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  • TGT validation fails, but only for one user

    - by wzzrd
    I'm seeing the weirdest thing here. I have a couple of RHEL3, 4 and 5 machines that validate user credentials through Kerberos with an Active Directoy domain controller as their KDC. This works for all of my users, save one. There is one account that is unable to log into RHEL3 Linux machines and generates the following errors there: May 31 13:53:19 mybox sshd(pam_unix)[7186]: authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=10.0.0.1 user=user May 31 13:53:20 mybox sshd[7186]: pam_krb5: TGT verification failed for `user' May 31 13:53:20 mybox sshd[7186]: pam_krb5: authentication fails for `user' Other accounts, like my own, are fine: May 31 17:25:30 mybox sshd(pam_unix)[12913]: authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=10.0.0.1 user=myuser May 31 17:25:31 mybox sshd[12913]: pam_krb5: TGT for myuser successfully verified May 31 17:25:31 mybox sshd[12913]: pam_krb5: authentication succeeds for `myuser' May 31 17:25:31 mybox sshd(pam_unix)[12915]: session opened for user myuser by (uid=0) As you can see, TGT validation fails. This only happens for this specific account, not for any other. The failing useraccount's password has been reset, I inspected both user objects in Active Directory, but I see nothing out of the ordinary. If I have the failing useraccount log into a RHEL4 or 5 box, there is not problem, so it must be RHEL3 specific, but the fact that only one account suffers from this, alludes me. Maybe someone has seen this before?

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  • Twin Cities Connected Systems User Group Meeting - March 11th, 2010

    If you are in are in Minneapolis on Thursday March 11th please join us for the Twin Cities Connected Systems User Group Meeting. The meeting takes place at 6:00 p.m. at the Microsoft offices at 8300 Norman Center Drive, Bloomington, MN 55437.  I will be speaking on How to Create Windows Server AppFabric Applications Here is a write-up of what will be covered: You have heard about Dublin, now called Windows Server AppFabric, but do you know what it is and what it includes?  Do you know...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Completing a Basic ASP.NET 3.5 User Input Validation Project

    You learned the basics and configuration steps of the most common types of validation web controls used in ASP.NET 3.5 in the first two parts of this tutorial series. In this last part you will learn how to integrate all of these validation web controls in a working ASP.NET project. You will also learn not only how to validate user input in the client side but also how to validate the page on the server side.... Microsoft SQL Server? Value Calculator Reduce Costs & Increase Value with Microsoft SQL Server? 2008. Download Today!

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  • API to UPDATE Oracle FND User

    - by PRajkumar
    API - fnd_user_pkg.updateuser Example -- Consider a FND User having following Details --     Lets Try to Update its Email Id from [email protected] to [email protected]   -- ------------------------------------------------ -- API to UPDATE Oracle FND User -- ------------------------------------------------ DECLARE     lc_user_name                           VARCHAR2(100)   := 'PRAJ_TEST';     lc_user_password                   VARCHAR2(100)   := 'Oracle123';     ld_user_start_date                   DATE                      := TO_DATE('23-JUN-2012');     ld_user_end_date                    VARCHAR2(100)  := NULL;     ld_password_date                   VARCHAR2(100)  := TO_DATE('23-JUN-2012');     ld_password_lifespan_days  NUMBER               := 90;     ln_person_id                            NUMBER                := 32979;     lc_email_address                     VARCHAR2(100)  := '[email protected]'; BEGIN    fnd_user_pkg.updateuser    (  x_user_name                           => lc_user_name,       x_owner                                   => NULL,       x_unencrypted_password    => lc_user_password,       x_start_date                             => ld_user_start_date,       x_end_date                              => ld_user_end_date,       x_password_date                   => ld_password_date,       x_password_lifespan_days  => ld_password_lifespan_days,       x_employee_id                       => ln_person_id,       x_email_address                    => lc_email_address    );  COMMIT; EXCEPTION     WHEN OTHERS THEN                       ROLLBACK;                       DBMS_OUTPUT.PUT_LINE(SQLERRM); END; / SHOW ERR;       

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  • User input and automated input separation

    - by tpaksu
    I have a MySQL database and an automation script which modifies the data inside once a day. And these columns may have changed by an user manually. What is the best approach to make the system only update the automated data, not the manually edited ones? I mean yes, flagging the cell which is manually edited is one way to do it, but I want to know if there's another way to accomplish this? Just curiosity. BTW, the question is about cell values, not rows.

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  • User Password I didn't even know of [duplicate]

    - by KiriharaAkaya
    This question already has an answer here: How do I reset a lost administrative password? 13 answers I'm a new user of Ubuntu and I installed it on my computer using Virtual Box. I've been trying to install Java JDK for the past two hours without any success because when I try to do so, Terminal asks for my password, which I don't even remember creating. Can someone please help and tell me how am I suppose to change the password in order to install JDK? It will be very much appreciated, thank you.

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  • Implementing EAV pattern with Hibernate for User -> Settings relationship

    - by Trevor
    I'm trying to setup a simple EAV pattern in my web app using Java/Spring MVC and Hibernate. I can't seem to figure out the magic behind the hibernate XML setup for this scenario. My database table "SETUP" has three columns: user_id (FK) setup_item setup_value The database composite key is made up of user_id | setup_item Here's the Setup.java class: public class Setup implements CommonFormElements, Serializable { private Map data = new HashMap(); private String saveAction; private Integer speciesNamingList; private User user; Logger log = LoggerFactory.getLogger(Setup.class); public String getSaveAction() { return saveAction; } public void setSaveAction(String action) { this.saveAction = action; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public Integer getSpeciesNamingList() { return speciesNamingList; } public void setSpeciesNamingList(Integer speciesNamingList) { this.speciesNamingList = speciesNamingList; } public Map getData() { return data; } public void setData(Map data) { this.data = data; } } My problem with the Hibernate setup, is that I can't seem to figure out how to map out the fact that a foreign key and the key of a map will construct the composite key of the table... this is due to a lack of experience using Hibernate. Here's my initial attempt at getting this to work: <composite-id> <key-many-to-one foreign-key="id" name="user" column="user_id" class="Business.User"> <meta attribute="use-in-equals">true</meta> </key-many-to-one> </composite-id> <map lazy="false" name="data" table="setup"> <key column="user_id" property-ref="user"/> <composite-map-key class="Command.Setup"> <key-property name="data" column="setup_item" type="string"/> </composite-map-key> <element column="setup_value" not-null="true" type="string"/> </map> Any insight into how to properly map this common scenario would be most appreciated!

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  • User Mailer Failing

    - by Trevor Nederlof
    I have setup a process in my User model to send a bunch of @users to a mailing script, user_mailer.rb I am using the http://postageapp.com app to send out emails. The users are getting to the User_mailer but I am getting an error from there. Can anyone please point me in the right direction. User Model: class User < ActiveRecord::Base acts_as_authentic def self.mail_out weekday = Date.today.strftime('%A').downcase @users = find(:all, :conditions => {"#{weekday}sub".to_sym => 't'}) UserMailer.deliver_mail_out(@users) end end User_mailer.rb class UserMailer < ActionMailer::Base def mail_out(users) @recipients = { } users.each do |user| @recipients[user.email] = { :zipcode => user.zipcode } end from "[email protected]" subject "Check out the trailer of the day!" body :user => user end end mail_out.html.erb {{zipcode}}, Please check out the trailer of the day at http://www.dailytrailer.net Thank you! -- The DailyTrailer.net Team User db schema create_table "users", :force => true do |t| t.string "email" t.date "birthday" t.string "gender" t.string "zipcode" t.datetime "created_at" t.datetime "updated_at" t.string "crypted_password" t.string "password_salt" t.string "persistence_token" t.string "mondaysub", :default => "f", :null => false t.string "tuesdaysub", :default => "f", :null => false t.string "wednesdaysub", :default => "f", :null => false t.string "thursdaysub", :default => "f", :null => false t.string "fridaysub", :default => "f", :null => false t.string "saturdaysub", :default => "f", :null => false t.string "sundaysub", :default => "f", :null => false end Error: /var/lib/gems/1.8/gems/rails-2.3.5/lib/commands/runner.rb:48: undefined method `name' for #<User:0xb6e8ae48> (NoMethodError) from /home/tnederlof/Dropbox/Ruby/daily_trailer/app/models/user_mailer.rb:5:in `mail_out' from /home/tnederlof/Dropbox/Ruby/daily_trailer/app/models/user_mailer.rb:4:in `each' from /home/tnederlof/Dropbox/Ruby/daily_trailer/app/models/user_mailer.rb:4:in `mail_out' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:459:in `__send__' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:459:in `create!' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:452:in `initialize' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:395:in `new' from /home/tnederlof/.gem/ruby/1.8/gems/actionmailer-2.3.5/lib/action_mailer/base.rb:395:in `method_missing' from /home/tnederlof/Dropbox/Ruby/daily_trailer/app/models/user.rb:13:in `mail_out' from (eval):1 from /usr/lib/ruby/1.8/rubygems/custom_require.rb:31:in `eval' from /var/lib/gems/1.8/gems/rails-2.3.5/lib/commands/runner.rb:48 from /usr/lib/ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /usr/lib/ruby/1.8/rubygems/custom_require.rb:31:in `require' from script/runner:3

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  • Best way to ask confirmation from user before leaving the page

    - by JohnathanKong
    Hey Everyone, I am currently building a registration page where if the user leaves, I want to pop up a CSS box asking him if he is sure or not. I can accomplish this feat using confirm boxes, but the client says that they are too ugly. I've tried using unload and beforeunload, but both cannot stop the page from being redirected. Using those to events, I return false, so maybe there's a way to cancel other than returning false? Another solution that I've had was redirecting them to another page that has my popup, but the problem with that is that if they do want to leave the page, and it wasn't a mistake, they lose the page they were originally trying to go to. If I was a user, that would irritate me. The last solution was real popup window. The only thing I don't like about that is that the main winow will have their destination page while the pop will have my page. In my opinion it looks disjoint. On top of that, I'd be worried about popup blockers. Just to add to everyones comments. I understand that it is irritating to prevent users from exiting the page, and in my opinion it should not be done. Right now I am using a confirm box at this point. What happens is that it's not actually "preventing" the user from leaving, what the client actually wants to do is make a suggestion if the user is having doubts about registering. If the user is halfway through the registraiton process and leaves for some reason, the client wants to offer the user a free coupon to a seminar (this client is selling seminars) to hopefully persuade the user to register. The client is under the impression that since the user is already on the form, he is thinking of registering, and therefore maybe a seminar of what he is registering for would be the final push to get the user to register. Ideally I don't have to prevent the user from leaving, what would be just as good, and in my opinion better is if I can pause the unload process. Maybe a sleep command? I don't really have to keep the user on the page because either way they will be leaving to go to a different page. Also, as people have stated, this is a terriable title, so if someone knows a better one, I'd really appreciate it if they could change the title to something no so spammer inviting.

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  • Sharepoint AD imported users are becomming sporadically corrupted, causing us to have to create a new account

    - by TrevJen
    Sharepoint 2007 MOSS with AD imported users. All servers are 2008. ***UPDATE More details in testing. This Sharepoint is in an AD Child domain (clients.mycompany.local), which is sub to the root of the AD tree (mycompany.local). The user is in the parent tree (as are half of the other functional users. I have elevated the user rights to Domain. In looking at the logs, it seems that the Sharepoint server is trying to authenticate them by querying the DC for the clients domain (which is the way it normally works and still works for all existing identically configured users). I think if I could force it to authenticate up to the top domain DC then it would be ok?? I have around 50 users, over the past 2 months, I have had a handful of the users suddenly unable to login to Sharepoint. When they login, they either get a blank screen or they are repropmted. These users are using accounts that have been used for many months, sometimes the problem originates with a password change. In all cases, the users account works on every other Active Directory authenticated resource (domain, exchange, LDAP). In the most recent case, last night I was forced deleted a user ("John smith") because of corruption. The orifinal account name was jsmith. I deleted him from active directory, then deleted him from the profile list in Sharepoint Shared Services. I could not find a way to delete him from the Sharepoint user list, but I reran the import after recreating his account (renamed it too just to be sure to "smithj"). At first, this did not wor, the user could still access all other resources but Sharepoint. then, some 30 minutes later it inexplicably started working. This morning, the user changed passwords, which immediatly broke the login on Sharepoint again. Logs by request from matt b Office SharePoint Server Date: 4/13/2010 2:00:00 PM Event ID: 7888 Task Category: Office Server General Level: Error Keywords: Classic User: N/A Computer: nb-portal-01.clients.netboundary.local Description: A runtime exception was detected. Details follow. Message: Access is denied. (Exception from HRESULT: 0x80070005 (E_ACCESSDENIED)) – TrevJen 19 hours ago Techinal Details: System.UnauthorizedAccessException: Access is denied. (Exception from HRESULT: 0x80070005 (E_ACCESSDENIED)) at Microsoft.SharePoint.SPGlobal.HandleUnauthorizedAccessException(UnauthorizedAccessException ex) at Microsoft.SharePoint.Library.SPRequest.UpdateField(String bstrUrl, String bstrListName, String bstrXML) at Microsoft.SharePoint.SPField.UpdateCore(Boolean bToggleSealed) – TrevJen 19 hours ago at Microsoft.SharePoint.SPField.Update() at Microsoft.Office.Server.UserProfiles.SiteSynchronizer.UserSynchronizer.PushSchemaToList(Boolean& bAddedColumn) at Microsoft.Office.Server.UserProfiles.SiteSynchronizer.UserSynchronizer.SynchFull() at Microsoft.Office.Server.UserProfiles.SiteSynchronizer.Synch() at Microsoft.Office.Server.Diagnostics.FirstChanceHandler.ExceptionFilter(Boolean fRethrowException, TryBlock tryBlock, FilterBlock filter, CatchBlock catchBlock, FinallyBlock finallyBlock) – TrevJen 19 hours ago Log Name: Application Source: Office SharePoint Server Date: 4/13/2010 2:00:00 PM Event ID: 5553 Task Category: User Profiles Level: Error Keywords: Classic User: N/A Computer: nb-portal-01.clients.netboundary.local Description: failure trying to synch site 6fea15e2-0899-4c19-9016-44d77834c018 for ContentDB b2002b0b-3d4c-411a-8c4f-3d047ca9322c WebApp 3aff7051-455d-4a70-a377-5b1c36df618e. Exception message was Access is denied. (Exception from HRESULT: 0x80070005 (E_ACCESSDENIED)). – TrevJen 18 hours ago

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  • File Not Found error launching Guest OS in a non-administrator user account

    - by ToreTrygg
    Hi, I am running Fusion 2.0.6 (196839) on an iMac running 10.6.2 with 3 user accounts (1 Administrator). I have Fusion set up to share the Guest OS, and it's been working splendidly for nearly a year. Within the Guest OS (Windows XP PRO), there are also 3 user accounts (1 Administrator). Last night I went to back up my VM to an external drive, and to minimize the file size and transfer time, I deleted all Snapshots but the most-recent one. I then backed up the VM externally (28.23 GB). Today, one of my users tried to launch the Guest OS from within her user account, and received the following error message: "File Not Found: Windows XP Pro-000006.vmdk "This file is required to power on this virtual machine. If this file was moved, please provide its new location." My two choices are Cancel and Browse. When I browse, I can locate the Windows XP Pro-000006.vmdk file, which appears to be contained within the VM file (Windows XP Pro.vmwarevm). However, it still won't launch from a non-Admin user account. If I view the package contents of the VM file from the user account, the above file is present and appears to be created upon each launch of the Guest OS. If I go back to my Administrator account on the Mac and then launch Fusion, the Guest OS works perfectly for all 3 user accounts within XP Pro. I have tried to delete the Guest OS from Fusion's Library within the problem user account, then re-connect it to that Library, but the result is the same. The Guest OS data integrity is 100% -- but is accessible only from the OS X Administrator account. This problem only surfaced after deleting several older Snapshots. Again, the data is there, the Guest OS powers up normally in the Mac's Administrator account, but persistently returns the above error when attempting to power on from a non-Admin account on the Mac. I'm not sure how this is affecting the error, but when I look at Hard Disk Settings, the "unable-to-locate" file is the filename of the virtual HD. I don't want to make any changes to my (working) VM without any advice from the knowledgeable people on this forum. Any help will be greatly appreciated, thanks!

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  • Add user in CentOS 5

    - by Ron
    I created a new user in my CentOS web server with useradd. Added a password with passwd. But I can't log in with the user via SSH. I keep getting 'access denied'. I checked to make sure that the password was assigned and that the account is active. /var/log/secure shows the following error: Aug 13 03:41:40 server1 su: pam_unix(su:auth): authentication failure; logname= uid=500 euid=0 tty=pts/0 ruser=rwade rhost= user=root Please help, Thanks Thanks for the responses so far: I should add that it is a VPS on a remote computer, fresh out of the box. I can log in as the root user quite fine. I can also su to the new user, but I cannot log in as the new user. Here is my sshd_config file: # $OpenBSD: sshd_config,v 1.73 2005/12/06 22:38:28 reyk Exp $ # This is the sshd server system-wide configuration file. See # sshd_config(5) for more information. # This sshd was compiled with PATH=/usr/local/bin:/bin:/usr/bin # The strategy used for options in the default sshd_config shipped with # OpenSSH is to specify options with their default value where # possible, but leave them commented. Uncommented options change a # default value. #Port 22 #Protocol 2,1 Protocol 2 #AddressFamily any #ListenAddress 0.0.0.0 #ListenAddress :: # HostKey for protocol version 1 #HostKey /etc/ssh/ssh_host_key # HostKeys for protocol version 2 #HostKey /etc/ssh/ssh_host_rsa_key #HostKey /etc/ssh/ssh_host_dsa_key # Lifetime and size of ephemeral version 1 server key #KeyRegenerationInterval 1h #ServerKeyBits 768 # Logging # obsoletes QuietMode and FascistLogging #SyslogFacility AUTH SyslogFacility AUTHPRIV #LogLevel INFO # Authentication: #LoginGraceTime 2m #PermitRootLogin yes #StrictModes yes #MaxAuthTries 6 #RSAAuthentication yes #PubkeyAuthentication yes #AuthorizedKeysFile .ssh/authorized_keys # For this to work you will also need host keys in /etc/ssh/ssh_known_hosts #RhostsRSAAuthentication no # similar for protocol version 2 #HostbasedAuthentication no # Change to yes if you don't trust ~/.ssh/known_hosts for # RhostsRSAAuthentication and HostbasedAuthentication #IgnoreUserKnownHosts no # Don't read the user's ~/.rhosts and ~/.shosts files #IgnoreRhosts yes # To disable tunneled clear text passwords, change to no here! #PasswordAuthentication yes #PermitEmptyPasswords no PasswordAuthentication yes # Change to no to disable s/key passwords #ChallengeResponseAuthentication yes ChallengeResponseAuthentication no # Kerberos options #KerberosAuthentication no #KerberosOrLocalPasswd yes #KerberosTicketCleanup yes #KerberosGetAFSToken no # GSSAPI options #GSSAPIAuthentication no GSSAPIAuthentication yes #GSSAPICleanupCredentials yes GSSAPICleanupCredentials yes # Set this to 'yes' to enable PAM authentication, account processing, # and session processing. If this is enabled, PAM authentication will # be allowed through the ChallengeResponseAuthentication mechanism. # Depending on your PAM configuration, this may bypass the setting of # PasswordAuthentication, PermitEmptyPasswords, and # "PermitRootLogin without-password". If you just want the PAM account and # session checks to run without PAM authentication, then enable this but set # ChallengeResponseAuthentication=no #UsePAM no UsePAM yes # Accept locale-related environment variables AcceptEnv LANG LC_CTYPE LC_NUMERIC LC_TIME LC_COLLATE LC_MONETARY LC_MESSAGES AcceptEnv LC_PAPER LC_NAME LC_ADDRESS LC_TELEPHONE LC_MEASUREMENT AcceptEnv LC_IDENTIFICATION LC_ALL #AllowTcpForwarding yes #GatewayPorts no #X11Forwarding no X11Forwarding yes #X11DisplayOffset 10 #X11UseLocalhost yes #PrintMotd yes #PrintLastLog yes #TCPKeepAlive yes #UseLogin no #UsePrivilegeSeparation yes #PermitUserEnvironment no #Compression delayed #ClientAliveInterval 0 #ClientAliveCountMax 3 #ShowPatchLevel no #UseDNS yes #PidFile /var/run/sshd.pid #MaxStartups 10 #PermitTunnel no #ChrootDirectory none # no default banner path #Banner /some/path # override default of no subsystems Subsystem sftp /usr/libexec/openssh/sftp-server

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  • Add user in CentOS 5

    - by Ron
    I created a new user in my CentOS web server with useradd. Added a password with passwd. But I can't log in with the user via SSH. I keep getting 'access denied'. I checked to make sure that the password was assigned and that the account is active. /var/log/secure shows the following error: Aug 13 03:41:40 server1 su: pam_unix(su:auth): authentication failure; logname= uid=500 euid=0 tty=pts/0 ruser=rwade rhost= user=root Please help, Thanks Thanks for the responses so far: I should add that it is a VPS on a remote computer, fresh out of the box. I can log in as the root user quite fine. I can also su to the new user, but I cannot log in as the new user. Here is my sshd_config file: # $OpenBSD: sshd_config,v 1.73 2005/12/06 22:38:28 reyk Exp $ # This is the sshd server system-wide configuration file. See # sshd_config(5) for more information. # This sshd was compiled with PATH=/usr/local/bin:/bin:/usr/bin # The strategy used for options in the default sshd_config shipped with # OpenSSH is to specify options with their default value where # possible, but leave them commented. Uncommented options change a # default value. #Port 22 #Protocol 2,1 Protocol 2 #AddressFamily any #ListenAddress 0.0.0.0 #ListenAddress :: # HostKey for protocol version 1 #HostKey /etc/ssh/ssh_host_key # HostKeys for protocol version 2 #HostKey /etc/ssh/ssh_host_rsa_key #HostKey /etc/ssh/ssh_host_dsa_key # Lifetime and size of ephemeral version 1 server key #KeyRegenerationInterval 1h #ServerKeyBits 768 # Logging # obsoletes QuietMode and FascistLogging #SyslogFacility AUTH SyslogFacility AUTHPRIV #LogLevel INFO # Authentication: #LoginGraceTime 2m #PermitRootLogin yes #StrictModes yes #MaxAuthTries 6 #RSAAuthentication yes #PubkeyAuthentication yes #AuthorizedKeysFile .ssh/authorized_keys # For this to work you will also need host keys in /etc/ssh/ssh_known_hosts #RhostsRSAAuthentication no # similar for protocol version 2 #HostbasedAuthentication no # Change to yes if you don't trust ~/.ssh/known_hosts for # RhostsRSAAuthentication and HostbasedAuthentication #IgnoreUserKnownHosts no # Don't read the user's ~/.rhosts and ~/.shosts files #IgnoreRhosts yes # To disable tunneled clear text passwords, change to no here! #PasswordAuthentication yes #PermitEmptyPasswords no PasswordAuthentication yes # Change to no to disable s/key passwords #ChallengeResponseAuthentication yes ChallengeResponseAuthentication no # Kerberos options #KerberosAuthentication no #KerberosOrLocalPasswd yes #KerberosTicketCleanup yes #KerberosGetAFSToken no # GSSAPI options #GSSAPIAuthentication no GSSAPIAuthentication yes #GSSAPICleanupCredentials yes GSSAPICleanupCredentials yes # Set this to 'yes' to enable PAM authentication, account processing, # and session processing. If this is enabled, PAM authentication will # be allowed through the ChallengeResponseAuthentication mechanism. # Depending on your PAM configuration, this may bypass the setting of # PasswordAuthentication, PermitEmptyPasswords, and # "PermitRootLogin without-password". If you just want the PAM account and # session checks to run without PAM authentication, then enable this but set # ChallengeResponseAuthentication=no #UsePAM no UsePAM yes # Accept locale-related environment variables AcceptEnv LANG LC_CTYPE LC_NUMERIC LC_TIME LC_COLLATE LC_MONETARY LC_MESSAGES AcceptEnv LC_PAPER LC_NAME LC_ADDRESS LC_TELEPHONE LC_MEASUREMENT AcceptEnv LC_IDENTIFICATION LC_ALL #AllowTcpForwarding yes #GatewayPorts no #X11Forwarding no X11Forwarding yes #X11DisplayOffset 10 #X11UseLocalhost yes #PrintMotd yes #PrintLastLog yes #TCPKeepAlive yes #UseLogin no #UsePrivilegeSeparation yes #PermitUserEnvironment no #Compression delayed #ClientAliveInterval 0 #ClientAliveCountMax 3 #ShowPatchLevel no #UseDNS yes #PidFile /var/run/sshd.pid #MaxStartups 10 #PermitTunnel no #ChrootDirectory none # no default banner path #Banner /some/path # override default of no subsystems Subsystem sftp /usr/libexec/openssh/sftp-server

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  • Very simply, how can check if a user exists against my MySQL database?

    - by Sergio Tapia
    Here's what I have but nothing is output to the screen. :\ <html> <head> </head> <body> <? mysql_connect(localhost, "sergio", "123"); @mysql_select_db("multas") or die( "Unable to select database"); $query="SELECT * FROM usuario"; $result=mysql_query($query); $num=mysql_numrows($result); $i=0; $username=GET["u"]; $password=GET["p"]; while ($i < $num) { $dbusername=mysql_result($result,$i,"username"); $dbpassword=mysql_result($result,$i,"password"); if(($username == $dbusername) && ($password == $dbpassword)){ echo "si"; } $i++; } ?> </body> </html> I'm iterating through all users and seeing if there is a match for user && password. Any guidance?

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  • Feedback on meeting of the Linux User Group of Mauritius

    Once upon a time in a country far far away... Okay, actually it's not that bad but it has been a while since the last meeting of the Linux User Group of Mauritius (LUGM). There have been plans in the past but it never really happened. Finally, Selven took the opportunity and organised a new meetup with low administrative overhead, proper scheduling on alternative dates and a small attendee's survey on the preferred option. All the pre-work was nicely executed. First, I wasn't sure whether it would be possible to attend. Luckily I got some additional information, like children should come, too, and I was sold to this community gathering. According to other long-term members of the LUGM it was the first time 'ever' that a gathering was organised outside of Quatre Bornes, and I have to admit it was great! LUGM - user group meeting on the 15.06.2013 in L'Escalier Quick overview of Linux & the LUGM With a little bit of delay the LUGM meeting officially started with a quick overview and introduction to Linux presented by Avinash. During the session he told the audience that there had been quite some activity over the island some years ago but unfortunately it had been quiet during recent times. Of course, we also spoke about the acknowledged world dominance of Linux - thanks to Android - and the interesting possibilities for countries like Mauritius. It is known that a couple of public institutions have there back-end infrastructure running on Red Hat Linux systems but the presence on the desktop is still very low. Users are simply hanging on to Windows XP and older versions of Microsoft Office. Following the introduction of the LUGM Ajay joined into the session and it quickly changed into a panel discussion with lots of interesting questions and answers, sharing of first-hand experience either on the job or in private use of Linux, and a couple of ideas about how the LUGM could promote Linux a bit more in Mauritius. It was great to get an insight into other attendee's opinion and activities. Especially taking into consideration that I'm already using Linux since around 1996/97. Frankly speaking, I bought a SuSE 4.x distribution back in those days because I couldn't achieve certain tasks on Windows NT 4.0 without spending a fortune. OpenELEC Mediacenter Next, Selven gave us decent introduction on OpenELEC: Open Embedded Linux Entertainment Center (OpenELEC) is a small Linux distribution built from scratch as a platform to turn your computer into an XBMC media center. OpenELEC is designed to make your system boot fast, and the install is so easy that anyone can turn a blank PC into a media machine in less than 15 minutes. I didn't know about it until this presentation. In the past, I was mainly attached to Video Disk Recorder (VDR) as it allows the use of satellite receiver cards very easily. Hm, somehow I'm still missing my precious HTPC that I had to leave back in Germany years ago. It was great piece of hardware and software; self-built PC in a standard HiFi-sized (43cm) black desktop casing with 2 full-featured Hauppauge DVB-s cards, an old-fashioned Voodoo graphics card, WiFi card, Pioneer slot-in DVD drive, and fully remote controlled via infra-red thanks to Debian, VDR and LIRC. With EP Guide, scheduled recordings and general multimedia centre it offered all the necessary comfort in the living room, besides a Nintendo game console; actually a GameCube at that time... But I have to admit that putting OpenELEC on a Raspberry Pi would be a cool DIY project in the near future. LUGM - our next generation of linux users (15.06.2013) Project Evil Genius (PEG) Don't be scared of the paragraph header. Ish gave us a cool explanation why he named it PEG - Project Evil Genius; it's because of the time of the day when he was scripting down his ideas to be able to build, package and provide software applications to various Linux distributions. The main influence came from openSuSE but the platform didn't cater for his needs and ideas, so he started to work out something on his own. During his passionate session he also talked about the amazing experience he had due to other Linux users from all over the world. During the next couple of days Ish promised to put his script to GitHub... Looking forward to that. Check out Ish's personal blog over at hacklog.in. Highly recommended to read. Why India? Simply because the registration fees per year for an Indian domain are approximately 20 times less than for a Mauritian domain (.mu). Exploring the beach of L'Escalier af the meeting 'After-party' at the beach of L'Escalier Puh, after such interesting sessions, ideas around Linux and good conversation during the breaks and over lunch it was time for a little break-out. Selven suggested that we all should head down to the beach of L'Escalier and get some impressions of nature down here in the south of the island. Talking about 'beach' ;-) - absolutely not comparable to the white-sanded ones here in Flic en Flac... There are no lagoons down at the south coast of Mauriitus, and watching the breaking waves is a different experience and joy after all. Unfortunately, I was a little bit worried about the thoughtless littering at such a remote location. You have to drive on natural paths through the sugar cane fields and I was really shocked by the amount of rubbish lying around almost everywhere. Sad, really sad and it concurs with Yasir's recent article on the same topic. Resumé & outlook It was a great event. I met with new people, had some good conversations, and even my children enjoyed themselves the whole day. The location was well-chosen, enough space for each and everyone, parking spaces and even a playground for the children. Also, a big "Thank You" to Selven and his helpers for the organisation and preparation of lunch. I'm kind of sure that this was an exceptional meeting of LUGM and I'm really looking forward to the next gathering of Linux geeks. Hopefully, soon. All images are courtesy of Avinash Meetoo. More pictures are available on Flickr.

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  • Delight and Excite

    - by Applications User Experience
    Mick McGee, CEO & President, EchoUser Editor’s Note: EchoUser is a User Experience design firm in San Francisco and a member of the Oracle Usability Advisory Board. Mick and his staff regularly consult on Oracle Applications UX projects. Being part of a user experience design firm, we have the luxury of working with a lot of great people across many great companies. We get to help people solve their problems.  At least we used to. The basic design challenge is still the same; however, the goal is not necessarily to solve “problems” anymore; it is, “I want our products to delight and excite!” The question for us as UX professionals is how to design to those goals, and then how to assess them from a usability perspective. I’m not sure where I first heard “delight and excite” (A book? blog post? Facebook  status? Steve Jobs quote?), but now I hear these listed as user experience goals all the time. In particular, somewhat paradoxically, I routinely hear them in enterprise software conversations. And when asking these same enterprise companies what will make the project successful, we very often hear, “Make it like Apple.” In past days, it was “make it like Yahoo (or Amazon or Google“) but now Apple is the common benchmark. Steve Jobs and Apple were not secrets, but with Jobs’ passing and Apple becoming the world’s most valuable company in the last year, the impact of great design and experience is suddenly very widespread. In particular, users’ expectations have gone way up. Being an enterprise company is no shield to the general expectations that users now have, for all products. Designing a “Minimum Viable Product” The user experience challenge has historically been, to echo the words of Eric Ries (author of Lean Startup) , to create a “minimum viable product”: the proverbial, “make it good enough”. But, in our profession, the “minimum viable” part of that phrase has oftentimes, unfortunately, referred to the design and user experience. Technology typically dominated the focus of the biggest, most successful companies. Few have had the laser focus of Apple to also create and sell design and user experience alongside great technology. But now that Apple is the most valuable company in the world, copying their success is a common undertaking. Great design is now a premium offering that everyone wants, from the one-person startup to the largest companies, consumer and enterprise. This emerging business paradigm will have significant impact across the user experience design process and profession. One area that particularly interests me is, how are we going to evaluate these new emerging “delight and excite” experiences, which are further customized to each particular domain? How to Measure “Delight and Excite” Traditional usability measures of task completion rate, assists, time, and errors are still extremely useful in many situations; however, they are too blunt to offer much insight into emerging experiences “Satisfaction” is usually assessed in user testing, in roughly equivalent importance to the above objective metrics. Various surveys and scales have provided ways to measure satisfying UX, with whatever questions they include. However, to meet the demands of new business goals and keep users at the center of design and development processes, we have to explore new methods to better capture custom-experience goals and emotion-driven user responses. We have had success assessing custom experiences, including “delight and excite”, by employing a variety of user testing methods that tend to combine formative and summative techniques (formative being focused more on identifying usability issues and ways to improve design, and summative focused more on metrics). Our most successful tool has been one we’ve been using for a long time, Magnitude Estimation Technique (MET). But it’s not necessarily about MET as a measure, rather how it is created. Caption: For one client, EchoUser did two rounds of testing.  Each test was a mix of performing representative tasks and gathering qualitative impressions. Each user participated in an in-person moderated 1-on-1 session for 1 hour, using a testing set-up where they held the phone. The primary goal was to identify usability issues and recommend design improvements. MET is based on a definition of the desired experience, which users will then use to rate items of interest (usually tasks in a usability test). In other words, a custom experience definition needs to be created. This can then be used to measure satisfaction in accomplishing tasks; “delight and excite”; or anything else from strategic goals, user demands, or elsewhere. For reference, our standard MET definition in usability testing is: “User experience is your perception of how easy to use, well designed and productive an interface is to complete tasks.” Articulating the User Experience We’ve helped construct experience definitions for several clients to better match their business goals. One example is a modification of the above that was needed for a company that makes medical-related products: “User experience is your perception of how easy to use, well-designed, productive and safe an interface is for conducting tasks. ‘Safe’ is how free an environment (including devices, software, facilities, people, etc.) is from danger, risk, and injury.” Another example is from a company that is pushing hard to incorporate “delight” into their enterprise business line: “User experience is your perception of a product’s ease of use and learning, satisfaction and delight in design, and ability to accomplish objectives.” I find the last one particularly compelling in that there is little that identifies the experience as being for a highly technical enterprise application. That definition could easily be applied to any number of consumer products. We have gone further than the above, including “sexy” and “cool” where decision-makers insisted they were part of the desired experience. We also applied it to completely different experiences where the “interface” was, for example, riding public transit, the “tasks” were train rides, and we followed the participants through the train-riding journey and rated various aspects accordingly: “A good public transportation experience is a cost-effective way of reliably, conveniently, and safely getting me to my intended destination on time.” To construct these definitions, we’ve employed both bottom-up and top-down approaches, depending on circumstances. For bottom-up, user inputs help dictate the terms that best fit the desired experience (usually by way of cluster and factor analysis). Top-down depends on strategic, visionary goals expressed by upper management that we then attempt to integrate into product development (e.g., “delight and excite”). We like a combination of both approaches to push the innovation envelope, but still be mindful of current user concerns. Hopefully the idea of crafting your own custom experience, and a way to measure it, can provide you with some ideas how you can adapt your user experience needs to whatever company you are in. Whether product-development or service-oriented, nearly every company is ultimately providing a user experience. The Bottom Line Creating great experiences may have been popularized by Steve Jobs and Apple, but I’ll be honest, it’s a good feeling to be moving from “good enough” to “delight and excite,” despite the challenge that entails. In fact, it’s because of that challenge that we will expand what we do as UX professionals to help deliver and assess those experiences. I’m excited to see how we, Oracle, and the rest of the industry will live up to that challenge.

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  • Does Windows 7 Authenticate Cached Credentials on Startup

    - by Farray
    Problem I have a Windows domain user account that gets automatically locked-out semi-regularly. Troubleshooting Thus Far The only rule on the domain that should automatically lock an account is too many failed login attempts. I do not think anyone nefarious is trying to access my account. The problem started occurring after changing my password so I think it's a stored credential problem. Further to that, in the Event Viewer's System log I found Warnings from Security-Kerberos that says: The password stored in Credential Manager is invalid. This might be caused by the user changing the password from this computer or a different computer. To resolve this error, open Credential Manager in Control Panel, and reenter the password for the credential mydomain\myuser. I checked the Credential Manager and all it has are a few TERMSRV/servername credentials stored by Remote Desktop. I know which stored credential was incorrect, but it was stored for Remote Desktop access to a specific machine and was not being used (at least not by me) at the time of the warnings. The Security-Kerberos warning appears when the system was starting up (after a Windows Update reboot) and also appeared earlier this morning when nobody was logged into the machine. Clarification after SnOrfus answer: There was 1 set of invalid credentials that was stored for a terminal server. The rest of the credentials are known to be valid (used often & recently without issues). I logged on to the domain this morning without issue. I then ran windows update which rebooted the computer. After the restart, I couldn't log in (due to account being locked out). After unlocking & logging on to the domain, I checked Event Viewer which showed a problem with credentials after restarting. Since the only stored credentials (according to Credential Manager) are for terminal servers, why would there be a Credential problem on restart when remote desktop was not being used? Question Does anyone know if Windows 7 "randomly" checks the authentication of cached credentials?

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  • Is it okay to use an administrator account for everyday use if UAC is on?

    - by Valentin Radu
    Since I switched to Windows 7 about 3 years ago, and now using Windows 8.1, I have become familiar with the concept of User Account Control and used my PC the following way: a standard account which I use for every day work and the built-in Administrator account activated and used only to elevate processes when they request so, or to ”Run as administrator” applications when I need to. However, recently after reading more about User Account Control, I started wondering if my way of working is good? Or should I use an administrator account for every day work, since an administrator account is not elevated until requested by apps, or until I request so via the ”Run as administrator” option? I am asking this because I read somewhere that the built-in Administrator account is a true administrator, by which I mean UAC doesn't pop up when logged in within it, and I am scared of not having problems when potential malicious software come into scene. I have to mention that I do not use it on a daily basis, just when I need to elevate some apps. I barely log in into it 10 times a year... So, how's better? Thanks for your answers! And Happy New Year, of course! P.S. I asked this a year ago (:P) and I think I should reiterate it: is an administrator account as safe these days as a standard account coupled with the built-in Administrator account when needed?

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  • UIDs for service users in Mac OS X

    - by LaC
    Some third-party servers should be run under a special user for security reasons (eg, PostgreSQL is typically run by "postgres"). Of course, these service users should not show up in the Mac OS X login windows. I know how to create hidden users using dscl or dsimport, but I'm wondering what the best policy is for assigning UIDs (and matching GIDs). Apple's documentation states that UIDs from 0 to 100 are reserved (pg. 69), but OS X comes with several special users and groups outside that range. I used to use ids from 401 onwards for services, but I noticed that OS X 10.6 has started using that range for groups created by the Sharing pane in System Preferences. What is the recommended ID range to use for third-party services, then? Perhaps I should just use IDs in the 500 range, since all that is needed to hide a user in Snow Leopard is setting his password to "*"? Also, most of Apple's services have names starting with an underscore, with an alias sans underscore; eg, _sandbox and sandbox. Is there any special significance to this? Should I do the same for my services?

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  • WPF User Control is causing Out of Memory Exception

    - by Chairman Meow
    Looking for a free spell checking solution, I thought I was so smart in doing this but I guess not. I have created a windows form based application and I want the form to add a user specified amount of user controls (with textboxes) on to a panel. The user can then click some button and the controls on this panel are cleared and new ones are added. The user does something and the process is repeated. Now, I wanted these textboxes to support spell checking and looked all over for a free solution. WPF textboxes support spell checking where the ones in regular win forms do not. I thought I would be able to use these WPF textboxes by adding them to an ElementHost object which is, in turn, within a panel. This panel would be a user control. So, in my application, I would be able to add instances of these user controls onto the form and make use of .NET's spell checking goodness. This actually worked but after using the application for a while, found that the application would eventually freeze on me due to out of memory errors. I have pinpointed the memory errors to these WPF controls since this problem does not happen with normal textboxes. When the window is opened and the number of controls is specified, this is pretty much how the controls are added: Dim xOffset As Integer = 0 For i As Integer = 0 To theNumber Dim myUserControl As New SpecialUserControl() myPanel.Controls.Add(myUserControl) myUserControl.Location = New Point(7, 7) myUserControl.Location = New Point(xOffset, 7) xOffset = xOffset + 207 Next Note that: myPanel is a panel on a form SpecialUserControl is the user control with WPF textbox (within an ElementHost object) When the user pressed a button, the panel is cleared: myUserControl.Controls.Clear() The user can then repeat the process. There are a lot of results on the internet when I tried to find a solution and I'm thinking that the problem I am having is due to the fact that the WPF control is not going away even after clearing the panel. Following this conclusion, I have tried different solutions regarding disposing these controls or setting them to nothing but the memory problem keeps occurring. If someone could give me some advice or ideas here, I'd really appreciate it.

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  • Set HttpContext.Current.User from Thread.CurrentPrincipal

    - by Argons
    I have a security manager in my application that works for both windows and web, the process is simple, just takes the user and pwd and authenticates them against a database then sets the Thread.CurrentPrincipal with a custom principal. For windows applications this works fine, but I have problems with web applications. After the process of authentication, when I'm trying to set the Current.User to the custom principal from Thread.CurrentPrincipal this last one contains a GenericPrincipal. Am I doing something wrong? This is my code: Login.aspx protected void btnAuthenticate_Click(object sender, EventArgs e) { Authenticate("user","pwd"); FormsAuthenticationTicket authenticationTicket = new FormsAuthenticationTicket(1, "user", DateTime.Now, DateTime.Now.AddMinutes(30), false, ""); string ticket = FormsAuthentication.Encrypt(authenticationTicket); HttpCookie authenticationCookie = new HttpCookie(FormsAuthentication.FormsCookieName, ticket); Response.Cookies.Add(authenticationCookie); Response.Redirect(FormsAuthentication.GetRedirectUrl("user", false)); } Global.asax (This is where the problem appears) protected void Application_AuthenticateRequest(object sender, EventArgs e) { HttpCookie authCookie = Context.Request.Cookies[FormsAuthentication.FormsCookieName]; if (authCookie == null) return; if (HttpContext.Current.User != null && HttpContext.Current.User.Identity.IsAuthenticated && HttpContext.Current.User.Identity is FormsIdentity) { HttpContext.Current.User = System.Threading.Thread.CurrentPrincipal; //Here the value is GenericPrincipal } Thanks in advance for any help. }

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  • Spree customize/extend user roles and permissions

    - by swapnil
    I am trying to specify some custom roles in Spree for example role 'client' and extend the permissions to access the admin section for this role. This user will be able to access only those Product created by that user. Concept is letting a user with role 'client' manage only products and other certain Models. To start with I added CanCan plugin and defined a RoleAbility Class in role_ability.rb Just following this post : Spree Custom Roles Permissions class RoleAbility include CanCan::Ability def initialize(user) user ||= User.new if user.has_role? 'admin' can :manage, :all elsif user.has_role? 'client_admin' can :read, Product can :admin, Product end end end Added this to an initializer : config/initializers/spree.rb Ability.register_ability(RetailerAbility) Also extended admin_products_controller_decorator.rb :app/controllersadmin_products_controller_decorator.rb Admin::ProductsController.class_eval do def authorize_admin authorize! :admin, Product authorize! params[:action].to_sym, Product end end But I am getting flash message 'Authorisation Failure' Trying to find some luck, I referred following links A github gist for Customizing Spree Roles : https://gist.github.com/1277326 Here's a similar issue what I am facing : http://groups.google.com/group/spree-user/browse_thread/thread/1e819e10410d03c5/23b269e09c7ed47e All efforts in vain... Any pointers of what is going on here highly appreciated ? Thanks in advance.

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

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  • A good data model for finding a user's favorite stories

    - by wings
    Original Design Here's how I originally had my Models set up: class UserData(db.Model): user = db.UserProperty() favorites = db.ListProperty(db.Key) # list of story keys # ... class Story(db.Model): title = db.StringProperty() # ... On every page that displayed a story I would query UserData for the current user: user_data = UserData.all().filter('user =' users.get_current_user()).get() story_is_favorited = (story in user_data.favorites) New Design After watching this talk: Google I/O 2009 - Scalable, Complex Apps on App Engine, I wondered if I could set things up more efficiently. class FavoriteIndex(db.Model): favorited_by = db.StringListProperty() The Story Model is the same, but I got rid of the UserData Model. Each instance of the new FavoriteIndex Model has a Story instance as a parent. And each FavoriteIndex stores a list of user id's in it's favorited_by property. If I want to find all of the stories that have been favorited by a certain user: index_keys = FavoriteIndex.all(keys_only=True).filter('favorited_by =', users.get_current_user().user_id()) story_keys = [k.parent() for k in index_keys] stories = db.get(story_keys) This approach avoids the serialization/deserialization that's otherwise associated with the ListProperty. Efficiency vs Simplicity I'm not sure how efficient the new design is, especially after a user decides to favorite 300 stories, but here's why I like it: A favorited story is associated with a user, not with her user data On a page where I display a story, it's pretty easy to ask the story if it's been favorited (without calling up a separate entity filled with user data). fav_index = FavoriteIndex.all().ancestor(story).get() fav_of_current_user = users.get_current_user().user_id() in fav_index.favorited_by It's also easy to get a list of all the users who have favorited a story (using the method in #2) Is there an easier way? Please help. How is this kind of thing normally done?

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  • Loading user control dynamically looses data

    - by user228777
    I have a created a user control. This user control I dynamically load on a page inside Telerik Panelbar control. I have done all necessary coding to save the viewstate and load this dynamically created usercontrol every time page loads. On this User control I have a asp panel. By default this panel is invisible. When user clicks a button on this user control panel is made visible. On page load of this user control I populate all the controls on this panel. Everything works fine if I don’t load this use control dynamically but when I load this user control dynamically and if I make panel visible by default then only all fields on the panel are populated. But if I make by default invisible and on button click make panel visible none of the text boxes or comboboxes are populated. I populate comboboxes on page load of the userControl but inbetween postbacks all the comboboxes on the user control loose data. ON the parent page I am saving the viewstate This is my code on parent page to dynamically load userControl ( which has panel on it) Dim ucPiggyBank As SubscriberSetupPages_UserControls_PiggyBank = CType(LoadControl("~/SubscriberSetupPages/UserControls/PiggyBank.ascx"), SubscriberSetupPages_UserControls_PiggyBank) With ucPiggyBank .PiggyBankID = account.Id .ID = account.Id.ToString 'Setting up following 3 properties here to avoid database trips .PiggyBankEligibleAccounts = piggyBankEligibleAccountCollection .MemorizedNames = memorizednames .Period = period End With radPanelNewChild.Controls.Add(ucPiggyBank) radPanelNew.Items.Add(radPanelNewChild) radPanelNew.Expanded = True ‘this is the Panel item on parent page of Telerik Panelbar control. Dim radPanelPiggyBank As RadPanelItem = DirectCast(pnlbarPiggyBank.FindItemByValue("TestItem"), RadPanelItem) With radPanelPiggyBank .Items.Add(radPanelNew) .DataBind() End With ‘I am doing everything for saving viewstate on parent control This is the code on page load of userControl If Not IsPostBack Then If m_PiggyBankID <> Guid.Empty Then 'Load data Call GetPiggyBankDetails() End If I have a edit button on the user control which makes panel visible. It makes panel visible but with no data. Can you please tell me what’s happening? Thanks in advance.

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