Search Results

Search found 11227 results on 450 pages for 'login attempts'.

Page 65/450 | < Previous Page | 61 62 63 64 65 66 67 68 69 70 71 72  | Next Page >

  • how to login to criaglist through c#

    - by kosikiza
    i m using the following code to login to criaglist, but hav't successsed yet. string formParams = string.Format("inputEmailHandle={0}&inputPassword={1}", "[email protected]", "pakistan01"); //string postData = "[email protected]&inputPassword=pakistan01"; string uri = "https://accounts.craigslist.org/"; HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri); request.KeepAlive = true; request.ProtocolVersion = HttpVersion.Version10; request.Method = "POST"; byte[] postBytes = Encoding.ASCII.GetBytes(formParams); request.ContentType = "application/x-www-form-urlencoded"; request.ContentLength = postBytes.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(postBytes, 0, postBytes.Length); requestStream.Close(); HttpWebResponse response = (HttpWebResponse)request.GetResponse(); cookyHeader = response.Headers["Set-cookie"]; string pageSource; string getUrl = "https://post.craigslist.org/del"; WebRequest getRequest = WebRequest.Create(getUrl); getRequest.Headers.Add("Cookie", cookyHeader); WebResponse getResponse = getRequest.GetResponse(); using (StreamReader sr = new StreamReader(getResponse.GetResponseStream())) { pageSource = sr.ReadToEnd(); }

    Read the article

  • how can I know current viewcontroller name in iphone

    - by Shikhar
    I have BaseView which implement UIViewController. Every view in project must implement this BaseView. In BaseView, I have method: -(void) checkLoginStatus { defaults = [[NSUserDefaults alloc] init]; if(![[defaults objectForKey:@"USERID"] length] > 0 ) { Login *login=[[Login alloc] initWithNibName:@"Login" bundle:nil]; [self.navigationController pushViewController:login animated:TRUE]; [login release]; } [defaults release]; } The problem is my Login view also implement BaseView, checks for login, and again open LoginView i.e. stuck in to recursive calling. Can I check in checkLoginStatus method if request is from LoginView then take no action else check login. Ex: (void) checkLoginStatus { if(SubView is NOT Login){ defaults = [[NSUserDefaults alloc] init]; if(![[defaults objectForKey:@"USERID"] length] 0 ) { Login *login=[[Login alloc] initWithNibName:@"Login" bundle:nil]; [self.navigationController pushViewController:login animated:TRUE]; [login release]; } [defaults release]; } } Please help..

    Read the article

  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

    Read the article

  • redirecting _top page from asp:login control in iframe onloggedin

    - by jumpdart
    So yeah, Im building a little authenticated content(.NET app) to a large html site managed by another group. They are only comfortable with managing html so all my app content will be contained in iframes. Everything is working fine as far as navigation and calling services and whatnot but i cant bust out of the frame with my asp:login control. Im trying to register some JS on logged in but with no success. Thanks protected void login_LoggedIn(object sender, EventArgs e) { StringBuilder strScript = new StringBuilder(); strScript.Append("<script language='javascript'>"); string sHome = ConfigurationManager.AppSettings["AppHomePageURL"].ToString(); //strScript.AppendFormat("window.navigate('{0}');", sHome); //strScript.AppendFormat("parent.location.href='{0}';", sHome); //strScript.AppendFormat("window.open('{0}', '_top', '', false);", sHome); strScript.AppendFormat("top.location.href='{0}';", sHome); strScript.Append("WTF_let_me_outa_here();"); strScript.Append("</script>"); ClientScript.RegisterClientScriptBlock(typeof(Page), "LoginGO", strScript.ToString()); }

    Read the article

  • login using UITableView

    - by EquinoX
    How can I create a login for username/password just like in the skype application? I know it's a grouped table view.. but how can I do that? I searched the site and found the following code: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; UILabel *startDtLbl = [[UILabel alloc] initWithFrame:CGRectMake(10, 10, 80, 25)]; if (indexPath.row == 0) startDtLbl.text = @"Username"; else { startDtLbl.text = @"Password"; } startDtLbl.backgroundColor = [UIColor clearColor]; [cell.contentView addSubview:startDtLbl]; UITextField *passwordTF = [[UITextField alloc] initWithFrame:CGRectMake(100, 5, 200, 35)]; passwordTF.delegate = self; if (indexPath.row == 0) passwordTF.tag = 0; else { passwordTF.tag = 1; } [cell.contentView addSubview:passwordTF]; } return cell; } When I do: NSString * username = [((UITextField*)[self.view viewWithTag:0]) text]; NSString * password = [((UITextField*)[self.view viewWithTag:1]) text]; it gives me this error: Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIView text]: unrecognized selector sent to instance 0x6c3c600 Why is this?

    Read the article

  • Python - retrieving info from a syslog file

    - by Johnny
    Ive been asked to do a program using python for an assignment. Ive been given a syslog file and I have to find things out about it How do I find out how many attempts were made to login to the root account? Any advice would be highly appreciated as Im very new to python an completely lost!

    Read the article

  • Login function runs different between local and server

    - by quangnd
    Here is my check login function: protected bool checkLoginStatus(String email, String password) { bool loginStatus = false; bool status = false; try { Connector.openConn(); String str = "SELECT * FROM [User]"; SqlCommand cmd = new SqlCommand(str, Connector.conn); SqlDataAdapter da = new SqlDataAdapter(cmd); DataSet ds = new DataSet(); da.Fill(ds, "tblUser"); //check valid foreach (DataRow dr in ds.Tables[0].Rows) { if (email == dr["Email"].ToString() && password == Connector.base64Decode(dr["Password"].ToString())) { Session["login_status"] = true; Session["username"] = dr["Name"].ToString(); Session["userId"] = dr["UserId"].ToString(); status = true; break; } } } catch (Exception ex) { } finally { Connector.closeConn(); } return status; } And call it at my aspx page: String email = Login1.UserName.Trim(); String password = Login1.Password.Trim(); if (checkLoginStatus(email, password)) Response.Redirect(homeSite); else lblFailure.Text = "Invalid!"; I ran this page at localhost successful! When I published it to server, this function only can run if email and password correct! Other, error occured: A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: SQL Network Interfaces, error: 26 - Error Locating Server/Instance Specified) I tried open SQL Server 2008 Configuration Manager and enable SQL Server Browser service (Logon as:NT Authority/Local Service) but it stills error. (note: here is connection string of openConn() at Localhost (run on SQLEXpress 2005) connectionString="Data Source=MYLAPTOP\SQLEXPRESS;Initial Catalog=Spider_Vcms;Integrated Security=True" /> ) At server (run on SQL Server Enterprise 2008) connectionString="Data Source=SVR;Initial Catalog=Spider_Vcms;User Id=abc;password=123456;" /> anyone have an answer for my problem :( thanks a lot!

    Read the article

  • storing user info/pass in web.config authentication

    - by Tomaszewski
    Hello, I am trying to write a simple internal app with some simple authentication. I'm also trying to make this quick and learn about the forms authentication via web.config. So i have my authentication working if I hard code my 'user name' and 'password' into C# code and do a simple conditional. However, I'm having a tough time storing the a user/pass to be checked against in the web.config file. The MSDN manual says to put this into the web.config: <authentication mode="Forms"> <forms loginUrl="login.aspx"> <credentials passwordFormat="SHA1"> <user name="user1" password="27CE4CA7FBF00685AF2F617E3F5BBCAFF7B7403C" /> <user name="user2" password="D108F80936F78DFDD333141EBC985B0233A30C7A" /> <user name="user3" password="7BDB09781A3F23885CD43177C0508B375CB1B7E9"/> </credentials> </forms> </authentication> However, the minute I add 'credentials' into the 'authentication' section, I get this error: Server Error in '/' Application. Configuration Error Description: An error occurred during the processing of a configuration file required to service this request. Please review the specific error details below and modify your configuration file appropriately. Parser Error Message: Unrecognized element 'credentials'. Source Error: Line 44: <authentication mode="Forms"> Line 45: <forms loginUrl="login.aspx" /> Line 46: <credentials> Line 47: Line 48: </credentials> Source File: C:\inetpub\wwwroot\asp\projects\passwordCatalog\passwordCatalog\web.config Line: 46 So my question is, how and where would I add the following in the web.config file? <credentials passwordFormat="SHA1"> <user name="johndoe" password="mypass123" /> </credentials>

    Read the article

  • SHA function issues

    - by Damian James
    I have this php code from my login.php if (isset($_POST['logIn'])) { $errmsg = ""; $logname = mysqli_real_escape_string($dbc, trim($_POST['usernameIn'])); $logpassword = mysqli_real_escape_string($dbc, trim($_POST['passwordIn'])); $query = "SELECT user_id, username FROM members WHERE username = '$logname' AND password = SHA('$logpassword')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { $row = mysqli_fetch_array($data); setcookie('user_id', $row['user_id'], time() + (60 * 60 * 24 * 30)); //expires after 30 days setcookie('username', $row['username'], time() + (60 * 60 * 24 * 30)); $home = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index.php'; header('Location: ' . $home); } else { $errmsg = '<p class="errormsg">Username or password is incorrect.</p>'; } } And for some reason, it always ends up setting $errmsg in the else statement. I am sure that I'm entering information (username,password) that is correct and exists in the database. I insert my values (from a signup script) using this query: $query = "INSERT INTO members (username, password, email) VALUES ('$username', SHA('$password'), '$email')"; Anyone see the problem with this script? Thanks!

    Read the article

  • How does browser know when to prompt user to save password?

    - by Eric
    This is related to the question I asked here: http://stackoverflow.com/questions/2382329/how-can-i-get-browser-to-prompt-to-save-password This is the problem: I CAN'T get my browser to prompt me to save the password for the site I'm developing. (I'm talking about the bar that appears sometimes when you submit a form on Firefox, that says "Remember the password for yoursite.com? Yes / Not now / Never") This is super frustrating because this feature of Firefox (and most other modern browsers, which I hope work in a similar fashion) seems to be a mystery. It's like a magic trick the browser does, where it looks at your code, or what you submit, or something, and if it "looks" like a login form with a username (or email address) field and a password field, it offers to save. Except in this case, where it's not offering my users that option after they use my login form, and it's making me nuts. :-) (I checked my Firefox settings-- I have NOT told the browser "never" for this site. It should be prompting.) My question: exactly what the heuristics are that Firefox (or any other modern browser) uses to know when it should prompt the user to save? This shouldn't be too difficult to answer, since it's right there in the Mozilla source (I don't know where to look or else I'd try to dig it out myself). You'd think there would be a blog post or some other similar developer note from the Mozilla developers about this but I can't find that either. (* Note that if your answer to me has anything to do with cookies, encryption or anything else that is about how I'm storing the user's passwords in the database, you've probably misread my question. :-)

    Read the article

  • PHP mySQL Error

    - by happyCoding25
    Hello, Im new to php so I decided to follow this tutorial for a simple login screen. I got the code setup but when I try login I get this error: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in (a long file path to the script) on line 27 The code I got from the tutorial is: <?php ob_start(); $host="thehost"; // Host name $username="myusername"; // Mysql username $password="mypass"; // Mysql password $db_name="test"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Define $myusername and $mypassword $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; // To protect MySQL injection (more detail about MySQL injection) $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $myusername and $mypassword, table row must be 1 row if($count==1){ // Register $myusername, $mypassword and redirect to file "login_success.php" session_register("myusername"); session_register("mypassword"); header("location:login_success.php"); } else { echo "Wrong Username or Password"; } ob_end_flush(); ?> (Note: All of the mySQL database info is filled in on my version) Aslo, the author gives a php5 version and a normal php version. I have tried both and gotten the same error. If anyone knows why this is happening help is really appreciated.

    Read the article

  • Sending basic authentication information via form

    - by VolatileStorm
    I am working on a site that currently uses a basic authentication dialog box login system, that is the type of dialog that you get if you go here: http://www.dur.ac.uk/vm.boatclub/password/index.php I did not set this system up and am not in a position to easily/quickly work around it, but it DOES work. The issue however is that the dialog box is not very helpful in telling you what login information you have to use (that is which username and password combination), and so I would like to replace it with a form. I had been thinking that this wasn't possible but I wanted to ask in order to find out. Is it possible to set up an HTML form that sends the data to the server such that it accepts it in the same way that it would using this dialog box? Alternatively is it possible to set up a PHP script that would take normal form data and process it somehow passing it to the server such that it logs in? Edit: After being told that this is basic authentication I went around and have managed to find a way that works and keeps the user persistently logged in. However, this does not work in internet explorer. The solution was simply to redirect the user to: http://username:[email protected]/vm.boatclub/password/index.php But Internet Explorer removed it due to phishing uses about 3 years ago. Is there a way to use javascript to get the browser to access the site in this way? Or will I have to simply change my UI?

    Read the article

  • How to use sessions in PDO?

    - by Byakugan
    I am still redoing and getting rid of old mysql_* commands in my code. I tried to transfer my session login form old code and this is what I got so far: public function login($user, $password) { if (!empty($user) && !empty($password)) { $password = $web->doHash($user, $password); // in this function is (return sha1(strtoupper($user).':'.strtoupper($password)) $stmt = $db_login->prepare("SELECT * FROM account WHERE username=:user AND pass_hash=:password"); $stmt->bindValue(':user', $user, PDO::PARAM_STR); $stmt->bindValue(':password', $password, PDO::PARAM_STR); $stmt->execute(); $rows = $stmt->rowCount(); if ($rows > 0) { $results_login = $stmt->fetch(PDO::FETCH_ASSOC); $_SESSION['user_name'] = $results_login['username']; $_SESSION['user_id'] = $results_login['id']; return true; } else { return false; } } else { return false; } } After that I am using checks if user logged on site: public function isLogged() { return (!empty($_SESSION['user_id']) && !empty($_SESSION['user_name'])); } But it seems - this function returns always empty because $_SESSION does not exists in PDO? And of course logout is used in this form on my sites: public function logout() { unset($_SESSION['user_id']); unset($_SESSION['user_name']); } But I think PDO has different way of handling session? I did not find any so what is it can i somehow add $_SESSION in PDO withou changing code much? I am using variables $_SESSION['user_name'] and $_SESSION['user_id'] in all over my web project. Summary: 1) How to use sessions in PDO correctly? 2) What is difference between using $stmt->fetch(PDO::FETCH_ASSOC); and $stmt->fetchAll(); Thank you.

    Read the article

  • How to control access to third party HTML pages

    - by Wylie
    Hello, We have a Learning Management System (LMS) that runs on its own server (IIS/Server 2003). Students must login with Forms authentication to gain access to the content. We want to offer access to third party flash and audio that is embedded in HTML pages hosted on the third party server (IIS/Server 2003). Currently we use a frame in a pop-up window that is populated via a simple URL to the third party HTML pages. How can the third party control access to their content, so that only students who launch the pop-up windows from our site can access their content? Since the content is mostly video and flash, we would prefer not to stream all of their content through our server to the Student. We have a programming staff, so we could maybe... - either post or get for our HTTP request to the third party server - we could use SSL - we could programmatically assign a global NT user account to all of our users and then do some kind of Active Directory login from the LMS server to the third party server - could the third party content be hosted at Amazon S3? Would this allow for secure access/download? These are just ideas. We really have no idea. Any suggestions would be greatly appreciated. TIA, Wylie

    Read the article

  • Codeigniter: validation problem

    - by krike
    For some reason a user can login with any password, first I thought I forgot to check for the password but I didn't... and I just cant find the problem here is the model: /*#######################################################*/ function validate() /*#######################################################*/ { $this->db->where('username', $this->input->post('username')); $this->db->where('password', md5($this->input->post('password'))); $q = $this->db->get('user_extra'); if($q->num_rows() == 1): return true; else: return false; endif; }//end of function validate() The controller /*#######################################################*/ function validate_credentials() /*#######################################################*/ { $this->load->model('membership_model'); $this->load->library('form_validation'); $this->form_validation->set_rules('username', 'Name', 'trim|required'); $this->form_validation->set_rules('password', 'password', 'trim|required'); if(!$this->membership_model->validate()): $this->form_validation->set_message('check_login', 'Login not correct, please try again.'); endif; if($this->form_validation->run() == FALSE): $this->index(); else: $this->membership_model->userinfo($this->input->post('username')); //should redirect to last view redirect($this->session->flashdata('redirect_url')); endif; }// end of validate_credentials()

    Read the article

  • Running a process at the Windows 7 Welcome Screen

    - by peelman
    So here's the scoop: I wrote a tiny C# app a while back that displays the hostname, ip address, imaged date, thaw status (we use DeepFreeze), current domain, and the current date/time, to display on the welcome screen of our Windows 7 lab machines. This was to replace our previous information block, which was set statically at startup and actually embedded text into the background, with something a little more dynamic and functional. The app uses a Timer to update the ip address, deepfreeze status, and clock every second, and it checks to see if a user has logged in and kills itself when it detects such a condition. If we just run it, via our startup script (set via group policy), it holds the script open and the machine never makes it to the login prompt. If we use something like the start or cmd commands to start it off under a separate shell/process, it runs until the startup script finishes, at which point Windows seems to clean up any and all child processes of the script. We're currently able to bypass that using psexec -s -d -i -x to fire it off, which lets it persist after the startup script is completed, but can be incredibly slow, adding anywhere between 5 seconds and over a minute to our startup time. We have experimented with using another C# app to start the process, via the Process class, using WMI Calls (Win32_Process and Win32_ProcessStartup) with various startup flags, etc, but all end with the same result of the script finishing and the info block process getting killed. I tinkered with rewriting the app as a service, but services were never designed to interact with the desktop, let alone the login window, and getting things operating in the right context never really seemed to work out. So for the question: Does anybody have a good way to accomplish this? Launch a task so that it would be independent of the startup script and run on top of the welcome screen?

    Read the article

  • Hundreds of unknown entries in Linux logwatch

    - by Saif Bechan
    I have a dedicated server which runs centos. Today i got an email from loginwatch on my server with hundreds of lines of 'errors'. I don't really know what they are becasue i am fairly new at this. The lines are in a few sections, I will display the first 10 of all of them, i hope someone can help me fix these problems. --------------------- Named Begin ------------------------ **Unmatched Entries** client 216.146.46.136 notify question section contains no SOA: 8 Time(s) client 92.114.98.10 query (cache) 'adobe.com/A/IN' denied: 4 Time(s) network unreachable resolving '11.254.75.75.in-addr.arpa/PTR/IN': 2001:7fd::1#53: 1 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:13c7:7002:3000::11#53: 1 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:500:13::c7d4:35#53: 1 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:500:2e::1#53: 2 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:610:240:0:53::193#53: 1 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:610:240:0:53::3#53: 1 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:660:3006:1::1:1#53: 1 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:6b0:7::2#53: 1 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:dc0:1:0:4777::140#53: 1 Time(s) network unreachable resolving '136.176.97.93.in-addr.arpa/PTR/IN': 2001:dc0:2001:a:4608::59#53: 1 Time(s) network unreachable resolving '146.250.19.67.in-addr.arpa/PTR/IN': 2001:5a0:10::2#53: 1 Time(s) network unreachable resolving '149.207.106.87.in-addr.arpa/PTR/IN': 2001:7fd::1#53: 1 Time(s) network unreachable resolving '178.62.24.195.in-addr.arpa/PTR/IN': 2001:7fd::1#53: 1 Time(s) this goes on for hundreds of lines with all different domain names. --------------------- pam_unix Begin ------------------------ Failed logins from: 78.86.126.211 (78-86-126-211.zone2.bethere.co.uk): 111 times 93.97.176.136 (93-97-176-136.dsl.cnl.uk.net): 113 times 121.14.145.32: 136 times 190.152.69.5: 248 times 209.160.72.15: 572 times 210.26.48.35: 2 times 212.235.111.224 (DSL212-235-111-224.bb.netvision.net.il): 140 times 218.206.25.29: 140 times Illegal users from: 78.86.126.211 (78-86-126-211.zone2.bethere.co.uk): 2665 times 93.97.176.136 (93-97-176-136.dsl.cnl.uk.net): 2539 times 121.14.145.32: 116 times 190.152.69.5: 34 times 209.160.72.15: 324 times 218.206.25.29: 8051 times proftpd: Unknown Entries: session opened for user cent_ftp by (uid=0): 15 Time(s) session closed for user cent_ftp: 14 Time(s) sshd: Authentication Failures: unknown (218.206.25.29): 8051 Time(s) unknown (78-86-126-211.zone2.bethere.co.uk): 2665 Time(s) unknown (93.97.176.136): 2539 Time(s) root (209.160.72.15): 558 Time(s) unknown (209.160.72.15): 324 Time(s) root (190.152.69.5): 246 Time(s) unknown (121.14.145.32): 116 Time(s) root (121.14.145.32): 106 Time(s) root (dsl212-235-111-224.bb.netvision.net.il): 70 Time(s) root (93.97.176.136): 44 Time(s) root (78-86-126-211.zone2.bethere.co.uk): 37 Time(s) unknown (190.152.69.5): 34 Time(s) mysql (121.14.145.32): 30 Time(s) nobody (218.206.25.29): 26 Time(s) mail (218.206.25.29): 24 Time(s) news (218.206.25.29): 24 Time(s) root (218.206.25.29): 24 Time(s) --------------------- SSHD Begin ------------------------ **Unmatched Entries** pam_succeed_if(sshd:auth): error retrieving information about user tavi : 2 time(s) pam_succeed_if(sshd:auth): error retrieving information about user pam : 2 time(s) pam_succeed_if(sshd:auth): error retrieving information about user konchog : 1 time(s) pam_succeed_if(sshd:auth): error retrieving information about user stavrum : 2 time(s) pam_succeed_if(sshd:auth): error retrieving information about user rachel : 1 time(s) pam_succeed_if(sshd:auth): error retrieving information about user affiliates : 24 time(s) pam_succeed_if(sshd:auth): error retrieving information about user nen : 1 time(s) pam_succeed_if(sshd:auth): error retrieving information about user cobra : 1 time(s) pam_succeed_if(sshd:auth): error retrieving information about user pass : 7 time(s) pam_succeed_if(sshd:auth): error retrieving information about user hacer : 1 time(s) pam_succeed_if(sshd:auth): error retrieving information about user chung : 1 time(s) pam_succeed_if(sshd:auth): error retrieving information about user zainee : 1 time(s) pam_succeed_if(sshd:auth): error retrieving information about user radu : 2 time(s) pam_succeed_if(sshd:auth): error retrieving information about user alka : 4 time(s) pam_succeed_if(sshd:auth): error retrieving information about user albert : 5 time(s) pam_succeed_if(sshd:auth): error retrieving information about user turcia : 2 time(s) pam_succeed_if(sshd:auth): error retrieving information about user cordell : 2 time(s) pam_succeed_if(sshd:auth): error retrieving information about user silver : 2 time(s) pam_succeed_if(sshd:auth): error retrieving information about user dragon : 3 time(s) If someone wants to see the whole log i can upload it somewhere. Am i being hacked, what is this all?? I hope someone can help me, this does not look good at all.

    Read the article

  • Remote Desktop to Server 2008R2 fails from one particular Win7 client

    - by Jesse McGrew
    I have a VPS running Windows Web Server 2008 R2. I'm able to connect using Remote Desktop from my home PC (Windows 7), personal laptop (Windows 7), and work laptop (Windows XP). However, I cannot connect from my work PC (Windows 7). I receive the error "The logon attempt failed" in the RDP client, and the server event log shows "An account failed to log on" with this explanation: Subject: Security ID: NULL SID Account Name: - Account Domain: - Logon ID: 0x0 Logon Type: 3 Account For Which Logon Failed: Security ID: NULL SID Account Name: username Account Domain: hostname Failure Information: Failure Reason: Unknown user name or bad password. Status: 0xc000006d Sub Status: 0xc0000064 Process Information: Caller Process ID: 0x0 Caller Process Name: - Network Information: Workstation Name: JESSE-PC Source Network Address: - Source Port: - Detailed Authentication Information: Logon Process: NtLmSsp Authentication Package: NTLM Transited Services: - Package Name (NTLM only): - Key Length: 0 I can connect from the offending work PC if I start up Windows XP Mode and use the RDP client inside that. The server is part of a domain but my account is local, so I'm logging in using a username of the form hostname\username. None of the clients are part of a domain. The server uses a self-signed certificate, and connecting from home I get a warning about that, but connecting from work I just get the logon error.

    Read the article

  • How to reduce timeout for bad password on disconnected laptop?

    - by Elroy Flynn
    I use a Windows 7 laptop computer. When not attached to my AD domain, if I enter an incorrect password, I have to wait approximately a full minute before the failure response comes back. When attached to the domain, the response is instant. I think that what's happening is that is that when my entry fails against the cached pw, Windows tries to reach the domain controller and the timeout for that operation is about 60s. Is there a registry entry that controls the timeout? I'd love to reduce it.

    Read the article

  • Logging on as root without winbind timeouts

    - by Josh Kelley
    How can I set up my Linux box so that, if the Active Directory domain controller is down, I can still log in as root, without any timeouts or delays? Following the example of most of the documentation out there, I've listed pam_winbind.so before pam_unix.so in my /etc/pam.d configurations. I believe that this is the cause of the problem. I remember seeing alternate /etc/pam.d setups that change the order and maybe add either pam_localuser or pam_succeed_if (to see if the uid is less than 500), but I can't find any specifics now (and I'm not enough of an expert in PAM to quickly and easily come up with a robust configuration on my own). What is the recommended setup for PAM with Winbind to avoid timeouts and delays if Active Directory is unavailable?

    Read the article

  • "Breadcrumbs" for series of hostnames?

    - by Hamy
    Does anyone know of a shell that would show a series of breadcrumbs as I navigate into/out of various servers, like this: Home > Build Machine > Vagrant > Docker-base Hopefully it could auto-detect logging in and out of various boxes and display the hostnames. Perhaps with a simple "no circular links", one could just try and monitor the hostname, but I don't know if there is a shell that can easily act as a 'parent' to the other shells on these various systems so that it can query hostname and/or other item. Any thoughts?

    Read the article

  • Change DPI setting in Windows 8.1 for the Logon Screen

    - by jmc302005
    How can the DPI setting be changed for the Logon Screen in Windows 8.1? Microsoft has added per-user DPI settings. But this means that there is no adjustable DPI setting for the Lock/Logon screen. You can change the DPI setting to be the same across all displays and this does affect the icons and font on the lock/logon screen. However, it does not affect any app/program that can run on the lock/logon screen. Ex. I use a 44" flat screen TV for my monitor on my desktop. Big enough for me to sit in my recliner and use my computer. I use the on-screen keyboard most of the time. (I don't want to keep a keyboard next to me.) The problem is that with the new DPI setup the on-screen keyboard takes up nearly half the screen, which is too big. I tried looking through the registry to see if I could find a setting for it. In the key HKEY_USERS\.DEFAULT\Control Panel\Desktop there is a string value named LogicalDPIOverride with a value of -1. I have a feeling this is where I can fix the issue. I tried changing the value to 0 and to 1 with no change in the result. Instead I noticed that after logging out and back in the -1 value was back in the registry. How can I change this default DPI? Can I use the LogPixels string that worked for DPI in Windows 7? Here are two Screen shots, one of the Lock Screen and one of the Logon Screen:

    Read the article

  • Cannot connect to server via SSH

    - by Rayne
    I'm running RHEL 6.0, and I accidentally moved the /bin, /boot, /cgroup, console.txt, /data, /dev, /etc to another folder. I think I managed to move these folders back, but now I'm having trouble connecting to the server using SSH, but am able to access the server via VNC. When I tried to connect to the server using a terminal from another server, I get the error ssh_exchange_identification: Connection closed by remote host I'm currently still connected via SSH to the server (haven't closed the window yet), and am still able to access it normally. But if I try to open a new SSH terminal from my current session, I see /bin/bash: Permission denied If I try to open a new SSH File Transfer window from my current session, I get the error File transfer server could not be started or it exited unexpectedly. Exit value 0 was returned. Most likely the sftp-server is not in the path of the user on the server-side I checked and I have Subsystem sftp /usr/libexec/openssh/sftp-server which is the same path as the output of locate sftp-server Also, when I tried to restart sshd, I get the error Couldn't open /dev/null: Permission denied But my /dev/null has the permissions crw-rw-rw- for root,root. How can I resolve this? ETA: Thanks for all your help! I was able to start ssh by running the application directly /usr/sbin/sshd Even though the status of the openssh-daemon is still "stopped".

    Read the article

< Previous Page | 61 62 63 64 65 66 67 68 69 70 71 72  | Next Page >