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  • paperclip callbacks or simple processor?

    - by holden
    I wanted to run the callback after_post_process but it doesn't seem to work in Rails 3.0.1 using Paperclip 2.3.8. It gives an error: undefined method `_post_process_callbacks' for #<Class:0x102d55ea0> I want to call the Panda API after the file has been uploaded. I would have created my own processor for this, but as Panda handles the processing, and it can upload the files as well, and queue itself for an undetermined duration I thought a callback would do fine. But the callbacks don't seem to work in Rails3. after_post_process :panda_create def panda_create video = Panda::Video.create(:source_url => mp3.url.gsub(/[?]\d*/,''), :profiles => "f4475446032025d7216226ad8987f8e9", :path_format => "blah/1234") end I tried require and include for paperclip in my model but it didn't seem to matter. Anyideas?

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  • Amazon SQS invalid binary character in message body

    - by letronje
    I have a web app that sends messages to an Amazon SQS Queue. Amazon sqs lib throws a 'AmazonSQSException' since the message contained invalid binary character. The message is the referrer obtained from an incoming http request. This is what it looks like: http://ads.vrx.adbrite.com/adserver/display_iab_ads.php?sid=1220459&title_color=0000FF&text_color=000000&background_color=FFFFFF&border_color=CCCCCC&url_color=008000&newwin=0&zs=3330305f323530&width=300&height=250&url=http%3A%2F%2Funblockorkutproxy.com%2Fsearch.php%2FOi8vZG93%2FbmxvYWRz%2FLnppZGR1%2FLmNvbS9k%2Fb3dubG9h%2FZGZpbGUv%2FNTY5MTQ3%2FNi9NeUN1%2FdGVHaXJs%2FZnJpZW5k%2FWmFoaXJh%2FLndtdi5o%2FdG1s%2Fb0%2F^Fô}úÃ<99ë)j Looks like the characters in bold are the invalid characters. Is there an easy way to filter out characters characters that are not accepted by amazon ? Here are the characters allowed by amazon in message body. I am not sure what regex i should use to replace invalid characters by ''

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  • asp.net mvc routing id parameter

    - by parminder
    Hi Experts, I am working on a website in asp.net mvc. I have a route routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = UrlParameter.Optional } // Parameter defaults ); which is the default route. Now I have method public ActionResult ErrorPage(int errorno) { return View(); } now if i want to run this code with http://something/mycontroller/Errorpage/1 it doesnt work. but if i change the parameter name to id from errorno it works. Is it cumpulsory to have same parameter name for this method. Or I need to create seperate routes for such situations. Regards Parminder

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  • Android VideoView resume and seekTo

    - by Chris
    I am playing a Video using a VideoView in my app. On the click of a button, it records the current position of the video, and the app opens up the browser with some url. On pressing the back button, the app comes back to video app and resumes the video from where it left off. I looked at the Android Activity lifecycle and saw that onStart() method gets called once the video activity comes to the foreground. So I am creating my layout in onStart() and playing the video by seeking to the current position. My problem is that when the video resumes, it buffers from the start and then seeks to. Since it already buffered the first time, is there a way to eliminate buffering again while doing a seekTo? Thanks Chris

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  • Creating a customized video using Flash and XML

    - by Aaron Ladage
    The problem: I have to create a Flash video (in CS3) that will query a MySQL database and display that data at certain points in the video. The bigger problem: I'm not a Flash/ActionScript developer, so this is all very foreign to me! I've divided this project into two parts: a.) dynamically generate an XML feed from the data using PHP (using an ID number passed in the URL's query string), and b.) be able to work with it in Flash. I've got the first part working, but am pretty lost in Flash. I can parse the XML, but I'm not sure how to set the data up as variables and attach it to a video's cue points. Can anyone point me in the direction of a good tutorial or offer some advice?

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  • How do I set a default page in Pylons?

    - by Evgeny
    I've created a new Pylons application and added a controller ("main.py") with a template ("index.mako"). Now the URL http://myserver/main/index works. How do I make this the default page, ie. the one returned when I browse to http://myserver/ ? I've already added a default route in routing.py: def make_map(): """Create, configure and return the routes Mapper""" map = Mapper(directory=config['pylons.paths']['controllers'], always_scan=config['debug']) map.minimization = False # The ErrorController route (handles 404/500 error pages); it should # likely stay at the top, ensuring it can always be resolved map.connect('/error/{action}', controller='error') map.connect('/error/{action}/{id}', controller='error') # CUSTOM ROUTES HERE map.connect('', controller='main', action='index') map.connect('/{controller}/{action}') map.connect('/{controller}/{action}/{id}') return map I've also deleted the contents of the public directory (except for favicon.ico), following the answer to http://stackoverflow.com/questions/1279403/default-route-doesnt-work Now I just get error 404. What else do I need to do to get such a basic thing to work?

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  • problem with facebook api - Keeps redirecting

    - by Megan
    I created an application with a name and connect URL on facebook. I put below code in test.php here (test.php): include_once 'facebook.php'; $fb = new Facebook('api_key', 'secret'); $user = $fb->require_login(); echo $fb->api_client->user; echo $fb->api_client->session_key; when I go to that page, it takes me to facebook login, after I login it redirects me to same test.php with an auth_token. But it doesn't stop there. For some reason, the script is taking me to facebook again and since I already logged in facebook redirecting me to test.php with another auth_token just like below /test.php?auth_token=76a6eb21b872cdfe787ea85a240905dd&auth_token=597d7532bf53c8ce37cc003bcf7d2905 It never stops there, test.php taking me to facebook again and again :( Please tell me what wrong?? Thanks a lot

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  • Best Design for a Facebook clone on GAE Java

    - by charming30
    My current App is written in Python on GAE which can do Contacts management, Genealogy, Social Networking, Photo sharing, Telecom Integration (SMS, iVRS, URL Billing), CRON and performs business logic operations for our Mobile Apps. Current Architecture indlues python, django, jquery, memcache and few telecom APIs. Now, It feels that an SOA Architecture on GAE using Java would be really ideal and scalable for this kind of App where we want to build new features like widgets that users can turn on or off and third party developers can also develop and deploy features. Please correct me or improve the following design decision: UI (Current plan is GWT) Sessions, Security and ACL (Spring MVC 2.x) Reusable Business Logic components (?) Implementation of Web Services (?) Your advice would really help.

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  • How do we read the data from a public google spreadsheet using Zend_Gdata

    - by bobo
    I have read the examples here: http://framework.zend.com/manual/en/zend.gdata.spreadsheets.html But those examples assume the spreadsheet to be read needs authentication: $service = Zend_Gdata_Spreadsheets::AUTH_SERVICE_NAME; $client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass, $service); $spreadsheetService = new Zend_Gdata_Spreadsheets($client); $feed = $spreadsheetService->getSpreadsheetFeed(); The spreadsheet I am going to read from is a public one, so I don't really need to provide any authentication right? And what I need to provide is just the url of the spreadsheet. I tried to read the class description here but still have no idea how it can be done: http://framework.zend.com/apidoc/core/Zend_Gdata/Spreadsheets/Zend_Gdata_Spreadsheets.html

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  • Some special characters defined in "ISO-8859-1" can't be shown when encoding with "UTF-8"

    - by Mike.Huang
    I need to get a string from URL request of brower, and then create a text image by requested text. I know the default encoding of the Java net transmission is "ISO-8859-1", it can works normally with all characters what defined in "ISO-8859-1". But when I request a multi-byte Unicode character (e.g. chinese or something like ¤?), then I need to decode it by "UTF-8" from "ISO-8859-1". My codes like: String reslut = new String(requestString.getBytes("ISO-8859-1"), "UTF-8"); Everything is fine, but I found some characters in ISO-8859-1 are not been shown now, which characters are 0x80 - 0xFF(defined in" ISO-8859-1"), i.e. the characters after 0x80 (in "ISO-8859-1") not been shown when converted to "UTF-8" from "ISO-8859-1". Any other method can solve this query?

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  • capturing video from ip camera

    - by Ruby
    I am trying to capture video from ip camera into my application , its giving exception com.sun.image.codec.jpeg.ImageFormatException: Not a JPEG file: starts with 0x0d 0x0a at sun.awt.image.codec.JPEGImageDecoderImpl.readJPEGStream(Native Method) at sun.awt.image.codec.JPEGImageDecoderImpl.decodeAsBufferedImage(Unknown Source) at test.AxisCamera1.readJPG(AxisCamera1.java:130) at test.AxisCamera1.readMJPGStream(AxisCamera1.java:121) at test.AxisCamera1.readStream(AxisCamera1.java:100) at test.AxisCamera1.run(AxisCamera1.java:171) at java.lang.Thread.run(Unknown Source) its giving exception at image = decoder.decodeAsBufferedImage(); Here is the code i am trying private static final long serialVersionUID = 1L; public boolean useMJPGStream = true; public String jpgURL = "http://ip here/video.cgi/jpg/image.cgi?resolution=640×480"; public String mjpgURL = "http://ip here /video.cgi/mjpg/video.cgi?resolution=640×480"; DataInputStream dis; private BufferedImage image = null; public Dimension imageSize = null; public boolean connected = false; private boolean initCompleted = false; HttpURLConnection huc = null; Component parent; /** Creates a new instance of AxisCamera */ public AxisCamera1(Component parent_) { parent = parent_; } public void connect() { try { URL u = new URL(useMJPGStream ? mjpgURL : jpgURL); huc = (HttpURLConnection) u.openConnection(); // System.out.println(huc.getContentType()); InputStream is = huc.getInputStream(); connected = true; BufferedInputStream bis = new BufferedInputStream(is); dis = new DataInputStream(bis); if (!initCompleted) initDisplay(); } catch (IOException e) { // incase no connection exists wait and try // again, instead of printing the error try { huc.disconnect(); Thread.sleep(60); } catch (InterruptedException ie) { huc.disconnect(); connect(); } connect(); } catch (Exception e) { ; } } public void initDisplay() { // setup the display if (useMJPGStream) readMJPGStream(); else { readJPG(); disconnect(); } imageSize = new Dimension(image.getWidth(this), image.getHeight(this)); setPreferredSize(imageSize); parent.setSize(imageSize); parent.validate(); initCompleted = true; } public void disconnect() { try { if (connected) { dis.close(); connected = false; } } catch (Exception e) { ; } } public void paint(Graphics g) { // used to set the image on the panel if (image != null) g.drawImage(image, 0, 0, this); } public void readStream() { // the basic method to continuously read the // stream try { if (useMJPGStream) { while (true) { readMJPGStream(); parent.repaint(); } } else { while (true) { connect(); readJPG(); parent.repaint(); disconnect(); } } } catch (Exception e) { ; } } public void readMJPGStream() { // preprocess the mjpg stream to remove the // mjpg encapsulation readLine(3, dis); // discard the first 3 lines readJPG(); readLine(2, dis); // discard the last two lines } public void readJPG() { // read the embedded jpeg image try { JPEGImageDecoder decoder = JPEGCodec.createJPEGDecoder(dis); image = decoder.decodeAsBufferedImage(); } catch (Exception e) { e.printStackTrace(); disconnect(); } } public void readLine(int n, DataInputStream dis) { // used to strip out the // header lines for (int i = 0; i < n; i++) { readLine(dis); } } public void readLine(DataInputStream dis) { try { boolean end = false; String lineEnd = "\n"; // assumes that the end of the line is marked // with this byte[] lineEndBytes = lineEnd.getBytes(); byte[] byteBuf = new byte[lineEndBytes.length]; while (!end) { dis.read(byteBuf, 0, lineEndBytes.length); String t = new String(byteBuf); System.out.print(t); // uncomment if you want to see what the // lines actually look like if (t.equals(lineEnd)) end = true; } } catch (Exception e) { e.printStackTrace(); } } public void run() { System.out.println("in Run..................."); connect(); readStream(); } @SuppressWarnings("deprecation") public static void main(String[] args) { JFrame jframe = new JFrame(); jframe.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); AxisCamera1 axPanel = new AxisCamera1(jframe); new Thread(axPanel).start(); jframe.getContentPane().add(axPanel); jframe.pack(); jframe.show(); } } Any suggestions what I am doing wrong here??

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  • Getting info from NSData object

    - by Moshe
    How would I get returningResponse (into say, a NSString) from the following code: NSURLResponse* response; NSError* error; NSData* result = [NSURLConnection sendSynchronousRequest:theRequest returningResponse:&response error:&error]; I think I can get the info that I need into a string but I can't call anything on response because it's null. Therefore, I assume that I need to call something on result. The problem is, I don't know what to call. (The URL request has been coded prior to the code sample. I know that that works.) I want to be able to detect if the request as successful.

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  • Google Toolbox For Mac with Core Data on iPhone results in error

    - by JaanusSiim
    I have set up my project for using Google Toolbox for Mac as described on official wiki. And everything is working as expected. For core data usage I have created a 'database' class that uses for final application SQLite storage (this is done based on Xcode template code). For unit tests I have created separate init method for 'database' to use in memory storage (storage url is [NSURL URLWithString:@"memory://store"] and type NSInMemoryStoreType). Without adding my model file (*.xcdatamodel) to unit tests target, test fail in expected place with message: executeFetchRequest:error: A fetch request must have an entity. If I add model file to the test target, then test is executed as expected (core data part looks OK), but after tests execution I get: RunIPhoneUnitTest.sh: line 123: 9487 Segmentation fault "$TARGET_BUILD_DIR/$EXECUTABLE_PATH" -RegisterForSystemEvents Command /bin/sh failed with exit code 139 This problem does not looks directly related to core data, but only happens if model file is added to target. Any pointers on resolving this issue would be appreciated!

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  • Issue with JSON and jQuery

    - by Jason N. Gaylord
    I'm calling a web service and returning the following data in JSON format: ["OrderNumber":"12345","CustomerId":"555"] In my web service success method, I'm trying to parse both: $.ajax({ type: "POST", url: "MyService.asmx/ServiceName", data: "{}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(msg) { var data = msg.d; var rtn = ""; $.each(data, function(list) { rtn = rtn + this.OrderNumber + ", " + this.CustomerId + "<br/>"; } rtn = rtn + "<br/>" + data; $("#test").html(rtn); } }); but I'm getting a bunch of "undefined, undefined" rows followed by the correct JSON string. Any idea why? I've tried using the eval() method but that didn't help as I got some error message talking about ']' being expected.

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  • Blank installNotifyURI in OMA Download Descriptors

    - by joynes
    People can download content (music, images) for their mobile from my server. Im trying to use the installNotifyURI-tag of the download descriptors specified by OMA, to be able to find out if the download has been successful. When the user has downloaded the item I do get a POST to the url I specified in the installNotifyURI-tag. <installNotifyURIhttp://joynes.se/mytest.php</installNotifyURI Although I never get any status code. The POST is just blank. Anyone who knows about this problem? /Br Johannes

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  • cannot import name formats

    - by cadthecoder
    what does it mean? i ve googled but found nothing =/ ImportError at /admin/ cannot import name formats Request Method: GET Request URL: http://127.0.0.1:8000/admin/ Exception Type: ImportError Exception Value: cannot import name formats Exception Location: /usr/lib/python2.6/site-packages/django/contrib/admin/util.py in <module>, line 3 Python Executable: /usr/bin/python Python Version: 2.6.0 Python Path: ['/home/cad/project/lkd/gezegen/lkd_gezegen', '/usr/lib64/python26.zip', '/usr/lib64/python2.6', '/usr/lib64/python2.6/plat-linux2', '/usr/lib64/python2.6/lib-tk', '/usr/lib64/python2.6/lib-old', '/usr/lib64/python2.6/lib-dynload', '/usr/lib64/python2.6/site-packages', '/usr/lib64/python2.6/site-packages/Numeric', '/usr/lib64/python2.6/site-packages/PIL', '/usr/lib64/python2.6/site-packages/gst-0.10', '/usr/lib64/python2.6/site-packages/gtk-2.0', '/usr/lib64/python2.6/site-packages/wx-2.8-gtk2-unicode', '/usr/lib/python2.6/site-packages']

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  • Drupal 6: display image with View in blog posts listing page...

    - by artmania
    Hi friends, I'm new at Drupal, love it so far :) I added Photo and Logo File field to blog entry with CCK. I need to display these images at blog post listing page. So at View Module, I added fields as below; At View: Content: Logo URL to file Content: Photo Path to file and it displays only names of files, but I need to display image. how can I make it with View Module? Blog Listing Page: Logo: http://blabla.com/drupal/sites/default/files/Logo_0.jpeg Photo: sites/default/files/photoname_0.jpeg Appreciate helps!!!! Thanks a lot!

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  • appcfg.py upload_data entity kind problem

    - by Dingo
    Hi, I am developing application on app-engine-path and I would like to upload some data to datastore. For example I have a model models/places.py: class Place(db.Model): name = db.StringProperty() longitude = db.FloatProperty() latitude = db.FloatProperty() If I save this in view, kind() of this entity is "models_place". All is ok, Place.all() in view work fine. But: If I upload some next row using appcfg.py upload_data, the kind() of this entities is Place. loader.py look like this: import datetime, os, sys from google.appengine.ext import db from google.appengine.tools import bulkloader libs_path = os.path.join("/home/martin/myproject/src/") if libs_path not in sys.path: sys.path.insert(0, libs_path) from models import places class AlbumLoader(bulkloader.Loader): def __init__(self): bulkloader.Loader.__init__(self, 'Place', [('name', lambda x: x.decode('utf-8')), ('longitude', float), ('latitude', float), ]) loaders = [AlbumLoader] and command for uploading: python /usr/local/google_appengine/appcfg.py upload_data --config_file=places_loader.py --kind=models_place --filename=data/places.csv --url=http://localhost:8000/remote_api /home/martin/myproject/src/

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  • Is it possible to write C# code as below and send email using network in different country?

    - by kedar karthik
    Is it possible to write C# code as below and send email using mnetwork in different country? MSExchangeWebServiceURL = mail.something.com/ews/exchange.asmx It's a web service URL. This works great when I run the same code from home network, my friends home network anywhere around, but when I run it from my client's location in Columbia it fails. I have a valid user name and password on that Exchange Server. Is there any configuration that I can set to achieve this? BTW this code below works when I run it within office network and any network within any home network. I have tried it at least with five friends network in Plano, Texas. I want this code to work running from any network in another country. My client in Columbia can connect to the web service using a browser using the same user name and password, but when I run the code above it is not able to connect to our web service.

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  • What should a PHP generate to give back to a jQuery AJAX request?

    - by Alex Mcp
    Perhaps it's a syntax error, but I never assume that. I have a -dead- simple AJAX test set up: http://www.mcphersonindustries.com/bucket/api.php is a file with simply: <?php echo "test"; ?> And I have Apache as localhost with this jQuery bit running: $(document).ready(function() { function doAjaxPost() { $.ajax({ type: "POST", url: "http://www.mcphersonindustries.com/bucket/api.php", data: "null", success: function(resp){ console.log("Response: '" + resp + "'"); }, error: function(e){ console.log('Error: ' + e); } }); } doAjaxPost(); }); So Firebug spits out Response: '' each time, but nothing's coming through the request. Do I need to declare a header in PHP? Am I making a boneheaded mistake somewhere? Thanks for the insights, as always.

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  • download zip file using java?

    - by Mohamed
    I am downloading zip file from web server using Java but somehow I am loosing about 2kb in each file. I don't know why since same code works fine with other formats, e.g, text, mp3 and extra. any help is appreciated? here is my code. public void download_zip_file(String save_to) { try { URLConnection conn = this.url.openConnection(); conn.setDoOutput(true); conn.setDoInput(true); conn.setRequestProperty("content-type", "binary/data"); InputStream in = conn.getInputStream(); FileOutputStream out = new FileOutputStream(save_to + "tmp.zip"); byte[] b = new byte[1024]; int count; while ((count = in.read(b)) > 0) { out.write(b, 0, count); } out.close(); in.close(); } catch (IOException e) { e.printStackTrace(); } }

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  • Add api key to every request in ActiveResource

    - by Jared
    I have 2 RESTful Rails apps I'm trying to make talk to each other. Both are written in Rails 3 (beta3 at the moment). The requests to the service will require the use an api key which is just a param that needs to be on every request. I can't seem to find any information on how to do this. You define the url the resource connects to via the site= method. There should be an equivalent query_params= method or similar. There is one good blog post I found related to this and it's from October 2008, so not exactly useful for Rails 3.

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  • javscript delay output

    - by tazim
    I have written some code to display server's current date and time on browser every time user clicks the button . I have done this using ajax in django with the help of jquery. Now my, problem is I have to continously display the date and time once the button is clicked . Some Sample code or utilities allowing such kind of delay will be helpful . Thanks in advance The template is : $(document).ready(function() { $("button").click(function() { $.ajax({ type: "POST", url :"/showdate/", datatype: "json ", success : function(data){ var s = data.currentdate; var sd = s $(sd).appendTo("div"); } }); }); }); <button type="button">Click Me</button> <div id="someid"></div> The view function is : def showdate(request): now = datetime.datetime.now() string_now = str(now) return_dict = {'currentdate':string_now} json = simplejson.dumps(return_dict) return HttpResponse(json,mimetype="application/json")

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  • Problem referencing querystring using fb:req-choice

    - by vondip
    Hi all, I am building a small facebook application. I am using asp.net and currently working with the fb:req-choice control (tied along with fb:request-form and fb:multi-friend-selector). Problem is, that when I specify the redirect url for when the user clicks my invitation, instead of getting what I specified: http://apps.facebook.com/myApp/forum.aspx?tId=1&ref=app&code=2.74rRNejG7tpAOqgDCNf8qA__.3600.1275202400-106570384737670%7CPi8JpoHDW3xGuq2lxdZl1d4CLUU. This is what I am getting: http://apps.facebook.com/myApp/forum.aspx?tId&code=2.74rRNejG7tpAOqgDCNf8qA__.3600.1275202400-106570384737670%7CPi8JpoHDW3xGuq2lxdZl1d4CLUU. as you can see my query string isn't getting parsed. Instead, only the first parameter is written, why is that? How can I get this right?

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  • JPanel background image

    - by Zloy Smiertniy
    This is my code, it indeed finds the image so that is not my concern, my concern is how to make that image be the background of the panel. I'm trying to work with Graphics but i doesnt work, any ideas?? please?? try { java.net.URL imgURL = MAINWINDOW.class.getResource(imagen); Image imgFondo = javax.imageio.ImageIO.read(imgURL); if (imgFondo != null) { Graphics grafica=null; grafica.drawImage(imgFondo, 0, 0, this); panel.paintComponents(grafica); } else { System.err.println("Couldn't find file: " + imagen); } } catch...

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