Search Results

Search found 6375 results on 255 pages for 'colon syntax'.

Page 67/255 | < Previous Page | 63 64 65 66 67 68 69 70 71 72 73 74  | Next Page >

  • Updating PHP on Linux - "No Packages marked for Update"?

    - by Aristotle
    I'm very new to server-administration, but I was thinking the task of updating PHP to 5.2+ should be relatively simple. Online I found that the following was allegedly sufficient to do this: yum update php But when I run this, the following is output: [root@ip-XXX-XXX-XXX-XXX /]# php -v PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) Copyright (c) 1997-2006 The PHP Group Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technologies [root@ip-XXX-XXX-XXX-XXX /]# yum update php Loaded plugins: fastestmirror Determining fastest mirrors * addons: p3plmirror02.prod.phx3.secureserver.net * base: p3plmirror02.prod.phx3.secureserver.net * extras: p3plmirror02.prod.phx3.secureserver.net * turbopanel-base: p3plmirror02.prod.phx3.secureserver.net * turbopanel-centos5: p3plmirror02.prod.phx3.secureserver.net * update: p3plmirror02.prod.phx3.secureserver.net addons | 951 B 00:00 addons/primary | 201 B 00:00 base | 2.1 kB 00:00 base/primary_db | 1.6 MB 00:00 extras | 1.1 kB 00:00 extras/primary | 107 kB 00:00 extras 325/325 turbopanel-base | 951 B 00:00 turbopanel-base/primary | 72 kB 00:00 turbopanel-base 494/494 turbopanel-centos5 | 951 B 00:00 turbopanel-centos5/primary | 2.1 kB 00:00 turbopanel-centos5 8/8 update | 1.9 kB 00:00 update/primary_db | 463 kB 00:00 Setting up Update Process No Packages marked for Update [root@ip-XXX-XXX-XXX-XXX /]# php -v PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) Copyright (c) 1997-2006 The PHP Group Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technolog [root@ip-XXX-XXX-XXX-XXX /]# No Packages marked for Update [root@ip-XXX-XXX-XXX-XXX /]# php -v bash: No: command not found [root@ip-XXX-XXX-XXX-XXX /]# [root@ip-XXX-XXX-XXX-XXX /]# php -v bash: [root@ip-XXX-XXX-XXX-XXX: command not found [root@ip-XXX-XXX-XXX-XXX /]# PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) bash: syntax error near unexpected token `(' [root@ip-XXX-XXX-XXX-XXX /]# Copyright (c) 1997-2006 The PHP Group bash: syntax error near unexpected token `c' [root@ip-XXX-XXX-XXX-XXX /]# Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technologies bash: syntax error near unexpected token `(' [root@ip-XXX-XXX-XXX-XXX /]# My PHP version is 5.1.6 before, and after running the command. Am I being too naive here with this update process? Is there a more verbose route that is necessary for me to take?

    Read the article

  • Is there any functional-like unix shell?

    - by Caruccio
    I'm (really) newbie to functional programming (in fact only had contact with it using python) but seems to be a good approach for some list-intensive tasks in a shell environment. I'd love to do something like this: $ [ git clone $host/$repo for repo in repo1 repo2 repo3 ] Is there any Unix shell with these kind of feature? Or maybe some feature to allow easy shell access (commands, env/vars, readline, etc...) from within python (the idea is to use python's interactive interpreter as a replacement to bash). EDIT: Maybe a comparative example would clarify. Let's say I have a list composed of dir/file: $ FILES=( build/project.rpm build/project.src.rpm ) And I want to do a really simple task: copy all files to dist/ AND install it in the system (it's part of a build process): Using bash: $ cp ${files[*]} dist/ $ cd dist && rpm -Uvh $(for f in ${files[*]}; do basename $f; done)) Using a "pythonic shell" approach (caution: this is imaginary code): $ cp [ os.path.join('dist', os.path.basename(file)) for file in FILES ] 'dist' Can you see the difference ? THAT is what i'm talking about. How can not exits a shell with these kind of stuff build-in yet? It's a real pain to handle lists in shell, even its being a so common task: list of files, list of PIDs, list of everything. And a really, really, important point: using syntax/tools/features everybody already knows: sh and python. IPython seams to be on a good direction, but it's bloated: if var name starts with '$', it does this, if '$$' it does that. It's syntax is not "natural", so many rules and "workarounds" ([ ln.upper() for ln in !ls ] -- syntax error)

    Read the article

  • Escaping colons in hibernate createSQLQuery

    - by Stratosgear
    I am confused on how I can create an SQL statement containing colons. I am trying to create a view and I am using (notice the double colons): create view MyView as ( SELECT tableA.colA as colA, tableB.colB as colB, round(tableB.colD / 1024)::numeric, 2) as calcValue, FROM tableA, tableB WHERE tableA.colC = 'someValue' ); This is a postgres query and I am forced to use the double colons (::) in order to correctly run the statement. I then pass the above statement through: s.createSQLQuery(myQuery).executeUpdate(); and I get a: Exception in thread "main" org.hibernate.exception.DataException: \ could not execute native bulk manipulation query at org.hibernate.exception.SQLStateConverter.convert(\ SQLStateConverter.java:102) ... more stacktrace... with an output of my above statement changed as (notice the question mark): create view MyView as ( SELECT tableA.colA as colA, tableB.colB as colB, round(tableB.colD / 1024)?, 2) as calcValue, FROM tableA, tableB WHERE tableA.colC = 'someValue' ); Obviously, hibernate confuses my colons with named parameters. Is there a way to escape the colons (a google suggestion that mentions that a single colon is escaped as a double colon does NOT work) or another way of running this statement? Thanks.

    Read the article

  • What's wrong with my MySql query ?!

    - by Anytime
    This is a query I am doing with mysql using PHP This is the query line <?php $query = "SELECT * FROM node WHERE type = 'student_report' AND uid = '{$uid}' LIMIT 1 ORDER BY created DESC"; ?> I get the following error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ORDER BY created DESC' at line 1

    Read the article

  • How to add a default value to an already existing column?

    - by Earlz
    I have an existing column in my SQL Server database. I have tried about everything I can think of but can not get a default value to be added to the column. What works in every other database is alter table mytable alter column mycolumn set default(now()) --mycolumn is a datetime How do I do this in SQL Server? The error I get for that exact syntax is incorrect syntax near the keyword 'set'

    Read the article

  • busybox shell refuses to execute the particular line of script

    - by neil1234
    Hi, I am using busybox shell to execute a script which the bash executes when i boot linux using the nfs. Please let me know the correct alternative for this line. cur_major=$((0x`stat -c %t $dev 2>/dev/null`)) The busybox throws in an error saying "0x" syntax error, which i understand is the problem with the syntax of this line. Thanks in advance

    Read the article

  • Executing procedural queries in perl

    - by KalpaG
    I have a query like this set @valid_total:=0; set @invalid_total:=0; select week as weekno, measured_week,project_id as project, role_category_id as role_category, valid_count,valid_tickets, (@valid_total := @valid_total + valid_count) as valid_total, invalid_count,invalid_tickets, (@invalid_total := @invalid_total + invalid_count) as invalid_total from metric_fault_bug_project where measured_week = yearweek(curdate()) and role_category_id = 1 and project_id = 11; it executes fine in heidi (MySQL client) but when it comes to perl, it gives me this error DBD::mysql::st execute failed: You have an error in your SQL syntax; check the m anual that corresponds to your MySQL server version for the right syntax to use near ':=0; set :=0; select week as weekno, measured_week,project_id as project' at line 1 at D:\Mx\scripts\test.pl line 35. Can't execute SQL statement: You have an error in your SQL syntax; check the man ual that corresponds to your MySQL server version for the right syntax to use ne ar ':=0; set :=0; select week as weekno, measured_week,project_id as project' at line 1 The problem seem to be in the set @valid_total := 0; line. I am fairly new to Perl. Can anyone help? this is the complete perl code #!/usr/bin/perl #use lib '/x01/home/kalpag/libs'; use DBI; use strict; use warnings; my $sid = 'issues'; my $user = 'root'; my $passwd = 'kalpa'; my $connection = "DBI:mysql:database=$sid;host=localhost"; my $dbhh = DBI->connect( $connection, $user, $passwd) || die "Database connection not made: $DBI::errstr"; my $sql_query = 'set @valid_total:=0; set @invalid_total:=0; select week as weekno, measured_week,project_id, role_category_id as role_category, valid_count,valid_tickets, (@valid_total := @valid_total + valid_count) as valid_total, invalid_count,invalid_tickets, (@invalid_total := @invalid_total + invalid_count) as invalid_total from metric_fault_bug_project where measured_week = yearweek(curdate()) and role_category_id = 1 and project_id = 11'; my $sth = $dbhh->prepare($sql_query) or die "Can't prepare SQL statement: $DBI::errstr\n"; $sth->execute() or die "Can't execute SQL statement: $DBI::errstr\n"; while ( my @memory = $sth->fetchrow() ) { print "@memory \n"; }

    Read the article

  • MySQL query from subquery not working

    - by James Goodwin
    I am trying to return a number based on the count of results from a table and to avoid having to count the results twice in the IF statement I am using a subquery. However I get a syntax error when trying to run the query, the subquery I have tested by itself runs fine. Any ideas what is wrong with the query? The syntax looks correct to me SELECT IF(daily_count>8000,0,IF(daily_count>6000,1,2)) FROM ( SELECT count(*) as daily_count FROM orders201003 WHERE DATE_FORMAT(date_sub(curdate(), INTERVAL 1 DAY),"%d-%m-%y") = DATE_FORMAT(reqDate,"%d-%m-%y") ) q

    Read the article

  • Brackets around Stored Procedure in ADODB Command Text

    - by KennerL90
    Help me understand why this is happening! I use the ADODB.Command object. The Command Text is set to the Stored Procedure Name. Sometimes, if I DON'T add brackets around the stored procedure name, I get a Syntax Error or Access Violation error. Sometimes, if I DO add brackets around the stored procedure name, I get a Syntax Error or Access Violation error.

    Read the article

  • problem importing data into older mysql version

    - by conandor
    I dump data from MySQL version 5.1.30 from server 1 # mysqldump mydb1 > mydb1.sql Then I import it to server 2 which have MySQL version 5.1.24-rc However I got an error important halfway. # mysql mydb1 < mydb1.sql ERROR 1064 (42000) at line 1984: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''9012345678' at line 1 Any idea how I can solve it?

    Read the article

  • PHP object access using string

    - by Rob Waring
    Hi all, I have an object in PHP with some very odd property names. I just need to know how to access a property when it's name is "//www.w3.org/1999/02/22-rdf-syntax-ns#type". I found something that suggested $object->{'//www.w3.org/1999/02/22-rdf-syntax-ns#type'}; but that doesn't seem to work. Thanks in advance Rob

    Read the article

  • Toplink Exception, whats wrong?

    - by java_dude
    Hey, I've got an excpetion when I generate this EJB SQL Statement. Exception Description: Syntax error parsing the query [SELECT h FROM Busmodul h WHERE LOWER(h.modulNummer) LIKE :modulnummer AND h.einbauort.id = :einbauort_fk AND h.plattform.id = :plattform_fk ORDER BY TRIM(TRAILING '-' FROM CONCAT('0', h.modulNummer))], line 1, column 150: syntax error at [TRIM]. Internal Exception: line 1:150: expecting IDENT, found 'TRIM' Whats the meaning of IDENT. Any Ideas what I am doing wrong? Regards

    Read the article

  • Does REGEX differ from PHP to Python

    - by daemonfire300
    hi there, I found this post: http://stackoverflow.com/questions/118143/python-regex-vs-php-regex but I actually did not get if Python's REGEX syntax matches PHP's REGEX syntax. I started to convert some of my old PHP code to python (due to g's appengine etc.), and now I would like to know whether the regex is 100% convertable, by simple copy & paste. regards,

    Read the article

  • MySQL & PHP Parameter 1 as Resource

    - by Nik
    Alright, PHP is throwing this error at me (in the log) when I run the code mentioned below: Error mysql_num_rows() expects parameter 1 to be resource, string given in (place) on line 10 Line 9-11 $queryFP = ("SELECT * FROM db"); $countFP = mysql_num_rows($queryFP); $aID = rand(1, $countFP); I think it has something to do with the $queryFP's syntax, but I'm not completely sure how to fix it since $queryFP's syntax is the simplest query I've ever seen.

    Read the article

  • Destructuring assignment problem

    - by Eli Grey
    Why does for ([] in iterable); work fine but [void 0 for ([] in iterable)] throw a syntax error for invalid left-hand assignment? For example, I would expect the following code to work, but it doesn't (the assertion isn't even done due to the syntax error): let (i = 0, iterable = (i for (i in [1, 2, 3, 4]))) { for ([] in iterable) i++; console.assertNotGreater([void 0 for ([] in iterable)].length, i); }

    Read the article

  • Sending confirmation SMS automatically

    - by agentxy
    I hope this gets a response. Say Person A sends an SMS to a shortcode in a certain syntax. How could a confirmation SMS be sent to Person A's mobile phone automatically ("Your message has been received successfully!"), after determining that the SMS received from Person A is in the correct syntax? I'm a total newbie when it comes to SMS - so if anyone could describe the entire end-to-end process/architecture that could make this happen, I'd be grateful!

    Read the article

  • BULK INSERT problem in mysql

    - by kartiku
    Hi, I get an error with the following sql command for bulk insert....any help would be appreciated. BULK INSERT libra.faculty FROM 'd\:faculty.csv' WITH ( FIELDTERMINATOR = ',', ROWTERMINATOR = '\n' ); Here's the error message ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'BULK INSERT libra.faculty FROM 'd:\faculty.csv' WITH ( FIELDTERMINATOR = ',', RO' at line 1

    Read the article

  • Subfolders in py2exe

    - by rajat
    I would like to add subfolders while creating the python script using py2exe.. The syntax I have used is -- setup(windows = [{"script":"test.py"}],data_files= [('Folder A', [('Subfolder B' ,[os.path.join('Folder A','XYZ.py')] )] )] ) What will be the correct syntax for creating a folder A, a subfolder B which includes file XYZ??

    Read the article

  • How do I create a strongly typed BeginForm?

    - by itchi
    I've seen a few examples of people using this syntax for HTML.BeginForm: (Html.BeginForm<Type>(action => action.ActionName(id))) But when I try this syntax all I get is a: The non-generic method System.Web.Mvc.Html.FormExtensions.BeginForm(System.Web.Mvc.HtmlHelper)' cannot be used with type arguments What am I missing?

    Read the article

  • mysql real escape string error

    - by user547995
    Code mysql_query("INSERT INTO Account(User, Pw, email) VALUES('mysql_real_escape_string($_POST[user])', '$pw','mysql_real_escape_string($_POST[email]) ) ") or die(mysql_error()); Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''mysql_real_escape_string(123) )' at line 1 Please help

    Read the article

  • How to create nonclustered index in Create Table.

    - by isthatacode
    Create table FavoriteDish ( FavID int identity (1,1) primary key not null, DishID int references Dishes(DishID) not null , CelebrityName nvarchar(100) nonclustered not null ) This results in - Incorrect syntax near the keyword 'nonclustered'. I referred the MSDN help for create table syntax. I am not sure whats wrong here? Thanks for reading.

    Read the article

  • how do I update the date type column?

    - by Muhammad Hammad
    update answers a1 set a1.FilingDate=( select date_sub( a2.FilingDate ,Interval 1000 Year) as FilingDate from answers a2 where Year(a2.FilingDate)>=3000 ) where Year(a1.FilingDate)>=3000 but it gives me the following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'update answers a1 set a1.FilingDate=( select date_sub(a2.FilingDate,Interval 10' at line 1 Can anyone tell me about the issue and its solution?

    Read the article

  • I get an error when implementing tde in SQL Server 2008

    - by mahima
    While using USE mssqltips_tde; CREATE DATABASE ENCRYPTION KEY with ALGORITHM = AES_256 ENCRYPTION BY SERVER CERTIFICATE TDECert GO I'm getting an error Msg 156, Level 15, State 1, Line 2 Incorrect syntax near the keyword 'KEY'. Msg 319, Level 15, State 1, Line 3 Incorrect syntax near the keyword 'with'. If this statement is a common table expression or an xmlnamespaces clause, the previous statement must be terminated with a semicolon. please help in resolving the same as i need to implement Encryption on my DB

    Read the article

< Previous Page | 63 64 65 66 67 68 69 70 71 72 73 74  | Next Page >