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  • Likewise: joined Active Directory but cannot write shares.

    - by Aron Rotteveel
    I have never used a Linux system in an AD environment before and am trying to join my laptop running Ubuntu to join our Active Directory (DC is a Windows Server 2008 machine) using Likewise-open. Using the GUI wizard, I have joined the domain. I can mount network shares using CIFS Problem: I only have read access to our fileserver. What more is needed to get the AD to recognize me as a user who has the appropriate rights? Any help is appreciated.

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  • Google.org Crisis Response and the Google Maps APIs

    Google.org Crisis Response and the Google Maps APIs This week, Pete Giencke and Ka-Ping Yee of the Google Crisis Response Team join Paul Saxman to talk about the technologies and data they use for their mapping efforts, such as the Crisis Map and Google Public Alerts. Join us to learn how to use the Google Maps APIs to track hurricanes, monitor floods, and help affected users locate critical information such as shelters and evacuation routes in the aftermath of a disaster. From: GoogleDevelopers Views: 0 0 ratings Time: 00:00 More in Science & Technology

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  • Free Virtual Developer Day: Oracle Fusion Development on July, 10th

    - by Lionel Dubreuil
    Simpler Java Development with Oracle ADF and Fusion Middleware. Join a free online developer day where you can learn about the various components that make up the Oracle Fusion Middleware development platform including Oracle WebCenter, Business Intelligence, BPM and more! Online seminars, hands-on lab and live chats with our technical staff is available directly from your computer.  Register now and join us on July 10th: https://oracle.6connex.com/portal/fusiondev/login?langR=en_US

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  • Free Virtual Developer Day: Oracle Fusion Development on July, 10th

    - by Lionel Dubreuil
    Simpler Java Development with Oracle ADF and Fusion Middleware. Join a free online developer day where you can learn about the various components that make up the Oracle Fusion Middleware development platform including Oracle WebCenter, Business Intelligence, BPM and more! Online seminars, hands-on lab and live chats with our technical staff is available directly from your computer.  Register now and join us on July 10th: https://oracle.6connex.com/portal/fusiondev/login?langR=en_US

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  • Happy Birthday, SQLPeople!

    - by andyleonard
    One year ago today, I began sending out batches of SQLPeople interview emails to friends in the SQL Server Community. Since then, Brian Moran ( Blog | @briancmoran ) and Matt Velic ( Blog | @mvelic | SQLPeople ) have joined the effort, we have published dozens of interviews, and there have been two events! You can join in the fun. If you haven’t already, visit the interview page and answer the seven questions. You can also join us on LinkedIn and Facebook . And you can follow us on Twitter ( @SQLPeople...(read more)

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  • Free Webinar - Using Enterprise Data Integration Dashboards

    - by andyleonard
    Join Kent Bradshaw and me as we present Using Enterprise Data Integration Dashboards Tuesday 11 Dec 2012 at 10:00 AM ET! If data is the life of the modern organization, data integration is the heart of an enterprise. Data circulation is vital. Data integration dashboards provide enterprise ETL (Extract, Transform, and Load) teams near-real-time status supported with historical performance analysis. Join Linchpins Kent Bradshaw and Andy Leonard as they demonstrate and discuss the benefits of data...(read more)

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  • Stairway to T-SQL DML Level 5: The Mathematics of SQL: Part 2

    Joining tables is a crucial concept to understanding data relationships in a relational database. When you are working with your SQL Server data, you will often need to join tables to produce the results your application requires. Having a good understanding of set theory, and the mathematical operators available and how they are used to join tables will make it easier for you to retrieve the data you need from SQL Server.

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  • Spring SQL Connections 2011 and SQLServerCentral.

    Once again SQLServerCentral is sponsoring a track at SQL Connections in Orlando this March. Read about the event and our speakers and join us for SQL Server training in Florida. Join SQL Backup’s 35,000+ customers to compress and strengthen your backups "SQL Backup will be a REAL boost to any DBA lucky enough to use it." Jonathan Allen. Download a free trial now.

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  • Design pattern for isomorphic trees

    - by Peregring-lk
    I want to create a data structure to work with isomorphic tree. I don't search for a "algorithms" or methods to check if two or more trees are isomorphic each other. Just to create various trees with the same structure. Example: 2 - - - - - - - 'a' - - - - - - - 3.5 / \ / \ / \ 3 3 'f' 'y' 1.0 3.1 / \ / \ / \ 4 7 'e' 'f' 2.3 7.7 The first "layer" or tree is the "natural tree" (a tree with natural numbers), the second layer is the "character tree" and the third one is the "float tree". The data structure has a method or iterator to traverse the tree and to make diferent operations with its values. These operations could change the value of nodes, but never its structure (first I create the structure and then I configure the tree with its diferent layers). In case of that I add a new node, this would be applied to each layer. Which known design pattern fits with this description or is related with it?

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  • CodePlex Daily Summary for Sunday, August 26, 2012

    CodePlex Daily Summary for Sunday, August 26, 2012Popular ReleasesPhysics Helper XAML: Physics Helper XAML 1.1.0.0: This release supports creation of 2D Physics apps for Windows 8 RTM, Windows Phone 7.1 development, and Silverlight 5. It includes source code and samples in three separate solutions.TouchInjector: TouchInjector 1.0: Version 1.0BlackJumboDog: Ver5.7.1: 2012.08.25 Ver5.7.1 (1)?????·?????LING?????????????? (2)SMTP???(????)????、?????\?????????????????????Peulot Heshbon: Peulot Heshbon version 3.0.0: Available quizzes:Plus for Natural, Real and fragments Minus for Natural, Real and fragments Multiplication for Natural, Real and fragments Divide for Natural, Real and fragments Random for Natural, Real and fragments Compare 2 percentages Compare 2 fragments (Just for easy difficulty) Check if a number can be divided with another number exactly. Available Languages:Hebrew English Russian What's NewAdded new quiz: Compare 2 fragments. It is available only if you are in Eas...Visual Studio Team Foundation Server Branching and Merging Guide: v2 - Visual Studio 2012: Welcome to the Branching and Merging Guide Quality-Bar Details Documentation has been reviewed by Visual Studio ALM Rangers Documentation has been through an independent technical review Documentation has been reviewed by the quality and recording team All critical bugs have been resolved Known Issues / Bugs Spelling, grammar and content revisions are in progress. Hotfix will be published.Microsoft Ajax Minifier: Microsoft Ajax Minifier 4.62: Fix for issue #18525 - escaped characters in CSS identifiers get double-escaped if the character immediately after the backslash is not normally allowed in an identifier. fixed symbol problem with nuget package. 4.62 should have nuget symbols available again.nopCommerce. Open source shopping cart (ASP.NET MVC): nopcommerce 2.65: As some of you may know we were planning to release version 2.70 much later (the end of September). But today we have to release this intermediate version (2.65). It fixes a critical issue caused by a third-party assembly when running nopCommerce on a server with .NET 4.5 installed. No major features have been introduced with this release as our development efforts were focused on further enhancements and fixing bugs. To see the full list of fixes and changes please visit the release notes p...MyRouter (Virtual WiFi Router): MyRouter 1.2.9: . Fix: Some missing changes for fixing the window subclassing crash. · Fix: fixed bug when Run MyRouter at the first Time. · Fix: Log File · Fix: improve performance speed application · fix: solve some Exception.eel Browser: eel 1.1.0.41 beta: Improved UI New features Bug fixesDynamics CRM 2011 Dummy Entity: First Release: This has been tested on CRM 2011 RU8 On-Premise IFD. Known Issue: The Test Dummy CRM page load event may throw an exception loading the first time as the iframe may not have finished loading. I have not been able to get the iframe OnReadyStateChange event to fire. But it is only a sample anyway. The zip file contains: Dummy Entity Visual studio solution. Test Dummy Visual Studio solution. Dummy Entity CRM Solution Test Dummy CRM Solution Installation: Unzip and import the CRM Solutions...Private cloud DMS: Essential server-client full package: Requirements: - SQL server >= 2008 (minimal Express - for Essential recommended) - .NET 4.0 (Server) - .NET 4.0 Client profile (Client) This version allow: - full file system functionality Restrictions: - Maximum 2 parallel users - No share spaces - No hosted business groups - No digital sign functionality - No ActiveDirectory connector - No Performance cache - No workflow - No messagingJavaScript Prototype Extensions: Release 1.1.0.0: Release 1.1.0.0 Add prototype extension for object. Add prototype extension for array.Glyphx: Version 1.2: This release includes the SdlDotNet.dll dependency in the setup, which you will need.TFS Project Test Migrator: TestPlanMigration v1.0.0: Release 1.0.0 This first version do not create the test cases in the target project because the goal was to restore a Test Plan + Test Suite hierarchy after a manual user deletion without restoring all the Project Collection Database. As I discovered, deleting a Test Plan will do the following : - Delete all TestSuiteEntry (the link between a Test Suite node and a Test Case) - Delete all TestSuite (the nodes in the test hierarchy), including root TestSuite - Delete the TestPlan Test c...ERPStore eCommerce FrontOffice: ERPStore.Core V4.0.0.2 MVC4 RTM: ERPStore.Core V4.0.0.2 MVC4 RTM (Code Source)ZXing.Net: ZXing.Net 0.8.0.0: sync with rev. 2393 of the java version improved API, direct support for multiple barcode decoding, wrapper for barcode generating many other improvements and fixes encoder and decoder command line clients demo client for emguCV dev documentation startedScintillaNET: ScintillaNET 2.5.1: This release has been built from the 2.5 branch. Issues closed: Issue # Title 32524 32524 32550 32550 32552 32552 25148 25148 32449 32449 32551 32551 32711 32711 MFCMAPI: August 2012 Release: Build: 15.0.0.1035 Full release notes at SGriffin's blog. If you just want to run the MFCMAPI or MrMAPI, get the executables. If you want to debug them, get the symbol files and the source. The 64 bit builds will only work on a machine with Outlook 2010 64 bit installed. All other machines should use the 32 bit builds, regardless of the operating system. Facebook BadgeDocument.Editor: 2013.2: Whats new for Document.Editor 2013.2: New save as Html document Improved Traslate support Minor Bug Fix's, improvements and speed upsPulse: Pulse Beta 5: Whats new in this release? Well to start with we now have Wallbase.cc Authentication! so you can access favorites or NSFW. This version requires .NET 4.0, you probably already have it, but if you don't it's a free and easy download from Microsoft. Pulse can bet set to start on Windows startup now too. The Wallpaper setter has settings now, so you can change the background color of the desktop and the Picture Position (Tile/Center/Fill/etc...) I've switched to Windows Forms instead of WPF...New Projects508 Compliance Validator: This tool checks aspx and ascx pages against 508 Accessibilty guidelines and also allows you to add your own rules.BF for WP: BF for WP is a visual Brainfuck interpter for Windows Phone.Climate Control: App lets you vote on whether you're too hot or too cold so the dummy next to the air con controls can adjust the thermostat.Custom Captcha Plugin for Kooboo CMS for adding content or sending feedback: Custom Captcha Plugin for Kooboo CMS for adding content or sending feedbackGalleryDownloader: This project takes aim on downloading free photogalleries through the Internet. Highly Maintainable Web Services: The Highly Maintainable Web Services project is a reference architecture application for .NET that demonstrates how to build highly maintainable web services.Its.Validation: A C# DSL for writing rules in a composable, functional style.Kaku by wifi: The projects purpose: Make your phone a part of your house hold by being able to control certail elektric devices with your phone such as, light, electric curtaLogin with Google in ASP.Net MVC3 & Get data from Google User: ASP.Net developer can use this code: asp.net mvc3 web project which contains login with google and pull data from user's google accountMabiCommerce: MabiCommerce is an advanced Commerce Calculator for the MMORPG Mabinogi.Mapture the FLAG: A location based game for wp7mn: sumSharePoint 2010: SharePoint 2010 utilitiesSHIORI.NET: ???SHIORI????????????????????Temp and Stress: Tieni sotto controllo le temperature della tua CPU e effettua Stress Test e Benchmark!VisiblityControl – An Alternative to Converters: A templated content control hosting to remove the pain of using the BooleanToVisibilityConverter. The property IsTrue determines what is shown.Whatsnexx Integration for Orchard CMS: Orchard Whatsnexx makes it easier for Orchard users to send an event to the Whatsnexx Ticket Bus service API, of the Whatsnexx GatewayWINRT \ Metro Store \ open marketing solution: This project is aimed at creating a public shopping cart, that is available to all windows 8 users free. products are screened added by administrators

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  • xor of sequence of numbers

    - by ArG0NaUt
    You are given with a sequence of natural numbers, you can add any natural number to any number in the sequence such that their xor becomes zero. Your goal is to minimize the sum of added numbers. e.g. Consider the following examples : sequence : 1, 3 answer : 2, adding 2 to 1 we get 3^3=0. sequence : 10, 4, 5, 1 answer: 6, adding 3 to 10 & 3 to 8 we get 13^4^8^1 = 0. sequence : 4, 4 answer : 0, since 4^4 = 0. I tried working on binary representations of sequence number but it got so complex. I want to know if there is any simple and efficient way to solve this problem.

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  • SSIS is Case-Sensitive

    - by andyleonard
    Introduction SSIS is case-sensitive even if the database is case-insensitive. Imagine... ... you work in an ETL shop where someone who believes in natural keys won the Battle of the Joins. Imagine one of your natural keys is a string. (I know it's a stretch... play along!). Let's build some tables to sketch it out. If you do not have a TestDB database, why not? Build one! You'll use it often. Use TestDB go Create Table SSIS1 ( StrID char ( 5 ) , Name varchar ( 15 ) , Value int ) Insert Into SSIS1...(read more)

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  • problem with sIFR 3 not displaying in IE just getting XXX

    - by user288306
    I am having a problem with sIFR 3 not displaying in IE. I get 3 larges black XXX in IE yet it displays fine in Firefox. I have checked i do have the most recent version of flash installed correctly. Here is the code on the page <div id="features"> <div id="mainmessage_advertisers"><h2>Advertisers</h2><br /><br /><h3><a href="">Reach your customers where they browse. Buy directly from top web publishers.</a></h3><br /><br /><br /><a href=""><img src="img/buyads.gif" border="0"></a></div> <div id="mainmessage_publishers"><h2>Publishers</h2><br /><br /><h3>Take control of your ad space and start generating more revenue than <u>ever before</u>.</h3><br /><br /><br /><a href=""><img src="img/sellads.gif" border="0"></a></div> </div>` Here is the code from my global.css #mainmessage_advertisers { width: 395px; height: 200px; padding: 90px 50px; border: 1px; float: left; } #mainmessage_publishers { width: 395px; height: 200px; padding: 90px 50px; float: right; } and here is what i have in my sifr.js /*********************************************************************** SIFR 3.0 (BETA 1) FUNCTIONS ************************************************************************/ var parseSelector=(function(){var _1=/\s*,\s*/;var _2=/\s*([\s>+~(),]|^|$)\s*/g;var _3=/([\s>+~,]|[^(]\+|^)([#.:@])/g;var _4=/^[^\s>+~]/;var _5=/[\s#.:>+~()@]|[^\s#.:>+~()@]+/g;function parseSelector(_6,_7){_7=_7||document.documentElement;var _8=_6.split(_1),_9=[];for(var i=0;i<_8.length;i++){var _b=[_7],_c=toStream(_8[i]);for(var j=0;j<_c.length;){var _e=_c[j++],_f=_c[j++],_10="";if(_c[j]=="("){while(_c[j++]!=")"&&j<_c.length){_10+=_c[j]}_10=_10.slice(0,-1)}_b=select(_b,_e,_f,_10)}_9=_9.concat(_b)}return _9}function toStream(_11){var _12=_11.replace(_2,"$1").replace(_3,"$1*$2");if(_4.test(_12)){_12=" "+_12}return _12.match(_5)||[]}function select(_13,_14,_15,_16){return (_17[_14])?_17[_14](_13,_15,_16):[]}var _18={toArray:function(_19){var a=[];for(var i=0;i<_19.length;i++){a.push(_19[i])}return a}};var dom={isTag:function(_1d,tag){return (tag=="*")||(tag.toLowerCase()==_1d.nodeName.toLowerCase())},previousSiblingElement:function(_1f){do{_1f=_1f.previousSibling}while(_1f&&_1f.nodeType!=1);return _1f},nextSiblingElement:function(_20){do{_20=_20.nextSibling}while(_20&&_20.nodeType!=1);return _20},hasClass:function(_21,_22){return 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  • Create SAMBA node trust relationship to Windows 2003 PDC server

    - by Rod Regier
    I am having problems creating a trust relationship between an OpenVMS/IA64 node running V/IA64 8.3-1H1, TCPIP 5.6 ECO 5, CIFS 1.1 ECO1 PS11 (SAMBA 3.0.28a) and Windows 2003 server running as a PDC. I do have two other OpenVMS/Alpha nodes running V/A 8.3, TCPIP 5.6 ECO 4, CIS 1.1 ECO1 PS10 (SAMBA 3.0.28a) with working trust relationships to the same Windows 2003 server. Looking for assistance in resolving the trust "handshake". \\ Details from failing node. Unless otherwise noted, corresponding files on working nodes are similar or identical. SMB.CONF extract: [global] server string = Samba %v running on %h (OpenVMS) workgroup = WILMA netbios name = %h security = DOMAIN encrypt passwords = Yes name resolve order = lmhosts host wins bcast Password server = * log file = /samba$log/log.%m printcap name = /sys$manager/ucx$printcap.dat guest account = DYMAX print command = print %f/queue=%p/delete/passall/name="""""%s""""" lprm command = delete/entry=%j map archive = No printing = OpenVMS net rpc testjoin [2010/08/13 16:09:28, 0] SAMBA$SRC:[SOURCE.RPC_CLIENT]CLI_PIPE.C;1:(2443) get_schannel_session_key: could not fetch trust account password for domain 'WILMA' [2010/08/13 16:09:28, 0] SAMBA$SRC:[SOURCE.UTILS]NET_RPC_JOIN.C;1:(72) net_rpc_join_ok: failed to get schannel session key from server W2K3AD2 for domain WILMA. Error was NT_STATUS_CANT_ACCESS_DOMAIN_I NFO Join to domain 'WILMA' is not valid net rpc join "-Uaccount%password" tdb_open_isam: error verifying status of file SAMBA$ROOT:[PRIVATE]secrets.tdb tdb_open_isam: errno value = 1 [2010/08/13 16:21:13, 0] SAMBA$SRC:[SOURCE.PASSDB]SECRETS.C;1:(72) Failed to open /SAMBA$ROOT/PRIVATE/secrets.tdb [2010/08/13 16:21:13, 0] SAMBA$SRC:[SOURCE.UTILS]NET_RPC.C;1:(322) error storing domain sid for WILMA tdb_open_isam: error verifying status of file SAMBA$ROOT:[PRIVATE]secrets.tdb tdb_open_isam: errno value = 1 [2010/08/13 16:21:13, 0] SAMBA$SRC:[SOURCE.PASSDB]SECRETS.C;1:(72) Failed to open /SAMBA$ROOT/PRIVATE/secrets.tdb [2010/08/13 16:21:13, 0] SAMBA$SRC:[SOURCE.UTILS]NET_RPC_JOIN.C;1:(409) error storing domain sid for WILMA Unable to join domain WILMA. \\ Example from other node: net rpc testjoin Join to 'WILMA' is OK

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  • Slow INFORMATION_SCHEMA query

    - by Thomas
    We have a .NET Windows application that runs the following query on login to get some information about the database: SELECT t.TABLE_NAME, ISNULL(pk_ccu.COLUMN_NAME,'') PK, ISNULL(fk_ccu.COLUMN_NAME,'') FK FROM INFORMATION_SCHEMA.TABLES t LEFT JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS pk_tc ON pk_tc.TABLE_NAME = t.TABLE_NAME AND pk_tc.CONSTRAINT_TYPE = 'PRIMARY KEY' LEFT JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE pk_ccu ON pk_ccu.CONSTRAINT_NAME = pk_tc.CONSTRAINT_NAME LEFT JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS fk_tc ON fk_tc.TABLE_NAME = t.TABLE_NAME AND fk_tc.CONSTRAINT_TYPE = 'FOREIGN KEY' LEFT JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE fk_ccu ON fk_ccu.CONSTRAINT_NAME = fk_tc.CONSTRAINT_NAME Usually this runs in a couple seconds, but on one server running SQL Server 2000, it is taking over four minutes to run. I ran it with the execution plan enabled, and the results are huge, but this part caught my eye (it won't let me post an image): http://img35.imageshack.us/i/plank.png/ I then updated the statistics on all of the tables that were mentioned in the execution plan: update statistics sysobjects update statistics syscolumns update statistics systypes update statistics master..spt_values update statistics sysreferences But that didn't help. The index tuning wizard doesn't help either, because it doesn't let me select system tables. There is nothing else running on this server, so nothing else could be slowing it down. What else can I do to diagnose or fix the problem on that server?

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  • Domain joining debate for Outlook 2010 with Exchange 2007 on windows SBS 2008 for a user on a laptop that will travel a fair amount of the time.

    - by user71195
    I'm basically debating on whether or not to join the Domain on a Laptop, and was wondering if anyone has had a similar experience. If the computer were staying in the office, its a no brainer. Join the domain. In this case I have a user who will come into the office a few days a week, and work remotely the rest of the time. There is a working VPN using OpenVPN client/server, but it's not site-to-site. My knee jerk reaction is to not join the domain, so that the user can have 1 profile that they always use. In this configuration, should Outlook work properly with the user's domain account, and should the shared calendar still work (at least once inside the VPN)? My concern with joining the domain would be the inability to login to it when elsewhere. Is there maybe a way around this with caching or something? Would creating a second local login make sense for a user like this in any way? If so, why not just skip the domain join to begin with? Any thoughts on or experiences with this would be appreciated. Laptop OS Windows 7 (Not purchased yet.. pro if domain needed) Server SBS 2008, Exchange 2007 Outlook version 2010 Thanks for any help, Mike

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  • Nesting Linq-to-Objects query within Linq-to-Entities query –what is happening under the covers?

    - by carewithl
    var numbers = new int[] { 1, 2, 3, 4, 5 }; var contacts = from c in context.Contacts where c.ContactID == numbers.Max() | c.ContactID == numbers.FirstOrDefault() select c; foreach (var item in contacts) Console.WriteLine(item.ContactID); Linq-to-Entities query is first translated into Linq expression tree, which is then converted by Object Services into command tree. And if Linq-to-Entities query nests Linq-to-Objects query, then this nested query also gets translated into an expression tree. a) I assume none of the operators of the nested Linq-to-Objects query actually get executed, but instead data provider for particular DB (or perhaps Object Services) knows how to transform the logic of Linq-to-Objects operators into appropriate SQL statements? b) Data provider knows how to create equivalent SQL statements only for some of the Linq-to-Objects operators? c) Similarly, data provider knows how to create equivalent SQL statements only for some of the non-Linq methods in the Net Framework class library? EDIT: I know only some Sql so I can't be completely sure, but reading Sql query generated for the above code it seems data provider didn't actually execute numbers.Max method, but instead just somehow figured out that numbers.Max should return the maximum value and then proceed to include in generated Sql query a call to TSQL's build-in MAX function. It also put all the values held by numbers array into a Sql query. SELECT CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN '0X0X' ELSE '0X1X' END AS [C1], [Extent1].[ContactID] AS [ContactID], [Extent1].[FirstName] AS [FirstName], [Extent1].[LastName] AS [LastName], [Extent1].[Title] AS [Title], [Extent1].[AddDate] AS [AddDate], [Extent1].[ModifiedDate] AS [ModifiedDate], [Extent1].[RowVersion] AS [RowVersion], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[CustomerTypeID] END AS [C2], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[InitialDate] END AS [C3], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[PrimaryDesintation] END AS [C4], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[SecondaryDestination] END AS [C5], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[PrimaryActivity] END AS [C6], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[SecondaryActivity] END AS [C7], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[Notes] END AS [C8], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[RowVersion] END AS [C9], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[BirthDate] END AS [C10], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[HeightInches] END AS [C11], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[WeightPounds] END AS [C12], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[DietaryRestrictions] END AS [C13] FROM [dbo].[Contact] AS [Extent1] LEFT OUTER JOIN (SELECT [Extent2].[ContactID] AS [ContactID], [Extent2].[BirthDate] AS [BirthDate], [Extent2].[HeightInches] AS [HeightInches], [Extent2].[WeightPounds] AS [WeightPounds], [Extent2].[DietaryRestrictions] AS [DietaryRestrictions], [Extent3].[CustomerTypeID] AS [CustomerTypeID], [Extent3].[InitialDate] AS [InitialDate], [Extent3].[PrimaryDesintation] AS [PrimaryDesintation], [Extent3].[SecondaryDestination] AS [SecondaryDestination], [Extent3].[PrimaryActivity] AS [PrimaryActivity], [Extent3].[SecondaryActivity] AS [SecondaryActivity], [Extent3].[Notes] AS [Notes], [Extent3].[RowVersion] AS [RowVersion], cast(1 as bit) AS [C1] FROM [dbo].[ContactPersonalInfo] AS [Extent2] INNER JOIN [dbo].[Customers] AS [Extent3] ON [Extent2].[ContactID] = [Extent3].[ContactID]) AS [Project1] ON [Extent1].[ContactID] = [Project1].[ContactID] LEFT OUTER JOIN (SELECT TOP (1) [c].[C1] AS [C1] FROM (SELECT [UnionAll3].[C1] AS [C1] FROM (SELECT [UnionAll2].[C1] AS [C1] FROM (SELECT [UnionAll1].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable1] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable2]) AS [UnionAll1] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable3]) AS [UnionAll2] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable4]) AS [UnionAll3] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable5]) AS [c]) AS [Limit1] ON 1 = 1 LEFT OUTER JOIN (SELECT TOP (1) [c].[C1] AS [C1] FROM (SELECT [UnionAll7].[C1] AS [C1] FROM (SELECT [UnionAll6].[C1] AS [C1] FROM (SELECT [UnionAll5].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable6] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable7]) AS [UnionAll5] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable8]) AS [UnionAll6] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable9]) AS [UnionAll7] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable10]) AS [c]) AS [Limit2] ON 1 = 1 CROSS JOIN (SELECT MAX([UnionAll12].[C1]) AS [A1] FROM (SELECT [UnionAll11].[C1] AS [C1] FROM (SELECT [UnionAll10].[C1] AS [C1] FROM (SELECT [UnionAll9].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable11] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable12]) AS [UnionAll9] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable13]) AS [UnionAll10] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable14]) AS [UnionAll11] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable15]) AS [UnionAll12]) AS [GroupBy1] WHERE [Extent1].[ContactID] IN ([GroupBy1].[A1], (CASE WHEN ([Limit1].[C1] IS NULL) THEN 0 ELSE [Limit2].[C1] END)) Based on this, is it possible that Linq2Entities provider indeed doesn't execute non-Linq and Linq-to-Object methods, but instead creates equivalent SQL statements for some of them ( and for others it throws an exception )? Thank you in advance

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  • getelementbyid does not work in firefox

    - by gaurab
    hi, this below mentioned code works perfect in internet explorer but not in firefox... i get an error in line in firefox: document.getElementById("supplier_no").value= values_array[0]; that getElementById returns null. how to solve the problem? var winName; //variable for the popup window var g_return_destination = null ; //variable to track where the data gets sent back to. // Set the value in the original pages text box. function f_set_home_value( as_Value ) { if (document.getElementById(g_return_destination[0]).name == "netbank_supplier_name_info" ) { //clear the old values for (selnum = 1; selnum <= 5; selnum++) { document.getElementById("expense_account"+selnum).value = ""; document.getElementById("expense_account_name"+selnum).value = ""; document.getElementById("expense_vat_flag"+selnum).value = "off"; document.getElementById("expense_vat_flag"+selnum).checked = ""; document.getElementById("expense_vat_amount"+selnum).value = ""; document.getElementById("expense_vat_code"+selnum).value = ""; document.getElementById("expense_period"+selnum).value = ""; document.getElementById("expense_date"+selnum).value = ""; if (selnum!=1) {//these are sometimes defaulted in, and in any case you will always have line1 document.getElementById("expense_more_dept"+selnum).value = ""; document.getElementById("expense_more_prj"+selnum).value = ""; document.getElementById("expense_more_subj"+selnum).value = ""; } document.getElementById("expense_amount"+selnum).value = ""; } var values_array = as_Value[0].split("!"); document.getElementById("supplier_no").value= values_array[0]; document.getElementById("supplier_bankAccount_no").value= values_array[1]; str = values_array[2] ; str = str.split(";sp;").join(" "); document.getElementById("default_expense_account").value= str; document.getElementById("expense_account1").value= str; document.getElementById("expense_more_sok1").disabled= false; str = values_array[3] ; str = str.split(";sp;").join(" "); document.getElementById("payment_term").value= str; strPeriod = calcPeriod(str,document.getElementById("due_date").value); document.getElementById("expense_period1").value = (strPeriod); strExpenseDate = calcExpenseDate(str,document.getElementById("due_date").value); document.getElementById("expense_date1").value = (strExpenseDate); str = values_array[4] ; str = str.split(";sp;").join(" "); document.getElementById("expense_account_name1").value= str; str = values_array[5] ; str = str.split(";sp;").join(" "); document.getElementById("expense_vat_code1").value= str; if (str == 0) { document.getElementById("expense_vat_flag1").checked= ''; document.getElementById("expense_vat_flag1").disabled= true; }else{ document.getElementById("expense_vat_flag1").checked= 'yes'; document.getElementById("expense_vat_flag1").value= 'on'; document.getElementById("expense_vat_flag1").disabled= false; } str = values_array[6] ; str = str.split(";sp;").join(" "); document.getElementById("supplier_name").value= str; var str = values_array[7]; str = str.split(";sp;").join(" "); str = str.split("&cr;").join("\r"); document.getElementById("netbank_supplier_name_info").value= str; strx = justNumberNF(document.getElementById("amount").value); document.all["expense_vat_amount1"].value = NetbankToDollarsAndCents(strx * (24/124)) ; document.getElementById("amount").value=NetbankToDollarsAndCents(strx); document.getElementById("expense_amount1").value = document.getElementById("amount").value; document.getElementById("expense_amount2").value = ''; document.getElementById("expense_account2").value= ''; //document.getElementById("expense_vat_flag2").value= ''; document.getElementById("expense_vat_amount2").value= ''; document.getElementById("expense_amount3").value = ''; document.getElementById("expense_account3").value= ''; //.getElementById("expense_vat_flag3").value= ''; document.getElementById("expense_vat_amount3").value= ''; document.getElementById("expense_amount4").value = ''; document.getElementById("expense_account4").value= ''; //document.getElementById("expense_vat_flag4").value= ''; document.getElementById("expense_vat_amount4").value= ''; document.getElementById("expense_amount5").value = ''; document.getElementById("expense_account5").value= ''; //document.getElementById("expense_vat_flag5").value= ''; document.getElementById("expense_vat_amount5").value= ''; str = values_array[8] ; str = str.split(";sp;").join(" "); if (str=="2"){ document.frmName.ButtonSelPeriodisering1.disabled=false; document.frmName.ButtonSelPeriodisering1.click(); } winName.close(); } } //Pass Data Back to original window function f_popup_return(as_Value) { var l_return = new Array(1); l_return[0] = as_Value; f_set_home_value(l_return); } function justNumberNF(val){ val = (val==null) ? 0 : val; // check if a number, otherwise try taking out non-number characters. if (isNaN(val)) { var newVal = parseFloat(val.replace(/[^\d\.\-]/g, '.')); // check if still not a number. Might be undefined, '', etc., so just replace with 0. return (isNaN(newVal) ? 0 : newVal); } // return 0 in place of infinite numbers. else if (!isFinite(val)) { return 0; } return val; }; function NetbankToDollarsAndCents(n) { var s = "" + Math.round(n * 100) / 100 ; var i = s.indexOf('.') ; if (i < 0) {return s + ",00" } ; var t = s.substring(0, i + 1) + s.substring(i + 1, i + 3) ; if (i + 2 == s.length) {t += "0"} ; return t.replace('.',',') ; }

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  • Handling inheritance with overriding efficiently

    - by Fyodor Soikin
    I have the following two data structures. First, a list of properties applied to object triples: Object1 Object2 Object3 Property Value O1 O2 O3 P1 "abc" O1 O2 O3 P2 "xyz" O1 O3 O4 P1 "123" O2 O4 O5 P1 "098" Second, an inheritance tree: O1 O2 O4 O3 O5 Or viewed as a relation: Object Parent O2 O1 O4 O2 O3 O1 O5 O3 O1 null The semantics of this being that O2 inherits properties from O1; O4 - from O2 and O1; O3 - from O1; and O5 - from O3 and O1, in that order of precedence. NOTE 1: I have an efficient way to select all children or all parents of a given object. This is currently implemented with left and right indexes, but hierarchyid could also work. This does not seem important right now. NOTE 2: I have tiggers in place that make sure that the "Object" column always contains all possible objects, even when they do not really have to be there (i.e. have no parent or children defined). This makes it possible to use inner joins rather than severely less effiecient outer joins. The objective is: Given a pair of (Property, Value), return all object triples that have that property with that value either defined explicitly or inherited from a parent. NOTE 1: An object triple (X,Y,Z) is considered a "parent" of triple (A,B,C) when it is true that either X = A or X is a parent of A, and the same is true for (Y,B) and (Z,C). NOTE 2: A property defined on a closer parent "overrides" the same property defined on a more distant parent. NOTE 3: When (A,B,C) has two parents - (X1,Y1,Z1) and (X2,Y2,Z2), then (X1,Y1,Z1) is considered a "closer" parent when: (a) X2 is a parent of X1, or (b) X2 = X1 and Y2 is a parent of Y1, or (c) X2 = X1 and Y2 = Y1 and Z2 is a parent of Z1 In other words, the "closeness" in ancestry for triples is defined based on the first components of the triples first, then on the second components, then on the third components. This rule establishes an unambigous partial order for triples in terms of ancestry. For example, given the pair of (P1, "abc"), the result set of triples will be: O1, O2, O3 -- Defined explicitly O1, O2, O5 -- Because O5 inherits from O3 O1, O4, O3 -- Because O4 inherits from O2 O1, O4, O5 -- Because O4 inherits from O2 and O5 inherits from O3 O2, O2, O3 -- Because O2 inherits from O1 O2, O2, O5 -- Because O2 inherits from O1 and O5 inherits from O3 O2, O4, O3 -- Because O2 inherits from O1 and O4 inherits from O2 O3, O2, O3 -- Because O3 inherits from O1 O3, O2, O5 -- Because O3 inherits from O1 and O5 inherits from O3 O3, O4, O3 -- Because O3 inherits from O1 and O4 inherits from O2 O3, O4, O5 -- Because O3 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 O4, O2, O3 -- Because O4 inherits from O1 O4, O2, O5 -- Because O4 inherits from O1 and O5 inherits from O3 O4, O4, O3 -- Because O4 inherits from O1 and O4 inherits from O2 O5, O2, O3 -- Because O5 inherits from O1 O5, O2, O5 -- Because O5 inherits from O1 and O5 inherits from O3 O5, O4, O3 -- Because O5 inherits from O1 and O4 inherits from O2 O5, O4, O5 -- Because O5 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 Note that the triple (O2, O4, O5) is absent from this list. This is because property P1 is defined explicitly for the triple (O2, O4, O5) and this prevents that triple from inheriting that property from (O1, O2, O3). Also note that the triple (O4, O4, O5) is also absent. This is because that triple inherits its value of P1="098" from (O2, O4, O5), because it is a closer parent than (O1, O2, O3). The straightforward way to do it is the following. First, for every triple that a property is defined on, select all possible child triples: select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value from TriplesAndProperties tp -- Select corresponding objects of the triple inner join Objects as Objects1 on Objects1.Id = tp.O1 inner join Objects as Objects2 on Objects2.Id = tp.O2 inner join Objects as Objects3 on Objects3.Id = tp.O3 -- Then add all possible children of all those objects inner join Objects as Children1 on Objects1.Id [isparentof] Children1.Id inner join Objects as Children2 on Objects2.Id [isparentof] Children2.Id inner join Objects as Children3 on Objects3.Id [isparentof] Children3.Id But this is not the whole story: if some triple inherits the same property from several parents, this query will yield conflicting results. Therefore, second step is to select just one of those conflicting results: select * from ( select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value, row_number() over( partition by Children1.Id, Children2.Id, Children3.Id, tp.Property order by Objects1.[depthInTheTree] descending, Objects2.[depthInTheTree] descending, Objects3.[depthInTheTree] descending ) as InheritancePriority from ... (see above) ) where InheritancePriority = 1 The window function row_number() over( ... ) does the following: for every unique combination of objects triple and property, it sorts all values by the ancestral distance from the triple to the parents that the value is inherited from, and then I only select the very first of the resulting list of values. A similar effect can be achieved with a GROUP BY and ORDER BY statements, but I just find the window function semantically cleaner (the execution plans they yield are identical). The point is, I need to select the closest of contributing ancestors, and for that I need to group and then sort within the group. And finally, now I can simply filter the result set by Property and Value. This scheme works. Very reliably and predictably. It has proven to be very powerful for the business task it implements. The only trouble is, it is awfuly slow. One might point out the join of seven tables might be slowing things down, but that is actually not the bottleneck. According to the actual execution plan I'm getting from the SQL Management Studio (as well as SQL Profiler), the bottleneck is the sorting. The problem is, in order to satisfy my window function, the server has to sort by Children1.Id, Children2.Id, Children3.Id, tp.Property, Parents1.[depthInTheTree] descending, Parents2.[depthInTheTree] descending, Parents3.[depthInTheTree] descending, and there can be no indexes it can use, because the values come from a cross join of several tables. EDIT: Per Michael Buen's suggestion (thank you, Michael), I have posted the whole puzzle to sqlfiddle here. One can see in the execution plan that the Sort operation accounts for 32% of the whole query, and that is going to grow with the number of total rows, because all the other operations use indexes. Usually in such cases I would use an indexed view, but not in this case, because indexed views cannot contain self-joins, of which there are six. The only way that I can think of so far is to create six copies of the Objects table and then use them for the joins, thus enabling an indexed view. Did the time come that I shall be reduced to that kind of hacks? The despair sets in.

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  • JoinDomainOrWorkgroup Method FJoinOptions help

    - by Ben
    Anyone have experience of using the JoinDomainOrWorkgroup Method of the Win32_ComputerSystem Class? I want to write a powershell script to join a machine to a domain. There may be an existing computer account for the machine, and if so I want to delete it and rejoin to the domain. I've already scripted the "search and destroy" part that will delete the computer account if it exists, but just noticed the FJoinOptions switches on Technet. Trouble is - they're a bit ambiguous. Does 4 (0x4) Deletes an account when a domain exists. mean it will delete the computer account if it already exists on the domain? Also, can you specify the computername you want to join the machine under with this method, or should you do a rename and then join the domain. Cheers, Ben NB - I've been using the guide at http://msdn.microsoft.com/en-us/library/aa392154(VS.85).aspx - not sure if there's a better resource out there.

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  • UIView animation along a round path?

    - by david
    I need to make my little guy (in a UIIamgeView) jump forward and it has to look natural. I want to know is there a way to do it with CoreAnimation (beginAnimation/commitAnimation)? I could do it by setting a point in between in the air but the movement looks not natural :P

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  • %HOMEPATH% Posh-Git error in Powershell, in ConEmu on Windows 7 64-bit

    - by atwright
    I am always getting the following error in Posh-Git in Powershell, in ConEmu on Windows 7 64-bit: Resolve-Path : Cannot find path 'C:\wamp\www\MobileApps\Backbone\%HOMEPATH%' because it does not exist. At D:\Users\Andy\Documents\WindowsPowerShell\Modules\posh-git\GitUtils.ps1:265 char:13 + $home = Resolve-Path (Invoke-NullCoalescing $Env:HOME ~) + ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ + CategoryInfo : ObjectNotFound: (C:\wamp\www\Mob...bone\%HOMEPATH%:String) [Resolve-Path], ItemNotFoundException + FullyQualifiedErrorId : PathNotFound,Microsoft.PowerShell.Commands.ResolvePathComma nd Join-Path : Cannot bind argument to parameter 'Path' because it is null. At D:\Users\Andy\Documents\WindowsPowerShell\Modules\posh-git\GitUtils.ps1:266 char:29 + Resolve-Path (Join-Path $home ".ssh\$File") -ErrorAction SilentlyContinue 2> ... + ~~~~~ + CategoryInfo : InvalidData: (:) [Join-Path], ParameterBindingValidationExc eption + FullyQualifiedErrorId : ParameterArgumentValidationErrorNullNotAllowed,Microsoft.Po werShell.Commands.JoinPathCommand Can anybody advise what might be wrong?

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  • Get mutually and non mutually existening Fields in same table in Two columns

    - by ranabra
    This is a question similar to another question I posted here but is a little different. I am trying to get a list of all instances of mutual and non-mutual existing Users. What I mean is that the returned result from the query will return a list of users along with their co-worker. It is similar to the question here, but the difference is that non mutual users will be returned too and with out the "duplicity" mutually existing users return in the list (See image below in-order simplify it all). I took the original answer from Thomas (Thanx again Thomas) Select D1.u_username, U1.Permission, U1.Grade, D1.f_username, U2.Permission, U2.Gradefrom tblDynamicUserList As D1    Join tblDynamicUserList As D2        On D2.u_username = D1.f_username            And D2.f_username = D1.u_username    Join tblUsers As U1        On U1.u_username = D1.u_username    Join tblUsers As U2        On U2.u_username = D2.u_username and after some several trials I commented out 2 lines (Below). The returned result are exactly as described in the beginning of this question, but with the "duplicity" returned by mutually existing users in the table. How can I eliminate this duplicity? Select D1.u_username, U1.Permission, U1.Grade, D1.f_username, U2.Permission, U2.Gradefrom tblDynamicUserList As D1    Join tblDynamicUserList As D2        On D2.u_username = D1.f_username            /* And D2.f_username = D1.u_username */    Join tblUsers As U1        On U1.u_username = D1.u_username    Join tblUsers As U2        On U2.u_username = D2.u_username /* WHERE D1.U_userName < D1.f_username */ *Screenshot that hopefully helps explain it all. Database is SQL 2005. Many thanx in advance

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