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  • SQL Server v.Next (Denali) : More on contained databases and "contained users"

    - by AaronBertrand
    One of the reasons for contained databases (see my previous post ) is to allow for a more seamless transition when moving a database from one server to another. One of the biggest complications in doing so is making sure that all of the logins are in place on the new server. Contained databases help solve this issue by creating a new type of user: a database-level user with a password. I want to stress that this is not the same concept as a user without a login , which serves a completely different...(read more)

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  • Feature pack for SQL Server 2005 SP4 - collection of standalone packages

    - by ssqa.net
    With the release of SQL2005Sp4 an additional task is essential for DBAs & Developers to avoid any compatibility issues with existing code agains SP4 instance. Feature pack for SQL Server 2005 SP4 is available to download which contains the standalone packages such as SQLNative Client, ADOMD, OLAPDM etc.... as it states the feature pack are built on latest versions of add-on and backward compatibility contents for SQL Server 2005. The above link provides individual file to download for each environment...(read more)

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  • SQL Server Windows Auth Login sees Domain as untrusted...

    - by Mr Shoubs
    I've had someone set up a domain controller on windows 2008 on one server, and sql server 2008 on another. The domain seems to be working fine, I'm logged on as a domain user on both servers, nothing seems to be a problem there. However, when I try to add a domain user/group to SQL Server Security (e.g. clicking ok from the create login screen) it says it can't find it (even though I've used the search to find the correct account in the first place), when I try to logon (even though I haven't added it yet) it says something about the account being part of an untrusted domain instead of saying I don't have permission to log on. Anyone have any ideas on what is set up incorrectly?

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  • SQL SERVER – Introduction to CUME_DIST – Analytic Functions Introduced in SQL Server 2012

    - by pinaldave
    This blog post is written in response to the T-SQL Tuesday post of Prox ‘n’ Funx. This is a very interesting subject. By the way Brad Schulz is my favorite guy when it is about blogging. I respect him as well learn a lot from him. Everybody is writing something new his subject, I decided to start SQL Server 2012 analytic functions series. SQL Server 2012 introduces new analytical function CUME_DIST(). This function provides cumulative distribution value. It will be very difficult to explain this in words so I will attempt small example to explain you this function. Instead of creating new table, I will be using AdventureWorks sample database as most of the developer uses that for experiment. Let us fun following query. USE AdventureWorks GO SELECT SalesOrderID, OrderQty, CUME_DIST() OVER(ORDER BY SalesOrderID) AS CDist FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY CDist DESC GO Above query will give us following result. Now let us understand what is the formula behind CUME_DIST and why the values in SalesOrderID = 43670 are 1. Let us take more example and be clear about why the values in SalesOrderID = 43667 are 0.5. Now let us enhence the same example and use PARTITION BY into the OVER clause and see the results. Run following query in SQL Server 2012. USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, CUME_DIST() OVER(PARTITION BY SalesOrderID ORDER BY ProductID ) AS CDist FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID DESC, CDist DESC GO Now let us see the result of this query. We are have changed the ORDER BY clause as well partitioning by SalesOrderID. You can see that CUME_DIST() function provides us different results. Additionally now we see value 1 multiple times. As we are using partitioning for each group of SalesOrderID we get the CUME_DIST() value. CUME_DIST() was long awaited Analytical function and I am glad to see it in SQL Server 2012. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Cumulative Update #1 for SQL Server 2005 SP4

    - by AaronBertrand
    Well, much quicker than I would have suspected, the SQL Server Release Services team has incorporated all of the fixes in 2005 SP3's CU #12 into the first CU for SP4. Thanks to Chris Wood for the heads up. You can get the new Cumulative Update here: KB #2464079 : Cumulative update package 1 for SQL Server 2005 Service Pack 4 The nice round number of build 5000 didn't last long either; this CU will update you from 9.00.5000 to 9.00.5254....(read more)

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  • How can I connect to a Windows server using a Command Line Interface? (CLI)

    - by HopelessN00b
    Especially with the option to install Server Core in Server 2008 and above, connecting to Windows servers over a CLI is increasingly useful ability, if not one that's very widespread amongst Windows administrators. Practically every Windows GUI management tool has an option to connect to a remote computer, but there is no such option present in the built-in Windows CLI (cmd.exe), which gives the initial impression that this might not be possible. Is it possible to remotely management or administer a Windows Server using a CLI? And if so, what options are there to achieve this?

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  • How to add new filters to CAML queries in SharePoint 2007

    - by uruit
      Normal 0 21 false false false ES-UY X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin-top:0cm; mso-para-margin-right:0cm; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0cm; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} One flexibility SharePoint has is CAML (Collaborative Application Markup Language). CAML it’s a markup language like html that allows developers to do queries against SharePoint lists, it’s syntax is very easy to understand and it allows to add logical conditions like Where, Contains, And, Or, etc, just like a SQL Query. For one of our projects we have the need to do a filter on SharePoint views, the problem here is that the view it’s a list containing a CAML Query with the filters the view may have, so in order to filter the view that’s already been filtered before, we need to append our filters to the existing CAML Query. That’s not a trivial task because the where statement in a CAML Query it’s like this: <Where>   <And>     <Filter1 />     <Filter2 />   </And> </Where> If we want to add a new logical operator, like an OR it’s not just as simple as to append the OR expression like the following example: <Where>   <And>     <Filter1 />     <Filter2 />   </And>   <Or>     <Filter3 />   </Or> </Where> But instead the correct query would be: <Where>   <Or>     <And>       <Filter1 />       <Filter2 />     </And>     <Filter3 />   </Or> </Where> Notice that the <Filter# /> tags are for explanation purpose only. In order to solve this problem we created a simple component, it has a method that receives the current query (could be an empty query also) and appends the expression you want to that query. Example: string currentQuery = @“ <Where>    <And>     <Contains><FieldRef Name='Title' /><Value Type='Text'>A</Value></Contains>     <Contains><FieldRef Name='Title' /><Value Type='Text'>B</Value></Contains>   </And> </Where>”; currentQuery = CAMLQueryBuilder.AppendQuery(     currentQuery,     “<Contains><FieldRef Name='Title' /><Value Type='Text'>C</Value></Contains>”,     CAMLQueryBuilder.Operators.Or); The fist parameter this function receives it’s the actual query, the second it’s the filter you want to add, and the third it’s the logical operator, so basically in this query we want all the items that the title contains: the character A and B or the ones that contains the character C. The result query is: <Where>   <Or>      <And>       <Contains><FieldRef Name='Title' /><Value Type='Text'>A</Value></Contains>       <Contains><FieldRef Name='Title' /><Value Type='Text'>B</Value></Contains>     </And>     <Contains><FieldRef Name='Title' /><Value Type='Text'>C</Value></Contains>   </Or> </Where>             The code:   First of all we have an enumerator inside the CAMLQueryBuilder class that has the two possible Options And, Or. public enum Operators { And, Or }   Then we have the main method that’s the one that performs the append of the filters. public static string AppendQuery(string containerQuery, string logicalExpression, Operators logicalOperator){   In this method the first we do is create a new XmlDocument and wrap the current query (that may be empty) with a “<Query></Query>” tag, because the query that comes with the view doesn’t have a root element and the XmlDocument must be a well formatted xml.   XmlDocument queryDoc = new XmlDocument(); queryDoc.LoadXml("<Query>" + containerQuery + "</Query>");   The next step is to create a new XmlDocument containing the logical expression that has the filter needed.   XmlDocument logicalExpressionDoc = new XmlDocument(); logicalExpressionDoc.LoadXml("<root>" + logicalExpression + "</root>"); In these next four lines we extract the expression from the recently created XmlDocument and create an XmlElement.                  XmlElement expressionElTemp = (XmlElement)logicalExpressionDoc.SelectSingleNode("/root/*"); XmlElement expressionEl = queryDoc.CreateElement(expressionElTemp.Name); expressionEl.InnerXml = expressionElTemp.InnerXml;   Below are the main steps in the component logic. The first “if” checks if the actual query doesn’t contains a “Where” clause. In case there’s no “Where” we add it and append the expression.   In case that there’s already a “Where” clause, we get the entire statement that’s inside the “Where” and reorder the query removing and appending elements to form the correct query, that will finally filter the list.   XmlElement whereEl; if (!containerQuery.Contains("Where")) { queryDoc.FirstChild.AppendChild(queryDoc.CreateElement("Where")); queryDoc.SelectSingleNode("/Query/Where").AppendChild(expressionEl); } else { whereEl = (XmlElement)queryDoc.SelectSingleNode("/Query/Where"); if (!containerQuery.Contains("<And>") &&                 !containerQuery.Contains("<Or>"))        {              XmlElement operatorEl = queryDoc.CreateElement(GetName(logicalOperator)); XmlElement existingExpression = (XmlElement)whereEl.SelectSingleNode("/Query/Where/*"); whereEl.RemoveChild(existingExpression);                 operatorEl.AppendChild(existingExpression);               operatorEl.AppendChild(expressionEl);                 whereEl.AppendChild(operatorEl);        }        else        {              XmlElement operatorEl = queryDoc.CreateElement(GetName(logicalOperator)); XmlElement existingOperator = (XmlElement)whereEl.SelectSingleNode("/Query/Where/*");                 whereEl.RemoveChild(existingOperator);               operatorEl.AppendChild(existingOperator);               operatorEl.AppendChild(expressionEl);                 whereEl.AppendChild(operatorEl);         }  }  return queryDoc.FirstChild.InnerXml }     Finally the GetName method converts the Enum option to his string equivalent.   private static string GetName(Operators logicalOperator) {       return Enum.GetName(typeof(Operators), logicalOperator); }        This component helped our team a lot using SharePoint 2007 and modifying the queries, but now in SharePoint 2010; that wouldn’t be needed because of the incorporation of LINQ to SharePoint. This new feature enables the developers to do typed queries against SharePoint lists without the need of writing any CAML code.   Normal 0 21 false false false ES-UY X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi; mso-fareast-language:EN-US;} Post written by Sebastian Rodriguez - Portals and Collaboration Solutions @ UruIT  

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  • Need to get SMTP server on MS Server 2003

    - by Matt Dawdy
    Long story short, client paid networking company to move their website in house. Now I have to figure out how to email out from their website even though they don't have an SMTP server. At least until I install one. Their email is hosted with Gmail right now (the client's domain through Google App for Your Domain). I changed my code to connect as one of their users "[email protected]" and send email. Worked great for about 12 hours. All of a sudden none of the automated emails are going out now, and google is sending the emails back saying that it is a permanent failure and Message Rejected. The link they direct me to, http://mail.google.com/support/bin/answer.py?answer=69585 is telling me that our emails look like spam. They aren't. They are emails we send to out clients about the status of their applications. Seriously, they are NOT spam. So...long story short is out the window, sorry...but I need to get an SMTP server setup inside their domain that I can send emails out of. This thing won't need to receive emails ever, and really only needs 1 email account customercare. What can I do? Will I have to have the networking company open a port in the firewall? Is there one built into Server 2003?

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  • Is SQL Server 2008 R2 a full release of SQL Server?

    - by AaronBertrand
    This has come up in conversations more than once in the past little while - recently on twitter I made the casual comment that later this year, SQL Server 2008 will be "two versions old." Well, not everyone agrees that that is technically true. So, I thought I'd put something out there that isn't limited to 140 characters. There are certainly some valid arguments on both sides, but my opinion - based both on these facts and on my memory that Microsoft has marketed it as such - is that SQL Server...(read more)

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  • SQL SERVER – Template Browser – A Very Important and Useful Feature of SSMS

    - by pinaldave
    Let me start today’s blog post with a direction question. How many of you have ever used Template Browser? Template Browser is a very important and useful feature of SQL Server Management Studio (SSMS). Every time when I am talking about SQL Server there is always someone comes up with the question, why there is no step by step procedure included in SSMS for features. Honestly every time I get this question, the question I ask back is How many of you have ever used Template Browser? I think the answer to this question is most of the time either no or we have not heard of the feature. One of the people asked me back – have you ever written about it on your blog? I have not yet written about it. Basically there is nothing much to write about it. It is pretty straight forward feature, like any other feature and it is indeed difficult to elaborate. However, I will try to give a quick introduction to this feature. Templates are like a quick cheat sheet or quick reference. Templates are available to create objects like databases, tables, views, indexes, stored procedures, triggers, statistics, and functions. Templates are also available for Analysis Services as well. The template scripts contain parameters to help you customize the code. You can Replace Template Parameters dialog box to insert values into the script. Additionally users can create new custom templates as well with folder structure. To open a template from Template Explorer Go to View menu >> Template Explorer or type CTRL+ALT+L. You will find a list of categories click on any category and expand the folder structure. For our sample example let us expand Index Folder. In this folder you will notice the various T-SQL Scripts. These scripts can be opened by double click or can be dragged to editor area and modified as needed. Sample template is now available in the query editor area with all the necessary parameter place folder. You can replace the same parameter by typing either CTRL+SHIFT+M or by going to Query Menu >> Specify Values for Template Parameters. In this screen it will show  Specify Values for Template Parameters dialog box, accept the value or replace it with a new value. This will now get your script ready to go. Check it one more time and change the script to fit your requirement. I personally use template explorer for two things. First one is obviously for templates but the hidden one and an important one is for learning new features and T-SQL commands. There is so much to learn and so little time. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology

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  • My VPS Server's TimeZone always resets on reboot - Why?

    - by GenericTypeTea
    I'm using a VPS running Virtuozzo Containers with Parallels. Every time I reboot it sets the server's TimeZone to GMT+01 Amsterdam. If I change that to GMT+00 London and then reboot, it gets set back to Amsterdam again. Is there any way I can prevent this? I'm also have a very strange issue whereby .Net is reporting that the DateTime.Now as the +01 Amsterdam time instead of +00 GMT, even after I've change it to London's TimeZone. Is there somewhere else I need to change the TimeZone apart from in the Timezone tab under the system clock?

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  • issue in installing postgresql 9.3.4 on Windows server 2003 x64

    - by randydom
    Hello i really did all what i know to install the PostgreSQL 9.3.4 on my windows 2003 server x64, but i'm always stopped with this error : please see the error : http://oi57.tinypic.com/s4tb8i.jpg I really don't know what to do , if i click OK then when i go to the windows services list i don't find the PostgreSQL service so i can't Start the service . can any one please help me to install it correctly . PS: i've followed all steps in the : wiki.postgresql.org/wiki/Troubleshooting_Installation many thanks . here's the installer log * where i get " Failed to initialise the database cluster with initdb " : Called IsVistaOrNewer()... 'winmgmts' object initialized... Version:5.2 MajorVersion:5 Ensuring we can write to the data directory (using cacls): Executing batch file 'rad22ADE.bat'... processed dir: C:\Program Files\PostgreSQL\9.2\data Executing batch file 'rad22ADE.bat'... The files belonging to this database system will be owned by user "Administrator". This user must also own the server process. The database cluster will be initialized with locale "English_United States.1252". The default text search configuration will be set to "english". fixing permissions on existing directory C:/Program Files/PostgreSQL/9.2/data ... initdb: could not change permissions of directory "C:/Program Files/PostgreSQL/9.2/data": Permission denied Called Die(Failed to initialise the database cluster with initdb)... Failed to initialise the database cluster with initdb Script stderr: Program ended with an error exit code Error running cscript //NoLogo "C:\Program Files\PostgreSQL\9.2/installer/server/initcluster.vbs" "NT AUTHORITY\NetworkService" "postgres" "****" "C:\Program Files\PostgreSQL\9.2" "C:\Program Files\PostgreSQL\9.2\data" 5432 "DEFAULT" 0 : Program ended with an error exit code Problem running post-install step. Installation may not complete correctly The database cluster initialisation failed. Creating Uninstaller Creating uninstaller 25% Creating uninstaller 50% Creating uninstaller 75% Creating uninstaller 100% Installation completed Log finished 05/02/2014 at 04:04:04

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  • Are changes to the date and time logged in Windows Server?

    - by user17605
    We've recently gone into British Summer Time in the UK. One of our techs, anticipating the move, decided to change the time on one of our servers. Bad move. This server happens to have a number of time-based incidents logged to it, and as a result of this change, the times are unreliable. I'm trying to build a concrete timeline of when the clock was changed so I can apply corrective action to our time-based records. My question is:- Does Windows record date and time changes anywhere so I can get hard, actual data? Thanks

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  • TCP RST Reset Every 5 Minutes on Windows 2003 sp2

    - by Dan
    Hey, Recently I had a web developer come to me and ask why he was receiving connection errors in his app that was accessing a sql database. So, I went through my normal trouble shooting steps to isolate or reproduce the issue. I discovered that if I connected to the database using Query Analyzer and let the connection idle for 5 minutes it would disconnect. Meaning... I would no longer be able to refresh my tables or any other object/node within the object browser in Query Analyzer. I would have to right click on the instance and refresh for it to re-establish the connection. Next I went to wireshark and ran a capture on the client pc's nic card. Sure enough it was receiving a TCP RST reset every 5 min if the connection idled longer than 5 min. I also ran a capture on the SQL Server and noticed the TCP RST reset command as well. Attached below is the capture from the client Machine. If someone could please assist... That would be great. -I checked all settings within SQL Server 2000 against another server and they all seem to be the same. -Issue does not occur if I connect to any other SQL server 2000 server. -Issue does not occur if connecting to SQL on the server itself... so only over the network. -I consulted with network team and this is the response back: There are no firewalls or proxies in between SQL Server and your desktop. The traffic flows like this: Desktop-Access Switch-Distro Switch-Core Switch-Datacenter Switch-SQL Server None of the switches have security ACL’s configured on them. Also they stated that NAT was not turned on. -Issue does not occur with SQL server Enterprise Manager. -Ran SQL Profiler at the same time and did not see anything out of the ordinary during the RST I HAVE SEARCHED HIGH AND LOW ON GOOGLE FOR A RESOLUTION FOR THIS ISSUE. NO LUCK! My questions are: What could be causing this? Wrong Sequence number? setting in a router or switch the network team may have over looked? Setting within Windows? Setting within SQL Server 2000 that I have over looked? Better way to utilize Wireshark to find more answers? RST is about 10 from the bottom. No. Time Source Destination Protocol Info 258 24.390708 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [SYN] Seq=0 Len=0 MSS=1260 259 24.401679 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [SYN, ACK] Seq=0 Ack=1 Win=64240 Len=0 MSS=1460 260 24.401729 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [ACK] Seq=1 Ack=1 Win=65535 [TCP CHECKSUM INCORRECT] Len=0 261 24.402212 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [PSH, ACK] Seq=1 Ack=1 Win=65535 [TCP CHECKSUM INCORRECT] Len=42 262 24.413335 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [PSH, ACK] Seq=1 Ack=43 Win=64198 Len=37 285 24.466512 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [ACK] Seq=43 Ack=38 Win=65498 [TCP CHECKSUM INCORRECT] Len=1260 286 24.466536 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [PSH, ACK] Seq=1303 Ack=38 Win=65498 [TCP CHECKSUM INCORRECT] Len=437 289 24.478168 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [ACK] Seq=38 Ack=1740 Win=64240 Len=0 290 24.480078 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [PSH, ACK] Seq=38 Ack=1740 Win=64240 Len=385 293 24.493629 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [PSH, ACK] Seq=1740 Ack=423 Win=65113 [TCP CHECKSUM INCORRECT] Len=60 294 24.504637 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [PSH, ACK] Seq=423 Ack=1800 Win=64180 Len=17 295 24.533197 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [PSH, ACK] Seq=1800 Ack=440 Win=65096 [TCP CHECKSUM INCORRECT] Len=44 296 24.544098 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [PSH, ACK] Seq=440 Ack=1844 Win=64136 Len=17 297 24.544524 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [PSH, ACK] Seq=1844 Ack=457 Win=65079 [TCP CHECKSUM INCORRECT] Len=58 298 24.558033 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [PSH, ACK] Seq=457 Ack=1902 Win=64078 Len=31 299 24.558493 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [PSH, ACK] Seq=1902 Ack=488 Win=65048 [TCP CHECKSUM INCORRECT] Len=92 300 24.569984 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [PSH, ACK] Seq=488 Ack=1994 Win=63986 Len=70 301 24.577395 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [PSH, ACK] Seq=1994 Ack=558 Win=64978 [TCP CHECKSUM INCORRECT] Len=448 303 24.589834 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [PSH, ACK] Seq=558 Ack=2442 Win=63538 Len=64 304 24.590122 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [FIN, ACK] Seq=2442 Ack=622 Win=64914 [TCP CHECKSUM INCORRECT] Len=0 305 24.601094 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [ACK] Seq=622 Ack=2443 Win=63538 Len=0 306 24.601659 x.x.x.10 x.x.x.99 TCP 2226 > 14488 [FIN, ACK] Seq=622 Ack=2443 Win=63538 Len=0 307 24.601686 x.x.x.99 x.x.x.10 TCP 14488 > 2226 [ACK] Seq=2443 Ack=623 Win=64914 [TCP CHECKSUM INCORRECT] Len=0 321 25.839371 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [SYN] Seq=0 Len=0 MSS=1260 322 25.850291 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [SYN, ACK] Seq=0 Ack=1 Win=64240 Len=0 MSS=1460 323 25.850321 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [ACK] Seq=1 Ack=1 Win=65535 [TCP CHECKSUM INCORRECT] Len=0 324 25.850660 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=1 Ack=1 Win=65535 [TCP CHECKSUM INCORRECT] Len=42 325 25.861573 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=1 Ack=43 Win=64198 Len=37 326 25.863103 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [ACK] Seq=43 Ack=38 Win=65498 [TCP CHECKSUM INCORRECT] Len=1260 327 25.863130 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=1303 Ack=38 Win=65498 [TCP CHECKSUM INCORRECT] Len=463 328 25.874417 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [ACK] Seq=38 Ack=1766 Win=64240 Len=0 329 25.876315 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=38 Ack=1766 Win=64240 Len=385 330 25.876905 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=1766 Ack=423 Win=65113 [TCP CHECKSUM INCORRECT] Len=60 331 25.887773 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=423 Ack=1826 Win=64180 Len=17 332 25.888299 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=1826 Ack=440 Win=65096 [TCP CHECKSUM INCORRECT] Len=44 333 25.899169 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=440 Ack=1870 Win=64136 Len=17 334 25.899574 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=1870 Ack=457 Win=65079 [TCP CHECKSUM INCORRECT] Len=58 335 25.910618 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=457 Ack=1928 Win=64078 Len=31 336 25.911051 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=1928 Ack=488 Win=65048 [TCP CHECKSUM INCORRECT] Len=92 337 25.922068 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=488 Ack=2020 Win=63986 Len=70 338 25.922500 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2020 Ack=558 Win=64978 [TCP CHECKSUM INCORRECT] Len=34 339 25.933621 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=558 Ack=2054 Win=63952 Len=29 340 25.941165 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2054 Ack=587 Win=64949 [TCP CHECKSUM INCORRECT] Len=54 341 25.952164 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=587 Ack=2108 Win=63898 Len=17 342 25.952993 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2108 Ack=604 Win=64932 [TCP CHECKSUM INCORRECT] Len=72 343 25.963889 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=604 Ack=2180 Win=63826 Len=17 344 25.964366 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2180 Ack=621 Win=64915 [TCP CHECKSUM INCORRECT] Len=52 345 25.975253 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=621 Ack=2232 Win=63774 Len=17 346 25.975590 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2232 Ack=638 Win=64898 [TCP CHECKSUM INCORRECT] Len=32 347 25.986588 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=638 Ack=2264 Win=63742 Len=167 348 25.987262 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2264 Ack=805 Win=64731 [TCP CHECKSUM INCORRECT] Len=512 349 25.998464 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=805 Ack=2776 Win=63230 Len=89 350 25.998861 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2776 Ack=894 Win=64642 [TCP CHECKSUM INCORRECT] Len=46 351 26.009849 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=894 Ack=2822 Win=63184 Len=17 352 26.010175 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2822 Ack=911 Win=64625 [TCP CHECKSUM INCORRECT] Len=80 353 26.021220 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=911 Ack=2902 Win=63104 Len=33 354 26.022613 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [PSH, ACK] Seq=2902 Ack=944 Win=64592 [TCP CHECKSUM INCORRECT] Len=498 355 26.034018 x.x.x.10 x.x.x.99 TCP 2226 > 14492 [PSH, ACK] Seq=944 Ack=3400 Win=64240 Len=89 356 26.046501 x.x.x.99 x.x.x.10 TCP 14493 > 2226 [SYN] Seq=0 Len=0 MSS=1260 357 26.057323 x.x.x.10 x.x.x.99 TCP 2226 > 14493 [SYN, ACK] Seq=0 Ack=1 Win=64240 Len=0 MSS=1460 358 26.057355 x.x.x.99 x.x.x.10 TCP 14493 > 2226 [ACK] Seq=1 Ack=1 Win=65535 [TCP CHECKSUM INCORRECT] Len=0 359 26.057661 x.x.x.99 x.x.x.10 TCP 14493 > 2226 [PSH, ACK] Seq=1 Ack=1 Win=65535 [TCP CHECKSUM INCORRECT] Len=42 361 26.068606 x.x.x.10 x.x.x.99 TCP 2226 > 14493 [PSH, ACK] Seq=1 Ack=43 Win=64198 Len=37 362 26.070087 x.x.x.99 x.x.x.10 TCP 14493 > 2226 [ACK] Seq=43 Ack=38 Win=65498 [TCP CHECKSUM INCORRECT] Len=1260 363 26.070113 x.x.x.99 x.x.x.10 TCP 14493 > 2226 [PSH, ACK] Seq=1303 Ack=38 Win=65498 [TCP CHECKSUM INCORRECT] Len=485 364 26.081336 x.x.x.10 x.x.x.99 TCP 2226 > 14493 [ACK] Seq=38 Ack=1788 Win=64240 Len=0 365 26.083330 x.x.x.10 x.x.x.99 TCP 2226 > 14493 [PSH, ACK] Seq=38 Ack=1788 Win=64240 Len=385 366 26.083943 x.x.x.99 x.x.x.10 TCP 14493 > 2226 [PSH, ACK] Seq=1788 Ack=423 Win=65113 [TCP CHECKSUM INCORRECT] Len=46 368 26.094921 x.x.x.10 x.x.x.99 TCP 2226 > 14493 [PSH, ACK] Seq=423 Ack=1834 Win=64194 Len=17 369 26.095317 x.x.x.99 x.x.x.10 TCP 14493 > 2226 [PSH, ACK] Seq=1834 Ack=440 Win=65096 [TCP CHECKSUM INCORRECT] Len=48 370 26.107553 x.x.x.10 x.x.x.99 TCP 2226 > 14493 [PSH, ACK] Seq=440 Ack=1882 Win=64146 Len=877 371 26.241285 x.x.x.99 x.x.x.10 TCP 14492 > 2226 [ACK] Seq=3400 Ack=1033 Win=64503 [TCP CHECKSUM INCORRECT] Len=0 372 26.241307 x.x.x.99 x.x.x.10 TCP 14493 > 2226 [ACK] Seq=1882 Ack=1317 Win=65535 [TCP CHECKSUM INCORRECT] Len=0 653 55.913838 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 > 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 654 55.924547 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 > 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 910 85.887176 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 > 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 911 85.898010 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 > 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 1155 115.859520 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 1156 115.870285 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 1395 145.934403 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 1396 145.945938 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 1649 175.906767 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 1650 175.917741 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 1887 205.881080 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 1888 205.891818 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 2112 235.854408 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 2113 235.865482 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 2398 265.928342 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 2399 265.939242 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 2671 295.900714 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 2672 295.911590 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 2880 315.705029 x.x.x.10 x.x.x.99 TCP 2226 14493 [RST] Seq=1317 Len=0 2973 325.975607 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive] 14492 2226 [ACK] Seq=3399 Ack=1033 Win=64503 Len=1 2974 325.986337 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive ACK] 2226 14492 [ACK] Seq=1033 Ack=3400 Win=64240 Len=0 2975 326.154327 x.x.x.10 x.x.x.99 TCP [TCP Keep-Alive] 2226 14492 [ACK] Seq=1032 Ack=3400 Win=64240 Len=1 2976 326.154350 x.x.x.99 x.x.x.10 TCP [TCP Keep-Alive ACK] 14492 2226 [ACK] Seq=3400 Ack=1033 Win=64503 [TCP CHECKSUM INCORRECT] Len=0

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  • NAnt authorization access issue

    - by Luís Custódio
    I'm having a problem trying to move a file through my network, I want to transfer the release from my continuos integration virtual machine to the host of this VM. but i get this: System.UnauthorizedAccessException: Access to the path '\\192.168.0.36\E$\WebApps\MyProgram' is denied. at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.Directory.InternalCreateDirectory(String fullPath, String path, DirectorySecurity dirSecurity) at System.IO.Directory.CreateDirectory(String path, DirectorySecurity directorySecurity) at NAnt.Core.Tasks.MoveTask.DoFileOperations() at NAnt.Core.Tasks.CopyTask.ExecuteTask() at NAnt.Core.Task.Execute() at NAnt.Core.Target.Execute() at NAnt.Core.Project.Execute(String targetName, Boolean forceDependencies) at NAnt.Core.Project.Execute() at NAnt.Core.Project.Run() I'm trying to transfer from a Windows Server 2003 R2 to a Windows Server 2008 R2.

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  • SQL SERVER – Where Can YOU Get My Books – SQL Server Interview Question and Answers

    - by pinaldave
    Earlier month I released by third book SQL Server Interview Question and Answers. The focus of this book is ‘master the basics’. If you rate yourself 10 out of 10 in SQL Server – this book is not for you but if you want to learn fundamentals or want to refresh your fundamentals this book is for YOU. Earlier I was overwhelmed by love you all have shown to this book on release date leading our three digit inventory to run out of stock. Read detail blog post about the subject over here A Real Story of Book Getting ‘Out of Stock’ to A 25% Discount Story Available. Well, we learn the lesson from the experience and have made sure that the inventory does not run out any more. Since then we are now available on multiple outlets. Pretty much anywhere in USA and India the book is available. Additionally, where ever Amazon ships internationally. I have created dedicated page where I have listed where one can avail this book from Details of SQL Server Interview Question and Answers. Even though I keep on getting common question like – where one can get this book. You can get this book from: USA: Amazon India: Flipkart | IndiaPlaza | Crossword In India now you can walk into any crossword store and ask this book, if they do not have it, you can ask them get one for you. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Best Practices, Pinal Dave, PostADay, SQL, SQL Authority, SQL Documentation, SQL Download, SQL Interview Questions and Answers, SQL Query, SQL Server, SQL Tips and Tricks, SQLAuthority Author Visit, SQLAuthority Book Review, SQLAuthority News, T SQL, Technology

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  • SQL SERVER – A Puzzle – Fun with SEQUENCE in SQL Server 2012 – Guess the Next Value

    - by pinaldave
    Yesterday my friend Vinod Kumar wrote excellent blog post on SQL Server 2012: Using SEQUENCE. I personally enjoyed reading the content on this subject. While I was reading the blog post, I thought of very simple new puzzle. Let us see if we can try to solve it and learn a bit more about Sequence. Here is the script, which I executed. USE TempDB GO -- Create sequence CREATE SEQUENCE dbo.SequenceID AS BIGINT START WITH 3 INCREMENT BY 1 MINVALUE 1 MAXVALUE 5 CYCLE NO CACHE; GO -- Following will return 3 SELECT next value FOR dbo.SequenceID; -- Following will return 4 SELECT next value FOR dbo.SequenceID; -- Following will return 5 SELECT next value FOR dbo.SequenceID; -- Following will return which number SELECT next value FOR dbo.SequenceID; -- Clean up DROP SEQUENCE dbo.SequenceID; GO Above script gave me following resultset. 3 is the starting value and 5 is the maximum value. Once Sequence reaches to maximum value what happens? and WHY? Bonus question: If you use UNION between 2 SELECT statement which uses UNION, it also throws an error. What is the reason behind it? Can you attempt to answer this question without running this code in SQL Server 2012. I am very confident that irrespective of SQL Server version you are running you will have great learning. I will follow up of the answer in comments below. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – DMV to Identify Incremental Statistics – Performance improvements in SQL Server 2014 – Part 3

    - by Pinal Dave
    This is the third part of the series Incremental Statistics. Here is the index of the complete series. What is Incremental Statistics? – Performance improvements in SQL Server 2014 – Part 1 Simple Example of Incremental Statistics – Performance improvements in SQL Server 2014 – Part 2 DMV to Identify Incremental Statistics – Performance improvements in SQL Server 2014 – Part 3 In earlier two parts we have seen what is incremental statistics and its simple example. In this blog post we will be discussing about DMV, which will list all the statistics which are enabled for Incremental Updates. SELECT  OBJECT_NAME(sys.stats.OBJECT_ID) AS TableName, sys.columns.name AS ColumnName, sys.stats.name AS StatisticsName FROM   sys.stats INNER JOIN sys.stats_columns ON sys.stats.OBJECT_ID = sys.stats_columns.OBJECT_ID AND sys.stats.stats_id = sys.stats_columns.stats_id INNER JOIN sys.columns ON sys.stats.OBJECT_ID = sys.columns.OBJECT_ID AND sys.stats_columns.column_id = sys.columns.column_id WHERE   sys.stats.is_incremental = 1 If you run above script in the example displayed, in part 1 and part 2 you will get resultset as following. When you execute the above script, it will list all the statistics in your database which are enabled for Incremental Update. The script is very simple and effective. If you have any further improved script, I request you to post in the comment section and I will post that on blog with due credit. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: PostADay, SQL, SQL Authority, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL Tagged: SQL Statistics, Statistics

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  • SQL SERVER – SSMS: Database Consistency History Report

    - by Pinal Dave
    Doctor and Database The last place I like to visit is always a hospital. With the monsoon season starting, intermittent rains, it has become sort of a routine to get a cycle of fever every other year (seriously I hate it). So when I visit my doctor, it is always interesting in the way he quizzes me. The routine question of – “How many days have you had this?”, “Is there any pattern?”, “Did you drench in rain?”, “Do you have any other symptom?” and so on. The idea here is that the doctor wants to find any anomaly or a pattern that will guide him to a viral or bacterial type. Most of the time they get it based on experience and sometimes after a battery of tests. So if there is consistent behavior to your problem, there is always a solution out. SQL Server has its way to find if the server data / files are in consistent state using the DBCC commands. Back to SQL Server In real life, Database consistency check is one of the critical operations a DBA generally doesn’t give much priority. Many readers of my blogs have asked many times, how do we know if the database is consistent? How do I read output of DBCC CHECKDB and find if everything is right or not? My common answer to all of them is – look at the bottom of checkdb (or checktable) output and look for below line. CHECKDB found 0 allocation errors and 0 consistency errors in database ‘DatabaseName’. Above is a “good sign” because we are seeing zero allocation and zero consistency error. If you are seeing non-zero errors then there is some problem with the database. Sample output is shown as below: CHECKDB found 0 allocation errors and 2 consistency errors in database ‘DatabaseName’. repair_allow_data_loss is the minimum repair level for the errors found by DBCC CHECKDB (DatabaseName). If we see non-zero error then most of the time (not always) we get repair options depending on the level of corruption. There is risk involved with above option (repair_allow_data_loss), that is – we would lose the data. Sometimes the option would be repair_rebuild which is little safer. Though these options are available, it is important to find the root cause to the problem. In standard report, there is a report which can show the history of checkdb executed for the selected database. Since this is a database level report, we need to right click on database, click Reports, click Standard Reports and then choose “Database Consistency History” report. The information in this report is picked from default trace. If default trace is disabled or there is no checkdb run or information is not there in default trace (because it’s rolled over), we would get report like below. As we can see report says it very clearly: Currently, no execution history of CHECKDB is available or default trace is not enabled. To demonstrate, I have caused corruption in one of the database and did below steps. Run CheckDB so that errors are reported. Fix the corruption by losing the data using repair option Run CheckDB again to check if corruption is cleared. After that I have launched the report and below is what we would see. If you are lazy like me and don’t want to run the report manually for each database then below query would be handy to provide same report for all database. This query is runs behind the scenes by the report. All I have done is remove the filter for database name (at the last – highlighted). DECLARE @curr_tracefilename VARCHAR(500); DECLARE @base_tracefilename VARCHAR(500); DECLARE @indx INT; SELECT @curr_tracefilename = path FROM sys.traces WHERE is_default = 1; SET @curr_tracefilename = REVERSE(@curr_tracefilename); SELECT @indx  = PATINDEX('%\%', @curr_tracefilename) ; SET @curr_tracefilename = REVERSE(@curr_tracefilename); SET @base_tracefilename = LEFT( @curr_tracefilename,LEN(@curr_tracefilename) - @indx) + '\log.trc'; SELECT  SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),36, PATINDEX('%executed%',TEXTData)-36) AS command ,       LoginName ,       StartTime ,       CONVERT(INT,SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%found%',TEXTData) +6,PATINDEX('%errors %',TEXTData)-PATINDEX('%found%',TEXTData)-6)) AS errors ,       CONVERT(INT,SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%repaired%',TEXTData) +9,PATINDEX('%errors.%',TEXTData)-PATINDEX('%repaired%',TEXTData)-9)) repaired ,       SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%time:%',TEXTData)+6,PATINDEX('%hours%',TEXTData)-PATINDEX('%time:%',TEXTData)-6)+':'+SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%hours%',TEXTData) +6,PATINDEX('%minutes%',TEXTData)-PATINDEX('%hours%',TEXTData)-6)+':'+SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%minutes%',TEXTData) +8,PATINDEX('%seconds.%',TEXTData)-PATINDEX('%minutes%',TEXTData)-8) AS time FROM::fn_trace_gettable( @base_tracefilename, DEFAULT) WHERE EventClass = 22 AND SUBSTRING(TEXTData,36,12) = 'DBCC CHECKDB' -- AND DatabaseName = @DatabaseName; Don’t get worried about the logic above. All it is doing is reading the trace files, parsing below entry and getting out information for underlined words. DBCC CHECKDB (CorruptedDatabase) executed by sa found 2 errors and repaired 0 errors. Elapsed time: 0 hours 0 minutes 0 seconds.  Internal database snapshot has split point LSN = 00000029:00000030:0001 and first LSN = 00000029:00000020:0001. Hopefully now onwards you would run checkdb and understand the importance of it. As responsible DBAs I am sure you are already doing it, let me know how often do you actually run them on you production environment? Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL Tagged: SQL Reports

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  • Hotmail Senders receiving NDR : "550-Please turn on SMTP Authentication in your mail client..."

    - by DKNUCKLES
    Recently, senders from Hotmail have begun to get the following NDR when trying to e-mail our domain. EDIT : Full NDR Message Action: failed Status: 5.5.0 Diagnostic-Code: smtp;550-Please turn on SMTP Authentication in your mail client, or login to the 550-IMAP/POP3 server before sending your message. 550-snt0-omc3-s36.snt0.hotmail.com [65.55.90.175]:49271 is not permitted to 550 relay through this server without authentication This is seemingly out of the blue and I'm at a loss as to why this is happening. Pertinent Information We have multiple domains hooked up to our Exchange server. We changed our company name in January of this year, and the old primary domain (olddomain.com) will accept e-mails from Hotmail accounts, however e-mails sent to the new primary domain (newdomain.com) bounce back with the NDR listed above. The bounces only appear to be happening when the Hotmail sender is sending a new e-mail, and not if they are responding to an e-mail sent from our end. We have made no changes to the configuration of our server recently. This e-mail first appeared last Friday. As far as I can tell, the mail doesn't even seem to get to our server We performed an Exchange 2003 to 2010 migration last year. The 2003 acts as a Smart Host Any advice on this issue would be greatly appreciated! I'm at a loss

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  • Exchange 2010: Replication Service Still Trying to Replicate Deleted Mailbox Store

    - by ThaKidd
    In advance, thank you for your opinions! I just migrated from Server/Exchange 2003 to Server 2008 SR2 running Exchange 2010. I had an extra mailbox that appeared with some system mailboxes in it. I used the EMS to move those mailboxes over and then deleted the store out of the EMC. Since then every so often I get an Error in Event Viewer. Source: MSExchangeRepl ID: 4098 Error: The Microsoft Exchange Replication service couldn't find a valid configuration for database '5f012f40-3bad-4003-a373-dbc0ffb6736f' on server 'EXCHSERVER'. Error: (nothing after this) I can confirm that the above GUID is the mailbox store of that I deleted. No other Exchange errors occur. How can I tell Exchange Replication to ignore this store? Setup, one Exchange server 2003 transitioned over to 2010. No other Exchange servers. Is there a way to fix this? Do I need to change a setting to stop replication? I plan to add a second Exchange server in the next few days so stopping replication would be a bad thing. Thanks again in advance. Jason

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  • SocketException (Timeout) only when running as scheduled task

    - by BVartin
    I'm running a C# web-scrapper application (that I wrote) on a Windows Server 2003 instance under a user belonging to the local Administrator group. When I run it within a desktop/remote-desktop session the application runs successfully but when I schedule it to run under the same user/security-context outside of the desktop session, all socket connections timeout. The scheduled task calls a batch file which in-turn calls the application. The Windows Server 2003 instance has a very basic configuration and isn't even connected to a domain. I cannot find anything in any firewall or security configuration which is preventing this but maybe I have overlooked something, can anyone be of any assistance? System.Net.WebException: Unable to connect to the remote server --- System.Net.Sockets.SocketException: A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond X.X.X.X:443 at System.Net.Sockets.Socket.DoConnect(EndPoint endPointSnapshot, SocketAddress socketAddress) at System.Net.ServicePoint.ConnectSocketInternal(Boolean connectFailure, Socket s4, Socket s6, Socket& socket, IPAddress& address, ConnectSocketState state, IAsyncResult asyncResult, Int32 timeout, Exception& exception) --- End of inner exception stack trace --- at System.Net.HttpWebRequest.GetResponse()

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  • Global Address List, Multiple All Address Lists in CN=Address Lists Container

    - by Jonathan
    When my colleges (that was way before my time here) updated Exchange 2000 to 2003 a English All Address Lists appeared in addition to the German variant. The English All Address Lists have German titled GAL below it. This has just been a cosmetic problem for the last few years. Now as we are in the process of rolling out Exchange 2010 this causes some issues. Exchange 2010 picked the wrong i.e. English Address Lists Container to use. In ADSI Editor we see CN=All Address Lists,CN=Address Lists Container,CN=exchange org,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain and CN=Alle Adresslisten,CN=Address Lists Container,CN=exchange org,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain. In the addressBookRoots attribute of CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain both address lists were stored as values. We removed the English variant from addressBookRoots and restarted all (old and new) Exchange servers. User with mailboxes on the Exchange 2003 now only sees the German variant. Exchange 2010 is still stuck with the English/Mixed variant as are Users on Exchange 2010. Our goal would be to have Outlook display the German title of All Address Lists and get rid of the wrong Address Lists Container.

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  • Outlook 2007/2010 autodiscovering old Exchange info

    - by Dan
    I currently have an Exchange setup as follows: two Exchange 2003 servers clustered together set up as the current mailbox stores, one Exchange 2003 setup as a frontend, one Exchange 2007 set up as a frontend (was set up for testing by my predecessor, never really used intentionally), and now four Exchange 2010 servers - two mailboxes in a DAG and two with Hub/CAS. Everything seems to be working fine with one exception - Outlook 2007/2010 clients are still autodiscovering the test 2007 frontend and not the 2010 CAS array. I know this because there's an expired cert on the 2007 box so the client displays a cert error when you attempt to autocreate the outlook profile. From what I've read, there is an SCP (Service Connection Point) in AD that is pointing to the old server and it is getting returned first, causing Outlook to try it first. How can I prevent Outlook from even attempting to connect to this 2007 box from now on? http://www.msexchange.org/articles_tutorials/exchange-server-2010/management-administration/exchange-autodiscover.html When Outlook 2007 is installed on a domain joined workstation then the Outlook client will query Active Directory for the Autodiscover information. Active Directory will return a list of SCP’s and the Outlook client will automatically select the first SCP in this list. Using the information found in the SCP the Outlook client will contact the Client Access Server for its configuration information and the Outlook client will be configured automatically.

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  • Exchange MSExchangeIS Mailbox Store Error

    - by Bart Silverstrim
    Boss asked me to check to see if I could figure out why he's had to restart the services on the Exchange server three mornings in a row now. While going through the system logs I ran across an error from the MSExchangeIs Mailbox Store, category General, Event 9690. The message said (edited to make generalized): Exchange store 'First Storage Group\Mailbox Store (Servername)': The logical size of this database (the logical size equals the physical size of the .edb file and the .stm file minus the logical free space in each) is 22GB. This database size has exceeded the size limit of 22 GB. This database will be dismounted immediately. Hmm...happened at five in the morning, and I'm thinking this is a pretty good hint that this leads to the culprit. Thing is I'm not an Exchange expert, so I'm still googling around to figure out how to fix the problem. Any better guidance out there? Or am I barking up the wrong binary tree? Exchange System Manager reports that the server is "version 6.5 build 7638.2, SP2", standard, which I believe is Exchange 2003. It's running on Windows Server 2003 R2 Standard, SP2.

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