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  • add a number in while loop

    - by Luke
    if ($num_rows > 0) { while($row=mysql_fetch_assoc($res)) { $fromuser=$row['username']; $comment=$row['comment']; $commentdate=$row['date']; $date=strtotime($commentdate); $final_date=date("g:i a", $date); $final_date2=date("F j Y", $date); ?> <table align="center" width="100%"style='border-top: 1px dotted;'bgcolor="#eeeeee" > <tr><td><?echo "<a href=\"userprofile.php?user=$fromuser\"><b>$fromuser</b></a> commented:\n";?></td></tr> <tr><td><?echo "at $final_date on $final_date2\n";?></td></tr> <tr bgcolor="#ffffff"><td><?echo "$comment\n";?></td></tr> </table><br> <? } } else { echo"There are currently no comments on this user"; } ?> I am looking for a way to add a number to each comment. So 1, 2, 3, 4, etc in DESC order. I can't think how I can do this?

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  • Using $this when not in object context--i am using the latest version of php and mysql

    - by user309381
    This is user.php: include("databse.php");//retrieving successfully first name and lastname from databse file into user.php class user { public $first_name; public $last_name; public static function full_name() { if(isset($this->first_name) && isset($this->last_name)) { return $this->first_name . " " . $this->last_name; } else { return ""; } } } ?> Other php file, index.php: <?php include(databse.php); include(user.php); $record = user::find_by_id(1); $object = new user(); $object->id = $record['id']; $object->username = $record['username']; $object->password = $record['password']; $object->first_name = $record['first_name']; $object->last_name = $record['last_name']; // echo $object->full_name(); echo $object->id;// successfully print the id echo $object->username;//success fully print the username echo->$object->full_name();//**ERROR:Using $this when not in object context** ?>

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  • Is it possible to guarantee a unique id for multiple items using the same id variable at a point in

    - by Scarface
    First of all, do not be overwhelmed by the long code, I just put it for reference...I have a function that preg_replaces content and puts it in a jquery dialog box with a matching open-link. For example, if there is a paragraph with two matches, they will be put inside two divs, and a jquery dialog function will be echoed twice; one for each div. While this works for one match, if there are multiple matches, it does not. I am not sure how to distribute unique ids at a point in time for each of the divs and matching dialog open-scripts. Keep in mind, I removed the preg replace function since it kind of complicates the problem. If anyone has any ideas, they will be greatly appreciated. <?php $id=uniqid(); $id2=uniqid(); echo "<div id=\"$id2\"> </div>"; ?> $.ui.dialog.defaults.bgiframe = true; $(function() { $("<?php echo"#$id2"; ?>").dialog({hide: 'clip', modal: true ,width: 600,height: 350,position: 'center', show: 'clip',stack: true,title: 'title', minHeight: 25, minWidth: 100, autoOpen: false}); $('<?php echo"#$id"; ?>').click(function() { $('<?php echo"#$id2"; ?>').dialog('open'); }) .hover( function(){ $(this).addClass("ui-state-hover"); }, function(){ $(this).removeClass("ui-state-hover"); } ).mousedown(function(){ $(this).addClass("ui-state-active"); }) .mouseup(function(){ $(this).removeClass("ui-state-active"); }); });

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  • php insert doesnot take place _ URGENT HELP PLEASE

    - by reggie
    my code is as follows <?php include("config.php"); $ip=$_SERVER['REMOTE_ADDR']; if($_POST['id']) { $id=$_POST['id']; $id = mysql_escape_String($id); $ip_sql=mysql_query("select ip_add from Voting_IP where mes_id_fk='$id' and ip_add='$ip'"); $count=mysql_num_rows($ip_sql); if($count==0) { $sql = "update Messages set up=up+1 where mes_id='$id'"; mysql_query($sql); $sql_in = "insert into Voting_IP (mes_id_fk,ip_add) values ('$id','$ip')"; mysql_query($sql_in) or die(mysql_error()); echo "<script>alert('Thanks for the vote');</script>"; } else { echo "<script>alert('You have already voted');</script>"; } $result=mysql_query("select up from Messages where mes_id='$id'"); $row=mysql_fetch_array($result); $up_value=$row['up']; echo "<img src='button.png' width='110' height='90'>"; echo $up_value; } ?> My problem is that the insert process doesnot take place at all. the script tags echos an alert box. even the img tag is echoed to the web page. but the insert process doesnot take place. the config file is fine.. note: this code works on my local machine which has php 5.3 but it doesnot work on the server which has php 5.2.. any advice..???

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  • Function behaviour on shell(ksh) script

    - by footy
    Here are 2 different versions of a program: this Program: #!/usr/bin/ksh printmsg() { i=1 print "hello function :)"; } i=0; echo I printed `printmsg`; printmsg echo $i Output: # ksh e I printed hello function :) hello function :) 1 and Program: #!/usr/bin/ksh printmsg() { i=1 print "hello function :)"; } i=0; echo I printed `printmsg`; echo $i Output: # ksh e I printed hello function :) 0 The only difference between the above 2 programs is that printmsg is 2times in the above program while printmsg is called once in the below program. My Doubt arises here: To quote Be warned: Functions act almost just like external scripts... except that by default, all variables are SHARED between the same ksh process! If you change a variable name inside a function.... that variable's value will still be changed after you have left the function!! But we can clearly see in the 2nd program's output that the value of i remains unchanged. But we are sure that the function is called as the print statement gets the the output of the function and prints it. So why is the output different in both?

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  • Defining default value in combobox in CakePHP

    - by Keyur
    <?php echo $form->create('admin_merchant_form', array('action' => '#')); echo $form->input('company_name', array('label' => 'Company Name')); echo $form->input('ac_owner', array('label' => 'Account Owner', 'options' => array('a','b','b'), 'default' => $merchant_select)); echo $form->end('Update'); ?> This is CakePHP code to generate a form with one combobox containing the values "a,b,c" and assigning the default value as $merchant_select which is numerical data. Now the problem is when I assign like 'default'=1 it returns 'b' in the combobox as default value but when writing 'default' = $merchant_select the combobox shows only the first value which is 'a'. The $merchant_select variable is assigned a numeric value equal to merchant's id which 1,2 or 3 when I select any row in the grid. And I also have JavaScript code which alerts with the merchant value when I select any row in the grid so the numeric data is definitely assigned to the $merchant_select variable.

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  • PHP5 getrusage() returning incorrect information?

    - by Andrew
    I'm trying to determine CPU usage of my PHP scripts. I just found this article which details how to find system and user CPU usage time (Section 4). However, when I tried out the examples, I received completely different results. The first example: sleep(3); $data = getrusage(); echo "User time: ". ($data['ru_utime.tv_sec'] + $data['ru_utime.tv_usec'] / 1000000); echo "System time: ". ($data['ru_stime.tv_sec'] + $data['ru_stime.tv_usec'] / 1000000); Results in: User time: 29.53 System time: 2.71 Example 2: for($i=0;$i<10000000;$i++) { } // Same echo statements Results: User time: 16.69 System time: 2.1 Example 3: $start = microtime(true); while(microtime(true) - $start < 3) { } // Same echo statements Results: User time: 34.94 System time: 3.14 Obviously, none of the information is correct except maybe the system time in the third example. So what am I doing wrong? I'd really like to be able to use this information, but it needs to be reliable. I'm using Ubuntu Server 8.04 LTS (32-bit) and this is the output of php -v: PHP 5.2.4-2ubuntu5.10 with Suhosin-Patch 0.9.6.2 (cli) (built: Jan 6 2010 22:01:14) Copyright (c) 1997-2007 The PHP Group Zend Engine v2.2.0, Copyright (c) 1998-2007 Zend Technologies

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  • Why am I returning empty records when querying in mysql with php?

    - by Brian Bolton
    I created the following script to query a table and return the first 30 results. The query returns 30 results, but they do not have any text or information. Why would this be? The table stores Vietnamese characters. The database is mysql4. Here's the page: http://saomaidanang.com/recentposts.php Here's the code: <?php header( 'Content-Type: text/html; charset=utf-8' ); //CONNECTION INFO $dbms = 'mysql'; $dbhost = 'xxxxx'; $dbname = 'xxxxxxx'; $dbuser = 'xxxxxxx'; $dbpasswd = 'xxxxxxxxxxxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpasswd ) or die('Error connecting to mysql'); mysql_select_db($dbname , $conn); //QUERY $result = mysql_query("SET NAMES utf8"); $cmd = 'SELECT * FROM `phpbb_posts_text` ORDER BY `phpbb_posts_text`.`post_subject` DESC LIMIT 0, 30 '; $result = mysql_query($cmd); ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html dir="ltr"> <head> <title>recent posts</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> </head> <body> <p> <?php //DISPLAY while ($myrow = mysql_fetch_row($result)) { echo 'post subject:'; echo(utf8_encode($myrow ['post_subject'])); echo 'post text:'; echo(utf8_encode($myrow ['post_text'])); } ?> </p> </body>

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  • "for" loop inside another "for" loop

    - by jnkrois
    Hello everybody. I have quick question, and I'm sure some of you guys will be able to point out what I'm doing wrong. Basically, I want to create a table with (calendar), with the months and days of an entire year, and Im using php to do it, my code is doing something weird. What happens is that January is empty and the days for January are being put in february. My code so far is as follows: $months = 12; $monthsOfTheyear = array("Januany","February","March","April","May","June","July","August","September","October","November","December"); $currentMonth = date("n"); $currentYear = date("Y"); $daysOfTheMonth = cal_days_in_month(CAL_GREGORIAN, $currentMonth, $currentYear); for($i = 0; $i < $months; $i++){ echo " <tbody class='month'>"; echo " <tr> <td colspan='".$daysOfTheMonth."'> ".$monthsOfTheyear[$i]." </td> </tr> <tr> "; $daysOfEachMonth = cal_days_in_month(CAL_GREGORIAN, $i, $currentYear); for($d = 1; $d <= $daysOfEachMonth; $d++){ echo " <td> ".$d." </td> "; } echo " </tr> </tbody"; } I'm obviously doing something wrong, but I've been staring at the monitor for about an hour trying to figure it out. I'd appreciate any advice. Thanks

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  • php oop and mysql

    - by gloris
    I need to get data, to check and send to db. Programming with PHP OOP. Could you tell me if my class structure is good and how dislpay all data?. Thanks <?php class Database{ private $DBhost = 'localhost'; private $DBuser = 'root'; private $DBpass = 'root'; private $DBname = 'blog'; public function connect(){ //Connect to mysql db } public function select($rows){ //select data from db } public function insert($rows){ //Insert data to db } public function delete($rows){ //Delete data from db } } class CheckData{ public $number1; public $number2; public function __construct(){ $this->number1 = $_POST['number1']; $this->number2 = $_POST['number2']; } function ISempty(){ if(!empty($this->$number1)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number1); } else{ echo "Empty1"; } if(!empty($this->$number2)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number2); } else{ echo "Empty2"; } } } class DisplayData{ //How print all data? function DisplayNumber(){ $data = new Database(); $data->select(); } } $check = new CheckData(); $check->ISempty(); $display = new DisplayData() $display->DisplayNumber(); ?>

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  • explode is not working to split string

    - by pmms
    we unable to split the string following code.please Help us. <?php $i=0; $myFile = "testFile.txt"; $fh = fopen($myFile, 'a') or die("can't open file"); $stringData = "no\t"; fwrite($fh, $stringData); $stringData = "username \t"; fwrite($fh, $stringData); $stringData ="password \t"; fwrite ($fh,$stringData); $newline ="\r\n"; fwrite ($fh,$newline); $stringData1 = "1\t"; fwrite($fh, $stringData1); $stringData1 = "srinivas \t"; fwrite($fh, $stringData1); $stringData1 ="malayappa \t"; fwrite ($fh,$stringData1); fclose($fh); ?> $fh = fopen("testFile.txt", "r"); $ while (!feof($fh)) { $line = fgets($fh); echo $line; } fclose($fh); $Beatles = array('pmm','malayappa','sreenivas','PHP'); for($i=0;$i<count($Beatles);$i++) { if($i==2) { echo $Beatles[$i-1]; echo $Beatles[$i-2]; } } $pass_ar=array(); $fh = fopen("testFile.txt", "r"); while (!feof($fh)) { $line = fgets($fh); echo $line; $t1=explode(" ",$line); print_r($t1); array_push($pass_ar,t1); } fclose($fh); Thanks & Regards pmms

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  • accessing private variable from member function in PHP

    - by Carson Myers
    I have derived a class from Exception, basically like so: class MyException extends Exception { private $_type; public function type() { return $this->_type; //line 74 } public function __toString() { include "sometemplate.php"; return ""; } } Then, I derived from MyException like so: class SpecialException extends MyException { private $_type = "superspecial"; } If I throw new SpecialException("bla") from a function, catch it, and go echo $e, then the __toString function should load a template, display that, and then not actually return anything to echo. This is basically what's in the template file <div class="<?php echo $this->type(); ?>class"> <p> <?php echo $this->message; ?> </p> </div> in my mind, this should definitely work. However, I get the following error when an exception is thrown and I try to display it: Fatal error: Cannot access private property SpecialException::$_type in C:\path\to\exceptions.php on line 74 Can anyone explain why I am breaking the rules here? Am I doing something horribly witty with this code? Is there a much more idiomatic way to handle this situation? The point of the $_type variable is (as shown) that I want a different div class to be used depending on the type of exception caught.

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  • How to take html markup from a string and escape it to work within a script?

    - by zac
    I am using wordpress as a CMS and trying to allow user fields to be input to populate the info windows in a Google Map script. I am using this to select the id and pull in the content from a custom field : $post_id = 222; $my_post = get_post($post_id); $snip = get_post_meta($post_id, 'custom-field', true); $permalink = get_permalink( $post_id ); $pass_to = '<div class="content">'.$snip.'</div><div class="moreLink"><a href="'.$permalink.'">Find out more » </a></div></div>'; var point = new GLatLng('<?php echo $lat; $lat; ?>','<?php echo $long; $long; ?>'); var marker = createMarker(point,"<?php echo $mapTitle; $mapTitle; ?>", '<?php echo $pass_to; ?>') map.addOverlay(marker); It works fine unless there is any html in the custom-field which breaks the script. I looked at htmlspcialchar and htmlentities but rather than strip everything out I would like to have it escaped so it still works and the html is intact. Any suggestions? I am pretty new to PHP and would really appreciate any pointers.

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  • larger file upload problem with php

    - by chris
    I need to upload a csv file to a server. works fine for smaller files but when the file is 3-6 meg its not working. $allowedExtensions = array("csv"); foreach ($_FILES as $file) { if ($file['tmp_name'] > '') { if (!in_array(end(explode(".", strtolower($file['name']))), $allowedExtensions)) { die($file['name'].' is an invalid file type!<br/>'. '<a href="javascript:history.go(-1);">'. '&lt;&lt Go Back</a>'); } if (move_uploaded_file($file['tmp_name'], $uploadfile)) { echo "File is valid, and was successfully uploaded.\n"; } else { echo "Possible file upload attack!\n"; } echo "File has been uploaded"; } //upload form <form name="upload" enctype="multipart/form-data" action="<? echo $_SERVER['php_self'];?>?action=upload_process" method="POST"> <!-- MAX_FILE_SIZE must precede the file input field --> <input type="hidden" name="MAX_FILE_SIZE" value="31457280" /> <!-- Name of input element determines name in $_FILES array --> Send this file: <input name="userfile" type="file" /> <input type="submit" value="Send File" /> </form> I have also added this to htaccess php_value upload_max_filesize 20M php_value post_max_size 20M php_value max_execution_time 200 php_value max_input_time 200 Where am i going wrong?

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  • Trailing comments after variable assignment subvert comparison

    - by nobar
    In GNU make, trailing comments appended to variable assignments prevent subsequent comparison (via ifeq) from working correctly. Here's the Makefile... A = a B = b ## trailing comment C = c RESULT := ifeq "$(A)" "a" RESULT += a endif ifeq "$(B)" "b" RESULT += b endif ifeq "$(C)" "c" RESULT += c endif rule: @echo RESULT=\"$(RESULT)\" @echo A=\"$(A)\" @echo B=\"$(B)\" @echo C=\"$(C)\" Here's the output... $ make RESULT=" a c" A="a" B="b " C="c" As you can see from the displayed value of RESULT, the ifeq was affected by the presence of the comment in the assignment of B. Echoing the variable B, shows that the problem is not the comment, but the intervening space. The obvious solution is to explicitly strip the whitespace prior to comparison like so... ifeq "$(strip $(B))" "b" RESULT += b endif However this seems error prone. Since the strip operation is not needed unless/until a comment is used, you can leave out the strip and everything will initially work just fine -- so chances are you won't always remember to add the strip. Later, if someone adds a comment when setting the variable, the Makefile no longer works as expected. Note: There is a closely related issue, as demonstrated in this question, that trailing whitespace can break string compares even if there is no comment. Question: Is there a more fool-proof way to deal with this issue?

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  • Launch a new page in Zend/php on button click

    - by BlueMonster
    PHP & Zend Noob here I've downloaded the skeleton project from here: https://github.com/zendframework/ZendSkeletonApplication Say i want to open a new page that simply displays "hello world" text if click on the "ZF2 Development Portal" button(bottom left green button) on the page that launches --- how do i do this? See image: I've read through this tutorial, but i'm not sure how the model, view, or controller are actually launched? See tutorial: http://blog.wilgucki.pl/2012/07/tworzenie-modulw-w-zend-framework-2.html From looking at the code, i know that i will have to change this line of code: <div class="span4"> <h2><?php echo $this->translate('Follow Development') ?></h2> <p><?php echo sprintf($this->translate('Zend Framework 2 is under active development. If you are interested in following the development of ZF2, there is a special ZF2 portal on the official Zend Framework website which provides links to the ZF2 %swiki%s, %sdev blog%s, %sissue tracker%s, and much more. This is a great resource for staying up to date with the latest developments!'), '<a href="http://framework.zend.com/wiki/display/ZFDEV2/Home">', '</a>', '<a href="http://framework.zend.com/zf2/blog">', '</a>', '<a href="http://framework.zend.com/issues/browse/ZF2">', '</a>') ?></p> <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> </div> More specifically this line: <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> but i'm really confused as to what i'm supposed to change it to in order to launch a new page. Any ideas? Thanks in advance!

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  • Retrieving ids from MySQL query

    - by Matt Maclennan
    I am having trouble accessing the "model_id" and "brand_id" from the foreach loop that I am using. They are the right field names, because I have echoed them successfully, and I have also "var_dumped" the array, and the IDs are there. It is just a case of implementing the relevant links on each list section. Below is the code I have. <? $output = mysqli_query("SELECT * FROM bikes, bikeTypes WHERE bikes.model_id = bikeTypes.model_id"); $result = array(); while($row = mysqli_fetch_array($output)) { $result[$row['model']][] = $row; } foreach ($result as $category => $values) { echo "<li><a href='test.php?id=" . $row['model_id'] . "'>".$category.'</a><ul>'; foreach ($values as $value) { echo "<li><a href='details.php?id=" . $row['brand_id'] . "'>" . $value['bikeName'] . "</a></li>"; } echo '</ul>'; echo '</li>'; } ?>

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  • Php JSON Response Array

    - by Nick Kl
    I have this php code. As you can see i query a mysql database through a function showallevents. I return a the $result to the $event variable. I try to return all rows of the data that i take with the msql_fetch_assoc. I don't get response even when i encode the $response variable. It returns null to all fields. Can anyone help me on what i am doing wrong. I had a valid code but it was returning only 1 row of data so i tried to make an associative array but seems i am failing. if ($tag == 'showallevents') { // Request type is show all events // show all events $event = $db->showallevents(); if ($event != false) { $data = array(); while($row = mysql_fetch_assoc($event)) { $data[] = array( $response["success"] = 1, $response["uid"] = $event["uid"], $response["event"]["date"] = $event["date"], $response["event"]["hours"] = $event["hours"], $response["event"]["store_name"] = $event["store_name"], $response["event"]["event_information"] = $event["event_information"], $response["event"]["event_type"] = $event["event_type"], $response["event"]["Phone"] = $event["Phone"], $response["event"]["address"] = $event["address"], $response["event"]["created_at"] = $event["created_at"], $response["event"]["updated_at"] = $event["updated_at"]); } echo json_encode($data); } else { // event not found // echo json with error = 1 $response["error"] = 1; $response["error_msg"] = "Events not found"; echo json_encode($response); } } else { echo "Access Denied"; } } ?>

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  • Display two array's in the same table

    - by Naeem Ahmed
    $row = $query->fetchAll(PDO::FETCH_ASSOC); $num_rows = count($row); for ($i = 0; $i < $num_rows; $i++) { $title = htmlspecialchars($row[$i]['title']); $author =htmlspecialchars($row[$i]['author']); $school =htmlspecialchars($row[$i]['school']); $solution = $row[$i]['solution']; $notes = $row[$i]['notes']; $ad = array($title, $price, $author, $school, $contact, $content, $date); $inlcude = array($solutions, $notes); $field = 0; echo "<table border='1'>"; // foreach($inlcude as $in) This failled miserably foreach ($ad as $post) { if ($field < 3) //The first three values are placed in the first row { echo "<td>$post</td>"; } if ($field >= 3) { echo "<tr><td>$post</td><td>$in</td></tr>"; } $field++; } echo '</table>'; } I have two arrays and I would like to display them in different columns in my table. $ad displays perfectly fine but I'm having trouble displaying the contents in $inlcude in the second column. I've tried putting another foreach loop to iterate through contents of the second array but that really screws up my table by placing random values in different places on the table. Besides the foreach loop, I don't know of any other way to iterate through the array. Any suggestions would be appreciated.Thanks!

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  • "|" pipe operator not working in command line in C++

    - by user332024
    I am having a windows application interacting with DB2 database. In my application i have code to execute some DB2 commands through command line interface. I have used windowsAPI "ShellExecuteEx()" to execute those DB2 commands through command line. Following is the code written to execute DB2 command through command line. string command = "/c /w /i DB2 UNCATALOG NODE DB_DATABASE "" test.log | echo %date% %time% test.log SHELLEXECUTEINFO shellInfo; ZeroMemory(&shellInfo, sizeof(shellInfo)); shellInfo.cbSize = sizeof(shellInfo); shellInfo.fMask = SEE_MASK_FLAG_NO_UI | SEE_MASK_NOCLOSEPROCESS; //shellInfo.lpFile = "db2cmd"; shellInfo.lpFile = "db2cmd"; shellInfo.lpParameters = command.c_str(); The code is executed successfully , however if test.log is observered i only get result of DB2 command and not date and time. If you see the above command there is "|" pipe operator and echo command to log date and time in test.log Please note that if I execute above DB2 command through separately command line i.e. not through code. I am able to view date and time log along with DB2 command result in test.log. Following is the full command which i executed through command line. DB2CMD /c /i /w DB2 UNCATALOG NODE DB_DATABASE "" test.log | echo %date% %time% test.log According to me since DB2 command is executed successfully through code, there is problem with only usage of "|" pipe operator or echo command.

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  • php code in FTP to backup db using URL

    - by Giom
    I fund and inserted this code in my FTP in a backup.php that works great but it copy the file into the root folder (homez/) 1- I would like to put these backup files in a homez/backupDB any idea where to put this path? 2- the db backup files (DB.sql.bz2) have always the same name, is it possible to name each one with the date of creation? (I launch this php with the URL link) <? echo "Votre base est en cours de sauvegarde....... "; $db="nom_de_ma_base"; $status=system("mysqldump --host=mysql5-1.perso --user=$_POST[login] --password=$_POST[password] $db > ../$db.sql"); echo $status; echo "Compression du fichier..... "; system("bzip2 -f ../$db.sql"); echo "C'est fini. Vous pouvez récupérer la base par FTP \n "; ?> Thanks!

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  • MySQL query returning mysql_error

    - by Sebastian
    This returns mysql_error: <?php $name = $_POST['inputName2']; $email = $_POST['inputEmail2']; $instruments = $_POST['instruments']; $city = $_POST['inputCity']; $country = $_POST['inputCountry']; $distance = $_POST['distance']; // ^^ These all echo properly ^^ // CONNECT TO DB $dbhost = "xxx"; $dbname = "xxx"; $dbuser = "xxx"; $dbpass = "xxx"; $con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $query = "INSERT INTO depfinder (name, email, instrument1, instrument2, instrument3, instrument4, instrument5, city, country, max_distance) VALUES ($name, $email, $instruments[0], $instruments[1], $instruments[2], $instruments[3], $instruments[4], $city, $country, $max_distance)"; $result = mysqli_query($con, $query) or die(mysqli_error($con)); // script fails here if (!$result) { echo "There was a problem with the signup process. Please try again later."; } else { echo "Success"; } } ?> N.B. I'm not sure whether it's relevant, but the user may not choose five instruments so some $instrument[] array values may be empty. Bonus question: is my script secure enough or is there more I could do?

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  • Beginner PHP: I can't insert data into MYSQL database

    - by Victor
    I'm learning PHP right now and I'm trying to insert data into a MySQL database called "pumpl2" The table is set up like this. create table product ( productid int unsigned not null auto_increment primary key, price int(9) not null, value int(9) not null, description text ); I have a form and want to insert the fields from the form in the database. Here is what the php file looks like. <?php // create short variable names $price = $_POST['price']; $value = $_POST['value']; $description = $_POST['description']; if (!$price || !$value || !$description) { echo "You have not entered all the required details.<br />" ."Please go back and try again."; exit; } @ $db = new mysqli('localhost', 'pumpl', '********', 'pumpl2'); if (mysqli_connect_errno()) { echo "Error: Could not connect to database. Please try again later."; exit; } $query = "insert into pumpl2 values ('".$price."', '".$value."', '".$description."')"; $result = $db->query($query); if ($result) { echo $db->affected_rows." product inserted into database."; } else { echo "An error has occurred. The item was not added."; } $db->close(); ?> When I submit the form, I get an error message "An error has occurred. The item was not added." Does anyone know what the problem is? Thank you!

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  • can I add properties to a typo3 extbase domain model object?

    - by The Newbie Qs
    I want to store a username in a coupon object, each coupon object already has the uid of the user who created it. I can loop over the coupon objects and read the associated usernames from fe_users but how then will I save those usernames into the coupons so when they are passed to the template the usernames can be read like so coupon.username, or in some other easy way so each username will appear on the page with the right coupon as they are all printed out in a table? If I was doing basic php instead of typo3 i would just define a query but what is the typo3 v4.5 way? My code so far - which dies on the line where I try to assign the new property --creatorname -- to the $coup object. public function listAction() { $coupons = $this->couponRepository->findAll(); // @var Tx_Extbase_Domain_Repository_FrontendUserRepository $userRepository */ $userRepository = $this->objectManager->get("Tx_Extbase_Domain_Repository_FrontendUserRepository"); foreach ($coupons as $coup) { echo '<br />test '.$coup->getCreator(); echo '<br />count = '.$userRepository->countAll().'<br />'; $newObject = $userRepository->findByUid( intval($coup->getCreator())); //var_dump($newObject); var_dump($coup); echo '<br />getUsername '.$newObject->getUsername() ; $coup['creatorname'] = $newObject->getUsername(); echo '<br />creatorname '.$coup['creatorname'] ; } $this->view->assign('coupons', $coupons); }

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  • How to change image on locale base in magento?

    - by Nil
    I want to change search image in magento. On search in magento the image name is btn_search.gif. Right now it take image from skin/frontend/default/default/images. And the file is /app/design/frontend/default/default/template/catalogsearch/form.mini.phtml where mention this tag as <input id="search-button" type="image" src="<?php echo $this->getSkinUrl('images/btn_search.gif') ?>" alt="<?php echo $this->__('Search') ?>" /> I check the code and i found that we can pass locale as _type in this as <input id="search-button" type="image" src="<?php echo $this->getSkinUrl('images/btn_search.gif', array('_type'=>'local')) ?>" alt="<?php echo $this->__('Search') ?>" /> But when i check the code this will just check in locale directory that this file exist in that locale or not. If this exist then it will take skin image. I want to use that locale image instead of that skin image. So when i click on french store i get the image which is i set in /app/design/frontend/default/default/locale/fr_FR/images/btn_search.gif I check the code for getSkinUrl in /app/code/core/Mage/Core/Model/Design/Package.php. And i found that he check locale for file but it return skin url. Is there any method which return locale url ?

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