made by the handler to a validation service provided by the payment gateway. This effectively posts some of the original form values received back to the payment gateway to ensure they are valid. The url that I am posting back to is: "https://sandbox.payfast.co.za/eng/query/validate" and the code I am using: /// <summary> /// Posts the data back to the payment processor to validate the data received /// </summary> public static bool ValidateITNRequestData(NameValueCollection formVariables) { bool isValid = true; try { using (WebClient client = new WebClient()) { string validateUrl = (UseSandBox) ? SandboxValidateUrl : LiveValidateUrl; byte[] responseArray = client.UploadValues(validateUrl, "POST", formVariables); // get the resposne and replace the line breaks with spaces string result = Encoding.ASCII.GetString(responseArray); result = result.Replace("\r\n", " ").Replace("\r", "").Replace("\n", " "); if (result == null || !result.StartsWith("VALID")) { isValid = false; LogManager.InsertLog(LogTypeEnum.OrderError, "PayFast ITN validation failed", "The validation response was not valid."); } } } catch (Exception ex) { LogManager.InsertLog(LogTypeEnum.Unknown, "Unable to validate ITN data. Unknown exception", ex); isValid = false; } return isValid; } However, on calling WebClient.UploadValues the following exception is raised: System.Net.WebException: The underlying connection was closed: Could not establish trust relationship for the SSL/TLS secure channel. ---> System.Security.Authentication.AuthenticationException: The remote certificate is invalid according to the validation procedure. at System.Net.Security.SslState.StartSendAuthResetSignal(ProtocolToken message, AsyncProtocolRequest asyncRequest, Exception exception) at For the sake of brevity I haven't listed the full call stack (I can do if anyone thinks it will help). The remote certificate does appear to be valid. To get around the problem I did try adding a new RemoteCertificateValidationCallback that always returned true but just ended up getting the following exception: System.Security.SecurityException: Request for the permission of type 'System.Security.Permissions.SecurityPermission, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' failed. at System.Security.CodeAccessSecurityEngine.Check(Object demand, StackCrawlMark& stackMark, Boolean isPermSet) at System.Security.CodeAccessPermission.Demand() at System.Net.ServicePointManager.set_ServerCertificateValidationCallback(RemoteCertificateValidationCallback value) at NopSolutions.NopCommerce.Payment.Methods.PayFast.PayFastPaymentProcessor.ValidateITNRequestData(NameValueCollection formVariables) The action that failed was: Demand The type of the first permission that failed was: System.Security.Permissions.SecurityPermission The Zone of the assembly that failed was: MyComputer So I am not sure this will work in medium trust? Any help would be much appreciated. Thanks Ben

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  • Unable to find or obtain a context for request certificate

    - by Kanan
    I am trying to send push notification to iphone. By searching on internet i found that register the P12 file on server with winhttpcertcfg. But when I tried with this command winhttpcertcfg -g -c LOCAL_MACHINE\MY -s "CertificateName" -a "ASPNET" on command window after installing winhttpcertcfg. But I am getting the error "Unable to find or obtain a context for request certificate" Can you please suggest me, how to solve this error?

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  • Paypal Sandbox Do Direct Payment Internal Error 10001 Timeout Processing Request

    - by user552968
    This is what I'm sending to https://api-3t.sandbox.paypal.com/nvp: VERSION = 65.0 SIGNATURE = AFcWxV21C7fd0v3bYYYRCpSSRl31AxdW2pQp.tWHTjGNcHflR-LJhJ0t USER = seller_1283487740_biz_api1.gmail.com PWD = 1283487748 AMOUNT = 50.00 CREDITCARDTYPE = Visa ACCT = 4031477440127509 EXPDATE = 12/2015 CVV2 =123 IPADDRESS = 127.0.0.1 METHOD = DoDirectPayment I can GetBalance, I can produce other errors when I intentionally send something wrong, but DoDirectPayment or DoAuthorization returns this: TIMESTAMP = 2010-12-24T03:35:10Z CORRELATIONID = 2ca329fdbe3c0 ACK = Failure L_ERRORCODE0 = 10001 L_SHORTMESSAGE0 = Internal Error L_LONGMESSAGE0 = Timeout processing request

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  • ADO.NET Data Services Entity Framework request error when property setter is internal

    - by Jim Straatman
    I receive an error message when exposing an ADO.NET Data Service using an Entity Framework data model that contains an entity (called "Case") with an internal setter on a property. If I modify the setter to be public (using the entity designer), the data services works fine. I don’t need the entity "Case" exposed in the data service, so I tried to limit which entities are exposed using SetEntitySetAccessRule. This didn’t work, and service end point fails with the same error. public static void InitializeService(IDataServiceConfiguration config) { config.SetEntitySetAccessRule("User", EntitySetRights.AllRead); } The error message is reported in a browser when the .svc endpoint is called. It is very generic, and reads “Request Error. The server encountered an error processing the request. See server logs for more details.” Unfortunately, there are no entries in the System and Application event logs. I found this stackoverflow question that shows how to configure tracing on the service. After doing so, the following NullReferenceExceptoin error was reported in the trace log. Does anyone know how to avoid this exception when including an entity with an internal setter? Blockquote 131076 3 0 2 MOTOJIM http://msdn.microsoft.com/en-US/library/System.ServiceModel.Diagnostics.TraceHandledException.aspx Handling an exception. 685a2910-19-128703978432492675 System.NullReferenceException, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089 Object reference not set to an instance of an object. at System.Data.Services.Providers.ObjectContextServiceProvider.PopulateMemberMetadata(ResourceType resourceType, MetadataWorkspace workspace, IDictionary2 entitySets, IDictionary2 knownTypes) at System.Data.Services.Providers.ObjectContextServiceProvider.PopulateMetadata(IDictionary2 knownTypes, IDictionary2 entitySets) at System.Data.Services.Providers.BaseServiceProvider.PopulateMetadata() at System.Data.Services.DataService1.CreateProvider(Type dataServiceType, Object dataSourceInstance, DataServiceConfiguration&amp; configuration) at System.Data.Services.DataService1.EnsureProviderAndConfigForRequest() at System.Data.Services.DataService1.ProcessRequestForMessage(Stream messageBody) at SyncInvokeProcessRequestForMessage(Object , Object[] , Object[] ) at System.ServiceModel.Dispatcher.SyncMethodInvoker.Invoke(Object instance, Object[] inputs, Object[]&amp; outputs) at System.ServiceModel.Dispatcher.DispatchOperationRuntime.InvokeBegin(MessageRpc&amp; rpc) at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage5(MessageRpc&amp; rpc) at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage4(MessageRpc&amp; rpc) at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage3(MessageRpc&amp; rpc) at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage2(MessageRpc&amp; rpc) at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage1(MessageRpc&amp; rpc) at System.ServiceModel.Dispatcher.MessageRpc.Process(Boolean isOperationContextSet) </StackTrace> <ExceptionString>System.NullReferenceException: Object reference not set to an instance of an object. at System.Data.Services.Providers.ObjectContextServiceProvider.PopulateMemberMetadata(ResourceType resourceType, MetadataWorkspace workspace, IDictionary2 entitySets, IDictionary2 knownTypes) at System.Data.Services.Providers.ObjectContextServiceProvider.PopulateMetadata(IDictionary2 knownTypes, IDictionary2 entitySets) at System.Data.Services.Providers.BaseServiceProvider.P

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  • java Filter URL pattern specific to request params

    - by Rohit Desai
    Hi All, We have a situation where we want to use filter for URL's containing some specific request parameters. e.g htt://mydomain.com/?id=78&formtype=simple_form&....... htt://mydomain.com/?id=788&formtype=special_form&....... and so on , id are fetched at run time, I want configure filter in web.xml only if formtype=special_form. How should achieve the solution . Can filter be configure with regex patterns? Really appreciate your help on this. Thanks, Rohit

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  • IIS Smooth Streaming Manifest Bad Request Error

    - by snatch-02
    Hi, I installed IIS Media Services 3.0, and the Big Buck Bunny sample, but when I try to get the manifest file (http://localhost/Big_Buck_Bunny/Big Buck Bunny.ism/Manifest), I get 400.0 Bad Request error from the SmoothHandler. So the default.html appears in the browser, but the SL player shows error while trying to read the manifest. Anyone knows what can be the problem?

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  • Extending WCF Data Service to synthesize missing data on request

    - by Schneider
    I have got a WCF Data Service based on a LINQ to SQL data provider. I am making a query "get me all the records between two dates". The problem is that I want to synthesize two extra records such that I always get records that fall on the start and end dates, plus all the ones in between which come from the database. Is there a way to "intercept" the request so I can synthesize these records and return them to the client? Thanks

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  • .Net HttpWebRequest.GetResponse() raises exception when http status code 400 (bad request) is return

    - by chefsmart
    I am in a situation where when I get an HTTP 400 code from the server, it is a completely legal way of the server telling me what was wrong with my request (using a message in the HTTP response content) However, the .NET HttpWebRequest raises an exception when the status code is 400. How do I handle this? For me a 400 is completely legal, and rather helpful. The HTTP content has some important information but the exception throws me off my path.

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  • Passing input hidden params through urllib2 POST request

    - by ramrajedotcom
    I need to make POST request to CAS SSO server login page, and CAS login page has few input hidden params which are dynamically populated through java. I don't know how to read these hidden param values from response and pass in to CAS server. Without passing these hidden params I am not able to login. Does any one how to read input hidden param values from urllib2 response? Thanks in advance!

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  • How to send REGISTER request periodically from my SIP client to Asterisk server using Asterisk Manag

    - by Prashant
    Hi, I am using Asterisk 1.4 server and I have created a desktop client using the Asterisk.NET Library. I am able to log into the AMI (as a manager) using Asterisk.Net, but I cannot find a way to send the REGISTER command using the AMI, to share my client's location information with the server. I want to know an AMI or a CLI command that can send a REGISTER request to the Asterisk Server. Thanks

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  • asp.net MVC binding specific model results in error for post request

    - by Tomh
    Hi I'm having the following two actions defined in my controller [Authorize] [HttpGet] public ActionResult Edit() { ViewData.Model = HttpContext.User.Identity; return View(); } [Authorize] [HttpPost] public ActionResult Edit(User model) { return View(); } However if I post my editted data to the second action I get the following error: Server Error in '/' Application. An item with the same key has already been added. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.ArgumentException: An item with the same key has already been added. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. I tried several things like renaming parameters and removing editable fields, but it seems the model type is the problem, what could be wrong? Stack Trace: [ArgumentException: An item with the same key has already been added.] System.ThrowHelper.ThrowArgumentException(ExceptionResource resource) +51 System.Collections.Generic.Dictionary`2.Insert(TKey key, TValue value, Boolean add) +7464444 System.Linq.Enumerable.ToDictionary(IEnumerable`1 source, Func`2 keySelector, Func`2 elementSelector, IEqualityComparer`1 comparer) +270 System.Linq.Enumerable.ToDictionary(IEnumerable`1 source, Func`2 keySelector, IEqualityComparer`1 comparer) +102 System.Web.Mvc.ModelBindingContext.get_PropertyMetadata() +157 System.Web.Mvc.DefaultModelBinder.BindProperty(ControllerContext controllerContext, ModelBindingContext bindingContext, PropertyDescriptor propertyDescriptor) +158 System.Web.Mvc.DefaultModelBinder.BindProperties(ControllerContext controllerContext, ModelBindingContext bindingContext) +90 System.Web.Mvc.DefaultModelBinder.BindComplexElementalModel(ControllerContext controllerContext, ModelBindingContext bindingContext, Object model) +50 System.Web.Mvc.DefaultModelBinder.BindComplexModel(ControllerContext controllerContext, ModelBindingContext bindingContext) +1048 System.Web.Mvc.DefaultModelBinder.BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext) +280 System.Web.Mvc.ControllerActionInvoker.GetParameterValue(ControllerContext controllerContext, ParameterDescriptor parameterDescriptor) +257 System.Web.Mvc.ControllerActionInvoker.GetParameterValues(ControllerContext controllerContext, ActionDescriptor actionDescriptor) +109 System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName) +314 System.Web.Mvc.Controller.ExecuteCore() +105 System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext) +39 System.Web.Mvc.ControllerBase.System.Web.Mvc.IController.Execute(RequestContext requestContext) +7 System.Web.Mvc.<>c__DisplayClass8.<BeginProcessRequest>b__4() +34 System.Web.Mvc.Async.<>c__DisplayClass1.<MakeVoidDelegate>b__0() +21 System.Web.Mvc.Async.<>c__DisplayClass8`1.<BeginSynchronous>b__7(IAsyncResult _) +12 System.Web.Mvc.Async.WrappedAsyncResult`1.End() +59 System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult) +44 System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result) +7 System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +8679150 System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +155

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  • request response with activemq - always send double response.

    - by Chris Valley
    Hi, I'm new at activeMq. I tried to create a simple request response like this. public Listener(string destination) { // set factory ConnectionFactory factory = new ConnectionFactory(URL); IConnection connection; try { connection = factory.CreateConnection(); connection.Start(); ISession session = connection.CreateSession(); // create consumer for designated destination IMessageConsumer consumer = session.CreateConsumer(new Apache.NMS.ActiveMQ.Commands.ActiveMQQueue(destination)); consumer.Listener += new MessageListener(consumer_Listener); Console.ReadLine(); } catch (Exception ex) { Console.WriteLine(ex.ToString()); throw new Exception("Exception in Listening ", ex); } } The OnMessage static void consumer_Listener(IMessage message) { IConnectionFactory factory = new ConnectionFactory("tcp://localhost:61616/"); using (IConnection connection = factory.CreateConnection()) { //Create the Session using (ISession session = connection.CreateSession()) { //Create the Producer for the topic/queue // IMessageProducer prod = session.CreateProducer(new Apache.NMS.ActiveMQ.Commands.ActiveMQTempQueue(message.NMSDestination)); IMessageProducer producer = session.CreateProducer(message.NMSDestination); // Create Response // IMessage response = session.CreateMessage(); ITextMessage response = producer.CreateTextMessage("Replied from VS2010 Test"); //response.NMSReplyTo = new Apache.NMS.ActiveMQ.Commands.ActiveMQQueue("testQ1"); response.NMSCorrelationID = message.NMSCorrelationID; if (message.NMSReplyTo != null) { producer.Send(message.NMSReplyTo, response); Console.WriteLine("Receive: " + ((ITextMessage)message).NMSCorrelationID); Console.WriteLine("Received from : " + message.NMSDestination.ToString()); Console.WriteLine("----------------------------------------------------"); } } } } Every time i tried to send a request to the listener, the response always send repeatedly. The first response will have NMSReplyTo properties while the other not. My workaround to stop this situation by cheking the NMSReplyTo properties if (message.NMSReplyTo != null) { producer.Send(message.NMSReplyTo, response); Console.WriteLine("Receive: " + ((ITextMessage)message).NMSCorrelationID); Console.WriteLine("Received from : " + message.NMSDestination.ToString()); Console.WriteLine("----------------------------------------------------"); } In my understanding, this happened because there was a circular send response in the listener to the same Queue. Could you guys help me how to fix this? Many Thanks, Chris

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  • Pattern for verifying authenticity of a request to WCF service

    - by fung
    I have a client app that makes calls to a WCF service. This app is on a public computer that's easily accessible and anyone can easily copy the .EXE and .CONFIG of my app into another machine and start using it. Is there a pattern where I can check if the request is coming only from an app on a computer I installed it on and not on one it has been copied to? Thanks in advance.

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