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  • Refresh / Redraw a Layer in OpenLayers (KML) Network-Link Auto Refresh

    - by Ozaki
    TLDR I want to refresh a layer on a timer so it plots the new kml data (like update-link / network link) So far I have tried action function as follows: function RefreshKMLData(layer) { layer.loaded = false; layer.setVisibility(true); layer.redraw({ force: true }); } set interval of the function: window.setInterval(RefreshKMLData, 5000, KMLLAYER); the layer itself: var KMLLAYER = new OpenLayers.Layer.Vector("MYKMLLAYER", { projection: new OpenLayers.Projection("EPSG:4326"), strategies: [new OpenLayers.Strategy.Fixed()], protocol: new OpenLayers.Protocol.HTTP({ url: MYKMLURL, format: new OpenLayers.Format.KML({ extractStyles: true, extractAttributes: true }) }) }); the url for KMLLAYER with Math random so it doesnt cache: var MYKMLURL = var currentanchorpositionurl = 'http://' + host + '/data?_salt=' + Math.random(); I would have thought that this would Refresh the layer. As by setting its loaded to false unloads it. Visibility to true reloads it and with the Math random shouldn't allow it to cache? So has anyone done this before or know how I can get this to work?

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  • coin rotation, as3

    - by VideoDnd
    What's the best way to make a coin rotation? I tried Math.random, but the coin doesn't wobble correctly. starter code //ROTATION addEventListener(Event.ENTER_FRAME, enterFrameHandler); function enterFrameHandler(event:Event):void { /* ADD VELOCITY, GRAVITY, ACCELERATION */ coin.rotationY += 8; } tried this, but it has no gravity or accelleration //ROTATION AND RANDOM MATH function wobble():void { var wobble = ((Math.random()*4)-2); flk.rotationY -= 11+wobble/2; flk.rotationX -= 2+wobble/20; } var myInterval:uint = setInterval (wobble, 40); I took out the work physics from my title:) I want it to behave like its affected by velocity, gravity, and acceleration.

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  • Why is there an implicit conversion from Float/Double to BigDecimal, but not from String?

    - by soc
    Although the situation of conversion from Doubles to BigDecimals has improved a bit compared to Java scala> new java.math.BigDecimal(0.2) res0: java.math.BigDecimal = 0.20000000000000001110223024625156... scala> BigDecimal(0.2) res1: scala.math.BigDecimal = 0.2 and things like val numbers: List[BigDecimal] = List(1.2, 3.2, 0.7, 0.8, 1.1) work really well, wouldn't it be reasonable to have an implicit conversion like implicit def String2BigDecimal(s: String) = BigDecimal(s) available by default which can convert Strings to BigDecimals like this? val numbers: List[BigDecimal] = List("1.2", "3.2", "0.7", "0.8", "1.1") Or am I missing something and Scala resolved all "problems" of Java with using the BigDecimal constructor with a floating point value instead of a String, and BigDecimal(String) is basically not needed anymore in Scala?

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  • Good "Modelling & Simulation" book recommendations for programmers?

    - by Harry
    I'm a programmer, and have completely forgotten all the advanced engineering Math I studied ~20 years ago at school. I now have an urgent need to learn about Modelling and Simulation. Though the present context is Disease Modelling, I'm not sure if there's such a thing as 'general' modelling and simulation... with concepts / techniques / algorithms that could be used in just about any domain (and not just limited to biology, finance, trade, economic, weather, etc.) Would you have any recommendations that are easy to read by a semi-Math-literate programmer? Basically, I cannot afford to drown myself in too much Math and theory behind M & S, hence this post. Tia...

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  • Polygon area calculation using Latitude and Longitude generated from Cartesian space and a world fil

    - by Heath
    Given a series of GPS coordinate pairs, I need to calculate the area of a polygon (n-gon). This is relatively small (not larger than 50,000 sqft). The geocodes are created by applying an affine transform with data from a world file. I have tried to use a two step approach by doing converting the geocodes to cartesian coordinates: double xPos = (lon-lonAnchor)*( Math.toRadians( 6378137 ) )*Math.cos( latAnchor ); double yPos = (lat-latAnchor)*( Math.toRadians( 6378137 ) ); then I use a cross product calculation to determine the area. The issue is that the results are a bit off in accuracy (around 1%). Is there anything I can look into to improve this? Thanks.

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  • Objective c string formatter for distances

    - by nevan
    I have a distance as a float and I'm looking for a way to format it nicely for human readers. Ideally, I'd like it to change from m to km as it gets bigger, and to round the number nicely. Converting to miles would be a bonus. I'm sure many people have had a need for one of these and I'm hoping that there's some code floating around somewhere. Here's how I'd like the formats: 0-100m: 47m (as a whole number) 100-1000m: 325m or 320m (round to the nearest 5 or 10 meters) 1000-10000m: 1.2km (round to nearest with one decimal place) 10000m +: 21km If there's no code available, how can I write my own formatter? Thanks

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  • How to mask DLL in .NET ?

    - by ytrewq
    Let's say I have a DLL that provides math calculus functions. To use it, I include the using Colhq.Math.Basic; namespace. How could I use it by adding a statement like using Blala.Functions.Math; ? So how could I use everything (methods, enums, etc.) from a DLL by using a different namespace ? Is there a one-shot way to wrap or mask a DLL ?

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  • Stop 2 identical queries from executing almost simultaneously?

    - by James Simpson
    I have developed an AJAX based game where there is a bug caused (very remote, but in volume it happens at least once per hour) where for some reason two requests get sent to the processing page almost simultaneously (the last one I tracked, the requests were a difference of .0001 ms). There is a check right before the query is executed to make sure that it doesn't get executed twice, but since the difference is so small, the check hasn't finished before the next query gets executed. I'm stumped, how can I prevent this as it is causing serious problems in the game. Just to be more clear, the query is starting a new round in the game, so when it executes twice, it starts 2 rounds at the same time which breaks the game, so I need to be able to stop the script from executing if the previous round isn't over, even if that previous round started .0001 ms ago.

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  • How to determine position (x,y) relative to the page of every character inside spans through javascript?

    - by Fernando
    This is as simple as I can get. I will have several spans randomly positioned on the screen through something like: $(".hidden:first").css('-webkit-transform','rotate('+((0.5-Math.random())*40)+'deg)'); $(".hidden:first").animate({ left: '+=' + (((screen.width-800-224)/2) + Math.random()*800), top: '+=' + (50+Math.random()*600) } [...] and later on I would like to iterate through every char of every of those elements (that are randomly position and have random rotation), and I would need to discover the (x,y) position of every character on the screen so I can colorize it, forming certain draws according to certain functions. Is this easily achievable? I am really inexperienced at javascript. Thanks. Fernando.

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  • Subquery works in 9i but not in 11g

    - by Zsuetam
    Statement below is working on Oracle 9i but not on Oracle 11g SELECT * FROM ( SELECT 0 scrnfail_rate, '9' zz, 7 hh FROM DUAL UNION ALL SELECT 0 scrnfail_rate, '9' zz, 7 hh FROM DUAL ) WHERE zz IS NOT NULL AND TO_CHAR (hh) NOT IN ( SELECT DECODE ( scrnfail_rate, 0, -1, ROUND (LEVEL * 1 / (scrnfail_rate / 100)) - ROUND (1 / (2 * (scrnfail_rate / 100))) ) AS nno FROM DUAL WHERE NVL (scrnfail_rate, 0) > 0 CONNECT BY LEVEL <= ROUND(9 * scrnfail_rate / 100) ) It looks like Oracle 11g is ignoring where decode or even where clause in the subquery. This query should return two rows as it does on Oracle 9i, but results ORA-01476: divisor is equal to zero on Oracle 11g EE 11.2.0.1.0 - 64bit. Can anyone help? Thanks!

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  • Why might different computers calculate different arithmetic results in VB.NET?

    - by Eyal
    I have some software written in VB.NET that performs a lot of calculations, mostly extracting jpegs to bitmaps and computing calculations on the pixels like convolutions and matrix multiplication. Different computers are giving me different results despite having identical inputs. What might be the reason? Edit: I can't provide the algorithm because it's proprietary but I can provide all the relevant operations: ULong \ ULong (Turuncating division) Bitmap.Load("filename.bmp') (Load a bitmap into memory) Bitmap.GetPixel(Integer, Integer) (Get a pixel's brightness) Double + Double Double * Double Math.Sqrt(Double) Math.PI Math.Cos(Double) ULong - ULong ULong * ULong ULong << ULong List.OrderBy(Of Double)(Func) Hmm... Is it possible that OrderBy is using a non-stable QuickSort and that QuickSort is using a random pivot? Edit: Just tested, nope. The sort is stable.

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  • counting twice in a query, once using restrictions

    - by Andrew Heath
    Given the following tables: Table1 [class] [child] math boy1 math boy2 math boy3 art boy1 Table2 [child] [glasses] boy1 yes boy2 yes boy3 no If I want to query for number of children per class, I'd do this: SELECT class, COUNT(child) FROM Table1 GROUP BY class and if I wanted to query for number of children per class wearing glasses, I'd do this: SELECT Table1.class, COUNT(table1.child) FROM Table1 LEFT JOIN Table2 ON Table1.child=Table2.child WHERE Table2.glasses='yes' GROUP BY Table1.class but what I really want to do is: SELECT class, COUNT(child), COUNT(child wearing glasses) and frankly I have no idea how to do that in only one query. help?

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  • One big call vs. multiple smaller TSQL calls

    - by BrokeMyLegBiking
    I have a ADO.NET/TSQL performance question. We have two options in our application: 1) One big database call with multiple result sets, then in code step through each result set and populate my objects. This results in one round trip to the database. 2) Multiple small database calls. There is much more code reuse with Option 2 which is an advantage of that option. But I would like to get some input on what the performance cost is. Are two small round trips twice as slow as one big round trip to the database, or is it just a small, say 10% performance loss? We are using C# 3.5 and Sql Server 2008 with stored procedures and ADO.NET.

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  • how to add multiview in a radio button

    - by Naveen31
    protected void ddlto_SelectedIndexChanged(object sender, EventArgs e) { } protected void RadioButton1_CheckedChanged1(object sender, EventArgs e) { MultiView1.ActiveViewIndex = 0; } protected void RadioButton2_CheckedChanged(object sender, EventArgs e) { MultiView1.ActiveViewIndex = 2; } <asp:RadioButtonList ID="RadioButtonList2" runat="server" AutoPostBack="True" RepeatDirection="Horizontal" Font-Names="Arial" Font-Size="Small" onselectedindexchanged="MultiView1_ActiveViewChanged"> <asp:ListItem Selected="True">One Way</asp:ListItem> <asp:ListItem>Round Trip</asp:ListItem> <asp:ListItem>Multi City</asp:ListItem> </asp:RadioButtonList> i have a radiolist of thre buttons-one way,round trip and multicity, i have taken a multiview in which in view 2 i have added the codes codes,and i want to show that code when i click on the 2nd radio button i.e on round trip,how to do it. plzz help

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  • How can I make my counter look less fake?

    - by Eddy Pronk
    I'm using this bit of code to display the number of users on a site. My customer is complaining it looks fake. Any suggestions? var visitors = 187584; var updateVisitors = function() { visitors++; var vs = visitors.toString(), i = Math.floor(vs.length / 3), l = vs.length % 3; while (i-->0) if (!(l==0&&i==0)) vs = vs.slice(0,i*3+l) + ',' + vs.slice(i*3+l); $('#count').text(vs); setTimeout(updateVisitors, Math.random()*2000); }; setTimeout(updateVisitors, Math.random()*2000);

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  • LWJGL Circle program create's an oval-like shape

    - by N1ghtk1n9
    I'm trying to draw a circle in LWJGL, but when I draw I try to draw it, it makes a shape that's more like an oval rather than a circle. Also, when I change my circleVertexCount 350+, the shape like flips out. I'm really not sure how the code works that creates the vertices(I have taken Geometry and I know the basic trig ratios). I haven't really found that good of tutorials on creating circles. Here's my code: public class Circles { // Setup variables private int WIDTH = 800; private int HEIGHT = 600; private String title = "Circle"; private float fXOffset; private int vbo = 0; private int vao = 0; int circleVertexCount = 300; float[] vertexData = new float[(circleVertexCount + 1) * 4]; public Circles() { setupOpenGL(); setupQuad(); while (!Display.isCloseRequested()) { loop(); adjustVertexData(); Display.update(); Display.sync(60); } Display.destroy(); } public void setupOpenGL() { try { Display.setDisplayMode(new DisplayMode(WIDTH, HEIGHT)); Display.setTitle(title); Display.create(); } catch (LWJGLException e) { e.printStackTrace(); System.exit(-1); } glClearColor(0.0f, 0.0f, 0.0f, 0.0f); } public void setupQuad() { float r = 0.1f; float x; float y; float offSetX = 0f; float offSetY = 0f; double theta = 2.0 * Math.PI; vertexData[0] = (float) Math.sin(theta / circleVertexCount) * r + offSetX; vertexData[1] = (float) Math.cos(theta / circleVertexCount) * r + offSetY; for (int i = 2; i < 400; i += 2) { double angle = theta * i / circleVertexCount; x = (float) Math.cos(angle) * r; vertexData[i] = x + offSetX; } for (int i = 3; i < 404; i += 2) { double angle = Math.PI * 2 * i / circleVertexCount; y = (float) Math.sin(angle) * r; vertexData[i] = y + offSetY; } FloatBuffer vertexBuffer = BufferUtils.createFloatBuffer(vertexData.length); vertexBuffer.put(vertexData); vertexBuffer.flip(); vao = glGenVertexArrays(); glBindVertexArray(vao); vbo = glGenBuffers(); glBindBuffer(GL_ARRAY_BUFFER, vbo); glBufferData(GL_ARRAY_BUFFER,vertexBuffer, GL_STATIC_DRAW); glVertexAttribPointer(0, 2, GL_FLOAT, false, 0, 0); glBindBuffer(GL_ARRAY_BUFFER, 0); glBindVertexArray(0); } public void loop() { glClear(GL_COLOR_BUFFER_BIT); glBindVertexArray(vao); glEnableVertexAttribArray(0); glDrawArrays(GL_TRIANGLE_FAN, 0, vertexData.length / 2); glDisableVertexAttribArray(0); glBindVertexArray(0); } public static void main(String[] args) { new Circles(); } private void adjustVertexData() { float newData[] = new float[vertexData.length]; System.arraycopy(vertexData, 0, newData, 0, vertexData.length); if(Keyboard.isKeyDown(Keyboard.KEY_W)) { fXOffset += 0.05f; } else if(Keyboard.isKeyDown(Keyboard.KEY_S)) { fXOffset -= 0.05f; } for(int i = 0; i < vertexData.length; i += 2) { newData[i] += fXOffset; } FloatBuffer newDataBuffer = BufferUtils.createFloatBuffer(newData.length); newDataBuffer.put(newData); newDataBuffer.flip(); glBindBuffer(GL_ARRAY_BUFFER, vbo); glBufferSubData(GL_ARRAY_BUFFER, 0, newDataBuffer); glBindBuffer(GL_ARRAY_BUFFER, 0); } } 300 Vertex Count(This is my main problem) 400 Vertex Count - I removed this image, it's bugged out, should be a tiny sliver cut out from the right, like a secant 500 Vertex Count Each 100, it removes more and more of the circle, and so on.

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  • Rounding a positive number to a power of another number

    - by Sagekilla
    I'm trying to round a number to the next smallest power of another number. The number I'm trying to round is always positive. I'm not particular on which direction it rounds, but I prefer downwards if possible. I would like to be able to round towards arbitrary bases, but the ones I'm most concerned with at the moment is base 2 and fractional powers of 2 like 2^(1/2), 2^(1/4), and so forth. Here's my current algorithm for base 2. The log2 I multiply by is actually the inverse of log2: double roundBaseTwo(double x) { return 1.0 / (1 << (int)((log(x) * log2)) } Any help would be appreciated!

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  • How to read back and print text with newlines from a Python (Django) string with HTML?

    - by user1801486
    If someone types in a phrase, such as: I see you driving round town with the girl I love, and I’m like: haiku. (no blank lines between each line, but the text is written on three separate lines) into a text box on a web page, and then presses a button which is then stored in a database via Django, and that string is read back and printed on a page, how can I get it to print on an HTML page with the newlines still in the text? So instead of it being printed back as: I see you driving round town with the girl I love, and I’m like: haiku. It would print as: I see you driving round town with the girl I love, and I’m like: haiku. I know that if I use: (textarea)soAndSo.body(/textarea), this preserves the newlines that were in the file when the user typed it up originally. How can I get this same effect, but without having to use textarea boxes?

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  • Surface Area of a Spheroid in Python

    - by user3678321
    I'm trying to write a function that calculates the surface area of a prolate or oblate spheroid. Here's a link to where I got the formulas (http://en.wikipedia.org/wiki/Prolate_spheroid & http://en.wikipedia.org/wiki/Oblate_spheroid). I think I've written them wrong, but here is my code so far; from math import pi, sqrt, asin, degrees, tanh def checkio(height, width): height = float(height) width = float(width) lst = [] if height == width: r = 0.5 * width surface_area = 4 * pi * r**2 surface_area = round(surface_area, 2) lst.append(surface_area) elif height > width: #If spheroid is prolate a = 0.5 * width b = 0.5 * height e = 1 - a / b surface_area = 2 * pi * a**2 * (1 + b / a * e * degrees(asin**-1(e))) surface_area = round(surface_area, 2) lst.append(surface_area) elif height < width: #If spheroid is oblate a = 0.5 * height b = 0.5 * width e = 1 - b / a surface_area = 2 * pi * a**2 * (1 + 1 - e**2 / e * tanh**-1(e)) surface_area = round(surface_area, 2) lst.append(surface_area, 2) return lst

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  • Makefile automatic link dependency ?

    - by Kuang Chen
    It's easy to let program figure out the dependency at compile time, (with gcc -MM). Nevertheless, link dependency (deciding which libraries should be linked to) seems to be difficult to figure out. This issue become emergent when multiple targets with individual libraries to link to are needed. For instance, three dynamic library targets t1.so, t2.so and t3.so needs to be built. t1.so needs math library (-lm), while t2 and t3 don't. It would be tedious to write separate rules. A single rule requiring the three targets linked with math library saves the trouble. However, it causes inflation of target size since math library is unused for t2.so and t3.so. Any ideas?

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  • PHP - Why does my computation produce a different result when I assign it to a variable?

    - by David
    I want to round a number to a specific number of significant digits - basically I want the following function: round(12345.67, 2) -> 12000 round(8888, 3) -> 8890 I have the following, but there's a strange problem. function round_to_sf($number, $sf) { $mostsigplace = floor(log10(abs($number)))+1; $num = $number / pow(10, ($mostsigplace-$sf)); echo ($number / pow(10, ($mostsigplace-$sf))).' '.$num.'<BR>'; } round_to_sf(41918.522, 1); Produces the following output: 4.1918522 -0 How can the result of a computation be different when it's assigned to a variable?

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  • SensorManager method crashes program

    - by Aidan
    Hi guys, When I run the following method my Android application crashes. I can't find the error because I get a "Source Not Found" error. Anyone have any idea's what I'm doing wrong? public void bearing(){ SensorManager sm = (SensorManager)getSystemService(Context.SENSOR_SERVICE); Sensor aSensor = sm.getDefaultSensor(Sensor.TYPE_ACCELEROMETER); Sensor mfSensor = sm.getDefaultSensor(Sensor.TYPE_MAGNETIC_FIELD); sm.registerListener(myAccelerometerListener, aSensor, SensorManager.SENSOR_DELAY_UI); sm.registerListener(myMagneticFieldListener, mfSensor, SensorManager.SENSOR_DELAY_UI); float[] values = new float[3]; float[] R = new float[9]; SensorManager.getRotationMatrix(R, null, accelerometerValues, magneticFieldValues); SensorManager.getOrientation(R, values); //Convert from Radians to degrees values[0] = (float) Math.toDegrees(values[0]); values[1] = (float) Math.toDegrees(values[1]); values[2] = (float) Math.toDegrees(values[2]); }

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  • Heap property of this array

    - by davit-datuashvili
    From programming pearls, it is known that array[1...n] has heap property if for all 2<=i<=n x[i/2]<=x[i]. Here is my code: import java.math.*; public class Heap { public static void main(String[]args){ int x[]=new int[]{12,20,15,29,23,17,22,35,40,26,51,19}; int i=1; while (i<x.length) { if (x[Math.round(i/2)]<=x[i]) System.out.println("heap"); i++; } System.out.println("not heap"); } } Here I used Math.round because 4/2 and 5/2 is same and =2. When I compile this code it shows me at last line that it is not heap. Maybe because the index starts from 1 and we don't pay attention to index 0, yes?

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  • Jquery incrementing number +1 0n page refresh.

    - by sameast
    Hi guys i am trying to modify this code here. $(document).ready(function() { var randomImages = ['img-1','img-2','img-3','img-4']; var rndNum = Math.floor(Math.random() * randomImages.length); $("div#bg-image").css({ background: "url(http://example.com/images/" + randomImages[rndNum] + ".jpg) no-repeat" }); }); This works fine and gives me a random image each time which is great but what i need is for the image to increment +1 each time on page refresh. This is because sometimes i can refresh 3 times and will still get the same image show when using Math.random(). I need to cancel the random and set +1 each time. Any help

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  • JQuery Calculator not working

    - by user2798091
    I am trying to build a tile calculator but can't seem to get the following code to work: JQuery: $(document).ready( function caculateForm() { var length = document.getElementById('length').value; var width = document.getElementById('width').value; var size = document.getElementById('size').value; var compute = (length * width) / (size / 100); var total = compute * 100; var allowance = (compute * 100) * .10; allowance = Math.floor(total) + Math.floor(allowance + 1); document.getElementById('total').value = Math.floor(total); document.getElementById('allowance').value = allowance; } }); $(document).ready( function clearFileInput(id) { var elem = document.getElementById(id); elem.parentNode.innerHTML = elem.parentNode.innerHTML; } }); Here is my jsfiddle

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