Search Results

Search found 8610 results on 345 pages for 'django filter'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 67/345 | < Previous Page | 63 64 65 66 67 68 69 70 71 72 73 74  | Next Page >

  • Django: IE doesn't load locahost or loads very SLOWLY

    - by reedvoid
    I'm just starting to learn Django, building a project on my computer, running Windows 7 64-bit, Python 2.7, Django 1.3. Basically whatever I write, it loads in Chrome and Firefox instantly. But for IE (version 9), it just stalls there, and does nothing. I can load up "http://127.0.0.1:8000" on IE and leave the computer on for hours and it doesn't load. Sometimes, when I refresh a couple of times or restart IE it'll work. If I change something in the code, again, Chrome and Firefox reflects changes instantly, whereas IE doesn't - if it loads the page at all. What is going on? I'm losing my mind here....

    Read the article

  • TypeError while using django Form in editing an Entry

    - by damon
    I have an Entry model which can belong to a Category.I am providing a CategoryChoicesForm sothat the user can choose from various Categorys (from a dropdown list)when an Entry is created or edited. I am having trouble with the CategoryChoicesForm while editing the Entry.It throws a TypeError.. If somebody can make out what is happening..please advise me how to correct this. int() argument must be a string or a number, not 'QueryDict' /home/Django-1.4/django/db/models/fields/__init__.py in get_prep_value, line 537 ...views.py in edit_entry category_choices_form = CategoryChoicesForm(form_data) ... ...forms.py in __init__ self.fields['categoryoption'].queryset = Category.objects.filter(creator=self.creator) Here is the form class CategoryChoicesForm(forms.Form): categoryoption = forms.ModelChoiceField( queryset = Category.objects.none(), required=False,label='Category') def __init__(self, categorycreator,*args, **kwargs): super(CategoryChoicesForm, self).__init__(*args, **kwargs) self.creator=categorycreator self.fields['categoryoption'].queryset = Category.objects.filter(creator=self.creator) The edit_entry view is as follows @login_required @transaction.commit_on_success def edit_entry(request,id,template_name,page_title): form_data = get_form_data(request) entry = get_object_or_404(Entry,pk=id,author=request.user) ... category_choices_form = CategoryChoicesForm(form_data) ...

    Read the article

  • replay in django + apcahce + mod_wsgi ??

    - by Adam
    I have a simple django page that has a counter on it. I use Apache2 and mod_wsgi to serve it. First, when I enter this page, the counter shows 0, as it should. The second time when I enter the page the counter shows 1 - again, it is the right behavior. The problem begins now, cause when I enter this page the third time, I get 0 again. When I refresh it goes between 0, and 1, clearly using some cache or so. If I wait for some time and then try again, it will show 2, and 3, but will be stuck with those values, till this cache or whatever it is will be flushed, and then the counter continues. Does somebody knows how I can get it work right (the real scenario deals with getting data from the DB, but the problems with this strange cache are the same). BTW, I don't have any caching engine set in my django settings.

    Read the article

  • Django development server serving css but not js

    - by Wisco crew
    I am developing a django (1.4) app on my local machine. I am running the built-in development server with python manage.py runserver. In base.html I have: <link href="{{ STATIC_URL }}bootstrap.css" rel="stylesheet" type="text/css" /> <script src="{{ STATIC_URL }}boostrap-dropdown.js" type="text/javascript"></script> boostrap.css loads just fine when I load a page, but bootstrap-dropdown.js is 404'd. They are sitting right next to each other in my static directory. Relevant parts of settings.py: STATIC_URL = '/static/' STATICFILES_DIRS = ( '/home/username/projects/projectname/static',) Debug is set to True. I have tried it both with and without the staticfiles_urlpatterns trick. Django can find one file in the directory but not the other? I think I'm going crazy.

    Read the article

  • Value [...] not a valid choice, django-updown

    - by tamara
    I am trying to implemet django-updown https://github.com/weluse/django-updown. When I try to add vote trough the admin panel it says Value 1 not a valid choice. This is the models.py from the application: _SCORE_TYPE_CHOICES = ( ('-1', 'DISLIKE'), ('1', 'LIKE'), ) SCORE_TYPES = dict((value, key) for key, value in _SCORE_TYPE_CHOICES) class Vote(models.Model): content_type = models.ForeignKey(ContentType, related_name="updown_votes") object_id = models.PositiveIntegerField() key = models.CharField(max_length=32) score = models.SmallIntegerField(choices=_SCORE_TYPE_CHOICES) user = models.ForeignKey(User, blank=True, null=True, related_name="updown_votes") ip_address = models.IPAddressField() date_added = models.DateTimeField(default=datetime.datetime.now, editable=False) date_changed = models.DateTimeField(default=datetime.datetime.now, editable=False) Do you have an idea what could be wrong?

    Read the article

  • Add a :filter param to the end of a url

    - by bob
    Hello, I am building an application that requires a search to go deeper than the initial level. I am using nested scopes to accomplish this and params in the URL For example, when a user searches for "handbag" it creates a query like the following. http://localhost:3000/junks?search=handbag&condition=&category=&main_submit=Go! I want to add a :filter param to the end of this url and reload the page with the new url. http://localhost:3000/junks?search=handbag&condition=&category=&main_submit=Go!&filter=lowest_price As shown above the &filter=lowest_price is added to the query. I have already written controller code to handle this and I know it works as long as the query is like the 2nd link above. my views code <div class = "filter_options"> <p> <strong>Filter by:</strong> <%= link_to_unless_current "Recent", :filter => 'recent' %> | <%= link_to_unless_current "Lowest Price", :filter => 'lowest_price' %> | <%= link_to_unless_current "Highest Price", :filter => 'highest_price' %> </p> </div> This is how I have it currently, which works if my URL does not have a search string attached to it. Unfortunately, this will go to a http://localhost:3000/junks?filter=lowest_price even if there is a search string. I would like to know how to create my links so that they add onto the search string shown in the 2nd code example. Additionally, if a search string with a filter is already present, it would only change that filter and resubmit the search string with the new filter. I hope I am being clear.

    Read the article

  • Migration for creating and deleting model in South

    - by Almad
    I've created a model and created initial migration for it: db.create_table('tvguide_tvguide', ( ('id', models.AutoField(primary_key=True)), ('date', models.DateField(_('Date'), auto_now=True, db_index=True)), )) db.send_create_signal('tvguide', ['TVGuide']) models = { 'tvguide.tvguide': { 'channels': ('models.ManyToManyField', ["orm['tvguide.Channel']"], {'through': "'ChannelInTVGuide'"}), 'date': ('models.DateField', ["_('Date')"], {'auto_now': 'True', 'db_index': 'True'}), 'id': ('models.AutoField', [], {'primary_key': 'True'}) } } complete_apps = ['tvguide'] Now, I'd like to drop it: db.drop_table('tvguide_tvguide') However, I have also deleted corresponding model. South (at least 0.6.2) is however trying to access it: (venv)[almad@eva-03 project]$ ./manage.py migrate tvguide Running migrations for tvguide: - Migrating forwards to 0002_removemodels. > tvguide: 0001_initial Traceback (most recent call last): File "./manage.py", line 27, in <module> execute_from_command_line() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 353, in execute_from_command_line utility.execute() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/management/commands/migrate.py", line 91, in handle skip = skip, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 581, in migrate_app result = run_forwards(mapp, [mname], fake=fake, db_dry_run=db_dry_run, verbosity=verbosity) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 388, in run_forwards verbosity = verbosity, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 287, in run_migrations orm = klass.orm File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 62, in __get__ self.orm = FakeORM(*self._args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 45, in FakeORM _orm_cache[args] = _FakeORM(*args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 106, in __init__ self.models[name] = self.make_model(app_name, model_name, data) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 307, in make_model tuple(map(ask_for_it_by_name, bases)), File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 23, in ask_for_it_by_name ask_for_it_by_name.cache[name] = _ask_for_it_by_name(name) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 17, in _ask_for_it_by_name return getattr(module, bits[-1]) AttributeError: 'module' object has no attribute 'TVGuide' Is there a way around?

    Read the article

  • Subterranean IL: Exception handler semantics

    - by Simon Cooper
    In my blog posts on fault and filter exception handlers, I said that the same behaviour could be replicated using normal catch blocks. Well, that isn't entirely true... Changing the handler semantics Consider the following: .try { .try { .try { newobj instance void [mscorlib]System.Exception::.ctor() // IL for: // e.Data.Add("DictKey", true) throw } fault { ldstr "1: Fault handler" call void [mscorlib]System.Console::WriteLine(string) endfault } } filter { ldstr "2a: Filter logic" call void [mscorlib]System.Console::WriteLine(string) // IL for: // (bool)((Exception)e).Data["DictKey"] endfilter }{ ldstr "2b: Filter handler" call void [mscorlib]System.Console::WriteLine(string) leave.s Return } } catch object { ldstr "3: Catch handler" call void [mscorlib]System.Console::WriteLine(string) leave.s Return } Return: // rest of method If the filter handler is engaged (true is inserted into the exception dictionary) then the filter handler gets engaged, and the following gets printed to the console: 2a: Filter logic 1: Fault handler 2b: Filter handler and if the filter handler isn't engaged, then the following is printed: 2a:Filter logic 1: Fault handler 3: Catch handler Filter handler execution The filter handler is executed first. Hmm, ok. Well, what happens if we replaced the fault block with the C# equivalent (with the exception dictionary value set to false)? .try { // throw exception } catch object { ldstr "1: Fault handler" call void [mscorlib]System.Console::WriteLine(string) rethrow } we get this: 1: Fault handler 2a: Filter logic 3: Catch handler The fault handler is executed first, instead of the filter block. Eh? This change in behaviour is due to the way the CLR searches for exception handlers. When an exception is thrown, the CLR stops execution of the thread, and searches up the stack for an exception handler that can handle the exception and stop it propagating further - catch or filter handlers. It checks the type clause of catch clauses, and executes the code in filter blocks to see if the filter can handle the exception. When the CLR finds a valid handler, it saves the handler's location, then goes back to where the exception was thrown and executes fault and finally blocks between there and the handler location, discarding stack frames in the process, until it reaches the handler. So? By replacing a fault with a catch, we have changed the semantics of when the filter code is executed; by using a rethrow instruction, we've split up the exception handler search into two - one search to find the first catch, then a second when the rethrow instruction is encountered. This is only really obvious when mixing C# exception handlers with fault or filter handlers, so this doesn't affect code written only in C#. However it could cause some subtle and hard-to-debug effects with object initialization and ordering when using and calling code written in a language that can compile fault and filter handlers.

    Read the article

  • GAE/Django Templates (0.96) filters to get LENGTH of GqlQuery and filter it

    - by Halst
    I pass the query with comments to my template: COMM = CommentModel.gql("ORDER BY created") doRender(self,CP.template,{'CP':CP,'COMM':COMM, 'authorize':authorize()}) And I want to output the number of comments as a result, and I try to do things like that: <a href="...">{{ COMM|length }} comments</a> Thats does not work (yeah, since COMM is GqlQuery, not a list). What can I do with that? Is there a way to convert GqlQuery to list or is there another solution? (first question) Second question is, how to filter this list in template? Is there a construct like this: <a href="...">{{ COMM|where(reference=smth)|length }} comments</a> so that I can get not only the number of all comments, but only comments with certain db.ReferenceProperty() property, for example. Last question: is it weird to do such things using templates?

    Read the article

  • Combo box filter on Extjs4.1.3

    - by saravanakumar
    I have created a window with combo box. Combo configuration is xtype :'combo', fieldLabel : 'Command', labelAlign : 'right', id :'commandInputComboId', store : commandStore, displayField: 'command', valueField : 'id', width : 500, enableKeyEvents : true, allowblank : false, queryMode: 'local', typeAhead : true, triggerAction: 'all', query filter works for normal data. But I have data with escape chars like &lt; because I need to show it as '<' for ex my data is <get-all-users> Filter apply only when I type &lt; not for <. How can apply filter on this data?

    Read the article

  • installed openstack using devstack install shell script but getting 500 error when i try opening dashboard

    - by Arvind
    I followed the instructions at http://devstack.org/guides/single-machine.html to install OpenStack. I first installed Ubuntu on my Windows 7 PC using the officially supported Windows installer for Ubuntu 12.04 LTS. And after that I followed the instructions at above page to install OpenStack. As per instructions, I should be able to access the dashboard aka Horizon, at http://192.168.1.4/ (thats the IP of the PC on which I installed Ubuntu-OpenStack). However I am getting a 500 error web page when I open that. How do I resolve this error? I want to set up a dev environment for OpenStack. For your ref, the whole error message is given now-- FilterError at / /usr/bin/env: node: No such file or directory Request Method: GET Request URL: http://192.168.1.4/ Django Version: 1.4.2 Exception Type: FilterError Exception Value: /usr/bin/env: node: No such file or directory Exception Location: /usr/local/lib/python2.7/dist-packages/compressor/filters/base.py in input, line 133 Python Executable: /usr/bin/python Python Version: 2.7.3 Python Path: ['/opt/stack/horizon/openstack_dashboard/wsgi/../..', '/opt/stack/python-keystoneclient', '/opt/stack/python-novaclient', '/opt/stack/python-openstackclient', '/opt/stack/keystone', '/opt/stack/glance', '/opt/stack/python-glanceclient/setuptools_git-0.4.2-py2.7.egg', '/opt/stack/python-glanceclient', '/opt/stack/nova', '/opt/stack/horizon', '/opt/stack/cinder', '/opt/stack/python-cinderclient', '/usr/local/lib/python2.7/dist-packages', '/usr/lib/python2.7', '/usr/lib/python2.7/plat-linux2', '/usr/lib/python2.7/lib-tk', '/usr/lib/python2.7/lib-old', '/usr/lib/python2.7/lib-dynload', '/usr/lib/python2.7/dist-packages', '/usr/lib/python2.7/dist-packages/PIL', '/usr/lib/python2.7/dist-packages/gst-0.10', '/usr/lib/python2.7/dist-packages/gtk-2.0', '/usr/lib/pymodules/python2.7', '/usr/lib/python2.7/dist-packages/ubuntu-sso-client', '/usr/lib/python2.7/dist-packages/ubuntuone-client', '/usr/lib/python2.7/dist-packages/ubuntuone-control-panel', '/usr/lib/python2.7/dist-packages/ubuntuone-couch', '/usr/lib/python2.7/dist-packages/ubuntuone-storage-protocol', '/opt/stack/horizon/openstack_dashboard'] Server time: Sat, 27 Oct 2012 08:43:29 +0000 Error during template rendering In template /opt/stack/horizon/openstack_dashboard/templates/_stylesheets.html, error at line 3 /usr/bin/env: node: No such file or directory 1 {% load compress %} 2 3 {% compress css %} 4 <link href='{{ STATIC_URL }}dashboard/less/horizon.less' type='text/less' media='screen' rel='stylesheet' /> 5 {% endcompress %} 6 7 <link rel="shortcut icon" href="{{ STATIC_URL }}dashboard/img/favicon.ico"/> 8 Also, the traceback is now given below-- Environment: Request Method: GET Request URL: http://192.168.1.4/ Django Version: 1.4.2 Python Version: 2.7.3 Installed Applications: ('openstack_dashboard', 'django.contrib.contenttypes', 'django.contrib.auth', 'django.contrib.sessions', 'django.contrib.messages', 'django.contrib.staticfiles', 'django.contrib.humanize', 'compressor', 'horizon', 'openstack_dashboard.dashboards.project', 'openstack_dashboard.dashboards.admin', 'openstack_dashboard.dashboards.settings', 'openstack_auth') Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', 'horizon.middleware.HorizonMiddleware', 'django.middleware.doc.XViewMiddleware', 'django.middleware.locale.LocaleMiddleware') Template error: In template /opt/stack/horizon/openstack_dashboard/templates/_stylesheets.html, error at line 3 /usr/bin/env: node: No such file or directory 1 : {% load compress %} 2 : 3 : {% compress css %} 4 : <link href='{{ STATIC_URL }}dashboard/less/horizon.less' type='text/less' media='screen' rel='stylesheet' /> 5 : {% endcompress %} 6 : 7 : <link rel="shortcut icon" href="{{ STATIC_URL }}dashboard/img/favicon.ico"/> 8 : Traceback: File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py" in get_response 111. response = callback(request, *callback_args, **callback_kwargs) File "/usr/local/lib/python2.7/dist-packages/django/views/decorators/vary.py" in inner_func 36. response = func(*args, **kwargs) File "/opt/stack/horizon/openstack_dashboard/wsgi/../../openstack_dashboard/views.py" in splash 38. return shortcuts.render(request, 'splash.html', {'form': form}) File "/usr/local/lib/python2.7/dist-packages/django/shortcuts/__init__.py" in render 44. return HttpResponse(loader.render_to_string(*args, **kwargs), File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py" in render_to_string 176. return t.render(context_instance) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in render 140. return self._render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in _render 134. return self.nodelist.render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in render 823. bit = self.render_node(node, context) File "/usr/local/lib/python2.7/dist-packages/django/template/debug.py" in render_node 74. return node.render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/loader_tags.py" in render 155. return self.render_template(self.template, context) File "/usr/local/lib/python2.7/dist-packages/django/template/loader_tags.py" in render_template 137. output = template.render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in render 140. return self._render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in _render 134. return self.nodelist.render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in render 823. bit = self.render_node(node, context) File "/usr/local/lib/python2.7/dist-packages/django/template/debug.py" in render_node 74. return node.render(context) File "/usr/local/lib/python2.7/dist-packages/compressor/templatetags/compress.py" in render 147. return self.render_compressed(context, self.kind, self.mode, forced=forced) File "/usr/local/lib/python2.7/dist-packages/compressor/templatetags/compress.py" in render_compressed 107. rendered_output = self.render_output(compressor, mode, forced=forced) File "/usr/local/lib/python2.7/dist-packages/compressor/templatetags/compress.py" in render_output 119. return compressor.output(mode, forced=forced) File "/usr/local/lib/python2.7/dist-packages/compressor/css.py" in output 51. ret.append(subnode.output(*args, **kwargs)) File "/usr/local/lib/python2.7/dist-packages/compressor/css.py" in output 53. return super(CssCompressor, self).output(*args, **kwargs) File "/usr/local/lib/python2.7/dist-packages/compressor/base.py" in output 230. content = self.filter_input(forced) File "/usr/local/lib/python2.7/dist-packages/compressor/base.py" in filter_input 192. for hunk in self.hunks(forced): File "/usr/local/lib/python2.7/dist-packages/compressor/base.py" in hunks 167. precompiled, value = self.precompile(value, **options) File "/usr/local/lib/python2.7/dist-packages/compressor/base.py" in precompile 210. command=command, filename=filename).input(**kwargs) File "/usr/local/lib/python2.7/dist-packages/compressor/filters/base.py" in input 133. raise FilterError(err) Exception Type: FilterError at / Exception Value: /usr/bin/env: node: No such file or directory

    Read the article

  • How to recreate Windows Live Mail filter rules in Thunderbird?

    - by FernandoSBS
    I have some filters in Windows Live Mail that I'm trying to port to thunderbird without success. It seems Thunderbird filter is very limited. Here is an ex of a filter i'm trying to recreate: Apply this rule after the message arrives Where the From line contains '[email protected]' or '[email protected]' or 'Programa TAM Fidelidade' and Where the message body contains 'esteja visualizando' and 'por ser cadastrado no Programa TAM Fidelidade' Move it to the Deleted items folder and Stop processing more rules In Thunderbird I can´t combine a list of "or"s with some "and"s, because it only allows you to select "message matches ALL of the criteria below" or "ANY of the below". Am I missing something or it really is very limited?

    Read the article

  • Need a workaround to filter on related model and aggregated fields in Django

    - by parxier
    I opened a ticket for this problem. In a nutshell here is my model: class Plan(models.Model): cap = models.IntegerField() class Phone(models.Model): plan = models.ForeignKey(Plan, related_name='phones') class Call(models.Model): phone = models.ForeignKey(Phone, related_name='calls') cost = models.IntegerField() I want to run a query like this one: Phone.objects.annotate(total_cost=Sum('calls__cost')).filter(total_cost__gte=0.5*F('plan__cap')) Unfortunately Django generates bad SQL: SELECT "app_phone"."id", "app_phone"."plan_id", SUM("app_call"."cost") AS "total_cost" FROM "app_phone" INNER JOIN "app_plan" ON ("app_phone"."plan_id" = "app_plan"."id") LEFT OUTER JOIN "app_call" ON ("app_phone"."id" = "app_call"."phone_id") GROUP BY "app_phone"."id", "app_phone"."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan"."cap" and errors with: ProgrammingError: column "app_plan.cap" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: ...."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan".... Is there any workaround apart from running raw SQL?

    Read the article

  • Django IN query as a string result - invalid literal for int() with base 10

    - by bmelton
    Trying to query a 'Favorites' model to get a list of items a user has favorited, and then querying against a different model to get the objects back from that query to present to the template, but I'm getting an error: "invalid literal for int() with base 10" Looking over all of the other instances of that error, I couldn't find any in which the asker actually wanted to work with a comma separated list of integers, so I'm kind of at a loss. Model class Favorite(models.Model): # key should be the model name, id is the model.id, and user is the User object. key = models.CharField(max_length=255, unique=True) val = models.IntegerField(default=0) user = models.ForeignKey(User) class Admin: list_display = ('key', 'id', 'user') View def index(request): favorites = Favorite.objects.filter(key='blog', user=request.user.pk) values = "" for favorite in favorites: values += "%s," % favorite.val #values = "[%s]" % values blogs = Blog.objects.filter(pk__in=values) return render_to_response('favorite/index.html', { "favorites" : favorites, "blogs" : blogs, "values" : values, }, context_instance=RequestContext(request) ) enter code here

    Read the article

  • Intersection of two querysets in django

    - by unagimiyagi
    Hello, I can't do an AND on two querysets. As in, q1 & q2. I get the empty set and I do not know why. I have tested this with the simplest cases. I am using django 1.1.1 I have basically objects like this: item1 name="Joe" color = "blue" item2 name="Jim" color = "blue" color = "white" item3 name="John" color = "red" color = "white" Is there something weird about having a many-to-many relationship or what am I missing? queryset1 = Item.objects.filter(color="blue") this gives (item1, item2) queryset2 = Item.objects.filter(color="white") this gives (item2, item3) queryset1 & queryset2 gives me the empty set [] The OR operator works fine (I'm using "|" ) Why is this so?

    Read the article

  • Getting an entry before and after a given entry in a Django Queryset

    - by Vernon
    I am creating a simple blog as part of a website and I am getting stuck on something that I am assuming is simple. If I call any blog post, say by it's title, from a queryset, how can I get the entry before and after the post in it's published order. I can iterate over the whole thing, get the position of the entry I have and use that to call the one before and the one after. But that is a long bit of code for something that I am sure I can do more simply. What I want would be something like this: next_post = Posts.object.filter(title=current_title).order_by("-published")[-1] Of course because of the filter, it is not going to work, but just to give you the idea of what I am looking for.

    Read the article

  • django blog - post- reply system display replies

    - by dana
    I have a mini blog app, and a reply system. I want to list all mini blog entries, and their replies, if there are any. i have in views.py def profile_view(request, id): u = UserProfile.objects.get(pk=id) paginator = New.objects.filter(created_by = request.user) replies = Reply.objects.filter(reply_to = paginator) return render_to_response('profile/publicProfile.html', { 'object_list': u, 'list':paginator, 'replies':replies }, context_instance=RequestContext(request)) and in the template: <h3>Recent Entries:</h3> {% for object in list %} <li>{{ object.post }} <br /> {% for object in replies %} {{ object.reply }} <br /> {% endfor %} mention : reply_to is a ForeignKey to New, and New is the name of the 'mini blog' table But it only shows all the replies for each blog entry, not the reply for every entry, if there is one thanks

    Read the article

  • what is this 'map' mean..in django

    - by zjm1126
    this is the code: def create(request, form_class=MapForm, template_name="maps/create.html"): map_form = form_class(request.POST or None) if map_form.is_valid(): map = map_form.save(commit=False) and the map_form is : class MapForm(forms.ModelForm): slug = forms.SlugField(max_length=20, help_text = _("a short version of the name consisting only of letters, numbers, underscores and hyphens."), #error_message = _("This value must contain only letters, numbers, underscores and hyphens.")) ) def clean_slug(self): if Map.objects.filter(slug__iexact=self.cleaned_data["slug"]).count() > 0: raise forms.ValidationError(_("A Map already exists with that slug.")) return self.cleaned_data["slug"].lower() def clean_name(self): if Map.objects.filter(name__iexact=self.cleaned_data["name"]).count() > 0: raise forms.ValidationError(_("A Map already exists with that name.")) return self.cleaned_data["name"] class Meta: model = Map fields = ('name', 'slug', 'description')

    Read the article

  • Django: order by count of a ForeignKey field?

    - by AP257
    This is almost certainly a duplicate question, in which case apologies, but I've been searching for around half an hour on SO and can't find the answer here. I'm probably using the wrong search terms, sorry. I have a User model and a Submission model. Each Submission has a ForeignKey field called user_submitted for the User who uploaded it. class Submission(models.Model): uploaded_by = models.ForeignKey('User') class User(models.Model): name = models.CharField(max_length=250 ) My question is pretty simple: how can I get a list of the three users with the most Submissions? I trued creating a num_submissions method on the User model: def num_submissions(self): num_submissions = Submission.objects.filter(uploaded_by=self).count() return num_submissions and then doing: top_users = User.objects.filter(problem_user=False).order_by('num_submissions')[:3] but this fails, as do all the other things I've tried. Can I actually do it using a smart database query? Or should I just do something more hacky in the views file?

    Read the article

  • Show a django relationship in a template

    - by kevin_82
    I have a django model as follows: class Person(models.Model): name = models.CharField(max_length=255) class Relationship(models.Model): parent = models.ForeignKey(Person) child = models.ForeignKey(Person) description = models.TextField(blank=True) In my view, I pass a certain person, and the relationships in which he/she is parent: person = Person.objects.filter(name ='some name') descendant_relationships = Relationship.objects.filter(parent = person) An I want to show this person's descendants in a list in a template: <ul> {% for item in descendant_relationships%} <li> {{item.child.name}} - {{item.description}} </li> {% endfor %} </ul> But this template code will not show the children of children (i.e. grandchildren, great-grandchildren etc.). How can I get these lower level descendants to show up? I imagine recursion is necessary somewhere, but where?

    Read the article

  • Django: optimizing queries

    - by Josh
    I want to list the number of items for each list. How can I find this number in a single query, rather than a query for each list? Here is a simplified version of my current template code: {% for list in lists %} <li> {{ listname }}: {% with list.num_items as item_count %} {{ item_count }} item{{ item_count|pluralize }} {% endwith %} </li> {% endfor %} lists is passed as: List.objects.filter(user=user) and num_items is a property of the List model: def _get_num_items(self): return self.item_set.filter(archived=False).count() num_items = property(_get_num_items) This queries SELECT COUNT(*) FROM "my_app_item" WHERE... n times, where n is the number of lists. Is it possible to make a single query here?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 63 64 65 66 67 68 69 70 71 72 73 74  | Next Page >