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  • Linq to Entities (EF): How to get the value of a FK without doing the join

    - by Chu
    I'm using the Linq to Entities. I've got my main table, Employee setup with a field named vendorID. Vendor ID is a foreign key into the Vendors table. As it is right now, the Employee object does not directly expose the vendorID. Instead, I can only access it this way: var employee = (from e in context.Employees.Include("tbl_vendors") where e.employeeID = 1 select e).FirstOrDefault(); //this gets the vendor ID int vendorID = employee.tbl_vendors.vendorID; That is just fine and dandy, but it is extra work on the database because it is forcing a join where none is needed. Is there a way to get that key value without being forced to do a join to the tbl_vendors table?

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  • Sql join, 2 tables, same fields

    - by Lobuno
    I have 2 tables. To simplify: Table 1, users: userId int, userName nvarchar(50) Table 2 , messages: msgId int, msgFrom int, msgTo int... msg1 and msg2, both contain userId. Now I want to get all messages, but instead of the msgFrom I want the user name. I know what to do here: select tabMessages.*, tabUsers.userName as Sender from tabMessages inner join tabUsers on msgFrom=userId where msgId = @someParameter; Everything works fine and dandy. The same to get the user name instead of msgTo. Now the problem is, how do I do to get BOTH fields in the same call? I want to get the table as msgId, msgFrom, msgTo, Sender, Recipient. I have tried as: select tabMessages.*, tabUsers.userName as Sender, tabUsers.userName as Recipient from tabMessages inner join tabUsers on msgFrom=userId and msgTo=userId where msgId = @someParameter; but that doesn't work. I'm using Ms sql2000 by the way.

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  • Compare two object lists with LINQ on specific property

    - by Niklas
    I have these two lists (where the Value in a SelectListItem is a bookingid): List<SelectListItem> selectedbookings; List<Booking> availableBookings; I need to find the ids from selectedBookings that are not in availableBookings. The LINQ join below will only get me the bookingids that are in availableBookings, and I'm not sure how to do it the other way around. != won't work since I'm comparing strings. results = ( from s in selectedbookings join a in availableBookings on s.bookingID.ToString() equals a.Value select s);

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  • MySQL customized join query using multiple tables

    - by itgeek
    I am searching one student from each class from one group. There are different class groups and every group has different classes and every class has multiple students. See below: Group1 --> Class1, Class2 etc Class1 --> GreenStudent1, GreenStudent2 etc Class2 --> RedStudent1, RedStudent2 etc ------------------------------------------------------ SELECT table1.id, table1.myname, table1.marks table2.studentid, table2.studentname FROM table1 INNER JOIN table3 ON table1.oldid = table3.id INNER JOIN table2 ON table2.studentid = table3.newid WHERE table1.classgroup = 'SCI79' GROUP BY table1.oldid ORDER BY table1.marks DESC There are different joins applied in the query. Above mentioned query giving me correct results but I need little modification in it. Current query returning me one student from each class. What I need? I need one student from each class but only that student who has MAXIMUM table1.marks So I should have one student from each class who has maximum number in their relevant classes. Can anyone suggest some solution or rewrite this query? Thanks :)

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  • mysql query to concat information from 3 tables - getting incorrect result count

    - by iPfaffy
    I have 3 tables in my database. ab_contacts id first_name last_name addressbook_id ab_addressbooks name id co_comments id link_id comment I'd like to create a query that will let me select all the contacts and comments related to them in a given addressbook. To select all the people in a given addressbook, I can use: select count(*) from ab_contacts where addressbook_id = '50'; This returns 8152 people. However, when I run my query: select ab_contacts.first_name, ab_contacts.last_name, ab_contacts.email, ab_addressbooks.name, co_comments.comments from ab_contacts JOIN ab_addressbooks ON (ab_contacts.addressbook_id = ab_addressbooks.id) JOIN co_comments ON (ab_contacts.id = co_comments.link_id) WHERE ab_contacts.addressbook_id = '50';` the format works, but I only get 1045 results. I'm sure there is something I am missing, but I cannot figure it out. Any help would be greatly appreciated.

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  • mysql syntax how to add a third table to $query

    - by IberoMedia
    I have code: $query = "SELECT a.*, c.name as categoryname, c.id as categoryid". " FROM #__table_one as a". " LEFT JOIN #__table_two c ON c.id = a.catid"; $query .= " WHERE a.published = 1" ." AND a.access <= {$aid}" ." AND a.trash = 0" ." AND c.published = 1" ." AND c.access <= {$aid}" ." AND c.trash = 0" ; I would like to add a third table ('__some_table') for the parts of the query where a.publish, a.access and a.trash. In other words, I want these fields to be retrieved from another table, not "#__table_one", but I do not know how to incorporate the #__some_table into the current query I imagine the JOIN command can help me, but I do not know how to code mysql Thank you,

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  • Help with MySQL Query?

    - by Devyn
    I have two tables rooms and users. I want to get only rooms.room_id, users.user_name with user_id = 1. I can get the result of all users with following sql... select rooms.room_id, rooms.user_id, users.user_name from rooms LEFT JOIN users ON rooms.user_id = users.user_id When I do like this to filter the result with user_id = 1 ... I got error. select rooms.room_id, rooms.user_id, users.user_name from rooms where rooms.user_id = 1 LEFT JOIN users ON rooms.user_id = users.user_id What should I do?

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  • Pattern for unidirectional has_many join?

    - by Kris
    It occurred to me that if I have a has_many join, where the foreign model does not have a belongs_to, and so the join is one way, then I don't actually need a foreign key. We could have a column, category_ids, which stores a marshaled Array of IDs which we can pass to find. So here is an untested example: class page < AR def categories Category.find(self.category_ids) end def categories<<(category) # get id and append to category_ids save! end def category_ids @cat_ids ||= Marshal.load(read_attribute(:category_ids)) rescue [] end def category_ids=(ids) @cat_ids = ids write_attribute(:category_ids, ids) end end page.category_ids = [1,4,12,3] page.categories = Array of Category Is there accepted pattern for this already? Is it common or just not worth the effort?

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  • MYSQL - Adding result set A to result set B? Please see my example

    - by BlackberryFan
    I have two mysql tables. They are laid out in this manner: user_info id | emailContact _______________________ 1 | [email protected] 3 | [email protected] user_biz_info id | emailContact _________________________ 8 | [email protected] 9 | [email protected] What kind of join would I use to create a result set of information like this: id | emailContact ________________________________ 1 - [email protected] 3 - [email protected] 8 - [email protected] 9 - [email protected] I have tried the following: SELECT p.id, p.emailContact, b.id, b.emailContact FROM user_info p, user_business_info b But it seems that this is an incorrect approach. Would someone be able to suggest the correct approach in this or possibly point me in the direction of some tutorials that cover this type of mysql join, as this is what I assume is needed in this case. Thanks for your time in reading through my question!!

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  • Partition loop understanding

    - by user1795732
    Why the loop body of the partition method never throws an ArrayIndexOutOfBounds Exception? public static int partition( int[] a, low, high ) { int k = low, m = low; /* loop invariant: * low <= k <= m <= high and * all elements in a[low..k-1] are RED (i.e., < pivot) and * all elements in a[k..m-1] are BLUE (i.e., >= pivot) */ while (m != high) { if (a[m] >= pivot) // a[m] is BLUE { } else { // a[m] is RED swap(a,k,m); k = k+1; } m = m+1; } return k; }

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  • How can I sum a group of sums? SQL-Sever 2008

    - by billynomates
    I have a query with a sum in it like this: SELECT Table1.ID, SUM(Table2.[Number1] + Table2.[Number2]) AS SumColumn FROM Table1 INNER JOIN Table3 ON Table1.ID = Table3.ID INNER JOIN Table2 ON Table3.ID = Table2.ID WHERE (Table2.[Something] = 'Whatever') GROUP BY Table1.ID, Table2.[Number1] , Table2.[Number2] and it gives me a table like this: ID SumColumn 67 1 67 4 70 2 70 6 70 3 70 6 80 5 97 1 97 3 How can I make it give me a table like this, where the SumColumn is summed, grouped by the ID column? ID SumColumn 67 5 70 17 80 5 97 4 I cannot GROUP BY SumColumn because I get an error (Invalid column name 'SumColumn'.) COALESCE doesn't work either. Thanks in advance. EDIT: Just grouping by the ID gives me an error: [Number1, Number2 and the other column names that I'm selecting] is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

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  • How to join the results of two tables in django python

    - by user1787524
    I have two models class Weather(model.model): region = models.ForeignKey(Region) district = models.ForeignKey(District) temp_max = models.IntegerField(blank=True, null=True, verbose_name='Max temperature (C)') temp_min = models.IntegerField(blank=True, null=True, verbose_name='Min temperature (C)') and class Plan(model.model): name = tinymce_models.HTMLField(blank=True, null=True) region = models.ForeignKey(Region) district = models.ForeignKey(District) Provided for every region and district have unique row. I want to combine the result so that i can get all the columns of both tables These two Models are not related to each other. ' I need to make the join like join weather w on w.region = A.region and w.distric = A.district so that result contains all the columns in everyobject like obj.temp_max etc

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  • MySQL UPDATE WHERE IN for each listed value separately?

    - by Tom
    Hi, I've got the following type of SQL: UPDATE photo AS f LEFT JOIN car AS c ON f.car_id=c.car_id SET f.photo_status=1 , c.photo_count=c.photo_count+1 WHERE f.photo_id IN ($ids) Basically, two tables (car & photo) are related. The list in $ids contains unique photo ids, such as (34, 87, 98, 12). With the query, I'm setting the status of each photo in that list to "1" in the photo table and simultaneously incrementing the photo count in the car table for the car at hand. It works but there's one snag: Because the list can contain multiple photo ids that relate to the same car, the photo count only ever gets incremented once. If the list had 10 photos associated with the same car, photo_count would become 1 .... whereas I'd like to increment it to 10. Is there a way to make the incrementation occur for each photo individually through the join, as opposed to MySQL overthinking it for me? I hope the above makes sense. Thanks.

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  • Hibernate and mssql inner join rowcount

    - by ez2sarang
    I am struggling with Hibernate Criteria. My aim is to create the following request using Hibernate Criteria : select count(*) as y0_ from PInterface this_ inner join Product product2_ on this_.product_id=product2_.id where this_.product_interface_type_id=? Here is my code: @Entity @Table(name = "PInterface") public class PInterface { @Id @GeneratedValue @Column(name = "id", nullable = false, insertable = false, updatable = false) private int id; @Column(name = "product_id") private int productId; @Column(name = "product_interface_type_id") private int type; @ManyToOne(optional=false) @JoinColumn(name = "product_id", referencedColumnName = "id", insertable=false, updatable=false) private Product product; } @Entity @Table(name = "Product") public class Product { @Id @GeneratedValue @Column(name = "id", nullable = false, insertable = false, updatable = false) private int id; private String name; } //Criteria is : Object criteria = sessionFactory.getCurrentSession() .createCriteria(PInterface.class) .add(Restrictions.eq("type", 1)) .setProjection(Projections.rowCount()) .uniqueResult() ; However, the results ... select count(*) as y0_ from PInterface this_ where this_.product_interface_type_id=? Where Inner join? Thank you for help!

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  • How to move the Windows 7 bootloader to the Windows 7 partition?

    - by pauldoo
    I recently installed Windows 7 in a triple boot setup alongside XP and Linux. When I was finished and was in the process of restoring the bootloader for Linux I discovered something strange about what Windows 7 had done. I discovered that Windows 7 had not installed a bootloader to it's own partition, and instead had instead set up a bootloader on the pre-existing XP partition that offers a choice between 7 and XP. This behaviour has been noticed by others. Now my booting is slightly odd. I have GRUB on the MBR which lets me choose between Linux and Windows. When I select Windows I have Grub boot to the XP partition where I get the 2nd choice between 7 and XP. Why doesn't the Windows 7 installer put the Windows 7 bootloader on the Windows 7 partition like all previous MS OSs? This is now going to be a real problem for me, as I now want to wipe the XP partition and install something else there (probably another non-MS OS). How can I move the bootloader for Windows 7 onto the Windows 7 partition, thus making it bootable and allowing me to safely wipe the XP partition?

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  • Can't find partition tab in disk utility osX ver. 10.6.8

    - by John W
    I just got a used Mac Book Pro. I created a new admin account and deleted the old one as well as one other user. This is an older late 2007 MBP... the osX upgrade to 10.6.8 was just performed. My Macintosh HD is showing up as Partition 2. I ran disk utility (not from install disk), but there was no partition tab. I have a 160GB drive with only 53GB of space left on it. Since I am the only user and have no files on the laptop yet, I don't understand why there is so little space left. Surely the OS can't use up over 100GB. I wanted to run disk utility to see if there were any recovery partitions or other partition left over from the previous owner that could be erased to make room for expanding the main partition. Unfortunately, there is no partition tab in disk utility. The documentation I have found on line states that this version of osX includes that utility. The osX disks I have are for an older version so I wasn't sure if they would be of any use in solving this problem. Also, I was afraid if using the disks, would I lose the little bit of data/apps that I have assembled. I would rather not do a fresh install and have to do all the updates again to achieve this. The previous owner had some apps that I don't want to lose as I would have to pay handsomely to get them back. Simply, if all the previous users data is backed up on here after deleting user is still taking up space on a recovery partition (that I can't see)... I need to locate it erase it and expand the primary partition to re-aquire disk space for my files. I am new to Mac, so please be as descriptive as possible. Thanks.

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  • How to reinstall Mac OS X on OS X/Linux dual-boot system?

    - by strangeronyourtrain
    My setup: I have a MacBook Pro 5,5 with a Mac OS X Snow Leopard partition and a Linux partition. I use rEFIt to boot into Linux. I didn't use Boot Camp when I originally installed Linux; instead, I manually created the partition (with either Disk Utility in OS X or Gparted on a Linux live CD--I don't recall which one) and then installed Linux on it from a live CD. The problem: My OS X partition is corrupt, and I need to reinstall Snow Leopard. Since I installed rEFIt from within OS X, I'm concerned that wiping the OS X partition will prevent me from booting into my Linux partition. How can I do this without losing access to my Linux partition? Is it possible to install Snow Leopard on the partition I reserved for it, or will it automatically overwrite the entire drive? And if I do the fresh OS X install and then install rEFIt again, will it automatically recognize my Linux partition? Thanks for any tips! Specs: MacBook Pro 5,5 (Mid-2009); Snow Leopard 10.6.7/64-bit Sabayon Linux, 2.6.36 kernel EDIT/UPDATE: Thanks, but the situation has taken a more complicated turn: I tried to reinstall Snow Leopard from the DVD, but it refused to install onto my Mac partition, claiming: "The disk cannot be used to start up your computer." Disk Utility wouldn't let me resize the partition or create a new one, and it doesn't see my Linux partition. It only displays the two partitions "Macintosh HD" and Linux Swap. I can, however, see all the partitions from Linux. This is the partition table as shown in Gparted: And the output of "fdisk -l" is: WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 250.1 GB, 250059350016 bytes 255 heads, 63 sectors/track, 30401 cylinders, total 488397168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sda1 1 409639 204819+ ee GPT /dev/sda2 409640 349590464 174590412+ af HFS / HFS+ /dev/sda3 483122745 488392064 2634660 82 Linux swap / Solaris /dev/sda4 * 349590465 483122744 66766140 83 Linux Partition table entries are not in disk order I wonder if this is because I originally partitioned my disk with Gparted instead of OS X's Disk Utility (at this point, I don't recall whether I used Gparted or Disk Utility). In any case, it doesn't seem safe to do any reformatting with Disk Utility now, as I'm afraid it will wipe sda2 ("Macintosh HD") as well as sda4 (my Linux partition). So... I'm hoping to find a solution that doesn't involve wiping my entire hard disk. Would it be safe/possible to use Gparted to erase sda2 ("Macintosh HD") and then use the Snow Leopard DVD to install OS X onto [I]just[/I] sda2 without touching the other partitions? Thanks for any insight!

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  • Can i lock a record from a join sql statment using ROWLOCK,UPDLOCK ?

    - by Andrea.Ko
    I have a store procedure to get the data i want: SELECT a.SONum, a.Seq1, a.SptNum, a.Qty1, a.SalUniPriP, a.PayNum, a.InvNum, a.BLNum, c.ETD, c.ShpNum, f.IssBan FROM OrdD a JOIN OrdH b ON a.SONum = b.SONum LEFT JOIN Invh c ON a.InvNum = c.InvNum LEFT JOIN cus d ON b.CusCod = d.CusCod LEFT JOIN BL e ON a.BLNum = e.BLNum LEFT JOIN PayMasH f ON f.PayNum = a.PayNum LEFT JOIN Shipment g ON g.ShpNum = c.ShpNum WHERE b.CusCod IN (SELECT CusCod FROM UsrInc WHERE UseID=@UserID and UseLev=@UserLvl) AND d.CusGrp = @CusGrp After i get those records into cursor, i used RowLock, UpdLock to lock all the related invoice number. SELECT InvNum FROM Invh WITH (ROWLOCK,UPDLOCK) WHERE InvNum = Can i issue locking on the table INVH at the point i select the table from a few table using join command? Any advice, please!

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  • Have I fixed my partition problem with os x 10.5.8? Are my GPT and MBR back to normal?

    - by David Schaap
    I'm new to linux and I have overstepped by abilities. I tried dual booting os x 10.5.8 with ubuntu 11.10 with rEFIt, but I been having problems with partitioning. Instead of enduring more headaches, I've made the decision to simply use ubuntu on VirtualBox. I've tried to return my HDD to normal, but I am looking for confirmation that my partitions are ok. Here is the report from partition inspector: *** Report for internal hard disk *** Current GPT partition table: # Start LBA End LBA Type 1 409640 233917359 Mac OS X HFS+ Current MBR partition table: # A Start LBA End LBA Type 1 1 234441647 ee EFI Protective MBR contents: Boot Code: GRUB Partition at LBA 409640: Boot Code: None File System: HFS Extended (HFS+) Listed in GPT as partition 1, type Mac OS X HFS+ Also, my HDD directory has a bunch of extra folders in them and they appear to be ubuntu related, although it is no longer installed. folders like bin, sbin, cores, var, user, and so on. Those folders aren't supposed to be there, right? Thanks in advance.

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  • ROW_NUMBER() VS. DISTINCT

    - by ramadan2050
    Dear All, I have a problem with ROW_NUMBER() , if i used it with DISTINCT in the following Query I have 2 scenarios: 1- run this query direct : give me for example 400 record as a result 2- uncomment a line which start with [--Uncomment1--] : give me 700 record as a result it duplicated some records not all the records what I want is to solve this problem or to find any way to show a row counter beside each row, to make a [where rownumber between 1 and 30] --Uncomment2-- if I put the whole query in a table, and then filter it , it is work but it still so slow waiting for any feedback and I will appreciate that Thanks in advance SELECT * FROM (SELECT Distinct CRSTask.ID AS TaskID, CRSTask.WFLTaskID, --Uncomment1-- ROW_NUMBER() OVER (ORDER By CRSTask.CreateDate asc ) AS RowNum , CRSTask.WFLStatus AS Task_WFLStatus, CRSTask.Name AS StepName, CRSTask.ModifiedDate AS Task_ModifyDate, CRSTask.SendingDate AS Task_SendingDate, CRSTask.ReceiveDate AS Task_ReceiveDate, CRSTask.CreateDate AS Task_CreateDate, CRS_Task_Recipient_Vw.Task_CurrentSenderName, CRS_Task_Recipient_Vw.Task_SenderName, CRS_INFO.ID AS CRS_ID, CRS_INFO.ReferenceNumber, CRS_INFO.CRSBeneficiaries, CRS_INFO.BarCodeNumber, ISNULL(dbo.CRS_FNC_GetTaskReceiver(CRSTask.ID), '') + ' ' + ISNULL (CRS_Organization.ArName, '') AS OrgName, CRS_Info.IncidentID, COALESCE(CRS_Subject.ArSubject, '??? ????') AS ArSubject, COALESCE(CRS_INFO.Subject, 'Blank Subject') AS CRS_Subject, CRS_INFO.Mode, CRS_Task_Recipient_Vw.ReceiverID, CRS_Task_Recipient_Vw.ReceiverType, CRS_Task_Recipient_Vw.CC, Temp_Portal_Users_View.ID AS CRS_LockedByID, Temp_Portal_Users_View.ArabicName AS CRS_LockedByName, CRSDraft.ID AS DraftID, CRSDraft.Type AS DraftType, CASE WHEN CRS_Folder = 1 THEN Task_SenderName WHEN CRS_Folder = 2 THEN Task_SenderName WHEN CRS_Folder = 3 THEN Task_CurrentSenderName END AS SenderName, CRS_Task_Folder_Vw.CRS_Folder, CRS_INFO.Status, CRS_INFO.CRS_Type, CRS_Type.arName AS CRS_Type_Name FROM CRS_Task_Folder_Vw LEFT OUTER JOIN CRSTask ON CRSTask.ID = CRS_Task_Folder_Vw.TaskID LEFT OUTER JOIN CRS_INFO ON CRS_INFO.ID = CRSTask.CRSID LEFT OUTER JOIN CRS_Subject ON COALESCE( SUBSTRING( CRS_INFO.Subject, CHARINDEX('_', CRS_INFO.Subject) + 1, LEN(CRS_INFO.Subject) ), 'Blank Subject' ) = CRS_Subject.ID LEFT OUTER JOIN CRSInfoAttribute ON CRS_INFO.ID = CRSInfoAttribute.ID LEFT OUTER JOIN CRS_Organization ON CRS_Organization.ID = CRSInfoAttribute.SourceID LEFT OUTER JOIN CRS_Type ON CRS_INFO.CRS_Type = CRS_Type.ID LEFT OUTER JOIN CRS_Way ON CRS_INFO.CRS_Send_Way = CRS_Way.ID LEFT OUTER JOIN CRS_Priority ON CRS_INFO.CRS_Priority_ID = CRS_Priority.ID LEFT OUTER JOIN CRS_SecurityLevel ON CRS_INFO.SecurityLevelID = CRS_SecurityLevel.ID LEFT OUTER JOIN Portal_Users_View ON Portal_Users_View.ID = CRS_INFO.CRS_Initiator LEFT OUTER JOIN AD_DOC_TBL ON CRS_INFO.DocumentID = AD_DOC_TBL.ID LEFT OUTER JOIN CRSTask AS Temp_CRSTask ON CRSTask.ParentTask = Temp_CRSTask.ID LEFT OUTER JOIN Portal_Users_View AS Temp_Portal_Users_View ON Temp_Portal_Users_View.ID = AD_DOC_TBL.Lock_User_ID LEFT OUTER JOIN Portal_Users_View AS Temp1_Portal_Users_View ON Temp1_Portal_Users_View.ID = CRS_INFO.ClosedBy LEFT OUTER JOIN CRSDraft ON CRSTask.ID = CRSDraft.TaskID LEFT OUTER JOIN CRS_Task_Recipient_Vw ON CRSTask.ID = CRS_Task_Recipient_Vw.TaskID --LEFT OUTER JOIN CRSTaskReceiverUsers ON CRSTask.ID = CRSTaskReceiverUsers.CRSTaskID AND CRS_Task_Recipient_Vw.ReceiverID = CRSTaskReceiverUsers.ReceiverID LEFT OUTER JOIN CRSTaskReceiverUserProfile ON CRSTask.ID = CRSTaskReceiverUserProfile.TaskID WHERE Crs_Info.SUBJECT <> 'Blank Subject' AND (CRS_INFO.Subject NOT LIKE '%null%') AND CRS_Info.IsDeleted <> 1 /* AND CRSTask.WFLStatus <> 6 AND CRSTask.WFLStatus <> 8 */ AND ( ( CRS_Task_Recipient_Vw.ReceiverID IN (1, 29) AND CRS_Task_Recipient_Vw.ReceiverType IN (1, 3, 4) ) ) AND 1 = 1 )Codes --Uncomment2-- WHERE Codes.RowNum BETWEEN 1 AND 30 ORDER BY Codes.Task_CreateDate ASC

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  • Is it perfectly safe to install grub bootloader on regular partition?

    - by Flint
    One of the methods to do dual booting Windows with Linux OS is by installing grub boot loader onto Linux partition so you can retain Windows boot loader and let Windows handles the dual booting process. What's the odd that grub bootloader could partially overwrite the data at the beginning of the Linux partition and corrupt the file? Does grub actually check if there's a data at the beginning of the partition and move it to other location on the partition before writing its bootloader?

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  • Why does Ubuntu 13.10 not detect my Win7 partition?

    - by goutham
    I'm trying to install Ubuntu 13.10 alongside Windows 7 on my DELL INSPIRON 14z 5423 laptop and I'm new to all of this. I'm using the Ubuntu 13.10 64-bit ISO burned onto a CD. The first time I tried to install it, Ubuntu said it did not detect any other OS, which meant I only had 4 options: Erase disk and install Ubuntu (I don't want to do this) Encrypt new Ubuntu. Use LVM. Something else. If I choose the Something else option, it brings me to the partition menu and says that I have 1 disk with free space of (500Gb), but that's not true because I have Windows 7. I restarted the laptop several times and booted the CD again and I got exactly the same as I did previously. How do fix this problem and install Ubuntu alongside Windows 7? After executing "sudo fdisk -l" command in terminal ubuntu@ubuntu:~$ sudo fdisk -l WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders, total 976773168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0xd2b811c5 Device Boot Start End Blocks Id System /dev/sda1 * 2048 206847 102400 7 HPFS/NTFS/exFAT /dev/sda2 206848 314574847 157184000 7 HPFS/NTFS/exFAT /dev/sda3 314574848 629147647 157286400 7 HPFS/NTFS/exFAT /dev/sda4 629147648 976771071 173811712 7 HPFS/NTFS/exFAT After removing one partition I executed command once again ubuntu@ubuntu:~$ sudo fdisk -l WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders, total 976773168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0xd2b811c5 Device Boot Start End Blocks Id System /dev/sda1 * 2048 206847 102400 7 HPFS/NTFS/exFAT /dev/sda2 206848 629145599 314469376 7 HPFS/NTFS/exFAT /dev/sda3 629147648 976771071 173811712 7 HPFS/NTFS/exFAT

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  • Partition tool with console UI (as in server installation)?

    - by lepe
    Back in 2006, Ray (3DLover) posted the same question in: http://ubuntuforums.org/showthread.php?t=309680 but none of the answers were really useful. Now with a little help from AskUbuntu community, I would like to repeat his question again to see if this time it can be answered correctly. So this is the question (and what I wish too): I'm looking for a UI tool for managing partitions in a console. I have installed Ubuntu Server, so I don't have X Windows at all. fdisk and sfdisk are entirely command line. parted is slightly better, but it's not really a UI. cfdisk has somewhat of a UI, but it only works on one disk at a time, and there's no advanced options like configuring LVM or RAID. Just partitioning. I love the partition tool that is available during the OS install procedure. You can partition, configure RAID's and LMV sets. It can format the partitions with several different file systems, it can set labels, mount options and it can insert your volumes into your fstab. Is this tool available as a stand-alone program? I can't find it anywhere. I think it's called parted_server, but I can't find much information about where to get it. In the past, I have run the Ubuntu install procedure just to use the partition manager that comes with it. (canceling the install after making my partition edits) Anyone help me on this? Thanks -Ray Thanks in advance.

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  • Querying a self referencing join with NHibernate Linq

    - by Ben
    In my application I have a Category domain object. Category has a property Parent (of type category). So in my NHibernate mapping I have: <many-to-one name="Parent" column="ParentID"/> Before I switched to NHibernate I had the ParentId property on my domain model (mapped to the corresponding database column). This made it easy to query for say all top level categories (ParentID = 0): where(c => c.ParentId == 0) However, I have since removed the ParentId property from my domain model (because of NHibernate) so I now have to do the same query (using NHibernate.Linq) like so: public IList<Category> GetCategories(int parentId) { if (parentId == 0) return _catalogRepository.Categories.Where(x => x.Parent == null).ToList(); else return _catalogRepository.Categories.Where(x => x.Parent.Id == parentId).ToList(); } The real impact that I can see, is the sql generated. Instead of a simple 'select x,y,z from categories where parentid = 0' NHibernate generates a left outer join: SELECT this_.CategoryId as CategoryId4_1_, this_.ParentID as ParentID4_1_, this_.Name as Name4_1_, this_.Slug as Slug4_1_, parent1_.CategoryId as CategoryId4_0_, parent1_.ParentID as ParentID4_0_, parent1_.Name as Name4_0_, parent1_.Slug as Slug4_0_ FROM Categories this_ left outer join Categories parent1_ on this_.ParentID = parent1_.CategoryId WHERE this_.ParentID is null Which doesn't seems much less efficient that what I had before. Is there a better way of querying these self referencing joins as it's very tempting to drop the ParentID back onto my domain model for this reason. Thanks, Ben

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