Search Results

Search found 22623 results on 905 pages for 'base address'.

Page 65/905 | < Previous Page | 61 62 63 64 65 66 67 68 69 70 71 72  | Next Page >

  • msginit email address command line argument?

    - by C.W.Holeman II
    msginit prompts for an email address. Is there a way to tell msginit what email address to use without being prompted for it such as a command line argument? cat >hellogt.cxx <<EOF // hellogt.cxx #include <libintl.h> #include <locale.h> #include <iostream> int main (){ setlocale(LC_ALL, ""); bindtextdomain("hellogt", "./"); textdomain( "hellogt" ); std::cout << gettext("hello, world!") << std::endl; } EOF g++ -ohellogt hellogt.cxx xgettext -d hellogt -o hellogt.pot hellogt.cxx msginit -l es_MX -o spanish.po -i hellogt.pot

    Read the article

  • WCF - Beginners question on Address (of ABC)

    - by Lijo
    Hi Team, I am new to WCF. Following is a question on WCF. Suppose, I have a service defined as follows. The host has two addresses. I usually click on the base address http://.... to generate proxy. When the proxy is generated, will it have address of http alone? How can I generate a proxy with net.tcp. Is there any article that explains the use of net.tcp with local host and ASP.NET? service name="XXX.RRR.Common.ServiceLayer.MySL" behaviorConfiguration="returnFaults" endpoint contract="XXX.RRR.Common.ServiceLayer.IMySL" binding="netTcpBinding" bindingConfiguration="MessagingBinding" behaviorConfiguration="LargeEndpointBehavior"/ host baseAddresses add baseAddress="net.tcp://localhost:86/XXX/RRR/ManagerService" add baseAddress="http://localhost:76/XXX/RRR/ManagerService" baseAddresses host /service Thanks Lijo

    Read the article

  • VBScript LDAP: Is there a way to query for physicalDeliveryOfficeName using the email address in Act

    - by phill
    I'm attempting to utilize VBScript to connect pull the physicalDeliveryOfficeName attribute in Active Directory by providing the email address. I know how to do it with a common name like the following: Set MyUser = GetObject ("LDAP://cn=" & uname & ",ou=" & strname & ",DC=bobdom,DC=net") However only the email address is available. How to do this? I've even tried Set MyUser = GetObject ("LDAP://mail=" & uname & ",ou=" & strname & ",DC=bobdom,DC=net") and that doesn't work.

    Read the article

  • How best to implement "favourites" feature? (like favourite products on a data driven website)

    - by ClarkeyBoy
    Hi, I have written a dynamic database driven, object oriented website with an administration frontend etc etc. I would like to add a feature where customers can save items as "favourites", without having to create an account and login, to come back to them later, but I dont know how exactly to go about doing this... I see three options: Log favourites based on IP address and then change these to be logged against an account if the customer then creates an account; Force customers to create an account to be able to use this functionality; Log favourites based on IP address but give users the option to save their favourites under a name they specify. The problem with option 1 is that I dont know much about IP addresses - my Dad thinks they are unique, but I know people have had problems with systems like this. The problem with 1 and 2 is that accounts have not been opened up to customers yet - only administrators can log in at the moment. It should be easy to alter this (no more than a morning or afternoons work) but I would also have to implement usergroups too. The problem with option 3 is that if user A saves a favourites list called "My Favourites", and then user B tries to save a list under this name and it is refused, user B will then be able to access the list saved by user A because they now know it already exists. A solution to this is to password protect lists, but to go to all this effort I may as well implement option 2. Of course I could always use option 4; use an alternative if anyone can suggest a better solution than any of the above options. So has anyone ever done something like this before? If so how did you go about it? What do you recommend (or not recommend)? Many thanks in advance, Regards, Richard

    Read the article

  • Getting the valid email address.

    - by user219315
    Hi In a MVC application i want to validate the email addresses. I want to get the valid emailID from the list.If I use the emailaddress from the address book of any mail account then the name of the user get appended with the emailID .eg:"Ayushi Soni" ,.. and then copy these address to a textbox in an MVC application. Now I want to retrieve the actual EmailID from the list ignoring the name that is appended.Is there any utitliy or jquery that we can use to filter this out and validate the filtered email. I donot want to use regex,substring method for this. Thanks. skothari

    Read the article

  • Android Broadcast Address

    - by Eef
    Hey, I am making a Client Server application for my Android phone. I have created a UDP Server in Python which sits and listens for connections. I can put either the server IP address in directly like 192.169.0.100 and it sends data fine. I can also put in 192.168.0.255 and it find the server on 192.169.0.100. Is it possible to get the broadcast address of the network my Android phone is connected to? I am only ever going to use this application on my Wifi network or other Wifi networks. Cheers

    Read the article

  • change email address format with minimal disruption

    - by femi
    Hello, all the email addresses in my organization are in the format [email protected]. this was started when we were a small organization. Now we have grown and need to use something a bit more professional like [email protected] how can this change be implemented with minimal disruption? We currently only use smarteremail. Could recieving ONLY with the old and replying with the new be a solution..till we wean our recipients off the old email address? Any suggestions are welcome. How will moving to exchange help in this instance? Can it be configured to automatically send out using a different address? Thanks

    Read the article

  • Create link on page w/ web address stored in database

    - by RememberME
    This seems like it should be easy, but I can't seem to figure it out. All of my google searches lead me to linking to databases which isn't what I want to do. I'm a complete web development newb. I've roughly followed the NerdDinner tutorial in creating my web app. One of my stored fields is a web address. On the Index and Details pages, when I display the info from my record, I want the web address to be a clickable link to the website. It's currently displayed as: <%= Html.Encode(Model.Subcontract.company1.website) %>

    Read the article

  • Address Book is returning old values

    - by Marcus Wood
    Hi there, I am having a problem with the AddressBook framework. It all seems to be stemming from ABCopyRecordForUniqueId returning a record with old data. Example: I run up the program below in one terminal window - it shows the current data. I make a change through the address book UI - my program continues to show old data. I run up another instance of the same program in a new terminal window - it shows the updated data. I have tried posting on the omnigroup site with no luck :( so any guidance is really appreciated PS: If you would like to try the code, to get an address book ID you can export a contact as a vCard and open it with a text editor int main (int argc, const char * argv[]) { ABAddressBookRef addressBook = ABGetSharedAddressBook(); while(1) { ABRecordRef addressBookRecord = NULL; addressBookRecord = ABCopyRecordForUniqueId(addressBook, CFSTR("4064D587-0378-4DCF-A6B9-D3702F01C94C:ABPerson")); CFShow(addressBookRecord); CFRelease(addressBookRecord); sleep(1); } return 0; }

    Read the article

  • Syncing with Address Book: Last modified property in ABPerson/ABRecord

    - by Oliver
    I'm syncing data from the Address Book into a Core Data database and I've nearly got it working perfectly. The only issue remaining is checking for changes and modifications on startup and reflecting the changes inside Core Data. Currently, I simply check the ID of each ABRecord and see if it is already in Core Data. Of course, this only works in the case of new contacts and not changed information inside an existing contact. One solution would be to go through each contact already in the database and check each property against the Address Book. The down side of this is that it's really slow. One method that would work is if the ABRecord had a last modified date. I could then store the date inside the Core Data database and check on startup to see if I need to update the contact. However, I can't find anything like this in the documentation. Any ideas?

    Read the article

  • Obtaining the server IP address in WCF?

    - by chris
    How can I obtain the server IP address that was used to connect to a service? The server has multiple IP addresses and I need to know which one the client is connected to. So far I only found that OperationContext.Current.EndpointDispatcher.EndpointAddress and OperationContext.Current.Channel.LocalAddress contain the address from .config (e.g. localhost) OperationContext.Current.IncomingMessageProperties.Via contains the Url that the client used to connect to the server (but this might just be a name from the clients hosts file). EDIT - Sorry, I wasn't being clear enough: The server needs to know which of its IP addresses were used by the client. E.g. the server has the addresses 10.0.0.1 and 10.0.0.2. when processing the request the server service needs to know if 10.0.0.1 or 10.0.0.2 was used by the client to connect to it.

    Read the article

  • Git using wrong email address when talking to Heroku

    - by David
    git clone [email protected]:myapp.git Results in a "myoldemailaddress not authorized to access myapp" myoldemailaddress was an email address I was using on an old heroku account, but it seems to be stuck using it, I can use my new one. I've removed the .heroku directory, and regenerated it, it has the correct user name and password, I can see my apps listed I've uploaded my key (I've regenerated my several times now) ssh-keygen -t rsa -C mynewaddress I uninstalled and reinstalled heroku on a different user in the same machine it works just fine. Something about my account has my old address, but I can't figure out where.

    Read the article

  • How can I retrieve the last IP address of a user in Microsoft Exchange

    - by Pierre
    I need to determine the location of (mobiles) users within the enterprise buildings & floors. They are all using Microsoft Exchange & Office Communicator. If I have access to the IP address, I can know the location. Is there a way to retrieve the last IP address of the user by using Microsoft Exchange or Office Communication Server API ? If yes how ? Thanks a lot in advance.

    Read the article

  • Printing the address of a struct object

    - by bdhar
    I have a struct like this typedef struct _somestruct { int a; int b; }SOMESTRUCT,*LPSOMESTRUCT; I am creating an object for the struct and trying to print it's address like this int main() { LPSOMESTRUCT val = (LPSOMESTRUCT)malloc(sizeof(SOMESTRUCT)); printf("0%x\n", val); return 0; } ..and I get this warning warning C4313: 'printf' : '%x' in format string conflicts with argument 1 of type 'LPSOMESTRUCT' So, I tried to cast the address to int like this printf("0%x\n", static_cast<int>(val)); But I get this error: error C2440: 'static_cast' : cannot convert from 'LPSOMESTRUCT' to 'int' What am I missing here? How to avoid this warning? Thanks.

    Read the article

  • Matching an IP address with an IP range?

    - by Legend
    I have a MySQL table setup as follows: +---------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------+-------------+------+-----+---------+----------------+ | ipaddress_s | varchar(15) | YES | MUL | NULL | | | ipaddress_e | varchar(16) | YES | | NULL | | +---------------+-------------+------+-----+---------+----------------+ where, ipaddress_s and ipaddress_e look something like: 4.100.159.0-4.100.159.255 Now is there a way I can actually get the row that contains a given IP address? For instance, given the IP address: "4.100.159.5", I want the above row to be returned. So I am trying for a query that looks something like this (but of course this is wrong because in the following I am considering IPs as strings): SELECT * FROM ranges WHERE ipaddress_s<"4.100.159.5" AND ipaddress_e>"4.100.159.5" Any suggestions?

    Read the article

  • Catching the redirected address from NSURLConnection

    - by Vic
    I'm working on a software which follows the HTTP redirection which is dynamically calculated by the server depending on a pparameter. I don't want to show the primary server in Mobile Safari but rather the redirected address only. The following code workks: request = [NSMutableURLRequest requestWithURL:originalUrl cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:10]; [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; // Extract the redirected URL target = [response URL]; The problem is that the server requires several seconds to answer. The sendSynchronousRequest blocks the app for this time completely which is messy, I can't even display the "Busy" animation. Does anyone know how I can retrieve the redirected address asynchronously without safari appearance in the meanwhile with the redirecting server URL or display some sort of the "Be patient" animation during the sendSynchronousRequest? What disadvantages would have the passing of sendSynchronousRequest in another thread?

    Read the article

  • Getting the 'external' IP address in Java

    - by Caylem
    Hi I'm not too sure how to go about getting the external IP address of the machine as a computer outside of a network would see it. My following IPAddress class only gets the local IP address of the machine. Any help would be appreciated. Thanks. public class IPAddress { private InetAddress thisIp; private String thisIpAddress; private void setIpAdd(){ try{ InetAddress thisIp = InetAddress.getLocalHost(); thisIpAddress = thisIp.getHostAddress().toString(); } catch(Exception e){} } protected String getIpAddress(){ setIpAdd(); return thisIpAddress; } }

    Read the article

< Previous Page | 61 62 63 64 65 66 67 68 69 70 71 72  | Next Page >