response transmitfile - Page 66

Saving ntext data from SQL Server to file directory using asp

- by April

A variety of files (pdf, images, etc.) are stored in a ntext field on a MS SQL Server. I am not sure what type is in this field, other than it shows question marks and undefined characters, I am assuming they are binary type. The script is supposed to iterate through the rows and extract and save these files to a temp directory. "filename" and "contenttype" are given, and "data" is whatever is in the ntext field. I have tried several solutions: 1) data.SaveToFile "/temp/"&filename, 2 Error: Object required: '????????????????????' ??? 2) File.WriteAllBytes "/temp/"&filename, data Error: Object required: 'File' I have no idea how to import this, or the Server for MapPath. (Cue: what a noob!) 3) Const adTypeBinary = 1 Const adSaveCreateOverWrite = 2 Dim BinaryStream Set BinaryStream = CreateObject("ADODB.Stream") BinaryStream.Type = adTypeBinary BinaryStream.Open BinaryStream.Write data BinaryStream.SaveToFile "C:\temp\" & filename, adSaveCreateOverWrite Error: Arguments are of the wrong type, are out of acceptable range, or are in conflict with one another. 4) Response.ContentType = contenttype Response.AddHeader "content-disposition","attachment;" & filename Response.BinaryWrite data response.end This works, but the file should be saving to the server instead of popping up save-as dialog. I am not sure if there is a way to save the response to file. Thanks for shedding light on any of these problems!

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How to pass value in url using web request GET method asp.net

- by Narasi

Am new to .Net and web service..i like to pass id through url..how to do that?whether it was done post or get method?guide me string url = "http://XXXXX//"+id=22; WebRequest request = WebRequest.Create(url); request.Proxy.Credentials = new NetworkCredential(xxxxx); request.Credentials = CredentialCache.DefaultCredentials; //add properties request.Method = "GET"; request.ContentType = "application/json"; //convert byte[] byteArray = Encoding.UTF8.GetBytes(data); request.ContentLength = byteArray.Length; //post data Stream streamdata = request.GetRequestStream(); streamdata.Write(byteArray, 0, byteArray.Length); streamdata.Close(); //response WebResponse response = request.GetResponse(); // Get the stream containing content returned by the server. Stream dataStream = response.GetResponseStream(); // Open the stream using a StreamReader for easy access. StreamReader reader = new StreamReader(dataStream); // Read the content. string responseFromServer = reader.ReadToEnd(); // Clean up the streams and the response. reader.Close(); response.Close(); Thanks in advance

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Django test client gets 301 redirection when accessing url

- by Michal Klich

I am writing unittests for django views. I have observed that one of my views returns redirection code 301, which is not expected. Here is my views.py mentioned earlier. def index(request): return render(request, 'index.html', {'form': QueryForm()}) def query(request): if request.is_ajax(): form = QueryForm(request.POST) return HttpResponse('valid') Below is urls.py. urlpatterns = patterns('', url(r'^$', 'core.views.index'), url(r'^query/$', 'core.views.query') ) And unittest that will fail. def so_test(self): response = self.client.post('/') self.assertEquals(response.status_code, 200) response = self.client.post('/query', {}) self.assertEquals(response.status_code, 200) My question is: why there is status 301 returned?

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This .NET code snippet will NOT actually create a cookie, right?

- by Ryan

I just realized that this cookie is not showing up like it should, and I checked the code which was not written by me but I am pretty sure that this is NOT enough to create a cookie right?? public static void CreateSSOCookies(string tokenID) { System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Domain = System.Web.HttpContext.Current.Request.ServerVariables["SERVER_NAME"].ToString().ToLower(); System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Value = tokenID.ToString(); System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Path = "~/"; System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Expires = DateTime.Now.AddDays(7); } If it does work, where is the cookie then? Is the cookie name 'ssocookies' ?

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How to print object data in javascript

- by rxzhang

I have the following object data: var response = { "response": { "numFound": 7945, "docs": [{ "description": "target", "url": "target", "id": "269653", "score": 6.9186745 }, { "description": "Target Kent", "url": "Target_Kent", "id": "37275", "score": 4.3241715 }] }, "highlighting": { "269653": { "description": ["target"] }, "37275": { "description": ["Target Kent"] } } }; I can use response.response.docs[0].description to print out "target". But I don't know how to print out "target". Thanks.

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C# Sending cookie in an HttpWebRequest which is redirected

- by Nir

I'm looking for a way to work with an API which requires login, and then redirects to another URL. The thing is that so far I've only come up with a way to make 2 Http Requests for each action I want to do: first, get cookie with AllowRedirect=false, then get the actual URI and do a second request with the cookie: HttpWebRequest request = (HttpWebRequest)WebRequest.Create(sUrl); request.AllowAutoRedirect = false; HttpWebResponse response = (HttpWebResponse)request.GetResponse(); string redirectedUrl = response.Headers["Location"]; if (!String.IsNullOrEmpty(redirectedUrl)) { redirectedUrl = "http://www.ApiUrlComesHere.com/" + redirectedUrl; HttpWebRequest authenticatedRequest = (HttpWebRequest)WebRequest.Create(redirectedUrl); authenticatedRequest.Headers["Cookie"] = response.Headers["Set-Cookie"]; response = (HttpWebResponse)request.GetResponse(); } It seems terribly inefficient. Is there another way? Thanks!

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programs hangs during socket interaction

- by herrturtur

I have two programs, sendfile.py and recvfile.py that are supposed to interact to send a file across the network. They communicate over TCP sockets. The communication is supposed to go something like this: sender =====filename=====> receiver sender <===== 'ok' ======= receiver or sender <===== 'no' ======= receiver if ok: sender ====== file ======> receiver I've got The sender and receiver code is here: Sender: import sys from jmm_sockets import * if len(sys.argv) != 4: print "Usage:", sys.argv[0], "<host> <port> <filename>" sys.exit(1) s = getClientSocket(sys.argv[1], int(sys.argv[2])) try: f = open(sys.argv[3]) except IOError, msg: print "couldn't open file" sys.exit(1) # send filename s.send(sys.argv[3]) # receive 'ok' buffer = None response = str() while 1: buffer = s.recv(1) if buffer == '': break else: response = response + buffer if response == 'ok': print 'receiver acknowledged receipt of filename' # send file s.send(f.read()) elif response == 'no': print "receiver doesn't want the file" # cleanup f.close() s.close() Receiver: from jmm_sockets import * s = getServerSocket(None, 16001) conn, addr = s.accept() buffer = None filename = str() # receive filename while 1: buffer = conn.recv(1) if buffer == '': break else: filename = filename + buffer print "sender wants to send", filename, "is that ok?" user_choice = raw_input("ok/no: ") if user_choice == 'ok': # send ok conn.send('ok') #receive file data = str() while 1: buffer = conn.recv(1) if buffer=='': break else: data = data + buffer print data else: conn.send('no') conn.close() I'm sure I'm missing something here in the sorts of a deadlock, but don't know what it is.

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Send and receive data in same ajax request with jquery

- by Pedro Esperança

What is the best way to send data and receive a response dependent on that data? Consider the php file used for the request: $test = $_POST['test']; echo json_encode($test); I have tried unsucessfully to achieve this with: $.ajax({ type: "POST", dataType: "json", data: '{test : worked}', url: 'ajax/getDude.php', success: function(response) { alert(response); } });

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xmlhttprequest responsetext coming for Accept header: text/xml , but server error for application/JS

- by encryptor

I have to get response text from a resourceindex page as JSON object. When I dont put a Accept header in the request, it shows me the xml response (i see it in an alert).. But I want the response as a JSON object.. What should I do. One solution would have been httpRequest.setRequestHeader('Accept', 'application/JSON'); but this gives me a server error :500 Also it says A message body writer for Java type, class ...., and MIME media type, application/octet-stream, was not found Can someone suggest on what to do to overcome this and get the response as JSON?

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how to hide the image? how can i do ?

- by user309381

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C++ Stack Overflow

- by PhilMAN

Here is some code: void main() { GameEngine ge("phil", "anotherguy"); string response; do { ge.playGame(); cout << endl << "Do you want to (r)eplay the same battle, (s)tart a new battle, or (q)uit? "; cin >> response; } while(response == "r" || response == "R" || response == "s" || response == "S" ); } GameEngine::GameEngine(string name1, string name2) { p1Name = name1; p2Name = name2; } void GameEngine::playGame() { cout << "PLAY GAME" << endl; Army p1, p2; Battlefield testField; RuleSet rs; int xSize = 13; // Number of rows int ySize = 13; // Number of columns loadData(p1, p2, testField, rs, xSize, ySize); ... } void GameEngine::loadData(Army& p1, Army& p2, Battlefield& testField, RuleSet& rs, int& xSize, int& ySize) { string terrain = BattlefieldUtils::pickTerrain(); string armySplit[14];//id index 1 string ruleSplit[19];//in index 7 string armyP1, armyP2, ruleSet; Skill p1Skills[8]; Skill p2Skills[8]; CreatureStack p1Stacks[20]; CreatureStack p2Stacks[20]; ... } CreatureStack(){quantity = 0; isLive = false; id = -1;}; Army(){}; Battlefield(){}; RuleSet(){}; I have posted every line of code that executes until the program crashes. This code ran fine for a long time, I added some stuff that does not even execute until way after the code I have posted here, and bam stack overflow that occurs at GameEngine::loadData() line: CreatureStack p2Stacks[20]; will not go away. What am I doing wrong here? Is that all the stack can handle? I increased the stack size in Visual Studio and got the error to go away, but that slowed things down considerably, so I would rather just get to the source of the issue and fix that.

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Can i create different observables and different corresponding observers in java?

- by mithun1538

Hello everyone, Currently, I have one observable and many observers. What i need is different observables, and depending on the observable, different observers. How do I achieve this? ( For understanding, assume I have different apples - say apple1 apple2... I have observer_1 observing apple1, observer_2 observing apple2, observer_3 observing apple 2 and so on..). I tried creating different objects of the Observable class, but since observers are observing the same class of observable, I don't know how to access a particular instance of the Observable. I have included the following servlet code that contains Observer and Observable classes: public class CustomerServlet extends HttpServlet { public String getNextMessage() { // Create a message sink to wait for a new message from the // message source. return new MessageSink().getNextMessage(source); } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ObjectOutputStream dout = new ObjectOutputStream(response.getOutputStream()); String recMSG = getNextMessage(); dout.writeObject(recMSG); dout.flush(); } public void broadcastMessage(String message) { // Send the message to all the HTTP-connected clients by giving the // message to the message source source.sendMessage(message); } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { ObjectInputStream din= new ObjectInputStream(request.getInputStream()); String message = (String)din.readObject(); ObjectOutputStream dout = new ObjectOutputStream(response.getOutputStream()); dout.writeObject("1"); dout.flush(); if (message != null) { broadcastMessage(message); } // Set the status code to indicate there will be no response response.setStatus(response.SC_NO_CONTENT); } catch (Exception e) { e.printStackTrace(); } } @Override public String getServletInfo() { return "Short description"; }// </editor-fold> MessageSource source = new MessageSource(); } class MessageSource extends Observable { public void sendMessage(String message) { setChanged(); notifyObservers(message); } } class MessageSource extends Observable { public void sendMessage(String message) { setChanged(); notifyObservers(message); } } class MessageSink implements Observer { String message = null; // set by update() and read by getNextMessage() // Called by the message source when it gets a new message synchronized public void update(Observable o, Object arg) { // Get the new message message = (String)arg; // Wake up our waiting thread notify(); } // Gets the next message sent out from the message source synchronized public String getNextMessage(MessageSource source) { // Tell source we want to be told about new messages source.addObserver(this); // Wait until our update() method receives a message while (message == null) { try { wait(); } catch (Exception e) { System.out.println("Exception has occured! ERR ERR ERR"); } } // Tell source to stop telling us about new messages source.deleteObserver(this); // Now return the message we received // But first set the message instance variable to null // so update() and getNextMessage() can be called again. String messageCopy = message; message = null; return messageCopy; } }

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Path to background in servlet

- by kapil chhattani

//the below line is the element of my HTML form which renders the image sent by the servlet written further below. <img style="margin-left:91px; margin-top:-6px;" class="image" src="http://www.abcd.com/captchaServlet"> I generate a captcha code using the following code in java. public class captchaServlet extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { int width = 150; int height = 50; int charsToPrint = 6; String elegibleChars = "ABCDEFGHJKLMPQRSTUVWXYabcdefhjkmnpqrstuvwxy1234567890"; char[] chars = elegibleChars.toCharArray(); StringBuffer finalString = new StringBuffer(); for ( int i = 0; i < charsToPrint; i++ ) { double randomValue = Math.random(); int randomIndex = (int) Math.round(randomValue * (chars.length - 1)); char characterToShow = chars[randomIndex]; finalString.append(characterToShow); } System.out.println(finalString); BufferedImage bufferedImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); Graphics2D g2d = bufferedImage.createGraphics(); Font font = new Font("Georgia", Font.BOLD, 18); g2d.setFont(font); RenderingHints rh = new RenderingHints( RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON); rh.put(RenderingHints.KEY_RENDERING, RenderingHints.VALUE_RENDER_QUALITY); g2d.setRenderingHints(rh); GradientPaint gp = new GradientPaint(0, 0, Color.BLUE, 0, height/2, Color.black, true); g2d.setPaint(gp); g2d.fillRect(0, 0, width, height); g2d.setColor(new Color(255, 255, 0)); Random r = new Random(); int index = Math.abs(r.nextInt()) % 5; char[] data=new String(finalString).toCharArray(); String captcha = String.copyValueOf(data); int x = 0; int y = 0; for (int i=0; i<data.length; i++) { x += 10 + (Math.abs(r.nextInt()) % 15); y = 20 + Math.abs(r.nextInt()) % 20; g2d.drawChars(data, i, 1, x, y); } g2d.dispose(); response.setContentType("image/png"); OutputStream os = response.getOutputStream(); ImageIO.write(bufferedImage, "png", os); os.close(); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } } But in the above code background is also generated using the setPaint menthod I am guessing. I want the background to be some image from my local machine whoz URL i should be able to mention like URL url=this.getClass().getResource("Desktop/images.jpg"); BufferedImage bufferedImage = ImageIO.read(url); I am just writing the above two lines for making the reader understand better what the issue is. Dont want to use the exact same commands. All I want is the the background of the captcha code generated should be an image of my choice.

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Access to the path Server.MapPath is denied

- by Alex

I created one pdf document var document = new Document(); string path = Server.MapPath("AttachementToMail"); PdfWriter.GetInstance(document, new FileStream(path + "/"+DateTime.Now.ToShortDateString()+".pdf", FileMode.Create)); Now I want to download this document Response.ContentType = "Application/pdf"; Response.AppendHeader("Content-Disposition", "attachment; filename="+ DateTime.Now.ToShortDateString() + ".pdf" + ""); Response.TransmitFile(path); Response.End(); but it gave me error Access to the path '~\AttachementToMail' is denied. read / write access for IIS_IUSRS exists

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How do i close a socket after a timeout in node.js?

- by rramsden

I'm trying to close a socket after a connection times out after 1000ms. I am able to set a timeout that gets triggered after a 1000ms but I can't seem to destroy the socket... any ideas? var connection = http.createClient(80, 'localhost'); var request = connection.request('GET', '/somefile.xml', {'host':'localhost'}); var start = new Date().getTime(); request.socket.setTimeout(1000); request.socket.addListener("timeout", function() { request.socket.destroy(); sys.puts("socket timeout connection closed"); }); request.addListener("response", function(response) { var responseBody = []; response.setEncoding("utf8"); response.addListener("data", function(chunk) { sys.puts(chunk); responseBody.push(chunk); }); response.addListener("end", function() { }); }); request.end(); returns socket timeout connection closed node.js:29 if (!x) throw new Error(msg || "assertion error"); ^ Error: assertion error at node.js:29:17 at Timer.callback (net:152:20) at node.js:204:9

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Best way to write an image to a Django HttpResponse()

- by k-g-f

I need to serve images securely to validated users only (i.e. they can't be served as static files). I currently have the following Python view in my Django project, but it seems inefficient. Any ideas for a better way? def secureImage(request,imagePath): response = HttpResponse(mimetype="image/png") img = Image.open(imagePath) img.save(response,'png') return response (Image is imported from PIL.)

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Python HTTPSConnection.close() does not appear to close the connection?

- by Dave

I'm not sure if this is a bug or if I'm just doing something wrong. If I were to do an HTTP connection like this: import httplib http_connection = httplib.HTTPConnection("192.168.192.196") http_connection.request("GET", "/") http_connection.sock.settimeout(20) response = http_connection.getresponse() data = response.read() http_connection.close() Then at a DOS prompt, I do this: netstat -ano | find /i "192.168.192.196:80" | find /i "ESTABLISHED" I get nothing. However, if I do the same thing, but change it to an HTTPSConnection: import httplib http_connection = httplib.HTTPSConnection("192.168.192.196") http_connection.request("GET", "/") http_connection.sock.settimeout(20) response = http_connection.getresponse() data = response.read() http_connection.close() Then do this: netstat -ano | find /i "192.168.192.196:443" | find /i "ESTABLISHED" I will actually see that the connection remains established until I actually ^Z out of the Python shell. This is happening in one of the applications I'm responsible for. Python isn't actually hanging there - it's simply leaving the connection open. Am I doing something wrong here? Do I need extra code to close the HTTPS connection? This is Python 2.6.4, btw.

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JSF: How to forward a request to another page in action?

- by Satya

I want to forward request to another page from action class I am using below code in my jsf action : public String submitUserResponse(){ ...... ...... parseResponse(uri,request,response); .... return "nextpage"; } public String parseResponse(String uri,request,response){ if(uri != null){ RequestDispatcher dispatcher = request.getRequestDispatcher(uri); dispatcher.forward(request, response); return null; } ................. .................. return "xxxx"; } "submitUserResponse" method is being called when user clicks the submit button from the jsp and this method returns "nextpage" string here request forwards to next page in normal flow. but in my requirement i will call "submitUserResponse () " which will execute and forwrd request to next page.It is going. but it is displaying some exceptions in server That is : java.lang.IllegalStateException: Cannot forward after response has been committed Here my doubts are: 1.why next lines of code is being executed after forwarding my request using dispatched.forward(uri) . Same thing happening in response.sendRedirect("").

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Facebook FB.api post how to specify a target

- by Laurent Luce

I am using FB.api OpenGraph to post a message on the user's wall. I would like the link target to be equal to '_blank' so it opens in a new tab. Is it possible ? The Facebook documentation doesn't give much details. var params = {}; params['message'] = 'message'; params['name'] = 'name'; params['link'] = 'http://link'; params['picture'] = 'http://picture'; params['description'] = 'description'; FB.api('/me/feed', 'post', params, function(response) { if (!response || response.error) { alert('Error occured'); } else { alert('Post ID: ' + response); } });

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how do i design a high pass filters in matlab without using the builtin function?

- by noura

hello everyone, i'm just not sure how to draw the frequency response (H) of the high pass filter? after drawing the frequency response i can get the b coefficient by taking the ifft of (H). so yeah, for a low pass filter, with a cutoff frequency of say pi/2 : the frequency response code will be H = exp(-1*j*w*4).*(((0 <= w) & (w<= pi/2)) | ((2*pi - pi/2 <= w) & (w<=2*pi)); sincr the response is "1" between 0 and pi/2 and between (2*pi - pi/2) and 2*pi. can you help me write H for a high pass filter? thanx in advance.

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Call an external web service from a servlet

- by pAkY88

Hi, I'm developing a servlet that gets a name of a web service and could be forward the request to an external web service, for example: "http://www.webservice.com/..." I have build a response wrapper that intercept response output but I can't forward request to an external web service, it works only if I redirect the request to a servlet that is on same server. Example: request.getRequestDispatcher("aMyServlet").forward(request, response) IT WORKS request.getRequestDispatcher("http://www.webservice.com/...").forward(request, response) IT DON'T WORKS because Tomcat search "http://www.webservice.com/..." on the server as a local resource. How can I do external request? Thanks

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Jquery .$.ajax is not working

- by Saravanan I M

I am using $.ajax for facebook invite and calling the url (Yii framework controller). The below code is not working. $.ajax is not working. function FacebookInviteFriends() { FB.ui ( { method : 'apprequests', data: '', display: 'dialog', title : 'Invite a Friend', message: 'I just sent you an invitation to play My Game.', filters: ['app_non_users'] }, function(response) { alert("start"); if (response && response.to) { alert("inside if"); $.ajax({ url: 'http://localhost:83/invitechips/createRecord', type: 'POST', data: {id : response.to} }).done(function() { alert( "Data Saved: "); }); } else { alert("inside else"); } } ); }

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Backbone.js "model" query

- by Novice coder

I'm a learning coder trying to understand this code from a sample MVC framework. The below code is from a "model" file. I've done research on Backbone.js, but I'm still confused as to exactly how this code pull information from the app's database. For example, how are base_url, Model.prototype, and Collection.prototype being used to retrieve information from the backend? Any help would be greatly appreciated. exports.definition = { config : { "defaults": { "title": "-", "description": "-" }, "adapter": { "type": "rest", "collection_name": "schools", "base_url" : "/schools/", } }, extendModel: function(Model) { _.extend(Model.prototype, { // Extend, override or implement Backbone.Model urlRoot: '/school/', name:'school', parse: function(response, options) { response.id = response._id; return response; }, }); return Model; }, extendCollection: function(Collection) { _.extend(Collection.prototype, { // Extend, override or implement Backbone.Collection urlRoot: '/schools/', name: 'schools', }); return Collection; } }

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NSPredicate aggregate function [SIZE] gives 'unsupported function expression' error

- by jinglesthula

iOS 4: I have entities in Core Data (using SQLite, which is a requirement) of: Request Response (which has a property personId) Revision Relationships are: Request <-- Revision Request <-- Response Revision <-- Response (e.g. each request may have many responses; each request/response pair may have many revisions) I'm trying to do a predicate to get all Responses with a given personId that have zero Revisions. Using: (personId == %d) && (Request.Revision[SIZE] == 0) in my predicate string gives me a runtime exception "Unsupported function expression Request.Revision[SIZE]" The documentation seems pretty sparse on aggregate functions, only noting that they exist, but with no syntax or examples. Not sure if it's my syntax or if the SIZE function really isn't supported in iOS.

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Should I HttpCombine Google Jquery Hosted File?

- by chobo2

Hi I am using something called HttpCombiner: http://code.msdn.microsoft.com/HttpCombiner An HTTP handler that combines multiple CSS, Javascript or URL into one response for faster page load. It can combine, compress and cache response which results in faster page load and better scalability of web application It's a good practice to use many small Javascript and CSS files instead of one large Javascript/CSS file for better code maintainability, but bad in terms of website performance. Although you should write your Javascript code in small files and break large CSS files into small chunks but when browser requests those javascript and css files, it makes one Http request per file. Every Http Request results in a network roundtrip form your browser to the server and the delay in reaching the server and coming back to the browser is called latency. So, if you have four javascripts and three css files loaded by a page, you are wasting time in seven network roundtrips. Within USA, latency is average 70ms. So, you waste 7x70 = 490ms, about half a second of delay. Outside USA, average latency is around 200ms. So, that means 1400ms of waiting. Browser cannot show the page properly until Css and Javascripts are fully loaded. So, the more latency you have, the slower page loads. You can reduce the wait time by using a CDN. Read my previous blog post about using CDN. However, a better solution is to deliver multiple files over one request using an HttpHandler that combines several files and delivers as one output. So, instead of putting many or tag, you just put one and one tag, and point them to the HttpHandler. You tell the handler which files to combine and it delivers those files in one response. This saves browser from making many requests and eliminates the latency. This Http Handler reads the file names defined in a configuration and combines all those files and delivers as one response. It delivers the response as gzip compressed to save bandwidth. Moreover, it generates proper cache header to cache the response in browser cache, so that, browser does not request it again on future visit. Now I am wondering since it can handle adding links should I put in it the jquery file? The reason I am not sure is if it gets combined with my other files I think I might close the advantages of it being hosted on googles servers such as caching(my thinking is if it gets combined it will look different so even if a user has it in it's cache I am not sure if it will use the one for the cahce or not). So should I combine it or only the finals that I am using locally?

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