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  • forms problem in django 1.1

    - by alexarsh
    I have the following form: class ModuleItemForm2(forms.ModelForm): class Meta: model = Module_item fields = ('title', 'media', 'thumb', 'desc', 'default', 'player_option') The model is: class Module_item(models.Model): title = models.CharField(max_length=100) layout = models.CharField(max_length=5, choices=LAYOUTS_CHOICE) media = models.CharField(help_text='Media url', max_length=500, blank=True, null=True) conserv = models.ForeignKey(Conserv, help_text= 'Redirect to Conserv', blank=True, null=True) conserve_section = models.CharField(max_length=100, help_text= 'Section within the redirected Conserv', blank=True, null=True) parent = models.ForeignKey('self', help_text='Upper menu.', blank=True, null=True) module = models.ForeignKey(Module, blank=True, null=True) thumb = models.FileField(upload_to='sms/module_items/thumbs', blank=True, null=True) desc = models.CharField(max_length=500, blank=True, null=True) auto_play = models.IntegerField(help_text='Auto start play (miliseconds)', blank=True, null=True) order = models.IntegerField(help_text='Display order', blank=True, null=True) depth = models.IntegerField(help_text='The layout depth', blank=True, null=True) flow_replace = models.IntegerField(blank=True, null=True) default = models.IntegerField(help_text='The selected sub item (Note: Starting from 0)', blank=True, null=True) player_options = models.CharField(max_length=1000, null=True, blank=True) In my view I build form: module_item_form2 = ModuleItemForm2() print module_item_form2 And I get the following error on the print line: 'NoneType' object has no attribute 'label' It works fine with django 1.0.2. I see the error only in django 1.1. Do you have an idea what am I doing wrong? Regards, Arshavski Alexander.

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

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  • How to paginate Django with other get variables?

    - by vagabond
    I am having problems using pagination in Django. Take the URL below as an example: http://127.0.0.1:8000/users/?sort=first_name On this page I sort a list of users by their first_name. Without a sort GET variable it defaults to sort by id. Now if I click the next link I expect the following URL: http://127.0.0.1:8000/users/?sort=first_name&page=2 Instead I lose all get variables and end up with http://127.0.0.1:8000/users/?page=2 This is a problem because the second page is sorted by id instead of first_name. If I use request.get_full_path I will eventually end up with an ugly URL: http://127.0.0.1:8000/users/?sort=first_name&page=2&page=3&page=4 What is the solution? Is there a way to access the GET variables on the template and replace the value for the page? I am using pagination as described in Django's documentation and my preference is to keep using it. The template code I am using is similar to this: {% if contacts.has_next %} <a href="?page={{ contacts.next_page_number }}">next</a> {% endif %}

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  • Accessing data entered into multiple Django forms and generating them onto a new URL

    - by pedjk
    I have a projects page where users can start up new projects. Each project has two forms. The two forms are: class ProjectForm(forms.Form): Title = forms.CharField(max_length=100, widget=_hfill) class SsdForm(forms.Form): Status = forms.ModelChoiceField(queryset=P.ProjectStatus.objects.all()) With their respective models as follows: class Project(DeleteFlagModel): Title = models.CharField(max_length=100) class Ssd(models.Model): Status = models.ForeignKey(ProjectStatus) Now when a user fills out these two forms, the data is saved into the database. What I want to do is access this data and generate it onto a new URL. So I want to get the "Title" and the "Status" from these two forms and then show them on a new page for that one project. I don't want the "Title" and "Status" from all the projects to show up, just for one project at a time. If this makes sense, how would I do this? I'm very new to Django and Python (though I've read the Django tutorials) so I need as much help as possible. Thanks in advance Edit: The ProjectStatus code is (under models): class ProjectStatus(models.Model): Name = models.CharField(max_length=30) def __unicode__(self): return self.Name

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  • Elegant Disjunctive Normal Form in Django

    - by Mike
    Let's say I've defined this model: class Identifier(models.Model): user = models.ForeignKey(User) key = models.CharField(max_length=64) value = models.CharField(max_length=255) Each user will have multiple identifiers, each with a key and a value. I am 100% sure I want to keep the design like this, there are external reasons why I'm doing it that I won't go through here, so I'm not interested in changing this. I'd like to develop a function of this sort: def get_users_by_identifiers(**kwargs): # something goes here return users The function will return all users that have one of the key=value pairs specified in **kwargs. Here's an example usage: get_users_by_identifiers(a=1, b=2) This should return all users for whom a=1 or b=2. I've noticed that the way I've set this up, this amounts to a disjunctive normal form...the SQL query would be something like: SELECT DISTINCT(user_id) FROM app_identifier WHERE (key = "a" AND value = "1") OR (key = "b" AND value = "2") ... I feel like there's got to be some elegant way to take the **kwargs input and do a Django filter on it, in just 1-2 lines, to produce this result. I'm new to Django though, so I'm just not sure how to do it. Here's my function now, and I'm completely sure it's not the best way to do it :) def get_users_by_identifiers(**identifiers): users = [] for key, value in identifiers.items(): for identifier in Identifier.objects.filter(key=key, value=value): if not identifier.user in users: users.append(identifier.user) return users Any ideas? :) Thanks!

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  • Serving static media in django application

    - by Ed
    I notice that when I reference my java scripts and static image files from my templates, they show up in development, but not from the production server. From development, I access them as such: <img src="/my_proj/media/css/images/collapsed.png" /> but from production, I have to remove the project directory: <img src="/media/css/images/collapsed.png" /> I'm assuming I'm doing something wrong with regard to serving static media. I'm caught between a number of seemingly different options for serving static media in Django. On one hand, it's been recommended that I use django-staticfiles to serve media. On the other I see reference to STATIC_ROOT and STATIC_URL in the documentation (with caveats about use in production). I have small .png files of "plus" and "minus" symbols for use in some of my jQuery scripts. In addition, the scripts themselves need to be referenced. 1) Am I correctly categorizing scripts and site images as static media? 2) What is the best method to access this media (from production)?

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  • Query distinct list of choices for Django form with App Engine Datastore

    - by Brian
    I've been trying to figure this out for hours across a couple of days, and can not get it to work. I've been everywhere. I'll continue trying to figure it out, but was hoping for a quicker solution. I'm using App Engine datastore + Django. Using a query in a view and custom forms, I was able to get a list to the form but then I was not able to post. I have been trying to figure out how to dynamically add the choices as part of the Django form... I've tried various ways with no success. Help! Below are the two models. I'd like to get a distinct list of address_id to show in the location field in InfoForm. This fields could (and maybe should) be named the same, but I thought it'd be easier if they were named different. class Info(db.Model): user = db.UserProperty() location = db.StringProperty() info = db.StringProperty() created = db.DateTimeProperty(auto_now_add=True) modified = db.DateTimeProperty(auto_now=True) class Locations(db.Model): user = db.UserProperty() address_id = db.StringProperty() address = db.StringProperty() class InfoForm(djangoforms.ModelForm): info = forms.ChoiceField(choices=INFO_CHOICES) location = forms.ChoiceField() class Meta: model = Info exclude = ['user','created','modified']

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  • Building a survey to put in a WordPress website using Python/Django

    - by chiurox
    So I've been given a task to build a survey to get data regarding time slot preferences of prospective students for a particular course. I know there are really quick solutions to this like Google Forms, SurveyMonkey, but since it's not unusually hard, I want to implement the survey myself in a totally new language as an opportunity to get started with it and also be able to customize and provide dynamic info to the users who are voting. Although I have done some stuff in PHP, C++, javascript, etc, I'm pretty new to Python+Django framework but it's something I've been meaning to get into since a long time ago. Initially, what I want is to make a grid with the days of the week as columns and time-durations as rows. In each cell I want to provide users a way to choose how strong (high/medium/low) their preference for this particular day+time is. I also want to show how many "votes" have already been cast for this particular preference because this will influence a lot in their decisions and as a result make this process easier when we are going to define the classes. I'll probably store the data in MySQL. Could anyone point me to some really good Python+Django tutorials for my particular purpose? Does anyone think I'm wasting my time with this trivial task by choosing new tools and that I should just use something I already know (like PHP) or a free service or plugin for Wordpress? Thanks!

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  • How to setup and teardown temporary django db for unit testing?

    - by blokeley
    I would like to have a python module containing some unit tests that I can pass to hg bisect --command. The unit tests are testing some functionality of a django app, but I don't think I can use hg bisect --command manage.py test mytestapp because mytestapp would have to be enabled in settings.py, and the edits to settings.py would be clobbered when hg bisect updates the working directory. Therefore, I would like to know if something like the following is the best way to go: import functools, os, sys, unittest sys.path.append(path_to_myproject) os.environ['DJANGO_SETTINGS_MODULE'] = 'myapp.settings' def with_test_db(func): """Decorator to setup and teardown test db.""" @functools.wraps def wrapper(*args, **kwargs): try: # Set up temporary django db func(*args, **kwargs) finally: # Tear down temporary django db class TestCase(unittest.TestCase): @with_test_db def test(self): # Do some tests using the temporary django db self.fail('Mark this revision as bad.') if '__main__' == __name__: unittest.main() I should be most grateful if you could advise either: If there is a simpler way, perhaps subclassing django.test.TestCase but not editing settings.py or, if not; What the lines above that say "Set up temporary django db" and "Tear down temporary django db" should be?

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  • Cannot get MEDIA_URL from Django widget's template

    - by Eric
    Hi folks, I am a new Djangoer, and figuring out how to build custom widget, my problem is cannot get the MEDIA_URL in my widget's template, while the form use MySelectWidget able to get the MEDIA_URL itself. # #plus_sign.html # <a href="" class="" id="id_{{ field }}"> <img src="{{ MEDIA_URL }}images/plus_sign.gif" width="10" height="10" alt="Add"/> </a> *^ cannot load the {{ MEDIA_URL}} to this widget's template, and therefore I can't load the .gif image properly. :(* # #custom_widgets.py # from django import forms class MySelectMultiple(forms.SelectMultiple): def render(self, name, *args, **kwargs): html = super(MySelectMultiple, self).render(name, *args, **kwargs) plus = render_to_string("plus_sign.html", {'field': name}) return html+plus # #forms.py # from django import forms from myapp.custom_widgets.py import MySelectMultiple class MyForm(forms.ModelForm): contacts = forms.ModelMultipleChoiceField(Contact.objects, required=False, widget=MySelectMultiple) # #views.py # def AddContacts(request): if request.method == 'POST': form = MyForm(request.POST) if form.is_valid(): cd = form.cleaned_data new = form.save() return HttpResponseRedirect('/addedContact/') else: form = MyForm() return render_to_response('shop/my_form.html', {'form': form}, context_instance=RequestContext(request)) # #my_form.html # {% extends "base.html" %} {% block content %} {{ form.contacts }} {% endblock %} Please let me know how can I load the widget's image properly. Thank you so much for all responses.

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  • Django: getting the list of related records for a list of objects

    - by Silver Light
    Hello! I have two models related one-to many: class Person(models.Model): name = models.CharField(max_length=255); surname = models.CharField(max_length=255); age = models.IntegerField(); class Dog(models.Model): name = models.CharField(max_length=255); owner = models.ForeignKey('Person'); I want to output a list of persons below each person a list of dogs he has. Here's how I can do it: in view: persons = Person.objects.all()[0:100]; in template: {% for p in persons %} {{ p.name }} has dogs:<br /> {% for d in persons.dog_set.all %} - {{ d.name }}<br /> {% endfor %} {% endfor %} But if I do it like that, Django will execute 101 SQL queries which is very inefficient. I tried to make a custom manager, which will get all the persons, then all the dogs and links them in python, but then I can't use paginator (my another question: http://stackoverflow.com/questions/2532475/django-paginator-raw-sql-query ) and it looks quite ugly. Is there a more graceful way doing this?

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  • [Django] One single page to create a Parent object and its associated child objects

    - by ahmoo
    Hi all, This is my very first post on this awesome site, from which I have been finding answers to a handful of challenging questions. Kudos to the community! I am new to the Django world, so am hoping to find help from some Django experts here. Thanks in advance. Item model: class Item(models.Model): name = models.CharField(max_length=50) ItemImage model: class ItemImage(models.Model): image = models.ImageField(upload_to=get_unique_filename) item = models.ForeignKey(Item, related_name='images') As you can tell from the model definitions above, every Item object can have many ItemImage objects. My requirements are as followings: A single web page that allows users to create a new Item while uploading the images associated with the Item. The Item and the ItemImages objects should be created in the database all together, when the "Save" button on the page is clicked. I have created a variable in a custom config file, called NUMBER_OF_IMAGES_PER_ITEM. It is based on this variable that the system generates the number of image fields per item. Questions: What should the forms and the template be like? Can ModelForm be used to achieve the requirements? For the view function, what do I need to watch out other than making sure to save Item before ItemImage objects?

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  • Which web framework to use under Backbonejs?

    - by egidra
    For a previous project, I was using Backbonejs alongside Django, but I found out that I didn't use many features from Django. So, I am looking for a lighter framework to use underneath a Backbonejs web app. I never used Django built in templates. When I did, it was to set up the initial index page, but that's all. I did use the user management system that Django provided. I used the models.py, but never views.py. I used urls.py to set up which template the user would hit upon visiting the site. I noticed that the two features that I used most from Django was South and Tastypie, and they aren't even included with Django. Particularly, django-tastypie made it easy for me to link up my frontend models to my backend models. It made it easy to JSONify my front end models and send them to Tastypie. Although, I found myself overriding a lot of tastypie's methods for GET, PUT, POST requests, so it became useless. South made it easy to migrate new changes to the database. Although, I had so much trouble with South. Is there a framework with an easier way of handling database modifications than using South? When using South with multiple people, we had the worse time keeping our databases synced. When someone added a new table and pushed their migration to git, the other two people would spend days trying to use South's automatic migration, but it never worked. I liked how Rails had a manual way of migrating databases. Even though I used Tastypie and South a lot, I found myself not actually liking them because I ended up overriding most Tastypie methods for each Resource, and I also had the worst trouble migrating new tables and columns with South. So, I would like a framework that makes that process easier. Part of my problem was that they are too "magical". Which framework should I use? Nodejs or a lighter Python framework? Which works best with my above criteria?

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  • Changing the RSS and Dynamic Views layout when using Blogger as a Podcast index

    - by Stuart
    I'm trying to set up a podcast service at present. This is just a 'spare time' task - so I wanted a quick, easy way to do it. To get this working: I've ripped (with owner permission) some YouTube content across to MP3 and hosted this content on Azure Blob Storage. I've posted blog posts - with linked mp3 content - inside a Blogger website. I've registered the RSS feed with iTunes This all seems to be working OK - http://dotnetmobilepodcast.blogspot.co.uk/ However, when it comes to a couple of final touches, then I'm hitting problems. RSS I would like to add iTunes metadata to the RSS feed. However, I can't find any way to do this inside the Blogger system. To workaround this I've tried using FeedBurner with its StreamCast plugin. However, the output from FeedBurner doesn't seem to be accepted by iTunes - e.g. http://feeds.feedburner.com/MobileAppCSharpPodcasts leads to this very unhelpful 11111 message: Is there any other way I can get this iTunes metadata content into the Blogger RSS feed - e.g. maybe an alternative service or a Yahoo! Pipe? Showing the MP3 files in the Blog I'm trying to work out how to automatically display the linked enclosures inside the blog posts - do the blogger Dynamic Views don't seem to have any way of doing this? I've found the HTML in those views very difficult to follow. If necessary I can workaround this using manual entries into each blog post... but I'd prefer to do this programatically if I can.

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  • Running two wsgi applications on the same server gdal org exception with apache2/modwsgi

    - by monkut
    I'm trying to run two wsgi applications, one django and the other tilestache using the same server. The tilestache server accesses the db via django to query the db. In the process of serving tiles it performs a transform on the incoming bbox, and in this process hit's the following error. The transform works without error for the specific bbox polygon when run manually from the python shell: Traceback (most recent call last): File "/usr/lib/python2.7/dist-packages/TileStache/__init__.py", line 325, in __call__ mimetype, content = requestHandler(self.config, environ['PATH_INFO'], environ['QUERY_STRING']) File "/usr/lib/python2.7/dist-packages/TileStache/__init__.py", line 231, in requestHandler mimetype, content = getTile(layer, coord, extension) File "/usr/lib/python2.7/dist-packages/TileStache/__init__.py", line 84, in getTile tile = layer.render(coord, format) File "/usr/lib/python2.7/dist-packages/TileStache/Core.py", line 295, in render tile = provider.renderArea(width, height, srs, xmin, ymin, xmax, ymax, coord.zoom) File "/var/www/tileserver/providers.py", line 59, in renderArea bbox.transform(METERS_SRID) File "/usr/local/lib/python2.7/dist-packages/django/contrib/gis/geos/geometry.py", line 520, in transform g = gdal.OGRGeometry(self.wkb, srid) File "/usr/local/lib/python2.7/dist-packages/django/contrib/gis/gdal/geometries.py", line 131, in __init__ self.__class__ = GEO_CLASSES[self.geom_type.num] File "/usr/local/lib/python2.7/dist-packages/django/contrib/gis/gdal/geometries.py", line 245, in geom_type return OGRGeomType(capi.get_geom_type(self.ptr)) File "/usr/local/lib/python2.7/dist-packages/django/contrib/gis/gdal/geomtype.py", line 43, in __init__ raise OGRException('Invalid OGR Integer Type: %d' % type_input) OGRException: Invalid OGR Integer Type: 1987180391 I think I've hit the non thread safe issue with GDAL, metioned on the django site. Is there a way I could configure this so that it would work? Apache Version: Apache/2.2.22 (Ubuntu) mod_wsgi/3.3 Python/2.7.3 configured Apache apache2/sites-available/default: <VirtualHost *:80> ServerAdmin ironman@localhost DocumentRoot /var/www/bin LogLevel warn WSGIDaemonProcess lbs processes=2 maximum-requests=500 threads=1 WSGIProcessGroup lbs WSGIScriptAlias / /var/www/bin/apache/django.wsgi Alias /static /var/www/lbs/static/ </VirtualHost> <VirtualHost *:8080> ServerAdmin ironman@localhost DocumentRoot /var/www/bin LogLevel warn WSGIDaemonProcess tilestache processes=1 maximum-requests=500 threads=1 WSGIProcessGroup tilestache WSGIScriptAlias / /var/www/bin/tileserver/tilestache.wsgi </VirtualHost> Django Version: 1.4 httpd.conf: Listen 8080 NameVirtualHost *:8080 UPDATE I've added the a test.wsgi script to determine if the GLOBAL interpreter setting is correct, as mentioned by graham and described here: http://code.google.com/p/modwsgi/wiki/CheckingYourInstallation#Sub_Interpreter_Being_Used It seems to show the expected result: [Tue Aug 14 10:32:01 2012] [notice] Apache/2.2.22 (Ubuntu) mod_wsgi/3.3 Python/2.7.3 configured -- resuming normal operations [Tue Aug 14 10:32:01 2012] [info] mod_wsgi (pid=29891): Attach interpreter ''. I've worked around the issue for now by changing the srs used in the db so that the transform is unnecessary in tilestache app. I don't understand why the transform() method, when called in the django app works, but then in the tilestache app fails. tilestache.wsgi #!/usr/bin/python import os import time import sys import TileStache current_dir = os.path.abspath(os.path.dirname(__file__)) project_dir = os.path.realpath(os.path.join(current_dir, "..", "..")) sys.path.append(project_dir) sys.path.append(current_dir) os.environ['DJANGO_SETTINGS_MODULE'] = 'bin.settings' sys.stdout = sys.stderr # wait for the apache django lbs server to start up, # --> in order to retrieve the tilestache cfg time.sleep(2) tilestache_config_url = "http://127.0.0.1/tilestache/config/" application = TileStache.WSGITileServer(tilestache_config_url) UPDATE 2 So it turned out I did need to use a projection other than the google (900913) one in the db. So my previous workaround failed. While I'd like to fix this issue, I decided to work around the issue this type by making a django view that performs the transform needed. So now tilestache requests the data through the django app and not internally.

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  • Looking into ASP.Net MVC 4.0 Mobile Development - part 2

    - by nikolaosk
    In this post I will be continuing my discussion on ASP.Net MVC 4.0 mobile development. You can have a look at my first post on the subject here . Make sure you read it and understand it well before you move one reading the remaining of this post. I will not be writing any code in this post. I will try to explain a few concepts related to the MVC 4.0 mobile functionality. In this post I will be looking into the Browser Overriding feature in ASP.Net MVC 4.0. By that I mean that we override the user agent for a given user session. This is very useful feature for people who visit a site through a device and they experience the mobile version of the site, but what they really want is the option to be able to switch to the desktop view. "Why they might want to do that?", you might wonder.Well first of all the users of our ASP.Net MVC 4.0 application will appreciate that they have the option to switch views while some others will think that they will enjoy more the contents of our website with the "desktop view" since the mobile device they view our site has a quite large display.  Obviously this is only one site. These are just different views that are rendered.To put it simply, browser overriding lets our application treat requests as if they were coming from a different browser rather than the one they are actually from. In order to do that programmatically we must have a look at the System.Web.WebPages namespace and the classes in it. Most specifically the class BrowserHelpers. Have a look at the picture below   In this class we see some extension methods for HttpContext class.These methods are called extensions-helpers methods and we use them to switch to one browser from another thus overriding the current/actual browser. These APIs have effect on layout,views and partial views and will not affect any other ASP.Net Request.Browser related functionality.The overridden browser is stored in a cookie. Let me explain what some of these methods do. SetOverriddenBrowser() -  let us set the user agent string to specific value GetOverriddenBrowser() -  let us get the overridden value ClearOverriddenBrowser() -  let us remove any overridden user agent for the current request   To recap, in our ASP.Net MVC 4.0 applications when our application is viewed in our mobile devices, we can have a link like "Desktop View" for all those who desperately want to see the site with in full desktop-browser version.We then can specify a browser type override. My controller class (snippet of code) that is responsible for handling the switching could be something like that. public class SwitchViewController : Controller{ public RedirectResult SwitchView(bool mobile, string returnUrl){if (Request.Browser.IsMobileDevice == mobile)HttpContext.ClearOverriddenBrowser();elseHttpContext.SetOverriddenBrowser(mobile ? BrowserOverride.Mobile : BrowserOverride.Desktop);return Redirect(returnUrl);}} Hope it helps!!!!

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  • Why second user login redirects me to /accounts/profile/ url?

    - by drupality
    I am using Django built in view for user login: url(r'^user/login/$', 'django.contrib.auth.views.login', {'template_name': 'users/templates/login.html'}, name='user-login'), After login when I goto user/login again I can login second time. I submit the form and getting: The current URL, accounts/profile/, didn't match any of these. I haven't declare this url in urls.py. What I am doing wrong? Why framework want to redirect to this url?

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  • Select distinct values from a table field

    - by alj
    I'm struggling getting my head around the Django's ORM. What I want to do is get a list of distinct values within a field on my table .... the equivalent of one of the following: SELECT DISTINCT myfieldname FROM mytable (or alternatively) SELECT myfieldname FROM mytable GROUP BY myfieldname I'd at least like to do it the Django way before resorting to raw sql.

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  • can't figure out serving static images in django dev environment

    - by photographer
    I've read the article (and few others on the subject), but still can't figure out how to show an image unless a link to a file existing on a web-service is hard-coded into the html template. I've got in urls.py: ... (r'^galleries/(landscapes)/(?P<path>.jpg)$', 'django.views.static.serve', {'document_root': settings.MEDIA_URL}), ... where 'landscapes' is one of the albums I'm trying to show images from. (There are several more of them.) In views.py it calls the template with code like that: ... <li><img src=160.jpg alt='' title='' /></li> ... which resolves the image link in html into: http://127.0.0.1:8000/galleries/landscapes/160.jpg In settings.py I have: MEDIA_ROOT = 'C:/siteURL/galleries/' MEDIA_URL = 'http://some-good-URL/galleries/' In file system there is a file C:/siteURL/galleries/landscapes/160.jpg and I do have the same file at http://some-good-URL/galleries/landscapes/160.jpg No matter what I use in urls.py — MEDIA_ROOT or MEDIA_URL (with expectation to have either local images served or from the web-server) — I get following in the source code in the browser: <li><img src=160.jpg /></li> There is no image shown in the browser. What am I doing wrong?

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  • Django: Named URLs / Same Template, Different Named URL

    - by TheLizardKing
    I have a webapp that lists all of my artists, albums and songs when the appropriate link is clicked. I make extensive use of generic views (object_list/detail) and named urls but I am coming across an annoyance. I have three templates that pretty much output the exact same html that look just like this: {% extends "base.html" %} {% block content %} <div id="content"> <ul id="starts-with"> {% for starts_with in starts_with_list %} <li><a href="{% url song_list_x starts_with %}">{{ starts_with|upper }}</a></li> {% endfor %} </ul> <ul> {% for song in songs_list %} <li>{{ song.title }}</li> {% endfor %} </ul> </div> {% endblock content %} My artist and album template look pretty much the same and I'd like to combine the three template's into one. The fact that my variables start with song can easily be changed to the default obj. It's my <ul id="starts-with"> named url I don't know how to correct. Obviously I want it to link to a specific album/artist/song using the named urls in my urls.py but I don't know how to make it context aware. Any suggestions? urlpatterns = patterns('tlkmusic.apps.tlkmusic_base.views', # (r'^$', index), url(r'^artists/$', artist_list, name='artist_list'), url(r'^artists/(?P<starts_with>\w)/$', artist_list, name='artist_list_x'), url(r'^artist/(?P<artist_id>\d+)/$', artist_detail, name='artist_detail'), url(r'^albums/$', album_list, name='album_list'), url(r'^albums/(?P<starts_with>\w)/$', album_list, name='album_list_x'), url(r'^songs/$', song_list, name='song_list'), url(r'^songs/(?P<starts_with>\w)/$', song_list, name='song_list_x'), )

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  • Django error - no module named

    - by Shreyas
    Here is my relevant directory structure (Windows 7, Python 2.7, virtualenv) -userProf - - manage.py - -UserProfile - sampleapp_db - urls.py - views.py - wsgi.py - __init__.py - -libs - - __init__.py - -allauth - - app_settings.py - - models.py - - tests.py - - urls.py - - utils.py - - - -account - - - admin.py - - - context_processors.py - - - models.py - - - urls.py - - - __init__.py - -socialaccount - - - admin.py - - - context_processors.py - - - models.py - - - urls.py - - - views.py - - - __init__.py - - - - -templates - -account - - - base.html - - - email.html -settings - base_settings.py - dev.py - __init__.py - -static -css I get the following error when I try to run this dango app Error: No module named account I have read other posts on SO that refer to the syspath being the issue or that the appname matches the project name Django Shell No module named settings ...as a result of this, I added the following statements in the base_settings.py file import sys base = os.path.abspath(os.path.dirname(os.path.dirname(__file__))) base_parent = os.path.dirname(base) sys.path.append(base) sys.path.append(base_parent) sys.path.append(os.path.join(base,'libs')) sys.path.append(os.path.join(base,'libs','allauth','account')) I verified that the sys.path is correct by putting a break in PyCharm and evaluating sys.path Should I be putting this in manage.py? Some other SO postings referred to not being able to import the module but I can launch the python console and import UserProfile.libs.allauth.account without any exceptions being thrown! My base_setings.py has the following relevant section INSTALLED_APPS = ( 'UserProfile.libs.allauth.account', )

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  • Return 0 where django quersyet is none

    - by gramware
    I have a django queryset in my views whose values I pack before passing to my template. There is a problem when the queryset returns none since associated values are not unpacked. the quersyet is called comments. Here is my views.py def forums(request ): post_list = list(forum.objects.filter(child='0')&forum.objects.filter(deleted='0').order_by('postDate')) user = UserProfile.objects.get(pk=request.session['_auth_user_id']) newpostform = PostForm(request.POST) deletepostform = PostDeleteForm(request.POST) DelPostFormSet = modelformset_factory(forum, exclude=('child','postSubject','postBody','postPoster','postDate','childParentId')) readform = ReadForumForm(request.POST) comments =list( forum.objects.filter(deleted='0').filter(child='1').order_by('childParentId').values('childParentId').annotate(y=Count('childParentId'))) if request.user.is_staff== True : staff = 1 else: staff = 0 staffis = 1 if newpostform.is_valid(): topic = request.POST['postSubject'] poster = request.POST['postPoster'] newpostform.save() return HttpResponseRedirect('/forums') else: newpostform = PostForm(initial = {'postPoster':user.id}) if request.GET: form = SearchForm(request.GET) if form.is_valid(): query = form.cleaned_data['query'] post_list = list((forum.objects.filter(child='0')&forum.objects.filter(deleted='0')&forum.objects.filter(Q(postSubject__icontains=query)|Q(postBody__icontains=query)|Q(postDate__icontains=query)))or(forum.objects.filter(deleted='0')&forum.objects.filter(Q(postSubject__icontains=query)|Q(postBody__icontains=query)|Q(postDate__icontains=query)).values('childParentId'))) if request.method == 'POST': delpostformset = DelPostFormSet(request.POST) if delpostformset.is_valid(): delpostformset.save() return HttpResponseRedirect('/forums') else: delpostformset = DelPostFormSet(queryset=forum.objects.filter(child='0', deleted='0')) """if readform.is_valid(): user=get_object_or_404(UserProfile.objects.all()) readform.save() else: readform = ReadForumForm()""" post= zip( post_list,comments, delpostformset.forms) paginator = Paginator(post, 10) # Show 10 contacts per page # Make sure page request is an int. If not, deliver first page. try: page = int(request.GET.get('page', '1')) except ValueError: page = 1 # If page request (9999) is out of range, deliver last page of results. try: post = paginator.page(page) except (EmptyPage, InvalidPage): post = paginator.page(paginator.num_pages) return render_to_response('forum.html', {'post':post, 'newpostform': newpostform,'delpost':delpostformset, 'username':user.username, 'comments':comments, 'user':user, },context_instance = RequestContext( request ))

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  • sending the data from form to db in django

    - by BharatKrishna
    I have a form in which I can input text through text boxes. How do I make these data go into the db on clicking submit. this is the code of the form in the template. <form method="post" action="app/save_page"> <p> Title:<input type="text" name="title"/> </p> <p> Name:<input type="text" name="name"/> </p> <p> Phone:<input type="text" name="phone"/> </p> <p> Email:<input type="text" name="email"/> </p> <p> <textarea name="description" rows=20 cols=60> </textarea><br> </p> <input type="submit" value="Submit"/> </form> I have a function in the views.py for saving the data in the page. But I dont know how to impliment it properly: def save_page(request): title = request.POST["title"] name = request.POST["name"] phone = request.POST["phone"] email = request.POST["email"] description = request.POST["description"] Now how do I send these into the db? And what do I put in views.py so that those data goes into the db? so how do I open a database connection and put those into the db and save it? should I do something like : connection=sqlite3.connect('app.db') cursor= connection.cursor() ..... ..... connection.commit() connection.close() Thank you.

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  • .NET MVC: How to fix Visual Studio's lack of awareness of CSS classes in partial views?

    - by Mega Matt
    Hi all, This has been sort of an annoyance for me for a while. I make pretty heavy use of partial views in MVC, and am using Visual Studio 2008 to develop. The problem is that when I give html elements a class in a partial view (<div class="someClass">), it will underline them in green like it doesn't know what they are. I realize this is because I'm in a partial view, and haven't put link tags anywhere in that file for it to know where the CSS is (the link tags are in the main view that renders the partial view). The CSS still works fine on my site because the browser will render all views as one long html page anyway, but it's really annoying to look through my partial views and see all of my classes underlined in green. Is there a way that I can still tell Visual Studio that those classes exist somewhere, from the partial view? I figured there has to be a way to let it know, but am not sure what it is. Maybe a way to import the stylesheets from the parent view? Thanks for your help.

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