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• Configure IPv6 on your Linux system (Ubuntu)

  After the presentation on IPv6 at the first event of the Emtel Knowledge Series and some recent discussion on social media networks with other geeks and Linux interested IT people here in Mauritius, I thought that I should give it a try (finally) and tweak my local network infrastructure. Honestly, I have been to busy with contractual project work and it never really occurred to me to set up IPv6 in my LAN. Well, the following paragraphs are going to shed some light on those aspects of modern computer and network technology. This is the first article in a series on IPv6 configuration: Configure IPv6 on your Linux system DHCPv6: Provide IPv6 information in your local network Enabling DNS for IPv6 infrastructure Accessing your web server via IPv6 Piece of advice: This is based on my findings on the internet while reading other people's helpful articles and going through a couple of man-pages on my local system. Let's embrace IPv6 The basic configuration on Linux is actually very simple as the kernel, operating system, and user-space programs support that protocol natively. If your system is ready to go for IP (aka: IPv4), then you are good to go for anything else. At least, I didn't have to install any additional packages on my system(s). We are going to assign a static IPv6 address to the system. Hence, we have to modify the definition of interfaces and check whether we have an inet6 entry specified. Open your favourite text editor and check the following entries (it should be at least similar to this): $ sudo nano /etc/network/interfaces auto eth0# IPv4 configurationiface eth0 inet static  address 192.168.1.2  network 192.168.1.0  netmask 255.255.255.0  broadcast 192.168.1.255# IPv6 configurationiface eth0 inet6 static  pre-up modprobe ipv6  address 2001:db8:bad:a55::2  netmask 64 Of course, you might have to adjust your interface device (eth0) or you might be interested to have multiple directives for additional devices (eth1, eth2, etc.). The auto instruction takes care that your device is enabled and configured during the booting phase. The use of the pre-up directive depends on your kernel configuration but in most scenarios this might be an optional line. Anyways, it doesn't hurt to have it enabled after all - just to be on the safe side. Next, either restart your network subsystem like so: $ sudo service networking restart Or you might prefer to do it manually with identical parameters, like so: $ sudo ifconfig eth0 inet6 add 2001:db8:bad:a55::2/64 In case that you're logged in remotely into your PC (ie. via ssh), it is highly advised to opt for the second choice and add the device manually. You can check your configuration afterwards with one of the following commands (depends on whether it is installed): $ sudo ifconfig eth0eth0      Link encap:Ethernet  HWaddr 00:21:5a:50:d7:94            inet addr:192.168.160.2  Bcast:192.168.160.255  Mask:255.255.255.0          inet6 addr: fe80::221:5aff:fe50:d794/64 Scope:Link          inet6 addr: 2001:db8:bad:a55::2/64 Scope:Global          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1 $ sudo ip -6 address show eth03: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qlen 1000    inet6 2001:db8:bad:a55::2/64 scope global        valid_lft forever preferred_lft forever    inet6 fe80::221:5aff:fe50:d794/64 scope link        valid_lft forever preferred_lft forever In both cases, it confirms that our network device has been assigned a valid IPv6 address. That's it in general for your setup on one system. But of course, you might be interested to enable more services for IPv6, especially if you're already running a couple of them in your IP network. More details are available on the official Ubuntu Wiki. Continue to configure your network to provide IPv6 address information automatically in your local infrastructure.

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• Change array format in PHP.

  - by Muhammad Sajid

  I have an array like: Array ( [6] => Array ( [quantity] => 23 [orgId] => 6 [validity] => 20 ) [2] => Array ( [quantity] => 5 [orgId] => 2 [validity] => 2 ) [5] => Array ( [quantity] => 5 [orgId] => 5 [validity] => 4 ) [4] => Array ( [quantity] => 7 [orgId] => 4 [validity] => 10 ) ) and i want to show that like this: Array ( [0] => Array ( [quantity] => 23 [orgId] => 6 [validity] => 20 ) [1] => Array ( [quantity] => 5 [orgId] => 2 [validity] => 2 ) [2] => Array ( [quantity] => 5 [orgId] => 5 [validity] => 4 ) [3] => Array ( [quantity] => 7 [orgId] => 4 [validity] => 10 ) ) To do that i used array_push & some other technique but fail. can someone help me thanks.

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• Difference in System. exit(0) , System.exit(-1), System.exit(1 ) in java

  - by girinie

  Hi I like to know difference between the following in java System.exit(0); System.exit(-1); System.exit(1); When do I have to use the above code appropriately. Thanks

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• C++ simple arrays and pointers question

  - by nashmaniac

  So here's the confusion, let's say I declare an array of characters char name[3] = "Sam"; and then I declare another array but this time using pointers char * name = "Sam"; What's the difference between the two? I mean they work the same way in a program. Also how does the latter store the size of the stuff that someone puts in it, in this case 3 characters? Also how is it different from char * name = new char[3]; If those three are different where should they be used I mean in what circumstances?

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• php multidimensional arrays, memory management

  - by srk

  i need a structure like this array(){ [0] = array(){ [0] = array(){ // this array will have 'n' values(n is large, like 2000) } [1] = array(){ // this array will have 'n' values(n is large, like 2000) } } . . . . [n] = ............ n arrays will each have a 2 element array, where each element has an array of n values. I used $list[$m][0][$n] and $list[$m][1][$n] inside 2 for loops where $m,$n vary from 0...2000 this crosses the allowed memory size.. i can change the size in php.ini, but i want to optimize my memory usage and not change the limit. will using objects help ? Please provide some sample code to understand. Thank you.

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• How to sort multiple arrays in PHP

  - by Phil Jackson

  hi, i have wrote a script to produce an array of data but now want to display in order of score. The array outputs as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user1_design [2] => user2_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 6 [2] => 15 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) so in a nutshell I am wanting it to be converted as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user2_design [2] => user1_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 15 [2] => 6 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) I have been looking at asort() but cant get anything to work. any help would be much appreciated.

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• How can I define an empty array in a Perl construtor?

  - by Laimoncijus

  I am just beginner with Perl, so if it sounds stupid - sorry for that :) My problem is - I am trying to write a class, which has an empty array, defined in constructor of a class. So I am doing this like this: package MyClass; use strict; sub new { my ($C) = @_; my $self = { items => () }; bless $self, ref $C || $C; } sub get { return $_[0]->{items}; } 1; Later I am testing my class with simple script: use strict; use Data::Dumper; use MyClass; my $o = MyClass->new(); my @items = $o->get(); print "length = ", scalar(@items), "\n", Dumper(@items); And while running the script I get following: $ perl my_test.pl length = 1 $VAR1 = undef; Why am I doing wrong what causes that I get my items array filled with undef? Maybe someone could show me example how the class would need to be defined so I would not get any default values in my array?

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• is it possible if callback in array_filter receive parameter ?

  - by justjoe

  i got this multiple array name $files[], who consist keys and values as below : [0] = Array ( [name] = index1.php [path] = http://localhost/php/gettingstarted/ [number] = 1 ) [1] = Array ( [name] = index10.php [path] = http://localhost/php/gettingstarted/ [number] = 2 ) [2] = Array ( [name] = index11.php [path] = http://localhost/php/gettingstarted/ [number] = 3 ) and i use this code to create new array consist of 'name' keys only. but it failed array_filter($files, "is_inarr_key('name')"); function is_inarr_key($array, $key) { //TODO : remove every array except those who got the same $key } and i got this error array_filter() [function.array-filter]: The second argument, 'is_inarr_key('name')', should be a valid callback in C:\xampp\htdocs\php\gettingstarted\index.php on line 15 so the queastion : 1. is it possible to make call-back function on array_filter has ability to receive parameter ? What is general rule of thumb on how to use callback in anyPHP built-in function ?

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• Why doesen't the number 2 work in this for-loop?

  - by Emil

  Hello. I have a function that runs trough each element in an array. It's hard to explain, so I'll just paste in the code here: NSLog(@"%@", arraySub); for (NSString *string in arrayFav){ int favoriteLoop = [string intValue] + favCount; NSLog(@"%d", favoriteLoop); id arrayFavObject = [array objectAtIndex:favoriteLoop]; [arrayFavObject retain]; [array removeObjectAtIndex:favoriteLoop]; [array insertObject:arrayFavObject atIndex:0]; [arrayFavObject release]; id arraySubFavObject = [arraySub objectAtIndex:favoriteLoop]; [arraySubFavObject retain]; [arraySub removeObjectAtIndex:favoriteLoop]; [arraySub insertObject:arraySubFavObject atIndex:0]; [arraySubFavObject release]; id arrayLengthFavObject = [arrayLength objectAtIndex:favoriteLoop]; [arrayLengthFavObject retain]; [arrayLength removeObjectAtIndex:favoriteLoop]; [arrayLength insertObject:arrayLengthFavObject atIndex:0]; [arrayLengthFavObject release]; } NSLog(@"%@", arraySub); The array arrayFav contains these strings: "3", "8", "2", "10", "40". Array array contains 92 strings with a name. Array arraySub contains numbers 0 to 91, representing a filename with a title from the array array. Array arrayLength contains 92 strings representing the size of each file from array arraySub. Now, the first NSLog shows, as expected, the numbers 0 to 91. The NSLog-s in the loop shows the numbers 3, 8, 2, 10, 40, also as expected. But here's the odd part: the last NSLog shows these numbers: 40, 10, 0, 8, 3, 1, 2, 4, 5, 6, 7, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91 that is 40, 10, 0, 8, 3, and so on. It was not supposed to be a zero in there, it was supposed to be a 2.. Do you have any idea at why this is happening or a way to fix it? Thank you.

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• Weird behavior of matching array keys after json_decode()

  - by arnorhs

  I've got some very weird behavior in my PHP code. I don't know if this is actually a good SO question, since it almost looks like a bug in PHP. I had this problem in a project of mine and isolated the problem: // json object that will be converted into an array $json = '{"5":"88"}'; $jsonvar = (array) json_decode($json); // notice: Casting to an array // Displaying the array: var_dump($jsonvar); // Testing if the key is there var_dump(isset($jsonvar["5"])); var_dump(isset($jsonvar[5])); That code outputs the following: array(1) { ["5"]=> string(2) "88" } bool(false) bool(false) The big problem: Both of those tests should produce bool(true) - if you create the same array using regular php arrays, this is what you'll see: // Let's create a similar PHP array in a regular manner: $phparr = array("5" => "88"); // Displaying the array: var_dump($phparr); // Testing if the key is there var_dump(isset($phparr["5"])); var_dump(isset($phparr[5])); The output of that: array(1) { [5]=> string(2) "88" } bool(true) bool(true) So this doesn't really make sense. I've tested this on two different installations of PHP/apache. You can copy-paste the code to a php file yourself to test it. It must have something to do with the casting from an object to an array.

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• Speed up executable program Linux. Bit Toggling

  - by AK_47

  I have a ZyBo circuit board which has a ArmV7 processor. I wrote a C program to output a clock and a corresponding data sequence on a PMOD. The PMOD has a switching speed of up to 50MHz. However, my program's created clock only has a max frequency of 115 Hz. I need this program to output as fast as possible because the PMOD I'm using is capable of 50MHz. I compiled my program with the following code line: gcc -ofast (c_program) Here is some sample code: #include <stdio.h> #include <stdlib.h> #define ARRAYSIZE 511 //________________________________________ //macro for the SIGNAL PMOD //________________________________________ //DATA //ZYBO Use Pin JE1 #define INIT_SIGNAL system("echo 54 > /sys/class/gpio/export"); system("echo out > /sys/class/gpio/gpio54/direction"); #define SIGNAL_ON system("echo 1 > /sys/class/gpio/gpio54/value"); #define SIGNAL_OFF system("echo 0 > /sys/class/gpio/gpio54/value"); //________________________________________ //macro for the "CLOCK" PMOD //________________________________________ //CLOCK //ZYBO Use Pin JE4 #define INIT_MYCLOCK system("echo 57 > /sys/class/gpio/export"); system("echo out > /sys/class/gpio/gpio57/direction"); #define MYCLOCK_ON system("echo 1 > /sys/class/gpio/gpio57/value"); #define MYCLOCK_OFF system("echo 0 > /sys/class/gpio/gpio57/value"); int main(void){ int myarray[ARRAYSIZE] = {//hard coded array for signal data 1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,0,1,1,0,0,1,1,0,1,0,0,0,0,0,1,0,0,1,1,1,0,0,1,1,1,0,1,1,1,1,0,0,1,0,0,0,1,0,1,0,0,1,1,1,0,0,1,0,1,0,1,0,0,1,0,1,1,0,1,0,1,1,0,0,1,1,1,1,0,0,1,0,1,0,0,1,1,1,1,1,1,0,0,1,0,0,1,1,0,1,0,0,0,0,1,0,0,0,1,1,0,0,1,0,1,1,1,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,0,1,0,1,1,1,1,0,1,1,0,1,0,0,1,0,0,0,1,0,1,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,1,0,1,1,0,0,0,0,0,0,0,0,1,0,1,1,0,1,1,1,1,1,0,0,1,1,1,0,0,1,1,0,1,1,0,1,1,1,0,0,1,1,1,1,1,0,0,1,0,1,0,1,0,1,1,0,1,0,0,0,1,1,1,0,1,0,1,0,1,0,1,0,1,0,1,0,0,1,0,0,0,0,1,1,1,0,1,1,1,1,0,1,1,0,1,0,1,0,1,0,0,1,0,1,1,1,0,1,1,1,0,0,1,1,1,0,1,0,0,1,0,1,1,1,1,1,0,1,1,1,1,1,1,1,0,1,1,0,0,1,0,1,1,0,1,0,1,1,1,0,0,0,0,0,1,0,0,0,1,0,1,1,1,1,1,1,1,0,0,0,0,0,1,1,0,1,1,1,1,1,1,1,1,0,1,1,0,1,0,0,0,1,1,1,1,1,1,1,1,1,1,0,1,1,1,1,0,1,1,1,0,1,0,1,1,1,0,0,0,1,0,1,0,1,0,0,1,1,0,0,1,1,0,1,0,0,1,0,0,1,0,1,1,1,1,1,1,0,1,1,0,1,0,1,1,1,1,1,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,1,0,1,0,1,0,1,0,0,1,1,1,0,1,1,0,0,0,0,1,1,0,1,1,0,1,1,1,1,1,1,1,0,1,0,1,1,0,0,0,0,0,0,0,0,0,0,0 }; INIT_SIGNAL INIT_MYCLOCK; //infinite loop int i; do{ i = 0; do{ /* 1020 is chosen because it is twice the size needed allowing for the changes in the clock. (511= 0-510, 510*2= 1020 ==> 0-1020 needed, so 1021 it is) */ if((i%2)==0) { MYCLOCK_ON; if(myarray[i/2] == 1){ SIGNAL_ON; }else{ SIGNAL_OFF; } } else if((i%2)==1) { MYCLOCK_OFF; //dont need to change the signal since it will just stay at whatever it was. } ++i; } while(i < 1021); } while(1); return 0; } I'm using the 'system' call to tell the system to output 1 volt or 0 volts onto a pin on the board (to represent the data signal and clock signal. One pin for the data and another for the clock). That was the only way I knew to tell the system to output a voltage. What can I do to make my executable program output to be at least in the magnitude of MegaHertz?

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• Rewriting usort function because of fatal error (PHP bug)

  - by Lionel

  The two following usort functions throw fatal error Base lambda function for closure not found in our productive environment (PHP 5.4). This seems to be a known PHP bug that should be fixed by now (https://bugs.php.net/bug.php?id=52144), but it still occurs for us. Anyway, we unfortunately don't have time to figure out what's wrong with our PHP configurations etc. We would like to rewrite these two functions without the use of anonymous functions, so that the error doesn't occur anymore. Ordering of a multidimensional array ($array) by value of key "position": usort($array, function($a, $b) { return $a['position'] - $b['position']; }); Ordering of a multidimensional array ($array) according to the order of a second array ($position_order): usort($array, function($a, $b) use($position_order) { return (isset($position_order[$a['ftid']]) ? ($position_order[$a['ftid']] - $position_order[$b['ftid']]) : 1); }); Especially the latter causes some headache, as we don't know how to pass the "outside" array $position_order.

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• How to check if numbers are in correct sequence?

  - by Nazariy

  I have a two dimensional array that contain range of numbers that have to be validated using following rules, range should start from 0 and follow in arithmetic progression. For example: $array = array(); $array[] = array(0);//VALID $array[] = array(0,1,2,3,4,5);//VALID $array[] = array("0","1");//VALID $array[] = array(0,1,3,4,5,6);//WRONG $array[] = array(1,2,3,4,5);//WRONG $array[] = array(0,0,1,2,3,4);//WRONG what is most efficient way to do that in php? UPDATE I forgot to add that numbers can be represented as string

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• str_replace() and strpos() for arrays?

  - by Josh

  I'm working with an array of data that I've changed the names of some array keys, but I want the data to stay the same basically... Basically I want to be able to keep the data that's in the array stored in the DB, but I want to update the array key names associated with it. Previously the array would have looked like this: $var_opts['services'] = array('foo-1', 'foo-2', 'foo-3', 'foo-4'); Now the array keys are no longer prefixed with "foo", but rather with "bar" instead. So how can I update the array variable to get rid of the "foos" and replace with "bars" instead? Like so: $var_opts['services'] = array('bar-1', 'bar-2', 'bar-3', 'bar-4'); I'm already using if(isset($var_opts['services']['foo-1'])) { unset($var_opts['services']['foo-1']); } to get rid of the foos... I just need to figure out how to replace each foo with a bar. I thought I would use str_replace on the whole array, but to my dismay it only works on strings (go figure, heh) and not arrays.

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• arrays format (Javascript)

  - by João Melo

  i have a list of users, with minions, something like this: User52: minion10 minion12 User32: minion13 minion11 i've been keeping in an array where the "location" is the id, like this: Users: [52]User minions: [10]minion [12]minion [32]User minions: [13]minion [11]minion so i can access them easily like this: user[UserID].minions[MinionID] (ex: user[32].minions[11]) but when i print it or send it by json i get something like this: {,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,minion,,,,,,,,,,,,,,minion} but should i keep using like this or should i change to something like this: User = function(){ this.minions = ...; this.getMinion = function(value){ for(var m in this.minions){ if(this.minions[m].id == value){ return this.minions[m]; break; } } } } and get it like this: user.getMinion(MinionID); Question: i get better performance using a "short" array but using loops every time i need a minion, or using "long" arrays, but no need for loop and getting values directly from the id "name"?

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• Finding and marking the largest of three values in a two dimensional array

  - by DavidYell

  I am working on a display screen for our office, and I can't seem to think of a good way to find the largest numerical value in a set of data in a two dimensional array. I've looked at using max() and also asort() but they don't seem to cope with a two dimensional array. I'm returning my data through our mysql class, so the rows are returned in a two dimensional array. Array( [0] => Array( [am] => 12, [sales] => 981), [1] => Array( [am] => 43, [sales] => 1012), [2] => Array( [am] => 17, [sales] => 876) ) I need to output a class when foreaching the data in my table for the AM with the highest sales value. Short of comparing them all in if statements. I have tried to get max() on the array, but it returns an array, as it's look within the dimension. When pointing it at a specific dimension it returns the key not the value. I figured that I could asort() the array and pop the top value off, store it in a variable and then compare against that in my foreach() loop, but that seems to have trouble sorting across two dimensions. Lastly, I figured that I could foreach() the values, comparing them against the previous one each time, untill I found the largest. This approach however means storing every value, luckily only three, but then comparing against them all again. Surely there must be a simpler way to achieve this, short of converting it into a single dimension array, then doing an asort() on that?

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• Why doesen't the number 2 work in this for-loop?

  - by Emil

  Hello. I have a function that runs trough each element in an array. It's hard to explain, so I'll just paste in the code here: NSLog(@"%@", arraySub); for (NSString *string in arrayFav){ int favoriteLoop = [string intValue] + favCount; NSLog(@"%d", favoriteLoop); id arrayFavObject = [array objectAtIndex:favoriteLoop]; [arrayFavObject retain]; [array removeObjectAtIndex:favoriteLoop]; [array insertObject:arrayFavObject atIndex:0]; [arrayFavObject release]; id arraySubFavObject = [arraySub objectAtIndex:favoriteLoop]; [arraySubFavObject retain]; [arraySub removeObjectAtIndex:favoriteLoop]; [arraySub insertObject:arraySubFavObject atIndex:0]; [arraySubFavObject release]; id arrayLengthFavObject = [arrayLength objectAtIndex:favoriteLoop]; [arrayLengthFavObject retain]; [arrayLength removeObjectAtIndex:favoriteLoop]; [arrayLength insertObject:arrayLengthFavObject atIndex:0]; [arrayLengthFavObject release]; } NSLog(@"%@", arraySub); The array arrayFav contains these strings: "3", "8", "2", "10", "40". Array array contains 92 strings with a name. Array arraySub contains numbers 0 to 91, representing a filename with a title from the array array. Array arrayLength contains 92 strings representing the size of each file from array arraySub. Now, the first NSLog shows, as expected, the numbers 0 to 91. The NSLog-s in the loop shows the numbers 3, 8, 2, 10, 40, also as expected. But here's the odd part: the last NSLog shows these numbers: 40, 10, 0, 8, 3, 1, 2, 4, 5, 6, 7, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91 that is 40, 10, 0, 8, 3, and so on. It was not supposed to be a zero in there, it was supposed to be a 2.. Do you have any idea at why this is happening or a way to fix it? Thank you.

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• CakePHP - Paginating an Array

  - by Ashok

  Cake handles pagination of a model with a simple $this-paginate(), but what should I use if I want to paginate a array of values? The Scenario is like this: $this->set('sitepages', $this->paginate()); This code in my index() returns an array like Array ( [0] => Array ( [Sitepage] => Array ( [id] => 13 [name] => Home [urlslug] => home [parent_id] => 1 [page_title] => Welcome to KIAMS, Pune [order] => 1 ) ) [1] => Array ( [Sitepage] => Array ( [id] => 26 [name] => About Us [urlslug] => aboutus [parent_id] => 1 [page_title] => [order] => 2 ) ) [2] => Array ( [Sitepage] => Array ( [id] => 27 [name] => Overview of KIAMS [urlslug] => aboutus/overview [parent_id] => 26 [page_title] => [order] => 2 ) ) I retrieved the same data using $this-Sitepage-find('all') and then performed some manipulations as required and form a array which is very similar to the above one, but the ordering gets changed. I want to paginate this new array and pass it to the view. I tried $this->set('sitepages',$this->paginate($newarray)) But the data is not getting paginated. Can some one please help with paginating the $newarray in CakePHP?

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• Trouble recording unique regex output to array in perl

  - by Structure

  The goal of the following code sample is to read the contents of $target and assign all unique regex search results to an array. I have confirmed my regex statement works so I am simplifying that so as not to focus on it. When I execute the script I get a list of all the regex results, however, the results are not unique which leads me to believe that my manipulation of the array or my if (grep{$_ eq $1} @array) { check is causing a problem(s). #!/usr/bin/env perl $target = "string to search"; $inc = 0; $once = 1; while ($target =~ m/(regex)/g) { #While a regex result is returned if ($once) { #If $once is not equal to zero @array[$inc] = $1; #Set the first regex result equal to @array[0] $once = 0; #Set $once equal to zero so this is not executed more than once } else { if (grep{$_ eq $1 } @array ) { #From the second regex result, check to see if the result is already in the array #If so, do nothing } else { @array[$inc] = $1; #If it is not, then assign the regex search result to the next unused position in the array in any position. $inc++; #Increment to next unused array position. } } } print @array; exit 0;

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• php Getting the 'new' values in an array

  - by Mark

  Trying to learn about php's arrays today. I have a set of arrays like this: $a = array ( 0 => array ( 'value' => 'America', ), 1 => array ( 'value' => 'England', ), 2 => array ( 'value' => 'Australia', ), ) $b = array ( 0 => array ( 'value' => 'America', ), 1 => array ( 'value' => 'England', ), 2 => array ( 'value' => 'Canada', ), ) I need to get the 'new' subarrays that array b brings to the table. ie, I need to return array ( 'value' => 'Canada', ) I thought I could first merge $a+$b and then compare the result to $a. $merge = array_merge($a,$b); $result = array_diff($merge,$a); But somehow that does not work. It returns array() How come? And thanks!

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• How to convert this procedural programming to object-oriented programming?

  - by manus91

  I have a source code that is needed to be converted by creating classes, objects and methods. So far, I've just done by converting the initial main into a separate class. But I don't know what to do with constructor and which variables are supposed to be private. This is the code : import java.util.*; public class Card{ private static void shuffle(int[][] cards){ List<Integer> randoms = new ArrayList<Integer>(); Random randomizer = new Random(); for(int i = 0; i < 8;) { int r = randomizer.nextInt(8)+1; if(!randoms.contains(r)) { randoms.add(r); i++; } } List<Integer> clonedList = new ArrayList<Integer>(); clonedList.addAll(randoms); Collections.shuffle(clonedList); randoms.addAll(clonedList); Collections.shuffle(randoms); int i=0; for(int r=0; r < 4; r++){ for(int c=0; c < 4; c++){ cards[r][c] = randoms.get(i); i++; } } } public static void play() throws InterruptedException { int ans = 1; int preview; int r1,c1,r2,c2; int[][] cards = new int[4][4]; boolean[][] cardstatus = new boolean[4][4]; boolean gameover = false; int moves; Scanner input = new Scanner(System.in); do{ moves = 0; shuffle(cards); System.out.print("Enter the time(0 to 5) in seconds for the preview of the answer : "); preview = input.nextInt(); while((preview<0) || (preview>5)){ System.out.print("Invalid time!! Re-enter time(0 - 5) : "); preview = input.nextInt(); } preview = 1000*preview; System.out.println(" "); for (int i =0; i<4;i++){ for (int j=0;j<4;j++){ System.out.print(cards[i][j]); System.out.print(" "); } System.out.println(""); System.out.println(""); } Thread.sleep(preview); for(int b=0;b<25;b++){ System.out.println(" "); } for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ System.out.print("*"); System.out.print(" "); cardstatus[r][c] = false; } System.out.println(""); System.out.println(" "); } System.out.println(""); do{ do{ System.out.print("Please insert the first card row : "); r1 = input.nextInt(); while((r1<1) || (r1>4)){ System.out.print("Invalid coordinate!! Re-enter first card row : "); r1 = input.nextInt(); } System.out.print("Please insert the first card column : "); c1 = input.nextInt(); while((c1<1) || (c1>4)){ System.out.print("Invalid coordinate!! Re-enter first card column : "); c1 = input.nextInt(); } if(cardstatus[r1-1][c1-1] == true){ System.out.println("The card is already flipped!! Select another card."); System.out.println(""); } }while(cardstatus[r1-1][c1-1] != false); do{ System.out.print("Please insert the second card row : "); r2 = input.nextInt(); while((r2<1) || (r2>4)){ System.out.print("Invalid coordinate!! Re-enter second card row : "); r2 = input.nextInt(); } System.out.print("Please insert the second card column : "); c2 = input.nextInt(); while((c2<1) || (c2>4)){ System.out.print("Invalid coordinate!! Re-enter second card column : "); c2 = input.nextInt(); } if(cardstatus[r2-1][c2-1] == true){ System.out.println("The card is already flipped!! Select another card."); } if((r1==r2)&&(c1==c2)){ System.out.println("You can't select the same card twice!!"); continue; } }while(cardstatus[r2-1][c2-1] != false); r1--; c1--; r2--; c2--; System.out.println(""); System.out.println(""); System.out.println(""); for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ if((r==r1)&&(c==c1)){ System.out.print(cards[r][c]); System.out.print(" "); } else if((r==r2)&&(c==c2)){ System.out.print(cards[r][c]); System.out.print(" "); } else if(cardstatus[r][c] == true){ System.out.print(cards[r][c]); System.out.print(" "); } else{ System.out.print("*"); System.out.print(" "); } } System.out.println(" "); System.out.println(" "); } System.out.println(""); if(cards[r1][c1] == cards[r2][c2]){ System.out.println("Cards Matched!!"); cardstatus[r1][c1] = true; cardstatus[r2][c2] = true; } else{ System.out.println("No cards match!!"); } Thread.sleep(2000); for(int b=0;b<25;b++){ System.out.println(""); } for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ if(cardstatus[r][c] == true){ System.out.print(cards[r][c]); System.out.print(" "); } else{ System.out.print("*"); System.out.print(" "); } } System.out.println(""); System.out.println(" "); } System.out.println(""); System.out.println(""); System.out.println(""); gameover = true; for(int r=0;r<4;r++){ for( int c=0;c<4;c++){ if(cardstatus[r][c]==false){ gameover = false; break; } } if(gameover==false){ break; } } moves++; }while(gameover != true); System.out.println("Congratulations, you won!!"); System.out.println("It required " + moves + " moves to finish it."); System.out.println(""); System.out.print("Would you like to play again? (1=Yes / 0=No) : "); ans = input.nextInt(); }while(ans == 1); } } The main class is: import java.util.*; public class PlayCard{ public static void main(String[] args) throws InterruptedException{ Card game = new Card(); game.play(); } } Should I simplify the Card class by creating other classes? Through this code, my javadoc has no constructtor. So i need help on this!

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• How can I back up my ubuntu system?

  - by Eloff

  I'm sure there's a lot of questions on here similar to this, and I've been reading them, but I still feel this warrants a new question. I want nightly, incremental backups (full disk images would waste a lot of space - unless compressed somehow.) Preferably rotating or deleting old backups when running out of space or after a fixed number of backups. I want to be able to quickly and painlessly restore my system from these backups. This is my first time running ubuntu as my main development machine and I know from my experience with it as a server and in virtual machines that I regularly manage to make it unbootable or damage it to the point of being unable to rescue it. So how would you recommend I do this? There are so many options out there I really don't know where to start. There seems to be a vocal school of thought that it's sufficient to backup your home directory and the list of installed packages from the package manager. I've already installed lots of things from source, or outside of the package manager (development tools, ides, compilers, graphics drivers, etc.) So at the very least, if I do not back up the operating system itself I need to grab all config files, all program binaries, all created but required files, etc. I'd rather backup too much than too little - an ubuntu install is tiny anyway. Also this drastically reduces the restore time, which would cost me more in my time than the extra storage space. I tried using Deja Dup to backup the root partition, excluding some things like /mnt /media /dev /proc etc. Although many websites assured me you can backup a running linux system this way - that seems to be false as it complained that it could not backup the following files: /boot/System.map-3.0.0-17-generic /boot/System.map-3.2.0-22-generic /boot/vmcoreinfo-3.0.0-17-generic /boot/vmlinuz-3.0.0-17-generic /boot/vmlinuz-3.2.0-22-generic /etc/.pwd.lock /etc/NetworkManager/system-connections/LAN Connection /etc/apparmor.d/cache/lightdm-guest-session /etc/apparmor.d/cache/sbin.dhclient /etc/apparmor.d/cache/usr.bin.evince /etc/apparmor.d/cache/usr.lib.telepathy /etc/apparmor.d/cache/usr.sbin.cupsd /etc/apparmor.d/cache/usr.sbin.tcpdump /etc/apt/trustdb.gpg /etc/at.deny /etc/ati/inst_path_default /etc/ati/inst_path_override /etc/chatscripts /etc/cups/ssl /etc/cups/subscriptions.conf /etc/cups/subscriptions.conf.O /etc/default/cacerts /etc/fuse.conf /etc/group- /etc/gshadow /etc/gshadow- /etc/mtab.fuselock /etc/passwd- /etc/ppp/chap-secrets /etc/ppp/pap-secrets /etc/ppp/peers /etc/security/opasswd /etc/shadow /etc/shadow- /etc/ssl/private /etc/sudoers /etc/sudoers.d/README /etc/ufw/after.rules /etc/ufw/after6.rules /etc/ufw/before.rules /etc/ufw/before6.rules /lib/ufw/user.rules /lib/ufw/user6.rules /lost+found /root /run/crond.reboot /run/cups/certs /run/lightdm /run/lock/whoopsie/lock /run/udisks /var/backups/group.bak /var/backups/gshadow.bak /var/backups/passwd.bak /var/backups/shadow.bak /var/cache/apt/archives/lock /var/cache/cups/job.cache /var/cache/cups/job.cache.O /var/cache/cups/ppds.dat /var/cache/debconf/passwords.dat /var/cache/ldconfig /var/cache/lightdm/dmrc /var/crash/_usr_lib_x86_64-linux-gnu_colord_colord.102.crash /var/lib/apt/lists/lock /var/lib/dpkg/lock /var/lib/dpkg/triggers/Lock /var/lib/lightdm /var/lib/mlocate/mlocate.db /var/lib/polkit-1 /var/lib/sudo /var/lib/urandom/random-seed /var/lib/ureadahead/pack /var/lib/ureadahead/run.pack /var/log/btmp /var/log/installer/casper.log /var/log/installer/debug /var/log/installer/partman /var/log/installer/syslog /var/log/installer/version /var/log/lightdm/lightdm.log /var/log/lightdm/x-0-greeter.log /var/log/lightdm/x-0.log /var/log/speech-dispatcher /var/log/upstart/alsa-restore.log /var/log/upstart/alsa-restore.log.1.gz /var/log/upstart/console-setup.log /var/log/upstart/console-setup.log.1.gz /var/log/upstart/container-detect.log /var/log/upstart/container-detect.log.1.gz /var/log/upstart/hybrid-gfx.log /var/log/upstart/hybrid-gfx.log.1.gz /var/log/upstart/modemmanager.log /var/log/upstart/modemmanager.log.1.gz /var/log/upstart/module-init-tools.log /var/log/upstart/module-init-tools.log.1.gz /var/log/upstart/procps-static-network-up.log /var/log/upstart/procps-static-network-up.log.1.gz /var/log/upstart/procps-virtual-filesystems.log /var/log/upstart/procps-virtual-filesystems.log.1.gz /var/log/upstart/rsyslog.log /var/log/upstart/rsyslog.log.1.gz /var/log/upstart/ureadahead.log /var/log/upstart/ureadahead.log.1.gz /var/spool/anacron/cron.daily /var/spool/anacron/cron.monthly /var/spool/anacron/cron.weekly /var/spool/cron/atjobs /var/spool/cron/atspool /var/spool/cron/crontabs /var/spool/cups

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• Why Your ERP System Isn't Ready for the Next Evolution of the Enterprise

  - by ken.pulverman

    ERP has been the backbone of enterprise software.  The data held in your ERP system is core of most companies.  Efficiencies gained through the accounting and resource allocation through ERP software have literally saved companies trillions of dollars. Not only does everything seem to be fine with your ERP system, you haven't had to touch it in years.  Why aren't you ready for what comes next? Well judging by the growth rates in the space (Oracle posted only a 3% growth rate, while SAP showed a 12% decline) there hasn't been much modernization going on, just a little replacement activity. If you are like most companies, your ERP system is connected to a proprietary middleware solution that only effectively talks with a handful of other systems you might have acquired from the same vendor.   Connecting your legacy system through proprietary middleware is expensive and brittle and if you are like most companies, you were only willing to pay an SI so much before you said "enough."  So your ERP is working.  It's humming along.  You might not be able to get Order to Promise information when you take orders in your call center, but there are work arounds that work just fine. So what's the problem? The problem is that you built your business around your ERP core, and now there is such pressure to innovate your business processes to keep up that you need a whole new slew of modern apps and you need ERP data to be accessible from everywhere.   Every time you change a sales territory or a comp plan or change a benefits provider your ERP system, literally the economic brain of your business, needs to know what's going on.  And this giant need to access and provide information to your ERP is only growing. What makes matters even more challenging is that apps today come in every flavor under the Sun™.   SaaS, cloud, managed, hybrid, outsourced, composite....and they all have different integration protocols. The only easy way to get ahead of all this is to modernize the way you connect and run your applications.  Unlike the middleware solutions of yesteryear, modern middleware is effectively the operating system of the enterprise.  In the same way that you rely on Apple, Microsoft, and Google to find a video driver for your 23" monitor or to ensure the Word or Keynote runs, modern middleware takes care of intra-application connectivity and process execution.  It effectively allows you to take ERP out of the middle while ensuring connectivity to your vital data for anything you want to do.  The diagram below reflects that change.    In this model, the hegemony of ERP is over.  It too has to become a stealthy modern app to help you quickly adapt to business changes while managing vital information.  And through modern middleware it will connect to everything.  So yes ERP as we've know it is dead, but long live ERP as a connected application member of the modern enterprise. I want to Thank Andrew Zoldan, Group Vice President Oracle Manufacturing Industries Business Unit for introducing me to how some of his biggest customers have benefited by modernizing their applications infrastructure and making ERP a connected application. by John Burke, Group Vice President, Applications Business Unit

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• Why Your ERP System Isn't Ready for the Next Evolution of the Enterprise

  - by [email protected]

  By ken.pulverman on March 24, 2010 8:51 AM ERP has been the backbone of enterprise software. The data held in your ERP system is core of most companies. Efficiencies gained through the accounting and resource allocation through ERP software have literally saved companies trillions of dollars. Not only does everything seem to be fine with your ERP system, you haven't had to touch it in years. Why aren't you ready for what comes next? Well judging by the growth rates in the space (Oracle posted only a 3% growth rate, while SAP showed a 12% decline) there hasn't been much modernization going on, just a little replacement activity. If you are like most companies, your ERP system is connected to a proprietary middleware solution that only effectively talks with a handful of other systems you might have acquired from the same vendor. Connecting your legacy system through proprietary middleware is expensive and brittle and if you are like most companies, you were only willing to pay an SI so much before you said "enough." So your ERP is working. It's humming along. You might not be able to get Order to Promise information when you take orders in your call center, but there are work arounds that work just fine. So what's the problem? The problem is that you built your business around your ERP core, and now there is such pressure to innovate your business processes to keep up that you need a whole new slew of modern apps and you need ERP data to be accessible from everywhere. Every time you change a sales territory or a comp plan or change a benefits provider your ERP system, literally the economic brain of your business, needs to know what's going on. And this giant need to access and provide information to your ERP is only growing. What makes matters even more challenging is that apps today come in every flavor under the Sun™. SaaS, cloud, managed, hybrid, outsourced, composite....and they all have different integration protocols. The only easy way to get ahead of all this is to modernize the way you connect and run your applications. Unlike the middleware solutions of yesteryear, modern middleware is effectively the operating system of the enterprise. In the same way that you rely on Apple, Microsoft, and Google to find a video driver for your 23" monitor or to ensure that Word or Keynote runs, modern middleware takes care of intra-application connectivity and process execution. It effectively allows you to take ERP out of the middle while ensuring connectivity to your vital data for anything you want to do. The diagram below reflects that change. In this model, the hegemony of ERP is over. It too has to become a stealthy modern app to help you quickly adapt to business changes while managing vital information. And through modern middleware it will connect to everything. So yes ERP as we've know it is dead, but long live ERP as a connected application member of the modern enterprise. I want to Thank Andrew Zoldan, Group Vice President Oracle Manufacturing Industries Business Unit for introducing me to how some of his biggest customers have benefited by modernizing their applications infrastructure and making ERP a connected application. by John Burke, Group Vice President, Applications Business Unit

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• Populating a PHP array within a foreach loop

  - by patrick

  I am wanting to add each user into an array and check for duplicates before I do. $spotcount = 10; for ($topuser_count = 0; $topuser_count < $spotcount; $topuser_count++) //total spots { $spottop10 = $ids[$topuser_count]; $top_10 = $gowalla->getSpotInfo($spottop10); $usercount = 0; $c = 0; $array = array(); foreach($top_10['top_10'] as $top10) //loop each spot { //$getuser = substr($top10['url'],7); //strip the url $getuser = ltrim($top10['url'], " users/" ); if ($usercount < 3) //loop only certain number of top users { if (($getuser != $userurl) && (array_search($getuser, $array) !== true)) { //echo " no duplicates! <br /><br />"; echo ' <a href= "http://gowalla.com'.$top10['url'].'"><img width="90" height="90" src= " '.$top10['image_url'].' " title="'.$top10['first_name'].'" alt="Error" /></a> '; $array[$c++] = $getuser; } else { //echo "duplicate <br /><br />"; } } $usercount++; } print_r($array); } The previous code prints: Array ( [0] => 62151 [1] => 204501 [2] => 209368 ) Array ( [0] => 62151 [1] => 33116 [2] => 122485 ) Array ( [0] => 120728 [1] => 205247 [2] => 33116 ) Array ( [0] => 150883 [1] => 248551 [2] => 248558 ) Array ( [0] => 157580 [1] => 77490 [2] => 52046 ) Which is wrong. It does check for duplicates, but only the contents of each foreach loop instead of the entire array. How is this if I am storing everything into $array?

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