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  • problem in table:

    - by Ayyappan.Anbalagan
    i had table inside the another table, my inner table display the image, if i enter the text after the inner table,The text should display right side of the table and the bottom of the inner table.how do i do this??? "the below code display the outer table text always displayed bellow the inner table" Heading ## <tr style=" width:500px; float:left;"> <td style="border: thin ridge #008000; text-align:left;" align="left"; > <table class="" style=" border: 1px solid #800000; width:200px; float:left; height: 200px;"> <tr> <td>&nbsp;stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow&nbsp; </td> </tr> </table> stackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow statackoverflow sta</td> </tr> </table>

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  • Table cell in a split-view controller - selected cell becomes deselected when called by reloadData

    - by bpapa
    I'm working on a universal app that uses a SplitViewController to present a master-detail view. In the iPad HIG on Split Views, Apple states: In general, indicate the current selection in the left pane in a persistent way. This behavior helps people understand the relationship between the item in the left pane and the contents of the right pane. This is important because the contents of the right pane can change, but they should always remain related to the item selected in the left pane. So I'm trying to maintain selection state on the left. Easy enough when the user taps, I just remove the deselectRowAtIndexPath:animated: message from tableView:didSelectRowAtIndexPath: implementation. But, I also want the selection state to show up by default (without a user tap). I wound up putting this in my tableView:cellForRowAtIndexPath: implementation: if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) { if (cellShouldBeSelected) cell.selected = YES; else cell.selected = NO; } The behavior I'm seeing, is that when the cells finall appear, for a fraction of a section the cell is indeed selected, but then the selection disappears without any user interaction. Any ideas? I set the new clearsSelectionOnViewWillAppear property to NO, but that doesn't seem to fix it, and it shouldn't really matter because I'm marking the cell as selected long after viewWillAppear is called - I'm actually doing it after some network activity and then sending the table view a reloadData message.

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  • Monads and custom traversal functions in Haskell

    - by Bill
    Given the following simple BST definition: data Tree x = Empty | Leaf x | Node x (Tree x) (Tree x) deriving (Show, Eq) inOrder :: Tree x -> [x] inOrder Empty = [] inOrder (Leaf x) = [x] inOrder (Node root left right) = inOrder left ++ [root] ++ inOrder right I'd like to write an in-order function that can have side effects. I achieved that with: inOrderM :: (Show x, Monad m) => (x -> m a) -> Tree x -> m () inOrderM f (Empty) = return () inOrderM f (Leaf y) = f y >> return () inOrderM f (Node root left right) = inOrderM f left >> f root >> inOrderM f right -- print tree in order to stdout inOrderM print tree This works fine, but it seems repetitive - the same logic is already present in inOrder and my experience with Haskell leads me to believe that I'm probably doing something wrong if I'm writing a similar thing twice. Is there any way that I can write a single function inOrder that can take either pure or monadic functions?

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  • How to make an equation span the whole page / line in LaTeX?

    - by Reed Richards
    I have this equation and it's quite big (basically a FDM one) but it aligns with the text and then continues out on the right side to the nothingness. I've tried stuff like \begin{center} and \hspace*{-2.5cm} but to no avail. I want it to use the whole line not just from the left-margin and out to the right. How do I do it and do I need to install some special package for it? I use the \[ instead of the displaymath like this \[ Equation arrays here \] The code \[ \left( \begin{array}{cccccc} -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots & 0 \\ -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots \\ 0 & -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots \\ \vdots & 0 & \ddots & \vdots \\ \vdots & \vdots & \vdots & -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) \\ 0 & \vdots & \vdots & 0 & \kappa - \frac{2h\kappa_{v}}{\kappa}(\frac{hv\rho}{2} - \kappa) & -2\kappa \\ \end{array} \right) \left( \begin{array}{c} T_{1} \\ T_{2} \\ \vdots \\ T_{n} \\ \end{array} \right) = \left( \begin{array}{c} Q(0) + \kappa T_{0} \\ Q(h) \\ Q(2h) \\ \vdots \\ Q((n-1)h) \\ 2\frac{\kappa_{v}}{\kappa_{v}}T_{out} \\ \end{array} \right) \]

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  • How do you rotate a sprite around its center by caclulating a new x and y position?

    - by Sam152
    I'm using Dark GDK and C++ to create a simple 2d game. I'm rotating an object but it rotates from the top left corner of the sprite. I have the following variables available: PlayerX PlayerY PlayerWidth PlayerHeight RotateAngle (360 x 0) Is there an algorithm that will modify the pivot point of the sprite, preferable to the center? Here is a small code sample: void Player::Move( void ) { if ( checkLeft() ) { PlayerX -= PlayerSpeed; if ( PlayerX < 0 ) PlayerX = 0; } if ( checkRight() ) { PlayerX += PlayerSpeed ; if ( PlayerX > 800 - PlayerWidth ) PlayerX = 800 - PlayerWidth; } if ( checkUp()) { PlayerY -= PlayerSpeed; if ( PlayerY < 0 ) PlayerY = 0; } if ( checkDown()) { PlayerY += PlayerSpeed; if ( PlayerY > 600 - PlayerHeight) PlayerY = 600 - PlayerHeight; } RotateAngle += 5; if(RotateAngle > 360) RotateAngle -=360; dbRotateSprite(Handle,RotateAngle); dbSprite ( 1 , PlayerX , PlayerY , Handle ); } Edit I'm considering opening up some reputation for this question, I have yet to be provided with an answer that works for me. If someone can provide an actual code sample that does the job, I'd be very happy. The problem with Blindy's answer is that no matter how much I simply translate it back or forth, the spirte still rotates around the top left hand corner and moving it somewhere rotating around the top left corner, then moving it back to the same position accomplishes nothing. Here is what I believe to be going on: Just so there is no confusion I have created a an image of what is going on. The left shows what is actually happening and the right shows what I need to happen.

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  • Some jQuery-powered features not working in Chrome

    - by Enchantner
    I'm using a jCarouselLite plugin for creating two image galleries on the main page of my Django-powered site. The code of elements with navigation arrows is generating dynamically like this: $(document).ready(function () { $('[jq\\:corner]').each(function(index, item) { item = $(item); item.corner(item.attr('jq:corner')) }) $('[jq\\:menu]').each(function (index, item) { item = $(item); item.menu(item.attr('jq:menu')) }) $('[jq\\:carousel]').each(function(index, item) { item = $(item); var args = item.attr('jq:carousel').split(/\s+/) lister = item.parent().attr('class') + '_lister' item.parent().append('<div id="'+ lister +'"></div>'); $('#' + lister).append("<a class='nav left' href='#'></a><a class='nav right' href='#'></a>"); toparrow = $(item).position().top + $(item).height() - 50; widtharrow = $(item).width(); $('#' + lister).css({ 'display': 'inline-block', 'z-index': 10, 'position': 'absolute', 'margin-left': '-22px', 'top': toparrow, 'width': widtharrow }) $('#' + lister + ' .nav.right').css({ 'margin-left': $('#' + lister).width() + 22 }) item.jCarouselLite({ btnNext: '#' + lister + ' .nav.right', btnPrev: '#' + lister + ' .nav.left', visible: parseInt(args[0]) }) }) The problem is that if page is loaded through an url, typed in the adress bar, some functions doesn't work and the second gallery appears with the wrong parameters, but if I came to this page via clicking link - everything works perfectly. It happends only in Google Chrome (Ubuntu, stable 5.0.360.0), but not in Firefox or Opera. What could be the reason?

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  • SQL Query Returning Duplicate Results

    - by Jesse Bunch
    Hi, I've been working out this query now for a while and I thought I had it where I wanted it, but apparently not. There are two records in the database (orders). The query should return two different rows, but instead returns two rows that have exactly the same values. I think it may be something to do with the GROUP BY or derived tables I'm using but my eyes are tired and not seeing the problem. Can any of you help? Thanks in advance. SELECT orders.billerID, orders.invoiceDate, orders.txnID, orders.bName, orders.bStreet1, orders.bStreet2, orders.bCity, orders.bState, orders.bZip, orders.bCountry, orders.sName, orders.sStreet1, orders.sStreet2, orders.sCity, orders.sState, orders.sZip, orders.sCountry, orders.paymentType, orders.invoiceNotes, orders.pFee, orders.shipping, orders.tax, orders.reasonCode, orders.txnType, orders.customerID, customers.firstName AS firstName, customers.lastName AS lastName, customers.businessName AS businessName, orderStatus.statusName AS orderStatus, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax AS orderTotal, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax - IFNULL(payments.totalPayments, 0.00) AS orderBalance FROM orders LEFT JOIN customers ON orders.customerID = customers.id LEFT JOIN orderStatus ON orders.orderStatus = orderStatus.id LEFT JOIN ( SELECT orderItems.orderID, SUM(orderItems.itemPrice * orderItems.itemQuantity) as itemTotal FROM orderItems GROUP BY orderItems.orderID ) orderItems ON orderItems.orderID = orders.id LEFT JOIN ( SELECT payments.orderID, SUM(payments.amount) as totalPayments FROM payments GROUP BY payments.orderID ) payments ON payments.orderID = orders.id

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  • ios 4.1 doesn't call Phonegap API

    - by Johannes Klauß
    I'm working on a cross platform app for Android 2.2 and iOS 4.1 (dev devices). On Android everything works fine (accelerometer and geolocation) even if it's a little laggy. On iOS it's way more smooth, but he doesn't call the Phonegap functions. That's my JS code: var watchID = null; var shaking = { left: false, right: true }; function startWatch() { // Update acceleration every 100 ms var options = { frequency : 100 }; watchID = navigator.accelerometer.watchAcceleration(function(acceleration) { if(acceleration.x < -8) { shaking.left = true; } else if(acceleration.x > 8) { shaking.right = true; } if(shaking.left && shaking.right) { navigator.notification.vibrate(500); shaking.left = false; shaking.right = false; stopWatch(); } }, null, options); } I just call it with <a href="" onclick="startWatch();">start Accel</a> But iOS doesn't react at all. Is there any special call you need to do in iOS?

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  • How to preserve order of temp table rows when inner joined with another table?

    - by Triynko
    Does an SQL Server "join" preserve any kind of row order consistently (i.e. that of the left table or that of the right table)? Psuedocode: create table #p (personid bigint); foreach (id in personid_list) insert into #p (personid) values (id) select id from users inner join #p on users.personid = #p.id Suppose I have a list of IDs that correspond to person entries. Each of those IDs may correspond to zero or more user accounts (since each person can have multiple accounts). To quickly select columns from the users table, I populate a temp table with person ids, then inner join it with the users table. I'm looking for an efficient way to ensure that the order of the results in the join matches the order of the ids as they were inserted into the temp table, so that the user list that's returned is in the same order as the person list as it was entered. I've considered the following alternatives: using "#p inner join users", in case the left table's order is preserved using "#p left join users where id is not null", in case a left join preserves order and the inner join doesn't using "create table (rownum int, personid bigint)", inserting an incrementing row number as the temp table is populated, so the results can be ordered by rownum in the join using an SQL Server equivalent of the "order by order of [tablename]" clause available in DB2 I'm currently using option 3, and it works... but I hate the idea of using an order by clause for something that's already ordered. I just don't know if the temp table preserves the order in which the rows were inserted or how the join operates and what order the results come out in.

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  • Complex SQL query, one to many relationship

    - by Ethan
    Hey SO, I have a query such that I need to get A specific dog All comments relating to that dog The user who posted each comment All links to images of the dog the user who posted each link I've tried a several things, and can't figure out quite how to work it. Here's what I have (condensed so you don't have to wade through it all): SELECT s.dog_id, s.name, c.comment, c.date_added AS comment_date_added, u.username AS comment_username, u.user_id AS comment_user_id, l.link AS link, l.date_added AS link_date_added, u2.username AS link_username, u2.user_id AS link_user_id FROM dogs AS d LEFT JOIN comments AS c ON c.dog_id = d.dog_id LEFT JOIN users AS u ON c.user_id = u.user_id LEFT JOIN links AS l ON l.dog_id = d.dog_id LEFT JOIN users AS u2 ON l.user_id = u2.user_id WHERE d.dog_id = '1' It's sorta close to working, but it'll only return me the first comment, and the first link all as one big array with all the info i requested. The are multiple comments and links per dog, so I need it to give me all the comments and all the links. Ideally it'd return an object with dog_id, name, comments(an array of the comments), links(an array of the links) and then comments would have a bunch of comments, date_added, username, and user_id and links would have a bunch of links with link, date_added, username and user_id. It's got to work even if there are no links or comments. I learned the basics of mySQL somewhat recently, but this is pretty far over my head. Any help would be wonderful. Thanks!

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  • Manipulating / Resizing / Scaling an image in vb.net

    - by Christian Payne
    Imagine I have a rectangle say 400px x 300px. Then let’s say I want to load an image in that. All of this is very easy using Sytem.Drawing.DrawImage. But then I want to leave the left hand side as 300px but change the right hand side to 250 px. I can draw the box using 4 DrawLines but I don’t know how to squash the image into the new shape. I want the right hand side of the shape to be 250, the left size 300 and the top and bottom 400px. I can’t use DrawImage as it expects the left and right sizes to be the same. Is there a way to manipulate the image into the new shape? I've looked at other questions, but they only apply where the left and right hand side is equal. Any thoughts on how to squash an image into a shape which did not have parallel sides? (If it helps, I'm happy to sacrifice image quality to fit the right shape.)

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  • How to make jquery hover event fire repeatedly.

    - by clinthorner
    I have a infinite carousel that I want to move when I hover over the next and previous buttons. Right now hover only fires this once. I want the carousel to continue moving while the mouse is within the next or previous buttons. Any Suggestions? jQuery.fn.carousel = function(previous, next, options){ var sliderList = jQuery(this).children()[0]; if (sliderList) { var increment = jQuery(sliderList).children().outerWidth("true"), elmnts = jQuery(sliderList).children(), numElmts = elmnts.length, sizeFirstElmnt = increment, shownInViewport = Math.round(jQuery(this).width() / sizeFirstElmnt), firstElementOnViewPort = 1, isAnimating = false; for (i = 0; i < shownInViewport; i++) { jQuery(sliderList).css('width',(numElmts+shownInViewport)*increment + increment + "px"); jQuery(sliderList).append(jQuery(elmnts[i]).clone()); } jQuery(previous).hover(function(event){ if (!isAnimating) { if (firstElementOnViewPort == 1) { jQuery(sliderList).css('left', "-" + numElmts * sizeFirstElmnt + "px"); firstElementOnViewPort = numElmts; } else { firstElementOnViewPort--; } jQuery(sliderList).animate({ left: "+=" + increment, y: 0, queue: true }, "swing", function(){isAnimating = false;}); isAnimating = true; } }); jQuery(next).hover(function(event){ if (!isAnimating) { if (firstElementOnViewPort > numElmts) { firstElementOnViewPort = 2; jQuery(sliderList).css('left', "0px"); } else { firstElementOnViewPort++; } jQuery(sliderList).animate({ left: "-=" + increment, y: 0, queue: true }, "swing", function(){isAnimating = false;}); isAnimating = true; } }); } };

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  • jquery-infinite-carousel - jump 3 items instead of one

    - by Rob B
    Successfully used jquery-infinite-carousel in the past but for my current project I need it to loop forever AND also jump 3 items at a time. Example of how it works jumping 1 at a time here. jQuery.fn.carousel = function(previous, next, options){ var sliderList = jQuery(this).children()[0]; if (sliderList) { var increment = jQuery(sliderList).children().outerWidth("true"), elmnts = jQuery(sliderList).children(), numElmts = elmnts.length, sizeFirstElmnt = increment, shownInViewport = Math.round(jQuery(this).width() / sizeFirstElmnt), firstElementOnViewPort = 1, isAnimating = false; //console.log("increment = " + increment); //console.log("numElmts = " + numElmts); //console.log("shownInViewport = " + shownInViewport); for (i = 0; i < shownInViewport; i++) { jQuery(sliderList).css('width',(numElmts+shownInViewport)*increment + increment + "px"); jQuery(sliderList).append(jQuery(elmnts[i]).clone()); } jQuery(previous).click(function(event){ if (!isAnimating) { if (firstElementOnViewPort == 1) { jQuery(sliderList).css('left', "-" + numElmts * sizeFirstElmnt + "px"); firstElementOnViewPort = numElmts; console.log("firstElementOnViewPort = " + firstElementOnViewPort); } else { firstElementOnViewPort--; } jQuery(sliderList).animate({ left: "+=" + increment, y: 0, queue: true }, "swing", function(){isAnimating = false;}); isAnimating = true; } }); jQuery(next).click(function(event){ if (!isAnimating) { if (firstElementOnViewPort > numElmts) { firstElementOnViewPort = 2; jQuery(sliderList).css('left', "0px"); } else { firstElementOnViewPort++; } jQuery(sliderList).animate({ left: "-=" + (increment), y: 0, queue: true }, "swing", function(){isAnimating = false;}); isAnimating = true; } }); } };

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  • BitShifting with BigIntegers in Java

    - by ThePinkPoo
    I am implementing DES Encryption in Java with use of BigIntegers. I am left shifting binary keys with Java BigIntegers by doing the BigInteger.leftShift(int n) method. Key of N (Kn) is dependent on the result of the shift of Kn-1. The problem I am getting is that I am printing out the results after each key is generated and the shifting is not the expected out put. The key is split in 2 Cn and Dn (left and right respectively). I am specifically attempting this: "To do a left shift, move each bit one place to the left, except for the first bit, which is cycled to the end of the block. " It seems to tack on O's on the end depending on the shift. Not sure how to go about correcting this. Results: c0: 11110101010100110011000011110 d0: 11110001111001100110101010100 c1: 111101010101001100110000111100 d1: 111100011110011001101010101000 c2: 11110101010100110011000011110000 d2: 11110001111001100110101010100000 c3: 1111010101010011001100001111000000 d3: 1111000111100110011010101010000000 c4: 111101010101001100110000111100000000 d4: 111100011110011001101010101000000000 c5: 11110101010100110011000011110000000000 d5: 11110001111001100110101010100000000000 c6: 1111010101010011001100001111000000000000 d6: 1111000111100110011010101010000000000000 c7: 111101010101001100110000111100000000000000 d7: 111100011110011001101010101000000000000000 c8: 1111010101010011001100001111000000000000000 d8: 1111000111100110011010101010000000000000000 c9: 111101010101001100110000111100000000000000000 d9: 111100011110011001101010101000000000000000000 c10: 11110101010100110011000011110000000000000000000 d10: 11110001111001100110101010100000000000000000000 c11: 1111010101010011001100001111000000000000000000000 d11: 1111000111100110011010101010000000000000000000000 c12: 111101010101001100110000111100000000000000000000000 d12: 111100011110011001101010101000000000000000000000000 c13: 11110101010100110011000011110000000000000000000000000 d13: 11110001111001100110101010100000000000000000000000000 c14: 1111010101010011001100001111000000000000000000000000000 d14: 1111000111100110011010101010000000000000000000000000000 c15: 11110101010100110011000011110000000000000000000000000000 d15: 11110001111001100110101010100000000000000000000000000000

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  • postgres - ERROR: operator does not exist

    - by cino21122
    Again, I have a function that works fine locally, but moving it online yields a big fat error... Taking a cue from a response in which someone had pointed out the number of arguments I was passing wasn't accurate, I double-checked in this situation to be certain that I am passing 5 arguments to the function itself... Query failed: ERROR: operator does not exist: point <@> point HINT: No operator matches the given name and argument type(s). You may need to add explicit type casts. The query is this: BEGIN; SELECT zip_proximity_sum('zc', (SELECT g.lat FROM geocoded g LEFT JOIN masterfile m ON g.recordid = m.id WHERE m.zip = '10050' ORDER BY m.id LIMIT 1), (SELECT g.lon FROM geocoded g LEFT JOIN masterfile m ON g.recordid = m.id WHERE m.zip = '10050' ORDER BY m.id LIMIT 1), (SELECT m.zip FROM geocoded g LEFT JOIN masterfile m ON g.recordid = m.id WHERE m.zip = '10050' ORDER BY m.id LIMIT 1) ,10); The PG function is this: CREATE OR REPLACE FUNCTION zip_proximity_sum(refcursor, numeric, numeric, character, numeric) RETURNS refcursor AS $BODY$ BEGIN OPEN $1 FOR SELECT r.zip, point($2,$3) <@> point(g.lat, g.lon) AS distance FROM geocoded g LEFT JOIN masterfile r ON g.recordid = r.id WHERE (geo_distance( point($2,$3),point(g.lat,g.lon)) < $5) ORDER BY r.zip, distance; RETURN $1; END; $BODY$ LANGUAGE 'plpgsql' VOLATILE COST 100;

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  • Vectors rotations 3D camera tiliting

    - by TallGuy
    Hopefully easy answer, but I cannot get it. I have a 3D render engine I have written. I have the camera position, the lookat position and the up vector. I want to be able to "tilt" the camera left, right, up and down. Like a camera on a fixed tripod that you can grab the handle and tilt it it up, down, left right etc. The maths stumps me. I have been able to do forwards/backwards dolly and up/down/left/right panning, but cannot work out the vector math to get it to tilt. For left and right tilt I want to rotate the lookat position around the camera position, but I need to take into account the up vector, otherwise the rotation doesn't know which axis to to turn around. The maths/algorithm I need is along the lines of... Camera=(cx,cy,cz) Lookat=(lx,ly,lz) Up=(ux,uy,uz) RotatePointAroundVector(lx,ly,lz,ux,uy,uz,amount) Can anyone assist with the maths involved? Many thanks.

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  • Get data on jquery ajax success

    - by jbatson
    anyone know how i would get from opening <table> to </table> in this data that is returned from ajax with jquery. // BEGIN Subsys_JsHttpRequest_Js Subsys_JsHttpRequest_Js.dataReady( '3599', // this ID is passed from JavaScript frontend '<table border=\"0\" width=\"100%\" cellspacing=\"0\" cellpadding=\"0\">\n <tr>\n <td>\n <script type=\"text/javascript\" language=\"javascript\" src=\"includes/ajax_sc.js\"></script>\n <div id=\"divShoppingCard\">\n\n <div class=\"infoBoxHeading\"><a href=\"shopping_cart.php\">Shopping Cart</a></div>\n\n <div>\n <div class=\"boxText\">\n<script language=\"javascript\" type=\"text/javascript\">\nfunction couponpopupWindow(url) {\n window.open(url,\"popupWindow\",\"toolbar=no,location=no,directories=no,status=no,menubar=no,scrollbars=yes,resizable=yes,copyhistory=no,width=450,height=280,screenX=150,screenY=150,top=150,left=150\")\n}\n//--></script><table width=\"100%\" cellspacing=\"0\" cellpadding=\"0\"><tr><td align=\"left\" valign=\"top\" class=\"infoBoxContents\"><span class=\"infoBoxContents\">1&nbsp;x&nbsp;</span></td><td valign=\"top\" class=\"infoBoxContents\"><a href=\"http://beta.vikingwholesale.com/catalog/eagle-vanguard-limited-edition-p-3769.html\"><span class=\"infoBoxContents\">192 Eagle Vanguard Limited Edition</span></a></td></tr><tr><td align=\"left\" valign=\"top\" class=\"infoBoxContents\"><span class=\"newItemInCart\">4&nbsp;x&nbsp;</span></td><td valign=\"top\" class=\"infoBoxContents\"><a href=\"http://beta.vikingwholesale.com/catalog/family-traditions-adrenaline-avid-black-p-3599.html\"><span class=\"newItemInCart\">085 Family Traditions Adrenaline - Avid, Black</span></a></td></tr><tr><td align=\"left\" valign=\"top\" class=\"infoBoxContents\"><span class=\"infoBoxContents\">1&nbsp;x&nbsp;</span></td><td valign=\"top\" class=\"infoBoxContents\"><a href=\"http://beta.vikingwholesale.com/catalog/painted-pony-paradigm-p-4022.html\"><span class=\"infoBoxContents\">336 Painted Pony Paradigm</span></a></td></tr></table></div>\n\n\n <div class=\"boxText\"><img src=\"images/pixel_black.gif\" width=\"100%\" height=\"1\" alt=\"\"/></div>\n\n\n <div class=\"boxText\">$940.00</div>\n\n\n</div>\n\n\n \n </div><!--end of divShoppingCard-->\n </td>\n </tr></table>', null ) // END Subsys_JsHttpRequest_Js

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  • Simulating 3D 'cards' with just orthographic rendering

    - by meds
    I am rendering textured quads from an orthographic perspective and would like to simulate 'depth' by modifying UVs and the vertex positions of the quads four points (top left, top right, bottom left, bottom right). I've found if I make the top left and bottom right corners y position be the same I don't get a linear 'skew' but rather a warped one where the texture covering the top triangle (which makes up the quad) seems to get squashed while the bottom triangles texture looks normal. I can change UVs, any of the four points on the quad (but only in 2D space, it's orthographic projection anyway so 3D space won't matter much). So basically I'm trying to simulate perspective on a two dimensional quad in orthographic projection, any ideas? Is it even mathematically possible/feasible? ideally what I'd like is a situation where I can set an x/y rotation as well as a virtual z 'position' (which simulates z depth) through a function and see it internally calclate the positions/uvs to create the 3D effect. It seems like this should all be mathematical where a set of 2D transforms can be applied to each corner of the quad to simulate depth, I just don't know how to make it happen. I'd guess it requires trigonometry or something, I'm trying to crunch the math but not making much progress. here's what I mean: Top left is just the card, center is the card with a y rotation of X degrees and right most is a card with an x and y rotation of different degrees.

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  • [jQuery 1.4] move one div over another

    - by Tomasz Zielinski
    I have two div elements that are twins (i.e. their dimensions and contents are identical). I want to move of those div-s over another, so that their corners are at exactly the same coordinates. What I try to do is: var offset = $('div#placeholder').offset(); $('div#overlay').css('position', 'absolute').css('left', offset.left + 'px').css('top', offset.top + 'px') -- but this causes the overlay to be exactly (or almost exactly, taking subpixel accuracy into account) 16px below the placeholder (below, i.e. overlay_top = placeholder_top + 16px). I'm aware that offset() gives position relative to the document, and position: absolute sets position relative to body element, but compensating for body offset() doesn't help much (I'm getting 8px offset, equal to margins): offset.top -= $('body').offset().top; offset.left -= $('body').offset().left; Also, compensating for body margins (in case they were different that offset() didn't help, as they were set to 8px). Does somebody know what I'm doing wrong here? UPDATE: Take a look at here - I'm getting the same result in FireFox 3.6.3 and Opera 10.10.

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  • Anchor HTML DIV tag to right of screen

    - by Phillip
    Hello, I have a site that has 2 DIV tags, one floats left the other floats right. The left DIV contains text for the page, the other DIV is used to display a video. When I have text in the left DIV that fits the entire width of the screen the video shows up where I want it. However, a few pages have very little text and cause the video to show up in the right-center of the screen. I want to anchor this DIV to the right of the screen regardless of how much text is shown. I don't seem to get this problem in lower resolutions, it occurs more in the higher resolutions (such as 1280x1024). You can see an example on these pages: http://www.quilnet.com/TechSupport.aspx - Positions the right DIV where I want it regardless of the resolution. http://www.quilnet.com/ContactUs.aspx - Makes the right DIV closer to the center in higher resolutions. I want it in the position of the page TechSupport.aspx. I am trying to refrain from using the width parameter because I want it to be resolutionally compliant. I don't want my viewers to have to move a scroll bar left and right. Any ideas? Thanks!

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  • Query with many CASE statements - optimization

    - by Nemanja Vujacic
    Hi guys, I have one very dirty query that per sure can be optimized because there are so many CASE statements in it! SELECT (CASE pa.KplusTable_Id WHEN 1 THEN sp.sp_id WHEN 2 THEN fw.fw_id WHEN 3 THEN s.sw_Id WHEN 4 THEN id.ia_id END) as Deal_Id, max(CASE pa.KplusTable_Id WHEN 1 THEN sp.Trans_Id WHEN 2 THEN fw.Trans_Id WHEN 3 THEN s.Trans_Id WHEN 4 THEN id.Trans_Id END) as TransId_CurrentMax INTO #MaxRazlicitOdNull FROM #PotencijalniAktuelni pa LEFT JOIN kplus_sp sp (nolock) on sp.sp_id=pa.Deal_Id AND pa.KplusTable_Id=1 LEFT JOIN kplus_fw fw (nolock) on fw.fw_id=pa.Deal_Id AND pa.KplusTable_Id=2 LEFT JOIN dev_sw s (nolock) on s.sw_Id=pa.Deal_Id AND pa.KplusTable_Id=3 LEFT JOIN kplus_ia id (nolock) on id.ia_id=pa.Deal_Id AND pa.KplusTable_Id=4 WHERE isnull(CASE pa.KplusTable_Id WHEN 1 THEN sp.BROJ_TIKETA WHEN 2 THEN fw.BROJ_TIKETA WHEN 3 THEN s.tiket WHEN 4 THEN id.BROJ_TIKETA END, '')<>'' GROUP BY CASE pa.KplusTable_Id WHEN 1 THEN sp.sp_id WHEN 2 THEN fw.fw_id WHEN 3 THEN s.sw_Id WHEN 4 THEN id.ia_id END Because I have same condition couple times, do you have idea how to optimize query, make it simpler and better. All suggestions are welcome! TnX in advance! Nemanja

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  • Two column layout, navigation div on the right, solution from previous thread didn't seem to work

    - by Tom
    I tried the solution from this thread, but I must be missing something because it doesn't work: <div style="float:left;margin-right:200px"> <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum.</p> </div> <div style="float:right;width:200px"> <p>navigation</p> </div> It works when the text in the content div (the left one) is short, but when it's long then the div takes up the whole width of the browser and the margin is there, but the right div is pushed below the first one nevertheless. What am I missing? Edit: The goal is to have a fix sized navigation column on the right of the browser window and the left div should get all the space left by the right navigation column (liquid layout).

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  • How to Post Javascript to a MySQL Database

    - by salientanimal
    Hi guys, I have created a form in HTLM and I m trying to post the information in the form to a MySQL database. My form make suse of a dynamic list selection that needs to be captured to the database. However when submtting the form I get the following error Error: Unknown column 'coulmn_name' in 'field list'. Here is my HTML CODE for the form <td height="94"><p align="justify">CALL TRACKER - ADMIN</p></td> Customer Name : E-Mail Address : </tr> <tr> <td width="29%" align="right" valign="middle"><strong>Case Number :</strong></td> <td> <input type="text" name="case_number" width="70%" align="left" valign="middle"> </td> </tr> <tr> <td width="29%" align="right" valign="middle"><strong>MSISDN :</strong></td> <td> <input type="text" name="msisdn" width="70%" align="left" valign="middle"> </td> </tr> <tr> <td width="29%" align="right" valign="middle"> <strong>Route Cause :</strong></td> <td width="71%" align="left" valign="middle"> <select name="route_cause" id="category" onChange="javascript: listboxchange1(this.options[this.selectedIndex].value);"> <!-- <select name="route_cause" id="route_cause"> --> <option value="">Select the Call Reason</option> <option value="Billing Admin">Billing Admin</option> <option value="Customer Care">Customer Care</option> <option value="Insurance">Insurance</option> <option value="Repairs">Repairs</option> <option value="SIM Swap">SIM Swap</option> <option value="UTI">UTI</option> </select> </td> </tr> <tr> <td align="right" valign="middle"> <strong>Call Type/Indexed To :</strong></td> <td align="left" valign="middle"> <script type="text/javascript" language="javascript" name="calltype_indexedto"> <!-- document.write('<select name="subcategory1" onChange="javascript: listboxchange2(this.options[this.selectedIndex].value);"><option value=""></option></select>') --> </script> </td> </tr> <tr> <td align="right" valign="middle"> <strong>Type/TAT :</strong></td> <td align="left" valign="middle"> <script type="text/javascript" language="javascript" name="type_tat"> <!-- document.write('<select name="subcategory2" onChange="javascript: listboxchange3(this.options[this.selectedIndex].value);"><option value=""></option></select>') --> </script> </td> </tr> <tr> <td width="29%" align="right" valign="middle"> <strong>Escalated To :</strong></td> <td width="71%" align="left" valign="middle"> <select name="escalatedto" id="escalated_to"> <option value="">Select the Escalation</option> <option value="Billing Ops">Billing Ops</option> <option value="Resolvers">Resolvers</option> <option value="Finance">Finance</option> <option value="Ressolver">Ressolver</option> <option value="Nudebt">Nudebt</option> <option value="Transunion">Transunion</option> <option value="N/A">N/A</option> </select> </td> </tr> <tr> <td width="29%" align="right" valign="middle"> <strong>Requested By :</strong></td> <td width="71%" align="left" valign="middle"> <select name="requestedby" id="requested_by"> <option value="">UTI Requested By</option> <option value="Billing">Billing</option> <option value="Customer Service">Customer Service</option> <option value="Insurance">Insurance</option> <option value="Management">Management</option> <option value="Repairs">Repairs</option> <option value="Retail Support">Retail Support</option> <option value="Retentions">Retentions</option> <option value="SIM Swap">SIM Swap</option> <option value="WOW">WOW</option> <option value="N/A">N/A</option> </select> </td> </tr> <tr> <td width="29%" align="right" valign="middle"> <strong>Province :</strong></td> <td width="71%" align="left" valign="middle"> <select name="province" id="province"> <option value="">Select the Province</option> <option value="Eastern Cape">Eastern Cape</option> <option value="Gauteng">Gauteng</option> <option value="Kwa-Zulu Natal">Kwa-Zulu Natal</option> <option value="Limpopo">Limpopo</option> <option value="Mpumalanga">Mpumalanga</option> <option value="North West">North West</option> <option value="Northern Cape">Northern Cape</option> <option value="Polokwane">Polokwane</option> <option value="Western Cape">Western Cape</option> <option value="Other">Other</option> </select> </td> </tr> <tr> <td width="29%" align="right" valign="middle"><strong>Comments :</strong></td> <td> <textarea rows ="5" cols="30" name="comments"> </textarea> </td> </tr> <tr> <td> <p> <input type="reset" value="Reset Form"><input type="Submit" value="Submit"> Here is my PHP CODE to write to the Database <?php $con = mysql_connect("hostname" ,"mysqusername" ,"mysqlpassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("databasename", $con); $sql="INSERT INTO customer_services_tracker (customer_name ,customer_email_address ,case_number ,msisdn ,route_cause ,calltype_indexedto ,type_tat ,escalatedto ,requestedby ,province ,comments ) VALUES ('$_POST[customer_name]' ,'$_POST[customer_email_address]' ,'$_POST[case_number]' ,'$_POST[msisdn]' ,'$_POST[route_cause]' ,'$_POST[calltype_indexedto]' ,'$_POST[type_tat]' ,'$_POST[escalatedto]' ,'$_POST[requestedby]' ,'$_POST[province]' ,'$_POST[comments]')"; $CatName = $rowCat["Name"]; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ?>

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  • Set scaleX property on a Sprite without altering the child inside

    - by grammar
    Is this possible? My site is set up with next and prev buttons on the right and left sides respectively, and as you roll over either of the hit areas around the buttons a Sprite fades in which contains a TextField that describes the next page. Said Sprite calls the StartDrag() method, so it follows the mouse within the bounds, which is all fine and dandy on the left side of the page. Adobe, however, seems to have forgotten to put a way to dynamically alter the registration point of a Sprite, MC, whatever else, so when you roll over the right side of the page, the sprite is displayed from the top left and is mostly off the stage. Trying to hack this problem I have tried numerous things ( classes written by others, other hacks) and the best that I have found is to use the scaleX method on the Sprite, changing the scale to -1. This, of course, makes the Sprite seem like it's reflected from its normal point, which means all its children show up backwards. Is there anyway I can use this hack without it altering the text? OR Does anyone know a different way to go about displaying a Sprite from another corner? Any way to make a Sprite fade in and follow the mouse on the LEFT HAND side of the mouse pointer? Thank you very much in advance. Here is a snippet to give an idea of what's happening: naxtPage.labelBG.scaleX = -1; nextPage.labelBG.startDrag( true, nextHitRect ); nextPage.labelBG.x = nextPage.labelBG.parent.mouseX; nextPage.labelBG.y = nextPage.labelBG.parent.mouseY; Cheers

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  • Image appearing in the wrong place.

    - by Luke
    I have a list that I want to precede on each line with a small image. The CSS: .left div.arrow{background-image: url(../images/design/box.png); float:left; height:15px; width:15px; margin-right:2px;} .left a.list:link, a:visited, a:active {color:black; font-size:0.8em; text-decoration:none; display:block; float:left;} The HTML: <div class="panel">My quick links</div> <div class="arrow"></div> <a href="/messages.php?p=new" class="list">Send a new message</a> <br /> <div class="arrow"></div> <a href="/settings.php#password" class="list">Change my password</a> <br /> <div class="arrow"></div> <a href="/settings.php#picture" class="list">Upload a new site image</a> <br /> As you can see, each image should go before the writing. On the first line, the text "Send a new message" has the preceeding image. However, each line afterwards has the image at the end. So "Send a new message" has an image at the start and finish. It is like the images are staying at the end of the previous line. Any ideas?

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