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  • Updates to Stairway to Integration Services

    - by andyleonard
    The Stairway to integration Services has been updated! I added content to Step 1 to provide more detail about creating a first SSIS project and corrected a typo in Step 2 that referred to an older name for the Step 1 article. I also made the corrected Step 1 article name a link to help. Thanks to Steve Jones ( blog | @way0utwest ) for all his hard work editing and corralling trifling authors. :{>...(read more)

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  • Pathfinding for fleeing

    - by Philipp
    As you know there are plenty of solutions when you wand to find the best path in a 2-dimensional environment which leads from point A to point B. But how do I calculate a path when an object is at point A, and wants to get away from point B, as fast and far as possible? A bit of background information: My game uses a 2d environment which isn't tile-based but has floating point accuracy. The movement is vector-based. The pathfinding is done by partitioning the game world into rectangles which are walkable or non-walkable and building a graph out of their corners. I already have pathfinding between points working by using Dijkstras algorithm. The use-case for the fleeing algorithm is that in certain situations, actors in my game should perceive another actor as a danger and flee from it. The trivial solution would be to just move the actor in a vector in the direction which is opposite from the threat until a "safe" distance was reached or the actor reaches a wall where it then covers in fear. The problem with this approach is that actors will be blocked by small obstacles they could easily get around. As long as moving along the wall wouldn't bring them closer to the threat they could do that, but it would look smarter when they would avoid obstacles in the first place: Another problem I see is with dead ends in the map geometry. In some situations a being must choose between a path which gets it faster away now but ends in a dead end where it would be trapped, or another path which would mean that it wouldn't get that far away from the danger at first (or even a bit closer) but on the other hand would have a much greater long-term reward in that it would eventually get them much further away. So the short-term reward of getting away fast must be somehow valued against the long-term reward of getting away far. There is also another rating problem for situations where an actor should accept to move closer to a minor threat to get away from a much larger threat. But completely ignoring all minor threats would be foolish, too (that's why the actor in this graphic goes out of its way to avoid the minor threat in the upper right area): Are there any standard solutions for this problem?

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  • Preview Oracle E-Business Suite Release 12!

    Steve Miranda, Oracle SVP of Applications Development speaks with Fred about the features and benefits of Oracle E-Business Suite Release 12 and how this release will streamline global operations and move customers father along the path to Oracle Fusion.

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  • Apple expulse Flash, Java et .NET de l'iPhone en modifiant ses conditions d'utilisation, et provoque

    Apple expulse Flash, Java et .NET de l'iPhone en mofidiant ses conditions d'utilisation, la stratégie de Steve Jobs provoque des réactions d'une rare violence Après la sortie de l'iPad, Apple vient de dévoiler le nouvel OS de son iPhone (iPhone OS 4). Deux évènements qui ont fait grand bruit. Un troisième est en train de créer la polémique. Apple a en effet décidé de changer les condit...

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  • FORBES.COM: Oracle's message is loud & clear – “we've got the cloud”

    - by Richard Lefebvre
    In a two-part series on Oracle's cloud strategy, Bob Evans reports on the October 4 meeting where Wall Street analysts questioned Mark Hurd and Safra Catz about the company's positioning for the shift to cloud computing. Check out Bob's related Forbes.com piece "The Dumbest Idea of 2013," in response to the preposterous chatter that Larry Ellison and Oracle don't "get" the cloud. His powerful six-point argument unravels our competitors' spin. Read the "Dumbest Idea."

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  • Facebook veut analyser les mouvements du curseur sur l'écran, la technologie est déjà en phase de tests

    Facebook veut analyser les mouvements du curseur sur l'écran, la technologie est déjà en phase de tests Ken Rudin, le directeur de l'analyse et de l'exploitation des données pour Facebook, a confié au Wall Street Journal que des tests sont en cours sur de nouvelles techniques d'observation du comportement des usagers. Tout d'abord Facebook a l'intention de traquer les habitudes de ses utilisateurs en suivant à la trace les mouvements du curseur de la souris lors de leurs passages sur le réseau...

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  • Allianz CIO 'lost hair' over Linux upgrade

    <b>ZDNet:</b> "Allianz Australia Insurance chief information officer (CIO) Steve Cole said yesterday he had done the equivalent of losing hair while undertaking an upgrade that saw the company move from multiple Wintel servers to a Linux mainframe."

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  • Bump mapping Problem GLSL

    - by jmfel1926
    I am having a slight problem with my Bump Mapping project. Although everything works OK (at least from what I know) there is a slight mistake somewhere and I get incorrect shading on the brick wall when the light goes to the one side or the other as seen in the picture below: The light is on the right side so the shading on the wall should be the other way. I have provided the shaders to help find the issue (I do not have much experience with shaders). Shaders: varying vec3 viewVec; varying vec3 position; varying vec3 lightvec; attribute vec3 tangent; attribute vec3 binormal; uniform vec3 lightpos; uniform mat4 cameraMat; void main() { gl_TexCoord[0] = gl_MultiTexCoord0; gl_Position = ftransform(); position = vec3(gl_ModelViewMatrix * gl_Vertex); lightvec = vec3(cameraMat * vec4(lightpos,1.0)) - position ; vec3 eyeVec = vec3(gl_ModelViewMatrix * gl_Vertex); viewVec = normalize(-eyeVec); } uniform sampler2D colormap; uniform sampler2D normalmap; varying vec3 viewVec; varying vec3 position; varying vec3 lightvec; vec3 vv; uniform float diffuset; uniform float specularterm; uniform float ambientterm; void main() { vv=viewVec; vec3 normals = normalize(texture2D(normalmap,gl_TexCoord[0].st).rgb * 2.0 - 1.0); normals.y = -normals.y; //normals = (normals * gl_NormalMatrix).xyz ; vec3 distance = lightvec; float dist_number =length(distance); float final_dist_number = 2.0/pow(dist_number,diffuset); vec3 light_dir=normalize(lightvec); vec3 Halfvector = normalize(light_dir+vv); float angle=max(dot(Halfvector,normals),0.0); angle= pow(angle,specularterm); vec3 specular=vec3(angle,angle,angle); float diffuseterm=max(dot(light_dir,normals),0.0); vec3 diffuse = diffuseterm * texture2D(colormap,gl_TexCoord[0].st).rgb; vec3 ambient = ambientterm *texture2D(colormap,gl_TexCoord[0].st).rgb; vec3 diffusefinal = diffuse * final_dist_number; vec3 finalcolor=diffusefinal+specular+ambient; gl_FragColor = vec4(finalcolor, 1.0); }

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  • Announcing the Fusion Applications Blog

    - by Theresa Hickman
    Want to learn more about Oracle's next generation applications, Fusion Applications, from key executives, strategy and development leaders? We have a Fusion Applications blog. Steve Miranda, Senior Vice President, Applications Development of Oracle kicks off the Fusion Applications blog series @blogs.oracle.com/applications. Content will vary; some content will be applicable to all Fusion Applications families, and some will focus on a particular family (HCM, CRM, Financials, etc.) You can also follow them on Facebook www.facebook.com/OracleApps.

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  • Five Day Forecast for the Mushroom Kingdom [Wallpaper]

    - by Asian Angel
    Definitely not going to be a dull week… Note: The original size of the wallpaper is 1600*900, but it can be easily placed on a larger matching color background to fit your monitor’s resolution. Mario, Weather, Forecast [The Paper Wall] How to Use an Xbox 360 Controller On Your Windows PC Download the Official How-To Geek Trivia App for Windows 8 How to Banish Duplicate Photos with VisiPic

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  • SQL in the City - Chicago 2012

    A free day of training in Chicago on Oct 5, 2012. Join Grant Fritchey, Steve Jones and more to discuss, debate, ask questions, and learn about how to better run your organizations SQL Servers. Are you sure you can restore your backups? Run full restore + DBCC CHECKDB quickly and easily with SQL Backup Pro's new automated verification. Check for corruption and prepare for when disaster strikes. Try it now.

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  • Google backs open codec against patent trolls

    <b>The Register:</b> "Google is "very confident" that the newly open-sourced VP8 video codec will stand up to the sort of patent attack Steve Jobs warned of when he defended Apple's decision to shun VP8's predecessor, the open-source Ogg Theora."

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  • Patent Pool to Thwart Open Source Codecs

    <b>DaniWeb:</b> "Just when you thought it couldn't get any worse in the world of software patents, a reliable source sent me this response from Steve Jobs about a patent pool that's forming and aiming to nail the open source codecs projects."

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  • Google officialise sa tablette 7 pouces à destination des développeurs, dans le cadre du Projet Tango

    Google officialise sa tablette 7 pouces à destination des développeurs, dans le cadre du Projet Tango Hier, Google a lancé sa Project Tango Tablet Development Kit, sa tablette spécialisée dans la capture d'images en 3D. Pour 1 024 dollars, les développeurs peuvent déjà passer une précommande de l'appareil développé en collaboration avec NVIDIA. Mountain View précise que le nombre est limité, probablement à 4 000 unités comme le suggérait tantôt le Wall Street Journal.La tablette de 7 pouces...

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  • Android 2.2 supportera Flash annonce le responsable de l'OS chez Google, qui répond également aux pr

    Mise à jour du 28/04/10 Android 2.2 supportera Flash C'est ce qu'annonce le responsable de l'OS chez Google, qui répond également à Steve Jobs et à ses propos sur Android L'ingénieur en charge du projet Android chez Google, Andy Rubin, vient d'accorder une interview au New York Times dans laquelle il annonce que Froyo (pour « Frozen Yourt » - nom de code de la prochaine version de l'OS mobile) assurera le « support total » ("full support") de Flash. Reste à savoir ce que ce « full support » recouvre : support d'une version Flash entière (différente de la version Lite généralement présente dans l'univers du développemen...

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  • Harnessing PowerShell's String Comparison and List-Filtering Features

    When you are first learning PowerShell, it often seems to be an 'Alice through the looking-glass' world. Just the simple process of comparing and selecting strings can seem strangely obtuse. Michael turns the looking-glass into wonderland with his wall-chart of the PowerShell string-comparison operators and syntax The Future of SQL Server MonitoringMonitor wherever, whenever with Red Gate's SQL Monitor. See it live in action now.

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  • SQL in the City - New York 2012

    Come join Grant Fritchey, Steve Jones and others for a free day of training in New York City on Sept 28, 2012. Learn Agile Database Development Best PracticesAgile database development experts Sebastian Meine and Dennis Lloyd are running day-long classes designed to complement Red Gate’s SQL in the City US tour. Classes will be held in San Francisco, Chicago, Boston and Seattle. Register Now.

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  • SQL in the City - Boston 2012

    A free day of training in Boston on Oct 8, 2012. Come join Grant Fritchey, Steve Jones and more to talk about SQL Server and how you can work more efficiently. Keep your database and application development in syncSQL Connect is a Visual Studio add-in that brings your databases into your solution. It then makes it easy to keep your database in sync, and commit to your existing source control system. Find out more.

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  • Java 2D Tile Collision

    - by opiop65
    I have been working on a way to do collision detection forever, and just can't figure it out. Here's my simple 2D array: for (int x = 0; x < 16; x++) { for (int y = 0; y < 16; y++) { map[x][y] = AIR; if(map[x][y] == AIR) { air.draw(x * tilesize, y * tilesize); } } } for (int x = 0; x < 16; x++) { for (int y = 6; y < 16; y++) { map[x][y] = GRASS; if(map[x][y] == GRASS) { grass.draw(x * tilesize, y * tilesize); } } } for (int x = 0; x < 16; x++) { for (int y = 8; y < 16; y++) { map[x][y] = STONE; if(map[x][y] == STONE) { stone.draw(x * tilesize, y * tilesize); } } } I want to do it with rectangles, and using the intersect() method, but how would I go about adding rectangles to all the tiles? Edit: My player moves like this: if(input.isKeyDown(Input.KEY_W)) { shiftY -= delta * speed; idY = (int) shiftY; if(shift == true) { shiftY -= delta * runspeed; } if(isColliding == true) { shiftY += delta * speed; } } if(input.isKeyDown(Input.KEY_S)) { shiftY += delta * speed; idY = (int) shiftY; if(shift == true) { shiftY += delta * runspeed; } if(isColliding == true) { shiftY -= delta * speed; } } if (input.isKeyDown(Input.KEY_A)) { steve = left; shiftX -= delta * speed; idX = (int) shiftX; if(shift == true) { shiftX -= delta * runspeed; } if(isColliding == true) { shiftX += delta * speed; } } if (input.isKeyDown(Input.KEY_D)) { steve = right; shiftX += delta * speed; idX = (int) shiftX; if(shift == true) { shiftX += delta * runspeed; } if(isColliding == true) { shiftX -= delta * speed; } } (I have tried my own collision code, but its horrible. Doesn't work in the slightest)

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  • SQL in the City - San Francisco 2012

    The city by the bay welcomes Steve Jones, Grant Fritchey and more for a day of debate, discussion and learning about SQL Server. It's free. Just register and join us. Are you sure you can restore your backups? Run full restore + DBCC CHECKDB quickly and easily with SQL Backup Pro's new automated verification. Check for corruption and prepare for when disaster strikes. Try it now.

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  • SQL Saturday #162 - Cambridge, UK

    Come to Cambridge in the UK for a free day of training on SQL Server. Steve won't be there, but plenty of other Red Gate'ers will be. Learn Agile Database Development Best PracticesAgile database development experts Sebastian Meine and Dennis Lloyd are running day-long classes designed to complement Red Gate’s SQL in the City US tour. Classes will be held in San Francisco, Chicago, Boston and Seattle. Register Now.

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  • HTML5 platformer collision detection problem

    - by fnx
    I'm working on a 2D platformer game, and I'm having a lot of trouble with collision detection. I've looked trough some tutorials, questions asked here and Stackoverflow, but I guess I'm just too dumb to understand what's wrong with my code. I've wanted to make simple bounding box style collisions and ability to determine on which side of the box the collision happens, but no matter what I do, I always get some weird glitches, like the player gets stuck on the wall or the jumping is jittery. You can test the game here: Platform engine test. Arrow keys move and z = run, x = jump, c = shoot. Try to jump into the first pit and slide on the wall. Here's the collision detection code: function checkCollisions(a, b) { if ((a.x > b.x + b.width) || (a.x + a.width < b.x) || (a.y > b.y + b.height) || (a.y + a.height < b.y)) { return false; } else { handleCollisions(a, b); return true; } } function handleCollisions(a, b) { var a_top = a.y, a_bottom = a.y + a.height, a_left = a.x, a_right = a.x + a.width, b_top = b.y, b_bottom = b.y + b.height, b_left = b.x, b_right = b.x + b.width; if (a_bottom + a.vy > b_top && distanceBetween(a_bottom, b_top) + a.vy < distanceBetween(a_bottom, b_bottom)) { a.topCollision = true; a.y = b.y - a.height + 2; a.vy = 0; a.canJump = true; } else if (a_top + a.vy < b_bottom && distanceBetween(a_top, b_bottom) + a.vy < distanceBetween(a_top, b_top)) { a.bottomCollision = true; a.y = b.y + b.height; a.vy = 0; } else if (a_right + a.vx > b_left && distanceBetween(a_right, b_left) < distanceBetween(a_right, b_right)) { a.rightCollision = true; a.x = b.x - a.width - 3; //a.vx = 0; } else if (a_left + a.vx < b_right && distanceBetween(a_left, b_right) < distanceBetween(a_left, b_left)) { a.leftCollision = true; a.x = b.x + b.width + 3; //a.vx = 0; } } function distanceBetween(a, b) { return Math.abs(b-a); }

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