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  • A couple PHP/MySQL questions...

    - by Jeff
    I am a college student taking a course in php and mysql progamming and my first question is about the "$variable" variables in the following code: <?php ob_start(); ?> <?php session_start(); if ($_SESSION['auth'] != "true") { header("Location: login.php"); exit; } $uid = $_SESSION['user']; $connection = mysql_connect("localhost", "username", "password"); mysql_select_db("username", $connection); $result = mysql_query ( "SELECT * FROM users where user_id = '$uid'", $connection); $num = mysql_numrows($result); $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"firstname"); $f2=mysql_result($result,$i,"lastname"); ?> <html><body> <p> <td><center><font size = "18" face="Arial"><?php echo "Name: $f1 "; echo $f2; ?> </font></center></td> </p> </body></html> <?php $i++; } ?> <?php $result1 = mysql_query ( "SELECT * FROM phone where user_id = '$uid'", $connection); $num1 = mysql_numrows($result1); $j=0; while ($j < $num1) { $f3=mysql_result($result1,$j,"type"); $f4=mysql_result($result1,$j,"number"); ?> <html><body> <p> <br> <td><center><font size = "12" face="Arial"><?php echo "$f5: "; echo "($f3) "; echo "$f4 <br />"; ?> </font></center></td> </p> </body></html> <?php $j++; } ?> <?php $result2 = mysql_query ( "SELECT * FROM address where user_id = '$uid'", $connection); $num2 = mysql_numrows($result2); $h=0; while ($h < $num2) { $f6=mysql_result($result2,$h,"type"); $f7=mysql_result($result2,$h,"address"); $f8=mysql_result($result2,$h,"city"); $f9=mysql_result($result2,$h,"state"); $f10=mysql_result($result2,$h,"zip"); ?> <html><body> <p> <br> <td><center><font size = "12" face="Arial"><?php echo "$f10 Address: $f6, $f7, $f8 $f9"; ?></font></center></td> </p> </body></html> <?php $h++; } ?> <?php include 'navbar.php'; ob_end_flush(); ?> I just don't really understand the $variables at all. Are they user-generated or are they entities in the database? And how does the code know which $result is which? My second question is that, if this was someone else in my class's code and I wanted to modify it to make it my own and substitute my own variables, how would I go about doing that? Do the $variables need to be changed if they are not user-defined and if so, how? I apologize if these are dumb questions, but I am a beginner at this programming language. Thanks in advance for your help. -Jeff

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  • BASH Install Of Wordpress, Without Visiting wp-admin/install.php

    - by user916825
    I wrote this little BASH script that creates a folder,unzips Wordpress and creates a database for a site. The final step is actually installing Wordpress, which usually involves pointing your browser to install.php and filling out a form in the GUI. I want to do this from the BASH shell, but can't figure out how to invoke wp_install() and pass it the parameters it needs: -admin_email -admin_password -weblog_title -user_name (line 85 in install.php) Here's a similar question, but in python #!/bin/bash #ask for the site name echo "Site Name:" read name # make site directory under splogs mkdir /var/www/splogs/$name dirname="/var/www/splogs/$name" #import wordpress from dropbox cp -r ~/Dropbox/Web/Resources/Wordpress/Core $dirname cd $dirname #unwrap the double wrap mv Core/* ./ rm -r Core mv wp-config-sample.php wp-config.php sed -i 's/database_name_here/'$name'/g' ./wp-config.php sed -i 's/username_here/root/g' ./wp-config.php sed -i 's/password_here/mypassword/g' ./wp-config.php cp -r ~/Dropbox/Web/Resources/Wordpress/Themes/responsive $dirname/wp-content/t$ cd $dirname CMD="create database $name" mysql -uroot -pmypass -e "$CMD" How do I alter the script to automatically run the installer without the need to open a browser?

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  • How can I extend PHP DOMElement?

    - by Michael Tsang
    a.php #!/usr/bin/php <?php class HtmlTable extends DOMElement { public function __construct($height, $width) { parent::__construct("table"); for ($i = 0; $i < $height; ++$i) { $row = $this->appendChild(new DOMElement("tr")); for($j = 0; $j < $width; ++$j) { $row->appendChild(new DOMElement("td")); } } } } $document = new DOMDocument("1.0", "UTF-8"); $document->registerNodeClass("DOMElement", "HtmlTable"); $document->appendChild(new HtmlTable(3, 2)); $document->saveXML(); Running it gets Fatal error: Uncaught exception 'DOMException' with message 'No Modification Allowed Error' in /home/www/a.php:9 Stack trace: #0 /home/www/a.php(9): DOMNode->appendChild(Object(DOMElement)) #1 /home/www/a.php(19): HtmlTable->__construct(3, 2) #2 {main} thrown in /home/www/a.php on line 9

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  • PHP won't parse MySQL statements

    - by Hussain
    I just installed Apache 2.2.15/PHP 5.3.2/MySQL 5.1.44 on Windows Vista. Apache is working fine, PHP is functional, and MySQL works on the CLI. However, when I try to access MySQL via PHP, I get an error (Fatal error: Call to undefined function mysql_connect()). extension=php_mysql.dll and extension=php_mbstring.dll are uncommented in the php.ini file, and PHP is in the system path. There is no libmysql.dll in either the top level PHP directory or the ext directory. There's a libmySQL.dll file in the MySQL bin directory (which is also in the system path); I tried renaming it, but that doesn't do anything Also, in case anyone wants to know, I originally installed PHP using the MSI installer, but it was missing some DLLs, so I installed from the zip file. I think I've exhausted all my options. Any help on this problem would be very appreciated. Thanks in advance.

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  • require wp-load.php 3 directories back

    - by sman591
    I'm trying to include a file (/wp-load.php) at the beginning of the /html/ directory. I'm trying to include it from /wp-content/themes/pw-steel-orange/index-load.php, but I always get the error message Warning: require_once(../wp-load.php) [function.require-once]: failed to open stream: No such file or directory in /nfs/c07/h01/mnt/102799/domains/platyworld.com/html/wp-content/themes/pw-steel-orange/index-load.php on line 1 Fatal error: require_once() [function.require]: Failed opening required '../wp-load.php' (include_path='.:/usr/local/php-5.2.6-1/share/pear') in /nfs/c07/h01/mnt/102799/domains/platyworld.com/html/wp-content/themes/pw-steel-orange/index-load.php on line 1 Am I doing something wrong? I though ../ brings the includes to the beginning directory Sorry if this is a duplicate, I couldn't find something related to this in my searches...

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  • PHP Dynamic include based on current file path

    - by Adrian M.
    Hello, I want to find a method to include some files based on the current file path.. for example: I have "website.com/templates/name1/index.php", this "index.php should be a unique file that I will use in many different directories on different depths, so I want to make the code universal so I don't need to change anything inside this file.. So if this "index.php" is located in "website.com/templates/name1/index.php" than it should include the file located here: "website.com/content/templates/name1/content.php" another example: "website.com/templates/name2/index.php" than it should include the file located here: "website.com/content/templates/name2/content.php" Also I want to overrun "*Warning: include_once() [function.include-once]: http:// wrapper is disabled in the server configuration by allow_url_include=0*" kind of error.. because is disabled and unsafe.. Is there a way to achieve this? Thank you!

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  • PHP Launch Execute Files Concurrently

    - by Ozzy
    Hi all. Basically, I was doing some testing using apache bench. The file i was testing takes 2 seconds to execute (its optimised, it connects to an external server hence the slowdown) Basically I found that the more concurrent useres i emulated, the more executions of the file i could do per second. Is there anyway that i can do something like this in php? : <?php execute_file('file.php'); execute_file('file.php'); execute_file('file.php'); execute_file('file.php'); execute_file('file.php'); ?> That would execute the file 5 times but would NOT wait for the files to finish downloading so the above example would quickly call the 5 functions then exit. Im assuming somesort of timeout would be used?

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  • jquery load php file - result is not complete

    - by Mark Nolan
    I'm trying to load or better reload a DIV with content from an included php file. so the file is included in the webadmin.php from the location webadmin/pages.php. Then i alter some data in the DB through serializing. Now I would like to reload the pages.php from the callback of the serialize POST with load();. This all works fine up until the moment the data is supposed to be displayed in the div - i believe its because the php file is loaded from a different location, so the include paths for the DB Connection etc are probably wrong... Should I really write an extra PHP File for jquery or is there a way to tell jquery where to load it from? Its the first time I'm doing this - so bear with me for a moment on this one... Thanks! I guess it wont be much use, but heres the load code: $("#right").load("webadmin/pages.php");

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  • htaccess Redirect - First Segment to PHP File, Second Segment as Parameter

    - by Steve
    My htaccess redirect knowledge is somewhat weak, so I was hoping to get some help here. I currently have the following redirect, which works well: # remove trailing slash RewriteRule ^(.*)/$ /$1 [L,R=301] # redirect to clean URL RewriteCond /%{REQUEST_FILENAME}.php -f RewriteRule ^([a-zA-Z0-9_-\s]+)$ /$1.php This takes a URL like www.mysite.com/about to www.mysite.com/about.php Now I would like to keep this behavior, but add parameters (if applicable), as such: www.mysite.com/about = www.mysite.com/about.php www.mysite.com/gallery/1 = www.mysite.com/gallery.php?id=1 If possible, I might like to expand this system to 2 or more parameters, as such: www.mysite.com/gallery/1/2 = www.mysite.com/gallery.php?id=1&section=2 So the pattern would be: First URL segment redirects to a PHP file (Optionally) the second segment gets added as the id parameter (Optionally) the third segment gets added as the section parameter

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  • php is not recognized as an intern command (using windows)

    - by Tristan
    Hello, I want to develop using a framework called symfony BUT, i do not have a MAC and i don't want to dual boot with Debian. I tryed virtual hosts via Virtual Box but it's too crappy. So i decided to stay on windows So when the tutorial tells me to do php lib/vendor/symfony/data/bin/check_configuration.php i do in the windows cmd : php lib\vendor\symfony\data\bin\check_configuration.php and it tells me : 'php' is not recognized as an internal or external command I use UwAmp (php 5.2.12 + mysql + apache) which is stored in E:\logiciels\UwAmp\ inside i have buch of file, but i guess that is important : E:\logiciels\UwAmp\apache\php_5.2.11 How to make the cmd PHP in the windows cmd work propely please?

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  • php: security question

    - by Syom
    in my cms i have index.php, where client must enter username and password. if they are correct, he'll moove to admin.php, where the cms is. but now hacker can enter to cms/admin.php, so my security now is awful. i know, that i can use $_SESSION variable. index.php - i can give some value to $_SESSION['error']: $_SESSION['error'] = TRUE, and in admin.php just verify it admin.php if($_SESSION['error'] == TRUE) { my script here... } else header("Location: index.php"); but i want to rich this effect without SESSION. could you give me an idea, how can i do it? thanks

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  • PHP Fatal error on line number that doesn't exist

    - by alexantd
    Fatal error: Allowed memory size of 134217728 bytes exhausted (tried to allocate 523800 bytes) in /Library/WebServer/Documents/XMLDataStore.class.php on line 981 The curious thing about this error is not the memory leak, which would be easy enough to troubleshoot. Rather, it is the fact that XMLDataStore.class.php is only 850 lines long, which I have verified in multiple text editors. This is with the PHP 5.3 bundled with Snow Leopard. I'm not using an opcode cache. Here is my php.ini: allow_url_fopen = Off error_reporting = -1 display_errors = 1 display_startup_errors = 1 date.timezone = 'America/Los_Angeles' output_buffering = Off realpath_cache_size = 0k XMLDataStore.class.php has recently been refactored and it used to be longer than 981 lines. It's almost as if PHP has cached a 2-week-old version and is reading that. I'm positive that the current version at /Library/WebServer/Documents/XMLDataStore.class.php is only 850 lines long, though.

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  • Execute a method less times possible - PHP

    - by serhio
    I have a site in multiple languages. I have a method that returns me the today currencies in a array. I display that currencies in a table then. // --- en/index.php <?php include_once "../exchangeRates.php"; $currencies = ReadExchangeRates(); // --- fr/index.php <?php include_once "../exchangeRates.php"; $currencies = ReadExchangeRates(); ... // somewhere in the page <td><?php echo $currencies["eur"]["today"]; ?></td> So, every time I load, en/ or fr/ or other language, I request the exchange rates from a external site. Can I optimize this behavior (reading once per day or session)? maybe to store a global variable and check the update date?

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  • Accessing global variables within functions in PHP

    - by st3
    There are multiple times in one page where I need to connect and subsequently query a MySQL database, yet my code won't let me. I think it might be something to do with how my files are nested but it makes no sense. I am opening the SQL connection in the header file. The top of the offending page looks like the following: <?php $page_title = 'Dashboard'; include('templates/header.inc'); // includes a 'require_once('mysqli_connect.php') and a small query to the database; require_once('includes/functions.php'); require_once('includes/dashboard_sql.php'); // Contains functions which connect to database (which are failing.) ?> I get the PHP error Notice: Undefined variable: dbc in /Library/WebServer/Documents/pediatory_site/includes/dashboard_sql.php Where $dbc is the database connection defined in mysqli_connect.php. If anyone could help me out that would be great.

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  • php drop down how to control the hide and show

    - by user329394
    Hi all, i want to control the drop down box to control show or hide statement. I do like this but it seems it doesn't work, i have it working if im using radio button. can help me with the code? which part am i wrong? thank you. $dbcnx = mysql_connect('localhost', 'root', ''); mysql_select_db('dbase'); if($_POST['gred'])$gred=$_POST['gred'];else $gred=""; <script language="JavaScript"> function funcHide(elemHide1,elemHide2,elemHide3) { document.getElementById(elemHide1).style.display = 'none'; document.getElementById(elemHide2).style.display = 'none'; document.getElementById(elemHide3).style.display = 'none'; document.getElementById(elemShow).style.visibility = 'visible'; } function funcShow(elemShow1,elemShow2,elemShow3) { document.getElementById(elemShow1).style.display = 'block'; document.getElementById(elemShow2).style.display = 'block'; document.getElementById(elemShow3).style.display = 'block'; document.getElementById(elemShow1).style.visibility = 'visible'; document.getElementById(elemShow2).style.visibility = 'visible'; document.getElementById(elemShow3).style.visibility = 'visible'; } </script> <table> <tr> <td>Gred </td> <td>:</td> <td><select name="gred" id="gred"> <option value="">&nbsp;</option> <option value="A17" <?php if($gred=='A17')echo "selected";?> onClick="funcShow('box1', 'box2', 'box3');">A17</option> <option value="A22" <?php if($gred=='A22')echo "selected";?>>A22</option> <option value="A27" <?php if($gred=='A27')echo "selected";?>>A27</option> </select> </td> </tr> <tr> <td>TK</td> <td>:</td> <td> <select name="tk" id="tk"> <option value="">&nbsp;</option> <option value="01" <?php if($tk=='01')echo "selected";?>>01</option> <option value="02" <?php if($tk=='02')echo "selected";?>>02</option> <option value="03" <?php if($tk=='03')echo "selected";?>>03</option> <option value="04" <?php if($tk=='04')echo "selected";?>>04</option> <option value="05" <?php if($tk=='05')echo "selected";?>>05</option> <option value="06" <?php if($tk=='06')echo "selected";?>>06</option> </select> <?} ?> </td> </tr> <tr> <td colspan="2" valign="top">Status</td> <td valign="top">:</td> <td> <?php $qry = "SELECT * from dtable where userid='".$USER->id."'"; $sql = mysql_query($qry); $row = mysql_num_rows($sql); if($row==0) { ?> <input type=radio name="status" <?php if($status=='retake') {?>checked="checked"<?php } ?> value="retake" onClick="funcShow('box1', 'box2', 'box3');">Retake<br /></tr> <tr> <td colspan='2'> <div id="box1" style="display: none;">Last Date <br> Latest Date<br> </div></td> <td><div id="box2" style="display: none;">: <br> : <br></div></td> <td> <div id="box3" style="display: none;"> <?php $rsu[lastdate] ?> <br> <?php $rsu[latestdate] ?> </div> </td>

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  • How to avoid resending data on refresh in php

    - by Priyanka
    Hello.I have a page "index.php" where i have a link called "add_users.php".In "add_users.php",i accept user information and come back to the same page "index.php" where information comes through post action and gets inserted into the database.When i refresh the page orhit back button,resend box appears.I went through many solution where they asked me to create third page.I tried doing that as follows:After inserting values in database,I redirected ht page as header('Location:http://mysite.com/thankyou.php, and in thankyou.php I again redirected the page to index.php.But getting warning as Cannot modify header information - headers already sent by.... provide me a better solution. Thank You in advance.

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  • Confused as to why my PHP include isn't working

    - by Sam
    I had a prototype of my website working correctly, meaning it connected to the database correctly. This was done with just one file called "connect.php" which had mysql_connect() and such inside it. I then separated the connect information into to separate files, one containing the account information (account.php) and one containing the connect function (connect.php), with correct information (I triple checked) and it isn't connecting properly. All I can think of is that I'm not including it the right way. This is what I have in a file: <?php include('account.php'); include('connect.php'); include('functions.php'); ..... ?>

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  • Is putting $_GET in headers safe? (PHP)

    - by ggfan
    In my profile.php script, I have a flag function that allows users to flag that user. If they flag a user, it sends data (user_id, reason, etc) to a file called flag.php which does all the banning and stuff. The data is sent to flag.php through header("Location: flag.php?user_id=___&reason=___") Then in flag.php, after it does all the banning, it redirects the user back to the profile through another header. The user never sees the flag.php. Is my flag.php safe? because they never see the script?

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  • Deny access to a PHP file (Nginx)

    - by Desmond Hume
    I want Nginx to deny access to a specific PHP file, let's call it donotexposeme.php, but it doesn't seem to work, the PHP script is run as usual. Here is what I have in the config file: location / { root /var/www/public_html; index index.php; } location ~ \.php$ { fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME /var/www/public_html$fastcgi_script_name; include fastcgi_params; } location /donotexposeme.php { deny all; } Of course, I do sudo service nginx reload (or restart) each time I edit the config.

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  • My website directories downloads instead of actually opening up from browser

    - by numerical25
    I added some screencast to show what I am having issues with http://screencast.com/t/212t3ANINqk http://screencast.com/t/bR44U1wkvNZl http://screencast.com/t/iDS7APYYsa but the page downloads my subdirectories instead of opening them up and displaying the index file of that page Here is the situation. I am trying to get my web service up using mac ports and I am just trying to configure all the files. I am using php, apache, etc. the page goes to the localhost root but anything beyond that. it can not find. edit Ive tried to add the following to httpd.conf within the <IfModule mime_module> but no hope AddType application/x-httpd-php .php AddType application/x-httpd-php .phtml AddType application/x-httpd-php .php3 AddType application/x-httpd-php .php4 AddType application/x-httpd-php .html AddType application/x-httpd-php-source .phps

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  • Save Web Content Directly to Google Drive in Chrome [Extension]

    - by Asian Angel
    Are you looking for a quick and easy way to save images, documents, and more directly to Google Drive while browsing? Then you may want to grab a copy of the ‘Save to Google Drive’ extension for Chrome. Once you have installed the extension it is very easy to start saving all that wonderful web content to your Google Drive account via the Context Menu or the Toolbar Button as seen in the screenshot above. One thing to keep in mind is that the first time you use the extension you will be asked for permission to access your account as seen in the screenshot below. Here is a quick look at the options currently available for the extension… Secure Yourself by Using Two-Step Verification on These 16 Web Services How to Fix a Stuck Pixel on an LCD Monitor How to Factory Reset Your Android Phone or Tablet When It Won’t Boot

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  • Microsoft intègre Conversation Translator à Lync, une extension qui permet la traduction automatique des messages instantanés

    Microsoft intègre Conversation Translator à Lync Une extension qui permet la traduction automatique des messages instantanés Les utilisateurs de Lync, la solution de communication unifiée de Microsoft, pourront désormais bénéficier de la traduction en temps réel des messages instantanés grâce à une nouvelle extension « Conversation Translator ». Cet add-on effectue une traduction automatiquement des messages instantanés directement à l'intérieur de Lync. Ainsi, l'émetteur et le récepteur peuvent communiquer sans difficulté dans leur langue respective. Concrètement, l'extension utilise l'espace de nommage Microsoft....

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  • Would Using a PHP Framework Be Beneficial in My Context?

    - by Fractal
    I've just started work at a small start-up company who mainly uses PHP to develop their front-end apps. I had no prior PHP experience before joining, and this has led to my apps becoming large pieces of spaghetti code. I essentially started by adding code to implement an initial feature, and then continued to hack in more code to implement further features – without much thought for the overall design. The apps themselves output XML to render on small mobile devices. I recently started looking into frameworks that I could use. I reckon an advantage would be that they seem to force developers to modularise their programs using good-practice design patterns. This seems great for someone in my position. The extra functions they provide, for example: interfacing with databases in such a way as to make SQL injection impossible, would be very useful too. The downside I can see is that there will be a lot of overhead for me in terms of the time taken to learn the framework itself (while still getting to grips with PHP itself). I'm also worried that it will be overkill for the scale of the apps we develop. They tend to be programs that interface with a fairly simple back-end DB, and will generate about 5 different XML screens. Probably around 1 or 2 thousand lines of code. The time it takes just to configure the frameworks may not be worth it. The final problem I can see is that developers in the company – who have to go over my code, and who do not know the PHP framework I may use – will have a much harder time understanding it. Given those pros and cons, I'm still not sure on what the best course of action will be; so any advice will be greatly appreciated.

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  • Obtaining positional information in the IEnumerable Select extension method

    - by Kyle Burns
    This blog entry is intended to provide a narrow and brief look into a way to use the Select extension method that I had until recently overlooked. Every developer who is using IEnumerable extension methods to work with data has been exposed to the Select extension method, because it is a pretty critical piece of almost every query over a collection of objects.  The method is defined on type IEnumerable and takes as its argument a function that accepts an item from the collection and returns an object which will be an item within the returned collection.  This allows you to perform transformations on the source collection.  A somewhat contrived example would be the following code that transforms a collection of strings into a collection of anonymous objects: 1: var media = new[] {"book", "cd", "tape"}; 2: var transformed = media.Select( item => 3: { 4: Media = item 5: } ); This code transforms the array of strings into a collection of objects which each have a string property called Media. If every developer using the LINQ extension methods already knows this, why am I blogging about it?  I’m blogging about it because the method has another overload that I hadn’t seen before I needed it a few weeks back and I thought I would share a little about it with whoever happens upon my blog.  In the other overload, the function defined in the first overload as: 1: Func<TSource, TResult> is instead defined as: 1: Func<TSource, int, TResult>   The additional parameter is an integer representing the current element’s position in the enumerable sequence.  I used this information in what I thought was a pretty cool way to compare collections and I’ll probably blog about that sometime in the near future, but for now we’ll continue with the contrived example I’ve already started to keep things simple and show how this works.  The following code sample shows how the positional information could be used in an alternating color scenario.  I’m using a foreach loop because IEnumerable doesn’t have a ForEach extension, but many libraries do add the ForEach extension to IEnumerable so you can update the code if you’re using one of these libraries or have created your own. 1: var media = new[] {"book", "cd", "tape"}; 2: foreach (var result in media.Select( 3: (item, index) => 4: new { Item = item, Index = index })) 5: { 6: Console.ForegroundColor = result.Index % 2 == 0 7: ? ConsoleColor.Blue : ConsoleColor.Yellow; 8: Console.WriteLine(result.Item); 9: }

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