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  • Copying specific subfolders with directory structure to a new folder

    - by Shan
    I have the following directory structure: Main_Dir | ------------------------------ Subdir1 Subdir2 Subdir3 | | | ----------- ---------- --------- | | | | | | | | | fo1 fo2 f03 fo1 fo2 f03 fo1 fo2 f03 I want to copy all the subdirectories (Subdir1, Subdir2, Subdir3) to a new folder. But how would I only copy fo1 and fo2 folders to the new place?

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  • Git autocomplete is asking for a password, not sure why

    - by Soldier.moth
    I'm running into an issue with autocomplete using git... I am using ubuntu 12.10 and when I perform the following keystrokes g i t Space Bar Tab I am presented with the error Pseudo-terminal will not be allocated because stdin is not a terminal. and prompted for a password. I am not clear how to go about troubleshooting this error, I have tried uninstalling and reinstalling git to no avail. Screenshot of terminal with error:

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  • need a different backup solution

    - by DigitalJedi
    I just built a new media/backup server using Ubuntu 12.04 64bit. I installed a hard drive to be used only for music, pictures, and videos and formatted it fat32 so my 1 and only Windows PC could map those folders as netshares. My laptop, also running Ubuntu 12.04, is what I am using the most so new media is first downloaded on my laptop. I've already got the music, videos, and pictures folders from my server mounting as shares on my laptop on boot thanks to some fstab edits and sshfs. Now I'm wanting either an app or script that could backup any new files I add to my local media folders to the mounted folders on my server. I've been Googling all day and found a few apps like rsync but they seem to have issues with ext4 to vfat backups. I thought maybe a script would be best but I'm new to scripting in Linux and don't want to mess anything up. Basically I am looking for something that will backup only newly added files to the server. I figure I could schedule it once a week. There are some stipulations. For example, my local music folder has over 700 folders for each artist/band then sub folders inside those for albums. I want something smart enough to only copy newly added content so I'm guessing the modified date would probably be a good condition if I were scripting. I'm rambling. Any suggestions would be GREATLY appreciated. I'm not finding anything to suit my needs. I'm almost to the point of just learning bas scripting so I can write something but then it will be a couple weeks or so before I have a possible solution and I'd like something in place sooner.

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  • read file in shell script

    - by moata_u
    how can i read file in shell script , then assign each line to an variable that i can use later ,,,(am thinking in way to load an default setting from file) i already try : process (){ } FILE='' read -p "Please enter name of default file : " FILE if [ ! -f $FILE ]; then echo "$FILE : does not exists " exit 1 elif [ ! -r $FILE ]; then echo "$FILE : can not read " fi exec 0<"$FILE" n=0 while read -r line do (assign each line to an variable) done

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  • ssh:connection timed out

    - by user1155299
    I am trying the following command on ubuntu ssh [email protected] and I get the following error: ssh: connect to host xx.xx.xxx.xxx port 22: Connection timed out so, I tried the following: telnet xx.xx.xxx.xxx 22xx and I got the following message: Trying xx.xx.xxx.xxx... Connected to xx.xx.xxx.xxx. Escape character is '^]'. SSH-2.0-OpenSSH_5.5 Connection closed by foreign host. Can anyone help me understand what the problem is and how I can fix it.

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  • How to join two command output

    - by UAdapter
    for example I have command that shows how much space folder takes du folder | sort -n it works great, however I would like to have human readable form du -h folder however if I do that than I cannot sort it as numeric. How to join "du folder" and "du -h folder" to see output sorted as "du folder", but with first column from "du -h folder" P.S. this is just an example. this technique might be very useful for me (if its possible)

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  • echo difference between ubuntu and RedHat

    - by arcomber
    I have mostly been experimenting with ubuntu but recently was using a Red Hat Enterprise system and was surprised at a difference I found setting and displaying env variables. In ubuntu I might have an interaction like this: acomber@mail:~$ export MY_VAR=i686-linux acomber@mail:~$ echo $MY_VAR i686-linux acomber@mail:~$ echo "$MY_VAR" i686-linux But on RHEL: acomber@mail:~$ export MY_VAR=i686-linux acomber@mail:~$ echo $MY_VAR acomber@mail:~$ echo "$MY_VAR" i686-linux I know this is a ubuntu forum but why the difference? Why do I need to enclose in quotes on RH? There are no spaces in the variable name?

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  • With a username passed to a script, find the user's home directory

    - by Clinton Blackmore
    I am writing a script that gets called when a user logs in and check if a certain folder exists or is a broken symlink. (This is on a Mac OS X system, but the question is purely bash). It is not elegant, and it is not working, but right now it looks like this: #!/bin/bash # Often users have a messed up cache folder -- one that was redirected # but now is just a broken symlink. This script checks to see if # the cache folder is all right, and if not, deletes it # so that the system can recreate it. USERNAME=$3 if [ "$USERNAME" == "" ] ; then echo "This script must be run at login!" >&2 exit 1 fi DIR="~$USERNAME/Library/Caches" cd $DIR || rm $DIR && echo "Removed misdirected Cache folder" && exit 0 echo "Cache folder was fine." The crux of the problem is that the tilde expansion is not working as I'd like. Let us say that I have a user named george, and that his home folder is /a/path/to/georges_home. If, at a shell, I type: cd ~george it takes me to the appropriate directory. If I type: HOME_DIR=~george echo $HOME_DIR It gives me: /a/path/to/georges_home However, if I try to use a variable, it does not work: USERNAME="george" cd ~$USERNAME -bash: cd: ~george: No such file or directory I've tried using quotes and backticks, but can't figure out how to make it expand properly. How do I make this work?

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  • Are my Linux symbolic links acting correctly?

    - by Andy Castles
    Hi all I've been using Linux on and off for the last 15 years and today I came across something in bash that surprised me. Setup the following directory structure: $ cd /tmp $ mkdir /tmp/symlinktest $ mkdir /tmp/symlinktest/dir $ mkdir /tmp/symlinktarget Now create two sym links in symlinktest pointing to symlinktarget: $ cd /tmp/symlinktest $ ln -s ../symlinktarget Asym $ ln -s ../symlinktarget Bsym Now, in bash, the following tab completion does strange things. Type the following: $ cd dir $ cd ../A[TAB] Pressing the tab key above completes the line to: $ cd ../Asym/ as I expected. Now press enter to change into Asym and type: $ cd ../B[TAB] This time pressing the tab key completes the link to: $ cd ../Bsym[space] Note that there is now a space after the Bsym and there is no trailing slash. My question is, why when changing from the physical directory "dir" to Asym it recognises that Asym is a link to a directory, but when changing from one sym link to another, it doesn't recognise that it's a link to a directory? In addition, if I try to create a new file within Asym, I get an error message: $ cd /tmp/symlinktest/Asym $ cat hello > ../Bsym/file.txt -bash: ../Bsym/file.txt: No such file or directory I always thought that symlinks were mostly transparent except to programs that need to manipulate them. Is this normal behaviour? Many thanks, Andy

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  • Vim clobbering scrollback buffer outside of screen

    - by dotancohen
    If I'm not in a screen session, then when exiting Vim I get a bash prompt below the remnants of the VIM window. A side effect of this is that my scrollback buffer is clobbered, especially if I have paged through a long file in VIM. The problem only occurs if I'm not in screen, inside a screen window VIM exits to show the bash prompt and the previous lines just as before. I tried adding sett_ti=t_te= to my .vimrc to fix the problem, but the only effect that it has was to break VIM such that the problem occurs inside screen as well as outside. Thus, I removed the line. For good measure I do have altscreen on in .screenrc. This is on Ubuntu Server 12.04.1 LTS, with Bash 4.2.24, Screen 4.00, and VIM 7.3 (not vim-tiny), accessed over SSH in Cygwin version NT-6.1-WOW64 on a Windows 7 laptop. Thanks. EDIT: Note that in the same Cygwin install I can SSH into a different server (CentOS) and there VIM does not clobber the scrollback buffer. Therefore, I do not suspect a Cygwin issue. The CentOS machine does not have screen installed, and I did not have to add set t_ti= t_te= to .vimrc.

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  • Symlink path can be followed manually, but `cd` returns Permission denied

    - by Ricket
    I am trying to access the directory /usr/software/test/agnostic. There are several symlinks involved in this path. As you can see by the below transcript, I am unable to cd directly to the path, but I can check each step of the way and cd to the symlinked directories until I reach the destination. Why is this? (and how do I fix it?) Ubuntu 12.10, bash > ls /usr/software/test/agnostic ls: cannot access /usr/software/test/agnostic: Permission denied > cd /usr/software/test > cd agnostic bash: cd: agnostic: Permission denied > pwd -P /x/eng/localtest/arch/x86_64-redhat-rhel5 > ls -al | grep agnostic lrwxrwxrwx 1 root root 15 Oct 23 2007 agnostic -> noarch/agnostic > ls -al | grep noarch ... lrwxrwxrwx 1 root root 23 Oct 23 2007 noarch -> /x/eng/localtest/noarch > cd noarch > cd agnostic bash: cd: agnostic: Permission denied > ls -al | grep agnostic lrwxrwxrwx 1 5808 dip 4 Oct 5 2010 agnostic -> main > cd main > ls (correct output of `ls`) > pwd /usr/software/test/noarch/main > pwd -P /x/eng/localtest/noarch/main

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  • Using jQuery Live instead of jQuery Hover function

    - by hajan
    Let’s say we have a case where we need to create mouseover / mouseout functionality for a list which will be dynamically filled with data on client-side. We can use jQuery hover function, which handles the mouseover and mouseout events with two functions. See the following example: <!DOCTYPE html> <html lang="en"> <head id="Head1" runat="server">     <title>jQuery Mouseover / Mouseout Demo</title>     <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jquery/jquery-1.4.4.js"></script>     <style type="text/css">         .hover { color:Red; cursor:pointer;}     </style>     <script type="text/javascript">         $(function () {             $("li").hover(               function () {                   $(this).addClass("hover");               },               function () {                   $(this).removeClass("hover");               });         });     </script> </head> <body>     <form id="form2" runat="server">     <ul>         <li>Data 1</li>         <li>Data 2</li>         <li>Data 3</li>         <li>Data 4</li>         <li>Data 5</li>         <li>Data 6</li>     </ul>     </form> </body> </html> Now, if you have situation where you want to add new data dynamically... Lets say you have a button to add new item in the list. Add the following code right bellow the </ul> tag <input type="text" id="txtItem" /> <input type="button" id="addNewItem" value="Add New Item" /> And add the following button click functionality: //button add new item functionality $("#addNewItem").click(function (event) {     event.preventDefault();     $("<li>" + $("#txtItem").val() + "</li>").appendTo("ul"); }); The mouse over effect won't work for the newly added items. Therefore, we need to use live or delegate function. These both do the same job. The main difference is that for some cases delegate is considered a bit faster, and can be used in chaining. In our case, we can use both. I will use live function. $("li").live("mouseover mouseout",   function (event) {       if (event.type == "mouseover") $(this).addClass("hover");       else $(this).removeClass("hover");   }); The complete code is: <!DOCTYPE html> <html lang="en"> <head id="Head1" runat="server">     <title>jQuery Mouseover / Mouseout Demo</title>     <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jquery/jquery-1.4.4.js"></script>     <style type="text/css">         .hover { color:Red; cursor:pointer;}     </style>     <script type="text/javascript">         $(function () {             $("li").live("mouseover mouseout",               function (event) {                   if (event.type == "mouseover") $(this).addClass("hover");                   else $(this).removeClass("hover");               });             //button add new item functionality             $("#addNewItem").click(function (event) {                 event.preventDefault();                 $("<li>" + $("#txtItem").val() + "</li>").appendTo("ul");             });         });     </script> </head> <body>     <form id="form2" runat="server">     <ul>         <li>Data 1</li>         <li>Data 2</li>         <li>Data 3</li>         <li>Data 4</li>         <li>Data 5</li>         <li>Data 6</li>     </ul>          <input type="text" id="txtItem" />     <input type="button" id="addNewItem" value="Add New Item" />     </form> </body> </html> So, basically when replacing hover with live, you see we use the mouseover and mouseout names for both events. Check the working demo which is available HERE. Hope this was useful blog for you. Hope it’s helpful. HajanReference blog: http://codeasp.net/blogs/hajan/microsoft-net/1260/using-jquery-live-instead-of-jquery-hover-function

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  • Ruby through RVM fails

    - by TheLQ
    In constant battle to install Ruby 1.9.2 on an RPM system (OS is based off of CentOS), I'm trying again with RVM. So once I install it, I then try to use it: [root@quackwall ~]# rvm use 1.9.2 Using /usr/local/rvm/gems/ruby-1.9.2-p136 [root@quackwall ~]# ruby bash: ruby: command not found [root@quackwall ~]# which ruby /usr/bin/which: no ruby in (/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/root/bin) Now that's interesting; rvm info says something completely different: [root@quackwall bin]# rvm info ruby-1.9.2-p136: system: uname: "Linux quackwall.highwow.lan 2.6.18-194.8.1.v5 #1 SMP Thu Jul 15 01:14:04 EDT 2010 i686 i686 i386 GNU/Linux" bash: "/bin/bash => GNU bash, version 3.2.25(1)-release (i686-redhat-linux-gnu)" zsh: " => not installed" rvm: version: "rvm 1.2.2 by Wayne E. Seguin ([email protected]) [http://rvm.beginrescueend.com/]" ruby: interpreter: "ruby" version: "1.9.2p136" date: "2010-12-25" platform: "i686-linux" patchlevel: "2010-12-25 revision 30365" full_version: "ruby 1.9.2p136 (2010-12-25 revision 30365) [i686-linux]" homes: gem: "/usr/local/rvm/gems/ruby-1.9.2-p136" ruby: "/usr/local/rvm/rubies/ruby-1.9.2-p136" binaries: ruby: "/usr/local/rvm/rubies/ruby-1.9.2-p136/bin/ruby" irb: "/usr/local/rvm/rubies/ruby-1.9.2-p136/bin/irb" gem: "/usr/local/rvm/rubies/ruby-1.9.2-p136/bin/gem" rake: "/usr/local/rvm/gems/ruby-1.9.2-p136/bin/rake" environment: PATH: "/usr/local/rvm/gems/ruby-1.9.2-p136/bin:/usr/local/rvm/gems/ruby-1.9.2-p136@global/bin:/usr/local/rvm/rubies/ruby-1.9.2-p136/bin:bin:/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/root/bin:/usr/local/rvm/bin" GEM_HOME: "/usr/local/rvm/gems/ruby-1.9.2-p136" GEM_PATH: "/usr/local/rvm/gems/ruby-1.9.2-p136:/usr/local/rvm/gems/ruby-1.9.2-p136@global" MY_RUBY_HOME: "/usr/local/rvm/rubies/ruby-1.9.2-p136" IRBRC: "/usr/local/rvm/rubies/ruby-1.9.2-p136/.irbrc" RUBYOPT: "" gemset: "" So I have RVM that says one thing and bash which says another. Any suggestions on how to get this working?

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  • Externally disabling signals for a Linux program.

    - by Harry
    Hello, On Linux, is it possible to somehow disable signaling for programs externally... that is, without modifying their source code? Context: I'm calling a C (and also a Java) program from within a bash script on Linux. I don't want any interruptions for my bash script, and for the other programs that the script launches (as foreground processes). While I can use a... trap '' INT ... in my bash script to disable the Ctrl C signal, this works only when the program control happens to be in the bash code. That is, if I press Ctrl C while the C program is running, the C program gets interrupted and it exits! This C program is doing some critical operation because of which I don't want it be interrupted. I don't have access to the source code of this C program, so signal handling inside the C program is out of question. #!/bin/bash trap 'echo You pressed Ctrl C' INT # A C program to emulate a real-world, long-running program, # which I don't want to be interrupted, and for which I # don't have the source code! # # File: y.c # To build: gcc -o y y.c # # #include <stdio.h> # int main(int argc, char *argv[]) { # printf("Performing a critical operation...\n"); # for(;;); // Do nothing forever. # printf("Performing a critical operation... done.\n"); # } ./y Regards, /HS

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  • How to run bash script from windows using plink on linux

    - by user128877
    I'm trying to run a simple bat file from windows that will run a bash script on linux machine. The bash script is located on the linux machine. For example: I'm trying to run this bat file from windows plink.exe -pw <password> root@<ip> bash -c "/root/script.sh" Result: When running from windows the cmd is stuck forever when running the specific script (/root/script.sh) from the linux machine it's working just fine. The script contain ruby code and I'm using RVM

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  • have a bash script remotely shutdown another computer on the lan

    - by gletscher
    Hi I want to write a bash script that when called shuts down another computer on the lan. Maybe using ssh? The other computer is an ubuntu machine. Now I'm not sure how to send e.g. a sudo shutdown -h now command from withing a bash script to the ssh after logging in. Also I'm not sure how to obtain the rights for the sudo command, hence how to handle the communication between the server and client from within a bash script. Any suggestions are greatly appreciated.

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  • Windows CMD, show the current folder name at prompt dynamically like Bash

    - by guneysus
    I am trying to modify my CMD, to show only current dir name dynamically like: Desktop $ When i switched the folder, it must be updated. It is not required to be code in purely batch file, it may depend any external commands, cygwin bash, etc. @echo off set a=bash -c "pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'" %a% cmd outputs _test-et Microsoft Windows [Version 6.3.9600] (c) 2013 Microsoft Corporation. Tüm haklari saklidir. >> But >> prompt %a% gives bash -c "pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'"

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  • Fortran 90 How to call a function in a subroutine in a module?

    - by Feynman
    I have a module that "contains" a subroutine that "contains" a function. I say "use themodule" in my main program and I can "call thesubroutine", but how to I get the function that is "contained" in the subroutine? The code looks like this: module useful integer, parameter :: N=2 double precision, parameter :: xmin=1, xmax=10, pi=3.1415926535898 double complex :: green(N,N), solution(N), k=(2.0,0.0) contains subroutine y(n1) contains function x(n1) real :: n1, x x=n1*(xmax-xmin)/N end function x end subroutine y end module useful

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  • Mathematica: get number of arguments passed to a function?

    - by dbjohn
    How do I get the number of arguments passed to a function, such as Plus[2,3,4,5] has 4 arguments passed to it. I was thinking it may involve the use of the function Length and getting the arguments into a list. The intention is to iterate an operation based on the number of arguments for a function. There is probably a simple solution or function but I haven't come across it yet. Any other ways or suggestions are welcome as well?

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  • SQL SERVER – 2012 – Summary of All the Analytic Functions – MSDN and SQLAuthority

    - by pinaldave
    SQL Server 2012 (RC0 Available here) has introduced new analytic functions. These functions were long awaited and I am glad that they are here. Previously when any of this function was needed people use to write long T-SQL code to simulate that and now no need of the same. Having available native function also helps performance as well readability. In last few days I have written many articles on this subject on my blog. The goal was make these complex analytic functions easy to understand and make it widely accepted. As this new functions are available and as awareness spreads we should start using the new functions. Here is the quick list of the new function and relevant MSDN site. Function SQLAuthority MSDN CUME_DIST CUME_DIST CUME_DIST FIRST_VALUE FIRST_VALUE FIRST_VALUE LAST_VALUE LAST_VALUE LAST_VALUE LEAD LEAD LEAD LAG LAG LAG PERCENTILE_CONT PERCENTILE_CONT PERCENTILE_CONT PERCENTILE_DISC PERCENTILE_DISC PERCENTILE_DISC PERCENT_RANK PERCENT_RANK PERCENT_RANK I also enjoyed three different puzzles during the course of this series which gave clear idea to the SQL Server 2012 analytic functions. SQL SERVER – Puzzle to Win Print Book – Functions FIRST_VALUE and LAST_VALUE with OVER clause and ORDER BY SQL SERVER – Puzzle to Win Print Book – Write T-SQL Self Join Without Using LEAD and LAG SQL SERVER – Puzzle to Win Print Book – Explain Value of PERCENTILE_CONT() Using Simple Example This series will be always my dear series as during this series I had went through very unique experience of my book going out of stock and becoming available after 48 hours. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – Introduction to CUME_DIST – Analytic Functions Introduced in SQL Server 2012

    - by pinaldave
    This blog post is written in response to the T-SQL Tuesday post of Prox ‘n’ Funx. This is a very interesting subject. By the way Brad Schulz is my favorite guy when it is about blogging. I respect him as well learn a lot from him. Everybody is writing something new his subject, I decided to start SQL Server 2012 analytic functions series. SQL Server 2012 introduces new analytical function CUME_DIST(). This function provides cumulative distribution value. It will be very difficult to explain this in words so I will attempt small example to explain you this function. Instead of creating new table, I will be using AdventureWorks sample database as most of the developer uses that for experiment. Let us fun following query. USE AdventureWorks GO SELECT SalesOrderID, OrderQty, CUME_DIST() OVER(ORDER BY SalesOrderID) AS CDist FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY CDist DESC GO Above query will give us following result. Now let us understand what is the formula behind CUME_DIST and why the values in SalesOrderID = 43670 are 1. Let us take more example and be clear about why the values in SalesOrderID = 43667 are 0.5. Now let us enhence the same example and use PARTITION BY into the OVER clause and see the results. Run following query in SQL Server 2012. USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, CUME_DIST() OVER(PARTITION BY SalesOrderID ORDER BY ProductID ) AS CDist FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID DESC, CDist DESC GO Now let us see the result of this query. We are have changed the ORDER BY clause as well partitioning by SalesOrderID. You can see that CUME_DIST() function provides us different results. Additionally now we see value 1 multiple times. As we are using partitioning for each group of SalesOrderID we get the CUME_DIST() value. CUME_DIST() was long awaited Analytical function and I am glad to see it in SQL Server 2012. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Have loaded a php variable into flash but cant apply it in a function...

    - by Paul Elliot
    hi I have created an actionscript function which stops an animation on a specific frame which works fine. I have then loaded in a php file with a variable which will contain the number for the frame i want the animation to stop on. This has loaded in fine and i have loaded it in a function. what i cant seem to do is to get the variable into the function which tells the animation to stop playing. here is my code: //load variables varReceiver = new LoadVars(); // create an object to store the variables varReceiver.load("http://playground.nsdesign6.net/percentage/external.php"); //load variables //function1 varReceiver.onLoad = function() { //value is the var that is created. var paul = this.percentage; } //function1 //function2 this.onEnterFrame = function() { if(this._currentframe==(percentage)) { this.stop(); this.onEnterFrame = undefined; } } play(); //function2 cheers paul

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  • Delay function from running for n seconds then run it once. (2minute question)

    - by Ozaki
    TLDR I have a function that runs on the end of a pan in an openlayers map. Don't want it to fire continously. I have a function that runs on the end of panning a map. I want it so that it will not fire the function until say 3 secconds after the pan has finished. Although I don't want to queue up the function to fire 10 or so times like setTimeout is currently doing. How can I delay a function from running for n seconds then run it only once no matter how many times it has been called?

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